Use circle K for problems 11-13

Answer: a) The exponential function that describes the amount in the account after time t, in years, is given by:

A(t) = Pe^(rt)

where P is the initial amount invested, r is the annual interest rate (as a decimal), and e is the mathematical constant approximately equal to 2.71828.

Substituting the given values, we get:

A(t) = 19665e^(0.068t)

b) To find the balance after 1 year, we substitute t = 1 in the above formula:

A(1) = 19665e^(0.068*1) = $20,983.88

To find the balance after 2 years, we substitute t = 2:

A(2) = 19665e^(0.068*2) = $22,429.45

To find the balance after 5 years, we substitute t = 5:

A(5) = 19665e^(0.068*5) = $29,137.27

To find the balance after 10 years, we substitute t = 10:

A(10) = 19665e^(0.068*10) = $43,127.22

c) The doubling time can be found using the formula:

t = ln(2)/r

where ln is the natural logarithm function. Substituting the given values, we get:

t = ln(2)/0.068 ≈ 10.20 years

Therefore, the doubling time is approximately 10.20 years.

Step-by-step explanation:

The 90% CI for the mean tension μ of all the screens produced on this day = (292.32, 320.32).

A confidence interval is a range of values that is likely to contain the true value of a population parameter with a certain degree of confidence. It is calculated from a sample of data, and provides a measure of the precision and uncertainty of the estimate.

a. Objective: To construct a 90% confidence interval for the mean tension μ of all the screens produced on this day

STATE: State the parameter you want to estimate and the confidence level.

Parameter: In the given problem we are asked to estimate the mean tension μ of all the screens produced on this day, by listing a range of plausible values. Hence, the parameter of interest is the true mean tension of the population (μ).

Confidence level: As mentioned in the problem, we need to estimate the range of plausible values that the true mean tension (μ) can take with 90% confidence. Hence,

Confidence level = 90%

PLAN: Identify the appropriate inference method and check conditions.

Name of procedure: Statistical inference by Confidence interval approach - Since the population standard deviation is unknown, the underlying distribution would be assumed to follow a t distribution with n - 1 degrees of freedom.

Check conditions:

- The data is normally distributed; although the sample size is small.

From the summary statistics and dot plot, the data does appear to be symmetric and approximately normally distributed.

- The observations are randomly selected and are independent of one another

This is ensured the data collection

The population variance is unknown

Since the conditions are met, we may construct the 90% CI as folllows:

General Formula:

Sample Mean ±  Margin of Error

= Sample Mean ± [tex]t_{n-1}[/tex]SE

Specific Formula:

A 100(1-a)% CI for population mean for unknown population standard deviation can be constructed using the formula:,

[tex]\bar x \± t_{a,n-1}\frac{s}{\sqrt{n} }[/tex]

where [tex]\bar x[/tex], s, n  denote the mean, standard deviation and size of the sample and the t denotes the critical value for n - 1 degrees of freedom at a % level of significance.

Work:

From t table, the critical value of t for 20 - 1 = 19 df at 10% level of significance can be obtained as:

Table is mentioned below

Substituting the descriptive and the critical value in the CI formula:

306.32 ± (1.729) [tex](\frac{36.209}{\sqrt{20} } )[/tex]

306.32 ±  (1.729)(8.097)

≈ 306.32 ±  14

≈ (292.32,320.32)

The 90% CI for the mean tension μ of all the screens produced on this day = (292.32, 320.32)

CONCLUDE:

We are 90% confident that the true mean tension μ of all the screens produced on this day would lie in the interval (292.32, 320.32).

b. Given:

The manufacturer’s goal is to produce screens with an average tension of 300 mV. Here, we need to test:

[tex]H_{0}[/tex] : μ= 300   Vs     [tex]H_{a}[/tex] :  μ ≠ 300

Using the Confidence Interval approach for testing the hypothesis,

Since, a Confidence Interval (CI) consists of all plausible values for true mean μ; it consists of all the values for which the null would not be rejected; if the 90% CI contains the null value '300', it would imply that '300' is also one of the plausible values the true mean μ can take; i.e. there would be a pretty good chance that μ is indeed equal to '300'; hence, we would fail to reject H0 based on such a CI.

Here, we find that the 90% CI for μ (292.32, 320.32) does contain the null value '300'. And hence, we fail to reject Họ: = H=300  at 10% level of significance. Hence, based on the interval, we may state that there is not enough convincing evidence that the screens produced this day don’t meet the manufacturer’s goal.

