There were some people on a train.
18 people get off the train at the first stop and 21 people get on the train.
Now there are 65 people on the train.
How many people were on the train to begin with?

Answer: 6

Step-by-step explanation:

The factors of 42 are: 1, 2, 3, 6, 7, 14, 21, 42

The factors of 78 are: 1, 2, 3, 6, 13, 26, 39, 78

Then the greatest common factor is 6.

Heres something you need to learn about the greatest common factor (gcf)

What is the Greatest Common Factor?

The largest number, which is the factor of two or more numbers is called the Greatest Common Factor (GCF). It is the largest number (factor) that divide them resulting in a Natural number. Once all the factors of the number are found, there are few factors that are common in both. The largest number that is found in the common factors is called the greatest common factor. The GCF is also known as the Highest Common Factor (HCF)

Let us consider the example given below:

Greatest Common Factor (GCF)

For example – The GCF of 18, 21 is 3. Because the factors of the number 18 and 21 are:

Factors of 18 = 2×9 =2×3×3

Factors of 21 = 3×7

Here, the number 3 is common in both the factors of numbers. Hence, the greatest common factor of 18 and 21 is 3.

Similarly, the GCF of 10, 15 and 25 is 5.

How to Find the Greatest Common Factor?

If we have to find out the GCF of two numbers, we will first list the prime factors of each number. The multiple of common factors of both the numbers results in GCF. If there are no common prime factors, the greatest common factor is 1.

Finding the GCF of a given number set can be easy. However, there are several steps need to be followed to get the correct GCF. In order to find the greatest common factor of two given numbers, you need to find all the factors of both the numbers and then identify the common factors.

Find out the GCF of 18 and 24

Prime factors of 18 – 2×3×3

Prime factors of 24 –2×2×2×3

They have factors 2 and 3 in common so, thus G.C.F of 18 and 24 is 2×3 = 6

Also, try: GCF calculator

GCF and LCM

Greatest Common Factor of two or more numbers is defined as the largest number that is a factor of all the numbers.

Least Common Multiple of two or more numbers is the smallest number (non-zero) that is a multiple of all the numbers.

Factoring Greatest Common Factor

Factor method is used to list out all the prime factors, and you can easily find out the LCM and GCF. Factors are usually the numbers that we multiply together to get another number.

Example- Factors of 12 are 1,2,3,4,6 and 12 because 2×6 =12, 4×3 = 12 or 1×12 = 12. After finding out the factors of two numbers, we need to circle all the numbers that appear in both the list.

Greatest Common Factor Examples

Example 1:

Find the greatest common factor of 18 and 24.

Solution:

First list all the factors of the given numbers.

Factors of 18 = 1, 2, 3, 6, 9 and 18

Factors of 24 = 1, 2, 3, 4, 6, 8, 12 and 24

The largest common factor of 18 and 24 is 6.

Thus G.C.F. is 6.

Example 2:

Find the GCF of 8, 18, 28 and 48.

Solution:

Factors are as follows-

Factors of 8 = 1, 2, 4, 8

Factors of 18 = 1, 2, 3, 6, 9, 18

Factors of 28 = 1, 2, 4, 7, 14, 28

Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The largest common factor of 8, 18, 28, 48 is 2. Because the factors 1 and 2 are found all the factors of numbers. Among these two numbers, the number 2 is the largest numbers. Hence, the GCF of these numbers is 2.

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The total number of hours is 30 hours as the sum of 7/8 and 3/8 comes out to be 30 hours.

1) We know that there is a total of 24 hours in a day.

therefore, 7/8 hours of Wednesday =

number of hours in a day = 24

number of hours every Wednesday = 7/8

= 7/8 x 24 hours

= 7 x 3 hours

= 21 hours

7/8 hours every Wednesday means 21 hours every Wednesday.  

2) We know that there are a total of 24 hours in a day;

therefore, 3/8 hours of Friday =

number of hours in a day = 24

number of hours every Friday = 3/8

= 3/8 x 24 hours

= 3 x 3 hours

= 9 hours

3/8 hours every Friday means 9 hours every Friday.

therefore, the total number of hours = 21 + 9 = 30

The total number of hours is 30 hours as the sum of 7/8 and 3/8 comes out to be 30 hours.

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The probability that exactly 8 of the 19 people in the random sample are employed is 27.93%.

We need to calculate the probability that exactly 8 of the 19 people in the random sample are employed. The probability of a single person being employed is 4%, or 0.04.

To calculate the probability of 8 people being employed out of the 19, we can use the binomial distribution formula:

P(X=8) = nCx * (p^x) * (1-p)^(n-x) Where n = 19, x = 8, p = 0.04, and 1-p = 0.96

So, P(X=8) = 19C8 * (0.04^8) * (0.96^11) = 0.2793 or 27.93%.

Therefore, the probability that exactly 8 of the 19 people in the random sample are employed is 27.93%.

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The probability that a randomly selected adult weighs between 120 and 165 lbs is approximately 0.8186.

Since the weights of adults are normally distributed with a mean of 140 lbs and a standard deviation of 25 lbs, we can use the standard normal distribution to calculate the probability.

We first need to standardize the values using the formula: z = (x - μ) / σ, where x is the weight, μ is the mean, and σ is the standard deviation.

For x = 120 lbs, z = (120 - 140) / 25 = -0.8, and for x = 165 lbs, z = (165 - 140) / 25 = 1.0. We can then use a calculator to find the probability between -0.8 and 1.0, which is approximately 0.8186.

Thus, the chance of picking an adult at random who weighs between 120 and 165 lbs is roughly 0.8186.

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The admission fee at an amusement park is $4.25 for children and $7.00 for adults. on a certain day, 303 people entered the park, and the admission fees collected totaled 1824 dollars. There are 108 children and 195 adults were admitted

Let the number of children admitted = C and the number of adults admitted = A

Total number of people admitted = 303

We can form two equations from the given information.

The first equation is to represent the number of people admitted in terms of children and adults.

So, the equation will be

C + A = 303 ------(1)

The second equation represents the total amount collected from admission fees.

So, the equation will be

4.25C + 7A = 1824 ------(2)

Multiplying equation (1) by 4.25, we get

4.25C + 4.25A = 1289.25 ------(3)

Subtracting equation (3) from equation (2), we get:

7A - 4.25A = 1824 - 1289.25

Simplifying, we get:

2.75A = 534.75

Dividing by 2.75, we get:

A = 195

Putting A = 195 in equation (1), we get:

C + 195 = 303

Simplifying, we get:

C = 108

So, there were 108 children and 195 adults admitted on that day.

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The option that would result in the smallest margin of error in estimating the mean salt content, u, is 95% confidence, n = 50. The correct answer is Option D.

The margin of error is the amount by which a statistic is expected to differ from the true value of the population parameter. The interval estimate is calculated with the help of a margin of error. The margin of error and the interval estimate are inversely related to each other. If we want a small margin of error, we must increase the sample size.

The confidence level is the likelihood that a population parameter will fall within a specified range of values. The confidence level is determined by the sample size and margin of error. The sample size and margin of error are directly related to each other. When the sample size is smaller, the margin of error is larger. When the sample size is larger, the margin of error is smaller.

The margin of error is the highest at a confidence level of 50%. In general, as the confidence level increases, the margin of error decreases, and vice versa. As the sample size increases, the margin of error decreases. It follows that a 95% confidence level, n = 50 would yield the smallest margin of error in estimating the mean salt content, u. Hence, option D) 95% confidence, n = 50 would result in the smallest margin of error in estimating the mean salt content, u.

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The best type of inspection to use depends on the nature of the purchase. Each type of inspection has its own advantages and disadvantages, and should be chosen based on the requirements of the product and the level of risk associated with the inspection.

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There is no solution if the boundary conditions are inconsistent, i.e., if y(0) ≠ y(L) = 1.

We are given the boundary-value problem:

y" + 16y = 0, y(0) = 1, y(L) = 1

The characteristic equation is r^2 + 16 = 0, which has roots r = ±4i.

The general solution to the differential equation is then y(x) = c1cos(4x) + c2sin(4x).

Using the boundary conditions, we get:

y(0) = c1 = 1

y(L) = c1cos(4L) + c2sin(4L) = 1

Substituting c1 = 1 into the second equation, we get:

cos(4L) + c2*sin(4L) = 1

Solving for c2, we get:

c2 = (1 - cos(4L))/sin(4L)

Thus, the general solution to the differential equation that satisfies the given boundary conditions is:

y(x) = cos(4x) + (1 - cos(4L))/sin(4L)*sin(4x)

Now, we can answer the questions:

(a) To have precisely one nontrivial solution, we need the coefficients c1 and c2 to be uniquely determined. From the above expression for c2, we see that this is only possible if sin(4L) is nonzero. Thus, if sin(4L) ≠ 0, there exists precisely one nontrivial solution.

(b) If sin(4L) = 0, then c2 is undefined and we have a family of solutions that differ by a constant multiple of sin(4x). Hence, there are infinitely many solutions.

(c) There is no solution if the boundary conditions are inconsistent, i.e., if y(0) ≠ y(L) = 1.

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Coupling tetraalkylammonium and ethylene glycol ether side chain is an effective method to enable highly soluble anthraquinone-based ionic species for nonaqueous redox flow battery. The side chains of the tetraalkylammonium are modified with the ethylene glycol ether, which is a highly polar solvent, allowing for better solubility in nonaqueous electrolyte solutions. Additionally, the ethylene glycol ether has the ability to modify the stability of the ionic species, preventing aggregation and ensuring the longevity of the battery. This increases the redox capacity and enhances the performance of the flow battery.

The ethylene glycol ether-tetraalkylammonium coupling has been proven to be an effective method for improving the solubility and stability of anthraquinone-based ionic species. For example, it has been observed that the coupling of ethylene glycol ether to anthraquinone-based ionic species enhanced the current density of the battery by more than 3 times. Furthermore, the coupling process has also been found to improve the energy efficiency and storage capacity of the nonaqueous redox flow battery.

Overall, coupling tetraalkylammonium and ethylene glycol ether side chain is an effective method for enabling highly soluble anthraquinone-based ionic species for nonaqueous redox flow battery. This process has been proven to improve the performance of the battery, including current density, energy efficiency, and storage capacity.

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The probability of selecting two non-defective DVD players from a group of six is 2/5. This is based on the assumption that the selection is done without replacement.

We can use the formula for calculating probabilities of combinations:

P(not defective) = number of ways to choose 2 non-defective DVD players / total number of ways to choose 2 DVD players

Total number of ways to choose 2 DVD players out of 6 is:

C(6,2) = 6! / ([2!] [4!]) = 15

Number of ways to choose 2 non-defective DVD players out of 4 is:

C(4,2) = 4! / ([2!] [2!]) = 6

Therefore, the probability that Cecil chooses 2 non-defective DVD players is:

P(not defective) = 6/15 = 2/5

So the value of P(not defective) is 2/5.

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There are 5²⁵ possible ways to select 25 cans of soda from 5 types, while there are [5¹⁸] (25 choose 7) possible ways to select 25 cans with at least 7 Dr. Peppers, and only [3²²] (25 choose 3) possible ways to select 25 cans with only 3 Dr. Peppers available.

(a) Since there are five types of soda and we are selecting 25 cans, we can choose any type of soda for each can. Therefore, the number of ways to select 25 cans of soda is 5²⁵.

