Answer:
The equation of the line is;
[tex]y=-\frac{6}{5}x-8[/tex]Explanation:
Given the slope of the line as;
[tex]m=-\frac{6}{5}[/tex]And passes through point;
[tex](-5,-2)[/tex]Using the Point-slope equation to derive the equation of the line;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-2)=-\frac{6}{5}(x-(-5)) \\ y+2=-\frac{6}{5}(x+5) \end{gathered}[/tex]Simplifying;
[tex]\begin{gathered} y+2=-\frac{6}{5}x-\frac{6}{5}(5) \\ y+2=-\frac{6}{5}x-6 \\ y=-\frac{6}{5}x-6-2 \\ y=-\frac{6}{5}x-8 \end{gathered}[/tex]Therefore, the equation of the line is;
[tex]y=-\frac{6}{5}x-8[/tex]
Comparing Two Linear Functions (Context - Graphically)
start identifying the slope and y-intercept for each high school.
The slope represents the growth for each year, in this case for high school A is 25 and for high school B is 50.
The y-intercept is the number of students that are enrolled currently, in this case for A is 400 and for B is 250.
The complete equations in the slope-intercept form are
[tex]\begin{gathered} A=25x+400 \\ B=50x+250 \end{gathered}[/tex]Continue to graph the equations
High school B is projected to have more students in 8 years.
H +6g when 9=g and h=4
Hey there!
[tex]g+6g\\g=9,h=4[/tex]
[tex]4(h)+6(9(g))[/tex]
[tex]4+6(9)[/tex]
[tex]=58[/tex]
Hope this helps!
Decide whether the change is an increase or decrease and find the percent change. Original number = 45 New number = 18 Answer: 60% decrease 60% increase 150% increase 150% decrease
The percentage change can be found below
[tex]\begin{gathered} \text{percentage change = }\frac{\text{ new number}-\text{original number}}{\text{original number}}\times100 \\ \text{percentage change=}\frac{18-45}{45}\times100 \\ \text{percentage change}=-60 \\ \end{gathered}[/tex]Since the percentage is negative, this means there is a 60% decrease.
Boy earns 20.56 on Monday 32.90 on Tuesday and 20.78 on Wednesday he spends half what he earned during three days how much he have left
First, we need to calculate the total earned during the three days, so we need to sum 20.56, 32.90, and 20.78 as:
So, the total earned is 74.24, then half of 74.24 is calculated as:
[tex]\frac{74.24}{2}=37.12[/tex]If he spends the half, he has left the half. Therefore, he has left 37.12
Answer: 37.12
In a right triangle, the hypotenuse is the longest side?
Okay, here we have this:
The hypotenuse of a right triangle is always the side opposite the right angle. It is the longest side in a right triangle. The other two sides are called the opposite and adjacent sides.
This mean that the statement is true.
Which expressions represent a quadratic expression in factored form? Select all the correct answers.
x^2 − x − 72
(x + 3)(x − 7)
-8(x + 56)
(x + 1)(x − 2)
(x − 2) + (x + 3)
The expressions that represent a quadratic expression in factored form is (x + 1)(x − 2).
What is quadratic expression?Quadratic expression can be described as the mathematical expression that posses the variable which have highest power of 2.
It should be noted that the quadratic equation is usually expressed in the form ax^2 + bx + c where the abc are the known numbers in the equation that will be used in the calculation of the factors of the equation and in the quadratic equation the number a will not be equal to zero in the equation.
Therefore, option C is correct.
Read more about quadratic expression at:
https://brainly.com/question/1214333
#SPJ1
Please help me answer the following question with the picture below.
Answer:
9x+b
Step-by-step explanation:
29 graph in desmos and label points of inflection, critical points, local extremes, absolute extremes, asymptotes, etc
Given:
There are given the function:
[tex]f(x)=\frac{3x}{x^2-1}[/tex]Explanation:
According to the question:
We need to draw the graph of the given equation:
So,
The graph is:
vertical asymptotes are (-1,1)
And,
The horizontal asymptotes is
y = 0.