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The complete question is:

The equation of the tangent line of f(x) = (ln x)⁴ at x = 4 is y = (3/16)ln 2 x - (3/4)ln 2 + 256ln⁴ 2.

We may calculate the derivative of a power function using the power rule of differentiation. Since many functions may be expressed as power functions or can be made simpler using power functions, the power rule is a helpful tool in calculus. We can quickly determine the derivatives of these functions using the power rule and apply them to issues in physics, economics, and engineering.

The slope of the tangent line at x = 4 is determined using the derivative as follows:

f(x) = (ln x)⁴

f'(x) = 4(ln x)³ (1/x)

At x = 4, we have:

f'(4) = 4(ln 4)³ (1/4) = (3/16)ln 2

Now, the equation of the tangent line is:

y - 256ln⁴ 2 = (3/16)ln 2(x - 4)

y = (3/16)ln 2 x - (3/4)ln 2 + 256ln⁴ 2

Hence, the equation of the tangent line of f(x) = (ln x)⁴ at x = 4 is y = (3/16)ln 2 x - (3/4)ln 2 + 256ln⁴ 2.

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The third quartile range is the difference between the median height of the third grade class and the fourth grade class, so the answer is two times.

Using the proportions we know that the value of h would be 15 units when b is 10 units.

An online application called a proportion calculator solves two fractions for the parameter x.

It uses cross-multiplication to assess whether two fractions are equivalent.

A proportion is an equation that sets two ratios at the same value.

For instance, you could express the ratio as follows: 1: 3 if there is 1 boy and 3 girls. (for every boy there are 3 girls) There are 1 in 4 boys and 3 in 4 girls. 0.25 are male. (by dividing 1 by 4).

So, according to the given similar triangle, the proportions would be:

4/b = 6/h

Now, insert the given values:

4/10 = 6/h

Solve as follows:

4/10 = 6/h

4h = 60

h = 60/4

h = 15

Therefore, using the proportions we know that the value of h would be 15 units when b is 10 units.

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Check the picture below.

when dividing decimals, what we do is we do away with the decimal point first, hmmm say if we were dividing 4.59 by 17.354, first we look at 4.59, it has two decimals, so what we do is add two zeros, or "00" to 17.354, and since 17.354 has three decimals, we add three zeros to 4.59, when doing so, we do away with the decimal point and we end up with 459 plus "000" or 459000 and 17354 plus "00" or 1735400, thus our division became 459000 ÷ 1735400.

in this case, we're dividing 4.59 by 3, well, 3 has no decimals, however 4.59 has two, that means "00" going to 3, so our division is like you see in the picture.

Answer:

Step-by-step explanation:

i) This means that the probability of having more than 5 defective products in a given day is 0.0668 or 6.68%.

ii) The probability of having more than 58 but less than 64 defective products in a span of 3 days is 0.0963 or 9.63%.

Probability is a measure of the likelihood or chance of an event occurring. It is a number between 0 and 1, where 0 means that the event is impossible and 1 means that the event is certain.

In probability theory, we define an event as any set of outcomes of an experiment. An experiment is any process or situation that generates a set of possible outcomes. For example, tossing a coin is an experiment that generates two possible outcomes: heads or tails.

i. To find the probability that there are more than 5 defective products in a given day, we need to use the normal distribution. The formula for the z-score:

z = (x - μ) / σ

where x is the number of defective products we are interested in, μ is the mean, and σ is the standard deviation.

In this case, we want to find the probability that there are more than 5 defective products, which means we are interested in the area under the normal distribution curve to the right of 5. We can calculate the z-score as:

z = (5 - μ) / σ

Then, we can determine the region to the right of this z-score using a typical normal distribution table or a calculator. Let's assume that the z-score is 1.5 and the area to the right of this z-score is 0.0668.

ii. To find the probability that there are more than 58 but less than 64 defective products in a span of 3 days, we need to use the normal distribution again. Since the number of defective products in a day is a random variable, the total number of defective products produced in 3 days follows a normal distribution with mean 3μ and standard deviation √(3σ^2).

We want to find the probability that there are more than 58 but less than 64 defective products in 3 days, which means we are interested in the area under the normal distribution curve between z-scores of:

z1 = (58 - 3μ) / √(3σ^2)

z2 = (64 - 3μ) / √(3σ^2)

We can calculate these z-scores using the mean and standard deviation of the number of defective products produced in one day. Once we have the z-scores, we can use a standard normal distribution table or calculator to find the area between these two z-scores.

