What fraction of an hour is 21 minutes in simplest form

Answer:

3

Step-by-step explanation:

3.45x+2*1.65+5>=20

3.45x+8.3>=20

3.45x>=11.7

after rounding

x>=3

Answer:

i believe the and\swe is g because it is located within the boundaries of plane p but is on a line (not the green segments) that goes outside of plane p

Step-by-step explanation:

Pascal's triangle up to the 7th row (starting with 0)

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

1 7 21 35 35 21 7 1

Then the 6th term in the expansion of (x + 5)⁷ is

7 • x¹ • 5⁶ = 109375x

Answer:

Step-by-step explanation: its b

Answer:

ninth grade teacher is going   skipping 30  to each class

Step-by-step explanation:

Answer:

-4 I believe is the answer

Step-by-step explanation:

Hope this helps:)

Answer:

9 months

Step-by-step explanation:

99 + 40 + 40 + 40 + 40 + 40 + 40 + 40 + 40 + 40 = $459

We can see that the number of 40's has been repeated 9 times. So therefore, 9 months is our answer.

Answer:

x=16/15

Step-by-step explanation:

Answer:

77.14L

Step-by-step explanation:

20.3x3.8=77.14L

Answer:

1/7

Step-by-step explanation:

4-3/7

1/7

Hope This Helps You.

Answer:

3 4/7

Step-by-step explanation:

Regroup 4 as 3 7/7.

Subtract 3 7/7 - 3/7 = 3 4/7

There's your answer!

please mark brainliest!

Answer:

70

Step-by-step explanation:

First you want to find the amount of x per 1 y so you divide 21 by 3 to get when x = 7 y = 1. Now you can just multiply 10 by 7 to get 70.

I hope this helps!

Answer:

y = -2x-1

Step-by-step explanation:

The formula for a line is [tex]y-y_{1} = m(x-x_{1})[/tex].

Plug in the information given in the problem: y-(-7) = -2(x-3)

So you get y+7 = -2x+6.

The final form you want needs to be equal to y (that means you want y by itself on the left side of the equals), so subtract 7 from both sides.  

You get y = -2x-1

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{-7})~\hspace{10em} m = -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-2}(x-\stackrel{x_1}{3}) \\\\\\ y+7=-2x+6\implies \blacktriangleright y=-2x-1 \blacktriangleleft[/tex]

Answer:

Where is the problem?

Step-by-step explanation:

Answer:

x = 0

Step-by-step explanation:

[tex]\frac{3}{2}(\frac{7}{3}x + 1) = \frac{3}{2}[/tex]

To start, let's multiply each side by the reciprocal of [tex]\frac{3}{2}[/tex].  Multiplying a fraction by its reciprocal gives us 1, which will make the left side of our equation simpler.

[tex]\frac{2}3} * \frac{3}{2}(\frac{7}{3}x + 1) = \frac{2}3} * \frac{3}{2}[/tex]

[tex]\frac{2}{3} * \frac{3}{2} = 1[/tex], so we have:

[tex]1(\frac{7}{3}x + 1) = 1[/tex] or [tex]\frac{7}{3}x + 1= 1[/tex]

Next, we can subtract 1 from both sides to further simplify the left side:

[tex]\frac{7}{3}x + 1 - 1= 1 - 1\\\frac{7}{3}x=0[/tex]

Finally, we can multiply by the reciprocal of [tex]\frac{7}{3}[/tex] on both sides in order to isolate x on the left.  Anything multiplied by 0 = 0, so now we have:

x = 0

7/2x + 3/2 = 3/2 <=> 7/2x = 0 <=> x=0

The demand is decreasing at the rate of 2units per week.

Given the price p (in dollars) and the demand x (in thousands of units) of a commodity satisfy the demand equation 6p+x+xp=94

Differentiating the function with respect to time will result in;

[tex]6\frac{dp}{dt}+\frac{dx}{dt} + x \frac{dp}{dt} + p\frac{dx}{dt} = 0[/tex]

Given the following paramters

p = $6

dp/dt = $2/wk

Substitute the given parameters into the formula to have:

[tex]6(2)+\frac{dx}{dt} + 2x + 9\frac{dx}{dt} = 0[/tex]

To get the demand x, we will simply substitute  p = 9 into the expression to have:

6(9)+x+9x=94

10x+54 = 94

10x = 94 - 54

10x = 40

x = 4

Substitute x = 4 into the derivative to have:

[tex]6(2)+\frac{dx}{dt} + 2x + 9\frac{dx}{dt} = 0\\6(2)+\frac{dx}{dt} + 2(4) + 9\frac{dx}{dt} = 0\\6(2)+\frac{dx}{dt} + 8 + 9\frac{dx}{dt} = 0\\20 + 10\frac{dx}{dt} =0\\10\frac{dx}{dt} =-20\\\frac{dx}{dt} =\frac{-20}{10}\\\frac{dx}{dt} =-\$2/wk[/tex]

Hence the demand is decreasing at the rate of 2units per week.

Learn more here: https://brainly.com/question/11859175

Answer:

True

Explanation:

3 feet is 1 yard so 13/3 is 4.3 yards approximately

True

[tex] \frac{1 \: yard}{3 \: feet} = \frac{x \: yard}{13 \: feet} [/tex]

3x = 13

[tex]x = \frac{13}{3} yards[/tex]

Step-by-step explanation:

Note: I'm only providing solutions for Problem 9.

