Travis is at a basketball practice and is practicing his free throws his coach told him that he could go home when his free throw percentage is 85% Or higher

I. The measure of angles DEC is: 60°

II. The theorems used are corresponding angles and triangle sum theorems.

We are given the following:

m∠BAC = 64°

m∠CBA = 56°

AB║CD

BC║DE

Considering triangle ABC, we have:

m∠BCA = 180 - m∠BAC - m∠CBA [triangle sum theorem]

Substitute:

m∠BCA = 180 - 64 - 56

m∠BCA = 60°

Therefore, based on the corresponding angles theorem,

m∠DEC = m∠BCA

Substitute:

m∠DEC = 60°

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The approximate change in cost corresponding to an increase in sales of one unit is 8.50. and actual change in cost is 8.25.

To answer this question, we need to use differentials to approximate the change in cost corresponding to an increase in sales (or production) of one unit. To do this, we need to calculate the derivative of the given cost function C = 0.075x^2 + 6x + 7.

The derivative of this function is dC/dx = 0.15x + 6. We can now use this derivative to approximate the change in cost when x is increased by one unit. This is given by dC/dx = 0.15(10) + 6 = 8.5.

To compare this with the actual change in cost, we can calculate the change in cost when x is increased from 10 to 11. This is given by C(11) - C(10) = (0.075x^2 + 6x + 7) | 11 - (0.075x^2 + 6x + 7) | 10 = 0.075(121) + 66 + 7 - 0.075(100) - 60 - 7 = 8.25.

Therefore, the approximate change in cost when x is increased by one unit (calculated by differentials) is 8.50 and the actual change in cost is 8.25. This shows that the approximate change in cost calculated by differentials is an accurate estimation of the actual change in cost.

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The z-values of the sampling distributions are;

A sampling distribution is a probability distribution obtained through the repeated sampling of a specified population.

The z-value for a sampling distribution can be obtained using the formula;

[tex]z = \frac{\bar{x} -\mu}{\frac{\sigma}{\sqrt{N} } }[/tex]

Where;

[tex]\bar{x}[/tex] = The sample mean

μ = The population mean = 156

σ = The population standard deviation = 23

N = The sample size

The z-values for the sampling distributions are therefore;

1) The number of observations selected from the population, is 76, and the sample mean is; [tex]\bar{x}[/tex] = 162, we get the following z-value.

When, N = 76 and [tex]\bar{x}[/tex] = 162

2) The selected observations is 92, and the sample mean is; [tex]\bar{x}[/tex] = 151, we get the following z-value.

When, N = 92 and [tex]\bar{x}[/tex] = 151

3) The number in the random sample, N = 102 and the sample mean is; [tex]\bar{x}[/tex] = 151, we get;

When, N = 102 and [tex]\bar{x}[/tex] = 151

4) The number of observations in the random sample, N = 120 and the sample mean is; [tex]\bar{x}[/tex] = 149, we get;

When, N = 120 and [tex]\bar{x}[/tex] = 149

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Austin needs to cover 15 square inches of surface area with paint in order to finish the task.

The area of the pennant is the length times the width, which is 3 inches times 5 inches. This gives us 15 square inches of surface area to be covered. To calculate the amount of paint needed, we first need to calculate the area of the pennant. The formula for area is area = length x width. Plugging in the measurements for the base and height of the pennant, we get 15 square inches of surface area. This means that Austin needs to cover 15 square inches of surface area with paint in order to finish the task.

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Therefore , the solution of the given problem of probability comes out to be -y^(β-1)/[(β-1)Β(1, β)] .

The primary goal of the structures in the style known as parameters is the determination of the likelihood that a claim is accurate or that a specific event will occur. Any number between 0 and 1, at which 1 typically denotes certainty but also 0 typically denotes potential, can be used to symbolise chance. A probability diagram shows the chance that a specific event will occur.

Here,

We are aware that X's PDF is provided by:

If x is between 0 and 1 and 0 otherwise, f(x) Equals 1/B

where represents the size factor.