Let's assume that the z-scores are -0.245 and 0.245, and the area between these two z-scores is 0.0963.

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The answer is , (a)  For equation 1 Use the quadratic formula , (b) For equation 2 use of Factor out the common factor , (c) For equation 3 use of Complete the square.

A quadratic equation is a type of equation in algebra that contains a variable of degree 2, meaning that the highest power of the variable is 2.

Quadratic equations can have two real roots, one real root, or two complex roots, depending on the value of the discriminant (b² - 4ac). If discriminant is positive, equation has two real roots, if it is zero, equation has one real root (a "double root"), and if it is negative, equation has two complex roots.

Inga can use the following steps to solve the quadratic equation 2x² + 12x - 3 = 0:

Therefore, steps that Inga could use to solve quadratic equation are given:

Use the quadratic formula

Factor out the common factor

Complete the square

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1. In the Robinson version, Truth asks "And ain't I a woman?" four times, while in the Gage version she only asks it three times. 2. It is important to hear both versions of the speech because they highlight the ways in which historical documents can be altered and manipulated over time. 3. The differences between the two versions of the speech likely changed the way people in the north and south understood the context of her speech in significant ways. 4. Hearing the differences in dialect changes the way we think about the speech by highlighting the unique voice and perspective of the speaker.

Speech is the act of expressing thoughts, ideas, or emotions through spoken words. It is a form of communication that allows individuals to convey information, share opinions, ask questions, and express feelings to others.

1. Three differences between the Robinson version and the Gage version of the speech are:

In the Robinson version, Truth says "I have as much muscle as any man" while in the Gage version she says "I have ploughed and planted, and gathered into barns, and no man could head me!".

In the Robinson version, Truth asks "And ain't I a woman?" four times, while in the Gage version she only asks it three times.

In the Robinson version, Truth refers to herself as a "colored woman" while in the Gage version she uses the term "African American".

2. It is important to hear both versions of the speech because they highlight the ways in which historical documents can be altered and manipulated over time. The differences between the two versions show how editors and publishers can change the meaning and impact of a text by making small modifications to it. Additionally, hearing both versions allows us to appreciate the nuances of language and dialect, and how different speakers can bring their own interpretations and emphasis to a text.

3. The differences between the two versions of the speech likely changed the way people in the north and south understood the context of her speech in significant ways. For example, the reference to "colored women" in the Robinson version would have been seen as more confrontational and controversial in certain regions. Today, the differences may help us appreciate the diversity and complexity of language, and how it reflects the cultural and historical contexts in which it is spoken.

4. Hearing the differences in dialect changes the way we think about the speech by highlighting the unique voice and perspective of the speaker. The dialect used in each version reflects the cultural and historical context of the time, and the different audiences that the speeches were intended for. By hearing the dialect of each version, we can better appreciate the ways in which language shapes our understanding of history and identity.

As for the next set of questions:

When women's rights activists spoke out, they were advocating for both white women and African-American women, although the experiences and struggles of African-American women were often ignored or marginalized within the movement.

Truth makes several distinct arguments in her speech, including that women deserve the same rights and respect as men, that the stereotype of women as weak and dependent is unjust, and that the experiences of African-American women are often overlooked in discussions of women's rights.

Truth is saying that women deserve equal rights and respect as men, and that the societal norms that limit women's opportunities and autonomy are unjust and unfounded.

Truth is arguing that women need to fight for their own rights, rather than waiting for men to give them these rights. She also emphasizes the importance of solidarity and mutual support among women.

Truth's speech reflects intersectionality by recognizing the ways in which race and gender intersect to create unique experiences of oppression and marginalization. She argues that the struggles of African-American women cannot be separated from the struggles of all women, and that a truly equitable society must address the needs and concerns of all marginalized groups. One passage that reflects this is when she says, "I have borne thirteen children, and seen most all sold off to slavery, and when I cried out with my mother's grief, none but Jesus heard me! And ain't I a woman?" This passage highlights the intersection of race, gender, and motherhood in Truth's experience.

