Triangle UVW, with vertices U(-5,5), V(-4,7), and W(-9,8), is drawn on the coordinate grid below.

Triangle UVW, With Vertices U(-5,5), V(-4,7), And W(-9,8), Is Drawn On The Coordinate Grid Below.

Answers

Answer 1

The area formula of a triangle given the coordinates of the vertices :

[tex]U(-5,5),V(-4,7),W(-9,8)[/tex][tex]A=\lvert\frac{U_x(V_y-W_y)+V_x(W_y-U_y)+W_x(U_y-V_y)}{2}\rvert[/tex]

Using the formula above, the area will be :

[tex]\begin{gathered} A=\lvert\frac{-5(7-8)-4(8-5)-9(5-7)}{2}\rvert \\ A=\lvert\frac{5-12+18}{2}\rvert \\ A=\lvert\frac{11}{2}\rvert \\ A=\lvert5.5\rvert \\ A=5.5 \end{gathered}[/tex]

The answer is 5.5 square units


Related Questions

A country's population in 1994 was 182 million.In 2002 it was 186 million. Estimatethe population in 2004 using the exponentialgrowth formula. Round your answer to thenearest million.

Answers

we have the exponential formula

[tex]P=Ae^{(kt)}[/tex]

so

we have

A=182 million ------> initial value (value of P when the value of t=0)

The year 1994 is when the value ot t=0

so

year 2002 -----> t=2002-1994=8 years

For t=8 years, P=186 million

substitute the value of A in the formula

[tex]P=182e^{(kt)}[/tex]

Now

substitute the values of t=8 years, P=186 million

[tex]\begin{gathered} 186=182e^{(8k)} \\ e^{(8k)}=\frac{186}{182} \\ \text{apply ln both sides} \\ 8k=\ln (\frac{186}{182}) \\ k=0.0027 \end{gathered}[/tex]

the formula is equal to

[tex]P=182e^{(0.0027t)}[/tex]

Estimate the population in 2004

t=2004-1994=10 years

substitute the value of t in the formula

[tex]\begin{gathered} P=182e^{(0.0027\cdot10)} \\ P=187 \end{gathered}[/tex]

therefore

the answer is 187 million

What is a rational number between -0.45 and -0.46?

Answers

Answer:-0.4545555...,-0.453333...,-0.45222.....

hope i helped

Step-by-step explanation:

Please help me answer the following question with the picture below.

Answers

Answer:

9x+b

Step-by-step explanation:

Need help with is math.

Answers

For the given polynomial the roots can't have multiplicity, and the polynomial is:

p(x) = (x - 2)*(x - 3)*(x - 5).

How to find the polynomial?

Here we know that we have a cubic polynomial (of degree 3) with the following zeros:

2, 3, and 5.

Can any of the roots have multiplicity?

No, because a cubic polynomial can have at maximum 3 zeroes, and here we already have 3.

Now let's get the polynomial

Remember that a cubic polynomial with zeros a, b, and c can be written as:

p(x) = (x - a)*(x - b)*(x - c)

Then the polynomial in this case is:

p(x) = (x - 2)*(x - 3)*(x - 5).

Learn more about polynomials:

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a local business Club has 11 exclusive board members and 22 General members how many committees of 7 members can be chosen so that only General members are excluded

Answers

we have:

general members are excluded then

[tex]11C7=330[/tex]

answer: 330

What’s the correct answer answer asap for brainlist

Answers

Answer: serbia

Step-by-step explanation:

what are the terms in 7h+3

Answers

Input data

7h + 3

Procedure

A term is a single mathematical expression.

3 = is a single term.

It is simply a numerical term called a constant.

