The vapor pressure of the solution of 1.48 m Al(NO₃)₃ at 45.0 °C is 71.93 torr.
This can be calculated using Raoult's law. The law states that the vapor pressure of a solution is inversely proportional to the mole fraction of the solvent (not the solute).
The following formula can be used to get the vapor pressure of a solution of 1.48 m Al(NO₃)₃ at 45.0 °C:
P = P° × Xsolvent
where P is the vapor pressure of the solution, Xsolvent is the solvent's molecular weight, and P° is the solvent's pure vapor pressure.
The solvent's mole fraction is equal to 1 because it is presumed that the solute has entirely broken down. In this instance, the solution's vapor pressure is the same as the pure solvent's, which is 71.93 torr at 45.0 °C.
Hence, the vapor pressure of the solution of 1.48 m Al(NO₃)₃ at 45.0 °C is 71.93 torr.
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To determine the melting point of ice, which procedure would best help measure the melting point temperature?
A - Mix ice with water until just before equilibrium is reached but some ice remains that is still melting.
B - Mix ice with water until equilibrium is reached but some ice remains that is still melting.
C - Mix ice with water until equilibrium is reached but some ice remains that is no longer melting.
D - Mix ice with water until just before equilibrium is reached but some ice remains that is no longer melting.
Answer:
Explanation:
C - Mix ice with water until equilibrium is reached but some ice remains that is no longer melting.
9. water draining from an abandoned coal mine is likely to have a. excess of hydrogen ions and a high ph c. excess hydrogen ions and a low ph b. excess hydroxide ions and a low ph d. excess of hydroxide ions and a high ph
The solution is excess hydrogen ions and a low ph.
It probably has a low pH and too many hydrogen ions. Acid mine drainage (AMD), which lowers the pH of water resources and makes dissolved metals easily available for uptake by benthic animals and fish, is a significant contributor to the entry of these contaminants into the human food chain. The term "acid mine drainage" refers to the runoff that results from water coming into touch with exposed sulfur-bearing minerals. These minerals react with the water and air to produce sulfuric acid and dissolved iron. Heavy metals like copper, lead, and mercury are dissolved by this acidic runoff, contaminating both groundwater and surface water. Mine drainage issues include tainted drinking water, hampered aquatic plant and animal development and reproduction, and the acid's corrosive effects on parts.
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Metal- Magnesium
Appearance of metal- ?
Reactant - cold water
Observation of reaction- ?
Cold water has a very modest interaction with very clean magnesium ribbon. Hydrogen bubbles start to appear on its surface after a while.
What happens when reactive metals react with cold water?Hydroxides are created when metals and cold water react. Oxides are produced when metals react with steam.Magnesium and oxygen interact to create light that is so intense that it temporarily renders you blind. Because so much heat is released during the reaction, magnesium burns so brightly. Magnesium provides two electrons to oxygen during this exothermic process, resulting in the formation of powdered magnesium oxide (MgO).When magnesium combines with water vapour, it can also produce hydrogen gas and magnesium hydroxide. Magnesium hydroxide and hydrogen are created when magnesium combines with hot water.what occurs if a heated piece of metal is dropped into room temperature water. The water will heat up while the metal cools over time. Both items' temperatures will eventually be equal.To learn more about bubbles refer to:
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to the best of your knowledge, classify each of the following as an element, compound, or mixture. explain how your everyday experiences influenced your response. a. silver coin b. air c. coffee d. soil
a. Silver coin - Element (Silver is a pure element and is not chemically combined with any other element in a silver coin)
b. Air - Mixture (Air is a mixture of gases, primarily nitrogen and oxygen, with trace amounts of other gases and particles)
c. Coffee - Mixture (Coffee is a mixture of various compounds such as water, caffeine, and organic compounds that give it its flavour and aroma)
d. Soil - Mixture (Soil is a mixture of various substances such as minerals, organic matter, water, and air)
My everyday experiences influenced my response because I have come across these examples in my daily life and have been taught about them in science classes. For example, I know that air is composed of different gases and particles, and that soil is made up of a mixture of substances, including minerals and organic matter. Similarly, I know that a silver coin is made of pure silver and that coffee is made of various compounds.
