use matrices D, E, and F to find each sum or product

Use Matrices D, E, And F To Find Each Sum Or Product

Answers

Answer 1

Problem

Solution

5. E-D

Procedure

-3-2 =-5

-4-1=-5

0-7=-7

1-5=-4

2-3=-1

6- (-4)=10

And the answer would be:

-5 -5

-7 -4

-1 10

6. 3F

Procedure

3* -2=-6

3 *5 = 15

3* 1= 3

3*3 = 9

3*14=12

3 * -6= -18

And the answer would be:

-6 15 3

9 12 -18

Use Matrices D, E, And F To Find Each Sum Or Product

Related Questions

The circle graph shows how the annual budget for a company is divided by department. If the amount budgeted for support, sales, and media combined is $25,000,000, what is the total annual budget?

Answers

Answer: $50,000,000

Explanation:

First, we add up the percentage of support, sales, and media covers. Given that:

Support = 23%

Sales = 22%

Media = 5%

The total percentage would be

[tex]23\%+22\%+5\%=50\%[/tex]

This would mean that $25,000,000 covers half of the annual budget. The other half would be of the same amount, therefore, the total annual budget would be:

[tex]\begin{gathered} 50\%+50\%=100\% \\ \$25,000,000+\$25,000,000=\$50,000,000 \end{gathered}[/tex]

What is the value of 3/8 dividend by 9/10
A) 3
B 5/12
C 27/80
D 2/3

Answers

Answer:

B 5/12 (im stupi d)

Step-by-step explanation:

(3/8)/(9/10) = (3/8) * (10/9) = 5/12

Answer:

B) [tex]\frac{5}{12}[/tex]

Step-by-step explanation:

Apply the fractions rule a/b ÷c/b = a/b × d/c

= 3/8 x 10/9

Multiply fractions a/b x c/d = [tex]\frac{axc}{b x d}[/tex]

Multiply the numbers: 3 x 10 = 30

= 3/10 8 x 9

Multiply the numbers: 8 x 9 = 72

= 30/72

Cancel the common factor: 6

5/12

Choose an equation that models the verbal scenario. The cost of a phone call is 7 cents to connect and an additional 6 cents per minute (m).

Answers

"The cost of a phone call is 7 cents to connect and an additional 6 cents per minute (m)"

If "C" indicates the total cost of a phone call and "m" corresponds to the number of minutes the phone call lasted.

The phone call costs 7 cents to connect, this means that regardless of the duration of the call, you will always pay this fee. This value corresponds to the y-intercept of the equation.

Then, the phone call costs 6 cents per minute, you can express this as "6m"

The total cost of the call can be calculated by adding the cost per minute and the fixed cost:

[tex]C=6m+7[/tex]

Let f(x) = 2x² + 14x – 16 and g(x) = x+8. Perform the function operation and then find the domain of the result.(x) = (simplify your answer.)

Answers

We need to find the following division of the functions f(x) and g(x):

[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=\frac{2x^2+14x-16}{x+8}[/tex]

We can note that the numerator can be rewritten as

[tex]2x^2+14x-16=2(x^2+7x-8)=2(x+8)(x-1)[/tex]

Then the division can be written as:

[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=\frac{2(x+8)(x-1)}{x+8}[/tex]

From this result, we can cancel out the term (x+8) from both sides and get,

[tex]\frac{f}{g}(x)=\frac{f(x)}{g(x)}=2(x-1)[/tex]

Therefore, the result of the division is:

[tex]\frac{f}{g}(x)=2(x-1)[/tex]

which domain is all real numbers:

[tex]x\in(-\infty,\infty)[/tex]

What is the equation of the following line written in slope-intercept form? Oy=-3/2x-9/2
Oy=-2/3x+9/2
Oy=3/2x-9/2​

Answers

The equation of the line in slope-intercept form is: C. y = -3/2x - 9/2

How to Write the Equation of a Line?

