use a sum or difference identity to find the exact value of :

Use A Sum Or Difference Identity To Find The Exact Value Of :

Answers

Answer 1
[tex]\begin{gathered} \sin 285\text{ } \\ 285\text{ can be split into 225 and 60} \end{gathered}[/tex][tex]\sin (225+60)[/tex]

Using the rule

[tex]\sin (x+y)=\sin x\cos y+\cos x\sin y[/tex][tex]\begin{gathered} \sin (225+60)=\sin 225\cos 60+\cos 225\sin 60 \\ \end{gathered}[/tex]

Sine is negative in the third quadrant therefore,

[tex]\begin{gathered} -(\sin 45)\cos 60+\cos 225\sin 60 \\ \sin \text{ 45=}\frac{\sqrt[]{2}}{2}\text{ then the negative sign} \\ -\frac{\sqrt[]{2}}{2} \\ -\frac{\sqrt[]{2}}{2}\cos 60+\cos 225\sin 60 \\ \cos \text{ 60=}\frac{1}{2} \\ -\frac{\sqrt[]{2}}{2}(\frac{1}{2})+\cos 225\sin 60 \end{gathered}[/tex]

Let us find the other side

[tex]\begin{gathered} \cos \text{ 45=}\frac{\sqrt[]{2}}{2} \\ cos\text{ is negative in the third quadrant } \\ -\frac{\sqrt[]{2}}{2} \\ \sin \text{ 60=}\frac{\sqrt[]{3}}{2} \\ \end{gathered}[/tex]

Bring everything together

[tex]\begin{gathered} -\frac{\sqrt[]{2}}{2}(\frac{1}{2})-\frac{\sqrt[]{2}}{2}(\frac{\sqrt[]{3}}{2}) \\ -\frac{\sqrt[]{2}}{4}-\frac{\sqrt[]{6}}{4}=\frac{-\sqrt[]{2}-\sqrt[]{6}}{4}=-0.965925826\ldots... \end{gathered}[/tex]


Related Questions

determine the area of figure round to the nearest tenth if necessary..

Answers

[tex]\begin{gathered} A1=\frac{4ft\cdot3ft}{2} \\ A1=6ft^2 \\ \\ A2=\frac{5ft\cdot6ft}{2} \\ A2=15ft^2 \\ \\ AT=A1+A2 \\ AT=6ft^2+15ft^2 \\ AT=21ft^2 \end{gathered}[/tex]

In a garden, there are 10 rows and 12 columns of mango trees. The distance between two trees is 2 meters and a distance of one meter is left from all sides of the boundary of the garden. What is the length of the garden?​

Answers

Answer:

20m

Step-by-step explanation:

(10-1)x2+1x2=20m

m(x)=-x^2+4x+21. prove the zeros and determine the extreme value algebraically

Answers

[tex]\begin{gathered} m(x)=-x^2+4x+21 \\ \text{Factor:} \\ \text{The factors of -21 that sum to -4 are 3 and -7, thus:} \\ m(x)=-x^2+4x+21=-(x+3)(x-7) \end{gathered}[/tex]

The zeros of the function are:

[tex]\begin{gathered} -(x+3)(x-7)=0 \\ x=-3 \\ or \\ x=7 \end{gathered}[/tex]

The vertex is a point V(h,k) on the function. It's either at the base or the top of the function, depending upon wether it opens, upward or downward respectively.

For a function of the form:

[tex]\begin{gathered} y=ax^2+bx+c \\ \text{The vertex(extreme value) is:} \\ h=\frac{-b}{2a} \\ k=y(h) \end{gathered}[/tex]

Therefore:

[tex]\begin{gathered} m(x)=-x^2+4x+21 \\ a=-1 \\ b=4 \\ c=21 \\ h=\frac{-4}{2(-1)}=\frac{-4}{-2}=2 \\ k=m(h)=-(2)^2+4(2)+21=-4+8+21=25 \end{gathered}[/tex]

Hence, the extreme value is 25 at x = 2

That's it, do you have any question?

Find the distance between the following points using the pythagorean theorem (5,10) and (10,12)

Answers

Answer:

\sqrt[29]

Explanation:

Given the coordinate (5,10) and (10, 12). The formula for calculating the distance between two points is expressed as;

[tex]D\text{ =}\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}^{}[/tex]

Given that;

x1 = 5

y1 = 10

x2 = 10

y2 = 12

Substitute:

[tex]\begin{gathered} D\text{ = }\sqrt[]{(10-5)^2+(12-10)^2} \\ D=\text{ }\sqrt[]{5^2+2^2} \\ D\text{ =}\sqrt[]{25+4} \\ D\text{ =}\sqrt[]{29} \end{gathered}[/tex]

Hence the distance between the points is \sqrt[29]

A is the incenter of Triangle FHG Find the length of AT. Explain your thinking.

