Step-by-step explanation:
the midpoint coordinates between 2 points A and B are
((xa + xb)/2, (ya + yb)/2)
xa = 3
ya = 0
and so we get
(3 + xb)/2 = 0
3 + xb = 0
xb = -3
(0 + yb)/2 = 5
yb = 10
therefore, S = (-3, 10)
Point (2,11.9),(4,10.5)
(2,8) , (4,7.5)
(2,6) , (4,1.5)
(2,0.5) , (4.-1)
(2,-1) , (4,-1)
(-2.8,-5.0) , (-3.6,-5.9)
rise over run so what's the answer
The slopes formed by each of the pairs of points are given as follows:
(2,11.9),(4,10.5): -0.7.(2,8) , (4,7.5): -0.25.(2,6) , (4,1.5): -2.25.(2,0.5) , (4.-1): -0.75.(2,-1) , (4,-1): 0.(-2.8,-5.0) , (-3.6,-5.9): 0.89.SlopeThe slope is equivalent to the rate of change, hence, given two points, the slope is calculated as the change in y, also called rise, of these two points divided by the change in x, also called run.
For the first case, the points are:
(2, 11.9) and (4, 10.5)
Hence:
The change in x is of 4 - 2 = 2.The change in y is of 10.5 - 11.9 = -1.4.The slope is:
m = -1.4/2 = -0.7.
The other slopes are calculated as follows:
(2,8) , (4,7.5): m = (7.5 - 8)/(4 - 2) = -0.25.(2,6) , (4,1.5): m = (1.5 - 6)/(4 - 2) = -2.25.(2,0.5) , (4.-1): m = (-1 - 0.5)/(4 - 2) = -0.75.(2,-1) , (4,-1): m = (-1 - (-1))/(4 - 2) = 0. (no change in the output).(-2.8,-5.0) , (-3.6,-5.9): m = (-3.6 - (-2.8))/(-5.9 - (-5)) = 0.89.More can be learned about slopes at https://brainly.com/question/28954211
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Cindy struck out 7, 14, 6, 4, 5, and 6 batters in softball games this season. In discussingher stats with a newspaper reporter, Cindy's coach mentions that the average number ofCindy's strikeouts is 7. Is the coach's statement misleading? Explain why or why not.O No; the mean of her strikeouts is 7.O None of the other answers are correctO Yes, she struck out 7 batters only one time.O No; she typically strikes out 7 batters in a game.O Yes; the median of her strikeouts is 7.
Given that the batters were 7, 14,6,4,5 and 6 then to find the average, you add the batters and divide by their number
[tex]\text{sum}=7+14+6+4+5+6=42[/tex][tex]\text{Average}=\frac{42}{6}=7[/tex]Here you notice that the average is 7, so the coach's statement is true.
Your answer is , No;the mean of her strikeouts is 7
Solve for x. Show each step of the solution.
5(2-x)-10=25-2(3x+40)
Answer:
x=-55Step-by-step explanation:
[tex]5(2-x)-10=25-2(3x+40)\\\\10-5x-10=25-6x-80\\\\-5x=-6x-55\\\\-5x+6x=-55\\\\x= -55 [/tex]
Answer:
x = -55
Step-by-step explanation:
Hello!
We can solve for x by isolating the variable.
Solve for x5(2 - x) - 10 = 25 - 2(3x + 40)5(2) - 5(x) - 10 = 25 - 2(3x) - 2(40)10 - 5x - 10 = 25 - 6x - 80-5x = -55 - 6xx = -55The value of x is -55.
Q1 A ball is thrown upwards with some initial speed. It goes up to a height of 19.6m and then returns. Find (a) The initial speed (b) The time taken in reaching the highest point (c) The velocity of the ball one second before and one second after it reaches the maximum height (d) The time taken by the ball to return to its original position
Answer:
(a) 19.6 ms⁻¹
(b) 2 s
(c) 9.8 ms⁻¹
(d) 4 s
Step-by-step explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Acceleration due to gravity = 9.8 ms⁻².
Part (a)When the ball reaches its maximum height, its velocity will momentarily be zero.