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A sheet of lead is 2.0 cm thick. What is the mass of the sheet of lead if it measures 1.0 m by 1.0 m and has a density of 1.42 g/mL
Answer:
Below
Explanation:
1 meter = 100 cm
Volume = 100 cm * 100 cm * 2 cm = 20 000 cm^3 = 20 000 ml
mass = volume * density
= 20 000 ml * 1.42 g/ ml = 28400 g ( or 28.4 kg)
The Kool-Aid company has hired you to modify the Kool-Aid solution to meet the needs of people with high diabetes. The original solution contains: 3 packs of Kool-Aid (6 g per pack), 1 gallon of water (3. 87 L of water). As a scientist, how would you modify the original Kool-Aid solution to better meet the needs of people with high diabetes. In your response, be sure to include all calculations and content specific vocabulary
As a scientist, I would recommend modifying the original Kool-Aid solution by reducing the amount of added sugar in the mix. The current recipe calls for 3 packs of Kool-Aid, each contains 6 grams of sugar.
To reduce the sugar content, we could reduce the number of packs of Kool-Aid used in the recipe or use a sugar-free or reduced-sugar version of the product. For example, if we used 1 pack of sugar-free Kool-Aid, the sugar content would be reduced to 0 grams. Or, if we used 2 packs of regular Kool-Aid, the sugar content would be reduced to 12 grams. Another option to consider would be to use a sugar substitute like Stevia or Erythritol which are low-calorie sweeteners and are safe for diabetics. It's also important to note that, as a scientist, it would be important to conduct taste tests with diabetic individuals to ensure that the modified recipe is still palatable and acceptable.
In summary, reducing the amount of sugar in the Kool-Aid mix or using a sugar substitute would be a way to modify the original Kool-Aid solution to better meet the needs of people with high diabetes.
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An increase in the biodiversity of an ecosystem leads to an increase in its productivity.
The increase in the diversity of species in an ecosystem definitely lead to an increase in the productivity from that ecosystem. Hence, the statement is true.
What is an ecosystem?An ecosystem is the regions in earth where a group of living things and their essential non living things reside. There are various kind of ecosystems such as aquatic systems, forests, deserts etc.
The biodiversity refers to the diverse species of plants , animals and all other kind of livings there. By raising the possibility that species would use complementary resources and by increasing the likelihood that a highly productive or efficient species is present in the population, increasing species diversity can impact ecosystem functions, such as production.
For instance, greater use of soil resources can boost ecosystem production when there is a large diversity of plants. Similarly, when diverse plants populate more dependent animal variants survives more.
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Answer:
A. True
Explanation:
Got it right on Edge 2023.
what volume of a 0.200 m solution of kbr is needed to precipitate 16.0 g of agbr from a solution containing 0.420 mol of agno3 .
To precipitate 16.0 g of AgBr from a solution containing 0.420 mol of Ag, 0.143 L of a solution containing 0.200 M KBr is required.
What's volume?"The amount of space an object or substance occupies" is the definition of volume, which is a scalar quantity. It is a measurement of an object's or substance's three-dimensional extent and is typically expressed in length-cubed units like cubic meters (m3), liters (L), or cubic centimeters (cm3).
The idea of stoichiometry can be used to figure out how much of a 0.200 M KBr solution is required to precipitate 16.0 g of AgBr from a solution containing 0.420 mol of AgNO3.AgNO3 + KBr = AgBr + KNO3
According to the balanced equation above, the reaction between AgNO3 and KBr is a one-to-one reaction, which indicates that the precipitated moles of AgNO3 are the same as the moles of AgBr.The amount of AgBr precipitated is also 0.420 mol, as the molecular weight of AgNO3 is 0.420 mol.Multiplying the number of moles by the molar mass of AgBr yields the precipitated mass of AgBr:Since AgBr has a mass of 16.0 g, the volume of KBr required is calculated by dividing the mass by the molarity and the number of moles in the solution:mass = moles x molar mass
= 0.420 mol x 247.8 g/mol
= 104 g
V = m / M x n
= 16 / (0.200 x 0.420)
= 0.143 L.
