Val's whole-house central air conditioner uses 4,000 watts when running. Val runs the AC 7 hours per summer day. Electricity costs (10 cents)/(1 kilowatt-hour). How much does Val's AC cost to run for a summer month of 30 days?

The value of x if the object is a square with a perimeter of 94 cm is 23.5 cm

From the question, we have the following parameters that can be used in our computation:

The permieter of object A is 94cm

Assuming the object is a square

So, we have

4x = 94

Divide both sides by 4

So, we have

x = 94/4

Evaluate

x = 23.5

Hence, the value of x is 23.5cm

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Answer:

Step-by-step explanation:

considering that it is not an equation but an algebraic expression we solve it like this

10 + 6k6k =

10 + 36k²

The limit as a definite integral is  given as   lim (n → ∞) Σ(8i²)/n³ = 8/3n³

The area under the curve f(x) from x= a to x  = b is represented by the definite integral of f(x  )

There are 2 kinds of    integrals

To express the limit as a definite integral, we can use the following formul

lim(n → ∞  ) Σf(i)/n = ∫  a^bf(x)dx

where....

a and b are the lower and upper limts of the definite integral

f (x) is the function being integrated

In this case, we have

lim(n → ∞) Σ(8i²)/n³

Let f  (x) = x ²

So, f(i/n) = (i/n) ²

And, the sum can be written as

Σ(8i^2)/n³ = 8/n³ Σi²

= 8/n³ Σ(i/n)²

= 8/n³ Σ[f(i/n)]

= 8/n³ ∫0¹ f(x) dx (using the formula above)

Therefore, the limit can be   expressed as

lim(n → ∞) Σ(8i²)/n³ = 8/n³ ∫0¹ x² dx

Simplifying the integral, we get....

8/n³  ∫0¹ x₂ dx = 8/n^3 [x³/3] from 0 to 1

= 8/3n ³

Se we can say here that  the limit as a definite integral is lim(n → ∞) Σ(8i ₂)/n^3 = 8/3n ₃

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Answer:

15.43 + 12.85 + 21.3 = 49.58

Rounding to the nearest whole number, the sum is 50.

Step-by-step explanation:

Answer:

15.43 + 12.85 + 21.3 = 49.58

Step-by-step explanation:

The angle of incline of the tram is 19.4 degree.

According to the question:

h=(10450-6311)ft

= 4139 ft

We know that, sinθ=Opposite/Hypotenuse

So, sinθ=h/12463

sinθ= 4139/12463

sinθ= 0.3321

Solve the trigonometric equation by isolating the function and then taking the inverse. Use the period to find the full set of all solutions.

θ=19.39

θ≈19.4°

Therefore, the angle of incline of the tram is 19.4 degree.

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The calculated value of the side length b is 17.32 meters

From the question, we have the following parameters that can be used in our computation:

Angle B = 60 degrees

Length a = 10 meters

The side length b is calculated as

tan(60) = b/a

So, we have

tan(60) = b/10

Make b the subject

b = 10 * tan(60)

Evaluate

b = 17.32

Hence, the side length b is 17.32 meters

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Answer: 2.35619

Step-by-step explanation: Hope this helps! :)

The exact value of tan2θ in simplest radical form is  -21/√7.

The value of tan2θ at the given quadrant is calculated as follows;

From Pythagorean identity, we know that;

sin² θ + cos² θ = 1

cos² θ is calculated as follows;

(3/4)² + cos² θ = 1

9/16 + cos² θ = 1

cos² θ = 1 - 9/16

cos² θ = 7/16

cos θ = √(7/16)

The value of tan θ is calculated as follows;

tan θ = sin θ / cos θ = 3/4 x 4/√7 = 3/√7

Now, we will find tan 2θ;

tan 2θ = 2tan θ / (1 - tan² θ)

tan 2θ = 2(3/√7) / (1 - (3/√7)²)

tan 2θ = (6/√7) / (-2/7)

tan 2θ = -21/√7

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The surface area of each square pyramid, we used the formula Surface Area = Base Area + 4 x (1/2 x Base x Height of Face) is 1049.2, 1285.8 and 2100mm². The cost to cover each pyramid was $1.05, $1.29 and $2.10

To calculate the surface area of each pyramid, we need to use the formula

Surface Area = Base x Height of face + 2 x ((Base/2) x Slant Height)

