What fraction equals 15/21 with a denominator of 7

Answer:

Step-by-step explanation:

Answer:

Truly, it's all of the above!

Answer:

60 yards

Step-by-step explanation:

300 = 2(30 + w) + 2(w)

300 = 60 +2w + 2w

300 = 60 + 4w

240 = 4w

60 = w

hich graph shows Point P as (–5,6) and Point Q as (3,–4)?

Answer:

Step-by-step explanation

RHS = cos 105° + cos 15°

         = cos (90° + 15°) + cos (90° – 75°)  

         = – sin 15° + sin 75°

         = sin 75° – sin 15°

          = LHS

Answer:

Step-by-step explanation:

sin75-sin15

=sin (90-15)-(-cos (90+15))

=cos 15+cos 105

Answer:

50 percent the cost of meals

Answer:

4/6

Step-by-step explanation:

ok so you have 2/3 for 1 group. so for 2 groups youll just have to add 2/3 + 2/3 and that gives u 4/6

Answer: 8.26

Step-by-step explanation:

Should I Explain How I got it?

132.16 divided by 16 is equal to 8.26.

Here, we have,

given that,

132.16 divided by 16

so, we have, 132.16 ÷ 16

To find the quotient of 132.16 divided by 16,

we can perform long division:

    8.26

____________

16 | 132.16

112

____________

20

Therefore, 132.16 divided by 16 is equal to 8.26.

To learn more on division click:

brainly.com/question/21416852

#SPJ6

Answer:

d x 7 = 105

Step-by-step explanation:

Answer:

Step-by-step explanation:

        3x − y = 9

           +3x − y = +9

Therefore, the answers are:

Hoped this helped.

[tex]BrainaicUser1357[/tex]

Answer:

c 146.7

Step-by-step explanation:

cuz

Answer:

thanks haahhahahaha

Step-by-step explanation:

[tex]f(x) = ab^x~\hfill \begin{array}{llll}\textit{we know that}~f(0)=-4\begin{cases}x=0\\f(x)=-4\end{cases}\\\\-4=ab^0\implies -4=a(1)\implies -4=a\end{array}\\\\\\\stackrel{therefore}{f(x)=-4b^x}~\hfill \textit{we also know that}~f(-2)=-64\begin{cases}x=-2\\f(x)=-64\end{cases}[/tex]

[tex]-64=-4b^{-2}\implies \cfrac{-64}{-4}=b^{-2}\implies 16=b^{-2}\implies 16=\cfrac{1}{b^2} \\\\\\ b^2=\cfrac{1}{16}\implies b=\sqrt{\cfrac{1}{16}}\implies b = \cfrac{\sqrt{1}}{\sqrt{16}}\implies b = \cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill f(x)=-4\left( \frac{1}{4} \right)^x~\hfill[/tex]

Answer:

33

Step-by-step explanation:

16-5=11

11×3=33

so yeah

Answer:

18

Step-by-step explanation:

Answer:

89) no 90) yes 91) yes 92) yes 93) yes

Step-by-step explanation:

use theorem of Triangle Inequality !! "the sum of two sides of a triangle must be greater than the third side" :)

Answer:

I think is there answer is 26.606

Answer:

y = 2x + -3

Step-by-step explanation:

Use the equation y=mx+b

m is the slope (2 in this case)

b is the y intercept (-3 in this case)

The equation of the line would be y = 2x + -3

Answer is -4

Step-by-step explanation:

8x-4< -36

8x < -36+4 (move [- 4] to the other side to find x)

8x < -32

8x < -4

Answer:

x < -4

Step-by-step explanation:

8x - 4 < -36

+4           +4 (Add 4 on both sides)

8x < -32

/8      /8        (Divide by 8 on both sides)

x < -4

Answer:

A. sec =12/13×

B. COS =12/13×

C. tan =12/5✓

D. sin =12/13 ✓

Step-by-step explanation:

we know,

using Pythagoras formula,

p=12,h=13 ,b=?

h^2 =p^2 +b^2

b=5

so tan = p/b

=12/5

sin=p/h and cosec= h/p

D. sin =12/13

Answer:

Step-by-step explanation:

Freddie rate of mowing=3/2=1.5 lawns /hr.

Tom's rate of mowimg=2 lawns/hr

so Tom can mow Smith's lawn faster.

Answer:

1003

Step-by-step explanation:

The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.

The simplest form of a telescoping product[tex]a_{k} \ = \ \displaystyle\frac{t_{k}}{t_{k+1}}[/tex], in which the products of n terms is

[tex]a_{1} \ \times \ a_{2} \ \times \ a_{3} \ \times \ \cdots \times \ a_{n-1} \ \times \ a_{n} \ = \ \displaystyle\frac{t_{1}}{t_{2}} \ \times \ \displaystyle\frac{t_{2}}{t_{3}} \ \times \ \displaystyle\frac{t_{3}}{t_{4}} \ \times \ \cdots \ \times \ \displaystyle\frac{t_{n-1}}{t_{n}} \ \times \ \displaystyle\frac{t_{n}}{t_{n+1}} \\ \\ \-\hspace{5.55cm} = \ \displaystyle\frac{t_{1}}{t_{n+1}}.[/tex].

In this particular case, [tex]t_{1} \ = \ 2[/tex] , [tex]t_{2} \ = \ 3[/tex], [tex]t_{3} \ = \ 4[/tex], ..... , in which each term follows a recursive formula of [tex]t_{n+1} \ = \ t_{n} \ + \ 1[/tex]. Therefore,

[tex]\displaystyle\frac{t_{2}}{t_{1}} \times \displaystyle\frac{t_{3}}{t_{2}} \times \displaystyle\frac{t_{4}}{t_{3}} \times \cdots \times \displaystyle\frac{t_{n}}{t_{n-1}} \times \displaystyle\frac{t_{n+1}}{t_{n}} \ = \ \displaystyle\frac{3}{2} \times \displaystyle\frac{4}{3} \times \displaystyle\frac{5}{4} \times \cdots \times \displaystyle\frac{2005}{2004} \times \displaystyle\frac{2006}{2005} \\ \\ \-\hspace{5.95cm} = \ \displaystyle\frac{2006}{2} \\ \\ \-\hspace{5.95cm} = 1003[/tex]

Answer:

15)alternate exterior, 16) corresponding angles 17) alternate exterior 18) same side interior

19) alternate interior

Answer:

undefined.......it's infinity

Answer:

The answer which I think is 3_4

Answer:

4 seconds

Step-by-step explanation:

Since we want to know the time when the height is 0, we can rewrite the problem as [tex]0=-2t^2+2t+24[/tex]. From there, we can plug it into the quadratic formula, which gives us [tex]\frac{-2-\sqrt{4-4(-2)(24)} }{2(-2)}[/tex](Since it's a real-world problem and we have a negative denominator, we won't be using the positive square root). We simplify this to get [tex]\frac{-2-\sqrt{196} }{-4}[/tex], then [tex]\frac{-2-14}{-4}[/tex]. Finally, we can calculate this to be 4 seconds.

Answer:

42

Step-by-step explanation:

Answer:

61 campers will focus on hockey.

Step-by-step explanation:

86+53=139

139-200=61

Answer:

Take the absolute value of -17.5

Step-by-step explanation:

Answer:

2. Take the absolute value of ' - 17. 5 '

Step by Step Explanation:

The distance/length is always positive, so make sure to take the absolute value of -17.5

Answer:

4a(3a+5)

We take H.C.F of both number and the variables then we compare the HCF number and variable with our question and equate and write the answer about how much should be multiplied from the H.C.F answer to get the question.