True, energy can be transferred from kinetic energy (KE) to potential energy (PE) and vice versa
Can energy be transferred from Kinetic Energy (KE) to Potential Energy (PE) and vice versa?The principle of the conservation of energy states that energy cannot be created or destroyed but can only transferred or transformed from one form to another.
When an object is in motion, it has kinetic energy, and when it is at rest, it has potential energy.
When the object moves from a stationary position to a position in motion, some of its potential energy is converted into kinetic energy.
Conversely, when the object moves from a position in motion to a stationary position, some of its kinetic energy is converted into potential energy.
Hence, the statement is TRUE.
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if the coconut from the taller tree reaches the ground with a speed v , what will be the speed (in terms of v ) of the coconut from the other tree when it reaches the ground?
Since both coconuts fall the same distance, they will reach the ground with the same speed (v). The speed of the coconut from the other tree when it reaches the ground is equal to the speed of the coconut from the taller tree (v).
The speed of the coconut from the other tree when it reaches the ground is equal to the speed of the coconut from the taller tree (v). This is because the force of gravity is the same on both coconuts and they experience the same acceleration. This means that they will reach the ground with the same speed, regardless of the height of the tree they are falling from.
The gravitational acceleration (g) is a constant and is independent of the mass of the coconut. Since both coconuts have the same mass, they will experience the same force of gravity, resulting in the same acceleration. This acceleration is independent of the initial height of the coconut, meaning that the coconuts will reach the ground with the same speed regardless of their initial height.
The speed (v) of the coconuts when they reach the ground is determined by their initial speed at the top of the tree (v0) and the distance they fall (d). If the initial speed is 0 (which is the case when the coconut is released from rest) then the final speed is determined by the distance the coconut has fallen (d). According to the equation v2 = 2gx, v = sqrt(2gd), where g is the gravitational acceleration and d is the distance fallen. Therefore, since both coconuts fall the same distance, they will reach the ground with the same speed (v).
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the reason that the primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape is
The primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape because a parabolic shape allows for the mirror to collect the most amount of light and focus the parallel rays of light to a single point for better image clarity.
The reason that the primary mirror of an astronomical telescope is often shaped and polished to a parabolic shape is to reduce spherical aberration.
What is an astronomical telescope?An astronomical telescope is an optical instrument that aids in the observation of remote objects by collecting electromagnetic radiation such as visible light. It consists of two primary components: a primary mirror or lens that gathers and focuses light, and an eyepiece or camera that magnifies and projects the image formed by the primary.
A parabolic shape is a mirror or lens that has a curve that is more curved in the center than at the edges, and it is often used in astronomical telescopes to reduce spherical aberration. Spherical aberration is an optical defect that causes the image of a point source to become fuzzy and blurred. It occurs when the rays passing through the edges of a spherical lens or mirror become focused at a different distance than those passing through the center. This causes the image to be blurred around the edges, which makes it difficult to view small or distant objects. Parabolic mirrors are used to correct this problem because they are designed to focus all incoming light to a single point, resulting in a sharper and clearer image.
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find the equivalent capacitance of a 4.20-mf capacitor and an 8.50-mf capacitor when they are connected (a) in series and (b) in parallel
(a) The equivalent capacitance of the 4.20 µF and 8.50 µF capacitors when connected in series is approximately 4.2017 µF.
(b) The equivalent capacitance of the 4.20 µF and 8.50 µF capacitors when connected in parallel is 12.70 µF.
When two capacitors are connected in series, the equivalent capacitance is given by the formula,
1/Ceq = 1/C1 + 1/C2
where C1 and C2 are the capacitances of the two capacitors.
Substituting the given values,
1/Ceq = 1/4.20 µF + 1/8.50 µF
1/Ceq = 0.238 µF^-1
Ceq = 1 / (0.238 µF^-1)
Ceq = 4.2017 µF (rounded to four significant figures)
When two capacitors are connected in parallel, the equivalent capacitance is given by the formula,
Ceq = C1 + C2
where C1 and C2 are the capacitances of the two capacitors.
