1) The x-intercept lies at (1, 14), and the y-intercept lies at (3, 42).
2) This means that after 3 cuts, the length of the string is 33 inches.
3) Therefore, the 42-inch string can be cut into 14 pieces of 3 inches each.
What are the x- and y-intercepts?The x-intercept is the point on the graph where a line crosses the x-axis.
The y-intercept is the point on the graph where a line crosses the y-axis.
The x- and y-intercepts are the coordinate points for graphing data.
Thus, the x- and y-intercepts are coordinate points where the graph of a function or an equation touches the two axes.
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How many ways can four guests sit in a row of six chairs?
Answer:
360
Step-by-step explanation:
There are 6 spaces and 4 people.
_ _ _ _ _ _
The first person to choose a seat can choose any of the 6 seats.
The second person can choose any of the 5 remaining seats.
The third person can choose any of the 4 remaining seats.
The fourth person can choose any of the 3 remaining seats.
Now, we do 6 x 5 x 4 x 3 to figure out the total number of ways they can sit in the seats.
6 x 5 x 4 x 3 = 360 ways
The coordinates of rhombus abcd are a(-4,-2) b(-2,6) c(6,8) d(4,0). What is the area of the rhombus
First, graph the rhombus:
Area of a rhombus = Product of diagonals / 2
Find the length of the diagonals:
Distance between points:
[tex]\sqrt[\placeholder{⬚}]{(x2-x1)^2+(y2-y1)2^}[/tex]Diagonal AC
[tex]AC=\sqrt[\placeholder{⬚}]{(6-(-4))^2+(8-(-2))^2}[/tex]AC= 10√2
Diagonal BD
[tex]BD=\sqrt[\placeholder{⬚}]{(4-(-2))^2+(0-6)^{^2}}[/tex]BD=6√2
Area= AC x BD / 2
Area = [(10√2) x (6√2)]/2
Area = 60
Determine if the correlation between the two given variables is likely to be positive or negative, or if they are not likely to display a linear relationship.The number of times a person exercises per week and their endurance.
Answer:
[tex]\text{Positive Correlation}[/tex]Explanation:
Here, we want to determine the type of correlation relationship
From science, we understand that engaging in exercise helps internal organs to function better. These are the sources of endurance
Exercising for a couple of more times, all things being equal means there will be more endurance. We can largely say that, for most people, it is expected that the higher the number of time spent exercising, the higher the endurance being built
Thus, we can conclude there is a positive correlation between the two
Find all possible values of the expression 1/a
1/2
__<1/a<__
The possible values of the expression 1/a = 1/2 is 2
The expression is the simple fraction form = 1/a
The expression is the defined as the a sentence with a minimum of two variables and at least one math operation.
The simple fraction is fraction that contains the numerator and denominator as whole number. The term one the top of the simple fraction called as the numerator and bottom term is called as the denominator.
Here it is given that
1/a = 1/2
Therefore the value of a = 2
Hence, the possible values of the expression 1/a = 1/2 is 2
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(8.59×10 4 )−(3.2×10 3 )
Answer:
The answer is 8.27×10^4
Answer: 8.27×10^4
Step-by-step explanation:
10. Evaluate (14-2)÷3(2-3) - 2²Mark only one oval.A. OB. 2C. 20D. 22
Order of the operations: parentheses, exponentials, division and multiplication, addition and subtraction.
1. Solve operations in parentheses:
[tex]=12\div3\cdot6-2^2[/tex]2. Solve exponentials:
[tex]=12\div3\cdot6-4[/tex]3. Solve division:
[tex]=4\cdot6-4[/tex]4. Solve multiplication:
[tex]=24-4[/tex]5. Solve subtraction:
[tex]=20[/tex]Then, the solution for the given expression is 20Answer: Answer is 20( please make me brainliest i just did this all in my head)
Step-by-step explanation: soo (14-2) =12 12divided by 3=4 so (2*3)= 6 so 4x6=24 24-2*2 =20 (2*2)=4 so 24-4=20 well this is confusing but i tried my best so hope my answer wasn't toooo confusing lol :)
When using elimination, when should you add the equations, and when should you subtract the equations?
