The probability of selecting two solid chocolates in a row is 0.0607 .
In the question ,
it is given that
there are total 39 chocolates in the box .
number of chocolates filled with nuts = 16
number of chocolates filled with caramel = 13
number of chocolates filled with solid = 10
Probability of selecting first chocolate as a solid is 10/39.
Now , there are 38 chocolates , with 9 solid chocolates ,
hence the probability of selecting second chocolate as a nut is = 9/38
So, the probability of selecting two solid chocolates in a row = 10/39×9/38
= 90/1482
= 0.0607
Therefore , the probability of selecting two solid chocolates in a row is 0.0607 .
The given question is incomplete , the complete question is
There are 39 chocolates in a box, all identically shaped. There 16 are filled with nuts, 13 with caramel, and 10 are solid chocolate. You randomly select one piece, eat it, and then select a second piece. Find the probability of selecting 2 solid chocolates in a row.
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find the value of tan A in simplest radical form
In the given right angle triangle BCA : BC = 5, CA = 3 and BA = root 34
From the trignometric ratio of right angle triangle :
The tangent of angle is the ratio of the Adjacent side to the opposite side
[tex]\tan \theta=\frac{Opposite\text{ side}}{Adjacent\text{Side}}[/tex]In the given triangle, the side opposite to angle A = BC and adjacent side CB
Substitute the value :
[tex]\begin{gathered} \tan \theta=\frac{Opposite\text{ side}}{Adjacent\text{Side}} \\ \tan A=\frac{BC}{CB} \\ \tan A=\frac{5}{3} \\ \tan A=1.66 \\ \\ ^{} \end{gathered}[/tex]The value of tanA = 5/3 or 1.66
I need help on writing the table and graphing it please !!
Given:
[tex]f(x)=2-\sqrt[]{x+6}[/tex]Calculate the values for f(x),
[tex]\begin{gathered} \text{for x=-6 , f(-6)=}2-\sqrt[]{-6+6} \\ f(-6)=2 \\ \text{for x=3 ,f(6)=2-}\sqrt[]{3+6} \\ f(3)=2-3=-1 \\ \text{for x=-2 f(-2)=2-}\sqrt[]{-2+6} \\ f(-2)=2-2=0 \\ \text{for x=1, f(1)=2-}\sqrt[]{1+6} \\ f(1)=-0.6 \end{gathered}[/tex]The graph of given function is,
you are given the point Q(-2,-5). A identify a point (x,y) that along with point Q defines a line with a positive slope.
Answer:
[tex] \sqrt{29} [/tex]
Three students that share a townhouse find that their electric bill for October is $2.65 less than the September bill. The total of both bills is $174.65, and eachbill is split evenly among the roommates. How much did each owe in September?
SOLUTION
Let the electric bill for September be x.
October's bill is $2.65 less than the September bill
This means that October's bill = x - 2.65
September + october bill = $174.65
That means that x + x - 2.65 = 174.65
Now let's find x which is september's bill
[tex]\begin{gathered} x+x-2.65=174.65 \\ 2x-2.65=174.65 \\ 2x=174.65+2.65 \\ 2x=177.3 \\ x=\frac{177.3}{2} \\ \\ x=88.65 \end{gathered}[/tex]So September's bill is $88.65, now each student pays
[tex]\begin{gathered} \frac{88.65}{3} \\ \\ =\text{ 29.55} \end{gathered}[/tex]So each student owe $29.55 for the month of September
Graph the line... running through: (1,3) with m=3
First, you have to locate the point (1,3)
Next, from that point, you have to locate the next one. To do that, you need the slope, which in this case is 3. So, from (1,3) you have to move 1 unit to the right and 3 units up, reaching the point (2, 6). Finally, you draw the line that passes through these two points
Unit 2: homework 9 shingle proofs
Solve the quadratic equation using any algebraic method. Show all work that leads to your answer.
6x² + 23x + 20 = 0
Answer:
x = - [tex]\frac{5}{2}[/tex] , x = - [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
6x² + 23x + 20 = 0 ( factorise the left side )
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 6 × 20 = 120 and sum = 23
the factors are + 8 and + 15
use these factors to split the x- term
6x² + 8x + 15x + 20 = 0 ( factor the first/second and third/fourth terms )
2x(3x + 4) + 5(3x + 4) = 0 ← factor out (3x + 4) from each term
(3x + 4)(2x + 5) = 0
equate each factor to zero and solve for x
2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - [tex]\frac{5}{2}[/tex]
3x + 4 = 0 ⇒ 3x = - 4 ⇒ x = - [tex]\frac{4}{3}[/tex]
Find a degree 3 polynomial with real coefficients having zeros 3 and 1 - 32 and a lead coefficient of 1.