If we determine the slope value, m, and the y-intercept value of the line, b, we can write the equation of a line in slope-intercept form as y = mx + b by substituting the values.

Slope of a line (m) = change in y / change in x.

y-intercept of a line is the point on the y-axis where the value of x = 0, and the line cuts the y-axis.

Slope of the line in the diagram, m = -3/2

y-intercept of the line, b = -9/2.

Substitute m = -3/2 and b = -9/2 into y = mx + b:

y = -3/2x - 9/2 [equation in slope-intercept form]

Learn more about slope-intercept form on:

https://brainly.com/question/1884491

#SPJ1

For the compound inequalities below (5-7), determine whether the inequality results in an overlapping region or a combined region. Then determine whether the circles are open are closed. Finally, graph the compound inequality. Simplify if needed. x-1>_5 and 2x<14

Answers

The inequalities are:

[tex]x-1\ge5\text{ and }2x<14[/tex]

So, we need to solve for x on both inequalities as:

[tex]\begin{gathered} x-1\ge5 \\ x-1+1\ge5+1 \\ x\ge6 \end{gathered}[/tex][tex]\begin{gathered} 2x<14 \\ \frac{2x}{2}<\frac{14}{2} \\ x<7 \end{gathered}[/tex]

Now, we can model the inequalities as:

So, the region that results is an overlapping region and it is written as:

6 ≤ x < 7

So, the lower limit 6 is closed and the upper limit 7 is open.

Answer: The region is overlaping and it is 6 ≤ x < 7

what is the constant of proportionality in this proportional relationship? x 2 2-1/2 3 3-1/2 y 5/2 25/8 15/4 35/8. answer choices 4/5, 5/4, 4, 5

Answers

a proportional relationship has the following form:

yyy=

I need help with some problems on my assignment please help

Answers

The circumcenter of a triangle is the center of a circumference where the three vertex are included. So basically we must find the circumference that passes through points O, V and W. The equation of a circumference of a radius r and a central point (a,b) is:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

We have three points which give us three pairs of (x,y) values that we can use to build three equations for a, b and r. Using point O=(6,5) we get:

[tex](6-a)^2+(5-b)^2=r^2[/tex]

Using V=(0,13) we get:

[tex](0-a)^2+(13-b)^2=r^2[/tex]

And using W=(-3,0) we get:

[tex](-3-a)^2+(0-b)^2=r^2[/tex]

So we have a system of three equations and we must find three variables: a, b and r. All equations have r^2 at their right side. This means that we can take the left sides and equalize them. Let's do this with the second and third equation:

[tex]\begin{gathered} (0-a)^2+(13-b)^2=(-3-a)^2+(0-b)^2 \\ a^2+(13-b)^2=(-3-a)^2+b^2 \end{gathered}[/tex]

If we develop the squared terms:

[tex]a^2+b^2-26b+169=a^2+6a+9+b^2[/tex]

Then we substract a^2 and b^2 from both sides:

[tex]\begin{gathered} a^2+b^2-26b+169-a^2-b^2=a^2+6a+9+b^2-a^2-b^2 \\ -26b+169=6a+9 \end{gathered}[/tex]

We substract 9 from both sides:

[tex]\begin{gathered} -26b+169-9=6a+9-9 \\ -26b+160=6a \end{gathered}[/tex]

And we divide by 6:

[tex]\begin{gathered} \frac{-26b+160}{6}=\frac{6a}{6} \\ a=-\frac{13}{3}b+\frac{80}{3} \end{gathered}[/tex]

Now we can replace a with this expression in the first equation:

[tex]\begin{gathered} (6-a)^2+(5-b)^2=r^2 \\ (6-(-\frac{13}{3}b+\frac{80}{3}))^2+(5-b)^2=r^2 \\ (\frac{13}{3}b-\frac{62}{3})^2+(5-b)^2=r^2 \end{gathered}[/tex]

We develop the squares:

[tex]\begin{gathered} (\frac{13}{3}b-\frac{62}{3})^2+(5-b)^2=r^2 \\ \frac{169}{9}b^2-\frac{1612}{9}b+\frac{3844}{9}+b^2-10b+25=r^2 \\ \frac{178}{9}b^2-\frac{1702}{9}b+\frac{4069}{9}=r^2 \end{gathered}[/tex]

So this expression is equal to r^2. This means that is equal

Ryan's car used 9 gallons to travel 396 miles. How many miles can the car go on one gallon of gas?On the double number line below, fill in the given values, then use multiplication or division to find the missing value.