Given values (taking up as positive):
[tex]s=19.6 \quad v=0 \quad a=-9.8[/tex]
[tex]\begin{aligned}\textsf{Using} \quad v^2&=u^2+2as\\\\\textsf{Substitute the given values:}\\0^2&=u^2+2(-9.8)(19.6)\\0&=u^2-384.16\\u^2&=384.16\\u&=\sqrt{384.16}\\\implies u&=19.6\; \sf ms^{-1}\end{aligned}[/tex]
Therefore, the initial speed is 19.6 ms⁻¹.
Part (b)Using the same values as for part (a):
[tex]\begin{aligned}\textsf{Using} \quad s&=vt-\dfrac{1}{2}at^2\\\\\textsf{Substitute the given values:}\\19.6&=0(t)-\dfrac{1}{2}(-9.8)t^2\\19.6&=4.9t^2\\t^2&=\dfrac{19.6}{4.9}\\t^2&=4\\t&=\sqrt{4}\\\implies t&=2\; \sf s\end{aligned}[/tex]
Therefore, the time taken to reach the highest point is 2 seconds.
Part (c)As the ball reaches its maximum height at 2 seconds, one second before this time is 1 s.
Given values (taking up as positive):
[tex]u=19.6 \quad a=-9.8 \quad t=1[/tex]
[tex]\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=19.6+(-9.8)(1)\\v&=19.6-9.8\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}[/tex]
The velocity of the ball one second before it reaches its maximum height is the same as the velocity one second after.
Proof
When the ball reaches its maximum height, its velocity is zero.
Therefore, the values for the downwards journey (from when it reaches its maximum height):
[tex]u=0 \quad a=9.8 \quad t=1[/tex]
(acceleration is now positive as we are taking ↓ as positive).
[tex]\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=0+9.8(1)\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}[/tex]
Therefore, the velocity of the ball one second before and one second after it reaches the maximum height is 9.8 ms⁻¹.
Part (d)From part (a) we know that the time taken to reach the highest point is 2 seconds. Therefore, the time taken by the ball to travel from the highest point to its original position will also be 2 seconds.
Therefore, the total time taken by the ball to return to its original position after it is thrown upwards is 4 seconds.
This is an online ACT prep guide problem that I’m having trouble on.Below, is the answer options to this problem.A. -4B. 1C. 6D. The limit does not exist.
Step 1
Given; A graph
Required; To find f(-4)
Step 2
The graph at x=-4 has a removable discontinuity. Therefore we can then conclude that f(-4) is undefined.
Hence, f(-4) is undefined
A removable discontinuity is a point on the graph that is undefined or does not fit into the rest of the graph.
Help on this question
Answer: Yes
Step-by-step explanation: 250-250
An outlier is when some of the data is spread farther away from the rest of the data. It is far off from other data
Based on the given proof that the triangles are congruent
Answer:
They are congruent by SAS:
Side: AB = CB
Angle: ∠ABD = ∠CBD
Side: BD = BD
Explanation:
Two triangles are congruent if they have the same interior angles and the same length of their corresponding sides.
If two of the angles are equal, we can say that all the interior angles are equal.
So, based on the given information we get:
1. AC ⊥ BD means that AC is perpendicular to BD, therefore,
∠ADB = ∠CDB = 90°
2. It is given that ∠A = ∠C
3. Since both of their interior angles are equal, we can say that all the interior angles are equal and:
∠ABD = ∠CBD
4. The triangle ABC is isosceles because two of their interior angles are equal, therefore AB = CB
5. BD = BD because it is the same segment.
6. By SAS (Side-angle-Side) we can say that ΔABD = ΔCBD
Because the side AB is equal to side CB, the angle ABD is equal to angle CBD, and the side BD is equal to itself.
Tara's office recycled a total of 60 kilograms of paper over 3 weeks. How many weeks will it take Tara's office to recycle a total of 80 kilograms of paper? Solve using unit rates.
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what is the rule for this pattern?
17, 20, 19, 22, 21
Answer:
+3, -1
Step-by-step explanation:
17 + 3 = 20
20 - 1 = 19
19 + 3 = 22
22 - 1 = 21
Please mark me brainliest if this helps!
◄) Solve for w.
