Explanation:
Gravity = 1.6 m/s^2
Mass = 85 kg
Full infomation needed your question is incomplete and BTW fomula : G Mm
R^2
Daryl uses a microphone connected to an oscilloscope to study sound waves. He finds that higher pitched sounds have higher frequencies and shorter wavelengths while lower pitched sounds have lower frequencies and longer wavelengths. Daryl concludes that the relationship between the frequency and the wavelength of sound waves in air is the result of causation and not correlation. In two to three sentences, describe whether Daryl’s conclusion is correct and explain why or why not.
Daryl’s conclusion that the relationship between the frequency and the wavelength of sound waves in air is the result of causation is correct.
What is Causation?This is defined as the relationship between successive events when the first event brings about the other.
The higher frequencies brings about shorter wavelengths which is why it is termed as being a result of causation.
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4. An archer pulls a bowstring back 0.440 m, and the spring constant of the bow is 545 N/m.
a.) Find the amount of work the archer did to draw the bow.
b.) Find the speed an arrow of mass 0.060 kg will have when it is shot from the bow.
Assume no losses from friction
Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)
(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS
Explanation:
SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.
FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.
An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the horizontal. Find the Rate of Climb.
The rate of climb of the aircraft in a steady climb making a 10 degree angle with the horizontal is : 17.36 knots
Given data
Airspeed = 100 knots
Angle with the horizontal ( ∅ ) = 10°
Determine the rate of climb of the aircraftwe will apply the formula below
Vy ( rate of climb ) = Airspeed * sin ∅
= 100 * sin ( 10 )
= 17.36 Knots
Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.
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A proton is moving south with a speed of 4500 m/s in a magnetic field of 5500 T directed into the page. Determine the magnitude and direction of the magnetic force on the charge.
a.3.96 x 10-12 N west
b.1.55 x 1026 west
c.1.55 x 1026 east
d.3.96 x 10-12 N east
Answer:
F = q V X B
V is south and B is into the page
The resultant vector is directed to the East
F = 1.6E-19 * 4.5E3 * 5.5E3 N = 3.96 N East
(Note q is negative for an electron producing a force in the opposite direction)
Hello people ~
last one I've got for y'all
Which of the following phenomenon is not explained by Huygen’s wave theory?
⇢Diffraction
⇢Interference
⇢Polarisation
⇢Photoelectric effect
Answer:
Photoelectric effect
Explanation:
Photo electric effect was a great invention of Albert EinsteinEinstein got nobel prize for discovering photoelectric effect.Option D is correct
what is the medium for an ocean wave? Provide evidence that the medium is not transferred when a water wave moves on a lake
The medium for an ocean wave is the ocean water which involves movement on the water body.
What is a Medium?This is defined as a substance or material that carries the wave. In the case of ocean waves, the medium is referred to the ocean water.
The medium is not transferred when a water wave moves on a lake as energy is transported but the water molecules aren't which is why lakes have water present in them.
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Lightning always follows
(a) a thunder
(b) rain pour
(c) the easiest path
(d) a straight path
Answer:
a thunder
Explanation:
It's because the difference in speed of light and sound
Light has speed about 3×10^8m/sSound has speed 344m/sSo we hear thunder later
Answer:
C
Explanation:
Lightning is a giant spark. A single stroke of lightning can heat the air around it to 30,000 degrees Celsius This extreme heating causes the air to expand at an explosive rate. The expansion creates a shock wave that turns to a booming sound wave, better known as thunder. Thunder & lightning occur at roughly the same time, although u see the flash of lightning before u hear the thunder. This is because light travels much faster than sound.Lightning always follows the easiest path. Lightning strikes buildings or projecting objects such as trees, poles, wires or building than larger, flatter surfaces because the material in them provide easier paths to the ground than the other. The primary target of lightning are lone buildings.Therefore, Thunder Follows The Easiest Part. And it is not (A) because Thunder Follows A Lightening Not Vice Versa.