Write Pin expanded form. Be sure to write the full equation, including P(x)
The polynomial function of least degree with only real coefficients will be; y = x³ - 8 · x² + 22 · x - 20.
What is polynomial ?Algebraic expressions called polynomials include constants and indeterminates. Polynomials can be thought of as a type of mathematics.
The statement indicates that the polynomial has real coefficients having zeros 3 and 1 - 32 and a lead coefficient of 1.
By algebra of quadratic equations, equations with real coefficients with complex roots are α + i β and α - i β. Then we get;
y = 1 · (x - 3) · (x - 3 - i) · (x - 3 + i)
y = (x - 3) · [x² - 3 · x - i · x - 3 · x + i · x + (3 + i) · (3 - i)]
y = (x - 3) · (x² - 6 · x + 9 - i²)
y = (x - 3) · (x² - 6 · x + 10)
y = x³ - 6 · x² + 10 · x - 2 · x² + 12 · x - 20
y = x³ - 8 · x² + 22 · x - 20
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Answer:
[tex]p(x)=x^3-5x^2+16x-30[/tex]
Step-by-step explanation:
Given information:
Degree 3 polynomial with real coefficients.Zeros: 3 and (1 - 3i).Lead coefficient of 1.For any complex number [tex]z = a+bi[/tex] , the complex conjugate of the number is defined as [tex]z^*=a-bi[/tex].
If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.
Therefore, if p(x) is a polynomial with real coefficients, and (1 - 3i) is a root of p(x)=0, then its complex conjugate (1 + 3i) is also a root of p(x)=0.
Therefore, the polynomial in factored form is:
[tex]p(x)=a(x-3)(x-(1-3i))(x-(1+3i))[/tex]
As the leading coefficient is 1, then a = 1:
[tex]p(x)=(x-3)(x-(1-3i))(x-(1+3i))[/tex]
Expand the polynomial:
[tex]\implies p(x)=(x-3)(x-(1-3i))(x-(1+3i))[/tex]
[tex]\implies p(x)=(x-3)(x-1+3i)(x-1-3i)[/tex]
[tex]\implies p(x)=(x-3)(x^2-x-3xi-x+1+3i+3ix-3i-9i^2)[/tex]
[tex]\implies p(x)=(x-3)(x^2-x-x-3xi+3ix+1+3i-3i-9i^2)[/tex]
[tex]\implies p(x)=(x-3)(x^2-2x+1-9(-1))[/tex]
[tex]\implies p(x)=(x-3)(x^2-2x+10)[/tex]
[tex]\implies p(x)=x^3-2x^2+10x-3x^2+6x-30[/tex]
[tex]\implies p(x)=x^3-2x^2-3x^2+10x+6x-30[/tex]
[tex]\implies p(x)=x^3-5x^2+16x-30[/tex]
4x- 1/2+ 2/3x combine like terms
Okay, here we heve this:
We need to combine like terms in the following equation:
[tex]\begin{gathered} 4x-\frac{1}{2}+\frac{2}{3}x \\ =(4x+\frac{2}{3}x)-\frac{1}{2} \\ =\frac{14}{3}x-\frac{1}{2} \end{gathered}[/tex]7. Martha baked 332 muffins. She packed them in boxes of twelve muffins and sold each full box for S6How much money did she make?
• Given that Martha baked 332 muffins,
,• 332 / 12 = 27.67 boxes
,• If she sold each box for $ 6 ; it will be
27*6 = $162
0.67 * 6 = 4.02
Total 162+4.02 = 166.02≈ $166
• She will make $166, ,
Use the tangent to find the length of side PR. Express your answer to the nearest tenth. P 559 The length of side PR is approximately units.
tan (Q) = opposite/ adjacent
tan (55º) = PR/ 4.9
________________________
1.43 = PR/ 4.9
PR= 1.4* 4.9 = 6.9
Answer
6.9
______________________________________
Can you see the updates?
Do you have any questions regarding the solution?
____________________
PR= tan (55)* 4.9 = 6.997925 ≅ 7
_________________________________
what is x^4 − 14x2 + 45 as factored
Answer: B=3
Step-by-step explanation:
In circle F with mZEFG = 30 and EF = 4 units, find the length of arc EG.. 4Round to the nearest hundredth.
The arc length can be found through the formula:
[tex]s=2\ast\pi\ast r\ast\frac{\theta}{360}[/tex]then, we can say that r is equal to 4 and the angle is 30°
[tex]\begin{gathered} s=2\ast\pi\ast4\ast\frac{30}{360} \\ s\approx2.09 \end{gathered}[/tex]Answer:
The arc length is approximately equal to 2.09
What is the complement of P(A) if P(A) = 0.52P(A) =
Given
P(A) = 0.52
Find
complement of P(A)
Explanation
As we know sum of probabilities is equal to one,
so ,
[tex]\begin{gathered} P(A)+P^{\prime}(A)=1 \\ P^{\prime}(A)=1-0.52 \\ P^{\prime}(A)=0.48 \end{gathered}[/tex]Final Answer
Therefore, the complement of P(A) = 0.48
I'll send in pictures of the question questions 2 goes with number 1
Since the equation is y=3/8x and x is equal to 44/3, we have
[tex]\begin{gathered} y=\frac{3}{8}\cdot\frac{44}{3}=\frac{132}{24} \\ \frac{132}{24}=\frac{66}{12}=\frac{33}{6}\text{ Simplifying} \\ \frac{33}{6}=5.5\text{ Dividing} \\ \text{Answer is: }y=5.5 \end{gathered}[/tex]yesenia knits 21 centimeters of a scarf every week. what Is yesenia's unit rate (cm per day)for her knitting?After 18 days of knitting, how many centimeters long will the scarf be?write an equation and solve.
Answer:
3cm per day
54cm long
Explanation
Let x be yesenia's unit rate
If yesenia knits 21 centimeters of a scarf every week, then;
21 cm = 1 week (7 days)
To determine the amount for her knitting in a day, we can write;
x = 1 day
Divide both expressions
21/x = 7/1
Cross multiply
7 * x = 21
7x = 21
x = 21/7
x = 3
hence yesenia's unit rate is 3cm per day
- Recall that;
21 cm = 1 week (7 days)
Let y be the length of the scaf sfter 18 days, To get the length of the scarf, we can write;
y = 18days
Divide both resulting expressions;
21/y = 7/18
7y = 21 * 18
y = 3 * 18
y = 54cm
Hence the scarf will be 54cm longy
-Fractions-My sister needs help with this, and I totally forgot how to do fractions Mind helping out?
Because we have the same denominator we can do the subtraction
[tex]\frac{12}{10}-\frac{3}{10}=\frac{12-3}{10}=\frac{9}{10}[/tex]Paul did well the representation of the fractions in the diagram, but the operation that he made as we can see is wrong because the result is 9/10
This is a graph of the motion of a small boat traveling at a constant speed. Total Distance Traveled 12 10 8 Distance (Kilometers) 6 0 2 4 6 8 1012 Time (Hours) How far will the boat travel in 15 hours? O A. 25 km O B. 30 km O C. 15 km O D. 10 km
The speed of the boat is given by the gradient of the line.
Given two points (x1,y1) and (x2,y2) on a graph, the gradient of the line that passes through the two points is given by
[tex]\text{ gradient = }\frac{y_2-y_1}{x_2-x_1}[/tex]In this case,
the line passes through the points (0,0) and (2,2).
We can set (x1,x2) = (0,0) and (y1,y2) = (2,2)
Therefore,
[tex]\begin{gathered} \text{ gradient = }\frac{2-0}{2-0}=\frac{2}{2}=1 \\ \text{therefore} \\ \text{the speed = 1km/h} \end{gathered}[/tex]Given that a body travels with speed, s, and in time, t, the distance travelled, d, is given by
[tex]d=st[/tex]In this case,
s = 1km/h, and t = 15hours
Therefore,
[tex]d=1\times15=15\operatorname{km}[/tex]Therefore, the boat travelled a distance of 15km
Describe and justify the methods you used to solve the quadratic equations in parts A and B.
We know that give any pair of real numbers A and B, the following statement will be true:
[tex]A\cdot B=0[/tex]if, and only if
[tex]\begin{gathered} A=0 \\ or \\ B=0 \end{gathered}[/tex]Now, if we factor a quadratic equation into two factors A and B, and use the fact we've just mentioned, we can then equal each factor to zero, solve for x and get the solutions to said quadratic equation.
Given the set of all even integers between and including -18 to -6 , what is the probability of choosing a multiple of -6 from this set?1/93/74/9
TheseGiven the set: {-18, -16, -14, -12, -10, -8, -6}
This is 7 numbers
Multiplies of -6 are:
[tex]\begin{gathered} -6\times1=-6 \\ -6\times2=-12 \\ -6\times3=-18 \end{gathered}[/tex]This is 3 numbers
Therefore, the probability is given by:
[tex]P=\frac{multiplies\text{ of }-6}{total\text{ set }}[/tex]So:
[tex]P=\frac{3}{7}[/tex]Answer: 3/7
What is the explicit formula for the sequence?3,1,-1, -3, -5,...a,= -2n +5a, = 17-5an= 2n-5an= -2n + 3
We need the formula that gives us the values of the sequence
where n is the value of the position
using the formula
[tex]a_n=-2n+5[/tex][tex]\begin{gathered} a_1=-2(1)+5=3 \\ a_2=-2(2)+5=1 \\ a_3=-2(3)+5=-1 \\ a_4=-2(4)+5=-3 \\ a_5=-2(5)+5=-5 \end{gathered}[/tex]as we can see the formula is the correct formula because we obtain the values of the sequence
Kaitlin got a prepaid debit card with $15 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 21
cents per yard. If after that purchase there was $4.92 left on the card, how many yards of ribbon did Kaitlin buy?
yards
Answer:
Kaitlin bought 48 yards of ribbon.
Step-by-step explanation:
Hey! Let's help you with your question here!
So, let's start by figuring out what we know and what we need to figure out. First of all, we started with $15 and ended with $4.92. We also know that the price of the ribbon is $0.21 per yard and we need to figure out how many yards of ribbon she purchased.
In order to figure this out, we first want to know the difference in the price between what we started and what we ended up with. So, we can subtract! It would look like this:
[tex]15-4.92=10.08[/tex]
So, we figured out that the difference in the price is $10.08, but how do we find out how many yards of ribbon Kaitlin bought? Well, since we know that it is $0.21 cents for a yard of ribbon, we can just take the difference in price and divide it by how much a ribbon cost for a yard of it. So it would look like this:
[tex]10.08/0.21=48[/tex]
We have a nice whole number and that's our answer! Therefore, Kaitlin bought 48 yards of ribbon.
Mathematical Way:
To do it in a more mathematical way, we can put it in the form of a formula. We know that the end total is $4.92 and the initial is $15. We also know that it's $0.21 cents per yard of ribbon but we don't know how many yards she bought. We can let the number of yards she bought represent x in the formula, so we have:
[tex]15=0.21x + 4.92[/tex]
This formula makes sense because we start with $15 at the beginning, so we want to add $4.92 from 0.21x because the end total is the remainder of how many yards Kaitlin bought. The process is essentially the same as the method above. If we were to solve the formula, it would give us the same answer:
[tex]15=0.21x+4.92[/tex]
[tex]15-4.92=0.21x[/tex] - Moving the 4.92 over to the left side, beginning to isolate x.
[tex]10.08=0.21x[/tex] - Subtracting $4.92 from $15.
[tex]\frac{10.08}{0.21} =\frac{0.21x}{0.21}[/tex] - We divide by $0.21 to solve for x.
[tex]48=x[/tex]
And here, we get the exact same answer, 48 yards of ribbon.
Which is an x-intercept of the continuous function in thetable?O (-1,0)O (0, -6)O (-6, 0)O (0, -1)
The x-intercept happens when:
[tex]f(x)=0[/tex]Therefore, the x-intercepts for that functions are:
[tex]\begin{gathered} x=-1 \\ x=2 \\ x=3 \end{gathered}[/tex]Answ
Lauren was going to by her mom her favorite perfume for Christmas at a price of $31.95. She waited until it got too close to Christmas and the price went up to $41.49. What was the percent of increase in the price?
The percent of increase in the cost of the perfume is 29.86%
What is percentage and how can it be calculated?
A percentage is a figure or ratio that can be stated as a fraction of 100 in mathematics. If we need to determine a percentage of a number, multiply it by 100 and divide it by the total. So, a part per hundred is what the percentage refers to. Percent signifies for every 100. The sign "%" is used to denote it. No dimension exists for percentages. Thus, it is referred to as a dimensionless number.
Mathematically,
Percent of increase = [(Final value - Initial value)/(Initial value)]×100
Given, the final value of the perfume at purchase = $41.49
Also, the initial value of the perfume as assessed = $31.95
Therefore using the formula established in the literature above,
Percentage increase = [(41.49 - 31.95)/31.95]×100 = 29.86%
Thus, the percent of increase in the cost of the perfume is 29.86%
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Find the area round to two decimal places as needed
To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:
[tex]A=\frac{b\cdot h}{2}[/tex]The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:
[tex]\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}[/tex]The area of the triangle is 28 square miles.