Answers

Given:

At 9 gallons, it can travel 396 miles.

Find: At one gallon, it can travel ___ miles.

Solution:

First, let's fill in the number line with the information we have.

Then, to find the missing value ?, let's do cross multiplication.

[tex]\begin{gathered} ?\times9=1\times396 \\ ?\times9=396 \end{gathered}[/tex]

Then, divide both sides of the equation by 9.

[tex]\begin{gathered} \frac{?\times9}{9}=\frac{396}{9} \\ ?=44 \end{gathered}[/tex]

Therefore, on 1 gallon of gas, the car can travel 44 miles.

Chase and his brother want to improve their personal information for when they startapplying to colleges of their choice. To accomplish this they decide to help the SalvationArmy with delivering hot meals to senior citizens. About a month ago, they decided tokeep track of how many successful deliveries they have each completed. As of today,Chase has successfully delivered 18 out of the 30 meals to senior citizens.Part AHow many more meals would Chase have to deliver in a row in order to have a 75%successful delivery record? Justify your answer.Part BHow many more meals would Chase have to deliver in a row in order to have a 90%successful delivery record? Justify your answer.PartAfter successfully delivering 18 out of 30 meals would Chase ever be able to reach a100% successful delivery record? Explain why or why not.

Answers

Part A.

Chase has successfully delivered 18 out of the 30 meals to senior citizens.

We have to calculate how many more meals (lets call it x) she has to deliver to have a 75% successful delivery record.

In order to do that, (18+x) meals have te be delivered successfully out of (30+x), and the successful meals (18+x) divided by (30+x) has to be 0.75:

[tex]\begin{gathered} \frac{18+x}{30+x}=0.75 \\ 18+x=0.75(30+x) \\ 18+x=22.5+0.75x \\ x-0.75x=22.5-18 \\ 0.25x=4.5 \\ x=\frac{4.5}{0.25} \\ x=18 \end{gathered}[/tex]

Chase has to deliver 18 more meals successfully in order to have a 75% success delivery record.

Part B.

We apply the same analysis but we replace 0.75 with 0.9 as the delivery record.

[tex]\begin{gathered} \frac{18+x}{30+x}=0.9 \\ 18+x=0.9(30+x) \\ 18+x=27+0.9x \\ (1-0.9)x=27-18 \\ 0.1x=9 \\ x=\frac{9}{0.1} \\ x=90 \end{gathered}[/tex]

Chase has to deliver 90 more meals successfully in order to have a 90% success delivery record.

Part C.

She won't be able to achieve 100% successful delivery record. We can prove it mathematically, but we already know as there are 12 meals that weren't successfully delivered, so we can get close to 100% but it can't never be reached.

Mathematically we have:

[tex]\begin{gathered} \frac{18+x}{30+x}=1 \\ 18+x=30+x \\ x-x=30-18 \\ 0=12 \end{gathered}[/tex]

This solution is not valid, so there is no valid solution for x.

What happens to F(x) when x is negative but approaches zero for the functionF(x) = 1/x, whose graph is shown below?

Answers

Given: The graph of the function below

[tex]F(x)=\frac{1}{x}[/tex]

To Determine: What happens to F(x) when x is negative but approaches zero

Solution:

It can be observed from the given graph that when x is negative but approaches zero, F(x) approaches negative infinity

This is as shown below

From the options provided, the best answer is F(x) is a negative number, OPTION C

could you please help me answer this please and thank you it's about the rectangular prism....