Substituting the given values,
Ceq = 4.20 µF + 8.50 µF
Ceq = 12.70 µF
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jeff 60 kg and julia 45 kg are in two separate bumper cars 130 each. jeff was moving at 4 m/s north while julie was going 6 m/s west. julia bounces off going 2 m/s at an angle of 15 s of w. what is the final velocity and direction of jeff car
Final velocity of Jeff's car is 7.133 m/s south. The direction is 59.3° south of east.
In this issue, we can utilize preservation of energy to track down the last speed and course of Jeff's crash mobile after the impact with Julia's. Before the impact, the energy in the x-heading is zero, and in the y-course, it is 60 kg × 4 m/s = 240 kg⋅m/s north. Julia's force is 45 kg × 6 m/s = 270 kg⋅m/s west.After the crash, the energy in the x-course is rationed. The absolute energy in the x-course is as yet zero, as Julia's force that way is likewise zero. In the y-heading, the absolute force after the crash is 60 kg × vj + 45 kg × 2 m/s sin 15°, where vj is Jeff's last speed in the y-course.Utilizing protection of energy, we can compare the force when the crash in the y-heading:
60 kg × 4 m/s + 45 kg × 6 m/s = 60 kg × vj + 45 kg × 2 m/s sin 15°
Working on this situation, we get:
240 kg⋅m/s + 270 kg⋅m/s = 60 kg × vj + 12.19 kg⋅m/s
Addressing for vj, we get:
vj = (240 kg⋅m/s + 270 kg⋅m/s - 12.19 kg⋅m/s)/60 kg
vj = 7.133 m/s south
Consequently, Jeff's last speed is 7.133 m/s south. To find the course, we can utilize geometry. The point of Jeff's last speed concerning the x-pivot is given by:
θ = tan^-1(vj/4 m/s)
θ = 59.3° south of east
Accordingly, the last speed and heading of Jeff's amusement cart are 7.133 m/s at a point of 59.3° south of east.
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the intensity of sound in a typical classroom is approxiamtely 10^-7 w/m2. what is the sound level for this noise/
The sound level for this noise is approximately 50 decibels.
Sound level is a logarithmic measure of the ratio between the sound pressure level of a particular sound wave and a reference level. The reference level is typically set at the threshold of human hearing, which corresponds to an intensity of 10^-12 W/m^2. The sound level (measured in decibels, dB) of a sound wave is given by,
L = 10 log10(I/I0)
where I is the intensity of the sound wave and I0 is the reference intensity, which is typically set at 10^-12 W/m^2.
So, for an intensity of 10^-7 W/m^2 in a typical classroom, we can calculate the sound level as,
L = 10 log10(I/I0) = 10 log10(10^-7/10^-12) = 10 log10(10^5) = 50 dB
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a child stands with each foot on a different scale. the left scale reads 200 n and the right scale reads 250 n. what is her mass in kg? the acceleration due to gravity is 9.8 m/s2? group of answer choices 36 kg 350 kg 3430 kg 45.9 kg
The mass of the child is 45.9 kg. Therefore, the answer is option D.
Given that a child stands with each foot on a different scale, the left scale reads 200 N and the right scale reads 250 N. To find the mass of the child, we need to use the formula: Weight = mass × acceleration due to gravity (w = mg). The acceleration due to gravity is 9.8 m/s². Therefore, the weight of the child on the left scale is w1 = 200 N, and the weight of the child on the right scale is w2 = 250 N. We can use these two weights to calculate the mass of the child. The sum of the weight of both scales will be equal to the total weight (w1 + w2 = W). Therefore, the total weight of the child is:
W = 200 N + 250 N= 450 N
We have the total weight of the child, and now we can calculate the mass of the child by dividing the weight by the acceleration due to gravity. Therefore, the mass of the child is:
m = W/g
= 450 N / 9.8 m/s²
= 45.92 kg
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a series circuit is a current divider and a parallel circuit is a voltage divider circuit. select one: a. true b. false
The given statement " A series circuit is a current divider and a parallel circuit is a voltage divider circuit " is True
In a series circuit, the electric current is the same through each component, and the total current is equal to the sum of the currents through each component. Therefore, the current is divided among the components.