The particles that make up matter are ______, ions or molecules.
Answer:
Atoms.
Explanation:
Atoms are purely one bit of an element. Ions are positive or negative atoms. Molecules are not pure, they have other stuff with it.
How does energy affecf a wave?
A regulation 145 g baseball can be hit at speeds of 100 mph. If a line drive is hit essentially horizontally at this speed and is caught by a 65 kg player who has leapt directly upward into the air, what
horizontal speed does he acquire by catching the ball?
This question involves the concept of the law of conservation of momentum.
The horizontal speed acquired by catching the ball will be "0.223 mph".
Law of Conservation of MomentumAccording to the law of conservation of momentum applied in horizontal direction:
Total Initial Momentum = Total Final Momentum
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = mass of baseball = 145 g = 0.145 kgm₂ = mass of player = 65 kgu₁ = initial horizontal speed of baseball = 100 mphu₂ = initial horizontal speed of player = 0 mphv₁ = final horizontal speed of baseball = 0 mphv₂ = final horizontal speed of player = ?Therefore,
[tex](0.145\ kg)(100\ mph)+(65\ kg)(0\ mph)=(0.145\ kg)(0\ mph)+(65\ kg)(v_2)\\\\v_2=\frac{14.5\ kg.mph}{65\ kg}\\\\[/tex]
v₂ = 0.223 mph
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This is less an answer more like the answers that should be it.
A) 9.9 cm/s
B) 5.6 cm/s
C) 11.8 cm/s
D) 4.2 cm/s
Tuning a piano to tune middle c on a piano, a tuner hits the key and at the same time sounds a 261 hz tuning fork. if the turner hears 3 beats per second, what are the possible frequencies of the piano key?
This question deals with the physics of resonance and sound. The possible frequency of the pano key is 258hz.
How to compute the variation in frequencyThe beat of a frequency is the difference (an absolute value) in the frequencies produced by the two waves.
Beat per second equals |f1 - f2| Where
ft = Frequency of the Tunning fork and
fp= Frequency of the Piano Key
Hence
3 = 261 - fp
Solving for fp,
fp = 261-3
= 258hz
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What are the postulates of the KMT of gases?
.
Which object has a constant speed?
a bicycle coming to a stop
a racecar starting a race
a ball falling off a table
a car traveling the speed limit
Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years
For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km, the period of the second plane is mathematically given as
T=2.2earth year
What is the period of the second planet?Generally, the equation for the time period is mathematically given as
[tex]T^{2} \appox a^{3}[/tex]
Therefore, for planet one
[tex]1^2\approx (150 x 10^6)^3[/tex]
In conclusion, For planet 2
T^2=(250/150)^3
T=√4.632
T=2.2earth year
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The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.
What is the time period of the revolution?The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.
The equation of the time period is found as;
[tex]\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year[/tex]
Hence the time period of the planet will be 2.2 earth years.
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Which is NOT a part of transverse waves?
A. wavelength
B. trough
C. compression
D. crest
Answer:
C. Compression
Explanation:
✧✧✧EMOTIONAL DAMAGE✧✧✧
kleann
When a thermometer is emersed in ice cold water, the Mercury thread is observed to rise before dropping steadily in the capillary tube. Explain
what is the result of ocean acidification
Answer:
Ocean acidification reduces the amount of carbonate, a key building block in seawater. This makes it more difficult for marine organisms, such as coral and some plankton, to form their shells and skeletons, and existing shells may begin to dissolve.
Answer:
The intake of carbon dioxide (CO2) from the atmosphere causes ocean acidification, which is the continual decline in the pH value of the Earth's oceans. The burning of fossil fuels by humans is the primary cause of ocean acidification. The amount of carbon dioxide absorbed by the ocean grows in lockstep with the amount of carbon dioxide in the atmosphere. This causes a sequence of chemical reactions in the seawater, which has a negative impact on the, however, their rine life that lives beneath the surface. Carbonic acid is formed when carbon dioxide dissolves in seawater (H2CO3). The pH value of the ocean surface is estimated to have decreased from approximately 8.25 to 8.14 between 1751 and 1996, representing a nearly 30% increase in H+ ion concentration in the world's oceans (note that the pH scale is logarithmic, so a change of one pH unit equals a tenfold change in H+ ion concentration). The pH of the ocean in 2020 will be 8.1, according to the National Oceanic and Atmospheric Administration.
