Answer:
The standard free energy of formation, ΔGf°, of N2 at 25 °C and 1 bar is -16.5 kJ/mol. This means that when one mole of N2 is formed from its constituent elements (N2 in the gas phase at 1 bar and 25 °C), there is a release of 16.5 kJ of free energy. The negative sign indicates that the reaction is exothermic, meaning that it releases heat.
The standard enthalpy of formation of all elements in their standard states are assumed to be zero. The standard free energy of formation, ΔGf°, of N₂ at 25 °C and 1 bar is -16.5 kJ/mol.
The standard enthalpy of formation of a compound is defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements.
When one mole of N₂ is formed from its constituent elements (N₂ in the gas phase at 1 bar and 25 °C), there is a release of 16.5 kJ of free energy.
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How many moles of MgS are in 1.00g MgS?
Answer:
24.31 g/mol.
Explanation:
moles =mass/molar mass
n=w/m
Imagine that humans achieve interstellar travel and are able to move from solar system to
solar system. What would change about the stars for these space travelers?
A: absolute magnitude
B:apparent magnitude
C:absorption spectrum
D:relative electromagnetism
Absolute magnitude, on the other hand, is a measure of how bright a star would appear if it were located at a standard distance of 10 parsecs (32.6 light-years) away from Earth.
What is Magnitude?
Magnitude is a measure of the brightness of a celestial object, such as a star, planet, or galaxy. It is based on the amount of light that is emitted by the object and is typically expressed using a numerical scale. The lower the magnitude value, the brighter the object appears.
Apparent magnitude is a measure of how bright an object appears to an observer on Earth, while absolute magnitude is a measure of how bright an object would appear if it were located at a standard distance of 10 parsecs (32.6 light-years) away from Earth.
Apparent magnitude is a measure of how bright a star appears to an observer on Earth. It is determined by the amount of light that reaches Earth from the star, as well as the distance between the star and Earth. As humans travel away from our solar system and to other solar systems, the distance between them and the stars will change, which will affect how bright the stars appear to the travelers. As they move closer to a star, its apparent magnitude will increase, and as they move away, its apparent magnitude will decrease.
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If a student had 28 moles of solid carbon would that be enough to produce 15 moles of C2H6
No, 28 moles of solid carbon would not be enough to produce 15 moles of [tex]C_2H_6[/tex] (Ethane).
This is because the reaction requires more than 1 mole of carbon to produce 1 mole of [tex]C_2H_6[/tex]. The mole ratio of [tex]C_2H_6[/tex]:C is 2:1, so 28 moles of carbon would only be enough to produce 14 moles of [tex]C_2H_6[/tex].A chemical compound having the molecular formula [tex]C_2H_6[/tex], ethane is an organic substance. Ethane is an odourless, colourless gas at ordinary pressure and temperature. Ethane is separated from natural gas on an industrial scale, and it is produced as a by-product of the petrochemical process used to refine crude oil. Its primary usage is as a feedstock for the creation of ethylene.The ethane moiety is known as an ethyl group, and it can be used to create related compounds by swapping out a hydrogen atom for another functional group.
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what is the answers to this someone pls help
Answer:
The nuclide formed by the β decay of 26Al is 26Mg.
Mark my answer as brainliest! this was a difficult one
When a protonated epoxide is attacked by water, the nucleophile attacks from the ___________ in an __________ process.
When a protonated epoxide is attacked by water, the nucleophile attacks from the "top" or "front" of the epoxide ring in an "S_N2" substitution nucleophilic bimolecular process.
What is protonated epoxide ?
A protonated epoxide is a molecule that contains an epoxide ring (a three-membered ring consisting of two carbon atoms and one oxygen atom) that has been protonated, or had a hydrogen ion (H+) added to it.
The protonation of an epoxide ring can occur in the presence of an acidic medium, such as a strong acid like sulfuric acid (H2SO4) or hydrochloric acid (HCl).
In acidic conditions, the lone pair of electrons on the oxygen atom of the epoxide ring can interact with the positively charged hydrogen ion, resulting in the formation of a protonated epoxide.
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What must the atoms of products equal in a chemical equation?
O atoms in molecules
O electrons in atoms
O protons in atoms
O atoms of reactants
20pts
Answer:
D
Explanation:
The temperature of an object increases by 38.1 °C when it absorbs 3647 J of heat. Calculate the heat capacity of the object.
The heat capacity of an object is defined as the amount of heat required to raise its temperature by 1 degree Celsius (or 1 Kelvin). It is denoted by the symbol "C" and has units of J/°C (Joules per degree Celsius) or J/K (Joules per Kelvin).