Answers

we have that

The incenter is the center of the triangle's incircle, the largest circle that will fit

AR=AT=AS -----> radius of the inscribed circle in the triangle

therefore

AT=3 units

−1= 8x+2i need help with this problem,

Answers

Given

-1 = 8x + 2

Answer

-1 = 8x + 2

-1 -2 =8x

-3 = 8x

x = -3/8

The graph used Is below ill attach a picture of the question and options after

Answers

Using the triangle sum theorem:

[tex]\begin{gathered} m\angle L+m\angle K+20=180 \\ 2m\angle L=180-20 \\ 2m\angle L=160 \\ m\angle L=\frac{160}{2} \\ m\angle L=80 \end{gathered}[/tex]

Using the exterior angle theorem:

[tex]\begin{gathered} m\angle E=m\angle L+m\angle J \\ m\angle E=80+20 \\ m\angle E=100 \end{gathered}[/tex]

Answer:

100

determine whether the equation defines y as function of x

Answers

To answer this question, we need to solve the equation for y in the third case:

[tex]3x+2y=5\Rightarrow2y=5-3x\Rightarrow y=\frac{5}{2}-\frac{3}{2}x\Rightarrow y=-\frac{3}{2}x+\frac{5}{2}[/tex]

We can see from this case that for every value of x, there must be a value in y, and this is the main condition for a relationship to be a function. Then, y is a function of x.

In the fourth case, we have a similar case, for every possible value of x, there must be a value for y. Then, y is a function of x.

As we can see, the red graph is for the linear equation and the black one is for the one with the radical ( y = -sqrt(x+1)).

If we pass a vertical line to either function (alone), we will have only a point that passes through this vertical line, and with this graphical information, we can also say that both are functions of y (for each case).

Write an equation for the linear function f(x) using the given information. ———————————————Using the points 2,0 & 4,3

Answers

To find the equation in the form

[tex]y=mx+b[/tex]

the slope is defined by:

[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1} \\ m=\frac{3-0}{4-2} \\ m=\frac{3}{2} \end{gathered}[/tex]

To find b you can replace any of the points on the equation an clear for b

(x,y)=(4,3)

[tex]\begin{gathered} y=\frac{3}{2}x+b \\ 3=\frac{3}{2}\cdot4+b \\ 3=6+b \\ 3-6=b \\ b=-3 \end{gathered}[/tex]

to check if the answer is correct replace 2 as x in the equation.

[tex]\begin{gathered} y=\frac{3}{2}\cdot2-3 \\ y=3-3 \\ y=0 \end{gathered}[/tex]

since the answer was 0 and point was 2,0 the equation is correct.

Which of the following is only true sometimes? A. The sum of a rational number and a rational number is rational. B. The sum of a rational number and an irrational number is irrational. C. The product of an irrational number and an irrational number is irrational. D. The product of a nonzero rational number and an irrational number is irrational.

Answers

The sum of a rational number and a rational number is rational. ALWAYS

The sum of a rational number and an irrational number is irrational.

The product of an irrational number and an irrational number is irrational. SOMETIMES

For example, the product of multiplicative inverses like √2 and 1/√2 will be 1

The product of a nonzero rational number and an irrational number is irrational.​

Help I’m stuck ‼️‼️‼️ Hw due in a couple minutes

Answers

The lines AD and BC cross at a point where we have two pairs of vertically opposite angles.

The angles labelled (2x +50) and 100 are vertically opposite angles.

Vertically opposite angles are equal. Therefore;

[tex]\begin{gathered} 2x+50=100 \\ \text{Subtract 50 from both sides} \\ 2x+50-50=100-50 \\ 2x=50 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{50}{2} \\ x=25 \end{gathered}[/tex]

ANSWER:

The value of x is 25. The correct answer is option A

Find the area of the compound shapes on the coordinate plane below.

Answers

Answer

Part A: 100 square units

Part B: 39 square units

Part C: 48 square units

Explanation

Part A

Scale: 1cm represent 2 units on x-axis and 1cm represents 5 units on y-axis.