As a result, in order to precipitate 16.0 g of AgBr from a solution containing 0.420 mol of Ag, 0.143 L of a solution containing 0.200 M KBr is required.Learn more about volume:
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which of the following forces stabilize protein 3-dimensional structure? choice 1 of 6:ionic interactions choice 2 of 6:h-bonding choice 3 of 6:van der waals forces choice 4 of 6:metal ions choice 5 of 6:disulfide bonds choice 6 of 6:all of the above
All of the above forces (ionic interactions, H-bonding, van der Waals forces, metal ions, and disulfide bonds) play a role in stabilizing the 3-dimensional structure of proteins. Thus, the correct answer is Choice 6 of 6: all of the above.
Ionic interactions occur between positively and negatively charged amino acid residues, which helps to maintain the overall charge balance of the protein. H-bonding involves the sharing of electrons between atoms, and helps to hold the protein's secondary and tertiary structures in place. Van der Waals forces are relatively weak interactions between atoms, but they can contribute to the stability of the protein by helping to hold the atoms in place. Metal ions can also play a role in stabilizing the protein by binding to specific amino acid residues. Disulfide bonds form between cysteine residues and help to hold the protein's tertiary structure in place.
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Suppose you are given a Stock Solution of 15.406 M hydrochloric acid. What volume of water must you add have ready to add your acid to (in mL) to prepare a solution with a hydrochloric acid molar concentration of 3.361 M and a volume of 372.510 mL? NOTE: When typing your answer below, round your answer to 3 decimal places. Show you work for part marks. Do not forget to upload your steps. Keep units according to the givens in the question.
M1V1 = M2V2
where M1 and V1 are the molar concentration and volume of the stock solution, and M2 and V2 are the molar concentration and volume of the final solution. We can use this formula to find the volume of water that we need to add to the stock solution to prepare the final solution.
Plugging in the given values, we have:
15.406 M x V1 = 3.361 M x 372.510 mL
To solve for V1, we can divide both sides of the equation by 15.406 M:
V1 = 3.361 M x 372.510 mL / 15.406 M
V1 = 24.227 mL
Therefore, we need to add 24.227 mL of water to the stock solution of 15.406 M hydrochloric acid to prepare a solution with a hydrochloric acid molar concentration of 3.361 M and a volume of 372.510 mL.
If you were to perform this reaction and actually produced 10.86 g of H2O, what would be your percent yield? (Your theoretical/expected yield is the amount produced from your limiting reactant.)
42.22 %
55.43 %
99.99 %
32.86 %
Other:
If the reaction were performed and actually produced 10.86 g of H₂O, the percent yield would be 52.54%.
What is the percent yield of a reaction?The percent yield of a reaction is the ratio of the actual yield of a reaction and the theoretical or expected yield of a reaction as obtained from the equation of the reaction expressed as a percentage.
Mathematically:
Percent yield = actual yield / theoretical yield * 100%The theoretical yield of the reaction from the equation of the reaction given below is 20.67 g
Equation of reaction:
Ca(OH)₂ ---> CaO + H₂O
Percent yield = 10.86/20.67 * 100%
Percent yield = 52.54%
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Complete question:
If 85.0 grams of Ca(OH)2 are used in this reaction, how many grams of water would be produced?
If you were to perform this reaction and actually produced 10.86 g of H2O, what would be your percent yield? (Your theoretical/expected yield is the amount produced from your limiting reactant.)
molybdenum can form a wide series of halide compounds, including four different fluoride compounds. the percent by mass of molybdenum in the four compounds is 63.0%, 63.0 %, 56.0%, 56.0 %, 50.0%, 50.0 %, and 46.0%. 46.0 %. determine the formula and name for each of the four different molybdenum fluorides.