In a parallel circuit, the potential voltage across each component is the same, and the total voltage is equal to the sum of the voltages across each component. Therefore, the voltage is divided among the components.
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what kind of pressure prevents a white dwarf from collapsing?
Answer:
The type of pressure that prevents a white dwarf from collapsing is the electron degeneracy pressure.
What is a white dwarf?A white dwarf is a stellar remnant of a low or medium-mass star that has died, formed by a white dwarf supernova.
White dwarfs are composed of electron-degenerate matter, a type of fermionic matter that is extremely dense.The inward gravitational force of a star causes it to compress and heat up as its hydrogen fuel runs out. The temperature at the center of a star reaches a few million degrees Celsius, allowing the helium in the core to undergo nuclear fusion. The star's outer layers are blown away as a result of the fusion process, leaving behind a hot and dense core called a white dwarf. This core is not supported by internal fusion reactions, and its heat energy is gradually lost through radiative cooling.How does a white dwarf stay stable?
The white dwarf's stability is maintained by electron degeneracy pressure, which is the result of electrons being packed so tightly in the star's core that they are forced to behave like a gas, rather than a collection of individual particles.
The quantum mechanical Pauli exclusion principle governs the behavior of these electrons, which prohibits two fermions from occupying the same quantum state at the same time.
As a result, each electron is forced into a higher-energy state, resulting in a pressure that resists gravitational compression.
Therefore, the type of pressure that prevents a white dwarf from collapsing is the electron degeneracy pressure.
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What would you expect the force to be if the distance was 30 meters? How did you come up with your answer?
The force would be 6 Newtons for a distance of 30 metres.
What connection exists between distance and force?A force is defined as any influence that results in a change in an object. Distance is the amount of distance that an object moves over time. A force is applied to an item, and the more force is applied, the farther the thing will move.
What is distance-based force?Action-at-a-distance forces are those that develop even when the two interacting objects are not in close proximity to one another but are nevertheless able to push or pull against one another despite this physical gap.
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a planet of mass 4 x 10^14 kg is orbiting a parent star 548 km away. if the star is 83 times the mass of the planet, what speed must the planet have to keep a perfectly circular orbit around the star?
To find the speed of the planet in a perfectly circular orbit around the star, we can use the equation v = sqrt(Gm2 / r). Plugging in the given values, we get v = 1843.3 m/s. Therefore, the planet must have a speed of approximately 1843.3 m/s.
A student holds a 0.06 kg egg out a window. Just before the student releases the egg, the egg has a 8.0 J of gravitational potential energy with respect to the ground. How far is the students arm from the ground? a.) 133m b.) 13.3m c.) 0.8m d.) 0.08m
if the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, what is the ratio of their final kinetic energies?
If the same horizontal net force were exerted on both vehicles, pushing them from rest over the same distance, then the ratio of their final kinetic energies is 1:2.
According to the Work-Energy principle, the net work done on an object is equal to the change in its kinetic energy. This principle states that the work done on a particle is equal to the change in its kinetic energy. We can then conclude that the final kinetic energy of an object is equal to the work done on it by the force acting on it.
Therefore, when the same horizontal net force is exerted on both vehicles, pushing them from rest over the same distance, the amount of work done is the same for both vehicles. Hence, their final kinetic energies will be proportional to their masses because the formula for kinetic energy is KE = 1/2mv². The ratio of the final kinetic energies of both vehicles can be calculated as follows:KE1/KE2 = (1/2mv1²)/(1/2mv2²) = (v1/v2)². Here, v1 and v2 are the final velocities of the two vehicles. Since both vehicles are pushed over the same distance, their final velocities will be proportional to the square root of their masses, so the ratio of their final kinetic energies will be 1:2.
