What is angle q in the triangle that is shown below? Side x =
66.1 cm, side y = 22.8 cm, and angle f = 23.3º.
Please round your answer to one decimal place.

On solving the linear equation y = 3/2x - 29, the missing value for x is obtained as 14.66.

What is a linear equation?

A linear equation is one that has a degree of 1 as its maximum value. No variable in a linear equation, thus, has an exponent greater than 1. A linear equation's graph will always be a straight line.

The table shows the points (18,-2) and (16,-5).

The slope-intercept form of an equation/function is - y = mx + b

To find the slope m use the formula -

(y2 - y1)/(x2 - x1)

Substituting the values in the equation -

[-5 - (-2)]/[16 - 18]

(-5 + 2)/(-2)

-3/-2

3/2

So, the slope point is obtained as m = 3/2.

The equation becomes - y = 3/2x + b

To find the value of b substitute the values of x and y in the equation -

-2 = 3/2(18) + b

-2 = 27 + b

b = -2 - 27

b = -29

So, the value for b is -29.

Now, the equation becomes -

y = 3/2x - 29

To find the missing value substitute the value of  y = -7 in the equation -

-7 = 3/2x - 29

3/2x = -7 + 29

3/2x = 22

x = 22 × 2/3

x = 44/3

x = 14.66

Therefore, the value of x = 14.66.

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Answer:

3. f

4. b

5. a, x

Step-by-step explanation:

3.

a/f = f/c

f² = ac

f = √ac

Answer: f

4.

x/b = b/c

b² = cx

b = √cx

Answer: b

5.

x/k = k/a

k² = ax

k = √ax

Answer: a, x

Answer: The answer is 3

Step-by-step explanation:

The coordinates of point p along the directed line segment ab are [tex]$p(-1,-2)$[/tex]

Let the coordinates of point p be (x,y)

The ratio of ap to pb is 2 to 6, so we have [tex]$$\frac{|ap|}{|pb|} = \frac{2}{6}$$[/tex]

We can calculate the distances between points $a$ and $p$ and points $p$ and $b$ using the distance formula as follows:

[tex]$$|ap| = \sqrt{(x+3)^2+(y-2)^2}$$$$|pb| = \sqrt{(5-x)^2+(y+4)^2}$$[/tex]

We can use the ratio of the distances to set up a proportion to solve for $x$ and $y$:

[tex]$$\frac{|ap|}{|pb|} = \frac{2}{6} \implies \frac{\sqrt{(x+3)^2+(y-2)^2}}{\sqrt{(5-x)^2+(y+4)^2}} = \frac{2}{6}$$\\[/tex]

Solving for $x$ and $y$, we get $x = -1$ and $y = -2$.

Therefore, the coordinates of point $p$ along the directed line segment $ab$ are [tex]$p(-1,-2)$[/tex]

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$52 hundred is introduced to the December 31, 20Y6.

A proportion is a unit of fairness possession in the capital inventory of a corporation, and may discuss with devices of mutual funds, restrained partnerships, and actual property funding trusts. Share capital refers to all the stocks of an enterprise. The proprietor of stocks in a employer is a shareholder (or stockholder) of the corporation.

Note that proportion is an indivisible unit of capital, expressing the possession dating among the employer and the shareholder.

Given that bond indenture for the 10-year, 9% debenture bonds issued January 2, 20Y5, required working capital of $100,000, a current ratio of 1.5, and a quick ratio of 1.0 at the end of each calendar year until the bonds mature.

The profits acquired from the possession of stocks is a dividend. There are extraordinary varieties of stocks consisting of fairness stocks, bonus stocks, proper stocks, and worker inventory choice plan stocks.

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The perimeter of a rectangle is 700 feet. A quadratic function for its area in terms of its width is A(w) = 350w - w²

The formula for the perimeter of a rectangle is given by:

p = 2w + 2l

While its area is:

A = w x l

Where:

w = width

l = length

Substitute p = 700 ft.,

700 = 2w + 2l

700 = 2(w + l)

w + l = 350

l = 350 - w

Substitute l = 350 - w into the formula of area:

A = w x l

A = w (350 - w)

A(w) = 350w - w²

Hence, the expression is: A(w) = 350w - w²

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The number of papers that Ms. Motley will grade in five days would be = 46 papers (approximately).

The number of papers Ms. Motley graded in first day = 9 papers

The number of papers Ms. Motley graded in the second day = 27 papers

The number of papers Ms. Motley graded in the third day = 31 papers

The average number of she graded for the three days is calculated as follows;

9+27+31 = 67/3 = 27.3 papers.

If in 3 days = 27.3 papers

5. days = X papers

Make X papers the subject of formula;

X papers = 5× 27.3/3

= 136.5/3

= 45.5 papers

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The decision rule given is x1 + x3 – 10 ≥ 0, which can be rearranged to x1 + x3 ≥ 10. This forms a line in the R2 space, and any point on or above this line will be classified as 1, while any point below this line will be classified as 0.

To draw the decision boundary, we can plot the line x1 + x3 = 10 on a graph with the x1 and x3 axes. The region above the line, where x1 + x3 ≥ 10, would be shaded to indicate that it is where the classifier predicts 1.

It is important to note that the classifier predicts 1 if x1 + x3 – 10 ≥ 0, but in the explanation above I have used x1 + x3 = 10 to draw the decision boundary, this is because x1 + x3 – 10 ≥ 0 is equivalent to x1 + x3 ≥ 10.

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Answer: 13:6

Ratio of length to width = 39:18

Divide both by 3 to simplify

13:6

Answer:

The value of z can be found using the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all three sides of the triangle. In other words, if a, b, and c are the lengths of the sides of a triangle opposite angles A, B, and C, respectively, and A, B, and C are the angles opposite sides a, b, and c, respectively, then: a/sin(A) = b/sin(B) = c/sin(C). This can be used to solve for the unknown side length.

The perimeter of the rectangle WXYZ is 96 cm.

Here we see that

WXYZ is a rectangle (given)

Therefore,

∠WZY = 90 = ∠WZS

Since JS is parallel to PZ and JP is parallel to SZ, we get

JPSZ as a rectangle. Similarly, PKWQ, SYMR, and XQRL are rectangles.

JS = PZ

or, JS = PW + WZ

or, JS = KQ + WZ

or, WZ = JS - KQ

or, WZ = 52 - 25

or, WZ = 27

The side of the rhombus PS is a diagonal of rectangle JSPZ

Therefore length of the diagonal PS = √(JP² + JS²)

= √(52² + 39²)

= 65 cm

Hence for PWKQ,

PK = √(PQ² - KQ²)

= √(65² - 25²)

= 60 cm

For triangles ΔPWQ and ΔSYR,

the corresponding sides are parallel to each other. Hence we can say that

PW/YR = WQ/SY = PQ/RS

Therefore,

60/SY = 65/65            [Since they are the sides of a rhombus]

or, SY = 60 cm

Now, SY = SZ + ZY

or, SY = JP + ZY               [Opposite sides of a rectangle are equal]

or, ZY = 60 - 39

or, ZY = 21

Hence the perimeter of WXYZ

2(length + width)

= 2(27 + 21)

= 96 cm

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Complete Question

Rhombus PQRS is inscribed in a rectangle JKLM, as shown. Segments PZ and XR are parallel to JM. Segments QW and YS are parallel to JK. If JP = 39 cm, JS = 52 cm, and KQ = 25 cm, what is the perimeter of rectangle WXYZ?

The equation of a line passing through the terminal point of a vector a and in the direction of vector b is  r = a + λb.

In math the equation of a straight line is y = m x + c

where m is the gradient and c is the height at which the line crosses the y -axis, also known as the y -intercept.

Here we need to find the equation of a line (or a set of lines) passing through the terminal point of a vector a and in the direction of vector b.

Based on the general form of the equation of the line, the vector form of the equation of a line passing through a point having a position vector a, and parallel to a vector line b is written as,

=> r = a + λb.

Where λ refers the constant term.

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The students expected to like soda are 324

from the question, we have the following parameters that can be used in our computation:

150 students out of a total of 800 students on campus did not like soda.

This means that

650 students out of a total of 800 students on campus like soda.

i.e. 800 - 150 = 650

When half of the students are considered, we have

Soda = 650/2

Evaluate

Soda = 325

Hence, the number of students is 325

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Given that IJ = 2, we know that IJ is the radius of the circle.

The area of the shaded sector is given as . Since the area of a sector is given by (angle of sector/360) * pi * r^2, we can set up the equation:

(x/360) * pi * 2^2 =

Solving for x:

x = (180/pi)*

We know that the arc JLK corresponds to the angle x, thus the length of JLK is (x/360)2pi*IJ = (x/180)*IJ * T = (180/pi) * T.

To find the slope of the line given the points (0,2) and (1,0), we can use the formula: m = (y2 - y1) / (x2 - x1).

m = (0 - 2) / (1 - 0) = -2

Using point-slope form, we can write the equation of the line as:

y - 2 = -2 (x - 0)

y = -2x + 2

To get the inequality we just need to change the equation to the inequality by replacing the equal sign with the inequality sign.

So the linear inequality for the points (0,2) and (1,0) is:

y >= -2x + 2

Answer: 7

Step-by-step explanation:

First, we need to prime factorize the number 189,

189 = 3 × 3 × 3 × 7 × m

From the factors we can see that there is no pair of same numbers for 7, so if we replace m with 7, we can get a perfect square.

Hence the answer is 7

The length of RV is 14, SV is 7, TP is 15 and VP is 10. The solution has been obtained using centroid theorem.

What is centroid theorem?

According to the centroid theorem, the centroid of a triangle is located at a distance of 2/3 between the vertex and the midpoint of the sides.

In the given figure, V is the centroid of the triangle

The medians RS and PT intersect at V.

Now, since V divides each median in the ratio 2:1, therefore,

⇒VT = 1/3 of PT

⇒PT = 3*VT

Since, VT=5

⇒PT = 15 = TP

So, VP = PT - VT

⇒VP = 15-5

⇒VP = 10

Similarly,

⇒RV = 2/3 of RS

Since, RS = 21, therefore,

⇒RV = 2/3 of 21

⇒RV = 14

So, SV = RS-RV

⇒SV = 23-14

⇒SV = 7

Hence, the length of RV is 14, SV is 7, TP is 15 and VP is 10.

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The complete question is attached below

The formula the ratio of the displacement thickness to the boundary layer thickness is u = δ / 2

The term displacement thickness is defined as the distance by which the body surface should be shifted in order to compensate for the reduction in mass flow rate on account of boundary layer formation.

Here we need to find the way to determine the ratio of the displacement thickness to the boundary layer thickness.

As we all know that the boundary layer thickness. ideal fluid viscous force is neglected but in actual viscous stresses are prominent within the boundary layer.

AS we all also know that when fluid flows past a solid body the fluid particles adhere to the boundary and the condition of no-slip occurs.

Here the term non-slip conditions means the velocity of the fluid at body surface will be same as the velocity of body.

Then it can be calculated by using the following formula,

=> u = δ / 2

Complete Question:

Here by using the equation  u/U = y/δ and to determine the ratio of the displacement thickness to the boundary layer thickness.

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Answer:111

Step-by-step explanation:

1111

The eastbound airplane has traveled 16 miles.

This can be determined using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

In this case, the distance the northbound airplane has traveled (12 miles) is one side of the triangle, the distance the eastbound airplane has traveled is the other side, and the distance between the two airplanes (20 miles) is the hypotenuse.

So, we can set up the equation as:

(distance eastbound airplane)^2 + 12^2 = 20^2

Solving for the distance eastbound airplane, we get:

distance eastbound airplane = sqrt(20^2 - 12^2) = sqrt(256 - 144) = sqrt(112) = 16 miles

Answer:

The area of a circle is pi multiplied by the radius squared (A = π r²)

The radius (r) is the distance from the center of the circle, to the edge of the circle.

Example:

if you have a circle with radius 2, the area would be:

r = 2

A = π (2)²

A = π(4)

A = 4π

Answer:

Area can be calculated by the formula = [tex]\pi r^{2}[/tex]

Step-by-step explanation:

We can calculate the area of a circle with the formula,

Area of Circle = [tex]\pi r^{2}[/tex]

Where r replicates the radius of the circle

A perimeter longer than 50 for any point, C satisfies the area requirement.

Consequently, we have a base-10 triangle whose area is 100. Since the area is equal to half the product of base and height, the object's height is then 20.

The next two sides. If one of the sides is exactly 20 inches tall (when it coincides with the height, forming a right triangle), the other side must be strictly greater than 20 inches tall (being the hypotenuse), in which case the perimeter must be greater than 50.

Alternately, both sides could be longer than 20 because neither side is a height. Once more, the perimeter exceeds 50.

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The full question

In a given plane, points A and B are 10 units apart. How many points C are there in the plane such that the perimeter of triangle ABC is 50 units and the area of triangle ABC is 100 square units?

The altitude of the second beetle above the first beetle when they are 72 cm apart horizontally is 14.4 cm.

In order to find the altitude of the second beetle, let x be the altitude of the second beetle above the first beetle.

The horizontal distance between the two beetles is 72 cm.

The first beetle moves twice as fast as the second beetle, so the vertical distance between them is 2x.

Therefore, the equation for the problem is:

3x + 2x = 72

5x = 72

x = 14.4 cm

Therefore, the altitude of the second beetle above the first beetle when they are 72 cm apart horizontally is 14.4 cm.

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The probability that 1 battery in a pack of 16 is defective is approximately 0.3706 or 37.06%.

The binomial model can be used to calculate the probability of a specific number of successful outcomes (in this case, defective batteries) in a fixed number of trials (in this case, 16 batteries) with a constant probability of success (in this case, 5%) for each trial.

The probability of 1 defective battery in a pack of 16 can be calculated using the formula:

P(X = 1) = (¹⁶C₁) × (0.05)¹ × (0.95)⁽¹⁶⁻¹⁾

where (¹⁶C₁) is the binomial coefficient, which is equal to 16.

So;

P(X = 1) = (¹⁶C₁) × (0.05)¹ × (0.95)⁽¹⁶⁻¹⁾

P(X = 1) = 16 × 0.05 × 0.95¹⁵

P(X = 1) = 0.3706

Therefore, the probability that 1 battery in a pack of 16 is defective is approximately 0.3706 or 37.06%.

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9 pounds of Chamomile tea needed  to make a mixture that costs $14.74 per pound

What is the solution to an equation?

In order to make the equation's equality true, the unknown variables must be given values as a solution. In other words, the definition of a solution is a value or set of values (one for each unknown) that, when used as a replacement for the unknowns, transforms the equation into equality.

let:

x pounds of Chamomile tea needed

Therefore,

18.10X + 12.22(12) = 14.74(12 + x)

18.10X + 146.64 = 176.88 +  14.74x

3.36X = 30.24

X = 9 pounds

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The probabilities for each type of blood are given as follows:

A probability is obtained as the division of the number of desired outcomes by the number of total outcomes.

The total number of people is given as follows:

22 + 20 + 6 + 2 = 50.

6 people have type B, hence the probability is given as follows:

6/50 = 0.12 = 12%.

2 people have type AB, hence the probability is given as follows:

2/50 = 0.04 = 4%.

8 people have either type B or type AB, hence the probability is given as follows:

8/50 = 0.16 = 16%.

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The expression for the simplified polynomial would be - x² - 10x - 24.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the polynomial ( x + 5 )² is subtracted from 1. The simplified polynomial can be written as:-

Polynomial = 1 - ( x + 5 )²

Polynomial = 1 - ( x² + 10x + 25 )

Polynomial = 1 - x² - 10x - 25

Polynomial = -x² - 10x - 24

Hence, the polynomial can be written as -x² - 10x - 24.

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Answer:

-9x + -3

Step-by-step explanation:

1. Primeiro, vamos penteinar SO prazoos que possuem um mesmamã variável, ou seja, -5x e -4x:

-5x - 4x

2.  Agora, vamos penteinar SO prazoos que possuem o mesmo coeficiente, ou seja, 1 e -4:

-5x - 4x + 1 -

4 3.  Por fim, vamos penteinar SO prazoos que possuem o mesmo coeficiente, ou seja, -4 e 1:

-5x - 4x + -4 + 1

No, new atoms are not created in a chemical reaction. Atoms are rearranged or combined to form new compounds. The total number of atoms before and after the reaction is the same. This is known as the law of conservation of mass.

The law of conservation of mass states that in a closed system, the total mass of the reactants (the substances before the reaction) is equal to the total mass of the products (the substances after the reaction). This means that the atoms present in the reactants must also be present in the products, but in different combinations or arrangements.

Therefore, It's important to note that in some reactions, atoms can be transformed into different forms, for example, a carbon atom can be transformed into a carbon dioxide molecule, but the mass of the atoms remains the same.

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