Answer:
In the elimination method you either add or subtract the equations to get an equation in one variable. When the coefficients of one variable are opposites you add the equations to eliminate a variable and when the coefficients of one variable are equal you subtract the equations to eliminate a variable.
You're very welcome my sir or ma'am
A triangle has 2 angles measuring 40 degrees and 50 degrees. What is the measure of the 3rd angle and classify the triangle.
A triangle has all three angles summing up to 180. If two of the sides measure 40 degrees and 50 degrees, then the third side measures as follows;
[tex]\begin{gathered} 40+50+A=180 \\ A=180-40-50 \\ A=90 \end{gathered}[/tex]The third angle, which is labelled as angle A measures 90 degrees, and that means the triangle is a "right angled triangle."
PEOPLE PLEASE HELP GO ON MY PROFIL AND HELP ME with the things i put today i really need help please help HELP HELP HELP ME PLEASE I NEED HELP!
Step-by-step explanation:
i don't knowhdjkedgeike
what is the difference written in scientific notion?0.00067 - 2.3 * 10^-5
Answer:
[tex]6.47\times10^{-4}[/tex]Explanation:
To evaluate the difference:
[tex]0.00067-2.3\times10^{-5}[/tex]First, rewrite the expression in the form below:
[tex]=67\times10^{-5}-2.3\times10^{-5}[/tex]Next, factor out the powers of 10.
[tex]\begin{gathered} =10^{-5}(67-2.3) \\ =10^{-5}(64.7) \\ =64.7\times10^{-5} \\ =6.47\times10^1\times10^{-5} \\ =6.47\times10^1^{-5} \\ =6.47\times10^{-4} \end{gathered}[/tex]Thus, the difference written in scientific notation is:
[tex]6.47\times10^{-4}[/tex]Note: A number is in scientific notation if it is expressed as a product of a number (between 1 and 10) and a power of 10.
|x + 6| < or equal to 1
8
x < or equal to 2
x < or equal to ?
Answer: -14
Step-by-step explanation:
[tex]\frac{1}{8}|x+6| \leq 1\\\\|x+6| \leq 8\\\\-8 \leq x+6 \leq 8\\\\-14 \leq x \leq 2[/tex]
i need help with this sorry I cant give much
Answer:
[tex]\frac{11}{20}[/tex]
Step-by-step explanation:
2[tex]\frac{3}{4}[/tex] ÷ 5
Convert mixed number fraction to improper fraction
[tex]\frac{11}{4}[/tex] ÷ 5
To divide fractions we turn the second fraction (the one you want to divide by) upside down (this is now called a reciprocal) and we multiply
[tex]\frac{11}{4}[/tex] × [tex]\frac{1}{5}[/tex] = [tex]\frac{11}{20}[/tex]
3|y|+(y-x²)
if x = -1 and y = -5
This math question please
A. 2x-1+3x=0 B. 5x-1=0 How can we get Equation B from Equation A ?
By taking x as a common factor we get:
2x - 1 + 3x = 0
(2 + 3)*x - 1 = 0
5x - 1 = 0
How to get equation B from equation A?Let's start with equation A, it is:
2x - 1 + 3x = 0
If we group like terms, we will get:
(2x + 3x) - 1 = 0
Now we can take x as a common factor in the left term, so we get:
(2x + 3x) - 1 = 0
(2 + 3)*x - 1 = 0
Now we simplify the sum in the left term:
(2 + 3)*x - 1 = 0
5x - 1 = 0
This is equation B.
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If the measures of two angles of a triangle are 96° and 29°, what is the measure of the third angle?
Answer: measure of the third angle is 55 degrees
Step-by-step explanation: the sum of all interior angles in a triangle is always 180 so, 96+29+x=180.
125+x=180
x=55
Working alone, it takes Kristen 10.2 hours to harvest a field. Kayla can harvest the same field in 16.5 hours. Find how long it would take them if they worked together.
ANSWER:
13.35 hours
EXPLANATION:
Given:
Time Kristen takes to harvest = 10.2 hours
Time Kayla takes to harvest = 16. 5 hours
Let X represent the time it would take them to work together.