7h = is also a single term. , The coefficient of the first term is 7

perpendicular lines homework

Answers

[tex]We\text{ have to find the slope of the lines, if the product of the slopes is -1, then they are perpendicular!}[/tex][tex]\begin{gathered} m_{AC}=\frac{7-1}{5-(-2)} \\ m_{AC}=\frac{6}{7} \\ \\ \\ m_{BC}=\frac{4-(-3)}{-3-3} \\ m_{BC}=\frac{7}{-6}=-\frac{7}{6} \end{gathered}[/tex][tex]\begin{gathered} m_{AC}\cdot m_{BD}=\frac{6}{7}\times(-\frac{7}{6}) \\ =-1 \\ \\ \text{ Thus the lines are perpendicular} \end{gathered}[/tex]

Mary Anne wants the professor to build a ramp to make it easier to get things into the cook hut. The ramp has to rise 2 feet and will have anangle of 12 degrees with the ground.Calculate how far out from the hut the ramp will go. Round to the nearest 1 decimal. _____What length of timbers will be needed to build the ramp (how long is the distance along the ramp) Round to the nearest 1 decimal. _____

Answers

The next figure illustrates the problem

x is computed as follows:

tan(12°) = opposite/adjacent

tan(12°) = 2/x

x = 2/tan(12°)

x = 9.4 ft

y is computed as follows:

sin(12°) = opposite/hypotenuse

sin(12°) = 2/y

y = 2/sin(12°)

y = 9.6 ft

b) A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown below:i) if two students are randomly selected, what is the probability that both of them are European (correct to 4 decimal places)ii) if one student is randomly selected, what is the probability that a student is not Asian. (correct to 4 decimal places)

Answers

Given:-

A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown.

To find if two students are randomly selected, what is the probability that both of them are European and if one student is randomly selected, what is the probability that a student is not Asian.

So now the total number of students are,

[tex]230+110+85+25=450[/tex]

So now the probability of getting European is,

[tex]\frac{110}{450}=\frac{11}{45}[/tex]

So the probability is,

[tex]\frac{11}{45}[/tex]

So now the probability is asian is,

[tex]\frac{230}{450}=\frac{23}{45}[/tex]

So the probability that it is not asian is,

[tex]1-\frac{23}{45}=\frac{45-23}{45}=\frac{22}{45}[/tex]

so the required probability is,

A very large bag contains more coins than you are willing to count. Instead, you draw a random sample of coins from the bag and record the following numbers of eachtype of coin in the sample before returning the sampled coins to the bag. If you randomly draw a single coin out of the bag, what is the probability that you will obtain apenny? Enter a fraction or round your answer to 4 decimal places, if necessary.Quarters27Coins in a BagDimes21Nickels24Pennies28

Answers

Given:

The number of quarters = 27

The number of dimes = 21

The number of Nickels = 24

The number of Pennies = 28

Required:

Find the probability to obtain a penny.

Explanation:

The total number of coins = 27 + 21 + 24 +28 = 100

The probability of an event is given by the formula:

[tex]P=\frac{Number\text{ of possible outcomes}}{Total\text{ number of outcomes}}[/tex]

The number of penny = 28

[tex]\begin{gathered} P(penny)=\frac{28}{100} \\ P(penny)=0.28 \end{gathered}[/tex]

Final Answer:

The probability of obtaining Penny is 0.28.

Order the numbers from least (1) to greatest (10).ITEM BANK-Move to Battom3.564.034.212V12mor

Answers

To order these numbers, we begin with the whole part of each number. In the case of having two numbers with equal whole part, we look for the greatest tenth. So, the order would be

[tex]3.56;4.03;4.2;12[/tex]

Notice that, 4.03 is less than 4.2, because its tenth is less.

URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!

Answers

C is your answer!

Simply use perimeter rules for a triangle in this instance.

Hope that helps!

What is the opposite of the number −12?
A(-1/12
B(1/12
C(0
D(12

Answers

Answer: D(12)

Step-by-step explanation: To find the opposite it the number you would do -12= -12 x -1 = 12

Decide whether the change is an increase or decrease and find the percent change. Original number = 45 New number = 18 Answer: 60% decrease 60% increase 150% increase 150% decrease

Answers

The percentage change can be found below

[tex]\begin{gathered} \text{percentage change = }\frac{\text{ new number}-\text{original number}}{\text{original number}}\times100 \\ \text{percentage change=}\frac{18-45}{45}\times100 \\ \text{percentage change}=-60 \\ \end{gathered}[/tex]

Since the percentage is negative, this means there is a 60% decrease.

29 graph in desmos and label points of inflection, critical points, local extremes, absolute extremes, asymptotes, etc

Answers

Given:

There are given the function:

[tex]f(x)=\frac{3x}{x^2-1}[/tex]

Explanation:

According to the question:

We need to draw the graph of the given equation:

So,

The graph is:

vertical asymptotes are (-1,1)

And,

The horizontal asymptotes is

y = 0.