Firstly, we convert the figure into two composite plane shapes, that is, a rectangle and a triangle.

Area of composite shapes = area of rectangle + area of triangle

= Length x Width + 1/2(base x height)

= 10 x 8 + 1/2(10 x 4)

= 80 + 20

= 100 square units

Part B

Scale: 1cm represent 3 units on x-axis and 1cm represents 1 unit on y-axis.

Convert the figure into two composite plane shapes, that is, a rectangle and a trapezium.

Area of composite shapes = area of rectangle + area of trapezium

= Length x Width + 1/2(sum of parallel sides)(perpendicular height)

= 3 x 9 + 1/2(3 + 9)(2)

= 27 + 1/2(24)

= 27 + 12

= 39 square units

Part C

Scale: 1cm represent 2 units on x-axis and 1cm represents 2 units on y-axis.

Convert the figure into two composite plane shapes, that is, a trapezium and a triangle.

Area of composite shapes = area of trapezium + area of triangle

= 1/2(sum of parallel sides)(perpendicular height) + 1/2(base x height)

= 1/2(4 + 8)(6) + 1/2(4 x 6)

=1/2(12 x 6) + 1/2(24)

= 36 + 12

= 48 square units

ITS NOT A REAL TEST! MY FRIENDS WANT TO SEE HOW SMART I AM.

Answers

The given triangle is:

From the properties of triangle,

The sum of all angle in a triangle is equal to 180 degree

In triangle ABC,

Angle A + Angle B + Angle C = 180

70 + 50 + x = 180

120 +x = 180

x = 180 -120

x = 60

The missing angle is 60 degree

What is the product of 0.976 and 1.2

Answers

The product of 0.976 and 1.2 is 1.1712

Part A: The Sun that produces 3.9 * 10^33ergs of a radiant energy per second. How many eggs of radiant energy does the Sun produce and 3.25 * 10^3 seconds?Part B: Which is more the reasonable measurement of the distance between the tracks on a railroad: 1.435 * 10^3mm or 1.435 * 10^3mm?

Answers

Answer:

Part A

[tex]1.2675\times10^{37}ergs[/tex]Explanations:

The sun can produce 3.9 * 10^33 ergs of radiant energy per second

[tex]\text{Amount of energy in 1 second = 3.9 }\times10^{33}ergs[/tex][tex]\text{Amount of energy produced in 3.25}\times10^3\sec \text{ = (3.9}\times10^{33}\times3.25\times10^3)[/tex][tex]\text{Amount of energy produced in 3.25}\times10^3\text{ seconds = }1.2675\times10^{37}ergs[/tex]

What is the equation of this graphed line?
Enter your answer in slope-intercept form in the box.
A graph with a line running through coordinates (-4, -6) and coordinates (2, 6)

Answers

Answer:

12/6 or 1/2

Step-by-step explanation:

you just plug the coordinates into demos calculator and then look at rise over run.

All the formation your name is on the picture picture provided

Answers

The range of the data is the difference between the maximum data value and the minimum.

In a box plot, the maximum and the minimum are indicated by the dots at the end of the horizontal line.

Here,

Maximum = 10

Minimum = 4.5

Thus, the range of the data is:

[tex]Range=10-4.5=5.5[/tex]

Find an angle θ with 0∘<θ<360∘that has the same:

Sine as 80∘ : θ = ______ degrees

Cosine as 80∘ : θ = _____ degrees

Answers

Answer:

sin80° = sin100°

cos80° = cos280°

Step-by-step explanation:

In general, sin(a)° = sin (180-a)° and cos(a)° = cos(360-a)°

Fill in the blank with the correct inequality symbol. State which property of inequalities is being utilized.If x-8>10, then x_18.

Answers

GIVEN

The inequality:

[tex]x-8>10[/tex]

SOLUTION

The inequality is to be solved.

Add 8 to both sides of the inequality. This follows the Addition Property of Inequalities:

[tex]if\text{ }xTherefore:[tex]\begin{gathered} x-8+8>10+8 \\ x>18 \end{gathered}[/tex]

ANSWER

[tex]x>18[/tex]

How4 x 8 sheet ofmanyply wood do you need tocover a 24 x 24 deck?