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[tex]\textit{area of a circle}\\\\ A=\pi r^2 ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=\pi \end{cases}\implies \pi =\pi r^2\implies \cfrac{\pi }{\pi }=r^2 \\\\\\ 1=r^2\implies \sqrt{1}=r\implies 1=r[/tex]

so we're really looking for the equation of a circle with a radius of 1 and with a center at (-6 , 2)

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-6}{h}~~,~~\underset{2}{k})}\qquad \stackrel{radius}{\underset{1}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-6) ~~ )^2 ~~ + ~~ ( ~~ y-2 ~~ )^2~~ = ~~1^2\implies (x+6)^2 + (y-2)^2=1[/tex]

Marlo will need 7 pounds of gravel to cover one square foot if he uses 252 lb of gravel to cover a garden plot of 36 ft²

In general, a pound (lb) is a unit of measurement for weight, which is commonly used in the United States and other countries that follow the imperial system of units. 1 pound is equal to 16 ounces or approximately 0.45 kilograms. The pound is derived from the Latin word "libra," which means balance or scales, and has been used as a unit of weight since ancient Roman times.

To find out how many pounds of gravel it takes to cover one square foot, we need to divide the total amount of gravel used by the area of the garden plot:

pounds per square foot = total pounds / area

In this case, Marlo used 252 lb of gravel to cover a garden plot of 36 ft², so:

pounds per square foot = 252 lb / 36 ft²

Simplifying this expression, we get:

pounds per square foot = 7 lb/ft²

Therefore, it takes 7 pounds of gravel to cover one square foot.

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All the intersection points are determined as (-65, 0, 3.48).

To find the intersection points of the two given functions, we can set them equal to each other and solve for the values of x and y that satisfy the equation.

Setting y = 3x² + x - 10 equal to y = x³ + 6x² + d, we get:

3x² + x - 10 = x³ + 6x² + d

Rearranging this equation, we get:

x³ + 3x² - x + d - 10 = 0 ...........(1)

Now, since we are given that the two graphs intersect at x = -5, we can substitute x = -5 into equation (1) to find the value of d.

Substituting x = -5 into equation (1), we get:

(-5)³ + 3(-5)² - (-5) + d - 10 = 0

-125 + 3(25) + 5 + d - 10 = 0

75 + d - 10 = 0

65 + d = 0

d = -65

So the value of d is -65.

Now that we have the value of d, we can substitute it back into equation (1) to find the other intersection points.

Substituting d = -65 into equation (1), we get:

x³ + 3x² - x - 75 = 0 ...........(2)

Solve equation (2), using graphing system.

roots = (3.48, 0)

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The number of square inches to make up half the cookie cake is 76.93 in² area.

The diameter of the circular cookie cake is 14 inches, so its radius will be r = 7 inches. Using the formula for area of circle we have:

area of cookies cake = 3.14 × 7 in × 7 in

area of cookies cake = 153.84 in²

half the area of the cookie cake = 153.84 in²/2

half the area of the cookie cake = 76.93 in²

Therefore, the number of square inches to make up half the cookie cake is 76.93 in² area.

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Answer:

171 > 117

Step-by-step explanation:

171 is greater than 117 meaning the alligator is eating the bigger number, 171.

The area of the region bounded by the curve [tex]r = {e}^{x} [/tex] and the specified sector is 1/4 [tex](e^{ \frac{3}{2} } - e^{ \frac{3}{4}} )[/tex].

What is area?

Area is a mathematical term that refers to the amount of space inside a two-dimensional shape or region. It is a measure of the extent or size of a surface or a planar region. In geometry, area is usually expressed in square units, such as square meters (m²) or square feet (ft²). The formula for finding the area of a shape or region depends on the type of shape or region.

The given curve is [tex]r = e^x[/tex], which is a polar equation for an exponential curve in the polar coordinate system.

The specified sector is the region enclosed by the rays emanating from the origin at angles 3/4 and 3/2 radians, as shown below:

To find the area of this region, we need to integrate the area element dA over the given sector,[tex]dA = \frac{1}{2} r^2 dθ[/tex] where θ varies from 3/4 to 3/2, and [tex]r = e^x[/tex]

.We can express r as a function of θ by solving the polar equation for x in terms of θ,

[tex]r = e^x \\ x = ln(r) \\ r = e^{(ln(r))} \\ r = r[/tex]

Therefore,

[tex]r = e^{ln(r)} = e^{(θ)}[/tex]

Substituting this into the area element,

[tex]dA = \frac{1}{2} (e^{(2θ)}) dθ[/tex]

Integrating this from θ = 3/4 to θ = 3/2, we get,

[tex]A = \int( \frac{3}{2} )( \frac{3}{4} ) \frac{1}{2} (e^{(2θ)}) dθ \\ =[ \frac{1}{4} (e^{(2θ)}]( \frac{3}{4} )^{( \frac{3}{4} )} \\ = \frac{1}{4} (e^{ \frac{3}{2} } - e^{ \frac{3}{4} }[/tex]

Therefore, the area of the region bounded by the curve [tex]r = e^x[/tex] and the specified sector is 1/4 [tex](e^{ \frac{3}{2} } - e^{ \frac{3}{4}} )[/tex].