For the small pyramid, we have

Surface Area = 20 x 25 + 2 x ((20/2) x 26.46)

Surface Area = 500 + 2 x 10 x 26.46

Surface Area = 1049.2 mm²

Cost to cover the small pyramid

Cost = Surface Area x 0.001

Cost = 1049.2 x 0.001

Cost = $1.05

For the medium pyramid, we have

Surface Area = 20 x 40 + 2 x ((20/2) x 42.43)

Surface Area = 800 + 2 x 10 x 42.43

Surface Area = 1285.8 mm²

Cost to cover the medium pyramid

Cost = Surface Area x 0.001

Cost = 1285.8 x 0.001

Cost = $1.29

For the large pyramid, we have

Surface Area = 30 x 40 + 2 x ((30/2) x 50)

Surface Area = 1200 + 2 x 15 x 50

Surface Area = 2100 mm²

Cost to cover the large pyramid

Cost = Surface Area x 0.001

Cost = 2100 x 0.001

Cost = $2.10

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The measure of the angles for the similar triangles are ∠G = 105°; ∠H = 55° and ∠I = 20°

Two triangles are said to be similar if the ration of their corresponding sides are in the same proportion. Also, all their corresponding angles are congruent with each other.

From the diagram shown:

∠X + ∠Y + ∠Z = 180° (sum of angles in a triangle)

20 + 105 + ∠Z = 180

∠Z = 55°

Since triangle XYZ and triangle GHI are similar, hence:

∠X = ∠G = 105°; ∠Z = ∠H = 55° and ∠Y = ∠I = 20°

The measure of the angles are ∠G = 105°; ∠H = 55° and ∠I = 20°

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Answer:204

Step-by-step explanation:

pemdas

6x[2--32]=6×[34]=204

The intervals for which each function is decreasing are f(x) = [0, ∝) and g(x) = (-∝, ∝)

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

From the graph of the functions, we can see that

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The length of the worktable is 82 inches and the width is 32 inches.

To find the length and width of the worktable, we can use a system of equations. Let's denote the width of the table by w.

Since the length is 18 inches more than twice the width, we can write:

Length = 2w + 18

The perimeter of the table is the sum of all its sides, which in this case is the sum of the length and the width, each multiplied by 2:

Perimeter = 2(length + width)

Perimeter = 2(2w + 18 + w)

Perimeter = 2(3w + 18)

Perimeter = 6w + 36

We know that the perimeter is 228 inches, so we can set up an equation:

6w + 36 = 228

Solving for w, we get:

w = 32

Now that we know the width, we can use the equation for the length to find:

Length = 2w + 18

Length = 2(32) + 18

Length = 82

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The amount that Katherine, who is going to invest in an account paying an interest rate of 5.8% compounded monthly, would need to invest, to the nearest ten dollars for the future value of the account for the account to reach $960 in 26 years, is $380 (present value).

The future value is the present value compounded at an interest rate.

The present value is the future value discounted at an interest rate.

The future value and the present value can be computed using an online finance calculator.

N (# of periods) = 192 months (16 years x 12)

I/Y (Interest per year) = 5.8%

PMT (Periodic Payment) = $0

FV (Future Value) = $960

Results:

Present Value (PV) = $380.38

Total Interest = $579.62

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Compare the data by observing the shape, center, and spread of the data in both representations.

1. Understand the data: Before comparing two representations of data, it is important to understand what the data represents and its context.

2. Identify the type of data: Identify the type of data represented in each representation to ensure the data is comparable.

3. Plot the data: Plot the data in each representation, such as a line plot, box plot, or histogram.

4. Compare the data: Compare the data by looking at the shape, center, and spread of the data in both representations.

Example: To compare data in two-line plots, plot the data as two lines on the same graph. Observe the difference in the shape of the two lines, the difference in center (the average value of the data), and the difference in spread (the range of the data).

Example: To compare data displayed in a box plot, plot the data as two box plots side by side. Observe the difference in the shape of the two box plots, the difference in center (the median value of the data), and the difference in spread (the interquartile range of the data).

Example: To compare data displayed in histograms, plot the data as two histograms side by side. Observe the difference in the shape of the two histograms, the difference in center (the mean value of the data), and the difference in spread (the standard deviation of the data).

List the steps to create a back-to-back stem-and-leaf plot:

1. Organize the data: Organize the data into two sets of numerical data.

2. Create stems: Create a stem for each set of data by dividing the values by a common multiple.

3. Create leaves: Create leaves for each set of data by recording the remainder of the original values after dividing them by the common multiple.

4. Plot the data: Arrange the stems and leaves into a back-to-back stem-and-leaf plot.

5. Compare the data: Compare the data by observing the shape, center, and spread of the data in both representations.

Therefore, compare the data by observing the shape, center, and spread of the data in both representations.

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Step-by-step explanation:

Answer:

Sure, here are the answers to your questions:

**A) The value of $f(-5)$ is $-2$.**

To find the value of $f(-5)$, we can simply substitute $x=-5$ into the equation $f(x)=-2x^2-8x+14$. This gives us:

$$f(-5)=-2(-5)^2-8(-5)+14=-2(25)+40+14=-50+54=4$$

**B) The vertex of the parabola is $(2,6)$.**

To find the vertex of the parabola, we can complete the square. This involves adding and subtracting $\left(\dfrac{{b}}{2}\right)^2$ to both sides of the equation, where $b$ is the coefficient of the $x$ term. In this case, $b=-8$, so we have:

$$\begin{aligned}f(x)&=-2x^2-8x+14\\\\ f(x)+20&=-2x^2-8x+14+20\\\\ f(x)+20&=-2(x^2+4x)\\\\ f(x)+20&=-2(x^2+4x+4)\\\\ f(x)+20&=-2(x+2)^2\end{aligned}$$

Now, if we subtract 20 from both sides, we get the equation of the parabola in vertex form:

$$f(x)=-2(x+2)^2-20$$

The vertex of a parabola in vertex form is always the point $(h,k)$, where $h$ is the coefficient of the $x$ term and $k$ is the constant term. In this case, $h=-2$ and $k=-20$, so the vertex of the parabola is $(-2,-20)$. We can also see this by graphing the parabola.

[Image of a parabola with vertex at (-2, -20)]

**C) The $y$-intercept is the point $(0,14)$.**

The $y$-intercept of a parabola is the point where the parabola crosses the $y$-axis. This happens when $x=0$, so we can simply substitute $x=0$ into the equation $f(x)=-2x^2-8x+14$ to find the $y$-intercept:

$$f(0)=-2(0)^2-8(0)+14=14$$

Therefore, the $y$-intercept is the point $(0,14)$.

**D) The two values of $x$ that make $f(x)=0$ are $2.5$ and $-3.5$.**

To find the values of $x$ that make $f(x)=0$, we can set the equation $f(x)=-2x^2-8x+14$ equal to zero and solve for $x$. This gives us:

$$-2x^2-8x+14=0$$

We can factor the left-hand side of the equation as follows:

$$-2(x-2)(x-3)=0$$

This means that either $x-2=0$ or $x-3=0$. Solving for $x$ in each case gives us the following values:

$$x=2\text{ or }x=3$$

However, we need to round our answers to two decimal places. To do this, we can use the calculator. Rounding $x=2$ and $x=3$ to two decimal places gives us the following values:

$$x=2.5\text{ and }x=-3.5$$

Therefore, the two values of $x$ that make $f(x)=0$ are $2.5$ and $-3.5$.

The number of days it would take for the investment to be valued at £3,800 is 4.4 days

From the question, we have the following parameters that can be used in our computation:

A = 1200 × 1.3^n

For the investment to be valued at £3,800, the value of A would be

A = 3800

Substitute the known values in the above equation, so, we have the following representation

1200 × 1.3^n = 3800

Divide both sides by 1200

1.3^n = 3800/1200

So, we have

n = ln(3800/1200)/ln(1.3)

Evaluate the quotient

n = 4.4

Hence, it would take 4.4 days

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Answer:

V = 3 × 2 × 6 = 36 cubic centimeters

movies 1.75 each

games 5.75 each

Answer:

x= -13/15

Step-by-step explanation:

x(15x +13)

x =0

15x + 13 = 0

15x = -13

x =-13/15

An inequality to find the least number of bananas your character slipped on: -3x ≤ -27

And  the least amount of race time character took to slip on bananas = 18 seconds.

Let us assume that x represents the number of bananas your character slipped on.

