waves disturb a medium by causing the particles to_____.

1st image - B) Object position

2nd image - A) Focal length

3rd image - C) Image position

Answer:

this pdf should help you out

Explanation:

[tex]\text{Volume,}~V = 50 \times 25 \times 8 = 10000~ m^3\\\\\text{Density,}~\rho = 1.2 ~ kg ~m^{-3}\\ \\\\\text{We know that,}\\\\`~~~~~~~\rho = \dfrac{m}{V}\\\\\implies m = \rho V \\\\\implies m = 1.2 \times 10000 = 12000~kg}\\\\\text{Hence the mass of air is 12000 kg.}[/tex]

If the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

This states that

Now, given that a negatively charged plastic comb is brought close to, but does not touch, a small piece of paper. If the comb and the paper are attracted to each other the charge on the paper, this implies that both the negatively charged plastic comb and the paper have opposite charges.

Since the charge on the plastic comb is negative, this means that the charge on the paper must be positive

So, if the comb and the paper are attracted to each other the charge on the paper, is D)must be positive

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Answer:25

Explanation: because higher means less kinetic energ

Based on the data provided, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s.

The terminal velocity of a body is the velocity at which the body falls at constant velocity through a fluid.

For the falling raindrop, let positive direction be downwards and negative direction upwards,

The raindrop experiences a downward gravitational force mg, and an upward drag force -bv.

The total force at a time t is given as

a)

Terminal velocity is achieved then the total force is 0,

0 = mg - bv0

Therefore

b = mg/v0

Substitutingthe values:

b = (3 × 10^-5 × 9.8)/9

b = 3.27 × 10^-5 kg/s

b) Applying Newton's Second Law

F = ma

where

Therefore,

mg = mv/t t = v/g

however, t is at 63% velocity

thus:

t = 0.63v/g

t = 0.63 × 9 /9.8

t = 0.58 s

Therefore, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s

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Answer:

Matter

Explanation:

A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.

Answer:

energy

Explanation:

I took the test think of hydropower dams

Answer: 20 m/s

Explanation:

Acceleration = change in velocity / time → 10 m/s^2 = final velocity - 0 (original velocity) / 2s → final velocity = 20 m/s

Answer:

A) nucleus, ribosomes, and chloroplasts

B) mitochondria, cell wall, chloroplasts

D) cell membrane, ribosomes, small vacuoles

E) cell wall, central vacuole, and cell membrane

Explanation:

It cannot be C as the list features centrioles, which is an animal-cell only structure.

Answer:

Burning coal and boiling water are both chemical changes. Burning coal is a chemical change, and boiling water is a physical change. Burning coal is a physical change, and boiling water is a chemical change.

Explanation:

The material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.

Latent heat is defined as the thermal energy absorbed or released during a phase change of a substance.

Latent heat can also be explained as the energy in hidden form which is supplied or extracted to change the state of a substance without changing its temperature.

From the above explanation, we can conclude that, the material is at its phase change temperature and the thermal energy is going to change the phase instead of increase the temperature.

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If a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr. Details about average speed can be found below.

Average speed can be calculated by dividing the distance moved by a body by the time taken. That is;

Average speed = Distance/Time

According to this question, a jogger runs a 10 kilometer race in 60 minutes. The average speed is calculated as follows:

Average speed = 10km/1hr

Average speed = 10km/hr.

Therefore, if a jogger runs a 10 kilometer race in 60 minutes, her average speed is 10km/hr.

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The magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].

The magnitude of the force each plate experiences due to the other plate is determined as follows;

F = U/d

where;

[tex]F = \frac{1}{2} \frac{Q^2}{C} \times \frac{1}{d} \\\\[/tex]

Q = CV

[tex]F = \frac{1}{2} \frac{C^2V^2}{C d} = \frac{CV^2}{2d}[/tex]

where;

The capacitance is given as;

[tex]C = \frac{\varepsilon _o A }{d}[/tex]

[tex]F = \frac{\varepsilon _o A }{d} \times \frac{V^2}{2d} \\\\F = \frac{V^2 A \varepsilon _o }{2d^2}[/tex]

Thus, the magnitude of the force each plate experiences due to the other plate as a function of V, the potential drop across the capacitor is determined as [tex]\frac{V^2 A \varepsilon _o }{2d^2}[/tex].

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Answer:

D. Neither the box nor people will move.

Explanation:

We are given three forces that are present on the box and friction is the result of someone trying to move the box. The net force of the people pulling/pushing is barely 50 Newtons which doesn't compare with the frictional force of 400 Newtons, you will need to surpass a net force of 400 Newtons in order for the box to START moving.

Answer:

300N

Explanation:

in your drawing make sure to put 230n and 160n on the same side with arrows facing the same direction on the opposite side of the box add an arrow with 0n and an arrow to represent friction

Based on the findings above, the accurate statements are:

The information that all three institutions gathered is quite similar with their results showing a range of annual temperature deviation of 0.05°C in 2010.

However, this data is not enough to say that temperatures are rising gradually because there is no information on temperatures from the previous years.

Find out more on annual temperatures at https://brainly.com/question/27043563.

Hi there!

Part 1:

According to Newton's Third Law, every action has an EQUAL and OPPOSITE reaction.

For a collision, the objects involved exert an EQUAL and OPPOSITE impulse on each other, which means the forces exerted are equal as well.

Therefore, the school bus and Toyota Prius exert an EQUAL FORCE on each other.

Part 2:
The school bus has a greater mass.

Part 3:

Using Newton's Second Law:
[tex]\Sigma F = ma[/tex]

Using this relationship, the smaller the mass, the larger the acceleration. Since the forces are EQUAL, the Toyota Prius will experience a larger acceleration because it has a smaller mass.

Answer:

did you get it done if not lmk I will help you out tomorrow when I get up

Answer:

In a series circuit, the same amount of current flows through all the components placed in it. On the other hand, in parallel circuits, the components are placed in parallel with each other due to which the circuit splits the current flow.

Answer:

Explanation:

Use that:

[tex]F=-\vec{\nabla}U(x,y)=-\left(\hat{i} \frac{\partial U}{\partial x}+\hat{j}\frac{\partial U}{\partial y}\right)=-11.6x\hat{i}+10.8y^{2}\hat{j}[/tex]

Then use the 2nd Newton's Law of Motion:

[tex]\vec{a}=\frac{\vec{F}}{m}=\frac{-11.6x\hat{i}+10.8y^{2}\hat{j}}{0.04}=-290x\hat{i}+270y^{2}\hat{j}[/tex]

At x = 0.3 and y = 0.6, we can find the acceleration as:

[tex]\vec{a}=-87\hat{i}+97.2\hat{j}[/tex] (in SI unit)

Then the magnitude of the acceleration on that point is:

[tex]a=\sqrt{(-87)^{2}+(97.2)^{2}}\approx 130.44[/tex] (SI Unit)

The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

⁻ΔP₁ = ΔP₂

ΔP₂ = m₂v₂ - m₂u₂

ΔP₂ = m₂(v₂ - u₂)

ΔP₂ = 3m₁(v₂ - u₂)

ΔP₂ = 3 x 3.8 x (1.7 - 0)

ΔP₂ = 19.38 kgm/s

Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.

The complete question is beblow

A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.

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Answer:

Fundamental quantities are quantities that were created to measure a object/substance which are the basis on which derived quantities are formed, where as derived quantities are created by extracting variables from the fundamental quantities.

Answer:

(A) 0.8 kgm/s

Explanation:

because of the even ground it would only slow down

Answer:

m = 4.5 kg

Explanation:

w = - 1800 j

Fd = - 1800 j

mgd = - 1800 j

m = - 1800 ÷(gd)

m = - 1800 ÷( 10×-40)

m = 4.5 kg

Answer:

a

Explanation:

Distance is simply the distance travelled which in this case would be 4km + 3km = 7km

To work out displacement, try to imagine the situation.

Draw a straight line to the east (label it 3) and then draw another line from the end of the first line upwards (label this one 4). Thus, you've created a right angles triangle. Now use pythagorean theorem to work out the displacement

4^2 + 3^2 = 25

sqrt 25 = 5 = displacement

All of the following are examples of physical properties except tearing.

This is used to describe the state of a physical system and is usually measurable.

Examples include:

Tearing isn't an example of a physical property which was why option A was chosen as the most appropriate choice.

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Hello!

We know that at the BOTTOM of the pendulum's trajectory, the bob has a maximum speed. This means that its KINETIC ENERGY is at a maximum, while its Gravitational POTENTIAL ENERGY is at a minimum.

On the other hand, when the bob is at its highest points, the bob has a velocity of 0 m/s, so its KE is at a minimum and its PE is at a maximum.

We can use the work-energy theorem to solve. Let the Initial Energy equal the bob's energy at one of the sides, while the final Energy equals the bob's energy at the bottom.

[tex]E_i = E_f\\\\PE = KE[/tex]

Recall that:
PE = mgh

m = mass (kg)

g = acceleration due to gravity (m/s²)

h = height (m)

KE = 1/2mv²

m = mass (kg)

v = velocity (m/s)

Set the two equal and solve for 'h'.

[tex]mgh = \frac{1}{2}mv^2[/tex]

Cancel mass.

[tex]gh = \frac{1}{2}v^2[/tex]

Solve for 'h'.

[tex]h = \frac{v^2}{2g}\\\\h = \frac{3^2}{2(9.8)} = \boxed{0.459 m}[/tex]