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how does the plot differ from the plots for tube radius, viscosity, and tube length? how well did the results compare with your prediction
The plot differs for tube radius, viscosity, and tube length in terms of their effect on fluid flow. The effect of each parameter is analyzed and plotted against the velocity profile of the fluid flow.
For tube radius, as the radius increases, the fluid flow velocity increases as well. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the right as the radius increases.
For viscosity, the effect is the opposite. As viscosity increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a flatter curve, with a smaller peak as the viscosity increases.
For tube length, there is a similar effect as tube radius. As the length increases, the fluid flow velocity decreases. This can be observed in the plot where the velocity profile is a bell-shaped curve, with the peak shifting to the left as the length increases.
In terms of the comparison with the prediction, the results were mostly in line with what was expected. The plots showed the expected trends for each parameter, and the quantitative analysis confirmed this as well. However, there were some discrepancies between the predicted and actual values, which could be due to experimental error or limitations in the model used.
Overall, the results provided valuable insights into the relationship between these parameters and fluid flow, and can be used to optimize fluid systems for various applications.
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for an incandescent bulb, initial cost may be high but the energy costs will be low over its life time. (1 point) group of answer choices true false
True. An incandescent bulb may have a higher initial cost than other types of lightbulbs, but it uses less energy over its lifetime and thus reduces energy costs.
For an incandescent bulb, the given statement is true. In candescent bulbs are traditional bulbs, which use a filament to create light. These bulbs are less efficient, as they waste most of the electricity they use as heat rather than light. As a result, the bulbs are less cost-effective in the long run.
They use up more energy than modern alternatives such as CFLs (compact fluorescent lights) or LEDs (light-emitting diodes). Despite their low initial cost, incandescent bulbs are not recommended for long-term use. They consume more electricity and thus have a greater impact on the environment. Therefore, it is not true that the energy costs of an incandescent bulb will be low over its life time.
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suppose an asteroid had an orbit with a semimajor axis of 4 au. how long would it take for it to orbit once around the sun? question 28 options: 2 years 4 years 8 years 16 years
It would take approximately 19.2 years for the asteroid to orbit once around the sun. But that none of the answer choices match the calculated value of approximately 19.2 years.
The period (T) of an orbit of a celestial body with semimajor axis (a) around the sun can be calculated using Kepler's third law:
T² = (4π² / GM) * a³
where G is the gravitational constant and M is the mass of the sun.
Plugging in the given value for the semimajor axis (a = 4 AU), we get:
T² = (4π² / (6.674 × 10⁻¹¹ m³/(kg s²) * 1.989 × 10³⁰ kg)) * (4 AU)³
T² = 3.652 × 10¹⁶ s²
Taking the square root of both sides, we get:
T = 6.04 × 10⁸ s
We can convert this time to years by dividing by the number of seconds in a year:
T = (6.04 × 10⁸ s) / (31,536,000 s/year)
T ≈ 19.2 years
Therefore, it would take approximately 19.2 years for the asteroid to orbit once around the sun. The closest answer choice is 16 years.
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what two forces act on a monkey hanging stationary by a vertical vine? which force, if either, is greater?
Two forces act on a monkey hanging stationary by a vertical vine: gravity and the tension of the vine. Gravity is the greater force in this situation because it is a constant force that acts downwards.
The two forces that act on a monkey hanging stationary by a vertical vine are tension and gravity. The tension force acts along the vine and pulls the monkey upwards, while the gravity force acts downwards towards the center of the Earth.
If the monkey is stationary, then the two forces are equal in magnitude and opposite in direction. This is because the tension force is balancing the gravity force, resulting in no net force acting on the monkey.
Therefore, if neither of the forces are greater than the other as they are equal in magnitude and opposite in direction.What is tension force?The force exerted by a string, rope, chain, or similar object on another object that it is connected to is referred to as tension. The tension is always directed along the length of the string and away from the object's surface that the string is attached to. When an object is suspended from a rope, the tension force on the rope is equal to the weight of the object (due to gravity), and this tension force is transmitted through the rope to any other objects that the rope is attached to.