29 + 17w = 624
W =
Helppp
Answer:
w = 35
Step-by-step explanation:
29 + 17w = 624
subtract 29 from both side
17 w = 595
divide both sides by 17
w = 35
Solve 7+y=5(2y-1)+3y. Y=
Answer: y = 1
Step-by-step explanation:
Given
7 + y = 5(2y - 1) + 3y ← distribute and simplify right side
7 + y = 10y - 5 + 3y
7 + y = 13y - 5 ( subtract y from both sides )
7 = 12y - 5 ( add 5 to both sides )
12 = 12y ( divide both sides by 12 )
1 = y
3. What is true for an image and a preimage in a reflection? (1 point)
The image is larger than the preimage.
The image is smaller than the preimage.
The image and the preimage have the same orientation.
The image and the preimage have different orientations.
Answer: The image and the preimage have the same orientation.
Answer:
The image and the preimage have the different orientation.
Step-by-step explanation:
i
took
the
test
consider the experiment of a worker assembling a product. a. define a random variable that represents the time in minutes required to assemble the product. b. what values may the random variable assume? c. is the random variable discrete or continuous?
(a) Let "X" be the random variable that represents the time in minutes required to assemble the product.
(b) The random variable may assume the values in the interval (0, ∞).
(c) The random variable "X" is continuous in nature.
A random variable is a mathematical representation of a number or object that is affected by random occurrences. It is a mapping or function between probable outcomes in a sample space and a measured space, which is frequently real numbers.A random variable is a variable with an unknown value or a function that gives values to each of the results of an experiment. A random variable might be discrete (with fixed values) or continuous (any value in a continuous range).To learn more about variables, visit :
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3. What is the probability of rolling a 5 on a fair die, if we know that the roll is odd? 4 Lamino dr
Let:
A = Rolling an odd number
B = Rolling a 5
N = Number of possible outcomes
so:
[tex]\begin{gathered} P(A)=\frac{3}{6}=\frac{1}{2} \\ P(B|A)=\frac{P(B\cap A)}{P(A)} \\ \text{Where:} \\ P(B\cap A)=P(A)\cdot P(B) \\ P(B)=\frac{1}{6} \\ so\colon \\ P(B|A)=\frac{\frac{1}{6}\cdot\frac{1}{2}}{\frac{1}{2}}=\frac{1}{6} \end{gathered}[/tex]suppose that the antenna lengths of woodlice are approximately normally distributed with a mean of inches and a standard deviation of inches. what proportion of woodlice have antenna lengths that are more than inches? round your answer to at least four decimal places.
Proportion = 0.2119
P (X is less than or equal to 0.18) = P [(X-μ)/ sigma is less than or equal to (0.18-0.22)/ 0.05] = P(Z is less than or equal to -0.80). Using z-table proportion = 0.2119
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Which of the following options results in a graph that shows exponential decay?
Group of answer choices
f(x) = 0.6(2)x
f(x) = 3(0.7)x
f(x) = 0.4(1.6)x
f(x) = 20(3)x
The equation of a function that results in a graph that shows exponential decay is f(x) = 3(0.7)ˣ
How to determine the function that represents an exponential decay?An exponential function is represented as
f(x) = abˣ
Where
Variable a represents the initial valueVariable b represents the rateA function that represents an exponential decay would have a rate less than 1
This is represented as b <1
From the list of options, we have
f(x) = 3(0.7)ˣ
By comparing f(x) = 3(0.7)ˣ and f(x) = abˣ, we have
b = 0.7
0.7 is less than 1
Hence, the exponential decay function is f(x) = 3(0.7)ˣ
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WILL GIVE BRAINLIEST PLS HELP
Passed exam | Did not pass exam | Row Totals
Completed exam review | 55% | 10% | 65%
Did not complete exam review | 20% | 15% | 35%
Column Totals | 75% | 25% | 100%
Part A: What is the percentage of students who failed the exam, given that they completed the exam review? Round to the nearest percentage. (2 points)
Part B: What is the percentage of students who failed the exam, given that they did not complete the exam review? Round to the nearest percentage. (2 points)
Part C: Is there an association between failing the exam and completing the exam review? Justify your answer. (2 points)
Answer:
A: 15%
B: 43%
C: yes
Step-by-step explanation:
You want the percentages of students who failed the exam, given that they (A) did, or (B) did not complete the exam review. You also want to know if this indicates an association between failing and reviewing.
NotationLet F represent the event "failed the exam." Let R represent the event "completed the exam review." R' will be the event "did not complete the review."
A: P(F|R)The probability is ...