Explanation:
The waves produced on the earth’s surface is called
(a) seismic wave
(b) longitudinal wave
(c) Micro wave
(d) Radio wave
Answer:
seismic wave
Explanation:
These waves are produced because of plate tectonicsThese helps are useful in measurements of earthquake.Used in seismograph.The magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s. What is the emf induced in the coil?
Since the magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s, the emf induced in the coil is -5.65 V
Induced emf in coilThe induced emf in the coil is given by ε = -NΔΦ/Δt where
ΔΦ = change in magnetic flux Φ₂ - Φ₁ where Φ₁ = initial magnetic flux = -58 Wb and Φ₂ = final magnetic flux = 38 Wb and and Δt = change in time = t₂ - t₁ where t₁ = initial time = 0 s and t₂ = final time = 34 sand N = number of loops of coil = 2Since ε = -NΔΦ/Δt
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
Substituting the values of the variables into the equation, we have
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)
ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)
ε = -2(96 Wb)/34 s
ε = -192 Wb/34 s
ε = -5.65 Wb/s
ε = -5.65 V
So, the emf induced in the coil is -5.65 V
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The electrical action generated by a non-electrical source, measured in volts. The emf induced in the coil is -564.7 V.
What is EMF?The electrical action generated by a non-electrical source, measured in volts, is referred to as emf or electromotive force. Devices, such as batteries or generators, generate an emf by converting various sources of energy into electrical energy.
The emf induced in a coil is given by
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
where
ΔΦ is the change in magnetic flux, Δt is the change in time, and N is the number of loops.
Given that the initial magnetic flux is -58 Wb while the final magnetic flux is 38 Wb. Also, the change in time is 0.34 seconds and the number of loops is 2. Therefore, the emf induced can be written as,
[tex]\varepsilon = \dfrac{-N \times \triangle \phi}{ \triangle t}[/tex]
[tex]\varepsilon = \dfrac{-(2) \times [38-(-58)]}{0.34}\\\\\varepsilon = -564.7\rm\ V[/tex]
Hence, the emf induced in the coil is -564.7 V.
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Amber is a
(a) metal
(b) rubber
(c) resin
(d) sugar
Answer:
c. Resin.
Explanation:
Amber is a resin.
more than one option this is hard
what does the word Cala stands for
Answer:
Caribbean and Latin America Region
Explanation:
One source error is __________, and one of its solutions is having a lie scale inserted into the assessment. a. social desirability bias b. deliberate deception c. response bias d. response set please select the best answer from the choices provided a b c d
One source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.]
What is the error?An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.
The discrepancy between the calculated value and the correct value is referred to as an "error" in statistics.
When a person is completely aware of what they are doing, they are engaging in deception. They are concealing the truth and making a deliberate decision to tell someone something that is false.
When describing a magic trick, such as a sleight of hand, the term deception can also be used.
When there are repetitive questions that ask the same questions over and over with different formats to check if the responses are constant over time, lie scales are utilized.
Hence one source error is deliberate deception and one of its solutions is having a lie scale inserted into the assessment.
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A student watches the tide change, and sees water waves pass the end of the dock
that follow the pattern shown below:
13)
The student counts the waves with a stopwatch, and determines that it takes 8.75
seconds for a single wave to go by. The wave frequency is ----
The frequency of the wave at the given period is 0.114 Hz. This frequency shows the number of revolution of the wave in a second.
What is frequency of a wave?The frequency of a wave is the number of revolutions of the wave per second.