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if a current of 5.5 a is used, what is the force generated per unit field strength on the 20.0 cm wide section of the loop? use units of newtons per tesla.
The force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is: 0.001 newtons per tesla
The force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is given by the formula F = (μI) / 2πr,
where μ is the permeability of free space, (4π x 10-7 N/A²)
I is current, and r is the radius of the loop.
In this case, the force is (4π x 10-7 x 5.5) / (2π x 0.1) = 0.001 N/T.
In other words, the force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is 0.001 newtons per tesla.
The formula for the force generated per unit field strength on a loop is derived from the fact that the force is a result of the magnetic field generated by the current flowing in the loop.
The magnitude of the magnetic field generated is proportional to the current and inversely proportional to the radius of the loop. Since the force is a product of the current and the magnetic field, it is proportional to the square of the current and inversely proportional to the square of the radius of the loop.
In summary, the force generated per unit field strength on a 20.0 cm wide section of the loop with a current of 5.5 A is 0.001 newtons per tesla, given by the formula F = (μI) / 2πr, where μ is the permeability of free space (4π x 10-7 N/A²), I is current, and r is the radius of the loop.
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a 6 kg block is pushed 8m up a rough 37 degree inclined plane by a horizontal force of 75 n. the initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 n opposes the motion. calculate:
The final kinetic energy of the block is 308.98 J.
Let's solve the problem using the work-energy theorem.
Mass of the block, m = 6 kgDistance covered, s = 8 mForce, F = 75 NInitial speed of the block, u = 2.2 m/sAngle of inclination, θ = 37°Coefficient of kinetic friction, μk = 0.28The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy
W = ΔKE
Initially, the block is at rest. Therefore, its initial kinetic energy is zero.
Ki = 0
We have to find the final kinetic energy of the block. Hence, Kf = ?
Work done on the block
W = Fscosθ
Work done by the applied force,
F = 75 Ns = 8 mθ = 37°
W = Fscosθ
W = 75 × 8 × cos 37°
W = 451.27 J
Work done by the frictional force
Ff = μkFn
The normal force
Fn = mg
Fn = 6 × 9.8
Fn = 58.8 N
Here,
Ff = μkFn
Ff = 0.28 × 58.8
Ff = 16.51 J
Work of friction:
W = Ff × s
W = 16.51 × 8
W = 132.1 J
The total work done on the block,
Wtotal = W + Wfriction
Wtotal = 451.27 + 132.1
Wtotal = 583.37 J
According to the work-energy theorem,
Wtotal = ΔKE
ΔKE = Wtotal
ΔKE = 583.37 J
Final kinetic energy of the block
Kf = KEFinal
Kf = ΔKE
Kf = 583.37 J
Kf = 308.98 J
Therefore, the final kinetic energy of the block is 308.98 J.
Complete question:
A 6 kg block is pushed 8m up a rough 37 degree inclined plane by a horizontal force of 75 N. The initial speed of the block is 2.2 m/s up the plane and a constant kinetic friction force of 25 N opposes the motion. Calculate the fianl kinetic energy of the block.
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how much energy is stored by the electric field between two square plates, 9.3 cm on a side, separated by a 2.5- mm air gap? the charges on the plates are equal and opposite and of magnitude 13 nc .
The electric field stored between two square plates of 9.3 cm on a side and separated by a 2.5 mm air gap is 1110 N/C. This can be calculated using Coulomb's law and the given information.
Coulomb's law states that the electric field is equal to the charge (Q) divided by the permittivity of free space (ε₀) multiplied by the distance (d) squared:
E=Q/(ε₀*d²).
Plugging in the given information,
E=(13 nC)/(8.85 x 10⁻¹² * 0.0025²) = 1110 N/C.
This answer uses Coulomb's law to calculate the electric field stored between two square plates, given the plates' side lengths, air gap width, and charge magnitude.
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what is the frequency of a standing wave with a wave speed of 12 m/s as it travels on a 4.0-m string fixed at both ends?
