What is the height of a parallelogram with an area of 50 square meters
and a base length of 5 meters?

Answers

Answer 1

The height of a parallelogram with an area of 50 square meters and a base length of 5 meters is 10 meters

What is a parallelogram?

The word "parallelogram" is a translation of the Greek phrase "parallelogrammon," which means "bounded by parallel lines." As a result, a quadrilateral that is bound by parallel lines is called a parallelogram. It has parallel and equal opposite sides on all sides. Square, rectangle, and rhombus are the three primary varieties of parallelograms, and each one has distinct characteristics. If a quadrilateral's opposite sides are parallel and congruent, it will be a parallelogram. So a quadrilateral with both pairs of opposite sides being parallel and equal is known as a parallelogram.

Various forms of parallelograms can be distinguished from one another based on their unique characteristics. It can be broadly classified into three distinct types:

RectangleSquareRhombus

Area = 50

Base = 5

Area of ║gm = base (height)

50 = 5(X)

x = 10

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Related Questions

Alisa walks 3.5 miles in 30 minutes. At this rate, how many miles can she walk in 45 minutes?385.7 miles5 miles386 miles5.25 miles

Answers

Given:

Alisa walks 3.5 miles in 30 minutes.

To find:

The number of miles if she walks 45 mins.

Explanation:

The unit rate for speed is,

[tex]\begin{gathered} Speed=\frac{Distance}{Time} \\ =\frac{3.5}{30} \end{gathered}[/tex]

The distance covered when she walks 45mins,

[tex]\begin{gathered} Distance=Speed\times Time \\ =\frac{3.5}{30}\times45 \\ =5.25miles \end{gathered}[/tex]

Final answer:

The number of miles she walks in 45mins is 5.25miles.

Hi, can you help me answer this question please, thank you!

Answers

1. Test statistic:

To find the test statistic, we use the formula:

[tex]\begin{gathered} Z=\frac{\bar{X_d}-\mu_d}{\frac{s_d}{\sqrt[]{n}}} \\ \text{where,} \\ \bar{X}_d=sample\text{ difference} \\ \mu_d=\text{population difference} \\ s_d=\text{standard deviation of the differences } \\ n=\text{ number of people in the survey.} \\ \\ \text{ We use Z statistic because the number of people are more than 30} \end{gathered}[/tex]

Solving for Z, we have:

[tex]\begin{gathered} \bar{X}-\mu_d=3.1\text{ (Average difference given in the question)} \\ \\ \therefore Z=\frac{3.1}{\frac{13.8}{\sqrt[]{40}}}=1.4207\approx1.421\text{ (To 3 decimal places} \end{gathered}[/tex]

Thus, the test statistic is 1.421

2. P-value:

To find the p-value, we check the Z-distribution table.

The value for the p-value is

[tex]2\times0.077658=0.15532\approx0.1553\text{ (To 4 decimal places)}[/tex]

(We multiply by 2 because it is a two-tailed test.

3. Comparison:

The alpha level is 0.001.

Thus, the p-value is greater than the alpha level

# 8 Write an equation in slope-intercept form to represent the line parallel to y = -3/4 x + 1/4 passing through the point (4, -2). O y = -3/4x + 1 O y y = 4/3x + 20/3 O y = -3/4 - 2 O y=-3x - 2

Answers

If the line is parallel to y = -3/4 x + 1/4 then the slope is -3/4

the form of an equation is y = mx +b

In this case m = -3/4

Using the point given (4, -2) we will find the value of b:

y = mx + b

y = -3/4 x + b

Using the values of the point (4, -2).... x = 4 and y = -2

-2 = (-3/4)(4) + b

Solving for b:

-2 = -3 + b

-2 + 3 = b

1 = b

b = 1

Therefore the equation would be:

y = (-3/4)x + 1

Answer:

y = (-3/4)x + 1

Suppose the purr of a cat has a sound intensity that is 320 times greater than the threshold level. Find the decibel value for this cats purr. Round to the nearest decibel.

Answers

The decibel value for this cats purr round to the nearest decibel is; 25

How to calculate the decibel level?

Decibel (dB) is a unit for expressing the ratio between two physical quantities, such as measuring the relative loudness of sounds. One decibel (0.1 bel) is equal to 10 times the common logarithm of the power ratio.

Decibels are a unit of measure used to describe how loud a sound is. Now, I₀ is the intensity of threshold sound, which is sound that can barely be perceived by the human ear.