Frequency of a wave is determined by taking the inverse of period of the wave.
The frequency of the wave at the given period is calculated as follows;
f = 1/T
Where;
f is the frequencyT is period of the wavef = 1/8.75
f = 0.114 Hz
Thus, the frequency of the wave at the given period is 0.114 Hz.
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If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then what is the impulse exerted by the force on the object? What is the momentum change of the object? What is the change in velocity for the object?
Answer:
orce = rate of change of momentum which is m a if the mass is constant
10 Newtons = change of momentum/0.10 second
so change of momentum = 1 kg m/s
by the way the change in speed would be 1/5 = .2 m/s
Explanation:
If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be 1 Ns.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then we have to find out what the impulse exerted by the force on the object.
P = force × time
= 10 × 0.1
= 1 Ns
Thus, If a 5-kg object experiences a 10-N force for a duration of 0. 10-second then the impulse exerted by the force on the object would be 1 Ns, and the change in the momentum would be 1 Ns.
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What is the average velocity of the fly between 0 and 15 seconds
Answer:
where is the displacement
[tex]v = \frac{s}{t} [/tex]
The average velocity of the fly between 0 and 15 seconds will be 10 m/sec.Velocity is the time-based component.
What is average velocity?
The average velocity is the ratio of the total distance traveled to the total time taken by the body. Its unit is m/sec.
From the given graph it is obsderved that the displacement from 0 to 15 seconds will be 150 m.
[tex]\rm V = \frac{D_2-d_1 }{t_2-t_1} \\\\ V = \frac{150}{15-0} \\\\ V= 10 \ m/sec[/tex]
Hence the average velocity of the fly between 0 and 15 seconds will be 10 m/sec.
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How can gravitational tugs from orbiting planets affect the motion of a star?.
Answer:
Gravitational tugs from orbiting planets don't affect the motion of a star. The star, being much larger than the planet, has a much smaller orbit. But it does move slightly. Explain how alien astronomers could deduce the existence of planets in our solar system by observing the Sun's motion.
A distant astronomical object (a quasar) is moving away from us at half the speed of light. what is the speed of the light we receive from this quasar?
For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar is mathematically given as c = 3x108 m/s
What is the speed of light?Generally, the equation for the is mathematically given as
The speed of light can be said to be measured to be approximately the value c = 3x108 m/s
.
In conclusion, An will not influence 3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to 3x108 m/s
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I will be giving the brainliest to whoever.What is the PERCENT efficiency if a computer is supplied with 500 J of energy and is able to convert 400 J to useful energy?
A. 0.8 %
B. 8 %
C. 80 %
D. 800 %
Two objects of the same mass travel in the same direction along a horizontal surface. Object X
has a speed of 5 ms
and object Y
has a speed of 2 ms
, as shown in the figure. After a period of time, object X
collides with object Y
.
Consider the situation in which the objects collide but do not stick together. Which of the following predictions is true about the center of mass of the two-object system immediately after the collision?
After the collision, object X will move at a speed of 2 m/s in its original direction while object Y will move at a speed of 5 m/s in its original direction.
Elastic collision of the two objectsWhen the two objects collide but do not stick together, the type of collision is elastic collision.
In elastic collision, both momentum and kinetic energy are conserved.
Final velocity of the two objects after collsionmu₁ + mu₂ = mv₁ + mv₂
5m + 2m = mv₁ + mv₂
m(5 + 2) = m(v₁ + v₂)
7 = v₁ + v₂ -------- (1)
Apply the concept of one direction velocity;
u₁ + v₁ = u₂ + v₂
5 + v₁ = 2 + v₂
v₂ = v₁ + 3 ------ (2)
Solve (1) and (2) together;
7 = v₁ + v₁ + 3
4 = 2v₁
v₁ = 2 m/s
v₂ = 2 + 3 = 5 m/s
Thus, after the collision, object X will move at a speed of 2 m/s in its original direction while object Y will move at a speed of 5 m/s in its original direction.
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