There are two varieties in a population of squirrels: short tails and long tails. Long-tailed squirrels are better at jumping and balancing in trees. Scientists observe that over the span of 100 years, the proportion of the population with long tails increases from 10% to 60%. Which statement is most likely? (1 point)

The proportion of long-tailed squirrels may have increased due to a decrease in trees.

The proportion of short-tailed squirrels may have decreased due to an increase in trees.

The proportion of short-tailed squirrels may have decreased due to decreased food availability.

The proportion of long-tailed squirrels may have increased due to increased food availability.

Answer:

ΔU = Q − W

Explanation:

the branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.

ΔU is the change in internal energy U of the system. Q is the net heat transferred into the system—that is, Q is the sum of all heat transfer into and out of the system.

The transition metals can form a variety of complexes because can lose as well as accept electrons .

The transition elements are those elements that are foud at the middle part of the periodic table having incompletely filled d orbitals.

These elements have a variable oxidation state. They can loose and accept electrons easily and this is why transition metal elements can form a variety of complexes with different colors and other properties.

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In the galvanic or voltaic cell, the standard cell potential is 1.67 V. The standard potential is the difference between the reduction potential of cathode and anode.

An electrochemical cell produces energy by a sponteanous chemical process. A galvanic or voltaic cell produces energy by a sponteanous chemical reaction.

Hence, given the standard reduction potentials;

Sn4+ + 2e- ==> Sn2+  Eº = 0.15 V (anode)

Co3+ + 2e- ==> Co2+  Eº = 1.82 V (cathode)

Eºcell = 1.82 V - 0.15 V = 1.67 V

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H_2S+O_2--->SO_2+H_2O

Balance it

So

Molar mass of oxygen=2(16)=32g/mol

Molar mass of SO_2=2(16)+32=32+32=64g/mol

Moles of oxygen:-

Here

Moles of so_2

Mass of water

Answer:

A. Oxygen pushes electrons towards the hydrogens.

Explanation:

The oxygen is reduced because it undergoes a partial gain of electrons. The oxygen atom in water has greater electron density near it than they did in the O₂ molecule.

Reduction is a chemical reactions in which the number of electrons associated with an atom or a group of atoms is increased.

The electrons taken up by the substance reduced are supplied by another substance, which is thereby oxidized.

The hydrogen is oxidized because it added oxygen to form water.

Conversely the oxygen is reduced because it added hydrogen to form water.

Therefore, The oxygen is reduced because it undergoes a partial gain of electrons. The oxygen atom in water has greater electron density near it than they did in the O₂ molecule.

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#SPJ2

[tex]\text{Morality}= \dfrac{\text{Number of moles}}{\text{Volume}}=\dfrac{3.25}{2.78}=1.169 ~mol/L[/tex]

Answer:

it thinks it pollution

Explanation:

hope that helps

Answer:

Can you repost this but flip it? It’s upside down rn

Explanation:

Answer: a

Explanation:

Industry uses only about 18% while the others use around 70-90% of water.

YW!!! please mark branlest!!!! =^.^=

Answer:

60 kilometres per hour is the slowest rate of travel

Explanation:

we convert

20 kilometer per minute into kilometer per second

it comes out 1/3 kilometer per sec

Answer:

c

Explanation:

a- 5/1km per second

b-1/3km per second

c. 1/60km per second

the larger the denominator the smaller the fraction

Given:

Initial pressure P1 = 3 atm

Initial volume = 3L

Temperature (constant)= 298 K

final volume V2 = 2L

To find:

Final pressure P2 = ?

Solution:

According to Boyle's Law,

P1V1 = P2V2

3×3 = 2 × P2

P2 = 9/2

P2 = 4.5 atm

[tex]{Answer = 4.5 atm}[/tex]

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I agree with idea of Kevin because bakong soda dissociates faster in hot water than cold water.

Baking soda is a chemical that can undergo a decomposition reaction when heated. At 80 degrees Celsius, sodium bicarbonate starts to break down into sodium carbonate (Na2CO3), water (H2O) and carbon dioxide (CO2) which is ready for reaction with other chemical.

So we can conclude that Kevin idea is correct because bakong soda dissociates faster in hot water than cold water.

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2KOH --> K²O + H²O

Explanation:

Potassium Hydroxide = KOH

Potassium oxide = K²O

Water = H²O

KOH --> K²O + H²O

K = 1. K = 2.