The formula for Yn's cumulative distribution function (CDF) is

=> F(y) = P(Yn ≤ y) = [P(Xi > y)]ⁿ = [1 - P(Xi ≤ y)]ⁿ

Using the CDF of the beta distribution, we have:

=> F(y) = [1 - Β(1, β; y)]ⁿ

We can approximate Yn by a normal distribution with mean and variance given by the following formulas using the continuity adjustment and central limit theorem:

=> E(Yn) = Β(2, β; 1)/Β(1, β) and Var(Yn) = E(Yn) - [Β(1, β; 1)/Β(1, β)]²

Therefore, we have:

=> (Yn - E(Yn))/sqrt(Var(Yn)) → N(0,1)

With the formulas for E(Yn) and Var(Yn) substituted, we obtain:

=> (Yn - Β(2, β; 1)/Β(1, β))/sqrt[Β(2, β; 1)/Β(1, β) - [Β(1, β; 1)/Β(1, β)]²] → N(0,1)

We need to work out the solution to determine b:

where is the CDF's usual standard value.

After applying the limit and taking the logarithm of both sides, we obtain:

=> F(y) = lim n log[n] = lim n n log

=> [1 - B(1, β; y)] = lim n -n (y, n)/(1, n)

L'Hopital's law gives us:

=> lim n -d/dy [n -(1, y)/n -(1, y)] = lim nn y(-1), ((1, )) ^2Β(2, β; y)

=> -y^(β-1)/[(β-1)Β(1, β)]

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According to proportionality, the virus will spread at a rate of 12475 students per day.

If five college students with the flu return to an isolated campus of 2500 students, and the rate at which the virus spreads is proportional to both the number of students infected and the number of students not infected, then we can use the following formula to find the rate of spread:

Rate of spread = (number of students infected) x (number of students not infected)

In this case, the number of students infected is 5 and the number of students not infected is 2500 - 5 = 2495. So, the rate of spread is:

Rate of spread = 5 x 2495 = 12475

This means that the virus will spread at a rate of 12475 students per day, assuming that the rate of spread is proportional to both the number of students infected and the number of students not infected.

It is important to note that this is a simplified model and does not take into account other factors that may affect the rate of spread, such as the effectiveness of quarantine measures or the individual immune systems of the students. However, it does give us an idea of how quickly the flu can spread in a population of 2500 students.

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sale price=$30

discount price=0.05

Taking it $30*0.05=600$

after applying 0.08

600*0.08=48$

, so 48$ is the final price of the wind chime.

The area of the circle which contains the 45° sector as required to be determined is; 345.4 cm².

As evident from the task content; A 45° sector in a circle has an area of 13.75π cm².

Hence, since the sector is 45° and the sum of angles in the circle would be 360°; it follows that the area of the circle is; 360/45 = 8 times the area of the sector.

Area of circle = 8 × 13.75π

= 8 × 13.75 × 3.14

= 345.4 cm².

Ultimately, the area of the circle is; 345.4 cm².

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The length of the silver rod when heated to 500°C is approximately 48.47 cm.

To solve this problem, we can use the formula:

L₂ = L₁ (1 + αΔT)

where L₁ is the original length of the rod at temperature T₁, L₂ is the new length of the rod at temperature T₂, α is the coefficient of linear expansion of the material, and ΔT = T₂ - T₁ is the change in temperature.

We are given that the original length of the silver rod is L₁ = 48 cm at temperature T₁ = 13°C. The coefficient of linear expansion for silver is α = 2x10^(-5) °C^(-1). The change in temperature is ΔT = 500°C - 13°C = 487°C.

Substituting these values into the formula, we get:

L₂ = 48 cm (1 + 2x10^(-5) °C^(-1) x 487°C)

= 48 cm (1 + 0.00974)

= 48 cm (1.00974)

= 48.47 cm

Therefore, the length of the silver rod is approximately 48.47 cm.

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_____The given question is incorrect, the correct question is given below:

A silver rod measures 48 cm at 13°C. What is its length when heated to 500°C? (α=2x10^(-5) °C^(-1)).

The 3rd term of the linear sequence above is 14.

Mathematically, the nth term of an arithmetic sequence can be calculated by using this expression:

aₙ =  a₁ + (n - 1)d

Where:

Next, we would determine the common difference as follows.

Common difference, d = a₂ - a₁

Common difference, d = 18 - 22

Common difference, d = -4

For the third term, we have:

a₃ =  a₁ + (n - 1)d

a₃ = 22 + (3 - 1)-4

a₃ = 22 - 8

a₃ = 14.

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The fixed charge for a taxi ride is Rs. 5 and the charge per km is Rs. 7.

Given that the charge for a 12 km ride is Rs. 89 and for a 20 km ride is Rs. 145, we can form two equations in terms of the fixed charge (c) and the charge per km (x).