Combining like terms involve performing the required mathematical operations (using the PEMDAS rule).  The terms must have the same degree (or exponents).  

Add the coefficients of both terms.  

3a + 7a  = 10a

Add the coefficients of both terms.  

4n + 3n = 7n

Subtract the coefficient of both terms.  

12y - 4y = 8y

Add the coefficients of all terms.  

5x + 2x + 4x = 11x  

The last term, "ba," can be rewritten as, "ab."  Remember that with algebraic expressions such as "ab," it essentially involves multiplication of both variables within the same term. Thus, ab = a × b. The variables ab also have a numerical coefficient of 1:  1a × 1b.

Now, we can perform the subtraction on all terms:

6ab - 2ab - ab = 3ab.  

Subtract 2mn from 2mn, which leaves you with 7mn:

7mn + 2mn - 2mn = 7mn  

For this algebraic expression, you could only combine the terms with the same variable and degree. Therefore, you'll have to subtract 3y from 4y, leaving the constant, 8, unaffected.  

4y - 3y + 8 = y + 8

Similar to question g, only combine the terms with the same degree and variable, leaving the constant unaffected.

7x + 5 - 4x = 3x + 5

You could only combine the terms with the same set of variables and degree, which are the first two terms on this given question. You cannot combine the last term, 4y, into the other terms.  

6xy + xy + 4y = 7xy + 4y

Using the same reasoning as in question e: the last term, 7ba, can be rewritten as 7ab, for which you could combine with the first term, 5ab.

5ab + 3 + 7ba = 12ab + 3  

Combine the like terms, which are the second and the last term.  

2 - 5m - m = 2 - 6m

Combine the like terms, which are the second and the last term.  

4 - 2x + x = 4 - x  

Answer:

1  C

2  A

Step-by-step explanation:

1 C No it cannot be defined because A and B are not congruent

2  A Yes, the lines will remain parallel

PS. It's only 50 points because two answers are allowed. Each answerer gets half.

Step-by-step explanation:

Avg = 20 + 14 + 28 + 18 /4

Avg = 80/4 = 20

Answer:

Infinity probally. But there is a number called the god's number reported by Galileo in which he states a number in which the enitre universe fits.

Answer:

5/6+1/8 = 23/24

Step-by-step explanation:

The lowest common denominator here is the smallest denominator that can be divided evenly by both 6 and 8.  It is 24.  Note that 6 = 2·3 and that 8 = 2·2².  We use the factors 2³ and 3 to come up with the LCD 24.

Then 5/6 + 1/8 can be rewritten with this LCD as:

20/24 + 3/24 = 23/24

5/6+1/8 = 23/24

let's recall that the conjugate of say a + b is simply the same thing with a different sign in between, namely a - b, so let's use the conjugate of the denominator and multiply top and bottom by it.

[tex]\textit{difference of squares} \\\\ (a-b)(a+b) = a^2-b^2 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{4+\sqrt{2}}{2-\sqrt{2}}\cdot \cfrac{2+\sqrt{2}}{2+\sqrt{2}}\implies \cfrac{(4+\sqrt{2})(2+\sqrt{2})}{\underset{\textit{difference of squares}}{(2-\sqrt{2})(2+\sqrt{2})}}\implies \cfrac{(4+\sqrt{2})(2+\sqrt{2})}{2^2-(\sqrt{2})^2}[/tex]

[tex]\cfrac{8+4\sqrt{2}+2\sqrt{2}+(\sqrt{2})^2}{4-2}\implies \cfrac{8+4\sqrt{2}+2\sqrt{2}+2}{2}\implies \cfrac{10+6\sqrt{2}}{2} \\\\\\ \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(5+3\sqrt{2})}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \boxed{5+3\sqrt{2}}[/tex]

Answer:

20

Step-by-step explanation:

9+9+2​=20

Hope this helps :)

Answer: 20

Step-by-step explanation:9x2=18 +2=20 or 9+9=18+2=20

Answer:

19

Step-by-step explanation:

Note that

[tex]\dfrac{10a}{b+c} + \dfrac{10b}{a+c} + \dfrac{10c}{a+b} = 10\left(\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b} \right)[/tex]

and

[tex]\dfrac{7-b-c}{b+c}+\dfrac{7-a-c}{a+c}+\dfrac{7-a-b}{a+b}=\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b}[/tex]

from [tex]a+b+c=7 \implies a=7-bc; b = 7-a-c; c = 7-a-b[/tex]

and

[tex]\dfrac{7-b-c}{b+c}+\dfrac{7-a-c}{a+c}+\dfrac{7-a-b}{a+b} = 7\left(\dfrac{1}{a+b}+\dfrac{1}{b+c}+\dfrac{1}{a+c}\right)-3[/tex]

because it is not difficult to note that

[tex]$\sum \dfrac a{b+c}=\dfrac a{b+c}+\dfrac b{c+a}+\dfrac c{a+b}$[/tex]

Therefore,

[tex]7\left(\dfrac{7}{10}\right)-3 = \dfrac{49}{10}-3 =\boxed{ \dfrac{19}{10}} = \dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b}[/tex]

Finally,

[tex]10\left(\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b} \right) = 10 \cdot \dfrac{19}{10} = 19[/tex]