Here, to find the time it would take them if they worked together, let's find their mean time, using the formula below:
[tex]X\text{ = }\frac{Time\text{ taken by kristen + Time taken by Kayla}}{2}[/tex][tex]\begin{gathered} X\text{ = }\frac{10.2\text{ + 16.5}}{2} \\ \\ X\text{ = }\frac{26.7}{2} \\ \\ X\text{ = }13.35\text{ hours} \end{gathered}[/tex]It would take them 13.35 hours if they worked together.
Will and Sarah are racing across the playground. Instead of running, they are hopping. During the race, they must both hop at the same time. In one hop, Will can travel 5 feet, and Sarah can travel 4 feet.
The playground is 200 feet wide. Will wins the race after hopping 40 times. How far had Sarah hopped when Will finished the race?
I know the answer i just need explanation.
Sarah has hopped for 160ft when Will finished the race.
What is basic arithmetic?
Specific numbers and their computations employing a variety of fundamental arithmetic operations are at the center of arithmetic mathematics. Algebra, on the other hand, deals with the limitations and guidelines that apply to all other types of numbers, including whole numbers, integers, fractions, functions, and so on. Arithmetic math serves as the foundation for algebra, which always adheres to its definition. A large range of subjects fall within the broad definition of mathematics, which encompasses a very broad range of topics. Beginning with the fundamentals like addition, subtraction, and division of numbers, they then move on to more complicated topics like exponents, variations, sequence, progression, and more. This part does touch on some of the mathematical formulas and mathematical sequence. Four essential mathematical operations—addition, subtraction, multiplication, and division—are covered in basic arithmetic.
For Will
5 × 40
= 200 feet
For Sarah
4 × 40
= 160 ft
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Solve the inequality for x. Show each step of the solution.
12(x+3)>4x-8
Answer:
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
12x+36>4x−8
Step 2: Subtract 4x from both sides.
12x+36−4x>4x−8−4x
8x+36>−8
Step 3: Subtract 36 from both sides.
8x+36−36>−8−36
8x>−44
Step 4: Divide both sides by 8.
8x/8 > -44/8
Therefore your answer will now equal [tex]x > \frac{-11}{2}[/tex]
[tex]{ \boxed{ \pink{ \sf{x > - \frac{11}{2}}}}}[/tex]
Step-by-step explanation:
The given inequality is, [tex]{ \green{ \sf{12(x + 3) > 4x - 8}}}[/tex]
[tex]{ \star}[/tex]Step 1: Simplify both the sides of inequality.
[tex]{ \green{ \sf{12x + 36 > 4x - 8}}}[/tex]
[tex]{ \star}[/tex]Step 2: Now Subtract 4x from both sides.
[tex]{ \purple{ \sf{12x+36−4x> { \cancel{4x}−8{ \cancel{−4x}}}}}}[/tex]
[tex]{ \purple{ \sf{8x+36>−8}}}[/tex]
[tex]{ \star}[/tex]Step 3: Subtract 36 from both sides.
[tex]{ \blue{ \sf{8x+{ \cancel{36}{ \cancel{−36}}}>−8−36}}}[/tex]
[tex]{ \blue{ \sf{8x>−44}}}[/tex]
[tex]{ \star}[/tex]Step 4: Divide both sides by 8.
[tex]{ \orange{ \sf{ \frac{ \cancel8}{ \cancel8} x > - \frac{ \cancel{44^{ \blue{ \tt{11}}}} }{ \cancel8_{ \blue{ \tt{2}}} }}}} [/tex]
[tex]{ \boxed{ \red{ \sf{x > - \frac{11}{2}}}}} [/tex]
Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. The sample of 2100 bacteria selected from this population reach the size of 2249 bacteria in two and a half hours. Find the hourly growth rate parameter.This is a continuous exponential growth model.Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.