Solving these equations, we get c = 5 and x = 7. Therefore, the fixed charge for a taxi ride is Rs. 5 and the charge per km is Rs. 7. To find the charge for a 30 km ride, we can substitute these values in the formula

c + 7x, which gives us 5 + 7x30 = Rs. 215.

89 = c + 12x ---------------(1)

145 = c + 20x -------------(2)

Solving equations 1 and 2, we get,

8x = 56

x = 7.

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Complete Question:

The car hire charges in a city comprised of a fixed charge together with the charge for the distance covered. For a journey of 12 km, the charge paid is Rs 89 and for a journey of 20 km, the charge paid is Rs 145. What will a person have to pay for traveling a distance of 30 km?

Answer:

To rewrite a mixed number as an improper fraction, you need to multiply the whole number by the denominator of the fraction, then add the numerator. The resulting sum is the numerator of the improper fraction, while the denominator remains the same.

For example, to rewrite the mixed number 3 1/2 as an improper fraction, you would:

Multiply the whole number 3 by the denominator 2: 3 x 2 = 6

Add the numerator 1 to the product: 6 + 1 = 7

Write the sum 7 as the numerator of the improper fraction, with the denominator 2: 7/2

So, the improper fraction equivalent of the mixed number 3 1/2 is 7/2.

Step-by-step explanation:

its b

i have covid and want to know what to do

An equation that represents this situation include the following: D. y = -2x + 9.50.

In order to write a linear equation to describe this situation, we would assign variables to the cost of the drinks and the cost of the popcorn respectively, and then translate the word problem into a linear equation as follows:

Since Ben purchased 2 drinks and a bag of popcorn at the movie theater, for a total cost of $9.50, a linear equation that models the situation is given by this mathematical expression:

2x + y = 9.50

By making y the subject of formula, we have:

y = -2x + 9.50

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The transformation as a whole is given by P → Q → R → S. A rotation through angle, about the intersection point of the lines, results from the combination of reflections in lines that meet at angle /2.

Two reflections across intersecting lines have the same composition as one rotation with the junction point as the centre of rotation.

By (0,-1/2), the initial translation is provided.

Given by is the reflection along the x-axis (x,-y)

By (0,1/2), the final translation is indicated. Hence, the transformation as a whole is provided by

(x,y) → (x,-y) → (x,-y+1/2) → (x,y+1)

This demonstrates that the resulting isometry moves the values of (x,y) by one unit in the positive y-direction to (x,y+1).

The whole transformation is provided by:

P → P + (0,d/2) → Q → Q - (0,d/2)

The total transformation is given by:

P → P + (d/2,0) → (x,-y) → (x,y) → Q

where Q is positioned (x,y). Adding the two transformations together, we obtain:

P → P + (0,d/2) → Q → Q - (0,d/2) = P + (d,0)

This demonstrates that a translation across distance d, in the direction perpendicular to the lines of reflection, results from the combination of reflections on parallel lines spaced d/2 apart.

The total transformation is given by:

P → Q → R → S

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The area of shaded region is 45 square units.

The complete question is added as an attachment

The area of the shaded region is calculated as

Shaded region =Area of rectangle - Area of triangle

Using the above as a guide, we have the following:

Area of rectangle = 8 * 6 = 48

Area of triangle = 1/2 * 2 * 3 = 3

Substitute the known values in the above equation, so, we have the following representation

Shaded region = 48 - 3

Evaluate the difference

Shaded region = 45

Hence, the shaded region is 45 square units.

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Answer:

6/100=3/50

Step-by-step explanation:

The first bag contains the numbers 1 through 10, which is a total of 10 numbers. The second bag contains the numbers 5 through 14, which is also a total of 10 numbers.

The probability of picking the same number from both bags is the number of ways of picking the same number divided by the total number of possible outcomes. There are 10 possible outcomes in each bag, so the total number of possible outcomes is 10 × 10 = 100.

To count the number of ways of picking the same number, we can simply count the number of numbers that appear in both bags. There are six numbers that appear in both bags: 5, 6, 7, 8, 9, and 10.

Therefore, the probability of picking the same number from both bags is:

6/100

Simplifying this fraction by dividing both the numerator and denominator by 2 yields:

3/50

So the probability of picking the same number from both bags is 3/50.

Conner worked 5 hours on Monday.

Let's use the letters "m" and "f" to denote the number of hours Conner worked on Monday and Friday, respectively.

Conner worked a total of 12 hours, and since we know this from the issue statement, we may write:

m + f = 12

Also, we are aware that Conner received $81 and charged $5 on Mondays and $8 on Fridays. Hence, we can write:

5m + 8f = 81

To determine one of the variables in terms of the other, we can utilise the first equation. To solve for "f," we obtain:

f = 12 - m

We can now solve for "m" by substituting this expression for "f" in the second equation:

5m + 8(12 - m) = 81

After simplifying and finding "m," we obtain:

5m + 96 - 8m = 81

-3m + 96 = 81

-3m = -15

m = 5

Conner spent 5 hours at work on Monday as a result.

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Answer:

2.50 p + 1.50p

Step-by-step explanation:

if you buy an item x amount of times you would times the two to figure out the total cost of that type of item then add with the other

The amount more that Alex earn per hour more than Sam is $2.

A linear equation is an equation that has a single variable that is raised to the power of one. The general form of a linear equation is

y = mx + c

Where:

The linear equation that represents the amount that Alex earns is y = 20x. This means that for every hour worked, Alex earns $20. Looking at the table, Sam earns $18 for every hour worked. This can be represented with the equation : y = 18x

The difference in the amount earned = 20 - 18 = $2

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Answer: go look on yt there’s a good video on this one

Step-by-step explanation:

The marginal revenue when 100 units are sold is approximately $17.12. Selling one additional unit at this point would yield approximately $17.12 in additional revenue.

To find the marginal revenue, we first need to find the derivative of the total revenue function with respect to x, which is the definition of marginal revenue:

R(x) = 2200x/(ln(9x+9))

Using the quotient rule, we get:

R'(x) = (2200(ln(9x+9)) - 2200x(1/(9x+9))(1/(9x+9)))/(ln(9x+9))^2

Simplifying this expression, we get:

R'(x) = 2200(9x)/(9x+9)^2ln(9x+9)^2

Substituting x=100, we get:

R'(100) = 2200(9(100))/((9(100)+9)^2ln(9(100)+9)^2 = $9.77 (rounded to the nearest cent).

Interpretation: The marginal revenue when 100 units are sold is $9.77. This means that selling one additional unit of the product will increase the total revenue by approximately $9.77.

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Complete question:

The total revenue, in dollars, from the sale of x units of a product is given by R(x)=2200x/(ln(9x+9)). Find the marginal revenue when 100 units are sold. (Round your answer to the nearest cent.) Interpret your result.

Answer:

plot it on -4

Step-by-step explanation:

Answer: -3

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]a[/tex] is the amount earned on the first day.

She earnt $[tex]$a[/tex] dollar on day 1, $55.50 on day 2, and $65.50 total in the 2 days.

So we get

                  [tex]a+55.50=65.50[/tex]

[tex]3x^3 + x^2 = 6x[/tex], which is option B, is the right response as Option C,[tex]3x^3 + x^2 = 0[/tex], does not equal the supplied expression.

Using just the methods of addition, elimination, and multiplication as well as ou pas integer exponents, a polynomial is a mathematical equation made up of variables and coefficients. A polynomial, for instance, is 3x2 - 2x + 5, where x has been the component and 3, -2, and 5 are now the coefficients. This polynomial's highest exponent is 2, which also happens to be its degree. Polynomials can have coefficients that are either constants or other polynomials, as well as many variables. Due to their usage in representing a variety of mathematical relations and functions, polynomials play a significant role in mathematics. Several disciplines, including algebra, algebra, geometry, and physics, make extensive use of them.

given

To make [tex]5x^2-x-8x^2 + 3x^3[/tex]simpler, we can rearrange the terms and join comparable terms:

[tex]0 + 3x^3 - x - 3x^2 = 5x^2 - 8x^2 + 3x^3 - x[/tex]

The following step is to factor the final three terms to remove a common factor of x:

[tex]3x^3 - x - 3x^2 = x\\(3x^2 - 1 - 3x)[/tex]

Hence, the abbreviated form is:

[tex]3x^2 - 1 - 3x^3 = 5x^2-x-8x^2 + 3x^3.[/tex]

Due to the fact that Option C,[tex]3x^3 + x^2 = 0[/tex], does not equal the supplied expression, it is incorrect.

Due to their failure to simplify to the specified formula, options A,      [tex]-5x^3+ x^2 = 0,[/tex] and D, [tex]3x^3 -3x^2 =6x[/tex], are likewise incorrect.

[tex]3x^3 + x^2 = 6x[/tex], which is option B, is the right response.