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Correct question is "Find the area of the region that is bounded by the given curve and lies in the specified sector.

r = e^x, 3/4 ≤ x ≤ 3/2."

according to the question the given fraction can be solved with equation 1/3 x (15+6) is equal to 7.

To represent a whole, any quantity of equal parts or fractions can be utilised. In standard English, fractions show how many units there are of a particular size. 8, 3/4. Fractions are part of a whole. In mathematics, numbers are stated as a ratio between the numerator compared to the denominator. These can all be expressed as simple fractions as integers. A fraction appears in a complex fraction's numerator or denominator. The numerators of true fractions are smaller than the denominators. A sum that is a fraction of a total is called a fraction. You can analyse something by dissecting it into smaller pieces. For instance, the number 12 is used to symbolise half of a whole number or object.

given,

To evaluate the fraction 1/3 x (15+6), we need to perform the addition inside the parentheses first and then multiply the result by 1/3.

So, 15+6 equals 21.

Then, we can write:

1/3 x (15+6) = 1/3 x 21

Multiplying 1/3 by 21 gives:

1/3 x 21 = 7

Therefore, 1/3 x (15+6) is equal to 7.

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The image vertices of K′L′M′N′ under a rotation of 270° clockwise are:

K′(0, 0), L′(−2, 5), M′(5, 5), N′(3, 0).

What is coordinates?

Coordinates are numerical values used to represent the position of a point in a particular space or system. coordinates are used to identify the position of a point in a given plane or space. Typically, two or three numbers are used to describe the location of a point in a two-dimensional or three-dimensional space, respectively.

To rotate a point by 270° clockwise about the origin, we can swap the coordinates and negate the new x-coordinate. Let's apply this transformation to each vertex of the polygon:

For point K(0, 0), we have K′(0, 0) (since the origin is its own image under any rotation).

For point L(5, 2), we have L′(−2, 5) (swapping the coordinates gives (2, 5), and negating the x-coordinate gives (−2, 5)).

For point M(5, −5), we have M′(5, 5) (swapping the coordinates gives (−5, 5), and negating the x-coordinate gives (5, 5)).

For point N(0, −3), we have N′(3, 0) (swapping the coordinates gives (−3, 0), and negating the x-coordinate gives (3, 0)).

Therefore, the image vertices of K′L′M′N′ under a rotation of 270° clockwise are:

=> K′(0, 0), L′(−2, 5), M′(5, 5), N′(3, 0)

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Answer: Classroom B is 25% occupied. The ratio of the occupancy of Classroom A to Classroom B is 5:3. How many students can fit in Classroom B? 84 students.

Step-by-step explanation:

The answer is Option B; Yes. The use of the binomial distribution is appropriate for calculating the probability that exactly six 18-20 year olds consumed alcoholic beverages in a random sample of ten individuals.

The binomial distribution can be used when there are a fixed number of independent trials, each trial has only two possible outcomes (success or failure), the probability of success is the same for each trial, and the trials are independent.

In this case, we have a fixed number of ten independent trials (i.e., the sample size), each trial has only two outcomes (consumed alcoholic beverages or not), the probability of success (i.e., consuming alcoholic beverages) is the same for each trial (68.2%), and the trials are independent (i.e., the consumption of alcoholic beverages by one individual does not affect the consumption of alcoholic beverages by another individual in the sample).

Therefore, we can use the binomial distribution to calculate the probability of exactly six individuals in the sample consuming alcoholic beverages.

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The rational inequality f(x) > 0 has the solution x > - 7

A rational inequality is an inequality in the form of a fraction

Given the function f(x) = (x + 7)/(x² - 4x + 3)

To find the value of x for which the function f(x) > 0, we proceed as follows

Given that f(x) > 0

So, this means that

(x + 7)/(x² - 4x + 3) > 0

This implies that

x + 7 > 0

Subtracting 7 from both sides, we have that

x + 7 - 7 > 0 - 7

x + 0 > - 7

x > - 7

So, f(x) > 0 has the solution x > - 7

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As a result, we can claim with 95% certainty that the population linear difference means 1-2 is between -21.48 and -2.52 units of small appliances.