In this problem, we have a continuous exponential growth model
so
the equation is of the form
[tex]y=a(e)^{kt}[/tex]where
a is the initial value ------> a=2,100
y is the number of bacteria
x ----> number of hours
so
[tex]y=2,100(e)^{kt}[/tex]For x=2.5 hours, y=2,249 bacteria
substitute
[tex]2,249=2,100(e)^{(2.5k)}[/tex]solve for k
apply ln both sides
[tex]\ln (\frac{2,249}{2,100})=2.5k\cdot\ln (e)[/tex]k=0.0274
convert to percentage
k=2.74%a standard poker deck of cards contains 52 cards, of which four are kings. suppose two cards are drawn sequentially, so that one random circumstance is the result of the first card drawn and the second random circumstance is the result of the second card drawn. find the probability that the first card is a king and the second card is not a king. (round your answer to four decimal places.)
The probability that the first card is a king and the second card is not a king is 0.0045
Suppose two cards are drawn sequentially so that one random circumstance is the result of the first card drawn and the second random circumstance is the result of the second card drawn. To find the probability that the first card is a king and the second card is not a king.
In the first case let's find the probability of drawing a king from the deck of cards,
A = ( 4/52 )
In the second case the probability of drawing a card that is not a king from the deck is,
B = ( 3/51 )
At last, to get the final probability to draw that the first card is a king and the second card is not a king we need to multiply the above two cases as,
A x B = ( 4/52 ) ( 3/51 )
= 1/221
= 0.0045
The probability that the first card is a king and the second card is not a king is 0.0045
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Astronomers use a light year to measure distance. a light year is the distance light travels in one year. The speed is approximately 300,00km/sec. how long will it take a rocket traveling 63,000km/hr to reach Alpha Centauri (the ⭐ closest to Earth other than the ). Note: Alpha Centauri is approximately 4.34 light years from Earth. which is 4.11 x 10^13 km away (when using scientific notation). one light year is 9.46 x 10^12 km.
Speed of light = 300,000 km/sec
Rocket's speed = 63,000 km/hr or 6.3 x 10⁴ km/hr
Alpha Centauri distance from Earth = 4.11 x 10¹³ km
One light year (distance) = 9.46 x 10¹² km
To solve for the time it takes it travel, we can manipulate the speed formula.
[tex]\begin{gathered} \text{speed}=\frac{dis\tan ce}{\text{time}} \\ \text{time}=\frac{dis\tan ce\text{ }}{\text{speed}} \end{gathered}[/tex]We already have the distance of Alpha Centauri from Earth written above. We also have the speed of the rocket written above too. We will substitute those values to the formula.
[tex]\begin{gathered} \text{time}=\frac{4.11\times10^{13}\operatorname{km}}{6.3\times10^4\operatorname{km}\text{ /hr}} \\ \text{time}=0.6523809524\times10^9 \\ \text{time}=6.52\times10^8\text{ hr} \end{gathered}[/tex]The table shows deshawna's science grade during four grading periods. How much greater was the percentage change in her grade from grading period 1 to 2 than from grading period 2 to 3. round to nearest tenth
Since the percent grade in period 1 was 92% and in period 2 was 96%, then the percent change from period 1 to 2 was 4%.
Since the percent grade in period 2 was 96% and in period 3 was 99%, then the percent change from period 2 to 3 was 3%.
Since 4% is 1% greater than 3%, then the percent change from grading period 1 to 2 was 1% greater than the percent change from grading period 2 to 3.
Therefore, the answer is: 1.0%.
Please help ASAP starting to fall behind! This equation really confuses me and if someone could help that would be amazing!
Given the function:
f(x) = x² - 4x - 2
Find the following values.