(b) If we must include at least seven Dr. Peppers, then we can choose the remaining 18 cans from any of the five types of soda (including Dr. Pepper). We can choose 7 Dr. Peppers in (25 choose 7) ways. Therefore, the number of ways to select 25 cans of soda with at least seven Dr. Peppers is (25 choose 7) [5¹⁸].

(c) If there are only three Dr. Peppers available, then we must choose all three Dr. Peppers and select the remaining 22 cans from the four types of soda (excluding Dr. Pepper). We can choose the remaining 22 cans in 4²² ways. Therefore, the number of ways to select 25 cans of soda with only three Dr. Peppers available is 3 [4²²].

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Complete question:

From an unlimited selection of five types of soda, one of which is Dr. Pepper, you are putting 25 cans on a table.

(a) Determine the number of ways you can select 25 cans of soda.

(b) Determine the number of ways you can select 25 cans of soda if you must include at least seven Dr. Peppers.

(c) Determine the number of ways you can select 25 cans of soda if it turns out there are only three Dr. Peppers available.

BC will be congruent to AD under the C.P.C.T rule (corresponding parts of congruent triangles.)

Triangle congruence: Two triangles are said to be congruent if their three corresponding sides and their three corresponding angles are of identical size.

You can move, flip, twist, and turn these triangles to produce the same effect. When relocated, they are parallel to one another.

Two triangles are congruent if they satisfy all five conditions for congruence.

They include the right angle-hypotenuse-side (RAHS), angle-side-angle (ASA), angle-angle-side (AAS), side-side-side (SSS), and angle-side-angle (SSS) (RHS).

So, in the given △DAB and △DCB:

AC = AC = Common

∠DAC = ∠BAC = AC is the angle bisector

∠DCA = ∠BCA = AC is the angle bisector

Then, △DAB ≅ △DCB under the ASA congruency rule,

Then, BC will be congruent to AD under the C.P.C.T rule (corresponding parts of congruent triangles.)

Therefore, BC will be congruent to AD under the C.P.C.T rule (corresponding parts of congruent triangles.)

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The 100th digit to the right of the decimal point in the decimal representation of (1 .fi.)3000 is 0.

First, let's convert the number (1 .fi.)3000 into its decimal representation. This is done by dividing 3000 by 10 raised to the power of the number of digits following the decimal point, which in this case is 3. We get the answer 1000, or 1.000.
Now, we can look at the 100th digit to the right of the decimal point. This will be the 0th digit from the right of the decimal point, which is 0. Therefore, the 100th digit to the right of the decimal point in the decimal representation of (1 .fi.)3000 is 0.

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The 4 in the hundredths place has a smaller value than the 4 in the tens place.

In the decimal number system, each digit to the left of the decimal point represents a power of 10, starting with 10^0 = 1 for the rightmost digit. Each digit to the right of the decimal point represents a negative power of 10, with the place value decreasing as you move farther to the right.

In the number 240.149, the 4 in the tens place represents 4 x 10 = 40. The 4 in the hundredth place represents 4/100 or 0.04, which is smaller than 40. Therefore, the 4 in the tens place has a greater value than the 4 in the hundredths place.

Hence, the value of a digit in a decimal number depends on its position relative to the decimal point. Digits to the left of the decimal point represent whole numbers, while digits to the right of the decimal point represent fractions or parts of a whole.


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the function represents exponential decay with a rate of decrease of 5.9% per unit increase in x.

In the exponential function y = [tex]620(0.941)^x:[/tex]

The base of the exponent is 0.941, which is between 0 and 1.

As x increases, the value of [tex](0.941)^x[/tex]gets smaller and smaller, approaching 0 but never reaching it.

Therefore, the function represents exponential decay.