Which equation shows the commutative property? CLEAR SUBMIT (10+5) (30 + 6) = 15 x 36 36 x 15 = 15 X 36 (10 + 30) x (5 + 6) = 15 x 36 36 + 15 = 15 X 36
Explanation
The commutative property states that the numbers on which we operate can be moved or swapped from their position without making any difference to the answer. The property holds for Addition and Multiplication,hence
Let's check every option
Step 1
a)
[tex]\begin{gathered} (10+5)\cdot(30+6)=15\cdot36 \\ \end{gathered}[/tex]this does not show the commutative property
b)
[tex]\begin{gathered} 36\cdot15=15\cdot36 \\ \end{gathered}[/tex]as we can see the factor were moved, and by the commutative property the result is not afected, so
[tex]\begin{gathered} \\ 36\cdot15=15\cdot36 \end{gathered}[/tex]is the answer.
I hope this helps you
Cube A has a side length of 8 inches and cube B has a side length of 2 inches. What isthe ratio of the volumes of cube B to cube A?ABMath Bits.com8"2"O 16Submit AnswerOhO 30da
The ratio of the volume of cube B to the volume of cube A is 1/64
Explanation:The volume of cube A is 8^3 = 512 cubic inches
The volume if cube B is 2^3 = 8 cubic inches
The ratio of the volume of cube B to the volume of cube A is:
8/512 = 1/64
I have a bag, with some balls in it. All but four are blue, all but four are green, and all but four are red.
In total, how many balls are there in the bag?
===============================================
Explanation:
x = total number of balls
x-4 = number of blue
x-4 = number of green
x-4 = number of red
3(x-4) = 3x-12 = total number of blue, green, or red
x - (3x-12) = x-3x+12 = -2x+12 = number of other colors
If there are other colors, then we want this quantity to be larger than 0, so,
-2x+12 > 0
-2x > -12
x < -12/(-2)
x < 6
There are less than 6 balls in the bag.
At the same time, we want each x-4 to be greater than zero
x-4 > 0
x > 4
------------------
We found that x > 4 and x < 6
This combines to 4 < x < 6 which has us land on x = 5
This computes x-4 = 5-4 = 1, showing there's one of each blue, green and red. There are 5-1-1-1 = 2 balls of some other color not mentioned.
------------------
If x = 6, then,
x-4 = 2 each of blue, green and red
There wouldn't be any other color since 6-2-2-2 = 0
Given the special right triangle, find the value of x and y. Express your answer in simplest radical form.
b) A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown below:i) if two students are randomly selected, what is the probability that both of them are European (correct to 4 decimal places)ii) if one student is randomly selected, what is the probability that a student is not Asian. (correct to 4 decimal places)
Given:-
A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown.
To find if two students are randomly selected, what is the probability that both of them are European and if one student is randomly selected, what is the probability that a student is not Asian.
So now the total number of students are,
[tex]230+110+85+25=450[/tex]So now the probability of getting European is,
[tex]\frac{110}{450}=\frac{11}{45}[/tex]So the probability is,
[tex]\frac{11}{45}[/tex]So now the probability is asian is,
[tex]\frac{230}{450}=\frac{23}{45}[/tex]So the probability that it is not asian is,
[tex]1-\frac{23}{45}=\frac{45-23}{45}=\frac{22}{45}[/tex]so the required probability is,
A country's population in 1994 was 182 million.In 2002 it was 186 million. Estimatethe population in 2004 using the exponentialgrowth formula. Round your answer to thenearest million.
we have the exponential formula
[tex]P=Ae^{(kt)}[/tex]so
we have
A=182 million ------> initial value (value of P when the value of t=0)
The year 1994 is when the value ot t=0
so
year 2002 -----> t=2002-1994=8 years
For t=8 years, P=186 million
substitute the value of A in the formula
[tex]P=182e^{(kt)}[/tex]Now
substitute the values of t=8 years, P=186 million
[tex]\begin{gathered} 186=182e^{(8k)} \\ e^{(8k)}=\frac{186}{182} \\ \text{apply ln both sides} \\ 8k=\ln (\frac{186}{182}) \\ k=0.0027 \end{gathered}[/tex]the formula is equal to
[tex]P=182e^{(0.0027t)}[/tex]Estimate the population in 2004
t=2004-1994=10 years
substitute the value of t in the formula
[tex]\begin{gathered} P=182e^{(0.0027\cdot10)} \\ P=187 \end{gathered}[/tex]therefore
the answer is 187 million4 groups of 30 tens is 120 tens 6x20= 120
URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100
POINTS!!!!!
13. The population of Maryland was 5.17 million in 1999, and it grew to 6.05 million in 2019.(a) Assuming that the population is growing exponentially, find the growth rate r for Maryland's population. Give your answer as a percentage, rounded to the nearest hundredth of a percent.r = %(b) Write an exponential model to describe the population of Maryland from 1999 onward (let t=0 in 1999).Pt = (c) What is Maryland's population expected to be in 2030? Round your answer to one decimal place. million people(d) When do you expect that Maryland's population will reach 7.5 million? Give your answer as a calendar year (ex: 1999).During the year
Answer:
a) r = 0.79%
b)
[tex]P_t=5.17(1.0079)^t[/tex]c) 6.6 million people
d) 2046
Explanation:
We'll use the below formula for exponential growth;
[tex]P_t=a(1+r)^t[/tex]where a = initial amount
r = growth rate
t = number of time intervals
a) From the question, we have that
a = 5.17 million
P(t)= 6.05 million
t = 20 years
Let's go ahead and substitute these values into our formula, and solve for r as shown below;
[tex]\begin{gathered} 6.05=5.17(1+r)^{20} \\ \frac{6.05}{5.17}=(1+r)^{20} \\ (1+r)=\sqrt[20]{\frac{6.05}{5.17}} \\ r=\sqrt[20]{\frac{6.05}{5.17}}-1 \\ r=0.00789 \\ r=0.79\text{\%} \end{gathered}[/tex]b) The exponential model can be written as shown below;
[tex]\begin{gathered} P_t=5.17(1+0.0079)^t \\ P_t=5.17(1.0079)^t \end{gathered}[/tex]c) When t = 31 years, let's go ahead and find P as shown below;
[tex]\begin{gathered} P_t=5.17(1.0079)^{31} \\ P_t=6.6\text{ million people} \end{gathered}[/tex]d) When P = 7.5 million, let's go ahead and solve for t as shown below;
[tex]\begin{gathered} 7.5=5.17(1.0079)^t \\ 1.45=(1.0079)^t \\ \log 1.45=\log (1.0079)^t \\ \log 1.45=t\times\log (1.0079) \\ t=\frac{\log 1.45}{\log (1.0079} \\ t=47.2\text{years} \\ \end{gathered}[/tex]So to get the particular year all we need to do is add 47 years to the initial year. That will us 1999 + 47 = 2046
help me pleaseeeeeeeee
Answer:
A. 200
B. 500
Step-by-step explanation:
1000x²
R(x) = --------------
x² + 4
x = years
A. the first year = 1
1000(1)²
R(1) = --------------
(1)² + 4
1000
R(1) = --------------
1 + 4
1000
R(1) = --------------
5
R(1) = 200
B. years = 2
1000(2)²
R(2) = --------------
(2)² + 4
1000(4)
R(2) = --------------
4 + 4
4000
R(2) = --------------
8
R(2) = 500
I hope this helps!
What is a rational number between -0.45 and -0.46?
Answer:-0.4545555...,-0.453333...,-0.45222.....
hope i helped
Step-by-step explanation:
Jonathan is playing a game or a regular board that measures 60 centimeters long and 450 mm wide. which measurement is closest to the perimeter of the Jonathan's game board in meters?
According to the problem, the length is 60 cm and the width is 450 mm.
Let's transform 450mm to cm. We know that 1 cm is equivalent to 10 mm. So,
[tex]450\operatorname{mm}\times\frac{1\operatorname{cm}}{10\operatorname{mm}}=45\operatorname{cm}[/tex]Then, we use the perimeter formula for rectangles.
[tex]P=2(w+l)[/tex]Where w = 45 cm and l = 60 cm.
[tex]\begin{gathered} P=2(45\operatorname{cm}+60\operatorname{cm})=2(105cm) \\ P=210\operatorname{cm} \end{gathered}[/tex]The perimeter is 210 centimeters long.However, we know that 1 meter is equivalent to 100 centimeters.
[tex]P=210\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=2.1m[/tex]Hence, the perimeter, in meters, is 2.1 meters long.
Option A is the answer.A very large bag contains more coins than you are willing to count. Instead, you draw a random sample of coins from the bag and record the following numbers of eachtype of coin in the sample before returning the sampled coins to the bag. If you randomly draw a single coin out of the bag, what is the probability that you will obtain apenny? Enter a fraction or round your answer to 4 decimal places, if necessary.Quarters27Coins in a BagDimes21Nickels24Pennies28
Given:
The number of quarters = 27
The number of dimes = 21
The number of Nickels = 24
The number of Pennies = 28
Required:
Find the probability to obtain a penny.
Explanation:
The total number of coins = 27 + 21 + 24 +28 = 100
The probability of an event is given by the formula:
[tex]P=\frac{Number\text{ of possible outcomes}}{Total\text{ number of outcomes}}[/tex]The number of penny = 28
[tex]\begin{gathered} P(penny)=\frac{28}{100} \\ P(penny)=0.28 \end{gathered}[/tex]Final Answer:
The probability of obtaining Penny is 0.28.
Hello, is it possible to show me the steps to simplify this problem? I don't understand the solution provided in my textbook.
Explanation
We are asked to simplify the given question
[tex](\frac{75d^{\frac{18}{5}}}{3d^{\frac{3}{5}}})^{\frac{5}{2}}[/tex]To simplify the terms, we will follow the steps below
Step 1: simplify the terms in the bracket using the exponential rule
Thus for the terms in the parentheses
[tex](\frac{75d^{\frac{18}{5}}}{3d^{\frac{3}{5}}})=\frac{75}{3}\times d^{\frac{18}{5}-\frac{3}{5}}[/tex]Hence
[tex]25\times d^{\frac{18-3}{5}}=25d^{\frac{15}{5}}=25d^3[/tex]Simplifying further
[tex]25d^3=25d^3[/tex]Step 2: substitute the value obtained above in step 1 into the parentheses, so that
[tex](\frac{75d^{18\/5}}{3d^{3\/5}})^{\frac{5}{2}}=(25d^3)^{\frac{5}{2}}[/tex]Step 3: Simplify further, we will apply the rule
so that
[tex](25d^3)^{\frac{5}{2}}=25^{\frac{5}{2}}d^{3\times\frac{5}{2}}[/tex]Simplifying further
[tex]\begin{gathered} we\text{ will have} \\ \sqrt{25^5}\times d^{\frac{15}{2}}=3125d^{\frac{15}{2}} \end{gathered}[/tex]Hence, our final answer is
[tex]3125d^{\frac{15}{2}}[/tex]a local business Club has 11 exclusive board members and 22 General members how many committees of 7 members can be chosen so that only General members are excluded
we have:
general members are excluded then
[tex]11C7=330[/tex]answer: 330
Order the numbers from least (1) to greatest (10).ITEM BANK-Move to Battom3.564.034.212V12mor
To order these numbers, we begin with the whole part of each number. In the case of having two numbers with equal whole part, we look for the greatest tenth. So, the order would be
[tex]3.56;4.03;4.2;12[/tex]Notice that, 4.03 is less than 4.2, because its tenth is less.
A quadratic function f(x)f is hidden from view. You must find all intervals where f(x) is positive. Choose the form of the quadratic function f(x) that you would like to see in order to answer the question most efficiently.
To find the positive intervals, we'll have:
[tex]-3x^2-18x-15>0[/tex]1. Divide both sides by -3:
(Remember that dividing or multiplying by a negative number turns the inequality around!)
[tex]\begin{gathered} -3x^2-18x-15>0 \\ \rightarrow x^2+6x+5<0 \end{gathered}[/tex]2. Factor the expression:
[tex]\begin{gathered} x^2+6x+3<0 \\ \rightarrow(x+5)(x+1)<0 \end{gathered}[/tex]3. Identify the interval we're looking for:
Therefore, the function is positive in the interval:
[tex]\begin{gathered} -5Watch help videoGiven the matrices A and B shown below, find – B - A.318154B12be-12
Given two matrices
[tex]A=\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix},B=\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}[/tex]We will solve for the resultant matrix -B - 1/2A.
This operation is represented as
[tex]-B-\frac{1}{2}A=-\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}-\frac{1}{2}\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix}[/tex]Let's simplify the matrices further based on scalar operations that can be done here. The B matrix will be multiplied by -1 while the A matrix will be multiplied by 1/2. We now have
[tex]-B-\frac{1}{2}A=\begin{bmatrix}{4} & {-12} & {} \\ {-8} & {12} & {} \\ {} & {} & {}\end{bmatrix}-\begin{bmatrix}{-9} & {\frac{3}{2}} & {} \\ {\frac{-15}{2}} & {-3} & {} \\ {} & {} & {}\end{bmatrix}[/tex]Now, we apply the subtraction of matrices to the simplified matrix operation above. We have
[tex]\begin{gathered} -B-\frac{1}{2}A=\begin{bmatrix}{4-(-9)} & {-12-\frac{3}{2}} & {} \\ {-8-(-\frac{15}{2})} & {12-(-3)} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{4+9} & {-12-\frac{3}{2}} & {} \\ {-8+\frac{15}{2}} & {12+3} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex]Hence, the resulting matrix for the operation -B - 1/2A is
[tex]-B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix}[/tex](1 3/4 - 1/8)+(5/6 ÷ 2/3)
ANSWER
23/8
EXPLANATION
To solve this, first, we have to do the operations in the parenthesis. The first one is a subtraction between a mixed number and a fraction, so before doing the subtraction, we have to convert the number to an improper fraction by adding the parts,
[tex]1\frac{3}{4}=1+\frac{3}{4}=\frac{7}{4}[/tex]So the subtraction is,
[tex]1\frac{3}{4}-\frac{1}{8}=\frac{7}{4}-\frac{1}{8}=\frac{2\cdot7-1}{8}=\frac{14-1}{8}=\frac{13}{8}[/tex]Then we divide the second term using the KCF rule:
• K,eep the first fraction
,• C,hange the division sign for a multiplication sign
,• F,lip the second fraction
[tex]\frac{5}{6}\div\frac{2}{3}=\frac{5}{6}\times\frac{3}{2}=\frac{15}{12}=\frac{5}{4}[/tex]Now, we add these two results,
[tex]\frac{13}{8}+\frac{5}{4}=\frac{13+5\cdot2}{8}=\frac{13+10}{8}=\frac{23}{8}[/tex]Hence, the answer is 23/8.
Last year, the numbers of skateboards produced per day at a certain factory were normally distributed with a mean of 20,500 skateboards and a standard deviation of 55 skateboards.
a) 84.13%
b) 2.28%
c) 15.86%
Explanation:Given:
the numbers of skateboards produced per day at a certain factory were normally distributed
mean = 20, 500
standard deviation = 55
To find:
a) On what percent of the day did the factories produced 20,555 or fewer?
b) On what percent of the day did the factories produced 20,610 or fewer?
c) On what percent of the day did the factories produced 20445 or fewer?
To determine the answers, we will use the z-score formula and then use the standard normal table to get the equivalence of the z-score
The formula of score is given as:
[tex]\begin{gathered} z=\frac{X-μ}{σ} \\ \mu\text{ = mean} \\ σ\text{ = standard deviation} \\ =\text{ value we want to find} \end{gathered}[/tex][tex]\begin{gathered} a)\text{ X}=\text{ 20555} \\ z\text{ = }\frac{20555\text{ - 20500}}{55}\text{ } \\ z\text{ = }\frac{55}{55}\text{ = 1} \\ on\text{ the standard normal table, z = 1 gives 0.84134} \\ Percent\text{ that they produced 20555 or fewer = 84.13\%} \end{gathered}[/tex][tex]\begin{gathered} b)\text{ X}=\text{ 20610} \\ z\text{ = }\frac{20610\text{ - 20500}}{55} \\ z\text{ = 2} \\ On\text{ the standard normal table, z = 2 corresponds to 0.97725} \\ \\ In\text{ this case, we were asked for the percent that produce 20610 or more} \\ To\text{ get ths percent, we will subtract 0.97725 from 1} \\ =\text{ 1 - 0.97725 = 0.02275 } \\ percent\text{ that produced 20610 or more = 2.28\%} \end{gathered}[/tex][tex]\begin{gathered} c)\text{ X = 20445} \\ z\text{ = }\frac{20445\text{ - 20500}}{55} \\ z\text{ = -1} \\ This\text{ translate to 0.1586} \\ percent\text{ that produced 20445 or fewer = 15.86\%} \end{gathered}[/tex]4. (09.01 MC) Let set A = {1, 3, 5, 7) and set B = {1, 2, 3, 4, 5, 6, 7, 8} Which notation shows the relationship between set A and set B? (2 points) O AUB O ASE O Ane OBCA
A set X is said to contain a set Y if every element in Y is an element in X.
[tex]X\supseteq Y\text{ or X}\subseteq Y[/tex]In this case
[tex]1\in B,\text{ 3 }\in B,5\in B,\text{ and 7}\in B[/tex][tex]\in\text{ means: is in}[/tex][tex]so\text{ m}\in N,\text{ means that m is in N}[/tex]Therefore,
[tex]B\supseteq A\text{ or A}\subseteq B[/tex]Which expression is equivalent to -(-r - 16)?
Answer: Hi that would be (r+16) since they are generally the same thing, hope this is what you are asking for!
Step-by-step explanation: