The volume of a right cone is 2325
�
π units
3
3
. If its radius measures 15 units, find its height.

The solution for the given expression is  7 + 5/12

First we need to write the expression, using fractions, we will get:

(5 + 6/8) + (4 + 4/15) - (2 + 6/10)

We can group like terms, and we will get:

(5 + 6/8) + (4 + 4/15) - (2 + 6/10) = (5 + 4 -2) + (6/8 + 4/15 - 6/10)

Now just simplify that to get.

(5 + 4 -2) + (6/8 + 4/15 - 6/10) =  7 + 3/4 + 4/15 - 3/5

                                                =  7 + 3/4 + 4/15 - 9/15

                                                = 7 + 3/4 - 5/15

                                                = 7 + 9/12 - 4/12

                                                 = 7 + 5/12

That is the answer.

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Answer:

D

Step-by-step explanation:

To reach this, you would divide both by half.

8.5 ÷ 2= 4.25

11 ÷ 2= 5.5

therefore, D

The value of x in the proportion is -9.

To solve the proportion [(3/4) is to -6] is to [(3/4) is to 3] is to x = [(3/4) is to -9], we can cross-multiply and solve for x.

Starting with the left side of the proportion:

[(3/4) is to -6] is to [(3/4) is to 3]

Cross-multiplying:

(3/4) * 3 = (3/4) * (-6)

Simplifying:

9/4 = -18/4

Now, moving to the right side of the proportion:

[(3/4) is to -9]

Cross-multiplying:

x * (3/4) = (3/4) * (-9)

Simplifying:

(3/4) * x = -27/4

To solve for x, we can multiply both sides of the equation by the reciprocal of (3/4), which is 4/3:

(4/3) * [(3/4) * x] = (4/3) * (-27/4)

Simplifying:

x = -9

Therefore, the value of x in the proportion is -9.

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Answer:

x = 71

Step-by-step explanation:

using the rule of logarithms

[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]

then

[tex]log_{4}[/tex] (x - 7) = 3 , then

x - 7 = 4³ = 64 ( add 7 to both sides )

x = 71

The value of angle C is calculated by applying cosine rule as  50.67 ⁰.

The value of angle C is calculated by applying cosine rule as shown below;

c² = a² + b² - 2ab cosC

The given parameters in the diagram;

length a = 22

length b = 18

c = 20

The value of angle C is calculated as;

20² = 22² + 18² - (2 x 22 x 18) cos C

792 cos C = 502

cos C = 502/792

cos C = 0.6334

C = arc cos (0.6334)

C = 50.67 ⁰

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The non-linear graph of the function y = -(x - 1)² + 1. is given by the image presented at the end of the answer.

We have to look at the graph of the function relative to the x-axis, as follows:

The function has a maximum point at (1,1), meaning that:

Considering the end behavior of the function, that it goes to negative infinity at both tails of the graph, a function that satisfies these features is given as follows:

y = -(x - 1)² + 1.

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Answer:

[tex]q=4, x=-1[/tex]

Step-by-step explanation:

The given equation is:

[tex]2(3+x)=3q-3+5x---(1)[/tex]

Since [tex]x=q-5[/tex] is a solution of the equation above, so substitute x=q-5 into (1) as follows:

[tex]2(3+q-5)=3q-3+5(q-5)\\2(q-2)=3q-3+5q-25\\2(q-2)=8q-28\\q-2=4q-14\\4q-q=-2+14\\3q=12\\q=4[/tex]

Then, it follows:

[tex]x=q-5\\\therefore x=4-5=-1[/tex]

A. A graph of the function is shown in the image below.

B. The illumination in foot-candles that the object receives at a distance of 20-feet from the light source is

C. In the context of the problem, a meaningful domain is {x | x ≤ 0} and a meaningful range is {y | y ≥ 0}.

In this exercise, we would plot the illumination on the y-axis (y-coordinates) of a graph while the square of the distance would be plotted on the x-axis (x-coordinate) of a graph on a coordinate plane.

Part B.

The illumination in foot-candles that this object would receive at a distance of 20-feet from the light source can be calculated by substituting the value of d, which is 20 feet into the function as follows;

I(d) = 4500/d²

I(20) = 4500/20²

I(20) = 4500/400

I(20) = 11.25 foot-candles.

Part C.

By critically observing the graph shown in the image attached below, we can reasonably and logically deduce the following domain and range:

Domain = [-∞, 0] ∪ [0, ∞] or {x | x ≤ 0}.

Range = [0, ∞] or {y | y ≥ 0}

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Answer:

  C.  1000/x + 5000/(2x -10)

Step-by-step explanation:

You want the total time a climber spent when he climbed 1000 feet at x feet per hour, and 5000 more feet at (2x -10) feet per hour.

The relation between time, speed, and distance is ...

  time = distance / speed

The total time is the sum of the times for the two distances.

The time for 1000 ft at x feet per hour is ...

  time 1 = 1000/x

The rate for the second part of the climb was 10 ft per hour less than twice the first rate, so was ...

  2x -10

Then the time for 5000 ft at this rate is ...

  time 2 = 5000/(2x -10)

The total time spent climbing was ...

  total = time 1 + time 2

  total = 1000/x + 5000/(2x -10) . . . . . . matches choice C

__

Additional comment

The relation between speed, time, and distance is usually seen as ...

  speed = miles per hour

As a fraction, this is ...

  speed = distance / time

Above, we rearranged this to ...

  time = distance / speed

It's just another form of the relationship ...

  distance = speed × time

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The choice of measure depends on the characteristics of the data and the purpose of the analysis.

The measure commonly used to describe the center of the data is the arithmetic mean or average. The arithmetic mean is calculated by summing all the data points and dividing the sum by the total number of data points. It provides a representative value that balances the contributions of all the data points.

Another measure of center is the median, which represents the middle value when the data is arranged in ascending or descending order. Unlike the mean, the median is not affected by extreme values or outliers, making it a robust measure of central tendency.

Additionally, there is the mode, which represents the most frequently occurring value in the dataset. It can be useful in cases where identifying the most common observation is important.

Each measure has its strengths and limitations, and researchers need to consider the nature of the data and the research question at hand to determine the most appropriate measure of center

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Answer:

B: 2/9

Step-by-step explanation:

There are a total of 9 bills in Scott's pocket, and he has 2 five dollar bills.

This means that the probability of pulling out a 5 dollar bill is 2/9.

Then you can state that angle DEF is congruent to angle GHJ.

The postulate or theorem that allows you to state that angle DEF is congruent to angle GHJ is the Angle-Angle (AA) Postulate.

This postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the third pair of angles must also be congruent.

In this case, if you have two triangles, one with angles DEF and the other with angles GHJ, and

you know that angle D is congruent to angle G and angle E is congruent to angle H, then by the AA Postulate, you can conclude that angle F is congruent to angle J.

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Answer:

The area of a leaf is obtained by using a graph paper. A graph paper has small squares of area 1 mm 2 each. The area of the leaf will be equal to the number of squares it covers on the graph paper.

Step-by-step explanation:

The measure of BC is 48x - 168.

In the given diagram of triangle BCD, we are told that E is the midpoint of BD and F is the midpoint of CD. Let's denote the measure of BC as y.

Since E is the midpoint of BD, we can say that BE = ED. Similarly, F is the midpoint of CD, so CF = FD.

Using the information given, we can write the equation EF = -9x + 82. Since F is the midpoint of CD, we can substitute FD for EF, so FD = -9x + 82.

Also, we know that BC = 80 - 6x.

In triangle BCD, we can write the equation BC = BE + EF + FD.

Substituting the given values, we have:

80 - 6x = (BE) + (-9x + 82) + (-9x + 82).

Simplifying the equation:

80 - 6x = BE - 9x + 82 - 9x + 82.

Combining like terms:

80 - 6x = BE - 18x + 164.

Moving the variables to one side and constants to the other side:

6x - BE + 18x = 164 - 80.

Combining like terms:

24x - BE = 84.

Rearranging the equation:

BE = 24x - 84.

Since E is the midpoint of BD, we can write:

BE = BD/2.

Substituting the value of BE:

BD/2 = 24x - 84.

Simplifying the equation:

BD = 48x - 168.

We are required to find the measure of BC, which is y. From the equation BC = BD, we have:

y = 48x - 168.

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y = 6x + 2 is the function which Adam charges a rate of $6 per hour and an additional fee of $2 for the bus fare.

The linear function in the form y = mx + b represents the situation where y represents the cost of the babysitting job

x represents the number of hours, "m" represents the hourly rate, and "b" represents the additional fee (bus fare).

y = 3x + 2 represents an hourly rate of 3 and an additional fee of 2.

y = 3x + 1 represents an hourly rate of 3 and an additional fee of 1.

y = 6x + 2 represents an hourly rate of 6 and an additional fee of 2.

y = -6x + 2 represents a negative hourly rate of -6 and an additional fee of 2.

Hence, y = 6x + 2 is the which Adam charges a rate of $6 per hour and an additional fee of $2 for the bus fare.

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Answer:

Step-by-step explanation:

median is 37 mode is 20

The angle the vector v, that has components of 9,6 makes with the x- axis is 33.7°

The angle of a vector with x and y components (x,y) is given by

Ф = tan⁻¹(y/x)

Given that vector v has components of 9,6. To determine the angle, Ф, in degrees , that vector v makes with the x-axis, we proceed as follows.

We know that the components of the vector are (9,6) which means that

So, we have that

So, substituting the values of the variables into the equation, we have that

Ф = tan⁻¹(y/x)

Ф = tan⁻¹(6/9)

Ф = tan⁻¹(2/3)

Ф = tan⁻¹(0.6667)

Ф = 33.69°

Ф ≅ 33.7°

So, the angle is 33.7°

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Angle EFG is an angle with a measure of 42 degrees is drawn below.

Given that, angle EFG= 42 degrees.

Angle EFG is an angle with a measure of 42 degrees. To draw angle EFG, first draw a line segment and mark two points on the line segment. Label the two points E and F. Then, using a protractor, measure out an angle with a measure of 42 degrees from the line segment EF, starting from point E. Finally, mark the end of the angle as point G.

Therefore, angle EFG is an angle with a measure of 42 degrees is drawn below.

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The correct comparison symbol from the drop-down box is,

⇒ 0.67 = 0.670

Since, Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

To compare between 0.67 and 0.670

Now, We know that;

The value of zero after any number in decimal expression has neglect.

So, By definition of decimal numbers, we get;

The correct comparison symbol from the drop-down box is,

⇒ 0.67 = 0.670

Hence, The correct comparison symbol from the drop-down box is,

⇒ 0.67 = 0.670

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The total number of shirts in the dresser is 4y + ×. The correct option is A

We need to add up the number of shirts on each shelf.

The first shelf's shirt count is indicated with the number x.

y indicates how many shirts are present on each of the four remaining shelves.

We may add up the shirts on each rack to determine the overall number of shirts:

Total = x + y + y + y + y

Simplifying the expression, we have:

Total = x + 4y

Therefore, The total number of shirts in the dresser is 4y + ×.

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Based on the provided information, we can say that Kibo has a volume of approximately 54.01 cubic meters.

To compare the volume of Kibo, Destiny, and Columbus, we need to calculate the volumes of each module.

The volume of a chamber can be determined utilizing the equation V = πr^2h, where r is the span and h is the level (or length for this situation) of the chamber.

For Kibo:

Radius (r) = 2.2 meters

Length (h) = 11.2 meters

V_kibo = π * (2.2^2) * 11.2

      = 4.84 * 11.2

      ≈ 54.01 cubic meters

For Destiny and Columbus, we would need their respective dimensions to calculate their volumes using the same formula.

Destiny is a U.S. laboratory module on the International Space Station. It is a multi-sided module, so we would need the measurements of each side to calculate its volume.

Columbus is a European laboratory module, which is also multi-sided.

Without the specific dimensions of Destiny and Columbus, we cannot accurately compare their volumes to Kibo. However, based on the provided information, we can say that Kibo has a volume of approximately 54.01 cubic meters.

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Answer:

undefined

Step-by-step explanation:

To find the slope of the line passing through the points (4, 7) and (4, -6), we can use the slope formula:

m = (y₂ - y₁) / (x₂ - x₁)

Substituting the coordinates of the points (4, 7) and (4, -6) into the formula:

m = (-6 - 7) / (4 - 4)

m = (-13) / (0)

The denominator is zero, which means the line is vertical and parallel to the y-axis. When the denominator is zero, the slope is undefined.

Therefore, the line passing through the points (4, 7) and (4, -6) has an undefined slope.

Answer:

hello

the answer is:

total mass = 3.94 + 14.81 + 11.27 + 7.65 = 37.65 kg

The value of x, applying the trigonometric ratios, is given by the following option:

B) 8.0.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are obtained according to the rules presented as follows:

For this problem, we have that side x is opposite to the angle of 28º, while the hypotenuse has a length of 17.

Hence the length x is obtained as follows:

sin(28º) = x/17

x = 17 x sine of 28 degrees

x = 8.

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Step-by-step explanation:

Let's start by using the formula for the volume of a cylinder:

V = πr^2h

where V is the volume of the cylinder, r is the radius of the cylinder, h is the height of the cylinder, and π is a mathematical constant (approximately equal to 3.14).

Since we are dealing with a drain pipe, we can assume that the height of the cylinder is fixed and does not change. Therefore, we can rewrite the formula as:

V = πr^2h = Ah

where A is the cross-sectional area of the cylinder.

Now, let's use the given information that the drain pipe can carry 36 litres per second. We know that the volume of water that passes through the pipe in one second is equal to 36 litres. We can therefore write:

36 = Ahv

where v is the velocity of the water flowing through the pipe. Since we are assuming that the height of the cylinder is fixed, we can simplify this equation to:

36 = Av

Now we need to determine the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second. Let's call the new diameter d2 and the old diameter d1. We can set up a proportion to solve for d2:

A1/A2 = d1^2/d2^2

We know that A1 and A2 are proportional to the volumes of water the pipe can carry, so we can write:

A1/A2 = 36/60

Simplifying this equation, we get:

A1/A2 = 3/5

Substituting in the formula for the cross-sectional area of a cylinder, we get:

πd1^2/4 / πd2^2/4 = 3/5

Simplifying further, we get:

d1^2/d2^2 = 3/5

Taking the square root of both sides, we get:

d1/d2 = sqrt(3/5)

Now we can solve for d2:

d2 = d1 / sqrt(3/5)

We want to know the percentage increase in the diameter, which we can find using the formula:

% Increase = (New Value - Old Value) / Old Value x 100%

Substituting in our values, we get:

% Increase = (d1 / sqrt(3/5) - d1) / d1 x 100%

Simplifying, we get:

% Increase = (1 / sqrt(3/5) - 1) x 100%

Using a calculator, we get:

% Increase ≈ 34.64%

Therefore, the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second is approximately 34.64%.

The measure of LA is . B'C'= 1, mLA' = 37"

A dilation is a mathematical operation that involves multiplying the distance between each point in an object and a fixed point, referred to as the center of dilation, by a constant factor known as the scale factor.

In the given scenario, the scale factor is specified as follows:

k = 1/3.

Consequently, the length of B'C' is obtained by multiplying the length of BC by 1/3, which can be understood as dividing the length by 3 after the dilation.

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A. A table of values and graph of the function is shown below.

B. The object would hit the ground at approximately 8.963 seconds.

Based on the information provided, we can logically deduce that the height (s) in meters, of this object above the​ ground is related to time by the following quadratic function:

s(t) = -4.9t² +39.2t + 42.3

When t = 0, s(t) is given by;

s(0) = -4.9(0)² +39.2(0) + 42.3

s(0) = 42.3

When t = 1, s(t) is given by;

s(1) = -4.9(1)² +39.2(1) + 42.3

s(1) = 76.6

When t = 2, s(t) is given by;

s(2) = -4.9(2)² +39.2(2) + 42.3

s(2) = 101.1

Therefore, the table can be created as follows;

Time (t)     Height s(t)

0                  43.3

1                   76.6

2                  101.1

3                  115.8

4                  120.7

5                  115.8

Part B.

Generally speaking, the height of this object would be equal to zero (0) when it hits the ground. By critically observing the graph (see attachment), we can logically deduce that the object would hit the ground at approximately 8.963 seconds.

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Hello!

Answer:

No

Explanation:

A statistical question is answered by collecting data that exhibits variability

[tex]\Huge \fbox{Answer = No}[/tex]

Statistical questions are open ended questions that are created to gather information or data about a population or a sample. Depending on the population or sample being investigated, they often involve variability and can have a variety of possible responses.

Because it is a straightforward factual question that can be answered with a single value, the question being asked is not a statistical one.

There are 1,760 yards in a mile, hence the answer to this question is an exact number. There is no variability or data gathering involved with this response. As a result, the question is not a statistical question.

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Answer:

There are 47.2242 miles in 76 kilometers.

1.6 km = 1 mile

76 km = 76/1.6 = 47.5 mile

There are 47.5 miles in 76 kilometers.

Answer:

Hope this helps :)

Step-by-step explanation:

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{2}{3}[/tex]

When dividing by a fraction, we just have to multiply by the reciprocal, making the equation:

[tex]\frac{1}{2}[/tex] × [tex]\frac{3}{2}[/tex]

Then we multiply and end up with:

[tex]\frac{1}{2}[/tex] × [tex]\frac{3}{2}[/tex] [tex]=\frac{3}{4}[/tex]