Answers

Given

Dimensions of deck = 24 by 24

dimensions of ply wood = 4 by 8

Find

Number of sheets of ply wood needed to cover the deck

Explanation

number of sheets = area of deck divided by area of 1 ply wood

so ,

area of deck =

[tex]\begin{gathered} 24\times24 \\ 576 \end{gathered}[/tex]

and

area of ply wood =

[tex]\begin{gathered} 4\times8 \\ 32 \end{gathered}[/tex]

so ,

number of sheets needed =

[tex]\begin{gathered} \frac{576}{32} \\ \\ 18 \end{gathered}[/tex]

Final Answer

Hence , the required number of sheets of ply wood is 18

Simplify the following expression. Assume variables are positive. Express your answer using rational exponents.

Answers

Let's simplify the expression:

[tex]\begin{gathered} (x^{-\frac{1}{2}}\cdot y^{-\frac{2}{3}}\cdot z^{-2})^{-\frac{1}{2}}=x^{(-\frac{1}{2})(-\frac{1}{2})}y^{(-\frac{2}{3})(-\frac{1}{2})}z^{(-2)(-\frac{1}{2})} \\ =x^{\frac{1}{4}}y^{\frac{1}{3}}z \end{gathered}[/tex]

Therefore the answer is:

[tex]x^{\frac{1}{4}}y^{\frac{1}{3}}z[/tex]

Find sinif cos 0 = is in the first quadrant. 5 OA. OB. OC. 2/20 OD. 25/ M5 Reset Selection

Answers

Answer: B. 3/5

This question can be solved by using trigonometric identities.

- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of the axis of symmetry and whether the function's graph is steeper than, flatter than, or the same shape as the graph of f(x)=x²

Answers

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

[tex]\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}[/tex]

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

[tex]=x^2-12x+37[/tex][tex]\mathrm{The\: parabola\: params\: are\colon}[/tex][tex]a=1,\: b=-12,\: c=37[/tex][tex]x_v=-\frac{b}{2a}[/tex][tex]x_v=-\frac{\left(-12\right)}{2\cdot\:1}[/tex][tex]\mathrm{Simplify}[/tex][tex]x_v=6[/tex][tex]y_v=6^2-12\cdot\: 6+37[/tex]

Simplify:

[tex]y_v=1[/tex]

[tex]\mathrm{Therefore\: the\: parabola\: vertex\: is}[/tex][tex]\mleft(6,\: 1\mright)[/tex][tex]\mathrm{If}\: a<0,\: \mathrm{then\: the\: vertex\: is\: a\: maximum\: value}[/tex][tex]\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}[/tex][tex]a=1[/tex][tex]\mathrm{Minimum}\mleft(6,\: 1\mright)[/tex][tex]\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}[/tex]

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

[tex]y=x^2-12x+37[/tex][tex]\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}[/tex][tex]a=1,\: b=-12[/tex][tex]x=\frac{-\left(-12\right)}{2\cdot\:1}[/tex][tex]\mathrm{Refine}[/tex]

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

r is the midpoint of op and qr is perpendicular to op in the diagram below find the the length of qr

Answers

Given:

OP = 20 in

QP = 26 in

Since R is the midpoint of OP, then, OR = RP

Thus

[tex]OR=RP=\frac{OP}{2}=\frac{20}{2}=10\text{ in}[/tex]

To find the length of QR, use pythagoras theorem below:

[tex]\begin{gathered} a^2+b^2=c^2 \\ \\ RP^2+QR^2=PQ^2 \end{gathered}[/tex]

Input values into the formula:

[tex]10^2+QR^2=26^2[/tex]

Subtract 10² from both sides:

[tex]\begin{gathered} 10^2-10^2+QR^2=26^2-10^2 \\ \\ QR^2=26^2-10^2 \end{gathered}[/tex]

Take the square root of both sides:

[tex]\begin{gathered} \sqrt[]{QR^2}=\sqrt[]{26^2-10^2} \\ \\ QR=\sqrt[]{676-100} \\ \\ QR=\sqrt[]{576} \\ \\ QR=24 \end{gathered}[/tex]

Therefore, the length of QR is 24 in

Please help, algebra 1, i dont know how to begin to solve it :/ thank you thank you.Simplify:

Answers

Given the expression:

[tex](x^2-4x^3)+(5x^3+3x^2)[/tex]

You can simplify it as follows:

1. Distribute the positive sign. Since the sign between the parentheses is positive, it does not change the signs of the second parentheses:

[tex]=x^2-4x^3+5x^3+3x^2[/tex]

2. Add the like terms.

By definition, like terms have the same variables with the same exponent.

