Three and seven tenths times five

Answer:

(a) To find the value of a and d, we use the formula for the sum of first n terms of the arithmetic series A which is given by:Sn = n/2[2a + (n-1)d]We are also given that Sn = 15 + 2n. So we can equate these two expressions to get:15 + 2n = n/2[2a + (n-1)d]Multiplying both sides by 2 and simplifying, we get:30 + 4n = n[2a + (n-1)d]Expanding the brackets and simplifying, we get:2an + nd - d + 30 = 2n^2Rearranging terms, we get:2a = 2n^2 - nd + d - 30Now we also know that the first term of the series A is a. So we can substitute this value of a in the formula above to get:a = (2n^2 - nd + d - 30)/2Simplifying, we get:a = n^2 - (n-1)d - 15Therefore, we have found the values of a and d in terms of n. (b) To find the 20th term of A, we use the formula for the nth term of an arithmetic series which is given by:an = a + (n-1)dSubstituting the value of a and d that we found in part (a) we get:a20 = (20^2 - 19d - 15) + 19dSimplifying, we get:a20 = 391 - dTherefore, the 20th term of A is given by a20 = 391 - d.(c) Given that S2p - 2Sp = 1 + S(p-1), we can use the formula for the sum of first n terms of an arithmetic series which we used in part (a) to get:2p/2[2a + (2p-1)d] - 2p/2[2a + (p-1)d] = 1 + p/2[2a + (p-2)d]Simplifying, we get:2apd = d(p^2 - 3p + 2)Dividing both sides by d and simplifying, we get:2ap = p^2 - 3p + 2Rearranging terms, we get:p^2 - 3p + (2-2ap) = 0This is a quadratic equation with coefficients a=1, b=-3, and c=2-2ap. We can use the quadratic formula to solve for p:p = [3 ± sqrt(9 - 4(1)(2-2ap))]/2Simplifying, we get:p = [3 ± sqrt(4ap + 1)]/2Therefore, we have found the value of p in terms of a.

The mode of this data set is 3 inches.

In the given data set, the values of rainfall in inches for each week are as follows:

Week 1: 2 inches

Week 2: 3 inches

Week 3: 1 inch

Week 4: 3 inches

Week 5: 5 inches

Week 6: 4 inches

The mode is the value that appears most frequently, which in this case is 3 inches. Therefore, the mode of this data set is 3 inches.

Note that a data set can have more than one mode if there are two or more values that appear with the same frequency and are more frequent than any other value in the data set.

However, in this data set, there is only one mode, which is 3 inches.

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An [tex]11[/tex]-vertex full graph has around [tex]19,958,931,200[/tex] Hamiltonian circuits in a complete graph.

At one vertex, the Hamiltonian route begins, and at another, it finishes. Yet, when following a Hamiltonian route, every vertex is encountered. At the same vertex, the Hamiltonian circuit begins and terminates. For instance, if a Hamiltonian circuit's path began at vertex 1, the loop will also conclude at that vertex.

Single circuit is the sole trip a Hamiltonian circuit makes to each vertex. It must begin and terminate at same vertex since it is a circuit. A Hamiltonian route does not start and end in a single location, but it does visit each vertex just once with no repetitions.

We have to divide by [tex]2(n-2)[/tex]

[tex]11!/(2(11-2)!) = 11!/2,520[/tex] Hamiltonian circuits we get:

[tex]11!/2,520 = 19,958,931,200[/tex]

Therefore, there are approximately [tex]19,958,931,200[/tex] Hamiltonian circuits in a complete graph with [tex]11[/tex] vertices.

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The area of the equilateral triangle is 36√3 square units

What is area of the equilateral triangle?

Area of an equilateral triangle is equal to(√3/4)a², where an is the length of the triangle's side.

In an equilateral triangle, the center, the centroid, and the circumcenter coincide.

The distance between the center and a vertex is 6cm, which is also the radius of the circumcircle.

The side length is [tex]6(3)^{1/2}[/tex], which is twice the length of the radius.

So, the radius of the circumcircle is 6 cm, and the length of each side of the equilateral triangle is 12 cm.

The area of an equilateral triangle with side length s is given by:

A = (s² * √3) / 4

Substituting s = 12, we get:

A = (12² * √3) / 4

= 36√3

Therefore, the area of the equilateral triangle is 36√3 square units.