Comparing Two Linear Functions (Context - Graphically)

Answers

start identifying the slope and y-intercept for each high school.

The slope represents the growth for each year, in this case for high school A is 25 and for high school B is 50.

The y-intercept is the number of students that are enrolled currently, in this case for A is 400 and for B is 250.

The complete equations in the slope-intercept form are

[tex]\begin{gathered} A=25x+400 \\ B=50x+250 \end{gathered}[/tex]

Continue to graph the equations

High school B is projected to have more students in 8 years.

H +6g when 9=g and h=4

Answers

Hey there!

[tex]g+6g\\g=9,h=4[/tex]

[tex]4(h)+6(9(g))[/tex]

[tex]4+6(9)[/tex]

[tex]=58[/tex]

Hope this helps!

For the function f(x) = 6e^x, calculate the following function values:f(-3) = f(-1)=f(0)= f(1)= f(3)=

Answers

Consider the given function,

[tex]f(x)=6e^x[/tex]

Solve for x=-3 as,

[tex]\begin{gathered} f(-3)=6e^{-3} \\ f(-3)=6(0.049787) \\ f(-3)=0.2987 \end{gathered}[/tex]

Thus, the value of f(-3) is 0.2987 approximately.

Solve for x=-1 as,

[tex]\begin{gathered} f(-1)=6e^{-1} \\ f(-1)=6(0.367879) \\ f(-1)=2.2073 \end{gathered}[/tex]

Thus, the value of f(-1) is 2.2073 approximately.

Solve for x=0 as,

[tex]\begin{gathered} f(0)=6e^0 \\ f(0)=6(1) \\ f(0)=6 \end{gathered}[/tex]

Thus, the value of f(0) is 6 .

Solve for x=1 as,

[tex]\begin{gathered} f(1)=6e^1 \\ f(1)=6(2.71828) \\ f(1)=16.3097 \end{gathered}[/tex]

Thus, the value of f(1) is 16.3097 approximately.

Solve for x=3 as,

[tex]\begin{gathered} f(3)=6e^3 \\ f(3)=6(20.0855) \\ f(3)=120.5132 \end{gathered}[/tex]

Thus, the value of f(3) is 120.5132 approximately.

Determine which of the following lines, if any, are perpendicular • Line A passes through (2,7) and (-1,10) • Line B passes through (-4,7) and (-1,6)• Line C passed through (6,5) and (7,9)

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

Line A:

point 1 (2,7)

point 2 (-1,10)

Line B:

point 1 (-4,7)

point 2 (-1,6)

Line C:

point 1 (6,5)

point 2 (7,9)

Step 02:

perpendicular lines:

slope of the perpendicular line, m’

m' = - 1 / m

Line A:

slope:

[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{10-7}{-1-2}=\frac{3}{-3}=-1[/tex]

Line B:

slope:

[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-7}{-1-(-4)}=\frac{-1}{-1+4}=\frac{-1}{3}[/tex]

Line C:

slope:

[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{9-5}{7-6}=\frac{4}{1}=4[/tex]

m' = - 1 / m ===> none of the slopes meet the condition

The answer is:

there are no perpendicular lines

Given the special right triangle, find the value of x and y. Express your answer in simplest radical form.

Answers

[tex]\begin{gathered} To\text{ calculate x} \\ \sin \text{ (60)=}\frac{x}{10} \\ x=10\cdot\sin \text{ (60)} \\ x=10\cdot\frac{\sqrt[]{3}}{2}=8.66\approx8.7 \\ x=8.7 \\ The\text{ value of x is 8}.7 \\ \\ To\text{ calculate y} \\ \cos (60)=\frac{y}{10} \\ y=10\cdot\cos (60) \\ y\text{ = 10}\cdot\frac{1}{2} \\ y=5 \\ \text{The value of y is 5} \end{gathered}[/tex]

What is the solution to the equation below ? 0.5x = 6 A . 3 B . 12 C . 60

Answers

Given the equation:

[tex]0.5x=6[/tex]

Multiplying both sides by 2

[tex]\begin{gathered} 2\cdot0.5x=2\cdot6 \\ x=12 \end{gathered}[/tex]

So, the answer will be option B) 12

Jonathan is playing a game or a regular board that measures 60 centimeters long and 450 mm wide. which measurement is closest to the perimeter of the Jonathan's game board in meters?

