Use the times and corresponding closing prices of the stock to create coordinate pairs. Let X represent the number of weeks since the first at a point, and Y represent the closing price of each time. So, X equals zero represents the data point from five years ago. There are 52 weeks in a year, and you can write the time for each closing price recorded in terms of weeks that have passed since five years ago, when X equals zero. Fill in the table to represent your data as coordinate pairs
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Combining both tables we get:
Related Questions
A business could not collect $5,000 that it was owed. The total owed to the business was $100,000. What fraction of the total was not collected? (Express As Fraction)
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Total owed to the business = $100,000
amount that could not be collected = $5000
Fraction of total not collected
[tex]\text{fraction not collected=}\frac{5000}{100000}=\frac{5}{100}=\frac{1}{20}[/tex]7. Find the slope of a line which passes through the origin and point (2,4).A 0.5B -0.5C 2D 4
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Answer:
C
Step-by-step explanation:
the slope of a line is the ratio (y coordinate change / x coordinate change) when going from one point on the line to another.
in our case here we are going e.g. from the origin (0, 0) to (2, 4).
so, x changes by +2 (from 0 to 2).
y changes by +4 (from 0 to 4).
therefore, the slope is
+4/+2 = 2
FYI - the direction is not important. it works the same way in the other direction. but what is important : once you pick a direction for one coordinate, you have to use the same direction for the second one. you cannot go e.g. for x in one direction and for y in the other.
In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC? BC ≅ AD CB ≅ AB AB ≅ CD DB ≅ DC
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By CPCTC this is the only valid answer:
CB ≅ AB
Another statement should be AD≅ CD
The first three terms of an arithmetic sequence are as follows.3, -1, -5
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We will take a look at how we go about with arithmatic progressions.
Arithmmetic sequences are caetgorized by the following two parameters:
[tex]\begin{gathered} a\text{ = First term} \\ d\text{ = common difference} \end{gathered}[/tex]Where,
[tex]\begin{gathered} \text{The value of the first term is called ( a )} \\ \text{The common difference between each and every successive value in a sequence is called ( d )} \end{gathered}[/tex]We are given the following arithmetic sequence:
[tex]3\text{ , -1 , -5 , }\ldots[/tex]Now we will try to determine the values of the two parameters ( a and d ) from the given sequence as follows:
[tex]\begin{gathered} a\text{ = 3 }(\text{ first term value )} \\ d\text{ = (-1 ) - ( 3 ) = (-5 ) - ( -1 ) = -4 ( common difference )} \end{gathered}[/tex]Now to determine the value of any term number ( n ) in an arithmetic sequence we use the following formula:
[tex]a_n\text{ = a + ( n - 1 )}\cdot d[/tex]Where,
[tex]n\text{ is the term number}[/tex]So if we plug in the values of arithmetic sequence parameters into the general equation above we get:
[tex]\textcolor{#FF7968}{a_n}\text{\textcolor{#FF7968}{ = 3 + ( n - 1 ) }}\textcolor{#FF7968}{\cdot}\text{\textcolor{#FF7968}{ ( -4 )}}[/tex]Now we are to determine the values of term numbers ( n = 4 ) and ( n = 5 ). We will evaluate the ( an ) for each term number as follows:
[tex]\begin{gathered} \text{\textcolor{#FF7968}{For n = 4}} \\ a_4\text{ = 3 + ( 4 - 1 )}\cdot(-4\text{ )} \\ a_4\text{ = 3 - 12} \\ \textcolor{#FF7968}{a_4}\text{\textcolor{#FF7968}{ = -9}} \\ \\ \text{\textcolor{#FF7968}{For n = 5}} \\ a_5\text{ = 3 + ( 5 - 1 )}\cdot(-4\text{ )} \\ a_5\text{ = 3 - 1}6 \\ \textcolor{#FF7968}{a_5}\text{\textcolor{#FF7968}{ = -}}\textcolor{#FF7968}{13} \end{gathered}[/tex]Hence, the next two consecutive numbers in the arithmetic sequence would be:
[tex]3\text{ , -1 , -5 ,}\text{\textcolor{#FF7968}{ -9}}\text{ , }\text{\textcolor{#FF7968}{-13}}[/tex]If AACB = ADCE, ZCAB = 63°,ZECD = 52°, and ZDEC = 5xDE(c сx = [?]