Answers

ANSWER:

[tex]A_T=8+8+20+20+40+40[/tex]

STEP-BY-STEP EXPLANATION:

In this case, what we must do is calculate the face area and then add each face, like this:

The area of each area is the product between its length and its width, therefore

[tex]\begin{gathered} A_1=2\cdot4=8 \\ A_2=10\cdot4=40 \\ A_3=10\cdot2=20_{} \\ A_4=10\cdot4=40 \\ A_5=10\cdot2=20_{} \\ A_6=2\cdot4=8 \end{gathered}[/tex]

The total area would be the sum of all the areas, if we organize it would be like this:

[tex]A_T=8+8+20+20+40+40[/tex]

Sally Sue had spent all day preparing for the prom. All the glitz and the glamour of the evening fell apart as she stepped out of the limousine and her heel broke and she fell to the ground. Within minutes, news of her crashing fall had spread to the 550 people already at the prom. The function, p(t) = 550(1-e^-0.039t) where t represents the number of minutes after the fall, models the number of people who were already at the prom who heard the news.How many minutes does it take before all 550 people already at the prom hear the news ofthe great fall? Show your work.

Answers

We have the function

[tex]p(t)=550(1-e^{-0.039t})[/tex]

Therefore we want to determine when we have

[tex]p(t_0)=550[/tex]

It means that the term

[tex]e^{-0.039t}[/tex]

Must go to zero, then let's forget the rest of the function for a sec and focus only on this term

[tex]e^{-0.039t}\rightarrow0[/tex]

But for which value of t? When we have a decreasing exponential, it's interesting to input values that are multiples of the exponential coefficient, if we have 0.039 in the exponential, let's define that

[tex]\alpha=\frac{1}{0.039}[/tex]

The inverse of the number, but why do that? look what happens when we do t = α

[tex]e^{-0.039t}\Rightarrow e^{-0.039\alpha}\Rightarrow e^{-1}=\frac{1}{e}[/tex]

And when t = 2α

[tex]e^{-0.039t}\Rightarrow e^{-0.039\cdot2\alpha}\Rightarrow e^{-2}=\frac{1}{e^2}[/tex]

We can write it in terms of e only.

And we can find for which value of α we have a small value that satisfies

[tex]e^{-0.039t}\approx0[/tex]

Only using powers of e

Let's write some inverse powers of e:

[tex]\begin{gathered} \frac{1}{e}=0.368 \\ \\ \frac{1}{e^2}=0.135 \\ \\ \frac{1}{e^3}=0.05 \\ \\ \frac{1}{e^4}=0.02 \\ \\ \frac{1}{e^5}=0.006 \end{gathered}[/tex]

See that at t = 5α we have a small value already, then if we input p(5α) we can get

[tex]\begin{gathered} p(5\alpha)=550(1-e^{-0.039\cdot5\alpha}) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550(1-0.006) \\ \\ p(5\alpha)=550\cdot0.994 \\ \\ p(5\alpha)\approx547 \end{gathered}[/tex]

That's already very close to 550, if we want a better approximation we can use t = 8α, which will result in 549.81, which is basically 550.

Therefore, we can use t = 5α and say that 3 people are not important for our case, and say that it's basically 550, or use t = 8α and get a very close value.

In both cases, the decimal answers would be

[tex]\begin{gathered} 5\alpha=\frac{5}{0.039}=128.2\text{ minutes (good approx)} \\ \\ 8\alpha=\frac{8}{0.039}=205.13\text{ minutes (even better approx)} \end{gathered}[/tex]

Slove this equation 19=n+22

Answers

Step-by-step explanation:

I think it helps you

please mark me as brainlist

Answer:

greyehahhsh[tex]5.5723[/tex]

You choose a marble from the bag. What is the probability you will NOT choose blue?1/25/72/72

Answers

Given a sample and required to get the probability of a particular outcome, we make a couple of considerations including:

- Sample Space: The universal set

- Required Outcome

We can identify these variables as:

Sample space: total number of marbles = 7

Required outcome: Not blue = 7 - 2 = 5

Probability is given as:

[tex]\begin{gathered} P=\text{ }\frac{\text{number of required outcome}}{Sample\text{ space}}=\frac{5}{7} \\ P=\frac{5}{7} \end{gathered}[/tex]

Which statement about the graph below is true?

Answers

Answer:

a. The relation is a function because every input has an output.

Step-by-step explanation:

a relation in which for every input there is exactly one output (for every x there is just one y)

quizlet

Answer:

A. The relation is a function because every input has an input

Step-by-step explanation:

A relation is a function as long as there are not multiple outputs for one input. It's okay if there are multiple inputs for one output, like we can see here with points (-6, 1) and (2, 1).

Another way to test if a graphed relation is a function is the vertical line test. Draw vertical lines at multiple spots on the graph and if any of the vertical lines touches 2 points, the graphed relation is not a function.

:)

Options for this are: 20 of the best selling cameras, same photographer, 100 pictures with each camera, consistent across all cameras 10 point scale, two were from companies who are major advertisers

Answers

It is given that:

A writer for a magazine recently did a test to determine which mid-range digital camera takes the best pictures. Her method is described below.

Which part of the method describes an area of potential bias?

She gathered 20 of the best.selling cameras and used the same photographer to take 100 pictures with each camera .She ensured that the environment and the subject of each picture were consistent across all cameras and used a 10.point scale to determine picture quality. Of the cameras tested, two were from companies who are major advertisers in the magazine.

Now if the reading is done carefully, it can be concluded that the information given by:

"Of the cameras tested, two were from companies who are major advertisers in the magazine." can be considered for a potential bias since the magazine may be pressured by these two companies to give them a higher rating than they deserve.

So the option:two were from companies who are major advertisers is correct.

Two wheelchair ramps, each 10 feet long, lead to the two ends of the entrance porch of Mr. Bell's restaurant. The two ends of the porch are at the same height from the ground, and the start of each ramp is the same distance from the base of the porch. The angle of the first ramp to the ground is 24°.Which statement must be true about the angle of the second ramp to the ground?A. It could have any angle less than or equal to 24°.B. It must have an angle of exactly 24°.C. It could have any angle greater than or equal to 24°.D. Nothing is known about the angle of the second ramp.

Answers

Given statement

The ramps have

- the same height

- the same angle measure relative to the ground

- the two ends of the porch are at the same height from the ground

- the start of each ramp is the same distance from the base of the porch

A pictorial description of the problem is shown below:

Since the two ramps have similar descriptions, the angle measure of the second ramp to the ground would be exactly 24 degrees

Answer: Option B

option  b your welcome

State the number of complex zeros and the possible number of real and imaginary zeros for each function. Then find all zeros. show all work

Answers

We have a cubic function

[tex]f(x)=x^3-3x^2-47x-87[/tex]

One way to find all the zeros is by factoring, we can easily find the first zero using the divisors test if we have an independent term, at our case it's -87, one of the divisors may be a zero. The divisors of -87 is 1, 3, 29 and 87.

If we check for all of the divisors we will see that -3 is a zero. (Check with both signals).

If -3 is a zero, the D'Alembert theorem tells us that f(x) is divisible by (x+3), if we do that division we'll have a quadratic function where we can just apply the quadratic formula, then

There's a theorem that says that, if f(a) is a zero, i.e f(a) = 0, and f(x) is a polynomial, then f(x) is divisible by (x-a), in other words, we can divide f(x) by (x-a) and the rest of the division will be 0.

Therefore, let's divide our function by (x+3)

Then we can write our function as

[tex]f(x)=(x+3)(x^2-6x-29)[/tex]

Look that now we have a quadratic function, and we can easily find its zeros, applying the quadratic formula

[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

We have a = 1, b = -6 and c = -29. Then

[tex]\begin{gathered} x=\frac{6\pm\sqrt[]{36+4\cdot29}}{2} \\ \\ x=\frac{6\pm\sqrt[]{156}}{2} \\ \\ x=\frac{6\pm2\sqrt[]{38}}{2} \\ \\ x=3\pm\sqrt[]{38} \end{gathered}[/tex]

Now we have all the zeros of f(x), it's

[tex]\begin{gathered} x=-3 \\ \\ x=3+\sqrt[]{38} \\ \\ x=3-\sqrt[]{38} \end{gathered}[/tex]

As we can see there's no complex zero, all the zeros are real numbers.

The max number of complex zeros is 2 because the complex zeros always come in pairs, so if we have 1 complex zero, automatically we have another, for a 3-degree equation, there's a maximum of 2 complex zeros and 1 real zero, or all the of them are real.

Then the correct answer is A)

A box contains six red pens, four blue pens, eight green pens, and some black pens. Leslie picks a pen and returns it to the box each time. The outcomes are recorded in the table.a. what is the experimental probability of drawing a green pen?b. if the theoretical probability of drawing a black pen is 1/10, how many black pens are in the box

Answers

given the follwing parameters,

number of times a Red Pen is picked is 8

numbr o f times the Blue Pen is picked is 5

Number of times the Green Pen is picked is 14

Number of times the Black Pen is picked is 3

so,

(a) to get the experimental probability of drawing a Green Pen is,

P = favoured results/all obtained

then,

14/(8+5+14+3)

= 14/30 that is a

(

Use the binomial expression (p+q)^n to calculate abinomial distribution with n = 5 and p = 0.3.

Answers

ANSWER :

The binomial distributions are :

0.16807

0.36015

0.3087

0.1323

0.02835

0.00243

EXPLANATION :

In a binomial distribution of (p + q)^n :

n = 5

p = 0.3 and

q = 1 - p = 1 - 0.3 = 0.7

[tex]_nC_x(p)^x(q)^{n-x}[/tex]

We are going to get the values from x = 0 to 5

[tex]\begin{gathered} _5C_0(0.3)^5(0.7)^{5-0}=0.16807 \\ _5C_1(0.3)^5(0.7)^{5-1}=0.36015 \\ _5C_2(0.3)^5(0.7)^{5-2}=0.3087 \\ _5C_3(0.3)^5(0.7)^{5-3}=0.1323 \\ _5C_4(0.3)^5(0.7)^{5-4}=0.02835 \\ _5C_5(0.3)^5(0.7)^{5-5}=0.00243 \end{gathered}[/tex]

What is the divisibility rule for 4
A. Last two digits divisible by 4
B. Add all of the digits and divide by 4
C. Last 3 digits divisible by 4
D. Even number​

Answers

Answer :- A) Last two digits divisible by 4.

hey there mr or ms could you please help me out here?

Answers

The two triangles have a common side, RQ.

Also, given the two sides (left and right) are equal.

Also, the angle between the two sides (one side given and bottom side) is given as 90 degrees.

Thus,

we have

2 sides AND 1 angle congruent in each triangle

That is:

Side-Angle-Side, which is

SAS

THe triangles are congruent according to SAS, option B

Find the variance for the set of data: 22, 26, 17, 20, 20.The variance is

Answers

The variance of a given data set with size N is given by the formula:

[tex]\begin{gathered} \sigma=\sqrt{\frac{1}{N}\sum_{i=1}^N(x_i-\mu)^2} \\ Var(X)=\sigma^2 \end{gathered}[/tex]

Then, for the data set {22, 26, 17, 20, 20} and N = 5, we have:

[tex]\begin{gathered} \mu=\frac{22+26+17+20+20}{5}=21 \\ \sigma=\sqrt{\frac{1^2+5^2+(-4)^2+(-1)^2+(-1)^2}{5}}=\sqrt{\frac{44}{5}}=2\sqrt{\frac{11}{5}} \\ \therefore Var(X)=\frac{44}{5}=8.8 \end{gathered}[/tex]

A lab assistant needs to create a 1000 ML mixture that is 5% hydroelectric acid. The assistant has solutions of 3.5% and 6% in supply at the lab. Using the variables x and y to represent the number of milliliters of the 3.5% solution and the number of milliliters of the 6% solution respectively, determine a system of equation that describes the situation the situation.Enter the equations below separated by a comma How many milliliters of the 3.5% solution should be used?How many milliliters of 6% solution should be used?

Answers

Given:

A lab assistant needs to create a 1000 ML mixture that is 5% hydroelectric acid.

The assistant has solutions of 3.5% and 6% in supply at the lab.

let the number of milliliters from the solution of 3.5% = x

And the number of milliliters from the solution of 6% = y

so, we can write the following equations:

The first equation, the sum of the two solutions = 1000 ml

So, x + y = 1000

The second equation, the mixture has a concentration of 5%

so, 3.5x + 6y = 5 * 1000

So, the system of equations will be as follows:

[tex]\begin{gathered} x+y=1000\rightarrow(1) \\ 3.5x+6y=5000\rightarrow(2) \end{gathered}[/tex]

Now, we will find the solution to the system using the substitution method:

From equation (1)

[tex]x=1000-y\rightarrow(3)[/tex]

substitute with (x) from equation (3) into equation (2):

[tex]3.5\cdot(1000-y)+6y=5000[/tex]

Solve the equation to find (y):

[tex]\begin{gathered} 3500-3.5y+6y=5000 \\ -3.5y+6y=5000-3500 \\ 2.5y=1500 \\ y=\frac{1500}{2.5}=600 \end{gathered}[/tex]

substitute with (y) into equation (3) to find x:

[tex]x=1000-600=400[/tex]

So, the answer will be:

Enter the equations below separated by a comma

[tex]x+y=1000,3.5x+6y=5000[/tex]

How many milliliters of the 3.5% solution should be used?

400 milliliters

How many milliliters of 6% solution should be used?

600 milliliters

Needing assistance with question in the photo (more than one answer)

Answers

By definition, the probability of an event has to be between 0 and 1.

Given that definition the options 1.01, -0.9, -5/6 and 6/5 cannot be the probability of an event.

The function table below is intended to represent the relationship y=-2x-5. However, one of the entries for y does not correctly fit the relationship with x.

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x = 1 , f(x) = -2•1 - 5 = -7

Then it doesnt corresponds to f(1) = 6

Answer is OPTION E)

i need help in this please

Answers

The isosceles right is given in the diagram below

We are to rotate clockwise about point B as the origin

Rotating ABC 180° Clockwisely, we have

Rotating ABC 270° clockwise about B, we have

We now combine the four triangles together in the diagram below

Which of the following is not a correct way to name the plane.

Answers

For this case the first option is correct Plane P

The perimeter of the triangle below is 91 units. Find the length of the side QR. write your answer without variables.

Answers

Given:

The perimeter of the triangle, P=91.

The sides of the triangle are,

PR=4z

QR=z+3

PQ=5z-2.

The perimeter of the triangle can be expressed as,

[tex]\begin{gathered} P=PR+QR+PQ \\ P=4z+z+3+5z-2 \\ P=10z+1 \end{gathered}[/tex]

Now, put P=91 in the above equation to find the value of z.

[tex]\begin{gathered} 91=10z+1 \\ 91-1=10z \\ 90=10z \\ \frac{90}{10}=z \\ 9=z \end{gathered}[/tex]

Now, the length of the side QR can be calculated as,

[tex]\begin{gathered} QR=z+3 \\ QR=9+3 \\ QR=12 \end{gathered}[/tex]

Now, the length of QR is 12 units.

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