What is the equation for calculating the electrical force, Fe1, between two charges?

The overbalanced wheel with attached spokes is a weakness in the system that Bernard Leon and Jamie Metz invented in terms of energy inputs and outputs.

Therefore, we can say that the wheel is unbalanced. The wheel is designed to turn clockwise just after the weighted spoke reaches the top of the wheel, and the spoke flips outward to the right exerting the force downward toward the ground. Some energy will be lost from friction as the mechanism rubs on the inner spoke, and more energy will be lost when it transferred into sound and thermal energy. Perpetual motion machines are one of the most frequently proposed perpetual motion machines designed.

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Given,

The length is r=5.70 m

The tangential speed is r=9.10 m/s

The centripetal acceleration is:

The acceleration is:

The current in the loop will be 6.13 A.

The magnetic field is the area in and around a magnet that is subject to the effects of magnetism. We employ the magnetic field as a tool to describe the distribution of the magnetic force in the vicinity and inside something magnetic in nature.

According to the question,

Radius of loop,

r =5.5 cm or,

r  = 0.055 m                          

Earth's magnetic field,  = 0.7G = 0.7 × 10⁻⁴ T

Number of turns, N = 1

We know the relation,

B = µ₀ ×N×I/2r

B = [tex]B_{e\\}[/tex]

then,

[tex]B_{e\\}[/tex] = µ₀ ×N×I/2r

By substituting the values,

0.7 × 10⁻⁴ = 4π × 10⁻⁷×1 × I / 2× 0.055

hence,

The current will be

I = 2× 0.055 × 0.7 × 10⁻⁴/ 4π ×10⁻⁷×1

I = 6.13A

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The edge counter is 0.0060 meters or 0.60 cm far as they fall from the edge of the counter to the point at which the servers catch them.

Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. When stretched or squeezed, a spring has higher potential energy.

When lifted above the ground, a steel ball has more potential energy than when it is brought to rest on the ground. It is capable of performing more work in the increased position.

From the given data of the question,

x = v/t

t = x/v       (1)

y = -1/2gt²

Substitute value of t from (1)

y = -1/2 g(x/v)²

y = -1/2 (9.8)(0.70/2.0)²

y = 0.0060 meters, or,

y = 0.60 cm.

Therefore, it is 0.60 cm far from the edge of the counter.

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Answer:

The answer is the letter B

Explanation:

Because velocity is a vector quality since to define it is necessary to specify its size (equivalent to speed) and its direction and the letter B tells then velocity is a vector quality that tells the distance an object has traveled over a period of time.

I think than is the letter B

Velocity is a vector quantity that tells the distance an object has traveled over a period of time. So, option (B) is correct.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.

Hence, velocity is a vector quantity which can tell displacement of a body , that is, distance between initial and final position - which is equal to  from the distance an object has traveled over a period of time.

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The direction of the velocity of the clod of dirt relative to the truck just before it hits is in the same direction as that of the truck.

The direction of the velocity of the clod of dirt relative to the ground just before it hits is in the opposite direction as that of the ground.

The relative velocity of an object in motion is the velocity of that object when viewed from a reference point.

The direction of the velocity of the clod of dirt before it hits the ground is in the same direction as that of the truck.

However, compared to the ground, the direction of the relative velocity is in the opposite direction.

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The velocity of the swimmer relative to the shore is 2 m/s south by vector addition

What is vector addition ?

Vector addition means putting two or more vectors together. In the addition of vectors, we are adding two or more vectors using the addition operation in order to obtain a new vector that is equal to the sum of the vectors. Vector addition finds its application in physical quantities where vectors are used to represent velocity, displacement, and acceleration.

We can solve this problem by using vector addition.

In fact, we can take north as positive direction, and we can write the following:

vc = - 4m/s is the velocity of the current (which is negative, since it is south)

v s= +2m/s is the velocity of the swimmer (which is positive, since it is north)

Therefore, the velocity of the swimmer relative to the shore is

v = vs + vc = 2+(-4) = - 2m/s

And the negative sign means the direction is south, so the answer is

v = 2 m/s south

The velocity of the swimmer relative to the shore is 2 m/s south by vector addition

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The velocity of a body or object determines its direction of motion. Speed is a scalar quantity in its most fundamental form. Velocity is essentially a vector quantity. It is the rate of change in distance. The displacement change rate is the issue.

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

V = u + a*t

V = 2 + 0.20 * (2.5*60)

V = 32 m/s

The rate at which the speed and direction of a moving object change over time is known as acceleration. Something is said to be accelerating when it starts to move faster or slower. Motion on a circle accelerates even while the speed is constant because the direction is always changing. Due to the frequent change in direction, motion on a circle accelerates even while the speed is constant.

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Answer:

Resultant force of the given forces: approximately [tex]11.2\; {\rm N}[/tex] at approximately [tex]53^{\circ}[/tex] west of south.

Explanation:

The resultant force of these forces will be:

Refer to the diagram attached. The resultant [tex]5\; {\rm N}[/tex] force to the south and the [tex]10\; {\rm N}[/tex] force to the west are perpendicular to each other, forming the two legs of a right triangle. The hypotenuse of this right triangle will be the net effect of these two forces.

Apply Pythagorean's Theorem on this triangle to find the magnitude of this net effect:

[tex]\begin{aligned}(\text{length of hypotenuse}) &= \sqrt{10^{2} + 5^{2}} \approx 11.2\end{aligned}[/tex].

Hence, the magnitude of this net effect will be approximately [tex]11.2\; {\rm N}[/tex].

Let [tex]\theta[/tex] denote the angle between this resultant force and west. In this right triangle:

[tex]\begin{aligned} \tan(\theta) &= \frac{(\text{opposite})}{(\text{adjacent})} \\ &= \frac{5\; {\rm N}}{10\; {\rm N}} \\ &= \frac{1}{2}\end{aligned}[/tex].

[tex]\begin{aligned} \theta &= \arctan\left(\frac{1}{2}\right) \approx 27^{\circ}\end{aligned}[/tex].

Hence, the angle between this resultant force and south will be approximately [tex](90^{\circ} - 27^{\circ}) = 63^{\circ}[/tex]. This resultant force will be at approximately [tex]63^{\circ}[/tex] west of south.

Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm

What is Rotation speed ?

The rate at which the Aeroplan should begin rotating into takeoff attitude is known as V r.

V r, the rotational speed, cannot be lower than V1. A subsequent rejected takeoff may not be achievable within the remaining runway length and is likely to result in a Runway Excursion if it is more than V1 and it is discovered that, at V r, rotation cannot be completed.

V r depends on the weight of the aircraft and the flap position, but it can also change according on temperature, pressure, and altitude.

Gravitational acceleration = g = 9.8 m/s2

Diameter of the space station = D = 275 m

Radius of the space station = R

R = D/2

R = 275/2

R = 137.5 m

Angular speed of the space station = [tex]\omega (rad/s[/tex])

Centripetal acceleration at the outermost points = ac = g = 9.8 m/s2

ac = [tex]\omega2R\\[/tex]

9.8 =[tex]\omega2(137.5)[/tex]

[tex]\omega \\[/tex]= 0.267 rad/s

Converting from rad/s to rpm,   (1 revolution = [tex]2\pi radians[/tex] , 1 minute = 60 seconds)

\omega = 0.267 [tex]\times (\frac{60}{2\pi })[/tex]

\omega = 2.55 rpm

Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm

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The center of mass exists a position defined relative to an object or system of objects.

The proper significant figures and proper rounding of digits exists 2.603 m.

The unique location where the weighted relative position of the scattered mass adds to zero is known as the center of mass in physics. Here is where a force can be applied to produce a linear acceleration without also producing an angular acceleration.

A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.

Given:

Mass of car, m = 1150 kg

Distance, d = 2.35 m

The new position of center of mass will be:

[tex]$=\frac{1150 \times 2.35+160 \times 2.7+240 \times 3.75}{240+260+1150} \\[/tex]

simplifying the above equation, we get

= (2702.5 + 432 + 900) / 1650

= 4034.5 / 1650

= 2.603 m

Therefore, the proper significant figures and proper rounding of digits exists 2.603 m.

The complete question is:

The CM of an empty 1150 kg car is 2.35 m behind the front of the car. How far from the front of the car will the CM be when two people sit in the front seat 2.70 m from the front of the car, and three people sit in the back seat 3.75 m from the front? Assume that each person has a mass of 80.0 kg.

express answers in proper significant figures and proper rounding of digits.

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13a  value of the hanging mass does the block accelerate at 1.8 m/s2

For 8 kg mass,

m 1 g - T = m 1 a

8g - T = 8a —————(I)

For 5 kg mass,

T - m 2 g = m 2 a

T - 5g = 5a —————(II)

Adding both equations, we get

8g - 5g = 13a

The constant velocity of the body on the frictionless surface is represented by the frictionless surface acceleration. No net force on the moving object can stop it from going when the surface is frictionless. As a result, the body keeps moving at the same speed. The skater has no net acceleration if no forces are operating on him and he is on a frictionless surface. The acceleration must be zero since the skier must have mass. If there is no acceleration when an item is moving, its velocity stays constant.

We must understand that acceleration always occurs in areas where there is friction. There are several types of forces at work on moving objects.

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Answer:

The speedometer of a car reveals information about the instantaneous speed of your car. It shows your speed at a particular instant in time.

Explanation:

When 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in the temperature of the water is less than the change in temperature of the wood because the intermolecular forces in water are greater than those in wood.

Intermolecular forces are the forces of attraction that exist between the molecules of the same substance.

Intermolecular forces help to keep the molecules of a substance.

The stronger the intermolecular forces between molecules of a substance, the more heat energy it will require to separate the molecules of the substance.

The molecules of water have in addition to the covalent bond between the atoms of hydrogen, hydrogen bonds that exists between its molecules.

These intermolecular forces present in water are responsible for the high heat capacity of water.

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E1 = [tex]E_{f}[/tex]

[tex]\frac{-GMM}{2R}[/tex] = [tex]\frac{-GMM}{R}[/tex] + [tex]\frac{1}{2} mv^{2}[/tex]

= [tex]\frac{GMM}{2R}[/tex] = [tex]\frac{1}{2} mv^{2}[/tex]

V = [tex]\sqrt{GM/R[/tex]

By the law of conservation of energy, the initial potential energy, and the final kinetic energy are equal. When an object hits the ground, its kinetic energy is converted into heat and sound energy. Energy from motion is called kinetic energy. object in motion.

Both vertical and horizontal movement has kinetic energy. Kinetic energy depends on the mass and velocity of the object. The basic reason for the existence of halves in the kinetic energy formula actually comes from special relativity from a more complete version of the kinetic energy formula. Briefly, this ½mv2 kinetic energy formula can be viewed as an approximation of special relativity.

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Answer:

See below

Explanation:

Assuming no resistance

DISTANCE =  1/2 a t^2

443 = 1/2 (9.81)t^2      Shows t = 9.5 seconds

Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed", students were more likely to report that there was broken glass involved in the accident.

A verb is one of the parts of speech in English language and it can be defined as a type of word which is used to describe an action, occurrence, experience, or a state of existence such as, smashed, living, contacted, clean, drive, etc.

Speed can be defined as the distance covered by a physical object per unit of time. This ultimately implies that, the higher the speed of a car that is involved in a road crash or accident, the higher would be the level of impact and damage that would be caused.

In this context, we can reasonably infer and logically deduce that changing the verb from contacted to smashed, ultimately implies that the road crash or accident was ghastly and fatal and such would cause broken glasses in the cars that were involved.

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Complete Question:

Students were asked about the speed of cars involved in an accident. When the verb was changed from "contacted" to "smashed" ______,

students were more likely to report that there was broken glass involved in the accident

students were less likely to report that the cars were traveling at high speeds

students were more likely to report that no one was injured in the accident

there was no differences noted.

The speed of the stone at the bottom of the circle is 4.85 ms⁻¹.

Speed is the time fee at which an object is moving alongside a course, even as the pace is the charge and path of an object's movement. The rate of speed of the function of an object in any course.

velocity is measured because of the ratio of distance to the time in which the space became blanketed. the pace is a scalar amount because it has the most effective route and no magnitude. Speed is the time fee at which an object is moving alongside a path, while the pace is the fee and direction of an item's motion. put another way, the pace is a scalar value, whilst pace is a vector.

At the bottom position,

T - mg = Fc = mv²/r

∴ (T - mg/m)r = v²

V² = (3mg - mg ) r/ m = 2mgr/m

v = [tex]\sqrt{2gr}[/tex]

   = 4.85 ms⁻¹

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The correct answer is option C.

Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. The average intensity of Wave 1 is nine times the intensity of Wave 2.

By comparing the two electromagnetic waves, we get:

Maximum Electric Field Strength of Wave(1) = 3 x Maximum Electric Field Strength of Wave (2), i.e.

[tex]E_{1}[/tex]  = 3 x [tex]E_{2}[/tex]

Now comparing the average intensities of the two waves. we get [tex]\frac{I1}{I2}[/tex]

The average intensity of electromagnetic wave 1 can be expressed as:

[tex]I_{1}[/tex] = [tex]\frac{1}{2}[/tex] x ε0 x  [tex]E1^{2}[/tex] x c ------- (1)

Now, the average intensity of the electro-magnetic wave 2 can be expressed as:

[tex]I_{2}[/tex]  =  [tex]\frac{1}{2}[/tex] x ε0 x  [tex]E2^{2}[/tex]  x c -----(2)

Now comparing equations 1 and 2 we get.

[tex]\frac{I1}{I2}[/tex]  =   [tex]E1^{2}[/tex] /  [tex]E2^{2}[/tex]

[tex]\frac{I1}{I2}[/tex]  =  ( 3 x [tex]E2)^{2}[/tex]/  [tex]E2^{2}[/tex]

[tex]\frac{I1}{I2}[/tex]  = 9

Thus, we can say that the average intensity of Wave 1 is nine times the intensity of Wave 2.

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The complete question is:

Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of Wave 2. How do the average intensities of the waves compare?

a. The average intensity of Wave 1 is three times the intensity of Wave 2.

b. The average intensity of Wave 2 is three times the intensity of Wave 1.

c. The average intensity of Wave 1 is nine times the intensity of Wave 2.

d. The average intensity of Wave 2 is nine times the intensity of Wave 1.

The boy pushed the sled for 15 seconds. The Work-Energy theorem can be applied in circumstances when a rigid body must move while being subjected to several forces.

The Work - Energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

The Work-Energy theorem can be applied in circumstances when a rigid body must move while being subjected to several forces. A rigid body can only have kinetic energy because of its rigid structure, which prevents it from storing potential energy in its lattice.

The sled is initially at rest → initial velocity (u) = 0.

Final velocity (v) = 3.2 m/s

Mass of boy and sled (M) = 40 kg

Power developed (P) = 18 W = 18 Joules/sec

According to work - energy theorem -

Work done (W) = Δ E(K) = E(f) - E(i)

Therefore -

W=[tex](1/2*40*3.2*3.2-1/2*40*0)[/tex]=204 joule

Now, Power is defined as the rate of doing work -

P =[tex]pw/dt[/tex]= [tex]w/t[/tex]

18 = 204/t

t = 15 seconds

Hence, the boy pushed the sled for 15 seconds.

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The boy pushed the sled for 15 seconds.

The sled is initially at rest → initial velocity (u) = 0.

Final velocity (v) = 3.2 m/s

Mass of boy and sled (M) = 40 kg

Power developed (P) = 18 W = 18 Joules/sec

According to work - energy theorem -

Work done (W) = Δ E(K) = E(f) - E(i)

Therefore -

[tex]$$\mathrm{W}=(1 / 2 * 40 * 3.2 * 3.2-1 / 2 * 40 * 0)=204 \text { joule }$$[/tex]

Now, Power is defined as the rate of doing work -

[tex]&\mathrm{P}=p w / d t=w / t \\[/tex]

[tex]&18=204 / \mathrm{t} \\[/tex]

[tex]&\mathbf{t}=15 \text { seconds }[/tex]

Hence, the boy pushed the sled for 15 seconds.

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Answer:

Explanation:

 Given:

L  = 881.0  m

F = 28.0 N

___________

A - ?

The work :

A = L*F = 881.0 * 28.0 ≈ 24 670  J

The distance traveled by car A when they pass each other is 3278.2 ft.

The time taken for the two cars to meet each other is calculated by applying the concept of relative velocity.

(Va + Vb)t = d

where;

(74 + 56)t = 5760

130t = 5760

t = 5760/130

t = 44.3 s

The distance traveled by car A when they pass each other is calculated as follows;

da = 74 ft/s x 44.3 s

da = 3,278.2 ft

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Angle 32rad turn during that time if the angular accelaration is constant.

What is accelaration?

acceleration, rate at which the  velocity changes with time, in terms of both speed and the  direction. A point or else it's an  object moving in a straighten line is accelerated if it is  speeds up or slows down. Motion on a circle is the  accelerated even if the  speed is constant, because of  the direction is continually changing.

Sol-  In an uniformly accelerated circular motion, the angle traveled by the object is given by-

∆=wf+wo/2×t

Here  wf is the final angular speed .

It is the initial angular speed and t is the time of the motion. Replacing the given values-

∆= 12 rad/s + 4 rad/s /2 (4s)

∆= 32rad .

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The paths of motion of the planets, if the gravitational force of the sun were to suddenly disappear will be a straight line.

The orbits in which the planets revolve around the Sun is elliptical in shape. Johannes Kepler was the first to discover the elliptical shape of orbits which was called as Kepler's laws of planetary motion.

According to Newton's first law of motion, objects always move in straight paths unless acted upon by an external force. This means that removing the force of gravity would cause them to move a straight line tangential to the orbit that it was revolving about.

Therefore,

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The conclusion reached by the student who is most warranted is that the comet originates between the Sun and the asteroid belt.

Can humans survive on an aster?

The magnetic field and atmosphere that protect humans on Earth from harm are absent on asteroids. One approach to shield yourself from dangerous radiation is to live inside an asteroid. It is expected that humans would be sufficiently protected from radiation by excavating 100 meters beneath an asteroid.

How likely is it that an asteroid will strike Earth?

While space rocks of this size are most likely to reach Earth only about once every hundred million years, NEOs that are 50 to 100 meters (164 to 328 feet) broad have the potential to strike much more frequently—roughly every thousand years.

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Comets orbit the Sun in incredibly eccentric paths. They move in close proximity to the Sun from the outer solar system to the inner solar system via their orbits. Comets may have carried water and other materials to Earth through crashes early in the planet's history.

As the comet approaches the Sun, the outer ice layers melt and create a luminous coma, which causes comet tails to develop. This gas and dust are pushed into a long tail by particles streaming from the Sun. Always facing away from the Sun is the tail. The coma appears vivid because it reflects sunlight . Comets only briefly appear when they are close to the Sun. As they move, they appear to vanish.

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The time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.

Based on the given information,

• The air-track glider connected with a spring oscillates between the 10 cm mark and the 60 cm mark.  

• In 33 seconds, the glider completes 10 oscillations.  

Here we have to find the period, frequency,amplitude and maximum speed of glider.

The time period of one oscillation is 33s/10 = 3.3s

The frequency f is the reciprocal of the time period.

f= 1/T =1/3.3 S = 0.303 Hz

The amplitude A is

A = 1/2 (60cm - 10cm)

= 25cm

Maximum speed of glider is

V max = 2π/t (0.25m)

V max = 0.47575m/s

Thus,  time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.

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The correct answer are as follows

(i) 250 m is the maximum height

(ii) Time to reach the height is 5 s

(iii) Time of the flight is 10 s

(iv) Horizontal distance from the foot of the tower to point Q is 433 m

Given,  π°= stand as the angle= 30°

h= height= 100m

u= initial velocity= 100m/s

g= acceleration due to gravity= 10m/s²

(i) maximum height= h(max)= u²sin²π°/g

= 100²(sin30°)²/10

= 10000(0.25)/10

= 1000(0.25)

= 250m

height(max)= 250m

(ii)time it takes to reach the height= using π°/g

= 100sin30°/10

= 10 × 0.5

= 5

t= 5s

(iii)time of flight, T= 2t

T= 2(5)= 10

T= 10s

(iv)horizontal distance=H= u²cosπ°/2g

= 100²(cos 30°)/2(10)

= 10000(0.866)/20

= 500(0.866)

= 433

H ( distance)= 433m.

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After a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east, her total displacement is 5 blocks. While the total distance covered is 13 blocks.

A displacement is a vector in geometry and mechanics whose length is the smallest distance between the beginning and final positions of a moving point P.

If an item moves relative to a reference frame, such as a lecturer moving to the right of a whiteboard or a passenger moving toward the back of an airliner, the object's location changes. This shift in location is referred to as displacement.

Displacement (change in position) = Last position – initial position

To Calculate displacement, let displacement be (d)

d = -3i + 4j + 6i (-i because she turned west, +i because she turned east)

d = 3i + 4j

d = √(3² + 4²)

d = √(9 + 16)

d = √25

d = 5 blocks.

Total distance (Td_  = Sum of all the blocks traveled.

Td = 3 + 4 + 6

Td = 13 blocks.

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Answer:

see below

Explanation:

18.5 m in .46 sec  =  18.5 /.46 m/s  = 40.2 m/s

By measuring the recession velocities and therefore the distant galaxies and noticing that these parameters are intimately related to time. Option A.

Find the oldest stars, measure the expansion rate of the universe, and extrapolate back to the large Bang. a bit like a detective can trace the origin of a sphere through a hole in the wall.

Current measurements put the world at about 4.54 billion years old and therefore the universe at About 13.8 billion years. Scientists measure the dimensions of the universe in a myriad of different ways. they will measure ripples from the early universe known as baryonic acoustic oscillations that fill the cosmic microwave background. you'll also use a standard candle, like a Type 1A supernova, to live within distance.

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