We can use the formula for heat capacity to calculate its value for the object:
[tex]C = \dfrac{Q}{\Delta T}[/tex]where:
Q is the amount of heat absorbed by the object andΔT is the change in temperature of the object.Substituting the given values, we get:
[tex]C = \dfrac{3647 \: J }{ 38.1\: ^{\circ}C}[/tex]Note that the units of temperature must match (either Celsius or Kelvin) in order for the calculation to be correct. Since the given change in temperature is in Celsius, we can use Celsius for the units of heat capacity as well.
Dividing, we get:
[tex]C = 95.8 \: J/^{\circ}C[/tex]Therefore, the heat capacity of the object is 95.8 J/°C. This means that it requires 95.8 Joules of heat to raise the temperature of the object by 1 degree Celsius (or Kelvin).
[tex]\rule{200pt}{5pt}[/tex]
42 grams of nitrogen gas react with
13 grams of hydrogen gas. What is the
limiting reactant and how many grams of
ammonia will be produced?
N2 + 3H22NH3
A) H2; 74 grams NH3 produced
B) H2; 4.3 grams NH3 produced
C) N2; 3.0 grams NH3 produced
D) N2; 51 grams NH3 produced
Answer:
d
Explanation:
Nitrogen is the limiting reactant.
42 g N2x (1mole N2/28 g N2) X (2 moles NH3/ 1mole N2) X (17 grams NH3/1mole NH3) = 51 g
13 g H2 x (1 mole H2/2 g H2) X (2 moles NH3/3moles H2) X (17 g NH3/1mole NH3) =73.66g
since 51 is smaller than 73.66 and it started with N2 that is why N2 is the limiting reactant)
What's absolute zero?
A. The temperature at which all liquids freeze
B. The temperature at which water freezes
C. The coldest temperature ever recorded in nature on Earth
D. The temperature at which all molecular motion is stopped
Answer:
D. The temperature at which all molecular motion is stopped.Explanation:Absolute zero is the theoretical temperature at which all matter would have zero thermal energy and all molecular motion would stop. This temperature is equal to -273.15 degrees Celsius or -459.67 degrees Fahrenheit. It is the lowest possible temperature in the universe and cannot be reached in practice, as it is impossible to completely eliminate all thermal energy from matter.
What type of spectrum does this represent?
A. Absorption Spectrum
B. Continuous Spectrum
C. Emission Spectrum
Answer:
Continuous Spectrum, a spectrum that contains all wavelengths of light within a specific range, with no gaps or lines. It is produced by a hot, dense object such as a star or a light bulb.
Emission Spectrum, a spectrum that contains bright lines or bands of specific wavelengths, with dark spaces in between. It is produced when light is emitted from a hot gas or plasma, and the specific wavelengths of the lines or bands depend on the elements present in the gas.
Absorption Spectrum, a spectrum that contains dark lines or bands of specific wavelengths, with bright spaces in between. It is produced when a continuous spectrum passes through a cool gas, and the specific wavelengths of the lines or bands depend on the elements present in the gas.
A 25.0 kg iron weight lifting plate has a volume of 3180 cm3 . what is the density of the iron plate in g/cm3?
Answer:
The density of a substance is given by dividing the mass by the volume.
The S.I units of density are kg/m³, but can be measured by other units such as g/cm³
The mass of the iron is 29 kg or 29000 g
Therefore; Density = 29000 g/ 3680 cm³
= 7.880 g/cm³
Hence, the density of the iron plate is 7.880 g/cm³
Explanation:
On a distance time graph of an objects motion distance is usually what
How many mL of 2.25M H2SO4 are needed to react completely with 69.9g BaO2
Answer:
4 millllllermeeters jb
What physical property of matter can be measured using the triple beam balance?
A
volume
B
mass
C
height
D
length
SUBMIT ANSWER
Answer:
B) Mass- I searched it up
When limestone (which is principally CaCO3) is heated, carbon dioxide and quicklime (CaO) are produced by the reaction CaCO3(s) →∆ CaO(s) + CO2(g) . If 16.3 g of CO2 was produced from the ther- mal decomposition of 41.48 g of CaCO3, what is the percentage yield of the reaction?
When 25 mL of 1.0M H₂SO4 is added to 50 mL of 1.0 M NaOH at 25°C in a calorimeter,
the temperature of the aqueous solution increases to 33.9 °C. Assuming that the specific
heat of the solution is 4.18 J/g°C, that its density is 1.00/mL, and that the calorimeter
itself absorbs a negligible amount of heat, calculate the amount of heat absorbed for the
reaction.
Answer: The amount of heat absorbed for the reaction of 25 mL of 1.0 M H₂SO4 and 50 mL of 1.0 M NaOH, resulting in a temperature increase from 25°C to 33.9°C, is 10.14 kJ.
Explanation:
The volume of a gas is 200 mL at 350.0 kPa pressure. What will the volume be when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.