Answers

According to the problem, the length is 60 cm and the width is 450 mm.

Let's transform 450mm to cm. We know that 1 cm is equivalent to 10 mm. So,

[tex]450\operatorname{mm}\times\frac{1\operatorname{cm}}{10\operatorname{mm}}=45\operatorname{cm}[/tex]

Then, we use the perimeter formula for rectangles.

[tex]P=2(w+l)[/tex]

Where w = 45 cm and l = 60 cm.

[tex]\begin{gathered} P=2(45\operatorname{cm}+60\operatorname{cm})=2(105cm) \\ P=210\operatorname{cm} \end{gathered}[/tex]The perimeter is 210 centimeters long.

However, we know that 1 meter is equivalent to 100 centimeters.

[tex]P=210\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=2.1m[/tex]

Hence, the perimeter, in meters, is 2.1 meters long.

Option A is the answer.

PLEASE ANSWER ASAP ! Thanks :)

Answers

The inverse function table of the function is given by the image at the end of the answer.

How to calculate the inverse function?

A function y = f(x) is composed by the following set of cartesian points:

(x,y).

In the inverse function, the input of the function represented by x and the output of the function represented by y are exchanged, meaning that the coordinate set is given by the following rule:

Thus, the points that will belong to the inverse function table are given as follows:

x = -8, f^(-1)(x) = -2, as the standard function has x = -2 and f(x) = -8.x = -4.5, f^(-1)(x) = -1, as the standard function has x = -1 and f(x) = -4.5.x = -4, f^(-1)(x) = 0, as the standard function has x = 0 and f(x) = -4.x = 0, f^(-1)(x) = 2, as the standard function has x = 2 and f(x) = 0.

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Answer:

[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]

Step-by-step explanation:

The inverse of the graph of a function is its reflection in the line y = x.

Therefore, the mapping rule to find the inverse of the given ordered pairs is:

(x, y) → (y, x)

Therefore:

The inverse of (-2, -8) is (-8, -2)The inverse of (-1, -4.5) is (-4.5, -1)The inverse of (0, -4) is (-4, 0)The inverse of (2, 0) is (0, 2)

Completed table:

[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]

Watch help videoGiven the matrices A and B shown below, find – B - A.318154B12be-12

Answers

Given two matrices

[tex]A=\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix},B=\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

We will solve for the resultant matrix -B - 1/2A.

This operation is represented as

[tex]-B-\frac{1}{2}A=-\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}-\frac{1}{2}\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

Let's simplify the matrices further based on scalar operations that can be done here. The B matrix will be multiplied by -1 while the A matrix will be multiplied by 1/2. We now have

[tex]-B-\frac{1}{2}A=\begin{bmatrix}{4} & {-12} & {} \\ {-8} & {12} & {} \\ {} & {} & {}\end{bmatrix}-\begin{bmatrix}{-9} & {\frac{3}{2}} & {} \\ {\frac{-15}{2}} & {-3} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

Now, we apply the subtraction of matrices to the simplified matrix operation above. We have

[tex]\begin{gathered} -B-\frac{1}{2}A=\begin{bmatrix}{4-(-9)} & {-12-\frac{3}{2}} & {} \\ {-8-(-\frac{15}{2})} & {12-(-3)} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{4+9} & {-12-\frac{3}{2}} & {} \\ {-8+\frac{15}{2}} & {12+3} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex]

Hence, the resulting matrix for the operation -B - 1/2A is

[tex]-B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

Question 2 of 10The one-to-one functions g and h are defined as follows.g={(-8, 6), (-6, 7), (-1, 1), (0, -8)}h(x)=3x-8Find the following.g-¹(-8)=h-¹(x) =(hoh− ¹)(-5) =

Answers

Answer: We have to find three unknown asked quantities, before we could do that we must find the g(x) from the coordinate points:

[tex]\begin{gathered} g=\left\{\left(-8,6\right),(-6,7),(-1,1),(0,-8)\right\}\Rightarrow(x,y) \\ \\ \text{ Is a tabular function} \\ \end{gathered}[/tex]

The answers are as follows:

[tex]\begin{gathered} g^{-1}(-8)=0\text{ }\Rightarrow\text{ Because: }(0,-8) \\ \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \text{ Because:} \\ \\ h(x)=3x-8\Rightarrow\text{ switch }x\text{ and x} \\ \\ x=3h-8 \\ \\ \\ \\ \text{ Solve for }h \\ \\ \\ h=h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \end{gathered}[/tex]

The last answer is:

[tex]\begin{gathered} (h\text{ }\circ\text{ }h^{-1})(-5) \\ \\ \text{ Can also be written as:} \\ \\ h[h^{-1}(x)]\text{ evaluated at -5} \\ \\ h(x)=3x-8 \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \therefore\Rightarrow \\ \\ \\ h[h^{-1}(x)]=3[\frac{x}{3}+\frac{8}{3}]-8=x+8-8=x \\ \\ \\ \\ h[h^{-1}(x)]=x \\ \\ \\ \\ h[h^{-1}(-5)]=-5 \end{gathered}[/tex]

Hello! I need some help with this homework question, please? The question is posted in the image below. Q6

Answers

Step 1

Given;

[tex]g(x)=3x^2-5x-2[/tex]

Required; To find the zeroes by factoring

Step 2

Find two factors that when added gives -5x and when multiplied give -6x

[tex]\begin{gathered} \text{These factors are;} \\ -6x\text{ and x} \end{gathered}[/tex][tex]\begin{gathered} -6x\times x=-6x^2 \\ -6x+x=-5x \end{gathered}[/tex]

Factoring we have and replacing -5x with -6x and x we have

[tex]\begin{gathered} 3x^2-6x+x-2=0 \\ (3x^2-6x)+(x-2)_{}=0 \\ 3x(x-2)+1(x-2)=0 \\ (3x+1)(x-2)=0 \\ 3x+1=0\text{ or x-2=0} \\ x=-\frac{1}{3},2 \\ \text{The z}eroes\text{ are, x=-}\frac{1}{3},2 \end{gathered}[/tex]

Graphically the x-intercepts are;

The x-intercepts are;-1/3,2

Hence, the answer is the zeroes and x-intercepts are the same, they are;

[tex]-\frac{1}{3},2[/tex]

PLEASE HELP ME!! a shoe company is going to close one of its two stores and combine all the inventory from both stores these polynomials represented the inventory in each store. which expression represents the combined inventory of the two stories?

Answers

Add the two expressions together;

[tex]\begin{gathered} (\frac{1}{2}g^2+\frac{7}{2})+(3g^2-\frac{4}{5}g+\frac{1}{4}) \\ =\frac{1}{2}g^2+3g^2-\frac{4}{5}g+\frac{7}{2}+\frac{1}{4} \\ =3\frac{1}{2}g^2-\frac{4}{5}g+(\frac{14+1}{4}) \\ =\frac{7}{2}g^2-\frac{4}{5}g+\frac{15}{4} \end{gathered}[/tex]

The first option is the correct answer

Boy earns 20.56 on Monday 32.90 on Tuesday and 20.78 on Wednesday he spends half what he earned during three days how much he have left

Answers

First, we need to calculate the total earned during the three days, so we need to sum 20.56, 32.90, and 20.78 as:

So, the total earned is 74.24, then half of 74.24 is calculated as:

[tex]\frac{74.24}{2}=37.12[/tex]

If he spends the half, he has left the half. Therefore, he has left 37.12

Answer: 37.12

I need help with system B. I have one right. And if the answer is infinitely. It asks to satisfy and it has Y=

Answers

We have the next system of equations

[tex]\begin{gathered} -5x-y=5 \\ -5x+y=5 \end{gathered}[/tex]

We can sum both equations we can eliminate one variable

[tex]\begin{gathered} -10x=10 \\ \end{gathered}[/tex]

then we isolate the x

[tex]x=\frac{10}{-10}=-1[/tex]

Therefore x=-1 then we substitute the value of x in order to find the value of y in the second equation

[tex]-5(-1)+y=5[/tex]

Then we simplify

[tex]5+y=5[/tex]

Then we isolate the y

[tex]y=5-5[/tex][tex]y=0[/tex]

ANSWER

x=-1

y=0

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