The frequency of a standing wave with a wave speed of 12 m/s as it travels on a 4.0-m string fixed at both ends is 3.0 Hz.
What Is A Standing Wave?A standing wave is produced by a wave with the same amplitude, frequency, and wavelength moving in the opposite direction with the initial wave. This indicates that the wave appears to stand in one place. Standing waves can only be generated in a medium if there is a boundary that restricts the movement of the wave. Standing waves can be observed in various shapes and sizes, and their frequencies are determined by a variety of factors, including the wave speed and the length of the string. When a standing wave is generated in a string, the points where the wave appears to be fixed are known as nodes, while the points where the string vibrates with the most amplitude are known as antinodes.In this scenario, the wave speed and the length of the string are given.
The wave speed, frequency, and wavelength of a wave are related by the formula v = fλ, where v is the wave speed, f is the frequency, and λ is the wavelength. Since the length of the string is fixed, the wavelength of the standing wave is twice the length of the string. Thus, λ = 2L = 8 m. Plugging in the values for the wave speed and wavelength, the frequency can be calculated as follows:f = v / λ = 12 m/s / 8 m = 1.5 Hz. The frequency of a standing wave with a wave speed of 12 m/s as it travels on a 4.0-m string fixed at both ends is 3 Hz.
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if a star is 11 pc away from us, will its apparent visual magnitude be higher or lower than its absolute visual magnitude? what if the star is 5 pc away?
If a star is 11 pc away from us, its apparent visual magnitude will be lower than its absolute visual magnitude. The star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude.
This is because the apparent magnitude of a star is affected by its distance from us. As the distance increases, the star appears dimmer, and its apparent magnitude decreases.
The distance modulus formula gives us a way to calculate the difference between the apparent and absolute magnitudes of a star:
Distance modulus = 5 * log(distance in parsecs) - 5
For a star that is 11 pc away, the distance modulus is,
Distance modulus = 5 * log(11) - 5 = 1.38
This means that the star's apparent magnitude will be 1.38 magnitudes lower than its absolute magnitude.
If the same star were only 5 pc away from us, the distance modulus would be,
Distance modulus = 5 * log(5) - 5 = 0.38
In this case, the star's apparent magnitude would be only 0.38 magnitudes lower than its absolute magnitude. This means that the star would appear brighter and have a higher apparent magnitude when it is closer to us.
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the generation of multiple forecasts of future conditions followed by an analysis of how to respond effectively to each of those conditions is
The process described in the question is known as scenario planning. It is a strategic planning method that involves generating multiple plausible scenarios of future conditions and analyzing the potential impact of each scenario on an organization or a system.
Scenario planning is a useful tool for decision-making, risk management, and identifying opportunities in an uncertain or rapidly changing environment.
By developing a range of scenarios, decision-makers can anticipate potential challenges and opportunities and develop strategies to respond effectively to each situation.
This approach allows organizations to be better prepared and more resilient in the face of future uncertainties. Scenario planning can be applied to various fields, including business, economics, environmental planning, and public policy.
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a 200 ohm, 250 ohm and 1000 ohm resistor are connected in parallel across a source. the source current is 6a. how much is the current that flows through the 200 ohm resisto
The current that flows through the 200 Ω resistor is 1.56 A.
Given resistance values of 200 Ω, 250 Ω, and 1000 Ω are connected in parallel across a source. The source current is 6 A. We are required to find the current that flows through the 200 Ω resistor.
Recall that when resistors are connected in parallel, the current is divided among them. And the voltage across each resistor is the same. The equivalent resistance of three parallel resistors is given by;
1/Rp = 1/R1 + 1/R2 + 1/R3Rp = (R1 x R2 x R3)/(R1R2 + R1R3 + R2R3)
Put the values into the formula;
Rp = (200 x 250 x 1000)/(200×250 + 200×1000 + 250×1000)
Rp = 52.17 Ω
The total current in the circuit, It = 6 A
From Ohm's Law;
V = IR,
where V is the voltage across each resistor
V1 = V2 = V3V = I×R
Therefore; V = I×Rp
The current flowing through the 200 Ω resistor, I1 = V1/200 = I × Rp/200The current flowing through the 200 Ω resistor, I1 = (6×52.17)/200I1 = 1.56 A
Thus, the current that flows through the 200 Ω resistor is 1.56 A.
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(a) when a 9.00-v battery is connected to the plates of a capacitor, it stores a charge of 27.0 mc. what is the value of the capacitance? (b) if the same capacitor is connected to a 12.0-v battery, what charge is stored?
The formula for calculating capacitance is as follows:
C = Q/V
Where,
C = capacitance (Farads)
Q = charge (Coulombs)
V = voltage (Volts)
As given,
Q = 27.0 μC
V = 9.00 V
Substituting the given values in the above equation
C = 27.0 μC/9.00 V = 3.00 μF
Therefore, the value of capacitance is 3.00 μF.
The formula for calculating charge stored is as follows:
Q = CV
Where,
Q = charge (Coulombs)
C = capacitance (Farads)
V = voltage (Volts)
As given,
C = 3.00 μF
V = 12.0 V
Substituting the given values in the above equation,
Q = (3.00 × 10⁻⁶ F) × 12.0 V = 36.0 μC
Therefore, the charge stored is 36.0 μC.
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an airplane flying horizontally with a speed of 500 km/h at a height of 800 m drops a crate of supplies. if the parachute fails to open, how far in front of the release point does the crate hit the ground? use si units.
If the parachute fails to open, 5609 m far in front of the release point does the crate hit the ground.
Break the motion of particle into two direction
1) vertical direction
2) horizontal direction
in vertical direction = [tex]V_{oy}[/tex]=0 m/s a=-9·8 m/s2
= Y = -800m t = time fraud
Y = [tex]V_{oy}[/tex] t + 1/2 at^2 = -800 = 0 + 1/2(-9.8)(t^2)
so, t = 12.785
in horizontal direction = [tex]V_{ox}[/tex] = 500 x 5/18 +300= 438.39m/s
t = 12.7885 & x = distance From releasing point
So, x = [tex]V_{ox}[/tex] t = (438.89) (12.78) = 5609m
X = 5609 m
The motion of a particle refers to its movement in space with respect to a particular reference point. This can include its speed, direction, and acceleration. There are several types of motion that a particle can exhibit, such as uniform motion, where it moves in a straight line with a constant speed, or non-uniform motion, where its speed changes over time.
A particle can move in a circular path, which is called circular motion, or it can move back and forth along a straight line, which is called oscillatory motion. The motion of a particle can be described using mathematical equations such as velocity, acceleration, and displacement. These equations help to quantify the particle's motion and provide insights into its behavior.
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an object floating in a container of water and partially submerged has the same density as the water. question 2 options: true false
The given statement "an object floating in a container of water and partially submerged has the same density as the water" is true.
When an object is placed in water, it sinks until the weight of the water displaced by the object equals the weight of the object.
If an object has the same density as water, it displaces an equal amount of water to its own weight. When it displaces the same amount of water that has an equivalent mass to the object, it will float partially submerged. If the object's density is greater than water, it will sink. If the object's density is less than that of water, it will float entirely above the water's surface.
Density is defined as the mass of an object per unit volume. The formula for density is mass/volume. Density is a crucial physical property that is used to define and classify materials. The density of an object is determined by its mass and volume. The unit of measurement for density is kg/m3 or g/cm3. The density of water is 1 g/cm3, which is why objects with a density of less than 1 g/cm3 float on water.
An object floating in a container of water and partially submerged has the same density as the water.
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use the impulse-momentum theorem to find how long a falling object takes to increase its speed from 4.23 m/s to 10.47 m/s?
The time it takes the object to fall through the change in speed using the impulse-momentum theorem is 0.62 seconds.
What is impilse-momentum theorem?
The impulse-momentum theorem states that the change in momentum of an object is equal to the impulse exerted on it.