P(F|R) = P(F&R) / P(R)
P(F|R) = 0.10/0.65 = 2/13 ≈ 15%
About 15% failed who completed the review.
B: P(F|R')P(F|R') = P(F&R') / P(R')
P(F|R') = 0.15/0.35 = 3/7 ≈ 43%
About 43% failed who did not complete the review.
C: AssociationIf the events "Failed the exam" and "Completed the review" were independent, then the probability of one would not be conditional upon the other. Here, the probability of failing is clearly different for those who completed the review, so there is an association between failing the exam and completing the exam review.
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on the number line drop box plot for data how many siblings does seventh grade have the number summaries below min:0,q1:1,medium:2,q3:3,max:10
Here, we want to drop a box plot on the number line given the listed numbers
We have the box plot as follows
The listing of the numbers is the actual way the numbers on the box plot will be listed from left to right
We have this as follows;
there are grass in a farm and the same amount of grass is grown each day. it takes 10 days for 17 cows to eat all grass in the farm. it takes 12 days for 15 cows to eat all grass in the farm. how many days does it take for 7 cows to eat all grass in the farm?
7 cows will eat all the grass on the farm in 28 days
17 cows eat all the grass on the farm in 10 days
15 cows eat all the grass in the farm in 12 days
We can see a relationship between the number of cows and the number of days. A reduction of 2 cows leads to an increase in 2 days for the cows to eat the grass.
As a result, when we reduce the cows by 4 the increase in the number of days will be 8.
Hence, to reduce the cows from 15 to 7 we will reduce the number of cows by 8 resulting in an increase in 16 days for the grass on the farm to be eaten up
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Andrew earns 30% on all sales plus a retainer of £125 per week.
If he earns £893 in one week, find the value of his sales for that week.
If Andrew earns 30% on all sales plus a retainer of $125 per week and If he earns $893 in one week, then the value of the his sales for that week is $2560.
The total amount he earned = $893
The amount of retainer he earned = $125
The percentage he earned = 30%
30% of the sales = The total amount he earned - The amount of retainer he earned
Substitute the values in the equation
= 893-125
= $768
Consider the total sales as x
Then,
x × (30/100) = 768
0.3x = 768
x = 768/0.3
x = $2560
Hence, if Andrew earns 30% on all sales plus a retainer of $125 per week and If he earns $893 in one week, then the value of the his sales for that week is $2560.
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AB, CD, and EF intersect at point O. Find m AOC, m BOF, m COF, and m COE.
Answer:
Step-by-step explanation:
an environmentalist wishes to conduct a hypothesis test on the percentage of cars driven in the city that are hybrids. is it sufficient for him to use a simple random sample of 172172 cars if hybrids currently account for 6%6% of the car sales in the country and he claims that the percentage of hybrids in the city is higher than that?
It is enough for him to use a simple random sample of 172 cars.
It is required that there are at least 10 successes and 10 failures to test a hypothesis that involves a proportion p in a sample of size n.
Following conditions are required for it:
1) np ≥ 10
2) n (1-p) ≥ 10
p = 6% = 0.06
n = 172
np = 172x0.06 = 10.322 ≥ 10172 (1-0.06) = 161.68 ≥ 10So, there are at least 10 successes and 10 failures in the 172 cars sample, it is enough for him to use a simple random sample of 172 cars.
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Students A and B have probabilities of failing an exam of 1/2 and 1/5 respectively. The probability of them both failing the examination is 1/10. Determine the probability that at least one of the two students fail.
Answer:
7/5
Step-by-step explanation:
1/2 + 1/5
probability that at least one of the two students fail is 7/5
The senior class sells hamburgers and hot dogs at a football game and makes a profit of $1.75 on each hamburger and $1.25 on each hot dog. The class would like a profit of at least $280. Let x represent the number of hamburgers and y represent the number of hot dogs sold
Answer:
1.75x + 1.25y >= 280
Step-by-step explanation:
1.75x + 1.25y >= 280
3. The following are the sizes in square feet of the seventeen new faculty office in the mathematics department at a college.102123142155104185159124154136113110107119120127155Find the mean square footage. Round your answer to the nearest tenth, if necessary. square feetFind the median square footage. square feet
Given a sample of the size, measured in square feet, of 17 faculty offices.
1) Mean
To calculate the mean of the sample you have to add all observations of the data set and divide it by the sample size:
[tex]\bar{x}=\frac{\Sigma x_i}{n}[/tex][tex]\begin{gathered} \bar{x}=\frac{102+123+142+155+104+185+159+124+154+136+113+110+107+119+120+127+155}{17} \\ \bar{x}=\frac{2235}{17} \\ \bar{x}=131.47\approx131.5ft^2 \end{gathered}[/tex]The mean square footage is 131.5 ft²
2) Median
To determine the median of the data set, first, you have to calculate the position of the median, following the formula:
[tex]\text{PosMe}=\frac{(n+1)}{2}[/tex]The sample size is n=17, then the position of the median is
[tex]\begin{gathered} \text{PosMe}=\frac{17+1}{2} \\ \text{PosMe}=\frac{18}{2} \\ \text{PosMe}=9 \end{gathered}[/tex]The median corresponds to the ninth observation of the data set.
Next, you have to order the data set from least to greatest:
102, 104, 107, 110, 113, 119, 120, 123, 124, 127, 136, 142, 154, 155, 155, 159, 185
Count the ninth observation from the left.
The median of the data set is Me= 124 ft²
monty takes a cab to work and pays a fare of $12.75, he tips the diver 20% and the tax rate is 8%. how much does he spend on the trip
The cost of the fare based on the information is $16.32.
How to calculate the value?Amount for the fare = $12.75
Tip for the driver = 20% = 20% × $12.75 = $2.55
Tax rate = 8% = 8% × $12.75 = $1.02
Therefore the total amount will be:
= Cost of fare + Tip + Tax
= $12.75 + $2.55 + $1.02
= $16.32
The cost is $16.32. This illustrate the concept of addition.
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what is the answer to 20x + 35y
The greatest common factor is 5 .
If you factor it out, the expression becomes 5 (4x + 7y) .
Answer: 55x^1 y^1
Step-by-step explanation:
Add 20+35= 55
x & y can't stand by it's self, so x^1 and y^1
So you take those answers and you got 55x^1 y^1
You must keep it in letters in alphabetic order or it's considered wrong.
two angles are a linear pair, and one has twice the measure of the other. Find the smaller angles measure
Answer:
60°Step-by-step explanation:
two angles are a linear pair, and one has twice the measure of the other. Find the smaller angles measure
linear pair = 180°
180 : 3 = 60° (smaller angle)
60° x 2 = 120° (bigger angle)
120 is twice 60 and the sum is 180°
the answer is good
A rectangles width (W) is 5 inches more than a third the length (L). If the perimeter is 42 inches what are the dimensions of the rectangle ?
The length and width of the rectangle are 5.5 inches and 10.5 inches.
What do we mean by rectangles?A rectangle is a quadrilateral with four right angles in Euclidean plane geometry.It can also be explained in terms of a parallelogram with a right angle or an equiangular quadrilateral—a quadrilateral whose angles are all equal.A square is an asymmetrical shape with four sides of equal length.So, the dimensions of the rectangle:
Let the length of the rectangle be 'x' and the width be 'x + 5'.The perimeter is 42 inches.Perimeter formula: 2(l + b)Substitute the values in the formula as follows:
P = 2(l + b)42 = 2(x + x + 5)42 = 2(2x + 5)42 = 4x + 204x = 42 - 204x = 22x = 22/4x = 5.5 inches (Length)x + 5 = 5.5 + 5 = 10.5 inches (Width )Therefore, the length and width of the rectangle are 5.5 inches and 10.5 inches.
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Find the distance between the two points rounding to the nearest tenth (if necessary).
(6,7) and (4,−1)
Answer:
8.2 units (nearest tenth)
Step-by-step explanation:
Distance between two points
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where (x₁, y₁) and (x₂, y₂) are the two points.
Given points:
(x₁, y₁) = (6, 7)(x₂, y₂) = (4, -1)Substitute the given points into the distance formula and solve for d:
[tex]\implies d=\sqrt{(4-6)^2+(-1-7)^2}[/tex]
[tex]\implies d=\sqrt{(-2)^2+(-8)^2}[/tex]
[tex]\implies d=\sqrt{4+64}[/tex]
[tex]\implies d=\sqrt{68}[/tex]
[tex]\implies d=8.2 \; \sf (nearest\;tenth)[/tex]
Therefore, the distance between the two given points is 8.2 units to the nearest tenth.