2KOH --> K²O + H²O

O = 2. O = 2.

H = 2. H = 2.

Balanced symbol = 2KOH --> K²O + H²O

Balanced word = 2Potassium Hydroxide --> Potassium oxide + Water.

Based on the fgiven K_{a} values of the acids, the equilibrim concentrations of[tex]HC_{2}H_{2}O_{2}[/tex] and [tex]NH_{4}^{+}[/tex] is dtermined using ICE tables.

An acid dissociation constant, [tex]K_{a}[/tex] of an acid is a measure of the strength of the acid in solution. The larger the [tex]K_{a}[/tex] value of an acid, the stronger the acid, therefore, acid dissociation constants are usually apply to only weak acids because strong acids have exceedingly large [tex]K_{a}[/tex] values.

It is written as a  qoutient of the equilibrium concentrations of the aqueous species in the acid solution.

For the weak acids such as [tex]HC_{2}H_{2}O_{2}[/tex] and [tex]NH_{4}^{+}[/tex], their equilibrim concentrations are determined using their [tex]K_{a}[/tex] values and an ICE table.

The pH of solutions are estimated using indicators such as methyl orange, methyl red and phenolphthalein. The colors of indicators change according to the pH of the solution

Acidic solutions have pH less than 7 while alkaline solutions have pH greater than 7.

Therefore, acids have low pH and weak acids have low [tex]K_{a}[/tex] values.

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The final pressure in the flasks (containing N₂ and CO) after the stopcock is opened is 1.57 atm

n = PV / RT

n = (2 × 4) / (0.0821 × 273)

n = 0.357 mole

n = PV / RT

n = (1.4 × 10) / (0.0821 × 273)

n = 0.625 mole

P = nRT / V

P = (0.982 × 0.0821 × 273) / 14

P = 1.57 atm

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Notes:-

electron configuration:-

Valency is 3

So 3 dots are included

The limiting reactant here is P4O10 . The percent yield of the product is caculated as 33.3%.

The limiting  reactant is the reactant that is in a minute quantity.

Number of moles of P4O10 =  85.5 g/284 g/mol = 0.3 moles

Number of moles of H2O =  74.9 g / 18 g/mol = 4.2 moles

From the reaction equation;

1 mole of P4O10 reacts with 6 moles of H2O

x moles of P4O10 reacts with 4.2 moles of H2O

x = 0.7  moles

Hence, P4O10 is the limiting reactant.

1 mole of P4O10 yields 4 moles of H3PO4

0.3 moles of P4O10 yields

0.3 moles * 4/1 = 1.2 moles

Mass of the H3PO4 = 1.2 moles * 98 g/mol = 117.6 g

Percent yield = 39.2 g/117.6 g * 100/1 = 33.3 %

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Answer: The gas generated by two antacid tablets has a smaller volume.

Explanation:

Since the antiacid is the limiting reagent, we know that the more tablets there are, the more gas there will be.

This means that there will be more gas generated by the four antiacid tablets when compared to the two antiacid tablets, which gives us that the gas generated by the two antiacid tablets has a smaller volume.

Answer:

bacteria

Explanation:

Bacteria removes nitrogen from the air and converts it into a form that is usable by plants.

Answer:

Bacteria

Explanation:

I took the test and got it right

Answer: because the hot water molecules are moving faster

Explanation: hot water=faster molecules= it spreads faster

Answer:

c, 8.32 mol

Explanation:

the molecular mass of water is about 18.02, to get the moles of water 150/18.02=8.32 mol, since the coefficients of HCl and H2O are the same, the number of moles would be the same as well

Answer:

Mobile sources

..........................

Answer:

it,s is so many people do you want to go then

you are not study then stage change of it

Answer:

Sodium nitride is exothermic reaction and hydrochloric acid is endothermic reaction.

Answer:

Answer:Fish play an important role in nutrient cycles because they store a large proportion of ecosystem nutrients in their tissues, transport nutrients farther than other aquatic animals and excrete nutrients in dissolved forms that are readily available to primary producers.

Given the Planck's constant and the speed of light, the energy of the ultraviolet light with a frequency of 9.58×10¹⁴ Hz is 6.35×10¯¹⁹ J (Option C)

The energy of the ultraviolet light can be obtained as follow:

E = hf

E = 6.626×10¯³⁴ × 9.58×10¹⁴

E = 6.35×10¯¹⁹ J

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