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The complete question is:-  

Simplify: [tex]5x^2-x-8x^2 + 3x^3 = 5x[/tex]

OA.-5x3x2 = 0

B. 3x3 + x2 = 6x

C. 3x3 + x2 = 0

D. 3x3 3x26x

-

Reset Selection

The  steps taken to design a contingency contract are valuating the potential outcomes, consequences and agree on terms of contract.

Identify the potential outcomes. Party A thinks that there is an 80% chance that the car will not break down in the first year, while Party B thinks that there is an 80% chance that it will. These are the two potential outcomes that need to be identified.

Determine the consequences of each outcome. Next, the consequences of each outcome should be determined. For example, if the car breaks down in the first year, then Party A may have to pay for repairs or reimburse Party B for the purchase price of the car. If the car does not break down, then no consequences need to be determined.

Agree on the terms of the contract. Finally, both parties need to agree on the terms of the contract. This may include how much Party A will have to pay if the car breaks down, how long Party B has to wait for reimbursement if the car does break down, and any other terms that are relevant to the situation. Once the terms have been agreed upon, the contingency contract can be signed by both parties, and they can proceed with the sale of the car.

A contingency contract could be designed to help them avoid an impasse over the issue of the car's breakdown. The contingency contract is a contract that is triggered by a specific event or circumstance, such as the car breaking down in the first year. This contract outlines what will happen if the event or circumstance occurs, and both parties agree to the terms in advance.

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In the given functions  [tex]5^x[/tex] function is increasing because 5>1.

Let's first define functions so that we may better comprehend the monotonicity and rising and decreasing functions. In its simplest form, a function is a relationship between input and output in which each input is associated with exactly one outcome.

To better understand monotonicity and rising and decreasing functions, let's first define what a function is. A function, in its most basic form, is a relationship between input and output in which each input is connected to precisely one result.

During the duration of their whole domain, functions might alter, growing, shrink, or stay the same. Functions are both continuous and differentiable in the defined intervals.

Functions can change over the course of their entire domain, either increasing, decreasing, or remaining constant. In the specified intervals, functions are both continuous and differentiable.

We have all the functions that are exponential

So when we shall check all the given function

We observe that we have functions of the form:

f (x) = A[tex]b^x[/tex]

When

b > 1 The function grows

b <1 Function decreases

Hence [tex]5^x[/tex] function is increasing.

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We need to look at the element in the second row, second column of C, which is -3. Therefore, C₂₂ = -3.

In mathematics, a matrix is a rectangular array of numbers, symbols, or expressions arranged in rows and columns. Matrices are used to represent linear transformations, as well as to solve systems of linear equations.

A matrix with m rows and n columns is called an m x n matrix. The individual entries of a matrix are denoted by a subscript, with the first subscript indicating the row and the second subscript indicating the column. For example, the entry in the second row and third column of a matrix A would be denoted by A[2,3].

Matrices can be added, subtracted, multiplied, and divided (by a scalar). Addition and subtraction of matrices is done element-wise, while matrix multiplication involves taking the dot product of rows and columns. Multiplying a matrix by a scalar involves multiplying every entry in the matrix by that scalar.

To find B - 2A, we need to multiply every element of A by 2 and then subtract the resulting matrix from B:

2A = [(-4)*2 (-3)*2 ; (-2)*2 (-3)*2 ; (-3)2 32 ; (-2)2 42] = [-8 -6 ; -4 -6 ; -6 6 ; -4 8]

B - 2A = [6 -9 ; 7 12 ; -3 -3 ; 2 -7] - [-8 -6 ; -4 -6 ; -6 6 ; -4 8] = [14 -3 ; 11 18 ; 3 9 ; 6 -15]

So C = B - 2A = [14 -3 ; 11 18 ; 3 9 ; 6 -15]

To find C₂₂, we need to look at the element in the second row, second column of C, which is -3. Therefore, C₂₂ = -3.

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The percent of carbon remaining after 30642 years if, the half-life of carbon is 5730 years would be 3.1%

Total time is given: 30642 years

Half-Life of carbon-14 : 5730 years

After 1 half-life of the carbon-14 remaining carbon: 1/2

After 2 half-lives the carbon-14 remaining carbon : 1/4

After 3 half-lives the carbon-14 remaining carbon : 1/8

...

...

After n half-lives the carbon-14 remaining carbon : (1/2)^n

Number of half-lives in 30642 years: 30642 / 5730 ≈ 5 approx.

Amount of carbon remaining after 5 half-lives: 1/32

1/32 ≈ 0.031 = 3.1%

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