Vapor-liquid equilibrium of the two-component ideal solution of the trichloroethene and the trichloromethane is established at 25 °C. The mass fraction of C₂HCl₃ in the liquid phase is 0.52.
The mole fraction of the CHCl₃ = 0.59
The mole fraction of the C₂HCl₃ = 0.41
The Pvap, C₂HCl₃ = 73.0 mmHg
The Pvap, CHCl₃= 199. 1 mm Hg
The Mass of the C₂HCl₃ = moles × molar mass
The Mass of the C₂HCl₃ = 0.41 × 131.4
The Mass of the C₂HCl₃ = 53.8 g/mol
The mass of the CHCl₃ = 0.41 × 119.3
The mass of the CHCl₃ = 48.9 g/mol
The total mass = 102.4 g/mol
The mass fraction of the C₂HCl₃ = 53.8 / 102.4
The mass fraction of the C₂HCl₃ = 0.52
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consider the reaction performed in the sn1 lab. what would be the effect on the rate of the reaction if 2-propanol (isopropanol) was used instead of 2-methyl-2-propanol (t-butanol) assuming only an sn1 reaction occurs? group of answer choices the rate of the reaction would decrease, because the secondary carbocation is more difficult to form. the rate of the reaction would increase, because the secondary carbocation is easier to form. there would be no difference in reaction rate. the reaction would not proceed at all.
The rate of the reaction is directly proportional to the stability of the carbocation intermediate, and any changes in the solvent will affect the rate of the reaction.
In an SN1 reaction, the rate-determining step is the formation of a carbocation intermediate. The stability of the carbocation intermediate affects the rate of the reaction.
In this case, if 2-propanol (isopropanol) was used instead of 2-methyl-2-propanol (t-butanol), the rate of the reaction would decrease. This is because the carbocation intermediate formed in 2-propanol is less stable compared to the one formed in t-butanol.
The carbocation intermediate formed in t-butanol is tertiary, which is more stable than the one formed in isopropanol, which is secondary. This means that the reaction will be slower in isopropanol due to the less stable carbocation intermediate.
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tamu it is frequently necessary to perform dilutions of a stock solution in the laboratory. if you were instructed to make a 1:5 dilution of a stock solution to arrive at a final volume of 13, how much stock solution would you need to pipet?
You would need to pipette 2.6 mL of stock solution to make a 1:5 dilution with a final volume of 13 mL.
To calculate this, first note that a 1:5 dilution means that for every 1 unit of stock solution, you need to add 4 units of solvent to make a total of 5 units. This can be expressed as a ratio of stock solution to solvent as 1:4. To find the amount of stock solution needed, you can use the following equation:
(volume of stock solution) / (total volume of diluted solution) = (ratio of stock solution to solvent)Plugging in the given values, we get:
(volume of stock solution) / 13 mL = 1/5Solving for the volume of stock solution, we get:
volume of stock solution = 13 mL * (1/5) = 2.6 mLTherefore, you would need to pipette 2.6 mL of stock solution to make a 1:5 dilution with a final volume of 13 mL.
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a sample of br2(g) takes 14.0 min to effuse through a membrane. how long would it take the same number of moles of ar(g) to effuse through the same membrane?
A sample of [tex]Br_2[/tex](g) takes 14.0 min to diffuse out through a membrane. It would take 7 min for the same number of moles of Ar(g) to effuse through the same membrane.
According to Graham's Law of Diffusion, it is known that the rate of diffusion of a gas is proportional to the reciprocal of the square root of the molar mass of the gas. The rate of diffusion is recorded under the same pressure and temperature conditions.
It can be written as [tex]\frac{r_1}{r_2}[/tex] ∝ [tex]\sqrt\frac{m_2}{m_1}[/tex]
where [tex]r_1[/tex] is the rate of diffusion of one of the gas
[tex]r_2[/tex] is the rate of diffusion of the second gas
[tex]r_1[/tex] is the molar mass of one of the gas
[tex]m_2[/tex] is the molar mass of the second gas
According to the question,
[tex]\frac{14}{r_2}=\sqrt\frac{160}{40}\\\frac{14}{r_2}=\sqrt\frac{4}{1} \\\\r_2 = 14\sqrt{\frac{1}{4} } = 7[/tex]
Therefore the time taken for the diffusion of Ar (g) is 7 min
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It would take approximately 7.0 minutes for the same number of moles of Ar(g) to effuse through the same membrane.
Using Graham's law of effusion, we can compare the rates of effusion for Br2(g) and Ar(g). The formula for Graham's law is:
Rate₁ / Rate₂ = √(M₂ / M₁)
Here, Rate₁ and Rate₂ are the effusion rates of the two gases, and M₁ and M₂ are their molar masses. In this case, Br2(g) is gas 1 and Ar(g) is gas 2. The molar mass of Br2 is 159.8 g/mol, and the molar mass of Ar is 39.95 g/mol.
Since we know the time it takes for Br2 to effuse, we can write:
Time₁ / Time₂ = Rate₂ / Rate₁ = √(M₁ / M₂)
Plugging in the given time and molar masses:
14.0 min / Time₂ = √(159.8 g/mol / 39.95 g/mol)
Solving for Time₂:
Time₂ = 14.0 min * √(39.95 g/mol / 159.8 g/mol) ≈ 7.0 min
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How many L in 1. 98m solution using 4. 2mol
The volume of the solution is 2.12 L.
Molarity (M) is defined as the number of moles of solute per liter of solution. So, if we know the molarity of a solution and the amount of solute present, we can calculate the volume of the solution.
To find the volume (in L) of a 1.98 M solution containing 4.2 moles of solute, we can use the following formula:
moles of solute = molarity x volume (in L)
We can rearrange this formula to solve for volume:
volume (in L) = moles of solute / molarity
Substituting the given values, we get:
volume (in L) = 4.2 moles / 1.98 M
volume (in L) = 2.12 L
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--The complete question is, What is the volume (in L) of a 1.98 M solution containing 4.2 moles of solute?--
acetylene c2h2 gas and oxygen o2 gas react to form carbon dioxide co2 gas and water h2o vapor. suppose you have 7.0 mol of c2h2 and 1.0 mol of o2 in a reactor. could half the c2h2 react? yes no if you answered yes, calculate how many moles of co2 would be produced after half the c2h2 was used up. round your answer to the nearest 0.1 mol. mol
Yes, half the C2H2 (acetylene) can react with the given amount of O2 (oxygen) in the reactor and 7.0 mol of CO2 would be produced after half the C2H2 is used up.
To determine how many moles of CO2 (carbon dioxide) would be produced after half the C2H2 is used up, we need to first write the balanced chemical equation:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
Given 7.0 mol of C2H2 and 1.0 mol of O2, let's find out how much C2H2 can react:
(1.0 mol O2) * (2 mol C2H2 / 5 mol O2) = 0.4 mol C2H2
Since 0.4 mol is less than half of the initial 7.0 mol of C2H2 (which is 3.5 mol), half the C2H2 can react.
Now, we'll calculate the moles of CO2 produced after half the C2H2 is used up:
(3.5 mol C2H2) * (4 mol CO2 / 2 mol C2H2) = 7.0 mol CO2
Thus, 7.0 mol of CO2 would be produced after half the C2H2 is used up, rounded to the nearest 0.1 mol.
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after half of the C₂H₂ is used up, 7.0 mol of CO₂ would be produced.
Yes, half of the 7.0 mol of C₂H₂ can react, leaving 3.5 mol of C₂H₂ unreacted. The balanced chemical equation for the reaction is
C₂H₂ + 2.5 O₂ -> 2 CO₂ + H₂O
From the equation, we can see that 1 mol of C₂H₂ reacts with 2.5 mol of O₂ to produce 2 mol of CO₂ So, to determine how many moles of CO₂are produced when half of the C₂H₂ is used up, we need to calculate how many moles of O2 are required to react with 3.5 mol of C₂H₂.
3.5 mol C₂H₂ × (2.5 mol O / 1 mol C₂H₂) = 8.75 mol O₂
So, to react with 3.5 mol of C2H2, we need 8.75 mol of O2. Since we only have 1.0 mol of O2, we can only react with 0.4 mol of C2H2. Therefore, half of the 7.0 mol of C₂H₂, which is 3.5 mol, can react with 1.0 mol of O₂.
When 3.5 mol of CH₂ reacts, it produces 2/1 x 3.5 = 7.0 mol of CO₂(rounded to the nearest 0.1 mol).
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what will be the molarity of a naoh solution made by diluting 20.0 ml of 1.50 m to a final volume of 50.0 ml.
Explanation:
Moles in the 20 ml
.020 L * 1.5 moles/L = .03 moles
now in 50 ml (which is .05 liters )
.03 moles / .05 L = .6 m
How can we separate porridge from cooked rice
We separate porridge from cooked rice using a strainer or a sieve.
Porridge and cooked rice are both similar in texture and appearance, making it difficult to separate them. One way to do it is to use a strainer or a colander with small holes. Pour the mixture of porridge and rice into the strainer or colander and let the liquid portion drain out. You can also use a cheesecloth or a muslin cloth to squeeze out the liquid while retaining the rice grains.
Another method is to use a spoon to scoop out the rice from the top, leaving the porridge at the bottom. However, this method may not be as effective as the others. Regardless of the method you choose, it is important to be gentle and patient to avoid breaking the rice grains and mixing them with the porridge.
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vinegar is an aqueous solution of acetic acid, ch3cooh. suppose you titrate a 49.6 ml sample of vinegar with 34.80 ml of a standardized 0.4164 n solution of naoh. what is the normality of acetic acid in this vinegar?
The normality of acetic acid in the vinegar is 0.2919 N.
To determine the normality of acetic acid in the vinegar, you can follow these steps:
1. Write the balanced equation for the reaction:
CH₃COOH (acetic acid) + NaOH → CH₃COONa + H₂O
2. Calculate the milliequivalents of NaOH used in the titration:
Milliequivalents of NaOH = volume (mL) × normality
Milliequivalents of NaOH = 34.80 mL × 0.4164 N
Milliequivalents of NaOH = 14.49 meq (rounded to two decimal places)
3. Since the reaction is a 1:1 ratio, the milliequivalents of acetic acid will be equal to the milliequivalents of NaOH:
Milliequivalents of acetic acid = 14.49 meq
4. Calculate the normality of acetic acid in the vinegar:
Normality of acetic acid = milliequivalents of acetic acid/volume of vinegar (mL)
Normality of acetic acid = 14.49 meq / 49.6 mL
Normality of acetic acid = 0.2919 N (rounded to four decimal places)
So, the normality of acetic acid in the vinegar is 0.2919 N.
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Vinegar is an aqueous solution of acetic acid, ch3cooh. suppose you titrate a 49.6 ml sample of vinegar with 34.80 ml of a standardized 0.4164 n solution of NaOH. The normality of acetic acid in this vinegar is 0.292 N.
To find the normality of acetic acid in the vinegar, we can use the titration information provided. Here's a step-by-step explanation:
1. Write down the balanced chemical equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH):
CH3COOH + NaOH → CH3COONa + H2O
2. Calculate the number of equivalents of NaOH used in the titration:
Number of equivalents of NaOH = Volume of NaOH solution × Normality of NaOH solution
Number of equivalents of NaOH = 34.80 mL × 0.4164 N
(Note: Convert mL to L by dividing by 1000)
Number of equivalents of NaOH = 0.03480 L × 0.4164 N = 0.0145 equivalents
3. Since the balanced equation shows a 1:1 ratio between acetic acid and NaOH, the number of equivalents of acetic acid in the vinegar is equal to the number of equivalents of NaOH used in the titration.
4. Calculate the normality of acetic acid in the vinegar:
Normality of acetic acid = Number of equivalents of acetic acid / Volume of vinegar sample
Normality of acetic acid = 0.0145 equivalents / 0.0496 L = 0.292 N
So, the normality of acetic acid in the vinegar is 0.292 N.
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g standard conditions include a concentration of 1.0 m for soluble aqueous species, pure solids and liquids, and a partial pressure of 1 atm for gaseous species. group of answer choices true false previousnext
True. The standard conditions for measuring thermodynamic properties such as enthalpy, entropy, and Gibbs free energy are well-defined and standardized.
These conditions are used to compare and evaluate the relative stability and reactivity of different chemical species. The standard conditions for measuring these properties include a concentration of 1.0 m for soluble aqueous species, pure solids and liquids, and
a partial pressure of 1 atm for gaseous species. This means that the molar concentration of soluble aqueous species is set at 1.0 mol/L, and the pressure of gaseous species is set at 1 atm.
Pure solids and liquids are considered to have an activity of 1, which means that they do not affect the thermodynamic properties.
These conditions are used to determine the standard thermodynamic properties of chemical reactions, which are used to predict the direction and extent of chemical reactions.
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as lactic acid accumulates, which compensatory mechanism is initially triggered to maintain acid-base balance?
When lactic acid accumulates, the compensatory mechanism initially triggered to maintain acid-base balance is the respiratory system. It increases the rate and depth of breathing to eliminate more carbon dioxide, which helps reduce acidity and restore pH balance in the body.
As lactic acid accumulates, the compensatory mechanism that is initially triggered to maintain acid-base balance is increased ventilation or hyperventilation. This is because the increased ventilation leads to a decrease in carbon dioxide (CO2) levels in the blood, which helps to offset the acidic effects of lactic acid accumulation. This is a temporary compensatory mechanism, however, as the body will eventually need to eliminate the excess lactic acid through other means such as metabolism and excretion.
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the sour mash used to make distilled spirits is blank . multiple choice question. the acidic product resulting from malolactic fermentation the liquid fermented grain collected from a previous batch the liquid fermented grain collected from beer fermentation the acidic product resulting from beer fermentation
The sour mash used to make distilled spirits is blank is the liquid fermented grain that is collected from the previous batch.
The Sour mash or we can say that the sourmash is the process that is used in the industry of the distilling which uses the material from the older batch of the mash and to start the fermentation for the new batch, the analogous to the make of the sourdough bread with the starter.
Therefore, the liquid fermented grain that is collected from the previous batch is the sour mash used to make the distilled spirits is blank.
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which of the following is not a postulate of the kinetic-molecular theory? question 4 options: the molecules of a gas move rapidly, constantly, and in straight lines. the average kinetic energy of the molecules of a gas is directly proportional to the kelvin temperature. a gas exerts pressure because the gas molecules repel each other. the molecules of a gas are small compared to the distance between them.
Answer:
the answer is D. the molecules of a gas are small compared to the distance between them
Explanation:
The postulates of Kinetic-Molecular Theory are as follows:
The molecules of a gas move rapidly, constantly, and in straight lines.
The average kinetic energy of the molecules of a gas is directly proportional to the Kelvin temperature.
A gas exerts pressure because the gas molecules repel each other.
The molecules of a gas are small compared to the distance between them1.
Therefore, “the molecules of a gas are small compared to the distance between them” is not a postulate of Kinetic-Molecular Theory
a dissolution process is exothermic if the amount of energy released in bringing about ? interactions is greater than the sum of the amounts of energy absorbed in overcoming ? and ? interactions. 1. solvent-solute; solute-solute; solventsolvent 2. solute-solute; crystal lattice; solventsolvent 3. solute-solute; solvent-solvent; solventsolute 4. solvent-solvent; solute-solute; solventsolute 5. solvent-solute; solute-solute; crystal lattice
The correct answer to your question is option 2, which states that a dissolution process is exothermic if the amount of energy released in bringing about solute-solute interactions is greater than the sum of the amounts of energy absorbed in overcoming crystal lattice and solvent-solvent interactions.
To understand this concept better, we need to understand what happens during the dissolution process. When a solute dissolves in a solvent, the solute particles break away from their crystal lattice structure and mix with the solvent particles. This process involves overcoming the attractive forces between the solute particles (solute-solute interactions) and the attractive forces between the solvent particles (solvent-solvent interactions). At the same time, energy is released when the solute particles interact with the solvent particles (solvent-solute interactions).
In an exothermic dissolution process, the energy released due to solvent-solute interactions is greater than the energy required to overcome the crystal lattice and solvent-solvent interactions. This means that more energy is released than absorbed, resulting in a net release of heat. This is because the attractive forces between the solute and solvent particles are stronger than the forces holding the solute particles in their crystal lattice structure.
Overall, the exothermic nature of a dissolution process depends on the balance between the energy released and absorbed during the process. By understanding the interactions between solute and solvent particles, we can predict whether a dissolution process will be exothermic or endothermic.
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in the reaction of thiosulfate ion with chlorine gas in an acidic solution, what is the reducing agent?
Mrs. Johnson is 44 years old. She has fluctuating weakness around her eyes, difficulty
chewing and swallowing. She is told she has an autoimmune disorder that has no
cure. These symptoms describe:
O myasthenia gravis
O Cumulative trauma disorders
O muscular distropy
O tetanus
Answer:
A
Explanation:
M.G has no cure. it's an autoimmune disease that affects communication between nervous and the muscles.
You are trying to determine the concentration of a stock solution of hydrochloric acid. You have 450.80 mL of 0.86 M dilute solution that was prepared with 25.50 of stock solution.
The concentration of stock solution is 15.2 M if You have 450.80 mL of 0.86 M dilute solution that was prepared with 25.50 of stock solution.
How to calculate concentration?This one is done as follows: First, you use the knowledge that molarity is expressed as mol/liter. We can then solve for the first of two unknowns using the conversions of 450.08 mL to L and 25.50 mL to L. The initial unknown is the mol count in the diluted HCl.By solving for xmol, we obtain xmol/.4508 =.86 M.86*.4508 =.38 mol = xmol. We then enter the discovered xmol (0.38 mol) into the concentration formula. As a result, we arrive at a final result of.38 mol/0.0255L = 15.2 M stock solution.An adequate amount of a pure solid or pure liquid is measured out, put in a suitable flask, and then weighed out to create a stock solution.For more information on stock solution kindly visit to
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what is the effect on the concentration of ammonia, hydroxide ion, and ammonium ion when the following are added to a basic buffer solution of equal concentrations of ammonia and ammonium nitrate:
Changes in the chemical environment of a basic buffer solution can cause shifts in the equilibrium between ammonia, hydroxide ion, and ammonium ion, leading to changes in their respective concentrations.
When a basic buffer solution of equal concentrations of ammonia and ammonium nitrate is subjected to changes in its chemical environment, the concentrations of ammonia, hydroxide ion, and ammonium ion will be affected as follows:
1) Addition of an acid: The acid reacts with the hydroxide ion present in the buffer solution to form water. This decreases the concentration of hydroxide ion and shifts the equilibrium towards the formation of more ammonia and ammonium ion, thus increasing their concentrations.
2)Addition of a base: The base reacts with the ammonium ion present in the buffer solution to form ammonia and water. This decreases the concentration of ammonium ion and shifts the equilibrium towards the formation of more hydroxide ion, thus increasing its concentration.
3)Dilution: Diluting the buffer solution with water decreases the concentrations of both ammonia and ammonium ion, but does not affect the concentration of hydroxide ion.
4)Addition of ammonium chloride: The ammonium chloride dissociates into ammonium ion and chloride ion in the buffer solution. The increase in ammonium ion concentration causes the equilibrium to shift towards the formation of more ammonia and hydroxide ion, thus increasing their concentrations.
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What is the equilibrium equation for the reaction: nh4no3(s) ⇌ n2o(g) + 2 h2o(g)?
The equilibrium equation for the reaction:
NH₄NO₃(s) ⇌ N₂O(g) + 2H₂O(g) is Kp = [ N₂O][H₂O]².
In the equilibrium expressions we only considered the gases and the aqueous compounds. When the one or the more of the substances in the system that will exists in the gaseous phase, and the partial pressure of the species which can be used for the equilibrium expression.
The chemical reaction is as :
NH₄NO₃(s) ⇌ N₂O(g) + 2H₂O(g)
The equilibrium expression is as :
Kp = [ N₂O][H₂O]².
The ratio of the concentrations for the reactants and the products is called as the equilibrium constant expression.
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Arrange the following events in the proper order in which they occur during an allergic response.
1 = Individual experiences symptoms
2 = Individual is sensitized to antigen
3 = IgE attaches to mast cells
4 = Antigen binds to IgE
Answer:
In order is 2, 3, 4, 1
Explanation:
It starts when you come into contact with a trigger that you inhale, swallow, or get on your skin. In response, your body starts to make a protein called IgE, which grabs onto the allergen. Then histamine and other chemicals get released into the blood.
if you add an acid, like acetic acid, to your slime you will disrupt the cross linking interactions between the borax and glue causing it to become a liquid with a lower viscosity. however, you can easily repair your slime. to repair your slime should you add an acid, base, or more borax to your slime. explain your reasoning.
When acid is added to the slime, the crosslinking is broken, resulting in a liquid with lesser viscosity. When alkali is added, the process is reversed, and the slime needs to be regenerated.
What happens if extra borax is added to a certain slime product?Two key components, polyvinyl alcohol and borate ion, combine chemically to create slime. You can find both of them in common home products. Simple PVA glue contains polyvinyl alcohol, while contact lens solutions including baking soda and bicarbonate of soda produce borate ions.More sodium borate is used, the more crosslinking there is. The best slime (with the right amount of crosslinking) for this can be chosen by the students by stretching or rolling the slime into long ropes. When there are drips, Additions of hydrochloric acid cause the slime to dissolve and turn into a thin, sticky liquid. The slime becomes less viscous as hydrochloric acid is applied in greater amounts.For more information on slime kindly visit to
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how much energy, in kj, is carried by one mole of photons of blue light absorbed by proflavine molecule at 470 nm?
A proflavine molecule absorbs one mole of blue light at 470 nm, which has an energy content of about 25.4 kJ.
What materials make up photon energy?A photon is a microscopic particle made up of electromagnetic radiation waves. Maxwell demonstrated that photons are merely electric fields moving through space. Photons move at the speed of light and have no charge or rest mass.
We can calculate by using the following formula:
E = hc/λ
E = energy of the photon
h = Planck's constant (6.626 × 10^-34 J·s)
c = speed of light (2.998 × 10^8 m/s)
λ = wavelength of the light
We have to multiply the energy per photon by Avogadro's number (6.022 × 10^23 photons/mol).
we have to convert the 470 nm to meters:
λ = 470 nm × (1 m/10^9 nm) = 4.70 × 10^-7 m
We calculate the energy per photon,
E = hc/λ
E = (6.626 × 10^-34 J·s) × (2.998 × 10^8 m/s) / (4.70 × 10^-7 m)
E = 4.21 × 10^-19 J
Now:
E = (4.21 × 10^-19 J/photon) × (6.022 × 10^23 photons/mol) / 1000 J/kJ = 25.4 kJ/mol
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3) 1.90 L of gas are heated from 25.00°C to 95.00°C. If the pressure remains constant, what will be the new
volume?
The new volume of the gas with 1.90 L of gas are heated from 25.00°C to 95.00°C. If the pressure remains constant, is 72.2L.
Calculation of volumeAccording to Charles Law the formula given here is V1/T1=V2/T2
Substituting the values in the equation we get
1.9/25=V2/ 95
V2= 1.9× 95/25
V2= 72.2 L
The experimental gas law known as Charles's law outlines how gases have a tendency to expand when heated. Charles's law is now expressed as follows: The volume and Kelvin temperature of a sample of a dry gas will be directly proportional to the pressure, when the pressure is held constant.
The volume of a gas is equal to a constant amount multiplied by the temperature of the gas as determined by the Kelvin scale (zero Kelvin is equivalent to -273.15 degrees Celsius), according to the physical law known as Charles' law.
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PLEASE ANSWER ASAP
1. How many atoms are present in 8.500 mole of chlorine atoms?
2. Determine the mass (g) of 15.50 mole of oxygen.
3. Determine the number of moles of helium in 1.953 x 108 g of helium.
4. Calculate the number of atoms in 147.82 g of sulfur.
5. Determine the molar mass of Co.
6. Determine the formula mass of Ca3(PO4)2.
IT WOULD BE HELPFUL
1) 5.1167 x 10²⁴atoms of chlorine. 2) 248.00 g. 3) 4.8825 x 10⁷ moles of helium. 4) 2.7757 x 10²⁴ atoms of sulfur. 5) Molar mass of Co (cobalt) is 58.93 g/mol. 6) Formula mass = 310.18 g/mol.
What is meant by formula mass?Sum of the atomic masses of all the atoms in chemical formula is called formula mass
1.) Number of atoms = 8.500 moles x 6.022 x 10²³ atoms/mole = 5.1167 x 10²⁴ atoms of chlorine.
2.) Molar mass of oxygen is 16.00 g/mol. Therefore:
Mass of 15.50 moles of oxygen = 15.50 moles x 16.00 g/mol = 248.00 g.
3.) Molar mass of helium is 4.00 g/mol. Therefore, the number of moles of helium in 1.953 x 10⁸ g is:
Number of moles = 1.953 x 10⁸ g / 4.00 g/mol = 4.8825 x 10⁷ moles of helium.
4.) Molar mass of sulfur is 32.06 g/mol. Therefore, the number of moles of sulfur in 147.82 g is:
Number of moles = 147.82 g / 32.06 g/mol = 4.6084 moles of sulfur.
To find the number of atoms, we can use Avogadro's number again:
Number of atoms = 4.6084 moles x 6.022 x 10²³ atoms/mole = 2.7757 x 10²⁴ atoms of sulfur.
5.) Molar mass of Co (cobalt) is 58.93 g/mol.
6.) Ca₃(PO₄)₂ contains 3 calcium atoms, 2 phosphorus atoms, and 8 oxygen atoms.
Atomic masses of these elements are:
Calcium (Ca) = 40.08 g/mol
Phosphorus (P) = 30.97 g/mol
Oxygen (O) = 16.00 g/mol
Therefore, formula mass of Ca₃(PO₄)₂ is:
Formula mass = (3 x 40.08 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol)
= 120.24 g/mol + 61.94 g/mol + 128.00 g/mol
= 310.18 g/mol.
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17) An ionic compound was dissolved in 250 mL of water and the temperature of the solution increased from 25°C to 42°C. a. Is the value for AH greater than zero or less than zero. Justify your answer. b. Would you expect that the AH value has a large or a small magnitude? Justify your answer. c. Is the value for AG greater than zero or less than zero. Justify your answer.
When an ionic compound was dissolved in 250 mL of water and the temperature of the solution increased from 25°C to 42°C, the value of ΔH is lesser than zero and has a small magnitude and the value of ΔG is also lesser than zero.
When ionic compounds dissolve in water, the ions in the solid separate and disperse uniformly throughout the solution because water molecules surround and solvate the ions, reducing the strong electrostatic forces between them. This process represents a physical change known as dissociation.
In this there is increase in temperature which means that heat energy is released which makes the dissolution exothermic and thus it has ΔH negative. Since the reaction is feasible, the ΔG will be less than zero.
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if the size of the zinc electrode were doubled, does the cell voltage increase, decrease or stay the same? justify your answer.
In changing the size of the zinc electrode would not impact the voltage of the cell.
If the size of the zinc electrode were doubled, the cell voltage would stay the same. This is because the voltage of a cell is dependent on the difference in potential between the two electrodes, not their size.
Doubling the size of the zinc electrode would not change the potential difference between the zinc and copper electrodes, therefore the cell voltage would remain constant.
The only factor that would affect the cell voltage would be a change in the concentration or temperature of the electrolyte solution or a change in the material or surface area of the copper electrode.
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Lila is a track and field athlete. She must complete four laps around a circular track. The track itself measures 400 meters from start to finish and the race took her 6 minutes to complete.
Which best describes her speed and velocity?
Her speed is 4. 4 m/s, and her velocity is 0 m/s.
Her speed is 1. 1 m/s, and her velocity is 0 m/s.
Her speed is 0 m/s, and her velocity is 2400 m/s.
Her speed is 4. 4 m/s, and her velocity is 4. 4 m/s
The best describes her speed and velocity is; Her speed is 4. 4 m/s, and her velocity will be 0 m/s. Option A is correct.
Lila's speed will be calculated by dividing the total distance she covered by time it took her to complete the race;
Speed = Total distance/Time
In this case, Lila will covered 4 laps, which is a total distance of 4 x 400 = 1600 meters. She completed the race in 6 minutes, which is 6 x 60 = 360 seconds. Therefore, her speed is;
Speed = 1600 meters / 360 seconds
Speed = 4.44 m/s (rounded to two decimal places)
Velocity, on the other hand, is a vector quantity that takes into account both speed and direction. Since Lila ran four laps around a circular track, she ended up at the same position where she started. However, her displacement (change in position) is zero, which means her velocity is also zero.
Hence, A. is the correct option.
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--The given question is incomplete, the complete question is
"Lila is a track and field athlete. She must complete four laps around a circular track. The track itself measures 400 meters from start to finish and the race took her 6 minutes to complete. Which best describes her speed and velocity? A) Her speed is 4. 4 m/s, and her velocity is 0 m/s. B) Her speed is 1. 1 m/s, and her velocity is 0 m/s. C) Her speed is 0 m/s, and her velocity is 2400 m/s. D) Her speed is 4. 4 m/s, and her velocity is 4. 4 m/s"--
Calculate the amount of copper obtained by the reaction. Was it the amount you expected? Explain.
The amount of copper obtained by the reaction depends on the amount of copper chloride reacted and the limiting reagent in the reaction.
Without information on the amounts of reactants used, it is not possible to calculate the amount of copper obtained by the reaction or compare it to the expected amount. However, if the reaction was carried out under controlled conditions and all reactants were used in the stoichiometric ratio, the amount of copper obtained should be the expected amount calculated based on the balanced chemical equation.
In order to calculate the expected amount of copper obtained, the amount of copper chloride reacted should be known, and the limiting reagent should be identified. The amount of copper obtained will be determined by the limiting reagent.
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The complete question is:
Calculate the amount of copper obtained by the reaction. Was it the amount you expected? Explain.
3CuCl2(aq) +2 Al (s) ----> 2AlCl3(aq) + 3Cu(s)
glyphosate is a common compound found in many herbicides. why was it thought to have no effect on human health before recent scientific studies?
Glyphosate was initially thought to have no effect on human health because it primarily targets enzymes found only in plants and bacteria, not humans.
Additionally, the compound was believed to have a low toxicity level and was considered to be safe when used according to the labeled instructions.
However, recent scientific studies have suggested potential health risks associated with glyphosate exposure, including links to cancer and other health issues.
These studies have prompted further investigation and controversy surrounding the safety of glyphosate in herbicides.
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what might be the result if you had 6 m acetic acid rather than glacial acetic acid in the first step of the friedel-crafts reaction? there would be no effect, acetic acid is just the solvent. more product would likely have formed. less product would likely have formed. more t-butanol would have reacted.
If you had 6 M acetic acid rather than glacial acetic acid in the first step of the Friedel-Crafts reaction, less product would likely have formed.
The Friedel-Crafts reaction requires a strong Lewis acid catalyst, such as aluminum chloride (AlCl3), which reacts with the acylating agent to form a reactive electrophile. In this case, the acylating agent is acetic anhydride, which reacts with AlCl3 to form an acylium ion that can then react with the aromatic ring. However, the reaction is sensitive to the amount of water present, and the presence of excess water (which would be more likely in the case of dilute acetic acid) can lead to hydrolysis of the acylium ion and a decrease in the yield of the desired product.
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show two different methods to carry out the following transformation: a one-step using a wittig reaction, and a two-step method using a grignard reaction. which route, if any, is preferred?
The one-step Wittig reaction is preferred over the two-step Grignard reaction for the conversion of aldehydes to alkenes due to its simplicity, higher yields, and fewer side reactions.
The change includes switching an aldehyde over completely to an alkene, which can be accomplished through a one-step Wittig response or a two-step Grignard response.
The one-step Wittig response includes responding the aldehyde with a Wittig reagent, which is a phosphonium ylide, within the sight of a base. The response delivers an alkene and a phosphine oxide as a result.
Then again, the two-step Grignard response includes the development of a Grignard reagent from an alkyl or aryl halide, trailed by the expansion of the subsequent Grignard reagent to the aldehyde to shape a liquor. The liquor is then got dried out to shape the ideal alkene.
As a general rule, the one-step Wittig response is liked over the two-step Grignard response for the transformation of aldehydes to alkenes since it is a less difficult and more straightforward interaction. The Wittig response additionally has better returns and less side responses contrasted with the Grignard response. In any case, the decision of response might rely upon the particular beginning material and the ideal item.
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The transformation in question involves the conversion of a carbonyl compound (such as an aldehyde or ketone) to an alkene.
One method to achieve this transformation is through a one-step reaction called the Wittig reaction. In this method, a phosphorus ylide is used to transfer a carbonyl group to the ylide, forming an intermediate called an oxaphosphetane. This intermediate then undergoes an elimination reaction to give the desired alkene.
Another method to achieve this transformation is through a two-step reaction called the Grignard reaction. In this method, a Grignard reagent is first prepared by reacting an alkyl or aryl halide with magnesium in the presence of an ether solvent. This Grignard reagent can then react with a carbonyl compound to form an intermediate called an alkoxide. This intermediate can then undergo an elimination reaction to give the desired alkene.
The preferred route depends on several factors, such as the nature of the starting material, the desired product, and the availability of reagents. In general, the Wittig reaction is preferred for the conversion of aldehydes to alkenes, while the Grignard reaction is preferred for the conversion of ketones to alkenes. However, both methods can be useful in different situations and should be considered based on the specific requirements of the synthesis.
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