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out of the families that have DS, 20 have both, so subtract them from the absolute to get 124 - 20 = 104.

out of the families that have WII, 20 have both, so subtract them from the all-out to get 186 - 20 = 166.

you presently have 3 classifications that are unadulterated.

104 own DS in particular.

266 own WII in particular.

20 own both.

the complete that possesses either a DS or a WII however not both is equivalent to 104 + 266 = 370.

you need to subtract 20 from every classification since it is remembered for both.

it is remembered for DS and it is remembered for WII.

Market surveys are apparatuses to straightforwardly gather criticism from the interest group to grasp their qualities, assumptions, and prerequisites. Marketers foster previously unheard-of techniques for impending items/benefits however there can be no affirmation about the outcome of these methodologies.

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the complete question is:

A company conducted a marketing survey for families with young children and found that 124 families own a Nintendo DS and 186 families own a Nintendo Wii. If 20 own a Wii and a DS, how many own either a Wii or DS, but not both?

p(x)= (x-4)²-(x-6)². ... 4X - 20 = 0 => X = 20/4 => X= 5.

To solve triangle ABC, we can use the Law of Cosines, which states that for any triangle with sides a, b, and c and opposite angles A, B, and C, respectively:

c^2 = a^2 + b^2 - 2ab*cos(C)

We are given B, a, and b, so we can solve for c as follows:

c^2 = 25^2 + 41^2 - 2(25)(41)cos(64)

c^2 = 625 + 1681 - 2135cos(64)

c^2 = 1829 - 2135*cos(64)

c^2 = 311.90

Taking the square root of both sides, we get:

c ≈ 17.7

So the length of side c is approximately 17.7 units.

To find the measures of angles A and C, we can use the Law of Sines, which states that for any triangle with sides a, b, and c and opposite angles A, B, and C, respectively:

a/sin(A) = b/sin(B) = c/sin(C)

We know a, b, and c, and we just solved for c, so we can use the Law of Sines to solve for angles A and C:

a/sin(A) = c/sin(C)

sin(A) = asin(C)/c

A = sin^{-1}(asin(C)/c)

A = sin^{-1}(25*sin(C)/17.7)

Similarly,

b/sin(B) = c/sin(C)

sin(B) = bsin(C)/c

B = sin^{-1}(bsin(C)/c)

B = sin^{-1}(41*sin(C)/17.7)

To find angle C, we can use the fact that the sum of the angles in a triangle is 180 degrees:

C = 180 - A - B

Using a calculator, we get:

A ≈ 41.6 degrees

B ≈ 74.1 degrees

C ≈ 64.3 degrees

Therefore, the measures of the angles in triangle ABC are approximately:

A ≈ 41.6 degrees

B = 64 degrees

C ≈ 64.3 degrees

And the lengths of the sides are approximately:

a = 25

b = 41

c ≈ 17.7

Therefore , the solution of the given problem of unitary method comes out to be the parking lot has 60 trucks.

It is possible to accomplish the objective by using this widespread convenience, pre-existing variables, or all significant components from the initial Diocesan adaptable survey that adhered to a specific methodology. If it doesn't, both of the essential components of a term confirmation outcome will undoubtedly be lost, but if it is, there is going to be another opportunity to contact the entity.

Here,

Let's begin by giving the unknowns variables:

x = number of vehicles

Van count = 4 times

Since there are 205 cars overall, the number of lorries is equal to (205 - 11x).

The value of x can be determined using the second bit of knowledge:

=> 4x/3 = (205 - 11x)/2

When we simplify this solution, we obtain:

=> 8x = 3(205 - 11x)

=> 8x = 615 - 33x

=> 41x = 615

=> x = 15

We can now determine the quantity of vans:

Van count = 4x = 4(15) = 60

Consequently, the parking lot has 60 trucks.

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Answer:

measure of angle MPQ is 125

Step-by-step explanation:

1) Corresponding angles are congruent

5x=3x+50

2x=50

x=25

2) Substitute back into the equation

3(25)+50 = 125

Therefore, the correct answer is: The range is the best measure of variability, and it equals 78.

Range is a measure of variability that represents the difference between the maximum and minimum values in a dataset. It gives an indication of how spread out the data is. To find the range of a dataset, you simply subtract the minimum value from the maximum value. Range is often used as a quick and simple measure of variability, but it can be sensitive to outliers and extreme values.