The volume of the gas will be 560 mL when the pressure is reduced to 125.0 kPa, assuming the temperature remains constant.
What will be the volume of the gas when the pressure is reduced to 125.0 kPa?Boyle's law simply states that "the volume of any given quantity of gas is inversely proportional to its pressure as long as temperature remains constant.
Boyle's law is expressed as;
P₁V₁ = P₂V₂
Where P₁ is Initial Pressure, V₁ is Initial volume, P₂ is Final Pressure and V₂ is Final volume.
Substituting the given values, we get:
P₁ = 350.0 kPa (initial pressure)
V₁ = 200 mL (initial volume)
P₂ = 125.0 kPa (final pressure)
V₂ = ?
Solving for V₂, we get:
V₂ = ( P₁ × V₁ ) / P₂
V₂ = (350.0 kPa × 200 mL) / 125.0 kPa
V₂ = 560 mL
Therefore, the final volume of the gas is 560 mL.
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what percentage of air is oxygen?
Answer:
21% percent
Explanation:
Air has small amounts of other gases, such as carbon dioxide,neon, and hydrogen. Oxygen shares some parts of air basically. The highest percentage of oxygen we can breathe is approximately 60℅
calculate the mole fraction of HCl in a 9.8% (by mass) aqueous solution. the density of the solution is 1.03 g/mL
The mole fraction of HCl in the given solution is 0.051.
What is the mole fraction of the HCL?To calculate the mole fraction of HCl in the given solution, we need to first find the mass of HCl and water present in the solution.
Let's assume we have 100 g of the solution, so 9.8 g of it is HCl, and 90.2 g is water.
Next, we need to find the moles of HCl present in the solution.
To do this, we divide the mass of HCl by its molar mass.
The molar mass of HCl is 36.46 g/mol (1.01 g/mol for hydrogen + 35.45 g/mol for chlorine).
moles of HCl = 9.8 g / 36.46 g/mol = 0.269 mol
The moles of water can be calculated using its molar mass which is 18.015 g/mol.
moles of water = 90.2 g / 18.015 g/mol = 5.005 mol
The total number of moles in the solution is the sum of the moles of HCl and water.
total moles = 0.269 mol + 5.005 mol = 5.274 mol
The mole fraction of HCl can now be calculated by dividing the moles of HCl by the total number of moles.
mole fraction of HCl = 0.269 mol / 5.274 mol = 0.051
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L 4.4.2 Test (CST): Electricity and Energy Resources
Question 11 of 25
What happens to the field lines of two positive charges as the charges are
brought close together?
A. The field lines are attracted to the other charge.
B. The field lines cross together.
C. It would depend on what kind of positive charges they are.
D. The field lines bend away from the other charge.
SUBMIT
Answer:
D
Explanation:
because replusive force is much more
which statement describes density? Check all that apply
Density is a chemical property of an object.
The density of an object is constant.
Density is a derived unit of measure.
Density is the sum of the mass and volume of an object.
The density of an object determines whether it will sink or float.
Answer:
The density of an object is constant.
Density is a derived unit of measure.
The density of an object determines whether it will sink or float.
What happens to the solubility of gases in water as pressure increases?
Question 9 options:
solubility increases so less solute dissolves
solubility decreases so more solute dissolves
solubility increases so more solute dissolves
solubility decreases so less solute dissolves
Answer: Solubility increases so more solute dissolves
Explanation:
The solubility is a measure of the concentration of the dissolved gas particles in the liquid and is a function of the gas pressure. As you increase the pressure of a gas, the collision frequency increases and thus the solubility goes up, as you decrease the pressure, the solubility goes down.
Zinc reacts with hydrochloric acid according to the reaction equation
Zn(s) + 2 HCl(aq) → ZnCl₂(aq) + H₂(g)
How many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: ___ mL
Answer:
many milliliters of 1.50 M HCl(aq) are required to react with 5.05 g Zn(s)?
volume: 16 mL
First, we need to calculate the number of moles of Zn:
m(Zn) = 5.05 g
M(Zn) = 65.38 g/mol (molar mass of Zn)
n(Zn) = m(Zn) / M(Zn) = 5.05 g / 65.38 g/mol = 0.0773 mol
According to the balanced chemical equation, 1 mole of Zn reacts with 2 moles of HCl. Therefore, the number of moles of HCl needed is:
n(HCl) = 2 × n(Zn) = 2 × 0.0773 mol = 0.1546 mol
Now we can use the molarity of the HCl solution to calculate the volume needed:
M(HCl) = 1.50 mol/L
n(HCl) = V(HCl) × M(HCl)
V(HCl) = n(HCl) / M(HCl) = 0.1546 mol / 1.50 mol/L = 0.103 L = 103 mL
Therefore, we need 103 mL of 1.50 M HCl(aq) to react with 5.05 g Zn(s).
