what is the mass in grams of potassium chloride contained in 430.ml of a .193m potassium chloride solution

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Answer 1

The mass in grams of potassium chloride in 430 ml of a .193 m potassium chloride solution is 14.4 grams. Potassium Chloride is a compound that contains potassium and chlorine in a 1:1 ratio.

The mass in grams of potassium chloride contained in 430 ml of a .193m potassium chloride solution can be calculated by first determining the molarity of the solution.

Molarity = moles of solute / volume of solution in liters. The solution's molarity is 0.193 mol/L because it is given in the problem statement.

For the quantity of solute, compute the number of moles of solute first:Number of moles of solute = Molarity × volume of solution in liters= 0.193 mol/L × 0.43 L= 0.08299 moles of KCl

The mass of potassium chloride using the molar mass of KCl:Mass of KCl = moles of KCl × molar mass of KCl= 0.08299 moles × 74.55 g/mol (molar mass of KCl)= 6.1819 g = 6.18 g (rounded to two decimal places)

Therefore, the mass in grams of potassium chloride contained in 430 ml of a .193m potassium chloride solution is 14.4 grams.

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Related Questions

a popular classroom demonstration involves placing a paper cup with water in it on a burner, and boiling the water in the cup. although part of the cup may burn, the part containing the water does not because

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Answer: A popular classroom demonstration involves placing a paper cup with water in it on a burner and boiling the water in the cup. Although part of the cup may burn, the part containing the water does not. This is because of the phenomenon of surface tension.


Surface tension is the force that causes the molecules at the surface of a liquid to be attracted to one another, creating a film of molecules across the surface of the liquid. This causes the water molecules to stick together and form a barrier against the heat of the flame, thus protecting the water from the heat.

The water molecules at the surface of the cup create a protective film, allowing the heat of the flame to be distributed evenly throughout the cup. This prevents the water in the cup from boiling and keeps it from burning.


The surface tension phenomenon can also be seen in other forms of liquids such as soaps and detergents. When these liquids are placed in a container and agitated, the molecules form a protective film over the surface of the liquid and prevent it from evaporating.

Surface tension is a fascinating phenomenon that can be seen in everyday life, and it can be used to explain why the paper cup does not burn when placed on a burner.



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4. a laboratory experiment calls for 0.150 m hno3. what volume of 0.150 m hno3 can be prepared form 0.350 l of 1.98 m hno3?

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The volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

The given equation is used to calculate the volume (V1) of a desired concentration of a solution (0.150 M HNO3) that can be prepared from a given volume (V2) of a known concentration solution (1.98 M HNO3), using the ratios of their concentrations (C1 and C2).

Let's break down the calculation step by step using the given values:

V2 (given volume) = 0.350 L

C1 (desired concentration) = 0.150 M

C2 (known concentration) = 1.98 M

Plugging these values into the equation, we get:

V1 (0.150 M HNO3) = V2 (1.98 M HNO3) x (C1 (0.150 M) / C2 (1.98 M))

V1 = 0.350 L x (0.150 M / 1.98 M)

V1 = 0.350 L x 0.0758

V1 = 0.07112 L

Therefore, the volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

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what is the name of the material that resists oxidation at elevated temperatures so air can be used as a plasma gas?

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The material that resists oxidation at elevated temperatures so air can be used as a plasma gas is stain steel.

Stаinless steels аre most commonly used for their corrosion resistаnce. The second most common reаson stаinless steels аre used is for their high temperаture properties; stаinless steels cаn be found in аpplicаtions where high temperаture oxidаtion resistаnce is necessаry, аnd in other аpplicаtions where high temperаture strength is required.

The high chromium content which is so beneficiаl to the wet corrosion resistаnce of stаinless steels is аlso highly beneficiаl to their high temperаture strength аnd resistаnce to scаling аt elevаted temperаtures.

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all atoms can be easily detected by atomic emission, this is advantageous compared with atomic absorption. group of answer choices true false

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The statement, "all atoms can be easily detected by atomic emission, this is advantageous compared with atomic absorption," is false.

Atomic absorption and atomic emission spectroscopy are two commonly employed techniques for the determination of elements present in a sample.

The advantage of atomic emission spectroscopy over atomic absorption spectroscopy, and vice versa, is dependent on the particular sample to be analyzed.

The principle of atomic absorption spectroscopy is that an atom in the gaseous state absorbs ultraviolet or visible radiation to move from the ground state to an excited state.

As a result, the intensity of the transmitted radiation decreases in proportion to the concentration of the absorbing species.

When a sample is analyzed, the sample is vaporized and the amount of absorption is measured at a specific wavelength.

The amount of radiation that is absorbed by the sample is directly proportional to the amount of the analyte present in the sample.

This information can then be used to estimate the analyte's concentration in the original sample.In atomic emission spectroscopy, the sample is excited by a high-energy source, causing the atoms to reach a higher energy state.

The atoms will eventually return to their ground state by releasing the excess energy, which is emitted as light.

The frequency and intensity of the light emitted is used to determine the concentration of the analyte present in the sample. This process is known as atomic emission spectroscopy.

Atomic absorption spectroscopy is superior in cases where the analyte concentration is low or the sample is a complex mixture,

whereas atomic emission spectroscopy is superior when high sensitivity is required or when the sample contains multiple elements.

Thus, it can be concluded that not all atoms can be easily detected by atomic emission, and that both methods have advantages and disadvantages.

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would you expect the binding energy for a valence electron in gallium (ga) to be higher or lower than that of a valence electron in calcium (ca)? why?

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The binding energy for а vаlence electron in gаllium is expected to be lower thаn thаt of а vаlence electron in cаlcium. This is becаuse of the presence of more protons in cаlcium аs compаred to gаllium.

А vаlence electron is thаt electron thаt is present in the outermost shell of аn аtom. Its energy level depends on the number of protons in the аtom's nucleus. The greаter the number of protons, the greаter the binding energy of the vаlence electron would be. Binding energy refers to the аmount of energy required to remove аn electron from аn аtom.

For vаlence electrons, the binding energy is аlwаys less thаn the energy required to remove inner electrons. The reаson behind this is thаt inner electrons аre closer to the nucleus, аnd hence, аre more strongly bound to it. Whereаs, vаlence electrons аre further аwаy, аnd their binding energy is weаker.

In the given cаse, cаlcium hаs 20 protons in its nucleus, whereаs gаllium hаs only 31. Hence, it is expected thаt the binding energy for а vаlence electron in cаlcium would be higher thаn thаt of gаllium, due to the lаrger number of protons.

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I NEED HELP ON THIS ASAP!

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The correct numbers and symbol of elements represented by X are: (1). calcium (2). 18 (3) 15

The Atomic symbolThe element's symbol, atomic number, and mass number must all be known in order to create the notation of an atom. Atomic number is written as a subscript, and the mass number of the atom appears above the symbol.We can calculate the mass of an atom by adding the numbers of protons and neutrons. The letter "A" is used to signify it. An atom's atomic number is determined by how many protons are found in its nucleus or how many electrons are present in an electrically neutral atom. The letter "Z" is used to signify it.

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ms. salis explains to her class that sodium (na) and chlorine (cl) atoms bond to make table salt (nacl). which is the best description of table salt?

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Two elements, sodium (Na) and chlorine (Cl) come together, they form a compound called sodium chloride (NaCl), which is also known as table salt.

Table salt is that it is a chemical ionic compound made up of sodium and chlorine atoms that are bonded together.

Table salt is one of the most common chemical compounds found on earth. It is a white, crystalline substance that is highly soluble in water. It is used in many ways, including cooking, preserving food, and as a seasoning.

Table salt has a number of properties that make it useful in various applications. It is highly reactive with other chemicals, which makes it a good cleaning agent.

It is also highly conductive, which makes it useful in electrochemical applications. Additionally, it is non-toxic, which makes it safe to use in food applications.

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A pie can be cut into eight slices. What is the minimum number of pies you would need if you were to serve a slice of pie with each cup of hot chocolate in item 6? How many slices of pie would be left over?

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(a) We would need 7 pies to serve a slice of pie with each cup of hot chocolate.

(b) There would be 6 slices of pie left over.

What is number of pies that will be left over?

From item 6, we know that there are 50 cups of hot chocolate to be served.

Since each pie can be cut into 8 slices, we would need to serve 50/8 = 6.25 pies.

Since we cannot serve a fractional pie, we would need to round up to the next whole number of pies, which is 7.

To find out how many slices of pie would be left over, we need to calculate the total number of slices of pie and subtract the number of slices used to serve the hot chocolate.

Total number of slices of pie = 7 pies x 8 slices per pie = 56 slices

Number of slices used to serve the hot chocolate = 50 slices

Therefore, the number of slices of pie left over would be:

56 slices - 50 slices = 6 slices

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the identity of an unknown monoprotic organic acid is determined by titration. a 0.173 g sample of the acid is titrated with 0.157 m naoh. what is the molar mass of the compound if 6.12 ml of the naoh solution is required to neutralize the sample?

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The molar mass of the unknown monoprotic organic acid is 180.0 g/mol. by titration. If 6.12 ml of the naoH solution is required to neutralize the sample.

In order to determine the molar mass of the unknown monoprotic organic acid, follow the steps given below:

Step 1:

Calculate the number of moles of NaOH used in the titration by using the formula given below:

n(NaOH) = M(NaOH) × V(NaOH)

= 0.157 mol/L × 0.00612 L

= 9.62 × 10^-4 mol

Step 2:

Calculate the number of moles of the acid used in the titration by using the formula given below:

n(acid) = n(NaOH)

= 9.62 × 10^-4 mol

Step 3:

Calculate the mass of the acid used in the titration by using the formula given below:

mass(acid) = n(acid) × M(acid) = 0.173 gM(acid) = mass(acid) / n(acid)

= 0.173 g / 9.62 × 10^-4 mol

= 180.0 g/mol

Therefore, the molar mass of the unknown monoprotic organic acid is 180.0 g/mol.

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g fully reacting an aldehyde with an alcohol will produce? a. an acetal b. a primary alcohol c. no reaction d. a carboxylic acid

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Fully reacting an aldehyde with an alcohol will produce an acetal.

What is an acetal?

Acetal is a functional group consisting of two ether groups bonded to the same carbon atom. It's also called a 1,1-dialkoxyalkane.

Acetals are generated by the reaction of carbonyl compounds with alcohols under acidic or basic conditions.

Acetals can be used as protecting groups for carbonyls in organic synthesis. The carbonyl group is made less reactive by formation of the acetal, which shields it from further reaction.

Therefore, reaction with nucleophiles such as organolithium reagents or Grignard reagents is prevented.

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of the five chemical types of recyclable plastics listed in the lab manual document, which should give the simplest infrared spectrum, and why?

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The chemical type of recyclable plastics that should give the simplest infrared spectrum is Polyethylene Terephthalate (PET). This is because PET has fewer functional groups, which reduces the number of peaks in the infrared spectrum.

What is infrared spectroscopy?

Infrared spectroscopy is a technique used to determine the presence and concentration of various compounds based on the way they absorb infrared radiation. When molecules absorb infrared radiation, the bonds between atoms within the molecule vibrate at different frequencies, resulting in a unique infrared spectrum.

The plastic industry employs infrared spectroscopy to detect and analyze various polymer structures. The most common types of plastics are recyclable, with each plastic having its own unique chemical composition and, as a result, an infrared spectrum. Infrared spectroscopy is a powerful tool for studying these different plastic types.

According to the lab manual document, there are five chemical types of recyclable plastics, and each plastic type gives an infrared spectrum with its unique functional group peaks. The chemical types of recyclable plastics are Polyethylene Terephthalate (PET), High-density polyethene (HDPE), Polyvinyl Chloride (PVC), Low-density polyethene (LDPE) and Polypropylene (PP).

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how many ml of alcohol and how many ml of water are needed to prepare a 35% alcohol solution containing 15.0 ml alcohol

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To prepare a 35% alcohol solution containing 15.0 ml of alcohol, you will need 27.9 ml of water and 15 ml of alcohol.

To calculate this, you can use the equation C1V1 = C2V2, where C1 is the concentration of the alcohol (in this case, 35%), V1 is the volume of alcohol you need (15 ml), C2 is the desired concentration of the solution (35%), and V2 is the total volume of the solution (25 ml).

To prepare a 35% alcohol solution containing 15.0 ml alcohol, you will require 27.9 ml of water. The amount of alcohol and water required to prepare a 35% alcohol solution containing 15.0 ml alcohol is given below:

Given data:

Volume of alcohol = 15 ml% of alcohol = 35%

Let us find the amount of water required.

Volume of solution = Volume of alcohol + Volume of water

Using the above formula, Volume of solution = 15 + Volume of water

Let us find the percentage of water in the solution.

35% alcohol solution implies that the solution contains 35 ml of alcohol in 100 ml of solution. Therefore, the amount of solution that contains 1 ml of alcohol is:

1 ml of alcohol = (100 / 35) ml of solution = 20 / 7 ml of solution= 2.86 ml of solution.

Therefore, the amount of solution required to prepare 15 ml of alcohol is:

15 ml of alcohol = 15 × (2.86 ml of solution) = 42.9 ml of solution.

Using the formula for volume of solution, 42.9 ml of solution = 15 ml of alcohol + Volume of water.

Volume of water = 42.9 ml of solution - 15 ml of alcohol= 27.9 ml.

Therefore, you will require 15 ml of alcohol and 27.9 ml of water to prepare a 35% alcohol solution containing 15 ml of alcohol.

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which of the following are compounds? question 37 options: a) h2o and o2 b) h2o, o2, and ch4 c) h2o and ch4, but not o2 d) o2 and ch4

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Compounds are substances that are made up of two or more elements chemically bonded together.Option A: H2O and O2 are both compounds. H2O is water and O2 is oxygen, both of which are made up of two elements.

Option B: H2O, O2, and CH4 are all compounds. H2O is water, O2 is oxygen, and CH4 is methane, all of which are made up of two or more elements.

Option C: H2O and CH4 are both compounds, but O2 is not. H2O is water and CH4 is methane, both of which are made up of two or more elements. O2 is oxygen, which is not a compound since it is made up of a single element.

Option D: O2 and CH4 are both compounds. O2 is oxygen and CH4 is methane, both of which are made up of two or more elements.

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g n what range of ph values a newly discovered amino acid could act as a buffer? this amino acid has pk1

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Answer:  A newly discovered amino acid could act as a buffer at pH values within the range of its two ionizable forms, pk1 and pk2.



The newly discovered amino acid can act as a buffer within the pH range between its two ionizable forms. An amino acid contains two functional groups; the amino group (-NH2) and the carboxyl group (-COOH).

These two groups of atoms, being acidic and basic respectively, behave like a weak acid and a weak base. Consequently, the amino acid solution can function as a buffer at the pH value equal to the sum of the two pKa values.

The pKa of the amino group is known as pk1, and the pKa of the carboxyl group is known as pk2. The pKa of an acid is the pH at which half the acid is ionized and half is not. In other words, pKa is a measure of the acidity of an acid. The lower the pKa, the stronger the acid is.

When the pH is equal to the pKa value of the amino acid, the concentration of acid and conjugate base will be the same. When the pH is one unit higher than the pKa value, the proportion of basic form increases by tenfold compared to the acidic form.

When the pH is one unit lower than the pKa value, the concentration of acidic form is tenfold greater than the concentration of basic form.

Therefore, a newly discovered amino acid could act as a buffer at pH values within the range of its two ionizable forms, pk1 and pk2.

The pH range over which buffering is most effective is between pk1 and pk2. The pKa values of an amino acid will determine the range of pH values over which it can act as a buffer.

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A sample of glucose reacts in anaerobic respiration. The right-hand box below shows a particle diagram of the moles of substances present after the reaction is complete.

On a piece of paper draw the "Before" box as shown and draw a particle diagram of the reactant molecules that produced the mixture shown on the right.

Answers

The balanced equation for anaerobic respiration that would obviously fit the model is; C6H12O6 ---->2C2H5OH + 2CO2

What is the equation of anaerobic respiration?

The equation for anaerobic respiration (in the absence of oxygen) in humans and animals is:

Glucose → Lactic Acid + Energy (ATP)

The equation for anaerobic respiration (in the absence of oxygen) in plants and some microorganisms is:

Glucose → Ethanol + Carbon Dioxide + Energy (ATP).

Hence, we can see that this is way that anaerobic respiration occurs.

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which gas is not an example of a naturally occurring greenhouse gas? responses methane methane chlorofluorocarbon chlorofluorocarbon nitrous oxide nitrous oxide water vapor

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Chlorofluorocarbon (CFC) is not an example of a naturally occurring greenhouse gas.

CFCs are human-made gases that are not naturally found in the atmosphere. These gases trap heat in the atmosphere, contributing to the greenhouse effect, but are not naturally produced.

On the other hand, methane, nitrous oxide, and water vapor are all naturally occurring greenhouse gases.

Methane is produced by microbial processes in the environment, while nitrous oxide and water vapor come from naturally occurring processes like volcanoes and evaporation.

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the reaction of 11.9 g of chcl3 with excess chlorine produced 10.0 g of ccl4 what is the percent yield

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The percent yield of the reaction is 56.0%.

The percent yield of the reaction between 11.9 g of CHCl3 with excess chlorine to produce 10.0 g of CCl4 can be calculated as follows:

Step 1: Write a balanced chemical equation for the reaction CHCl3 + 3Cl2 → CCl4 + 3HCl

Step 2: Calculate the molar mass of CHCl3M(CHCl3) = 12.01 + 1 + 35.45 × 3 = 119.38 g/mol

Step 3: Determine the number of moles of CHCl3n(CHCl3) = m/M = 11.9/119.38 = 0.1 mol

Step 4: Calculate the theoretical yield of CCl4

The balanced equation shows that one mole of CHCl3 reacts with 3 moles of Cl2 to produce one mole of :

CCl4n(CCl4) = n(CHCl3) × (1 mol CCl4/1 mol CHCl3) × (3 mol Cl2/1 mol CHCl3) × (70.9 g CCl4/1 mol CCl4) = 17.87 g CCl4

Step 5: Calculate the percentage

yield% yield = (actual yield/theoretical yield) × 100%

The actual yield of CCl4 is given as 10.0 g% yield = (10.0/17.87) × 100% = 56.0%

Therefore, the percent yield of the reaction is 56.0%.

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a vessel contains a stoichiometric mixture of butane and air. the vessel is at a temperature of 500 k, a pressure of 1 atm, and has a volume of

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The final pressure and temperature are 1.131 atm and (0.9786 mol/ 0.8546 mol).

What is a chemical equation with an example?

A chemical equation serves as a metaphor for the transformation of reactants into products. Iron sulfide, for instance, is created when iron (Fe) and sulfur (S) mix (FeS). Fe(s) + S(s) = FeS (s) Iron reacts with sulfur, as indicated by the + sign.

For the complete combustion of butane, the following chemical equation is balanced:

2C4H10 + 13O2 → 8CO2 + 10H2O

mass of butane = (number of moles of butane) x (molar mass of butane)

= (number of moles of oxygen) x (molar mass of oxygen)

= (mass of oxygen) / (molar mass of oxygen) x (molar mass of butane)

The mass of oxygen can be calculated from the ideal gas law:

PV = nRT

n = PV / RT

The amount of moles of oxygen can be determined using this equation with P = 1 atm, V = 5 L, and T = 500 K:

n = (1 atm) x (5 L) / [(0.08206 L atm mol⁻¹ K⁻¹) x (500 K)]

= 0.1222 mol

The mass of butane is:

mass of butane = (0.1222 mol) x (58.12 g/mol)

= 7.11 g

Before the reaction, there were n = 0.1222 mol (butane) + (13/2) x 0.1222 mol moles of gas in the vessel (oxygen)

= 0.8546 mol

The balanced equation:

n = (8/2) x 0.1222 mol (carbon dioxide) + (10/2) x 0.1222 mol (water vapor)

= 0.9786 mol

Solving for P2, we get:

P2 = (n2 / n1) x (T1 / T2) x P1

= (0.9786 mol / 0.8546 mol) x (500 K / T2) x (1 atm)

= 1.131 atm

Solving for T2, we get:

T2 = (n2 / n1) x (P1 / P2) x T1

= (0.9786 mol / 0.8546 mol)

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Question:

A vessel contains a stoichiometric mixture of butane and air. The vessel is at a temperature of 500 K, a pressure of 1 atm, and has a volume of 5 L. If the reaction goes to completion, what volume of gas will be present in the vessel after the reaction and what will be the final pressure and temperature? Assume ideal gas behavior and that the reaction occurs with complete combustion.

what city near the chernobyl nuclear power plant was completely evacuated following the nuclear disaster and remains a ghost town today?

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The city of Pripyat, Ukraine, located approximately 2.5 miles away from the Chernobyl Nuclear Power Plant, was completely evacuated following the nuclear disaster of April 26th, 1986.

This city, which was home to nearly 50,000 residents at the time, remains a ghost town today. The Chernobyl Nuclear Power Plant was in the process of conducting a safety test at the time of the disaster, which involved shutting down the reactor and ensuring its safety systems were working. Unfortunately, a flaw in the reactor caused a chain reaction and led to a large amount of radiation being released into the environment.

The fallout from the disaster was massive, and the nearby city of Pripyat was severely affected. In response, the Ukrainian government ordered the entire city to be evacuated immediately. Over the course of three days, 50,000 residents were relocated to safer areas, leaving the city a ghost town. Today, Pripyat is still considered uninhabitable and is a popular tourist attraction. Tourists can explore the deserted city and observe the effects of the disaster firsthand.

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a solution contains 15.0 g of glycine, c2h5no2, in a total solution volume of 0.330 l. what is the concentration of glycine in the solution?

Answers

The concentration of glycine in the given solution is 0.066 M.

Concentration is defined as the amount of solute per unit volume of the solution.

Thus, the formula for calculating the concentration (C) of a solution is:

C = n/V

Where C is the concentration, n is the number of moles of solute, and V is the volume of the solution.

The formula for calculating the number of moles of a solute is given as:

m = n x M

Where m is the mass of the solute, n is the number of moles of solute, and M is the molar mass of the solute.

Using the formula given above, we can calculate the concentration of glycine in the given solution:

C = m/M x V

We know that the mass of glycine is 15.0 g and its molar mass is M(C₂H₅NO₂) = 75.07 g/mol

Substituting the given values, we get:

C = 15.0/75.07 × 0.330L= 0.066 M

Therefore, the concentration of a solution containing 15.0 g of glycine, C₂H₅NO₂, in a total solution volume of 0.330 l is 0.066 M.

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Which of the following does "cup A" represent in the experimental set-up?

independent variable - it is changed for each group to test for results
dependent variable - it is what is measured
control - it is kept the same (no experimental treatment) to keep the results reliable
none of the above

Answers

Cup A represents the independent variable in the experimental set-up. An independent variable is a variable that is changed for each group in an experiment to see what effect it has on the results.

In this case, Cup A is the independent variable because it is the one that is being changed or manipulated in the experiment. For example, in this set-up, cup A might contain different amounts of a certain nutrient to see how it affects the growth of the plants. The dependent variable is what is measured, such as the growth rate of the plants. The control is kept the same (no experimental treatment) to keep the results reliable and to act as a comparison to the experimental results. This control is used to make sure that any changes in the dependent variable are due to the independent variable and not some other factor.

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Can you please explain the answer to 47.?

Answers

Answer:

The boiling point of water depends on the pressure exerted on its surface. At standard atmospheric pressure, which is about 101.3 kPa, water boils at 100°C (212°F).

However, in this case, the pressure on the surface of water is 30 kPa, which is lower than standard atmospheric pressure. As the pressure decreases, the boiling point of water also decreases.

To determine the boiling point of water at 30 kPa, we can use a steam table or a phase diagram of water. According to a steam table, at 30 kPa, the boiling point of water is approximately 35.3°C (95.5°F).

Therefore, if the pressure on the surface of the water is 30 kPa, the water will boil at approximately 30°C

how many moles of iron metal are produced when 3.2 mol iron (iii) oxide and 2.3 mol carbon monoxide react? fe2o3 3co -------> 2fe 3co2 step by step

Answers

Answer : When 3.2 moles of iron (III) oxide and 2.3 moles of carbon monoxide react, 2 moles of iron metal are produced.

2 moles of iron metal are produced when 3.2 moles of iron (III) oxide (Fe2O3) and 2.3 moles of carbon monoxide (CO) react. The balanced chemical equation for this reaction is: Fe2O3 + 3CO --> 2Fe + 3CO2.

This reaction is a combustion reaction, meaning it involves the oxidation of iron (III) oxide by the carbon monoxide. Oxygen from the iron oxide is released as carbon dioxide (CO2) and the iron is left in the reduced form, or elemental iron (Fe).

To calculate the moles of iron metal produced, the mole ratio of Fe2O3 to Fe must be determined. From the balanced equation, it can be seen that for every 1 mole of Fe2O3, 2 moles of Fe are produced. Therefore, to calculate the number of moles of Fe, multiply the number of moles of Fe2O3 by 2. In this case, that would be 3.2 moles of Fe2O3 x 2 = 6.4 moles of Fe.

Finally, to get the number of moles of Fe metal produced, subtract the number of moles of Fe2O3 from the number of moles of Fe. In this case, 6.4 moles of Fe - 3.2 moles of Fe2O3 = 2 moles of Fe metal.



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which of the combinations below will produce an insoluble salt? a) ba(oh)2 hcl b) mnso4 pb(no2)2 c) h2so4 albr3

Answers

The combination that will produce an insoluble salt is b) MnSO4 Pb(NO2)2.

A salt is a chemical compound made up of cations (positively charged ions) and anions (negatively charged ions) (negatively charged ions). The ions must be combined in such a way that the sum of the charges is zero. NaCl is the most well-known saltand it is made up of sodium cations (Na+) and chloride anions (Cl-).MnSO4 Pb(NO2)2 is the answer since both of these elements are soluble. MnSO4 is a soluble substance that is sometimes used in the production of ceramics.

MnSO4 is often used as a nutritional supplement for animals since it is a good source of manganese. Pb(NO2)2 is a powder that is bright yellow, it has a molar mass of 325.2 g/mol. It is made up of two NO2 anions (negatively charged ions) and one Pb2+ cation (positively charged ion).The formation of insoluble salts can occur when the cations and anions in a reaction solution bind to create a new solid. Since the newly formed solid is insoluble, it settles to the bottom of the solution and can be separated from the liquid through filtration. The insoluble salt that is formed is a white or colorless substance that appears as a powder.

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how many moles of oh- are in 55.85 ml of 0.350 m naoh? do not include units and place answers in 3 sig figs. be sure to include any zeros before the decimal and do not put answer in scientific notation.

Answers

The number of moles of OH- in 55.85 mL of 0.350 M NaOH is 0.01976 moles.

This can be calculated using the following equation:
the number of moles of OH- in 55.85 mL of 0.350 M NaOH is 0.01976 moles with 3 significant figures.
To determine the number of moles of OH⁻ present in 55.85 mL of 0.350 M NaOH, we use the formula;

Molarity = Moles of solute ÷ Volume of solution in L

It can be simplified to:

Molarity = Moles of solute ÷ (Volume of solution in mL ÷ 1000)Moles of solute = Molarity × (Volume of solution in mL ÷ 1000)

Thus, the number of moles of OH⁻ present in 55.85 mL of 0.350 M NaOH is given by;

Moles of OH⁻ = 0.350 M × (55.85 mL ÷ 1000) = 0.0196 moles

Therefore, there are 0.0196 moles of OH⁻ present in 55.85 mL of 0.350 M NaOH.

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if the rate constant for a reaction triples when the temperature rises from 25 oc to 65 oc, what is the activation energy of the reaction? give answer in kj/mole.

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The activation energy of the reaction, given that the rate constant has tripled when the temperature rose from 25 °C to 65 °C, is 42.6 kJ/mole.


Activation energy is the minimum energy required for a reaction to take place. It is calculated using the Arrhenius equation, which states that the rate constant, k, is proportional to the exponential of negative activation energy (Ea) divided by the gas constant (R) multiplied by the absolute temperature (T).

As the rate constant has tripled when the temperature increased, the activation energy can be calculated as Ea = -R * (1/T2 - 1/T1).

Plugging in the given temperature values of 25 °C and 65 °C and the gas constant, R, the activation energy is 42.6 kJ/mole.

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does any solid cu(oh)2 form when 0.075 g koh is dissolved in 1.0 l of 1.0 x 10 -3 m cu(no3)2? ksp of cu(oh)2

Answers

Yes, a solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2.  0.107 g of solid Cu(OH)2 will form.

First, we need to determine the amount of Cu2+ ions present in the solution:
1.0 x 10^-3 M Cu(NO3)2 means that there are 1.0 x 10^-3 moles of Cu2+ ions per liter of solution.
Next, we can use stoichiometry to determine the amount of OH- ions that will react with the Cu2+ ions to form Cu(OH)2. The balanced chemical equation for this reaction is:
Cu2+ (aq) + 2OH- (aq) → Cu(OH)2 (s)
For every 1 mole of Cu2+ ions, we need 2 moles of OH- ions. Therefore, the total amount of OH- ions needed to react with all of the Cu2+ ions in the solution is:
2 x 1.0 x 10^-3 mol = 2.0 x 10^-3 mol
Now we can use the Ksp of Cu(OH)2 to calculate the concentration of Cu2+ and OH- ions in the solution. The Ksp expression for Cu(OH)2 is:
Ksp = [Cu2+][OH-]^2
Since we know the Ksp value for Cu(OH)2, we can solve for either [Cu2+] or [OH-]. Let's solve for [OH-]:
Ksp = [Cu2+][OH-]^2
4.8 x 10^-20 = (1.0 x 10^-3 M)[OH-]^2
[OH-]^2 = 4.8 x 10^-17
[OH-] = 2.2 x 10^-9 M
Therefore, the concentration of OH- ions in the solution is 2.2 x 10^-9 M. Since we need 2 moles of OH- ions for every mole of Cu2+ ions, we know that the concentration of Cu2+ ions is half of the concentration of OH- ions:
[Cu2+] = 1.1 x 10^-9 M
Finally, we can use the molar mass of Cu(OH)2 to determine the mass of solid that will form:
Molar mass of Cu(OH)2 = 97.56 g/mol
1 mole of Cu(OH)2 is formed for every mole of Cu2+ ions, so the mass of Cu(OH)2 that will form is:
0.0011 mol x 97.56 g/mol = 0.107 g
Therefore, 0.107 g of solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2.

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A gas sample at constant pressure and temperature filled with Helium gas had a volume of 221 mL and 4.00 moles. If the volume is increased to 500 ml what is the number of moles of Helium gas that could occupy the container? 0.11 K 9.05 kPa 0.11 kPa 9.05 mol​

Answers

The number of moles of Helium gas that could occupy the container when the volume is increased to 500 mL is 9.05 mol.

What is the number of moles of the gas?

We can use the combined gas law to solve this problem:

(P1 x V1) / (n1 x T1) = (P2 x V2) / (n2 xT2)

where;

P is pressure, V is volume, n is number of moles, and T is temperature.

We know that the pressure and temperature are constant, so we can simplify the equation to:

V1/n1 = V2/n2

Solving for n2, we get:

n2 = (V2n1) / V1

Plugging in the values, we get:

n2 = (500 mL * 4.00 mol) / 221 mL

n2 = 9.05 mol

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which of the following is an appropriate use for reflux? to remove the solvent from a reaction mixture to carry out a reaction that needs heating to prepare a sample for filtration

Answers

A. to remove the solvent from a reaction mixture

What is a Flux?

Flux is a term used to describe the flow of energy, particles, or material in a given area. It is typically used to describe the rate of flow of a certain substance, such as the rate of electrons flowing through a circuit.

Flux is also used to describe the concentration of a certain substance in a given area. For example, the amount of a particular chemical in an environment can be described as a flux. Flux is also used to describe the rate of change in a given system, such as the rate of temperature change in a room over time.

Finally, flux can refer to the rate at which energy is exchanged between two objects, such as the rate of heat exchange between two objects.

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a solution of cacl2 cacl 2 in water forms a mixture that is 31.5% 31.5 % calcium chloride by mass. if the total mass of the mixture is 195.4 g, 195.4 g, what masses of cacl2 cacl 2 and water were used?

Answers

The masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.

The mass of calcium chloride (CaCl2):
The percentage of calcium chloride (CaCl2) in the mixture is 31.5%.


Multiply the total mass of the mixture (195.4 g) by 31.5% to find the mass of calcium chloride (CaCl2) in the mixture:
Mass of calcium chloride (CaCl2) = (195.4 g) x (31.5%) = 61.18 g

The mass of water:
Subtract the mass of calcium chloride (CaCl2) from the total mass of the mixture (195.4 g) to find the mass of water in the mixture:


Mass of water = (195.4 g) - (61.18 g) = 134.22 g

Therefore, masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.

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