To determine the percentage rate of decrease, we can use the formula:

rate of decrease = (1 - base) x 100%

In this case, the base is 0.941, so the rate of decrease is:

rate of decrease = (1 - 0.941) x 100% = 5.9%

The exponential function is y = 620(0.941)^x.
To determine whether the function represents growth or decay, we need to look at the base of the exponential function, which is 0.941. Since this base is less than 1, the function represents decay.
To determine the percentage rate of decrease, we can use the formula:

r = (1 - b) x 100%
where r is the percentage rate of decrease, and b is the base of the exponential function.
In this case, b = 0.941, so we have:

r = (1 - 0.941) x 100%
= 0.059 x 100%
= 5.9%

Therefore, the exponential function y = 620(0.941)^x represents decay with a rate of 5.9% per unit of x.

A sort of mathematical function called exponential decay can be used to explain a quantity's decline across time or space. The quantity at any given time will change at a pace that is proportionate to the quantity itself, which is characterised by a decreasing rate of change. In other words, the amount of reduction decreases as time or space grows, but it never decreases to zero.

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage rate of increase or decrease. y=620(0.941)^x y=620(0.941) x

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To represent the value of the bond after x years, we can use the function:f(x) = 100 * (1 + 0.04)^xwhere x is the number of years the bond has been held.The expression (1 + 0.04) represents the growth factor of the bond per year, since the bond grows in value by 4 percent each year. By raising this factor to the power of x, we obtain the cumulative growth of the bond over x years.Multiplying the initial value of the bond, 100$, by the growth factor raised to the power of x, gives us the value of the bond after x years. This is the purpose of the function f(x).

The third term of a sequence is 14. Term to term rule is square, then subtract 11. The first term of the sequence is 6.

The given information is about the third term of a sequence which is 14, and the term to term rule is square, then subtract 11.

We have to find the first term of the sequence. The sequence can be calculated using the following formula:

An = A1 + (n-1)d

Where, An is the nth term of the sequence A1 is the first term of the sequence d is the common difference between the terms of the sequence. Let's solve the problem by finding the value of the common difference between the terms of the sequence.

Using the given information, we can write: A3 = 14=> A1 + (3 - 1)d = 14=> A1 + 2d = 14 ----- (i)

Also, the term to term rule is square, then subtract 11.So, we can write, A2 = A1 + d = (A1)² - 11 ---- (ii)

Substituting the value of d from equation (ii) in equation (i),

we get: A1 + 2 [(A1)² - 11] = 14 Simplifying this equation, we get: A1² - 2A1 - 12 = 0 On solving this quadratic equation

we get: A1 = -2 or A1 = 6 Ignoring the negative value of A1, we get the first term of the sequence to be 6.

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The equation that represents the situation is (4 + x) / (10 + 25 + x) = 0.25

Let's start by finding the amount of medicine in the original mixture before adding any pure medicine.

The amount of medicine in the 10 grams of 15% solution is

0.15 × 10 = 1.5 grams

The amount of medicine in the 25 grams of 10% solution is

0.10 × 25 = 2.5 grams

So the total amount of medicine in the original mixture is,

1.5 + 2.5 = 4 grams

Now let x be the amount of pure medicine added.

The total amount of medicine in the final mixture is,

4 + x

The total amount of solution in the final mixture is,

10 + 25 + x

So the concentration of the final mixture is,

(4 + x) / (10 + 25 + x)

We know that this concentration is 25%, so we can write:

(4 + x) / (10 + 25 + x) = 0.25

This is the equation that represents the situation.

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The given question is incomplete, the complete question is:

A pharmacist mixes 10 grams of a 15% medicine solution with 25 grams of a 10% medicine solution. Suppose we know that after she adds the x grams of pure medicine the pharmacists mixture is 25% medicine solution. Write an equation that represents the situation

An exponential model for the worth of the savings account is [tex]W = 1250(1.045)^t[/tex]

The worth predicted by the exponential model is greater than predicted by the linear model at the end of 2020 by $131.2.