Here,

1. For question 5, the appropriate measure of variability for the given data set is the range, which is the difference between the maximum value and the minimum value in the data set.

To find the maximum and minimum values from the given stem-and-leaf plot, we can look at the highest and lowest digits in each row. The highest value is 83 and the lowest value is 5, so the range is:

Range = 83 - 5 = 78

2. For question 6, the appropriate measure of center to represent the data in the given line plot is the median, because the data is skewed to the right and there are outliers present. The median is less sensitive to outliers than the mean.

Therefore, the correct answer is: The median is the best measure of center because there are outliers present.

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The area of the figure rounded to the nearest square meter is 97 m². So correct option is A.

With five equal sides and five equal angles, a regular pentagon is a polygon. In other words, a regular pentagon's sides and angles are all congruent. It is a closed, two-dimensional object that is categorized as a sort of polygon since it is constructed of straight line segments.

Regular pentagons have a number of distinctive features, including:

A regular pentagon has 108 degree internal angles that are all equal.

A standard pentagon's outside angles are all 72 degrees in angle.

A regular pentagon is divided along its diagonals into three smaller triangles, two of which are congruent.

Regular pentagons are prevalent in a variety of fields, including geometry, architecture, and the arts.

First, you would need to determine the side length of the regular hexagon. This can be done using the radius of the circumscribed circle, which is given as 5 meters. The side length of the hexagon can be calculated using the formula:

s = r * √(3)

where s is the side length and r is the radius of the circumscribed circle. Plugging in the given value for r, we get:

s = 5 * √(3)

simplifying, we get:

s ≈ 8.7 meters

Next, you would need to calculate the area of one of the congruent triangles. This can be done using the formula:

A = (1/2) * b * h

where A is the area of the triangle, b is the base, and h is the height. The base of the triangle is equal to one side of the hexagon, which we just calculated to be approximately 8.7 meters. To find the height, we can draw an altitude from one vertex of the triangle to the opposite side, creating a 30-60-90 right triangle. The height is equal to the shorter leg of this triangle, which can be calculated using the formula:

h = (1/2) * s * √(3)

Plugging in the value for s, we get:

h ≈ 7.5 meters

Now we can calculate the area of one of the triangles:

A = (1/2) * 8.7 * 7.5 ≈ 32.6 square meters

Finally, we can calculate the total area of the figure by adding the area of the hexagon to three times the area of one of the triangles:

A = 6 * (s²) * √(3)/4 + 3 * A

Plugging in the values we calculated, we get:

A ≈ 96.9 square meters

Rounding to the nearest square meter, we get:

A ≈ 97 square meters

Therefore, the answer is A. 97 m².

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If the first and last pages of a document must be printed in color, and only two printers can print in color, then there are a total of 4⁹⁹ ways that 100 pages can be assigned for printing to four printers.

The fundamental principle of counting says that if there are p ways to do one thing and q ways to do another thing, then there are p×q ways to do both things. Number of printers that is able to print in color = 2

Number of colors printed by printers = 2

We have to determine the number of ways are there for the 100 pages to be assigned to the four printers. Now, consider there are no restrictions. Let's break this problem into two parts. First, we have to print 2 pages in color and there are only two color printers. So, number of ways to print the first and the last page of the document = 2²

= 4

Number of remaining pages of document = 98

Number of avaliabile printers = 4

Now, second part, we have only 98 pages (out of 100 pages, 2 colors pages are already printed). Each of these 98 pages can be assigned to a printer in 4 ways. So, number of ways to print remaining 98 pages of document = 4⁹⁸.

Using the counting principle, number of ways for printing the 100 pages by four printers = 2² × 4⁹⁸

= 4 × 4⁹⁸ = 4⁹⁹

Hence, required number of ways are 4⁹⁹.

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The frequency table shows that there is a relationship between buying a hot dog and buying a drink at a baseball game. The huge 70.2% is evidence of this.

The frequency table is meant to show the relationship between variables. Of all the values provided, the relationship with the highest percentage is 70.2%.

This shows that the number of people who purchased a hot dog while also purchasing a drink constituted the highest number. None of the figures come close to this one. So, there is a strong relationship between the variables.

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The government rectangular survey consisting SW 1/4, NE 1/4, and NW 1/4 of Section 13 in Blendon Township covers 480 acres.

We have,

In the Government Rectangular Survey System, a section is a square tract of land measuring 1 mile by 1 mile, covering an area of 640 acres.