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Since angles ACB and ECD are vertical angles, they are congruent, so we have
Calculating the sum of internal angles in triangle ABC, we have:
[tex]\begin{gathered} ABC+ACB+CAB=180 \\ ABC+52+63=180 \\ ABC=180-52-63 \\ ABC=65 \end{gathered}[/tex]Since triangles ACB and DCE are congruent, we have [tex]\begin{gathered} DEC=ABC \\ 5x=65 \\ x=13 \end{gathered}[/tex]
I need help with this answer can you explain it
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The solution.
The correct answer is y-intercept at (0,1) and decreasing over the interval
[tex]\lbrack-\infty,\infty\rbrack[/tex]Hence, the correct answer is the last option (option D)
The population of a country dropped from 52.5 million in 1995 to 44.2 million in 2007. Assume that P(t), the population, in millions, t years after 1995, is decreasing according to the exponential decay model.a) Find the value of k, and write the equation.b) Estimate the population of the country in 2018.c) After how many years will the population of the country be million, according to this model?
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we have the exponential decay function
[tex]P(t)=52.5(e)^{-0.0143t}[/tex]Part b
Estimate the population of the country in 2018
Remember that
t=0 -----> year 1995
so
t=2018-1995=23 years
substitute in the function above
[tex]\begin{gathered} P(t)=52.5(e)^{-0.0143\cdot23} \\ P(t)=37.8\text{ million} \end{gathered}[/tex]Part c
After how many years will the population of the country be 2 million, according to this model?
For P(t)=2
substitute
[tex]2=52.5(e)^{-0.0143t}[/tex]Solve for t
[tex]\frac{2}{52.5}=(e)^{-0.0143t}[/tex]Apply ln on both sides
[tex]\begin{gathered} \ln (\frac{2}{52.5})=\ln (e)^{-0.0143t} \\ \\ \ln (\frac{2}{52.5})=(-0.0143t)\ln (e)^{} \end{gathered}[/tex][tex]\ln (\frac{2}{52.5})=(-0.0143t)[/tex]t=229 years
EspañolAt a football game, a vender sold a combined total of 249 sodas and hot dogs. The number of sodas sold was 55 more than the number of hot dogs sold. Findthe number of sodas sold and the number of hot dogs sold.Number of sodas sold:Number of hot dogs sold:1Х5?
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Given:
Vender sold a combined total of 249 sodas and hot dogs.
The number of sodas sold was 55 more than the number of hot dogs sold.
Let x and y be the number of sodas and hot dogs sold.
[tex]x+y=249\ldots\text{ (1)}[/tex][tex]x=y+55\ldots\text{ (2)}[/tex]Substitute equation (2) in (1)
[tex]y+55+y=249[/tex][tex]2y=249-55[/tex][tex]2y=194[/tex][tex]y=97[/tex][tex]x=97+55[/tex][tex]x=152[/tex]Number of sodas sold is 152.
Number of hot dogs sold is 97.
put the numbers in order from least to greatest2.3,12/5,5/2,2.2,21/10
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Express the fraction in terms of decimal.
[tex]\frac{12}{5}=2.4[/tex][tex]\frac{5}{2}=2.5[/tex][tex]\frac{21}{10}=2.1[/tex]The numbers are,
2.3, 2.4, 2.5, 2.2, 2.1.
Now we arrange the number from least to greatest.
[tex]2.1,2.2,2.3,2.4,2.5[/tex]So answer is,
[tex]\frac{21}{10},2.2,2.3,\frac{12}{5},\frac{5}{2}[/tex]I have no clue what I'm supposed to do I need helpFind the equation of line.
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The general equation of line with slope m and point (x_1,y_1) is,
[tex]y-y_1=m(x-x_1)[/tex]Determine the equation of line.
[tex]\begin{gathered} y-1=3(x+2) \\ y-1=3x+6 \\ y=3x+6+1 \\ =3x+7 \end{gathered}[/tex]So equation of line is y = 3x +7.
There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing. If you have a ticket, what is the expected payoff
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Given that: There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing.
The expected payoff will be:
[tex]\begin{gathered} EV=\frac{1}{250}(320)+\frac{1}{250}(240)+\frac{1}{250}(180)+\frac{1}{250}(100)+\frac{246}{250}(0) \\ EV=\frac{320+240+180+100}{250} \\ EV=\frac{840}{250} \\ EV=3.36 \end{gathered}[/tex]So the expected payoff will be $3.36.
* #3: Write the mixed number shown below as a decimal. 6 3/4
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Answer:
6.75
Hope it helps!
Let me know if its wrong
Х о 12 3 4 у -6 1 8 15 22what is the slope intercept form
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When 80% of a number is added to the number, the result is 162.
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Given:
80% of a number is added to the number, the result is 162.
Required:
To find the number.
Explanation:
80% of a number is added to the number
[tex]\begin{gathered} \frac{80}{100}x+x \\ \\ =0.8x+x \end{gathered}[/tex]The result is 162, so
[tex]\begin{gathered} 0.8x+x=162 \\ \\ 1.8x=162 \\ \\ x=\frac{162}{1.8} \\ \\ x=90 \end{gathered}[/tex]Final Answer:
The number is 90.
consider the following linear equation 5x-5y=15 determine the slope and Y-intercept (entered as an ordered x and y pair) of the equation
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The first step to solve this problem is to rewrite the equation in slope intercept form, to do it, solve the given equation for y:
[tex]\begin{gathered} 5x-5y=15 \\ -5y=-5x+15 \\ y=x-3 \end{gathered}[/tex]According to this, the slope of the line is 1.
The y intercept is (0,-3).
The line graphed should look like this:
Drag the tiles to the correct boxes. Not all tiles will be used.
Match each equation with a value of x that satisfies it.
18
1
9
2
5
(x - 2) = 2
√²+7=4
V1-x
= -1
-3
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For a given exponential expression, the determined value is x=3,0,6.
What are exponential expressions?A component of an exponential expression is an exponent. Powers can be expressed succinctly using exponential expressions. The exponent represents the number of times the base has been multiplied.Powers can be expressed succinctly using exponential expressions. The exponent represents the number of times the base has been multiplied. Exponential expressions or the representation of multiplication with exponents can be streamlined to produce the most efficient notation possible.Each exponential expression's x value is evaluated.
Therefore,
1. [tex]$ \sqrt{x^2+7}=4 \\[/tex]
[tex]&\left(x^2+7\right)=4^2 \\[/tex]
[tex]&\left(x^2+7\right)=16 \\[/tex]
simplifying the above equation, then we get
x² = 16 - 7 = 9
x = 3
2. [tex]$\sqrt[2]{1-x}=-1$[/tex]
(1 -x) = (-1)²
1 - x = 1
x = 0
3. [tex](x-2)^{\frac{1}{2}}=2 \\[/tex]
(x - 2) = 2²
x - 2 = 4
x = 6
The determined value is x=3,0,6 for a given exponential expression.
To learn more about exponential expression, refer to:
https://brainly.com/question/8844911
#SPJ1
△VWY is equilateral, VZ≅WX, and ∠XWY≅∠YVZ. Complete the proof that △VYZ≅△WYX.VWXYZ
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The statement
[tex]VY\cong WX[/tex]is true because
[tex]\Delta VWY[/tex]is an equilateral triangle.
Now, the last statement is true because the triangles have 2 sides and one angle congruent, therefore, by the SAS criterion, the triangles are congruent.
Answer:4.- Triangle VWY is an equilateral triangle.
5.- SAS criterion.
Please help thank you sm it would be very helpful and very much appreciated ♥️‼️
2. Write the formula for the circumference of a circle.
a. Calculate the circumference of circle B if the diameter is 8 inches.
b. Calculate the radius of circle B if the circumference is 94.2 square centimeters.
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Step-by-step explanation:
2. C = [tex] 2 \pi r [/tex]
a. to find radius from diameter in order to calculate the value of the circumference we have to divide the diameter by 2
d/2 = 8/2 = 4
Next, Find the circumference
C = [tex] 2 \pi r [/tex]
C = [tex] 2 \cdot 3.142 \cdot 4 [/tex]
C = 25.13
b. Rearrange formula for circumference to find the value of the radius
Where, C = [tex] 2 \pi r [/tex]
Make r the subject of formula
C/[tex] 2 \pi [/tex] = [tex] 2 \pi r [/tex] /[tex] 2 \pi [/tex]
94.2/2 × 3.142 = r
94.2/6.3 = r
r = 14.95 ≈ 15
2.circumference= pi×diameter
a)25.136 inches
b)14.99 cm
Step-by-step explanation:
a) pi × 8
3.142× 8= 25.136
b) diameter = radius × 2
circumference = pi × diameter OR pi × radius×2
because we are trying to find the radius we will use the pi × 2 radius.
94.2= 3.142 × 2 radius
94.2 ÷ 3.142= 2 radius
29.981 = 2 radius
29.981 ÷ 2 = radius
14.99 = radius
Given that angle A lies in Quadrant III and sin(A)= −17/19, evaluate cos(A).
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As we know;
[tex]sin^2(x)+cos^2(x)=1[/tex]We will use this equality. We take the square of the sine of the given angle and subtract it from [tex]1[/tex].
[tex]sin^2(A)=(-\frac{17}{19} )^2=\frac{289}{361}[/tex][tex]sin^2(A)+cos^2(A)=1[/tex][tex]sin^2(A)=1-cos^2(A)[/tex][tex]\frac{289}{361}=1-cos^2(A)[/tex][tex]cos^2(A)=1-\frac{289}{361} =\frac{72}{361}[/tex][tex]\sqrt{cos^2(A)} =cos(A)[/tex][tex]\sqrt{\frac{72}{361} }=\frac{6\sqrt{2} }{19}[/tex]In the third region the sign of cosines is negative. Therefore, our correct answer should be as follows;
[tex]cos(A)=-\frac{6\sqrt{2} }{19}[/tex]giving the figure below, what is the measure of angle JKL
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The measure of < JKL = 25+25 = 50 degrees.
Angle JOK = 360 -230 = 130 degrees , (where O is the center of the circle)
< OLK = < OJK = 90 degrees ( tangent to a circle)
< LOK = < JOK = 180 - (90+65) = 180 - 155 = 25 degrees
The solution is: < JKL = 25 +25 = 50 degrees
if 2 angles from a line
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If two angles form a linear pair, then they form a straight line, and the sum of their measures is 180 degrees.
This illustrated below;
In the illustration above, angle measure 1 and 2 both equal to 180 degrees. Angle 1 and angle 2 are refered to as a linear pair.
A bridge AB is to be built across a river. The point C is located 62m from B, and angle A is 80 degrees, angle C is 60 degrees. How long is the bridge
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The points A, B, and C form a triangle.
From the given information in the question, the triangle ABC can be drawn to have the following parameters:
Recall the Sine Rule. Applied to the triangle above, the rule is stated as follows:
[tex]\frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C}[/tex]The length of the bridge is AB. Given that the measures of angles A and C, and side BC are known, the following ratio is used to solve:
[tex]\frac{BC}{\sin A}=\frac{AB}{\sin C}[/tex]Substituting known values, the length of AB is calculated as follows:
[tex]\begin{gathered} \frac{62}{\sin80}=\frac{AB}{\sin60} \\ AB=\frac{62\times\sin60}{\sin80} \\ AB=54.52 \end{gathered}[/tex]The bridge is 54.52 m long.
If the diameter of a quarter is 24.26 mm and the width of each quarter is 1.75 mm, to the nearest tenth, what is the approximate surface areaof the roll of quarters? Hint there are 40 quarters in a roll of quarters.A)14,366,2 mm
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For this problem, we are given the dimensions of a quarter and we need to determine the surface area of a roll of quarters.
We can approximate the roll as a cylinder, where the height is the sum of the heights of all the quarters and the dimater is equal to the diameter of one quarter. Therefore we have:
[tex]\begin{gathered} A_{base}=\pi r^2=\pi(\frac{24.26}{2})^2=462.24\text{ mm^^b2}\\ \\ h=40\cdot1.75=70\text{ mm}\\ \\ L_{base}=2\pi(\frac{24.26}{2})=76.22\text{ mm}\\ \\ A_{lateral}=70\cdot76.22=5335.4\text{ mm^^b2}\\ \\ A_{surface}=2\cdot462.24+5335.4=6259.88\text{ mm^^b2} \end{gathered}[/tex]The surface area is equal to 6259.88 mm, the correct option is C.
write an equation if a circle has a center of (3,-1) and the diameter 8
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Answer:
[tex](x-3)^2+(y+1)^2=16[/tex]Explanation:
The equation of a circle with center (h, k) and radius of r is generally given as;
[tex](x-h)^2+(y-k)^2=r^2[/tex]Given the center of the circle as (3, -1) and the diameter of 8 (r = d/2 = 8/2 = 4), the equation of the circle can then be written as shown below;
[tex]\begin{gathered} (x-3)^2+\lbrack y-(-1)\rbrack^2=4^2 \\ (x-3)^2+(y+1)^2=16 \end{gathered}[/tex]The ratio of girls to
boys in a math club
was 1:7. There were
6 girls. How many
boys
Were there in the
club?
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Answer: 42
Step-by-step explanation: If the ratio is 1 girl for 7 boys and there are 6 girls you do 6x7=42
Stacia has 28 red and blue marbles. The ratio of red to blue marbles is 1: 6.
How many blue marbles does Stacia have?
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Answer:You have 24
Step-by-step explanation:
solve and reduce 10÷2/9
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We have the following:
[tex]10\div\frac{2}{9}[/tex]solving:
[tex]\frac{10}{\frac{2}{9}}=\frac{\frac{10}{1}}{\frac{2}{9}}=\frac{10\cdot9}{2\cdot1}=\frac{90}{2}=45[/tex]The answer is 45
The mean mass of 8 men is 82.4 kg. What is the total mass of the 8 men?
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Given:
The mean mass of 8 men is 82.4 kg.
Required:
To find the total mass of 8 men.
Explanation:
Let the total mass be x.
Now,
[tex]\begin{gathered} \frac{x}{8}=82.4 \\ \\ x=82.4\times8 \\ \\ x=659.2 \end{gathered}[/tex]Final Answer:
The total mass of 8 men is 659.2.
I need to order the numbers least to greatest for the numbers: sq root of 144 234/3 and 68.12
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So, the order would be 8.25, 8.832 and 12
20 ping pong balls are numbered 1-20, with no repitition of any numbers. What is the probability of selecting one ball that is either odd or less than 5?
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given 20 ping pong balls
numbered 1-20
odd numbers = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19
total odd numbers = 10
numbers less than 5 = 1, 2, 3, 4
total numbers less than 5 = 4
since 1 and 3 are in both sides,
total number of porbabilities
= 10 + 4 - 2
= 12
the probability of selecting one ball
= 12/20
= 3/5
= 0.6
therefore the probabilty of selecting one ball that is either odd or less than 5 = 0.6