The pressure of compressed air that occupies 2 L is 30.0 atm. What will be the new volume of the gas if the pressure is reduced to 10.0 atm if the temperature is not allowed to change? Ty in advance!
Answer:
To solve this problem, we can use the Boyle's Law equation, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law: P1V1 = P2V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.
Using the given values:
P1 = 30.0 atm
V1 = 2 L
P2 = 10.0 atm
Substituting these values into the Boyle's Law equation, we get:
30.0 atm x 2 L = 10.0 atm x V2
Simplifying and solving for V2, we get:
V2 = (30.0 atm x 2 L) / 10.0 atm
V2 = 6 L
Therefore, the new volume of the gas will be 6 L if the pressure is reduced to 10.0 atm, assuming the temperature remains constant.
I Hope This Helps!
A buffer solution is made using weak acid, HA, with a pKa of 6.98. If the ratio of [A-] to [HA] is 1.0 x 10^3, what is the pH of the buffer
What does conserving mass mean in a chemical equation? Responses There is equal number of each type of atom on the reactant and product side. There is equal number of each type of atom on the reactant and product side. There are more of each type of atom on the product side than on the reactant side. There are more of each type of atom on the reactant side than on the product side. There is an unequal number of each type of atom on both sides of the equation.
Calculate the decrease in temperature when 6.0 L at 21.0 °C is compressed to 3.0 L.
The decrease in temperature is 147.075 K. The SI unit for temperature is the kelvin (K), but it can also be measured in degrees Celsius (°C) or Fahrenheit (°F).
What is Temperature?
Temperature is a physical property that measures the degree of hotness or coldness of an object or system, as compared to a standard reference point. It is a measure of the average kinetic energy of the particles (atoms or molecules) in a substance or system.
To solve this problem, we need to use the Charles's law equation which states:
V1/T1 = V2/T2
where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
We can rearrange the equation to solve for T2:
T2 = (V2/T2) x T1
First, we need to convert the initial temperature from Celsius to Kelvin by adding 273.15:
T1 = 21.0°C + 273.15 = 294.15 K
The initial volume (V1) is 6.0 L, and the final volume (V2) is 3.0 L. Substituting these values into the equation, we get:
(6.0 L/294.15 K) = (3.0 L/T2)
Solving for T2, we get:
T2 = (3.0 L x 294.15 K) / 6.0 L
T2 = 147.075 K
Finally, we can find the decrease in temperature by subtracting the final temperature (T2) from the initial temperature (T1):
ΔT = T1 - T2
ΔT = 294.15 K - 147.075 K
ΔT = 147.075 K
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What is the percent of O in
Ca(С2H302)2?
(Ca = 40.08 g/mol, C = 12.01 g/mol,
H= 1.01 g/mol, O = 16.00 g/mol)
40.5%
Explanation:
Ca×1 = 40
C×4 = 48
H×6 = 6
O×4 = 64
64÷158×100% = 40.5%
How many liters of a 3.58 MK2SO4 solution are needed to provide 85.1 g of K2SO4 (molar mass 174.01g/mol)? Recall that M is equivalent to mol/L.
Explanation:
Consider the reaction for the formation of aluminum oxide from aluminum and oxygen.
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
Express the enthalpy of the following reaction, Δ2,
in terms of Δ1.
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2
Express the enthalpy of the following reaction, Δ3,
in terms of Δ1.
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Express the enthalpy of the following reaction, Δ4,
in terms of Δ1.
2Al(s)+32O2(g)⟶Al2O3(s)Δ4
To solve for Δ2, we need to reverse the reaction and change the sign of Δ1:
2Al2O3(s)⟶4Al(s)+3O2(g)Δ2 = -Δ1
Therefore, Δ2 = -Δ1.
To solve for Δ3, we need to add the reactions for the formation of two moles of Al2O3 from aluminum and oxygen:
4Al(s)+3O2(g)⟶2Al2O3(s)Δ1
2Al2O3(s)⟶4Al(s)+3O2(g)Δ3
Adding these equations gives:
12Al(s)+9O2(g)⟶6Al2O3(s)Δ3
Therefore, Δ3 = 2Δ1.
To solve for Δ4, we need to divide the reaction for the formation of two moles of Al2O3 by two:
2Al(s)+3O2(g)⟶Al2O3(s)Δ1/2
Multiplying this equation by 16 gives:
32Al(s)+48O2(g)⟶16Al2O3(s)8Δ1/2
We can then cancel out the formation of 14 moles of Al2O3:
2Al(s)+32O2(g)⟶Al2O3(s)Δ4 = 8Δ1/2 - 7Δ1
Therefore, Δ4 = 8Δ1/2 - 7Δ1.