Here, based on the informtaion we get an inequality to find the least number of bananas your character slipped on -3x ≤ -27

We solve this inequality to find  the least number of seconds of race time.

-3x ≤ -27

⇒ x ≥ 9

When the character slips, it takes 2 seconds for him to resume the race.

Therefore, the least amount of race time your character took to slip on bananas would be,

9 × 2 = 18 seconds

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The complete question is:

In an online game, you receive -3 points for every banana your character slips on during a race. The total points from slipping on bananas during one race were at most -27. When the character slips, it takes 2 seconds for him to resume the race. Write and solve an inequality to find the least number of bananas your character slipped on. At least how many seconds of race time

Answer:

25000

Step-by-step explanation:

The correct statement regarding the graph is given as follows:

C. The graph is non-proportional and has the equation y = -2x + 18.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

The slope and the intercept of the line in this problem are given as follows:

Thus the equation is:

y = -2x + 18.

The equation is non-proportional, as it has an intercept which is different of zero.

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This prompt has to do with the analysis of random outcomes. See the attached tables and graphs accordingly.

An exhaustive depiction of all possible marble combinations that may arise out of a chance experiment involving two random selections has been depicted in this table.

The table enlists five different-colored marbles available in a bag and elaborates its varying conclusions based on two distinct selections.

The columns indicate colors, whereas each result depicts two correlated choices made during an experiment's progression to illustrate randomness accurately.

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Answer: 84 in

Step-by-step explanation:

A = h(b)/2

h= 7

b= 24

24x7= 168

168/2= 84

The strongest classification of the quadrilateral with the given vertices is rhombus.

The vertices of the quadrilateral is given as,

E(5, 4), F(9, 2), G(5, 0) and H(1, 2).

Find the adjacent sides EF and FG whether they are equal.

Using the distance formula,

EF = √(9 - 5)² + (2 - 4)²  = √(16 + 4) = √20

FG = √(5 - 9)² + (0 - 2)² = √(16 + 4) = √20

Adjacent sides are equal.

So they are either square or rhombus.

Find the lengths of the diagonals whether they are equal.

EG = √(5 - 5)² + (0 - 4)²  = √(0 + 16) = 4

FH = √(1 - 9)² + (2 - 2)²  = √(64 + 0) = 8

Diagonals are not equal.

So it is a rhombus.

Hence the quadrilateral is a rhombus.

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Evaluating the square root expression -2√(2r + 5) = 6 gives r = 2

From the question, we have the following expression that can be used in our computation:

-2 square root of 2r +5=6

Express properly

So, we have

-2√(2r + 5) = 6

Divide by -2

√(2r + 5) = -3

So, we have

2r + 5 = 9

Subtract 5 from both sides

2r = 4

Divide

r = 2

Hence, the solution is 2

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The value of the variable x;

1. x = -4, BC = 4x + 3 = -13

2. x = 72 degrees

3. x = 5/2, SV = 6.5, ZU = 6.4

4. x = 4

5. x = 5

6. x = 3

Tangent are simply described as any straight line that is drawn from the curve at a point but never reaches the center of the circle.

It is also important to note that tangent segments of a circle are equal.

From the information given, we have that;

1. The tangents are;

4x + 1 = 5x - 3

collect the like terms

-x = 4

x = -4

Then BC = 4x + 3 = -13

2. 2x - 1 = 143

collect the like terms

2x = 143 + 1

2x = 144

x = 72 degrees

3. 3x - 1 = 5x - 6

collect the like terms

-2x = -5

x = 5/2

Then,

SZ = ZU =  3(5/2) - 1 = 15/2 - 1 = 6.5

4. 5x² + 10 = x² + 74

collect the like terms

4x² = 64

x² = 16

x = 4

5. 2x + 7 = 5x - 8

collect the like terms

-3x = -15

divide the values

x = 5

6. 3x - 1.2 = 2x + 1.8

x = 3

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The equation that could be used to find the distance that the tornado traveled is: log d = 0.7

We are told that The wind speed near the center of a tornado is represented by the equation S = 93 log d + 65,

where:

d is the distance, in miles, that the tornado travels.

S is the wind speed, in miles per hour.

When S = 130, we have:

130 = 93 log d + 65

93 log d = 130 - 65

93 log d = 65

log d = 65/93

log d = 0.7

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