Vocabulary Are 23 and 24 adjacent angles? Explain. 1. 2. 3. 4 Reasoning Does every angle have a complement? Explain.
Answers
We will have the following:
1. We have that 3 & 4 are not adjacent angles.
2. We have that 3 and 4 are adjacent angles.
3. We have that 3 and 4 are not adjacent angles.
4. Not every angle has a complement. A complement is when two angles add up to 90°, so any angle greater than 90° won't have a complement.
***Explainations***
1- 3 & 4 in order to be adjacent have to share the same vertex [They do] and have to be one right next to the other [They are not, there is another angle between them].
2. 3 & 4 are adjacent since they share the same vertex and are one next to the other.
3. 3 & 4 are not adjacent since they do not share a vertex.
Related Questions
Colin is playing a video game. He wins 25 points for each gold coin he finds. His goal is to win more than 200 poijts. He wants to know how many gold coins he needs to find.
Answers
25 points for each gold coin
He wants more tha 200 points
Number of coins to get 200 points: = 200/25 = 8
Answer:
He needs to find 8 gold coins or more
>= 8
A company purchased 10,000 pairs of men'sslacks for $18.66 per pair and marked them up $22.93. What was the selling price of each pair of slacks? Use the formulaS=CMThe selling price of each pairs of slacks is ?
Answers
Given:
A company purchased slacks for $18.66 per pair.
Mark up= $22.93
[tex]\begin{gathered} \text{Selling price= cost price +mark up} \\ \text{Selling price=}18.66+22.93 \\ \text{Selling price= \$41.59} \end{gathered}[/tex]x- sq root 6 is a factor of x^4-36 true or false
Answers
We want to know if (x-sqroot(6)) is a factor of (x^4 - 36)
That's mean:
[tex](x^4-36)=(x-\sqrt[]{6})\text{ P(x)}[/tex]Where P(X) is a polinomial.
In this case, if x = sqroot(6) the polinomail (x^4 - 36) must be zero, that's mean sqroot(6) is a root (or a zero) of (x^4-36).
So, if we evaluate (x^4 - 36) in x=sqroot(6):
[tex](\sqrt[]{6})^4-36=6^2-36=0[/tex]So, the answer is true.
Choose the correct answer below
Answers
The book is not the same story or the movie is not the same story.
What is De Morgan's law?The intersection of two sets' complements is the complement of the union of two sets, and the intersection of two sets' complements is the complement of the intersection of two sets. They are referred to as De Morgan's laws. These have the name De Morgan after the mathematician.De Morgan's laws are a pair of transformation rules that can both be used as rules of inference in propositional logic and Boolean algebra. They have the name of the 19th-century British mathematician Augustus De Morgan.When attempting to demonstrate that the NAND gate is equivalent to an OR gate with inverted inputs and the NOR gate is equivalent to an AND gate with inverted inputs, we can employ De Morgan's theorems.To learn more about De Morgan's law refer to:
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1. 3 In right AXYZ, the length of the hypotenuse YZ is 85 inches and tan Z= 3/4 What is the length, in inches, of the leg XY?
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We have a right triangle XYZ.
The length of the hypotenuse is YZ=85.
We also know that the tangent of Z is 4.
We have to find the length of XY.
We can start by drawing the triangle and writing the data:
The tangent of an angle can be related with the sides by the following trigonometric ratio:
[tex]\tan (Z)=\frac{\text{Opposite}}{\text{Adyacent}}=\frac{XY}{XZ}=\frac{3}{4}[/tex]We can not find the value of the legs from the trigonometric ratio, but we have a proportion between them. We can write the previous result as:
[tex]\begin{gathered} \frac{XY}{XZ}=\frac{3}{4} \\ XZ=\frac{4}{3}\cdot XY \end{gathered}[/tex]Now we can relate XY with the hypotenuse YZ using the Pythagorean theorem:
[tex]\begin{gathered} XY^2+XZ^2=YZ^2 \\ XY^2+(\frac{4}{3}XY)^2=YZ^2 \\ XY^2+\frac{16}{9}XY^2=YZ^2 \\ (\frac{16}{9}+1)XY^2=YZ^2 \\ \frac{16+9}{9}XY^2=YZ^2 \\ \frac{25}{9}XY^2=YZ^2 \\ XY^2=\frac{9}{25}YZ^2 \\ XY=\sqrt[]{\frac{9}{25}YZ^2} \\ XY=\frac{3}{5}YZ \\ XY=\frac{3}{5}\cdot85 \\ XY=51 \end{gathered}[/tex]Answer: the length of the leg XY is 51 inches.
Write a situation for this equation
1.5 < 1.67
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The inequality equation is correct the way it is in the form 1.5 < 1.67 and will continue to be correct if 1.5x < 1.67 where x is
negative numberx less than or equal to 1What are inequalities?Inequalities as used in mathematics refers to the symbol that is used to related the values in the left hand side and the values at the right hand side of the expression
The symbol used in the inequality expression are
less than or equal togreater than or equal toless thangreater thanThe given expression is less than and read as 1.5 is less than 1.67
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Evaluate each function. Be sure to show your substitutions.h(x) = 7x^2 - 4x-15h(20)
Answers
The function is given as,
[tex]h(x)=7x^2-4x-15[/tex]The objective is to determine the value h(20).
This can be obtained by substituting 20 for 'x' in the given expression,
[tex]\begin{gathered} h(20)=7(20)^2-4(20)-15 \\ h(20)=7(400)-80-15 \\ h(20)=2800-95 \\ h(20)=2705 \end{gathered}[/tex]Thus, the value of the given function h(20) is 2705.
Write the equation below in standard form and then answer the following questions. If a value is a non-integer type your answer as a decimal rounded to the hundredths place. 4x^2+24x+25y^2+200y+336=0The center of the ellipse is (h,k). h= Answer and k= AnswerThe value for a is Answer . The value for b is Answer .The foci with the positive x value is the point ( Answer, Answer)The foci with the negative x value is the point ( Answer, Answer)
Answers
Given:
[tex]4x^2+24x+25y^2+200y+336=0[/tex]Aim:
We need to convert the given equation into the standard form of the ellipse equation.
Explanation:
Consider the standard form of the ellipse equation.
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]Consider the given equation.
[tex]4x^2+24x+25y^2+200y+336=0[/tex][tex]Use\text{ }336=36+400-100.[/tex][tex]4x^2+24x+25y^2+200y+36+400-100=0[/tex][tex]4x^2+24x+36+25y^2+200y+400-100=0[/tex]Take out the common terms.
[tex]4(x^2+6x+9)+25(y^2+8y+16)-100=0[/tex]Add 100 on both sides of the equation.
[tex]4(x^2+6x+9)+25(y^2+8y+16)-100+100=0+100[/tex][tex]4(x^2+6x+9)+25(y^2+8y+16)=100[/tex][tex]4(x^2+2\times3x+3^2)+25(y^2+2\times4y+4^2)=100[/tex][tex]\text{Use (a+b)}^2=a^2+2ab+b^2.[/tex][tex]4(x+3)^2+25(y+4)^2=100[/tex]Divide both sides by 100.
[tex]\frac{4\mleft(x+3\mright)^2}{100}+\frac{25\mleft(y+4\mright)^2}{100}=\frac{100}{100}[/tex][tex]\frac{\mleft(x+3\mright)^2}{25}+\frac{\mleft(y+4\mright)^2}{4}=1[/tex][tex]\frac{\mleft(x+3\mright)^2}{5^2}+\frac{\mleft(y+4\mright)^2}{2^2}=1[/tex][tex]\frac{\mleft(x-(-3)\mright)^2}{5^2}+\frac{\mleft(y-(-4)\mright)^2}{2^2}=1[/tex]The standard form of the given equation is
[tex]\frac{\mleft(x-(-3)\mright)^2}{5^2}+\frac{\mleft(y-(-4)\mright)^2}{2^2}=1[/tex]Compare with the general form of the ellipse equation.
We get h=-3, k=-4, a=5 and b=2.
The centre of the ellipse is h= -3 and k = -4.
The value of a is 5.
The value of b is 2.
We need to find the eccentricity of the ellipse.
[tex]e=\sqrt[]{1-\frac{b^2}{a^2}}[/tex]Substitute b=2 and a =5 in the formula.
[tex]e=\sqrt[]{1-\frac{2^2}{5^2}}=\sqrt[]{1-\frac{4}{25}}=\sqrt[]{\frac{25-4}{25}}=\sqrt[]{\frac{21}{25}}=0.9165[/tex][tex]e=0.9165[/tex]The foci of the ellipse are
[tex]((h\pm a)e,0)[/tex]Substitute h =-3, a=5 and e =0.9165 in the formula.
[tex]((-3\pm5)0.9165,0)[/tex]The foci with a positive x value are the point
[tex]((-3+5)0.9165,0)\text{ =}(1.83,0)[/tex]
[tex](1.83,0)[/tex]
The foci with a negative x value are the point
[tex]((-3-5)0.9165,0)\text{ =}(-7.33,0)[/tex][tex](-7.33,0)[/tex]Find mCBD. the number might be a bit blurry but it is 192
Answers
Circle is 360 degrees.
Arc DB = 360 - 192 = 168°
The measure of angle CBD is half the measure of Arc DB.
Thus,
[tex]\begin{gathered} \angle\text{CBD}=\frac{1}{2}(168) \\ =84\degree \end{gathered}[/tex]What’s eight less than four times a number in algebraic expression
Answers
Answer:
4x - 8, 4x just means four of x, and eight less means to subtract 8.
Step-by-step explanation:
Answer:
The answer is 4x - 8 and it equals -32
Help please not sure if I am right or wrong thank you
Answers
Given:
[tex]-1+\sqrt[]{-4}[/tex]To find the simplified complex number
[tex]\begin{gathered} -1+\sqrt[]{-4}=-1\pm2i \\ -1+\sqrt[]{-4}=-1+2i,-1-2i \end{gathered}[/tex]27–34: Describing Distributions. Consider the following distributions.-How many peaks would you expect the distribution to have? Explain.-Make a sketch of the distribution.-Would you expect the distribution to be symmetric, left-skewed, or right-skewed? Explain.-Would you expect the variation of the distribution to be small, moderate, or large? Explain.#29The annual snowfall amounts in 50 randomly selected American cities
Answers
Answer:
Step-by-step explanation:
At an appliance store, if 63 stereos were sold during a one-month period, which of the following must be true?A. At least one stereo was sold on each day of the monthB. Exactly two stereos were sold on the same day during the monthC. At least one stereo was sold on either Monday, Wednesday, or Friday during the monthD. At least three stereos were sold on one day of the month.
Answers
Answer:
Alternative D. At least three stereos were sold on one day of the month.
Explanation:
Now, let's evaluate the options:
A. At least one stereo was sold on each day of the month
It is false.
We can not affirm that. For example, all the stereos can be sold on only one day of the month
B. Exactly two stereos were sold on the same day during the month
It is false.
Same explanation as A.
C. At least one stereo was sold on either Monday, Wednesday, or Friday during the month
It is false.
We can not affirm that too. The explanation is the same as for alternative A.
D. At least three stereos were sold on one day of the month.
It is true.
If two stereos are sold every day, for a month of 30 days, 60 stereos are sold. So, on some days 3 or more stereos are sold.
Also, if all the stereos are sold on the same day, more than 3 stereos were also sold.
So, alternative D is correct.
F(x) = 5-7x find f(-3)
Answers
Answer:
26
Step-by-step explanation:
Just plug -3 in where ever you see x
[tex]f(x)=5-7x\\f(-3)=5-7(-3)\\f(-3)=5+21\\f(-3)=26[/tex]
q divided by 4 + 8q, for q=8
Answers
We have to calculate the value of the expression:
[tex]\frac{q}{4+8q}[/tex]when q = 8.
To calculate this, we replace q with its value and solve as:
[tex]\frac{q}{4+8q}=\frac{8}{4+8\cdot8}=\frac{8}{4+64}=\frac{8}{68}=\frac{2}{17}[/tex]Answer: 2/17
Determine the effect on the graph of the parent f(x)=x
Answers
To answer this question we first graph the parent function
Now we compare the two graphs. We notice that the graph shown is translated two units up.
To translate the graph of function we have to add the ammount we want to translate, then in this case
[tex]g(x)=f(x)+2[/tex]Therefore the answer is J.
1. Which scatter plot could have a trend line whose equation is y - 3x + 10 (A) 60 60 40 40 20 20 0 y M 10 20 0 10 20 D . 12 60 8 40 4 29 0 10 220 0 10 10 20
Answers
Explanation
Given the trend line equation that defines a scatter plot
We will have to substitute the values of x = 2.5,5,7.5,10,15,20 and check the graphs
So, when x =2.5
[tex]\begin{gathered} y=3(2.5)+10=7.5+10=17.5 \\ y=17.5 \end{gathered}[/tex]when x=5
[tex]\begin{gathered} y=3(5)+10=15+10 \\ y=25 \end{gathered}[/tex]When x= 7.5
[tex]y=3(7.5)+10=32.5[/tex]When x =10
[tex]\begin{gathered} y=3(10)+10=40 \\ y=40 \end{gathered}[/tex]If we check all the values obtained to the graph, we will discover that the best option will be
Option B is more correct
Because most of the points conform to the trend line equation
If 16 is added to a number, the result is 35 less than twice the number. Find the number.
Answers
Let us represent the number as x:
16 is added to a number is represented as:
[tex]16+x[/tex]The result been 35 less than twice the number is represented as:
[tex]2x-35[/tex]Combining the above expression together to find the number will be:
[tex]16+x=2x-35[/tex]Simplifying further:
[tex]\begin{gathered} 16+35=2x-x \\ 51=x \\ \end{gathered}[/tex]The number, therefore, is 51
Write a linear function f with f(0) = 3.75 and f(-6) =3.75
f(x) = ???
Answers
The linear function will be;
⇒ f (x) = 3.75
What is an expression?
Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The values are,
⇒ f (0) = 3.75
And, f (-6) = 3.75
Now,
Let the linear function is,
f (x) = ax + b
Since, The values is given as;
f (0) = 3.75
And, f (-6) = 3.75
So, We can substitute the given values in the linear function, we get;
f (x) = ax + b
Substitute x = 0 we get;
f (0) = a × 0 + b
f (0) = b
3.75 = b
b = 3.75
And, We can substitute x = -6 and f(0) = 3.75 we get;
f (-6) = a × -6 + b
3.75 = -6a + 3.75
- 6a = 0
a = 0
So, Substitute a = 0 and b = 3.75 in linear function we get;
f (x) = ax + b
f (x) = a × 0 + 3.75
f (x) = 3.75
Therefore,
The linear function will be;
⇒ f (x) = 3.75
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S = 2^0 + 2^1 + 2^2 + 2^3 + ...... 2^99a) Show that S can be divided by 15b) Show that S has at least 30 digits
Answers
Answer:
Explanation:
Here, we want to show that the sum is divided by 15
From what we have, the given sum is a geometric sequence
The first term is 1
Now, the pattern of ending afterwards will be 2, 4, 6 and 8
This ending keeps repeating itself
This 2,4,6,8 pattern could repeat itself 24 times
So we have a total of 1 + 24(4) = 97 terms
To make it 100, we have the last three terms as 2,4 and 8
So we have the ending number ONLY sum as follows:
1 + 24(2+4+6+8) + 2 + 4 + 8 = 1 + 480 + 14 = 495
We can divide this by 15 and that gives 495/15 = 33
That shows that the sum is divisible by 15
Secondly, we want to show that S has at least 30 digits
We can infer this from the last terms
We can write 2^99 as 2^33 * 2^33 * 2^33
A single 2^33 has a value of 8,589,934,592
That means 10 digits
The other two has 10 digits too
The sum of all possible digits in the largest term is 10 + 10 + 10 = 30
That makes a total of 30
The question states 30 or more
Hence, this is correct
What is the coefficient of the second term in this expression?-k + 10m² - 6 - n² ?
Answers
Given the expression:
[tex]-k+10m^2-6-n^{2^{}}[/tex]The second term in the expression means the 2nd term from left to right of an expression.
Here, the second term is 10m².
A coefficient is a number that is being multiplied by the variable.
Therefore, the coefficient of the term 10m² is 10.
Jason enjoys watching the squirrels in his neighborhood park. They eat the red oak acorns. After the city removed 4 diseased red oak trees, the population of squirrels decreased from 105 to 98 in one year. If the population continues to decline at the same rate, how many squirrels will live in the park in 15 years? First, calculate the rate of decay by subtracting the two populations and dividing the difference by the initial population. Then, use the formula A=a0e^kt
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given parameters
[tex]\begin{gathered} Initial\text{ squirrels}=105 \\ Num\text{ber of squirrels after one year}=98 \\ change\text{ in number of squirrels in a year}=105-98=7 \\ chan\text{ge in diseased oak trees}=y-4 \end{gathered}[/tex]STEP 2: Calculate the rate of decay (k)
[tex]\begin{gathered} rate\text{ of decay\lparen k\rparen}=\frac{Final\text{ population-Initial population}}{initial\text{ population}} \\ \text{By substitution,} \\ k=\frac{98-105}{105}=\frac{-7}{105}=-0.06666666\approx-0.0667 \end{gathered}[/tex]STEP 3: Calculate the number of squirrels after 15 years
[tex]\begin{gathered} A=a_0e^{kt} \\ a_0=105 \\ k=-0.0667 \\ t=15 \end{gathered}[/tex]By substitution,
[tex]A=105\cdot e^{-0.0667\times15}[/tex]By simplification,
[tex]\begin{gathered} \mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b} \\ =105\times \frac{1}{e^{15\times \:0.0667}} \\ \mathrm{Multiply\:fractions}:\quad \:a\times \frac{b}{c}=\frac{a\:\times \:b}{c} \\ =\frac{1\times \:105}{e^{1.0005}} \\ \mathrm{Multiply\:the\:numbers:}\:1\times \:105=105 \\ =\frac{105}{e^{1.0005}} \\ e^{1.0005}=2.71964 \\ =\frac{105}{2.71964} \\ \mathrm{Divide\:the\:numbers:}\:\frac{105}{2.71964}=38.60803 \\ =38.60803 \end{gathered}[/tex]By approximation, this leaves us with 34 squirrels
Given the figure below, determine the angle that is a same side interior angle with respect to
Answers
We remember that two interior angles are those inside the are of the lines, Thus, the angles in the area:
Are interior. Now, we identify two sides, the right side, and the left side, which have been separated by the transversal line.
Thus, the angle that is is the same side as ∡3, and also that is interior is ∡5.
The figure below shows two parallel lines, k and f, cut by a transversal. What is the value of x?
A 25
B 35
C 45
D 65
Answers
Answer:
x=65 0r in other words D
Step-by-step explanation:
110=2x-20
+20 +20
130=2x
/2 /2
65=x
Darcy mounted a motion sensor so it would light a path to the door on her deck. If you know AB=10 feet, and BE and BD trident angle ABC, what is the perimeter of the deck area to the right of the beam of light ?PART 1: what others angles or sides of triangle BDC can you label given that side AB is 10 feet, BE and BD trisect angle ABC? Label the diagram accordingly, and explain your reasoning
Answers
Part 1
The labelled disgram is shown below.
We would apply the pythagorean theorem which is expressed as
hypotenuse^2 = one leg^2 + other leg^2
Considering triangle ABE
Sin 60 = 10/BE
BE = 10/Sin60 = 11.55
tan60 =10/AE
AE = 10/tan60 = 5.77
Part 1
Side DC of triangle BDC = 10 feet(opposite sides of a rectangle are congruent)
angle DBC = 30 degrees because BE and BD trisect angle ABC. 90/3 = 30
The sum of the angles in a triangle is 180 degrees. Thus,
angle DBC + angle DCB + angle BDC = 180
30 + 90 + angle BDC = 180
angle BDC = 180 = 180 - (30 + 90 = 180 - 120
angle BDC = 60
Sin 30 = CD/BD = 10/BD
BD = 10/Sin30
BD = 20
tan 30 = DC/BC = 10/BC
BC = 10/tan30
BC = 17.32
Perimeter of deck area to the right of the beam of light = perimeter of triangle BDC
= BD + DC + BC
= 20 + 10 + 17.32
Perimeter = 47.32 feet
Move the sliders h and k so that the graph of y = r2 gets shifted up 3 units and to the right 2 units. Then type the new function, f(t) in the answer box 3 2 1 4. بنا -2 0 1 2 3 f(x) -1 h = 0.00 -2 K = 0.00 о Don't forget to shift the graph. Using function notation, i.e. f(x) = , enter the function that results from the transformation.
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Given the graph of the function:
[tex]y=x^2[/tex]The graph will be shifted 3 units and to the right 2 units
So, the new vertex will be the point ( 2, 3 )
The new function will be:
[tex]f(x)=(x-2)^2+3[/tex]So, we will adjust the slider on the following values:
[tex]\begin{gathered} h=2 \\ k=3 \end{gathered}[/tex]Simplify and give answer as positive exponentkoa) x4. x-7xb)k4
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To simplify the expression, we need to use an exponent propertie
[tex]a^n\cdot a^m=a^{n+m}[/tex]Then, we can see that in this case a = x, n = 4 and m = -7
So now we must replace the values
[tex]x^4\cdot x^{-7}=x^{4-7}=x^{-3}[/tex]What is the value of f(-5) in the piecewise function -3x + 1 when x > 1 f(x) = -2x when x = 1 2x - 1 when x < 1
Answers
Answer:
f(-5)=-11
Explanation:
Given the piecewise function:
[tex]f(x)=\begin{cases}{-3x+1,\text{ when }x>1} \\ {-2x,\text{ when }x=1} \\ {2x-1,\text{ when }x<1}\end{cases}[/tex]We want to find the value of f(-5).
When x=-5:
[tex]\begin{gathered} -5<1\implies f(x)=2x-1 \\ \text{ Therefore:} \\ f(-5)=2(-5)-1 \\ =-10-1 \\ =-11 \end{gathered}[/tex]The value of f(-5) is -11.
The absolute value of 1/4
Answers
Answer: 1/4 is the absolute
Step-by-step explanation:
Answer:
1/4
Step-by-step explanation:
Absolute value just means the distance from zero.
I need help with solving residential plots and correlation vs causation how do I solve a liner model from the data ?
Answers
The image shows point that have a value that is close to zero, so they are small values
In the question, they say that those points represent the residual plot, that means that they represent the error of the linear model
The error is very small, close to zero
So the residual plot shows a non-random pattern, becuase all the point are close to zero
And then the date can be represented by a linear model
So the answer for the left box is "non-random"
And for the right box is "linear"
On the left box:..... non-random
On the right box...... linear