Im confused on how to make the table and plug the dots while also describing both behaviors on this equation.
Here, we want to complete the table
To do this, we consider points on the plot
From what we have;
We are told that a graph of an exponential function does not cross the x-axis and thus, y cannot be zero
When x =0, y = 1
When x = 1, y = 2
when x = 2, y = 4
The y-intercept is the value of y when x = 0; it is the point at which the graph crosses the y-axis
What we have here is that wehn x = 0, y = 1
Hence, 1 is the y-intercept
Now, let us take a look at the end behavior
We can obtain this from the graph;
As x moves towards infinity, the y value moves towards infinity too as evident from the upward curve of the graph
As x moves toward negative infinity, y moves closer to zero
Find the average rate of change of the following equation on the given interval. y=3x+1 on [45,48]
Given:
The equation is given as,
[tex]y=3x+1[/tex]The interval is given as,
[tex]\lbrack a,b\rbrack=\lbrack45,48\rbrack[/tex]The objective is to find the average rate of change.
Explanation:
The general formula to find the average rate of change is,
[tex]A=\frac{f(b)-f(a)}{b-a}\text{ . . . . (1)}[/tex]On plugging the function in the equation (1),
[tex]A=\frac{(3(48)+1)-(3(45)+1)}{48-45}[/tex]On further solving the above equation,
[tex]\begin{gathered} A=\frac{145-136}{3} \\ =\frac{9}{3} \\ =3 \end{gathered}[/tex]Hence, the average rate of change is 3.
??????????????????????????
y = (5/7)x - 13
The slope of this line is (5/7)
I a line has a slope m, then a line perpendicular would have a slope -1/m
In this case m= 5/7
So the perpendicular would be: -1/m = -7/5
Answer: -7/5
In decimal numbers: -1.4
Answer:
Is there a real question?
I can't seem to find it...
Step-by-step explanation:
how much ice pop mixture can each mold hold when full?
Explanation:
To know how much ice pop mixture can each mold hold, we need to calculate the volume of the mold.
The volume of a cone is equal to
[tex]V=\frac{1}{3}\pi r^2h[/tex]Where r is the radius and h is the height of the cone. Replacing r = 2 cm and h = 15 cm, we get:
[tex]\begin{gathered} V=\frac{1}{3}\pi(2cm)^2(15cm) \\ V=\frac{1}{3}\pi(4cm^2)(15cm) \\ V=20\pi cm^3 \end{gathered}[/tex]Therefore, the answer is
A. 20
A boy goes to school by first taking a bus for 1 3/4 km and then by walking 1/3 km. Find the distance of his house from the school.
The boy goes to school by bus for 1 3/4km, then he walks 1/3 km.
To determine the total distance he traveled you have to add both distances:
[tex]1\frac{3}{4}+\frac{1}{3}[/tex]To solve this sum, add the fractions first and then add the result to the whole number:
- Add both fractions:
[tex]\frac{3}{4}+\frac{1}{3}[/tex]To add both fractions you have to express them using the same denominator first. A common multiple between the denominators "4" and "3" is "12". Multiply the first fraction by 3 and the second by 4 to express them as their equivalent fractions with denominator 12. Then proceed to add them:
[tex]\frac{3\cdot3}{4\cdot3}+\frac{1\cdot4}{3\cdot4}=\frac{9}{12}+\frac{4}{12}=\frac{9+4}{12}=\frac{13}{12}[/tex]The result is 13/12, as you can see the numerator is greater than the denominator, which indicates that this is an improper fraction, i.e. its value is greater than 1. You can write this fraction as a mixed number as follows:
- Solve the division:
[tex]13\div12=1.08\bar{3}[/tex]The mixed number will have the whole number "1".
- To express the decimal value as a fraction, multiply it by 12
[tex]0.08\bar{3}\cdot12=1[/tex]The result is the numerator of the fraction, and the denominator will be 12, so:
[tex]0.08\bar{3}=\frac{1}{12}[/tex]And the resulting mixed number is:
[tex]\frac{13}{12}=1\frac{1}{12}[/tex]Finally, add the remaining whole number from the first sum to determine the distance between his house and the school:
[tex]1+1\frac{1}{12}=2\frac{1}{12}[/tex]The distance he traveled from home to school is 2 1/12 km.