Each section is divided into quarters.

If we consider the SW 1/4, NE 1/4, and NW 1/4 of Section 13 in Blendon Township, the total acreage can be calculated as follows:

SW 1/4:

This represents one-fourth of the section.

The SW 1/4 of Section 13 is 640 acres / 4 = 160 acres.

NE 1/4:

The NE 1/4 of Section 13 is also 160 acres.

NW 1/4:

The NW 1/4 of Section 13 is 160 acres.

To find the total acreage, add up the individual acreages:

160 acres (SW 1/4) + 160 acres (NE 1/4) + 160 acres (NW 1/4)

= 480 acres

Therefore,

The government rectangular survey consisting SW 1/4, NE 1/4, and NW 1/4 of Section 13 in Blendon Township covers 480 acres.

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The geometric sequence is 9 + 2 + 20 = 29.

The smallest number the third term in the geometric sequence can be is 29.

This is because when you add 2 to the second term and 20 to the third term of the three-term arithmetic sequence with a first term of 9,

the third term of the geometric sequence is 9 + 2 + 20 = 29.

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a) The rate of change of the drug's concentration at 50 minutes is 1.7 mg/min.

b) The rate of change of the drug's concentration at 85 minutes is 0.2 mg/min.

c) The drug's concentration is decreasing at 115 minutes.

a) The central difference approach can be used to calculate the rate of medication change after 50 minutes.

f'(x) = (f(x+h) - f(x-h))/2 × h    ....(1)

As per the question, we have h = 10 and x = 50

Substitute the values of h = 10 and x = 50 in (1),

f'(40) = (f(50+10) - f(50-10))/2 × 10

f'(40) = (89-55)/20

f'(40) = 1.7 mg/min

b) For the rate of change of concentration at 85 minutes:

Here, f(80) = 111 mg and f(90) = 113.

The concentration at 90 minutes is 113 mg.

Rate of change = (f(90) - f(80)) / h

= (113 - 111) /10

= 2 / 10

= 0.2 mg/min

c) Since the concentration at 120 minutes (68 mg) is lower than the concentration at 110 minutes (103 mg), the drug's concentration is decreasing.

Therefore, the drug's concentration is decreasing at 115 minutes.

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There are 13,225 different ways to select a committee of size 3 from a group of 15 people, where one person will be president, one will be vice president, and one will be treasurer.

To calculate this, we can use a combination formula. The formula for combinations is nCr = n! / (r! * (n - r)!), where n is the size of the group and r is the number of people in the committee.

In this case, n = 15 and r = 3.

Using this formula, we can calculate that there are 15! / (3! * (15 - 3)!) = 13,225 different ways to select a committee of size 3 from a group of 15 people, where one person will be president, one will be vice president, and one will be treasurer.

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The required number of multiplications using a single composite transformation matrix for k transformations of n points is n × k.

In computer graphics, composite transformation matrices are used to transform points and shapes. These matrices are created by combining multiple transformations into a single matrix, allowing for efficient processing of large amounts of data. The number of multiplications required to perform a composite transformation depends on the number of points being transformed and the number of transformations being applied.

If there are n points and k transformations, then the required number of multiplications is n × k.

This is because each point needs to be multiplied by the composite transformation matrix k times.

Therefore, the total number of multiplications is n × k.

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Pr(total)=pr(blue)+pr(green)+pr(red)=4+1+2

=7

a) pr(blue)= pr(blue)/pr(total)=4/7

b) pr(green)= pr(green)/pr(total)=1/7

c) pr(not green)= pr(blue)+pr(red)= 4/7+2/7=6/7

d)pr(not purple)= ???

e)pr(red)=pr(red)/pr(total)=2/7

Question d seems like it is a problem cause we were not told that a purple ball was in the bag.

Answer:

15.556

Step-by-step explanation:

The length of the diagonal of a square is equal to the length of one side of the square multiplied by the square root of 2

22=x√2

 π(64a2 - 192a + 144) is the polynomial expression to find the area of 4 circles where circle has a radius of (4a-6) .