a) f(2)
f(2)=
b) f(4)
f(4)=
c) f(-3)
f(-3)=
The values of the functions is ,
(a) f(2) = -6
(b) f(4) = -2
(c) f(-3) = 19
In the question ,
it is given that the function is f(x) = x² - 4x - 2
we have to find the value of f(2) , f(4) , f(-3)
Part(a)
to find f(2) , we substitute x = 2 in the function
On substituting , we get
f(2) = 2² - 4*2 - 2
= 4 - 8 - 2
= 4 - 10
= -6
Part(b)
to find f(4) , we substitute x = 4 in the function f(x)
On substituting , we get
f(4) = 4² - 4*4 - 2
= 16 - 16 -2
= 0 - 2
= -2
Part(c)
to find f(-3) , we substitute x = -3 in the function
On substituting , we get
f(2) = (-3)² - 4*(-3) - 2
= 9 + 12 -2
= 9 + 10
= 19
Therefore , The values of the functions is , (a) f(2) = -6 , (b) f(4) = -2 , (c) f(-3) = 19
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Use the graph of f below. Assume the entire function is graphed below.Find ƒ(−1).ƒ(−1) = 0ƒ(−1) = −3ƒ(−1) = −1ƒ(−1) = −5
Answer:
ƒ(−1) = −3
Explanation:
From the graph, we have the point (-1, -3).
This means that:
• When x=-1
,• The value of f(x)=-3.
Therefore, the value of f(-1) is -3.
For each set of points below, determine the distance between them using the distance formula. each answer in this problem will be an integer
Distance between two coordinates:
[tex]\text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Given point: b) (10, -5) and ( -6, 7)
[tex]x_1=10,y_1=-5,x_2=-6,y_2=7[/tex]Substitute the value in the expression of distance formula
[tex]\begin{gathered} \text{ Distance=}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{Distance}=\sqrt[]{(-6-10)^2+(7-(-5))^2} \\ \text{Distance}=\sqrt[]{(-16)^2+(12)^2} \\ \text{Distance}=\sqrt[]{256+144} \\ \text{Distance}=\sqrt[]{400} \\ \text{Distance = 20 unit} \end{gathered}[/tex]The distance between coordinates (10,-5) & (-6,7) is 20 unit
30. Solve for x: 7^/10 = 2, approximate to 4 digitsa. 6.325 b. 3.256 c. 3.265 d. 3.652 e. 3.562
• Solution
[tex]7^{\frac{x}{10}}=2[/tex]
To solve for x, we take the logarithm of both sides.
[tex]\log 7^{\frac{x}{10}}=\log 2[/tex]Applying the law of logarithm to the equation above;
[tex]\log a^b=b\log a[/tex][tex]\begin{gathered} \log 7^{\frac{x}{10}}=\log 2 \\ \frac{x}{10}\log 7=\log 2 \\ \text{Dividing both sides by log 7;} \\ \frac{x}{10}=\frac{\log 2}{\log 7} \\ \frac{x}{10}=\frac{0.3010}{0.8451} \\ \frac{x}{10}=0.3562 \\ \text{Cross multiplying the equation;} \\ x=0.3562\times10 \\ x=3.562 \end{gathered}[/tex]Therefore, the approximate value of x is 3.562
The correct option is E.
PLEASE HELP!! Will mark brainliest!!
Answer:
-1, 0, 1, 2
Step-by-step explanation:
[tex]\sqrt{5-5} -1\\\sqrt{0} -1\\0-1\\-1[/tex]
[tex]\sqrt{6-5} -1\\\sqrt{1} -1\\1-1\\0[/tex]
[tex]\sqrt{9-5} -1\\\sqrt{4} -1\\2-1\\1[/tex]
[tex]\sqrt{14-5} -1\\\sqrt{9} -1\\3-1\\2[/tex]
PCA) = 1/3 P(В) = 2/9 PIAUB) = 4/9 Find P(An B). 1 1/9 ОООО 20/18 О 1/3
Solution:
Remember the following formula :
P(AUB) = P(A)+P(B)-P(AnB)
According to the data of the problem and applying the previous equation, we obtain the following equality:
[tex]\frac{4}{9}=\frac{1}{3}+\frac{2}{9}-\text{ P(A n B)}[/tex]This is equivalent to:
[tex]\frac{4}{9}=\frac{5}{9}-\text{ P(A n B)}[/tex]solving for P(A n B), we get:
[tex]\text{ P(A n B )= }\frac{5}{9}-\frac{4}{9}=\frac{1}{9}[/tex]so that, we can conclude that the correct answer is:
[tex]\frac{1}{9}[/tex]Please help i really need help please
Answer:
plane CGF and ABC
Step-by-step explanation: