Market share is simply the percentage of the total revenue or sales in a market which a particular business makes.
What is a market share?
Your information is incomplete. Therefore, an overview of the market share will be given. Market share is a measure of consumers' or businesses' preference for a product over other similar products.
A higher market share means greater sales and less effort is needed to sell more and a strong barrier to entry for other competitors.
For example, if there are 50,000 units sold per year in an industry, a company that has sales of 5,000 of those units would then have a 10 percent share in that market.
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Dylan owns a bag that contains 7 blue marbles, 5 purple marbles, 12 red marbles, and 6 orange marbles. If he randomly pulls a marble from the bag, What is the probability of him pulling a red marble? What is the probability of him pulling a blue or purple marble?
Answer:
The probability of him pulling a red marble is 12 to 30. The probability of him pulling a blue or purple marble is also 12 to 30.
Step-by-step explanation:
7+5+12+6=30 (all colors)
12 to 30 red ones
7+5+12+6=30 (all colors) and
7+5=12 (blue + purple)
12 to 30 blue or purple
What are quadratic equations? What are some examples?
Answer:Examples of quadratic equations are: 6x² + 11x – 35 = 0, 2x² – 4x – 2 = 0, 2x² – 64 = 0, x² – 16 = 0, x² – 7x = 0, 2x² + 8x = 0 etc. From these examples, you can note that, some quadratic equations lack the term “c” and “bx.”
Step-by-step explanation:
A quadratic equation in the variable x is an equation of the form ax^2 + b x + c = 0, where a, b, c are real numbers, a ≠ 0.
What are quadratic equations?Quadratics can be defined as a polynomial equation of a second degree, which implies that it comprises a minimum of one term that is squared. It is also called quadratic equations.
The standard form of a quadratic equation is;
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax^2 + bx + c where a, b, c, ∈ R and a ≠ 0.
These are the following examples of the quadratic equation;
x^2-2x
x^2+5x+6
x^2-5x
Any equation of the form p (x) = 0, where p (x) is a polynomial of degree 2, is a quadratic equation.
If we write the terms of p (x) in decreasing order of their degrees, then we get the standard form of the equation.
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help me please!! will choose brainlyest if you get it right
PLEASE HELP WILL GIVE BRAINLIEST
Answer:
(2, -1)
Step-by-step explanation:
x = 2, y = −1
Can sombody solve this please. :)
144 x m - 309.6 = 50.4
Add 309.6 to both sides:
144 - 309.6 + 309.6 = 50.4 + 309.6
Simplify the arithmetic:
144 x m = 50.4 + 309.6
Simplify the arithmetic:
144 x m =360
m = 5/2
the diameter of a circle is 13.8cm. Find the length of its radius
Hello!
R = D/2
R= 13,8/2 => 6,9cm
The length of the circle's radius is 6.9 cm.
The diameter of a circle is twice the length of its radius. So, to find the length of its radius (r), you can divide the diameter (d) by 2.
Given: Diameter (d) = 13.8 cm
Length of radius (r) = d / 2
r = 13.8 cm / 2
r = 6.9 cm
The length of the circle's radius is 6.9 cm.
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Solve the equation . 5x+17=42
Answer:
x = 5
Step-by-step explanation:
5x+17=42
5x + 17 - 17 = 42 - 17
How do you write a decimal for 30 divided by 8
Answer:
3.75?
Step-by-step explanation:
I dont know if this is what youre looking for but I guess?
The length of one leg of an isosceles right triangle is 3 ft. What is the perimeter of the triangle? 3 3 StartRoot 2 EndRoot ft 3 3 StartRoot 3 EndRoot ft 6 3 StartRoot 2 EndRoot ft 6 3 StartRoot 3 EndRoot ft.
The perimeter of the isosceles right triangle comes to be 6+3√2.
Given that the length of one leg of an isosceles right triangle = 3 ft
What is an isosceles right triangle?A right-angle triangle having sides other than hypotenuse equal to each other is called an isosceles right triangle.
So, The length of the other leg of an isosceles right triangle = 3 ft
From Pythagoras theorem
Hypotenuse²=Perpendicular²+Base²
So, in the given isosceles right triangle
Hypotenuse²=Leg 1²+Leg2²
Leg 1=Leg2 = 3 feet
Hypotenuse² = 3²+3²
Hypotenuse = 3√2 ft.
So, the perimeter of the triangle = 3+3+ 3√2
The perimeter of the triangle =6+3√2
Therefore, The perimeter of the isosceles right triangle comes to be 6+3√2.
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Answer:
6 + 3 StartRoot 2 EndRoot ft
Step-by-step explanation:
Edge2022
Please help, I'm stuck
Suppose ten distinct, positive integers have a median of $10$. ("Distinct integers" means that no two integers are the same.)
What is the smallest the average of those ten integers could be?
Explain your answer in complete sentences.
Answer:
8 (or 8.4)
Step-by-step explanation:
First, the problem states the words: Distinct and positive.
That means that the smallest number we can use is 0.
We can make 10 blanks for 10 numbers for us to fill in.
_ _ _ _ _ _ _ _ _ _
Since 10 is an even number, and the median is not one single number, it will be the middle of the two numbers.
In this case, our two numbers are the 5th and 6th blank.
Any two numbers can be used, as long as they are the same actual value from 10.
Let us first put in the numbers we can, which are the numbers before the two middle blanks.
0,1,2,3, _ _ _ _ _ _
To find the median between two numbers, we can do:
(a+b) divided by 2 = median
We can use the smallest following number, 4. Then the 6th number will have to be 16 for 10 to be in the middle.
Also try the largest possible number for the 5th blank, 9. Then the 6th number will be 11.
4+16 and 9+11 both equal 20, and 20 divided by 2 is 10. So both of these work.
Now let's place the other numbers in for these two equations.
0,1,2,3,4,16,17,18,19,20
0,1,2,3,9,11,12,13,14,15
If we add the numbers of each together, we get:
0,1,2,3,4,16,17,18,19,20=100
0,1,2,3,9,11,12,13,14,15= 80
If we now divide each sum by 10 (to find the average) we get:
10
8
Since both of these were the most we could go, one with the 5th number as small as possible and one with the 5th number as large as possible.
Since the smaller answer we got was 8, the answer must be 8.
(I believe 0 is a positive integer because it doesn't carry a negative sign. If 0 is not a positive integer, the answer is 8.4. Use the same process
Unit 10: circles homework 2: central angles & arc measures
The central angle (127 degrees) is the angle at point K
The measures of JL and JML are 127 and 233 degrees, respectively
How to determine the measures of angles JL and JML?From the complete question, we have:
JL = 127 degrees.
The sum of angles at a point is 360 degrees
So, we have:
JML + 127 = 360
Subtract 127 from both sides
JML = 233
Hence, the measures of JL and JML are 127 and 233 degrees, respectively
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Lines j and k are intersected by line m. At the intersection of lines j and m, the uppercase left angle is 93 degrees. At the intersection of lines k and m, the bottom right angle is 93 degrees.
Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?
alternate interior angles theorem
alternate exterior angles theorem
converse alternate interior angles theorem
converse alternate exterior angles theorem
Answer: converse alternate exterior angles theorem
Step-by-step explanation:
The angles are alternate exterior angles.
You can buy jars of the same jam in two sizes.
Step-by-step explanation:
Large Jar 540g for 2.16
540/2.16 = 250
(Always divide by the smallest ratio)
= 250g per 1£
Small Jar 360g for 1.37
360/1.37=262.77g
= 262.77g per 1£
Small Jar is the best value for money, more grams, same price.
Helppppppppppppppppppp
Answer:
8/27
Step-by-step explanation:
It says to use V=s^3.
s is the the side length of the cube which is 2/3 in this case.
So to get your answer you have to do: (2/3)^3 or 2/3 x 2/3 x 2/3.
Use the linear inequality + 8y 24 for Part A, Part B, and Part C. Part A: Determine the boundary line, and state whether the line will be dashed or solid. Part B: Which half-plane should be shaded? Describe where you should shade using the language "above" or "below" the line. Part C: Show your work for Part B to show how you determined which half-plane to shade.
Answer:
Given inequality: [tex]x+8y\leq 24[/tex]
Part A
Solid line: ≤ or ≥
Dashed line: < or >
Therefore, the line will be solid.
Part B
Shading above the line: y > or y ≥
Shading below the line: y < or y ≤
Therefore, shade below the line.
Part C
Make y the subject to determine where to shade.
Given inequality:
[tex]x+8y\leq 24[/tex]
Subtract x from both sides:
[tex]8y\leq 24-x[/tex]
Divide both sides by 8:
[tex]y\leq 3-\dfrac18x[/tex]
[tex]\\ \rm\Rrightarrow x+8y\leqslant 24[/tex]
#Part A
as ≤ is present line will be dashed#Part B
Put (0,0)
0+8(0)≤240≤24Satisfied
Shading below the line and towards origin
#Part C
turn into y=mx+b form
8y≤-x+24y≤-1/8x+3Christopher opened a savings account with $1800 that pays no interest. He deposits an additional $90 each week thereafter. How much money would Christopher have in the account 42 weeks after opening the account?
Answer:
I think 5580
Step-by-step explanation:
You move the 1800 away for a bit so since it's 42 weeks you have to multiply 90 and 42 then add that to 1800.
A rectangle has length 1. 5 times the width, and perimeter 12 cm. What are the dimensions of
the rectangle?
Answer:
Length = 3.6
Width= 2.4
Step-by-step explanation:
A rectangle has length 1. 5 times the width, and perimeter 12 cm. What are the dimensions of
the rectangle?
So a rectangle has 2 longer sides and 2 shorter sides.
Knowing the length is 1.5 times the width
and perimeter of 12 centimeters.
The Perimeter is the adding of all the values around a shape. A rectangle has 4 sides so you add up all the sides.
1.5w+1.5w+w+w=12
5w=12
12/5=w
w=2.4
To figure the length just multiply 1.5*2.4=3.6
And That is how you solve it :)
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Please Help! Will give Brainlest!
Answer:
amplitude = 2
Step-by-step explanation:
the amplitude is the distance from the x- axis(midline ) to the maximum value , that is
amplitude = 2
[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]
Option B ( 2 ) ✓
the amount by which the graph of the function travels above and below its midline.OR,
[tex] \sf{amplitude = distance \: from \: undisturbed \: position \div centre \: line \: to \: through \: or \: peak \: }[/tex]
[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]
[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]
For the following geometric sequence find the recursive formula: {-1, 3, -9, ...}.
an = (-3) n - 1
an = -3 · an - 1 where a1 = -1
an = -3 · an - 1 where a1 = 1
an = -1 · (-3) n - 1
Answer:
an = -3 · an - 1 where a1 = -1.
Step-by-step explanation:
The first term a1 = -1 and the common ratio is -3 so ecah term is formed form the previous one by multiplying by -3.
Find the smallest number by which 350
must be multiplied to give a perfect square.
Answer:
the smallest number by which 350 by answer is 15
6,402.66 divided by 459438.26
Answer: 0.0139358
Step-by-step explanation: 999,999,999,999,999,999,999,999,999,999,999% sure!
At which point would the graphs of the equations below intersect?
{
3
x
−
4
y
=
−
2
−
6
x
+
5
y
=
7
3x-4y = -2 -6x+5y = 7
A.
(
−
2
,
−
1
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(
-
2
,
-
1
)
B.
(
2
,
−
1
)
(
2
,
-
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C.
(
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1
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2
)
(
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D.
(
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1
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Answer:
can't explain without you arranging your mathematical expression
Which value is a solution to x <
Answer:
0
Step-by-step explanation:
it less than 4 so u can't pick 4,so it is any number less than 4
Answer:
B) 0
Step-by-step explanation:
The open circle on 4 and the arrow pointing to the left means x < 4
x < 4 means that x is smaller than 4
4 = 4 incorrect as this says 4 is equal to 4
0 < 4 CORRECT as zero is smaller than 4
5 > 4 incorrect as 5 is bigger than 4
4.5 > 4 incorrect as 4.5 is bigger than 4
Fill in the table using this function rule
y=2x+2
Photo ⬇️
Answer:
Step-by-step explanation:
Put the values of x to the equation y = 2x + 2 and calculate the value of y:
x = 2
y = 2 · 2 + 2 = 4 + 2 = 6
x = 5
y = 2 · 5 + 2 = 10 + 2 = 12
x = 6
y = 2 · 6 + 2 = 12 + 2 = 14
x = 8
y = 2 · 8 + 2 = 16 + 2 = 18
Please help, again. I really need this grade!
Can someone please answer & show work? Thanks.
HELPP PLEASE!!!!!!!!!!!!!!!!!!!!!!
Answer:
Third one down |2s + 1| -3
Step-by-step explanation:
there is no value of s where it is valid
Helpppppp!!!
(Show work)
Answer:
( - y - 3 , - x - 1 )
Step-by-step explanation:
( x , y ) ----> ( - y , x ) ----> ( - y - 3 , x + 1 ) ----> ( - y - 3 , - x - 1 )
4.5
3
5
х
Find the length of x
The area of a 2/3 cube
Answer:
2 that's what soup calculated says