To calculate the time it takes the object to increase it speed using the impulse-momentum theorem, we use the formula below.
Formula:
Ft = m(v-u)Ft/m = (v-u)Recall that F/m = acceleration. Therefore,
at = v-ua = (v-u)/t.......................... Equation 1Where:
a = Acceleration due to gravityv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 10.47 m/su = 4.23 m/sg = 9.8 m/s²Substitute these values into equation 1 and solve for t
9.8 = (10.27-4.23)/tt = (10.27-4.23)/9.8t = 6.04/9.8t = 0.62 secondsHence, the time it takes the object to fall is 0.62 seconds.
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a track star runs a 400-m race on a 400-m circular track in 45 s. what is his angular velocity assuming a constant speed?
The angular velocity assuming a constant speed for a track-star who runs 400 m circular track in 45 s is 0.139 radians/s.
To calculate the angular velocity first the circumference of the track is 400 meters.
This means that the angular displacement of the track star during the race is:
θ = s / r
where θ is the angular displacement,
s is the distance traveled by the track star (which is equal to the circumference of the track), and
r is the radius of the circular track.
2.) Since the radius of the circular track is half of its diameter, we have:
r = 400 m / 2 = 200 m
Plugging this into the equation for angular displacement, we get:
θ = 400 m / 200 m = 2π radians
3.) Next, we can use the formula for angular velocity:
ω = θ / t
where ω is the angular velocity and
t is the time it takes for the track star to complete the race.
4.)Plugging in the values we have:
ω = θ / t
ω = 2π radians / 45 s
Therefore, the angular velocity of the track star is:
ω = 0.139 radians/s (rounded to three significant figures)
Therefore, the track star's angular velocity assuming a constant speed is approximately 0.139 radians/s
The angular displacement of the track star is equal to one complete revolution around the circular track, which is equal to 2π radians.
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Convert the following to Fahrenheit 1) 10° C 50 °F = 1.8 x 10 +32 2) 30° C 3) 40° C
The corresponding temperature in Fahrenheit is 10° C = 50° F, 30° C = 86° F and 40° C = 104° F.
What is the corresponding temperature in Fahrenheit?In the Celsius temperature scale, water freezes at 0°C and boils at 100°C, while in the Fahrenheit temperature scale, water freezes at 32°F and boils at 212°F.
The conversion formula for Celsius to Fahrenheit is F = 1.8 x C + 32, where;
F is the temperature in Fahrenheit and C is the temperature in Celsius.So, to convert Celsius to Fahrenheit, we simply need to plug in the given Celsius temperature value into the formula F = 1.8 x C + 32, and then solve for F.
Let's take the first example of 10°C:
F = 1.8 x C + 32
F = 1.8 x 10 + 32
F = 18 + 32
F = 50°F
Therefore, 10°C is equivalent to 50°F in Fahrenheit.
Similarly, we can apply this formula to the other given Celsius temperature values of 30°C and 40°C to convert them to Fahrenheit.
30° C = 86° F (F = 1.8 x 30 + 32)
40° C = 104° F (F = 1.8 x 40 + 32)
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a square loop 5 cm on each side carries a 500 ma current. the loop is within a uniform magnetic field of 1.2t. the axis of the loop, perpendicular to the plane of the loop, makes an angle of 30 degrees with the b field. what is the magnitude of the torque on the current loop?
The magnitude of the torque on the current loop is calculated using the formula τ=BIA sinθ, where B is the magnitude of the magnetic field, I is the current, A is the area of the loop, and θ is the angle between the magnetic field and the loop's plane. In this case, the magnitude of the torque is τ = (1.2 T)(0.5 A)(5 cm x 5 cm)sin(30°) = 7.5 x 10-3 Nm.
The torque is the rotational force that causes the loop to rotate. This is due to the fact that a force is exerted on the loop by the magnetic field when there is a current running through it. This force generates a torque on the loop, which will cause it to rotate until the angle between the plane of the loop and the magnetic field is 0°.
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