The formula and the name for each of the four different molybdenum fluorides are :
1) Formula of the compound = MoF₃ = Molybdenum trifluoride
2. Formula of the compound = MoF₄ = Molybdenum tetrafluoride
3. Formula of the compound = MoF₅ = Molybdenum pentafluoride
4. Formula of the compound = MoF₆ = Molybdenum hexafluoride
1) Molybdenum (Mo) = 63.0%
Fluorine (F) = 100 – 63 = 37%
Moles, Mo = 63.0 / 96 = 0.656
Moles, F = 37 / 19 = 1.947
Divide by the smallest
Mo = 0.656 / 0.656 = 1
F = 1.947 / 0.656 = 3
The formula is MoF₃ = Molybdenum trifluoride
2) Molybdenum (Mo) = 56.0%,
Fluorine (F) = 100 – 56 = 44%
Moles are :
Mo = 56 / 96 = 0.583
F = 44 / 19 = 2.316
Divide by the smallest
Mo = 0.583 / 0.583 = 1
F = 2.316 / 0.583 = 4
The compound is MoF₄ = Molybdenum tetrafluoride
3) Molybdenum (Mo) = 50.0%,
Fluorine (F) = 100 – 50 = 50%
F = 50%
Mo = 50 / 96 = 0.520
F = 50 / 19 = 2.632
Divide by the smallest
Mo = 0.520 / 0.520 = 1
F = 2.632 / 0.520 = 5
The compound is MoF₅ = Molybdenum pentafluoride
4) Mo = 46%
F = 54%
Mo = 46 / 96 = 0.479
F = 54 / 19 = 2.842
Divide by the smallest
Mo = 0.479 / 0.479 = 1
F = 2.842 / 0.479 = 6
Formula of compound = MoF₆ = Molybdenum hexafluoride.
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10.000 g of boron (b) combines with hydrogen to form 11.554 g of a pure compound. what is the empirical formula of this compound?
The empirical formula of the compound is B₃H₅
According to the law of conservation of mass, "matter in a closed system is neither created nor destroyed by physical transformations or chemical reactions but changes from one form to the other"
This implies that, sum of masses of the reactants = sum of masses of the product
Therefore, according to the question:
10g of Boron + x grams of Hydrogen = 11.55g of the product
∴ Mass of hydrogen = 11.55 - 10.00 = 1.55g
We know that,
Molar mass of Boron = 10.811g
Molar mass of Hydrogen = 1.00784g
Number of moles of Boron
= (mass of Boron)/(molar mass of Boron)
= 10/10.811
= 0.9249 mol
Number of moles of Hydrogen
= (mass of Hydrogen)/(molar mass of Hydrogen)
= 1.55/1.00784
=1.5379mols
Thus, 0.9249 mole of Boron will combine with 1.5379mole of Hydrogen
Now, by dividing both sides of the mole by 0.9249, we get
1 mole of Boron combines with 1.66266 mole of Hydrogen
converting 1.66266 in fractions is approximately 5/3
which implies, 1 mole of Boron combines with 5/3 moles of Hydrogen
Now, by multiplying both sides by 3 we get
3 moles of Boron will combine with 5 moles of Hydrogen
∴ Empirical formula of the compound is B₃H₅
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a beaker contains 145.675 ml of a saline solution. if 24.2 ml of the saline solution are removed from the beaker, what volume of solution remains?
a beaker contains 145.675 ml of a saline solution. if 24.2 ml of the saline solution are removed from the beaker, The volume of solution remains is 121.5 ml.
Water and sodium chloride are combined to make saline. It can be used in medicine for a variety of purposes, such as cleaning wounds, removing and storing contact lenses, and treating dry eyes. As the saline solution is liquid. and no other solvents is added.The value of the solution remaining in the beaker can be calculate by simply substrating removed solution value from initial value
volume withdrawn from the flask substrate by total volume
= 145.675 ml - 24. 2 ml
= 121.475 ml
= 121.5 ml
So, the solution in the beaker is 121.5 ml
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The volume of the solution remained in the beaker after removing 24.2 ml of the saline solution is 121.5 ml.
A Saline solution is said to be a mixture of sodium chloride and water. This solution has a number of uses in medicine including cleaning wounds, removal and storage of contact lenses and help with dry eyes. It is used to treat dehydration by injecting the solution through vein.
A beaker contains 145.675 ml of a saline solution. if 24.2 ml of the saline solution are removed from the beaker. To find the remaining solution in the beaker we have to substract the total solution that was present in the beaker with the amount of the solution that is removed from the beaker.
Remaining volume of the solution = 145.675 ml - 24.2 ml
= 121.5 ml
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