In Mathematics, an exponential function can be modeled by using the following mathematical equation:

[tex]f(x) = a(b)^x[/tex]

Where:

Based on the information provided about the savings account, we would determine the growth rate as follows;

[tex]W = P_{0}e^{rt}[/tex]

Growth rate, r = 1/(1 - 0)ln(1250/1306)

Growth rate, r = ln(1250/1306)

Growth rate, r = 0.0438

In the form [tex]W = a(b)^t[/tex], the required exponential function is given by;[tex]W = 1250(1.045)^t[/tex]

Years = 2020 -2010 = 10 years.

From the linear function, we have:

W = 56t + 1250

W = 56(10) + 1250

W = $1,810.

From the exponential function, we have:

[tex]W = 1250(1.045)^t\\\\W = 1250(1.045)^{10}[/tex]

W = $1,941.2

Difference = $1,941.2 - $1,810

Difference = $131.2.

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The speed of the particle is 8 m/s, the force of resistance is [tex]0.3(8)^2[/tex], or 19.2 N.

A particle of mass 1.2 kg is moving with a speed of 8 m/s in a straight line on a horizontal table. A resistance force is applied to the particle in the direction of the motion. The magnitude of the force is proportional to the square of the speed, such that [tex]F=0.3v^2[/tex]

The force of resistance is an opposing force that acts to reduce the speed of the particle. As the particle moves faster, the resistance force increases. The force is proportional to the square of the speed, meaning that if the speed doubles, the force is multiplied by four. The force is also in the same direction as the motion, meaning that it will reduce the speed of the particle.

The equation for the force of resistance is [tex]F=0.3v^2[/tex], where v is the speed of the particle. Therefore, if the speed of the particle is 8 m/s, the force of resistance is [tex]0.3(8)^2,[/tex] or 19.2 N. This means that the force of resistance acting on the particle is 19.2 N.

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The bottom of the ladder is moving at a rate of 4/3 ft per second.

To solve the problem, we can use the Pythagorean Theorem:[tex]$x^2 + y^2 = 64$[/tex], where x is the distance from the wall to the bottom of the ladder and y is the length of the ladder. We differentiate this equation with respect to time t and use the chain rule to get [tex]$\frac{d}{dt} (x^2 + y^2) = \frac{d}{dt} 64$[/tex]

Simplifying, we get

[tex]$2x \frac{dx}{dt} + 2y \frac{dy}{dt} = 0$[/tex]

When the bottom of the ladder is 4 feet from the wall, we have x = 4 and y = 8, so we can substitute these values into our equation and solve for [tex]$\frac{dx}{dt}$[/tex]:

[tex]$2(4)\frac{dx}{dt} + 2(8)(-2) = 0$[/tex]

[tex]$\frac{dx}{dt} = \frac{16}{8} = \frac{4}{3}$[/tex]

Therefore, the bottom of the ladder is moving at a rate of [tex]$\frac{4}{3}$[/tex] ft/s.

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Step-by-step explanation:

Which of the following shows an example of two irrational numbers being multiplied to get a rational number?

Responses

option c

Answer:

Step-by-step explanation:

a. 100 divided by 75 = 1.3333333333333333333333333333333

1.3333333333333333333333333333333 times 43 = 57.333333333333333333333333333332

round it to the nearest whole number: ≅ 57%

The value of mean should be adjusted to 12 + 2.576σ so that 99% of the cans will contain 12 oz or more.

The process mean can be adjusted through calibration. The mean is a measure of central tendency in a dataset that represents the average value of a group of data. The population standard deviation is denoted by σ. The formula for the population mean is as follows: μ = (Σ xi) / n, where xi represents the data values and n represents the total number of data values.

Here we can use the formula of confidence interval as,μ±z σ/√n, Where μ is the mean, z is the z-score, σ is the standard deviation is the sample size. Given,The required confidence level is 99%. So,α = 1-0.99α = 0.01. We can find z from the z-score table at α/2 = 0.005 as, z = 2.576.

Now, we need to find out the value of μ when the mean will be 12 ounces so that 99% of cans will contain 12 ounces or more. So,μ ± z σ/√n = 12. We know that, P(X > 12) = 0.99. The formula for standardization is, Z = (X - μ) / σHere, X = 12, σ is given and we need to find the value of μ.z = (X - μ) / σ2.576 = (12 - μ) / σμ - 12 = 2.576 × σμ = 12 + 2.576 × σ.

Now, the value of μ should be adjusted to 12 + 2.576σ so that 99% of the cans will contain 12 oz or more.

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Alexis has 12 quarters and 8 dimes.

Let's use d to represent the number of dimes and q to represent the number of quarters. We know that Alexis has a total of 20 coins, so d + q = 20.

We also know that the value of these coins is $3.80. Since dimes are worth $0.10 and quarters are worth $0.25, we can write an equation for the total value in cents:

10d + 25q = 380

To make things easier, let's divide both sides of the equation by 5:

2d + 5q = 76

Now we can use the first equation to solve for d in terms of q:

d + q = 20

d = 20 - q

Substituting this into the second equation gives:

2(20 - q) + 5q = 76

Expanding the parentheses and simplifying, we get:

40 - 2q + 5q = 76

3q = 36

q = 12

Therefore, Alexis has 12 quarters. We can check this by plugging q back into the first equation to find that she has 8 dimes as well:

d + q = 20

d + 12 = 20

d = 8

The total value of 12 quarters and 8 dimes is:

12 quarters x $0.25 per quarter + 8 dimes x $0.10 per dime = $3.00 + $0.80 = $3.80


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The measure of angle R in ΔSRT which is drawn inside the circle is 77.5°.

Circle is a two-dimensional shape that is defined as the set of all points that are equidistant from a central point. It is often represented as a round shape with a curved boundary.

Since SR is a diameter of the circle, it follows that angle STR is a right angle (90°). Therefore, we can find the measure of angle SRT using the following equation:

∠SRT + ∠STR = 180°

(2x-23°) + 90° = 180°

2x + 67° = 180°

2x = 180° - 67°

2x = 113°

x = 56.5°

∠TRS = 5x-97°

∠TRS = 5(56.5°)-97°

∠TRS = 192.5°

Finally, we can find the measure of angle SRT:

∠SRT = 180° - ∠STR - ∠TRS

∠SRT = 180° - 90° - 192.5°

∠SRT = -102.5°

Therefore, to find the measure of angle R, we need to add 180° to angle SRT:

∠R = ∠SRT + 180°

∠R = -102.5° + 180°

∠R = 77.5°

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A. The equation of the line is expressed as: y = (-5/2)x + 13.

B. The x-intercept of the equation is calculated as: 26/5.

A. We can use the point-slope form of a linear equation:

y - y1 = m(x - x1), where m is the slope and (x1, y1) is the given point, to find the equation of a line passing through the point (4,3) with a slope of -5/2.

Substituting the values, we get y - 3 = (-5/2)(x - 4), which simplifies to y = (-5/2)x + 13 by expanding and adding 3 to both sides.

B. To find the x-intercept of the equation y = (-5/2)x + 13, we set y to 0 and solve for x. 0 = (-5/2)x + 13, which simplifies to x = 26/5 by multiplying both sides by -2/5 and adding (26/5) to both sides.

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Answer:

The answer should be 20,365.714 but I am not sure

Step-by-step explanation:

The sum of the first 50 terms is 3775. Let a be the first term and d be the common difference of the arithmetic sequence.

Then, the tenth term is a + 9d = 28, and the sum of the fifth and seventh terms is 2a + 12d = 32.

Solving these equations simultaneously, we get a = 2 and d = 3.

To find the sum of the first 50 terms, we use the formula for the sum of an arithmetic sequence:

S50 = (50/2)(2a + (50-1)d) = 25(2 + 49(3)) = 3775.

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