In this case, you need to add the terms with exponent 3 and add the terms with exponent 2. Notice that:

[tex]\begin{gathered} -4x^3+5x^3=x^3 \\ \\ x^2+3x^2=4x^2 \end{gathered}[/tex]

Then, you get:

[tex]=x^3+4x^2[/tex]

Hence, the answer is:

[tex]=x^3+4x^2[/tex]

How long does it take Tina to type 864 words, if she took 15 minutes to type out an assignment that comprised 720 words?

Answers

Given data:

The given time taken by Tin to type 720 words is t=15 min.

The given expression can be wriiten as,

720 word=15 min

720 words= 15(60 sec)

720 words= 900 sec

1 word = 900/720 sec

=1.25 sec

Multiplying the above equation with 864 on both sides .

864 words= 864(1.25) sec

= 1080 sec

=1080/60 min

= 18 min.

Thus, the time taken bby Tine to type 864 words is 18 min.

Paula will make fruit punch for a party she will mix 1 1/2 gallons of orange juice with 5/8 of a gallon of pineapple juice how many 1/8 gallon servings will Paula have

Answers

First let's find the total number of gallons of the fruit punch. To do so, we just need to sum the gallons of orange juice (1 1/2) ith the gallons of pineapple juice (5/8):

[tex]1\frac{1}{2}+\frac{5}{8}=\frac{3}{2}+\frac{5}{8}=\frac{12}{8}+\frac{5}{8}=\frac{17}{8}[/tex]

Now, in order to find how many 1/8 servings can be made, we need to divide the total number of gallons of the fruit punch by the number of gallons of a serving:

[tex]\frac{\frac{17}{8}}{\frac{1}{8}}=\frac{17}{8}\cdot\frac{8}{1}=17[/tex]

So Paula can have 17 servings.

Answer:

17

Step-by-step explanation:

5/8 - 5

1 1/2 - 12

The Muffin Shop makes no-fat blueberry muffins that cost $.70 each. The Muffin Shop knows that 15% of the muffins will spoil. If The Muffin Shop wants 40% markup on cost and produces 800 muffins, what should The Muffin Shop price each muffin?

Answers

If The Muffin Shop wants a 40% markup on cost and produces 800 muffins, The Muffin Shop should price each muffin at $1.15.

How is the price determined?

The total expected revenue is divided by the total unspoiled units sold to determine the selling price.

This is illustrated below.

Cost per unit of muffins = $0.70

The spoilage rate = 15%

Expected markup on cost = 40%

The total production units = 800 muffins

The total good units sold = 680 (800 x 1 - 15%)

Total cost for 800 units = $560 (0.70 x 800)

The markup on cost = $224 ($560 x 40%)

The total expected sales revenue = $784 ($560 + $224)

Seling price per unit = $1.15 ($784/680)

Thus, The Muffin Shop should price each muffin at $1.15 to meet its goals.

Learn more about pricing with the markup at https://brainly.com/question/1153322

#SPJ1

Solve for x. 8x-2x+7>21+10

Answers

Answer: [tex]x > 4[/tex]

Step-by-step explanation:

[tex]8x-2x+7 > 21+10\\\\6x+7 > 31\\\\6x > 24\\\\x > 4[/tex]

Element X decays radioactively with a half life of 14 minutes. If there are 460 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 35 grams?

Answers

Step 1

Given;

[tex]\begin{gathered} Intially\text{ y}_0=460g \\ Half\text{ life, h=14 minutes} \\ y=\frac{460}{2}=230g,\text{ when t=h=14 min} \\ \end{gathered}[/tex]

Putting these values in, we have;

[tex]\begin{gathered} 230=a(0.5)^1 \\ a=\frac{230}{0.5}=460g \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} y=460(0.5)^{\frac{t}{14}}---(1) \\ when\text{ y=35} \\ 35=460(0.5)^{\frac{t}{14}} \end{gathered}[/tex][tex]\begin{gathered} 35=460(0.5)^{\frac{t}{14}} \\ \frac{460\cdot \:0.5^{\frac{t}{14}}}{460}=\frac{35}{460} \\ 0.5^{\frac{t}{14}}=\frac{7}{92} \\ \frac{t}{14}\ln \left(0.5\right)=\ln \left(\frac{7}{92}\right) \\ t=\frac{14\ln\left(\frac{7}{92}\right)}{\ln\left(0.5\right)} \\ t=52.02689 \\ t\approx52.0\text{ minutes to the nearest tenth of a minute} \end{gathered}[/tex]

Answer;

[tex]52.0\text{ minutes to the nearest tenth of a minute}[/tex]

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