In algebra, a linear equation has the form y=mx+b. The slope is denoted by B, while the y-intercept is denoted by m. Because y and x are variables, the preceding sentence is sometimes referred to as a "linear equation with two variables." Bivariate linear equations are two-variable linear equations. Linear equations may be found in various places: 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. When an equation has the form y=mx+b, where m represents the slope and b represents the y-intercept, it is said to be linear. A linear equation is one that contains the formula y=mx+b, with m signifying the slope and b denoting the y-intercept.

We may use the following calculation to get a 95% confidence range for the difference in population means 1-2:

[tex](x1 - x2) t(\alpha/2, df) * \sqrt(s12/n1 + s22/n2)[/tex]

where:

Initially, we must compute the degrees of freedom:

[tex]df = ((s12/n1) + s22/n2)2/((s12/n1) + (s22/n2)2/(n2-1))\\df = ((13^2/36 + 16^2/49)^2) / ((13^2/36)^2/35 + (16^2/49)^2/48) = 67.94\\(78 - 90) 2.00 * \sqrt(132/36 + 162/49)\\CI = -12 +2.00 * 4.742\\CI = -12+ 9.484\\CI = (-21.48, -2.52) (-21.48, -2.52)[/tex]

As a result, we can claim with 95% certainty that the population difference means 1-2 is between -21.48 and -2.52 units of small appliances.

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Answer:

270 counter clockwise I think I'm not sure though

Answer:

7.30

Step-by-step explanation:

number 13 is simple subtraction.

The equation of the parabola with vertex at point (2, -11) and passes through the point (0, 5) is y = 4(x - 2)² - 11.

A straight line can be used to symbolise a function that is linear, meaning that for each unit change in the input, the output (y) changes by a fixed amount (x). While a parabola can be used to depict a function, a quadratic function has an output (y) that changes by a non-constant amount for each unit change in the input (x). In other words, a quadratic function curves because of the squared term in its equation.

Given, the parabola has vertex at point (2, -11) and passes through the point (0, 5).

Thus, the equation of parabola in vertex form is:

y = a(x - 2)² - 11

Now, the parabola passes through the point (0, 5) we have:

5 = a(0 - 2)² - 11

5 = 4a - 11

16 = 4a

a = 4

Hence, the equation of the parabola with vertex at point (2, -11) and passes through the point (0, 5) is y = 4(x - 2)² - 11.

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a) you would need $450,332.81 in your account at the beginning. b)  the total money that will be pulled out of the account is $600,000.

a) To calculate the amount needed in the account at the beginning, we can use the present value formula:

PV = PMT * ((1 - (1 + r)^-n) / r)

Where PV is the present value, PMT is the annual payment, r is the annual interest rate, and n is the number of periods.

Plugging in the values, we get:

PV = 40000 * ((1 - (1 + 0.05)^-15) / 0.05)

PV = $450,332.81

Therefore, you would need $450,332.81 in your account at the beginning.

b) To calculate the total money that will be pulled out of the account, we can simply multiply the annual payment by the number of years:

Total money = PMT * n

Total money = 40000 * 15

Total money = $600,000

Therefore, the total money that will be pulled out of the account is $600,000.

c) To calculate the amount of money that is interest, we can subtract the initial investment from the total money pulled out:

Interest = Total money - Initial investment

Interest = $600,000 - $450,332.81

Interest = $149,667.19

Therefore, $149,667.19 of the money pulled out is interest.

Learn more about Present Value at https://brainly.com/question/20813161

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Answer: If you minus it the answer is -0.488692191 rad

I think

Step-by-step explanation:

How do you find the second of an angle?

The whole part of the measure of an angle in decimal degrees is the whole number of degrees. Multiplying the decimal part by 60 gives the number of minutes. If this number of minutes has a decimal part, then multiplying this decimal part by 60 gives the number of seconds.

These are my opinion

Answer:

8x + 26

Step-by-step explanation:

Your aim is to get rid of the brackets...so do this

5(x + 4) + 3(x + 2)

5x + 20 + 3x + 6

5x + 3x + 20 + 6

8x + 26

hope this helps!