The loudness of a sound, in decibels, with intensity I is given by;

dB = 10 log₁₀(I/I₀)

We are given the intensity of a cat’s purr as I = 320I₀

Thus;

dB = 10 log₁₀(320I₀/I₀)

dB = 10 log₁₀(320)

dB = 25.05 ≈ 25

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$85000 is invested at 7.5% per annum simple interest for 5 years. Calculate the simple interest.

Answers

From the statement of the problem we know that:

• the principal amount of money invested is P = $85000,

,

• the rate per year is 7.5%, in decimals r = 0.075,

,

• the time is t = 5 years.

The interest earnt I is equal to the difference between the total accrued amount A and the principal amount P:

[tex]I=A-P=P(1+r\cdot t)-P=P\cdot r\cdot t.[/tex]

Replacing by the data of the problem we find that the simple interest is:

[tex]I=85000\cdot0.075\cdot5=31875.[/tex]

Answer

The simple interest is $31875.

A rectangular sheet of metal is 40 inches wide and 100 inches long. What is its perimeter?

Answers

Explanation

We are given the following:

[tex]Rectangle\begin{cases}width={\text{ }40inches} \\ length={\text{ }100inches}\end{cases}[/tex]

We are required to determine the perimeter of the rectangular sheet.

This is achieved thus:

We know that the perimeter of a rectangle is given as:

[tex]P=2(l+w)[/tex]

Therefore, we have:

[tex]\begin{gathered} P=2(100+40) \\ P=2(140) \\ P=280inches \end{gathered}[/tex]

Hence, the answer is:

[tex]280inches[/tex]

^3 sq root of 1+x+sq root of 1+2x =2

Answers

The given equation is

[tex]\sqrt[3]{1+x+\sqrt{1+2x}}=2[/tex]

First, we need to elevate each side to the third power.

[tex]\begin{gathered} (\sqrt[3]{1+x+\sqrt{1+2x}})^3=(2)^3 \\ 1+x+\sqrt{1+2x}=8 \end{gathered}[/tex]

Second, subtract x and 1 on both sides.

[tex]\begin{gathered} 1+x+\sqrt{1+2x}-x-1=8-x-1 \\ \sqrt{1+2x}=7-x \end{gathered}[/tex]

Third, we elevate the equation to the square power to eliminate the root

[tex]\begin{gathered} (\sqrt{1+2x})^2=(7-x)^2 \\ 1+2x=(7-x)^2 \end{gathered}[/tex]

Now, we use the formula to solve the squared binomial.

[tex](a-b)=a^2-2ab+b^2[/tex][tex]\begin{gathered} 1+2x=7^2-2(7)(x)+x^2 \\ 1+2x=49-14x+x^2 \end{gathered}[/tex]

Now, we solve this quadratic equation

[tex]\begin{gathered} 0=49-14x+x^2-2x-1 \\ x^2-16x-48=0 \end{gathered}[/tex]

We need to find two number which product is 48 and which difference is 16. Those numbers are 12 and 4, we write them down as factors.

[tex]x^2-16x-48=(x-12)(x+4)[/tex]

So, the possible solutions are

[tex]\begin{gathered} x-12=0\rightarrow x=12 \\ x+4=0\rightarrow x=-4 \end{gathered}[/tex]

However, we need to verify each solution to ensure that each of them satisfies the given equation. We just need to evaluate it with those two solutions.

[tex]\begin{gathered} \sqrt[3]{1+x+\sqrt{1+2x}}=2\rightarrow\sqrt[3]{1+12+\sqrt{1+2(12)}}=2 \\ \sqrt[3]{13+\sqrt{1+24}}=2 \\ \sqrt[3]{13+\sqrt{25}}=2 \\ \sqrt[3]{13+5}=2 \\ \sqrt[3]{18}=2 \\ 2.62=2 \end{gathered}[/tex]

As you can observe, the solution 12 doesn't satisfy the given equation.

Therefore, the only solution is -4.

HELP PLEASE!!!!!!!!!!! ILL MARK BRAINLIEST

Answers

the rational number :

-1 ³/₄ is located as point 1

14/8 is located as point 5

1.125  is located as point 6

-0.875 is located as point 4

What is number line ?

Number line is virtual representation of numbers along with coordinates axis with number equally spaced with equal number of interval.

Here,

the rational number -1 ³/₄ is located as point 1, as -1 ³/₄ is greater then -1 and less then -2 on number line and is 3/4 of the gap between -1 and -2.

the rational number 14/8 is located as point 5, as 14/8 is greater then 0 and less then 1 on number line and is 3/4 of the gap between 0 and 1.

the rational number 1.125  is located as point 6, as 1.125 is greater then 1 and less then 2 on number line and is 1/8th  of the gap between 1 and 2.

the rational number -0.875 is located as point 4, as -0.875 is greater then 0 and less then -1 on number line and is 1/8 th of the gap between -1 and 0.

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(Please show your work for question 18.)

Answers

It is given that AB = CB from this information we conclude that <A=<C by reason :angles opposite equal sides.

<A+<B+<C=180°(Sum of angles in a triangle)

[tex](4x - 13) + (5x - 2) + (4x - 13) = 180 \\ 4x + 5x + 4x - 13 - 2 - 13 = 180 \\ 13x - 28 = 180 \\ 13x = 180 + 28 \\ 13x = 208 \\ \frac{13x}{13} = \frac{208}{13} \\ x = 16[/tex]

x=6°

ATTACHED IS THE SOLUTION

GOODLUCK

1 1 10 1 b. What fraction of the whole square is shaded? Explain how you know.

Answers

1/100

Explanation:

To get the fraction of the square shaded we would use the rows and columns

For the row:

The total on the 1st row = 1

The first row is divided into 10. This means each box in the first row: 1/10

One of the box is shaded. This implies the fraction shaded in the first row is 1/10

For the column:

The total on the 1st column = 1

The column is also divided into 10 box which means each box represent 1/10

Since one of the box in the column is shaded, it represent 1/10

Fraction of the whole square shaded = fraction shaded in the row × fraction shaded in the column

Fraction of the whole square shaded = 1/10 × 1/10

Fraction of the whole square shaded = 1/100

Canvas that costs 3/4 cents/in squared is used to make golf bags. Find the cost (in dollars) of 200 rectangular pieces of canvas, each 6.0 in. by 4.0 in.

Answers

The cost of 200 rectangular pieces of canvas given its dimensions is $36.

What is the cost?

The first step is to determine the area of one of the rectangular pieces. A rectangle is a two-dimensional quadrilateral with four right angles.

Area of a rectangle = length x width

6 X 4 = 24 in²

The next step is to determine the area of the 200 rectangular pieces.

Area of the 200 rectangular pieces = 200 x 24in² = 4,800 in²

The last step is to determine the cost of the 200 rectangular pieces.

Total cost = total area x cost per squared inches

3 / 4 x 4800 = 3600 cents = $36

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Find the volume of 12 cm

Answers

Answer:

1728 cm ^ 3.

Step-by-step explanation:

we are given 12 cm

As we know formula of volume of cube = s ^3 ( side * side * side ) So = 12 * 12* 12 = 1728 cm ^ 3.

Find the Volume cylinder (8cm) (12cm) h = 8cm r = 12cm h = 8 cm r = 12 cm. The volume of a cylinder is equal to the area of the base πr2 π r 2 times the height. π⋅(radius)2 ⋅(height) π ⋅ ( r a d i u s) 2 ⋅ ( h e i g h t) Substitute the values of the radius r = 12 r = 12 and height h = 8 h = 8 into the formula to find the volume of the cylinder

P.s hopes this helps

How many times larger is 3 x 10⁹ than 3 x 10⁷ ?

Answers

Answer:

100 times

Step-by-step explanation:

[tex]\frac{10^{9} }{10^{7} }[/tex]  = [tex]10^{2}[/tex] = 100

When you are dividing exponents with the same bases, you subtract the exponents.

Answer:

3 x 10^9 is larger than 3 x 10^7 by 2,970,000,000

Step-by-step explanation:

which statement is true?

Answers

This is the graph of the function

The answer is (8,0)

The perimeter of the rectangle is 19.4 centimeters.What is the width in centimeters,of the rectangle Length is 6cm

Answers

SOLUTION

From the question, the Perimeter of the rectangle is 19.4 cm and we want to find the width. The perimeter of a rectangle is given by

[tex]\begin{gathered} P=2\left(l+w\right) \\ where\text{ P =perimeter = 19.4} \\ l=length\text{ of rectangle = 6 cm} \\ w=width=? \end{gathered}[/tex]

Applying this, we have

[tex]\begin{gathered} P=2\left(l+w\right) \\ 19.4=2\left(6+w\right) \\ 19.4=12+2w \\ 2w=19.4-12 \\ 2w=7.4 \\ w=\frac{7.4}{2} \\ w=3.7 \end{gathered}[/tex]

Hence the width is 3.7 cm, option C

3.2 x 104 bacteria are measured to be in a dirt sample that weighs 1 gram. Usescientific notation to express the number of bacteria that would be in a sampleweighing 21 grams.

Answers

The number of bacteria that weighs 1 gram are,

[tex]3.2\times10^4[/tex]

Determine the number of bacteria in a sample that weighs 21 grams.

[tex]\begin{gathered} 21\cdot3.2\times10^4=67.2\times10^4 \\ =6.72\times10^5 \end{gathered}[/tex]

So answer is,

[tex]6.72\times10^5[/tex]

find the exact values of the six trigonometric functions of the angle 0 shown in the figure(Use the Pythagorean theorem to find the third side of the triangle)

Answers

The right angled triangle is given with reference angle theta.

The opposite side (facing the reference angle) is 3, while the hypotenuse (facing the right angle) is 5. The adjacent shall be calculated using the Pythagoras' theorem as follows;

[tex]\begin{gathered} \text{Adj}^2+3^2=5^2 \\ \text{Adj}^2=5^2-3^2 \\ \text{Adj}^2=25-9 \\ \text{Adj}^2=16 \\ \text{Adj}=\sqrt[]{16} \\ \text{Adj}=4 \end{gathered}[/tex]

Therefore, the trigonometric functions of angle theta are shown as follows;

[tex]\begin{gathered} \sin \theta=\frac{opp}{hyp}=\frac{3}{5} \\ \cos \theta=\frac{adj}{hyp}=\frac{4}{5} \\ \tan \theta=\frac{opp}{adj}=\frac{3}{4} \\ \csc \theta=\frac{hyp}{opp}=\frac{5}{3} \\ \sec \theta=\frac{hyp}{adj}=\frac{5}{4} \\ \cot \theta=\frac{adj}{opp}=\frac{4}{3} \end{gathered}[/tex]

What is the factorization of496^4-9

Answers

The given expression is

[tex]496^4-9[/tex]

To factorize this, we find the square root of each term.

[tex]\begin{gathered} \sqrt[]{496^4}=496^2 \\ \sqrt[]{9}=3 \end{gathered}[/tex]

Then, we use the difference of perfect square which states

[tex]a^2-b^2=(a+b)(a-b)[/tex]

So, we have

[tex]496^4-9=(496^2+3)(496^2-3)[/tex]

How can a greatest common factor be separated from an expression

Answers

Answer: divide each term from the original expression (3x3+27x2+9x ) by the GCF (3x), then write it in the parenthesis

Step-by-step explanation:

Answer:

You take it out and place it as a multiple.

Step-by-step explanation:

5x+15

GCF = 5

5(x+3)

Hope that helps

In the diagram below, GD = 10.1,EF 28.1, and EG 16.9. Find the length==of FC. Round your answer to the nearest tenthif necessary.

Answers

Solution:

In the figure;

[tex]\begin{gathered} \frac{EG}{EF}=\frac{ED}{EC} \\ \\ EG=16.9,ED=27,EF=28.1 \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} \frac{16.9}{28.1}=\frac{27}{EC} \\ \\ EC=44.9 \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} FC=EC-EF \\ \\ FC=44.9-28.1 \\ \\ FC=16.8 \end{gathered}[/tex]

Find an equation of line L. Write your answer using fractions or integers.The equation of line L is y =

Answers

Find slope m, in equation y= mx + b

m = Y/X =( y - y')/ (x - x')

m= (5 - -5 )/ (-3 -3) = 10/-6 = -5/3

Now find b

b = y - mx

= 5 - (-5/3)•-3

. = 5 - 5 = 0

b = 0

Then answer is, equation is

y = (-5/3)x

decide wether the following sides are acute obtuse or a right triangle.

Answers

The acute triangle is defined by the condition,

[tex]a^2+b^2The obtuse triangle is defined by the condition, [tex]a^2+b^2>c^2[/tex]

Here, we have,

[tex]\begin{gathered} 19^2=361 \\ 12^2=144 \\ 15^2=225 \\ 12^2+15^2>19^2 \end{gathered}[/tex]

Thus, the triangle is an obtuse triangle.

the double number line shows the price of one cupcake complete the table and show the same information as a double number line 5 to blank blank to 18 and 18 to blank

Answers

From the first diagram shown, we can see that 1 cupcake costs $1.5

To get the price of 5 cupcakes

Since 1cupcake = $1.5

5 cupcakes = $x

cross multiply

1 * x = 5 * 1.5

x = $7.5

Hence 5 cupcakes will cost $7.5

Since 1cupcake = $1.5

18 cupcakes = $x

cross multiply

1 * x = 18 * 1.5

x = $27

Hence 5 cupcakes will cost $27

To get the number of cupcakes priced $18

Since 1cupcake = $1.5

x cupcake = $18

1.5x = 18

divide both sides by 1.5

1.5x/1.5 = 18/1.5

x =

Irlene has just returned from a business trip in Britain with £200 of uncashed traveller's cheques. How much would she receive from the bank when she converts the currency back to Canadian dollars, assuming that the bank offers an exchange rate of C$1.00 = £0.5544 and charges a 0.65% fee to convert the traveller's cheques to Canadian funds? For full marks your answer(s) should be rounded to the nearest cent.

Answers

The converted money in Canadian dollars is $111.6.

Given that, Irlene has just returned from a business trip in Britain with £200 of uncashed traveler's cheques.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the converted Canadian dollars be x.

x = 200 × 0.5544 + 0.65% of 200 × 0.5544

= 110.88 + 0.0065 × 110.88

= 111.60072

≈ 111.6

Therefore, the converted money in Canadian dollars is $111.6.

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Determine if u is a solution to 1 - 9u = 19u= -2, 7, 0, 6

Answers

-2

Replace u by -2, and check if the equality remains

1-9u = 19

1-9(-2) = 19

1-(-18)=19

1+18 = 19

19=19

-2 YES

7

1- 9(7) = 19

1-63 = 19

-62=19

NO

0

1-9(0) = 19

1= 19

NO

6

1-9(6) = 19

1-54=19

-53=19

NO

45. For customers generating their own solar power, ZG&E charges them $3 per month per kilowatt (kWh) for excess electricity they export to the grid. Ready Edison charges customers a flat rate of $20 per month and credits them $0.06 per kWh for excess electricity they export to the grid. Determine the monthly bills for customers of both companies for each of the following:(A) Customer owns a 3-kW system and exports 120 kWh monthly to the grid.(B) Customer owns a 5-kW system and export 300 kWh monthly to the grid.

Answers

(A) The customer that owns a 3-kW system exports 120 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

[tex]120kWh\times\frac{\$3}{1kWh}=\$360[/tex]

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

[tex]\$20+(120kWh\times\frac{\$0.06}{1kWh})=\$27.2[/tex]

(B) The customer that owns a 5-kW system exports 300 kWh monthly to the grid will have the following bills for both companies:

For ZG&E that collects $3 per kWh on a monthly basis, the monthly bill will be

[tex]300kWh\times\frac{\$3}{1kWh}=\$900[/tex]

For Ready Edison that collects $0.06 per kWh exported energy monthly, the computation of bill will be

[tex]\$20+(300kWh\times\frac{\$0.06}{1kWh})=\$38[/tex]

H D 2 cm 4 cm The two rectangles below are similar. What is the ratio of the perimeters of rectangle ABCD to rectangle EFGH? B А 4 cm E 8 cm F 2:1 8:1 1:4 1:2 2

Answers

In order to determine the ratio of the perimeters for the given rectangles, first calcualte their perimeters. Use the following formula:

P = 2w + 2l

w: width

l: length

For the smaller rectangle you have:

w = 2cm

l = 4 cm

P = 2(2cm) + 2(4cm) = 4cm + 8cm = 12cm

For the bigger triangle you have:

w' = 4cm

l' = 8cm

P' = 2(4cm) + 2(8cm) = 8cm + 16cm = 24cm

Then, you have:

P/P' = 12cm/24cm = 1/2

Hence, the ratio is 1:2

Nora has a job where she has a take home salary each month of $2400. if Nora wants to spend no more than 15% of her monthly take home salary on her car payment, how much can she afford?

Answers

Her take home salary is $2400 and she wants to spend no more than 15% on her car payment. Therefore, she can afford no more than 0.15*2400 = $360 on her car payment.

Find the next two numbers in the pattern -243, 81, -27, 9

Answers

Find the next two numbers in the pattern -243, 81, -27, 9​

Notice that all the values in the series are value of 3 raise to the power of a number.

-243 =

Given g=(1+2a)/a, solve for the variable a.

Answers

We are given the equality

[tex]g=\frac{1+2a}{a}[/tex]

and told to solve for a. That is, we should apply mathematical operations on both sides of the equality so we "isolate" variable a on one side of the equality. We start by multiplying both sides by a, so we get

[tex]a\cdot g=1+2a[/tex]

Now, we subtract 2a from both sides. We get

[tex]a\cdot g-2a=1[/tex]

We can factor on the left side a as a common factor, so we get

[tex]a\cdot(g-2)=1[/tex]

Finally, we divide by (g-2) on both sides, so we get

[tex]a=\frac{1}{g-2}[/tex]

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