When variables and coefficients are combined using arithmetic procedures like addition, subtraction, multiplication, and non-negative integer exponents, the result is a mathematical expression known as a polynomial. Any numerical value may be represented by the variables, and the expression's coefficients are constants that combine the variables.

given

A =  πr², where r is the circle's radius, is the method for calculating a circle's surface area. The area of one circle can be expressed as follows if the radius of each circle is (4a–6):

A₁ = π(4a-6)²

If we condense this phrase, we get:

A₁ = π(16a² - 48a + 36)

A₂ = π(4a-6)²

A₂ = π(16a² - 48a + 36)

A₃ = π(4a-6)²

A₃ = π(16a² - 48a + 36)

A₄ = π(4a-6)²

A₄ = π(16a² - 48a + 36)

We can add up the areas of each of the four circles to determine their combined area:

A1 + A2 + A3 + A4 Equals A total

A total is equal to π (16a2 - 48a + 36) +  π(16a2 - 48a + 36) +  π(16a2 - 48a + 36).

 π(64a2 - 192a + 144) = A total

 π(64a2 - 192a + 144) is the polynomial expression to find the area of 4 circles where circle has a radius of (4a-6) .

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Answer:

-45

Step-by-step explanation:

To calculate the percent yield of copper (II) oxide, you need to have the actual yield and the theoretical yield. The percent yield can be calculated using the following formula: Percent Yield = (Actual Yield / Theoretical Yield) * 100

1. Obtain the actual yield: This is the amount of copper (II) oxide produced in your experiment or reaction, typically measured in grams.
2. Calculate the theoretical yield: Use the balanced chemical equation and the stoichiometry of the reaction to determine the maximum amount of copper (II) oxide that could be produced from the given reactants.
3. Plug the values into the formula: Divide the actual yield by the theoretical yield and multiply the result by 100 to get the percent yield.
If you obtained a yield different than the expected or theoretical yield, there could be several reasons, including experimental errors, impure reactants, or side reactions occurring during the process. These factors can cause the actual yield to be higher or lower than the theoretical yield.

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Thus, the explicit formula for the simple interest sequence A(n) = P + (n-1)(i.P) is: A(n) = P * (1 + i * (n-1)).

Simple interest is a method of calculating interest on a loan or investment where interest is charged only on the initial principal amount. In simple interest, the interest rate is applied to the original principal amount, and the interest earned remains the same throughout the entire term of the loan or investment.

by the question.

The formula for a simple interest sequence A(n) = P + (n-1) (i.P) represents the value of an investment that earns simple interest over n periods, where:

A(n) is the value of the investment after n periods.

P is the principal or initial investment

i is the interest rate per period as a decimal fraction (e.g. 0.05 for 5%)

n is the number of periods

To derive the explicit formula for A(n), we can use the formula for simple interest:

I = P * i * n

where I am the total interest earned over n periods. We can then express A(n) as:

A(n) = P + I

Substituting the expression for I, we get:

A(n) = P + P * i * (n-1)

Simplifying, we can factor out P to get:

A(n) = P * (1 + i * (n-1))

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Let's denote the width and length of the pool by “w” and “l” respectively. Then, the width of the pool and deck combined would be:So the equation that represents the total area of the pool and deck as binomials is [tex]: A = 2(L + 8)(2L + 8)[/tex]

Let's start by drawing a diagram of the rectangular pool and the surrounding deck:

 ___________  Pool Length (L)

|           |

|           |

|           |

|           |

W|___________|

| Deck Width|

|    = 4ft  |

|___________|

We know that the width of the pool (W) is twice its length (L), so we can write:

[tex]W = 2L[/tex]

We also know that the deck is 4ft wide on each side, so the total width of the pool and deck is:

[tex]W_total = W + 8 = 2L + 8[/tex]

And the total length of the pool and deck is:

[tex]L_total = L + 8[/tex]

The total area of the pool and deck can be found by multiplying the total width by the total length:

[tex]A = W_total \times L_total[/tex]

Substituting our expressions for W_total and L_total, we get:

[tex]A = (2L + 8) * (L + 8)[/tex]

Expanding the brackets, we get:

[tex]A = 2L^2 + 24L + 64[/tex]

So the equation that represents the total area of the pool and deck is:

2L^2 + 24L + 64

To represent the sides of the shape as binomials, we can factor out a common factor of 2 from the quadratic expression:

[tex]A = 2(L^2 + 12L + 32)[/tex]

Then we can write the sides of the shape as:

[tex]L + 8[/tex]   and [tex]2L + 8[/tex]

Therefore, So the equation that represents the total area of the pool and deck as binomials is: [tex]A = 2(L + 8)(2L + 8)[/tex]

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a) r = 30 cm

b) The angle AOC is 0.523598775 radian

c) The area of the shaded region is 541.9 cm²

d) The perimeter of the shaded region is 106.8 cm.

The area of a circle is a measure of the size of the surface of the circle. It is calculated by multiplying the radius of the circle (the length from the center of the circle to its edge) by itself, and then multiplying the result by the constant pi (3.14). The formula for calculating the area of a circle is A = πr2, where “A” represents the area, “π” is pi, and “r” is the radius of the circle.

The radius of the circle, r, can be determined by the Pythagorean theorem. Since AC = 36 cm and AP = 6 cm, the hypotenuse of the right triangle formed by AC and AP is the radius of the circle, r. By applying the Pythagorean theorem, we get:

r² = 362 + 62

r² = 1296

r = √1296

r = 36 cm

b) The angle AOC is 0.523598775 radians

The angle AOC can be determined using the formula for arc length. The arc length of ABC is 36 cm and the radius of the circle is 30 cm. Therefore, the angle AOC is:

AOC = 36/30

AOC = 1.2 radians

c) The area of the shaded region is 541.9 cm²

The area of the shaded region can be determined using the formula for the area of a sector. The angle AOC is 1.2 radians and the radius of the circle is 30 cm. Therefore, the area of the shaded region is:

Area = (1.2)(30)(30)/2

Area = 541.9 cm²

d) The perimeter of the shaded region is 106.8 cm

The perimeter of the shaded region can be determined using the formula for the circumference of a circle. The radius of the circle is 30 cm. Therefore, the perimeter of the shaded region is:

Perimeter = 2π(30)

Perimeter = 106.8 cm

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the concentrations of nitrogen, phosphate, and potassium in the mixture are 13.33%, 13.67%, and 8%, respectively. To find the concentrations of nitrogen, phosphate, and potassium in the mixture, we need to calculate the total amount of each nutrient in the two bags and then divide by the total weight of the mixture.

First, let's calculate the amount of each nutrient in the 10 pound bag of 12-12-12:

Nitrogen: 12% of 10 pounds = 1.2 pounds

Phosphate: 12% of 10 pounds = 1.2 pounds

Potassium: 12% of 10 pounds = 1.2 pounds

Next, let's calculate the amount of each nutrient in the 5 pound bag of 16-17-0:

Nitrogen: 16% of 5 pounds = 0.8 pounds

Phosphate: 17% of 5 pounds = 0.85 pounds

Potassium: 0% of 5 pounds = 0 pounds

Now, let's add up the total amount of each nutrient in the two bags:

Nitrogen: 1.2 + 0.8 = 2 pounds

Phosphate: 1.2 + 0.85 = 2.05 pounds

Potassium: 1.2 + 0 = 1.2 pounds

Finally, let's divide the total amount of each nutrient by the total weight of the mixture (10 + 5 = 15 pounds) and express the answers as percentages:

Nitrogen: (2 / 15) x 100% = 13.33%

Phosphate: (2.05 / 15) x 100% = 13.67%

Potassium: (1.2 / 15) x 100% = 8%

Therefore, the concentrations of nitrogen, phosphate, and potassium in the mixture are 13.33%, 13.67%, and 8%, respectively.

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The central limit theorem is a statistical theory that specifies the probability distribution of a sum or average of several random variables whose distribution is not known.

It is an important theorem since it is utilized to help forecast or estimate the behavior of a specific set of data.

This theorem holds that when you take repeated samples of the same size from a population with a finite standard deviation, the means of those samples will be normally distributed, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

Further more, the theorem indicates that the larger the sample size, the more closely the sample mean distribution will approximate a normal distribution.

This is why it is vital in the development and use of statistical quality control techniques, since they rely on correct assumptions about the population’s normality.

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The length of Tanya's mural is 28 feet.

A rectangle is a 2-dimensional shape with parallel opposite sides equal to each other and four angles are right angles.

Area of a rectangle is expressed as;

Area = length × width

We know that the area of Tanya's mural is 224 square feet, and the height of the mural is 8 feet.

So we can use these values to find the length of the mural:

Area = length × width

224 = length × 8

To solve for the length, we can divide both sides of the equation by 8:

length = 224 ÷ 8

length = 28 feet

Therefore, the dimension of the length is 28 feet.

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The center of a dilation is a fixed point in the plane about which all points are expanded or contractedAnswer:

Step-by-step explanation: