what is the mass of 29.3 L of carbon monoxide at STP?

hey guys.. show. work.. i have no idea whats going on

Answer:

The correct answer is B.

Explanation:

The mass in the wax candle transforms into a gas that is released when burned, hence the lower mass after the reaction.

Burning a candle involves a chemical reaction in which the wax in the candle reacts with oxygen in the air to produce carbon dioxide and water vapor. During this reaction, some of the wax is transformed into a gas, which is released into the air. This means that the total mass of the reactants (wax and oxygen) is greater than the total mass of the products (carbon dioxide, water vapor, and unreacted oxygen), resulting in a lower mass after the reaction.

This is consistent with the Law of Conservation of Mass, which states that the total mass of the reactants is equal to the total mass of the products in a chemical reaction. However, it is important to note that in this case, the mass loss is due to the release of gas, rather than a violation of the law of conservation of mass.

The purpose of choosing two different metals as the reference to measure relative reduction potentials.

The process of determining the reduction potential of a metal necessitates the use of another metal for reference. A reference electrode with a well-known reduction potential is paired with the metal being studied as the working electrode to determine the reduction potential of the metal being studied.

There are a variety of reference electrodes available, but the standard hydrogen electrode is typically used as the reference electrode for electrochemical studies.

The standard hydrogen electrode's reduction potential has been calculated to be 0 volts. The reduction potential of a metal is a measure of the metal's tendency to gain electrons when it comes into touch with another substance. When a metal is oxidized or reduced, its reduction potential varies. As a result, when measuring reduction potentials, it is necessary to use two different metals as references.

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An ester is ethyl butyrate (C6H12O2), usually referred to as ethyl butanoate or butyric ether. In addition to function as a solvent, ethanol butyrate is often employed as an extractor, flavouring, or fragrance.

It is a flammable, colourless liquid with a smell of banana, orange, or pineapple. Alcoholic beverages contain the volatile ethyl ester ethyl butanoate, which saccharomyces produces during fermentation. When ethanol and a fatty acid interact, ethanol esters are created.

The chemical name for ethyl butyrate, popularly known as ethyl butanoate or butyric ether, is CH3CH2CH2COOCH2CH3. Kerosene, paraffin oil, and propylene glycol are all soluble in it. It is an important factor used as a taste enhancer in processed oranges and provides a delicious aroma comparable to banana.

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Answer:

The balanced chemical equation for the combustion of ethane (C2H6) is:

C2H6 + O2 → CO2 + H2O

According to the stoichiometry of the balanced equation, 1 mole of C2H6 reacts with 3 moles of O2 to produce 2 moles of CO2. Therefore, the ratio of moles of O2 consumed to moles of CO2 produced is:

3 mol O2 / 2 mol CO2

To determine how many moles of O2 are consumed per every 50 moles of CO2 produced, we can set up a proportion:

3 mol O2 / 2 mol CO2 = x mol O2 / 50 mol CO2

Cross-multiplying and solving for x, we get:

x = (3 mol O2 / 2 mol CO2) x 50 mol CO2 = 75 mol O2

Therefore, 75 moles of O2 are consumed per every 50 moles of CO2 produced during the combustion of ethane.

Explanation:

Plants that have evolved to surviving in aquatic settings are known as aquatic plants (saltwater or freshwater).

Aquatic plants offer a source of sustenance, a habitat, a way to get rid of carbon dioxide, and a way to make air through photosynthesis. Since they create sustenance for both themselves and the consumers or creatures in an environment, plants serve as its producers.

Aquatic plants do not require a solid stalk because of their buoyancy in the water. Instead, they are held erect by flotation devices like gas-filled stomata and intercellular spaces, which also allow them to develop toward the water's top and receive enough sunshine for photosynthesis.

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The concentration of the final solution, rounded to one significant figure, is 0.5 M.

To find the concentration of the final solution, we need to use the formula:

C1V1 = C2V2

where;

In this problem, we can plug in the given values and solve for C2:

C1 = 12 M

V1 = 20 mL = 0.02 L

V2 = 500 mL = 0.5 L

C1V1 = C2V2

(12 M)(0.02 L) = C2(0.5 L)

0.24 = 0.5C2

C2 = 0.48 M

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The most likely route to forming a cyclopentyl reagent from an amide would involve deprotonation of the amide with a strong base, such as lithium diisopropylamide (LDA), followed by treatment with an alkyl halide. The amide would be deprotonated, resulting in a carbanion that could be reacted with the alkyl halide, forming a new alkyl carbocation. A subsequent nucleophilic attack from a Lewis base, such as the conjugate base of the amide, would lead to formation of the cyclopentyl reagent.

This reaction can also be accomplished by a single-step procedure involving a Grignard reagent, such as ethylmagnesium bromide, and the amide. The Grignard reagent is deprotonated by the amide, and the resulting carbanion is reacted with the alkyl halide, resulting in a new alkyl carbocation. A subsequent nucleophilic attack from a Lewis base, such as the conjugate base of the amide, would lead to formation of the cyclopentyl reagent.

Therefore, the most likely route to forming the cyclopentyl reagent from the starting amide would involve deprotonation of the amide with a strong base followed by treatment with an alkyl halide. Alternatively, a single-step procedure using a Grignard reagent and the amide could also be used.

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The best summary of the given passage is Sumerians invented writing by drawing on soft pieces of clay because they needed some way to keep track of what they owned.

In the Mesopotamian areas, Sumer, an ancient civilization, was created. The area between the Euphrates and Tigris rivers is a fertile crescent.

They are well known for a variety of accomplishments, including their breakthroughs in the fields of language, government, architecture, and many others. The Sumerians are responsible for the contemporary human understanding of civilization.

The given text shows their contributions to drawing on soft pieces of clay which was their invention of writing.

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Which of the following is the best summary of the passage? Use the notes provided to guide you. Main Idea: The greatest gift the Sumerians gave the world was the invention of writing. Notes: Sumerians invented writing needed to keep records called cuneiform drew on clay tablets used shapes Sumerians The greatest gift the Sumerians gave the world was the invention of writing. The Sumerians were a wealthy people. They needed some way to keep track of what they owned. They began drawing pictures. They used a reed as a pen. They drew on soft pieces of clay. The soft clay was then dried in the sun. The tablet became a permanent record. Later, the Sumerian drawings changed into wedge-shaped symbols. This kind of writing is called cuneiform. By putting symbols together, the Sumerians could write entire sentences.

The correct option is D: each successive ionization requires increasing amounts of energy

The ionization energy of an atom is the energy that is required to remove an electron from the atom or a positive ion that is produced from the atom.

When an atom loses its electron, the ion that is produced is positively charged. Successive ionization energies are the amount of energy required to remove the next electron after the first electron is removed.

Each successive ionization requires increasing amounts of energy. The first ionization energy is the energy required to remove the first electron.

After the first electron is removed, the number of electrons that are left is less, so the remaining electrons experience more attraction to the nucleus.

So, the amount of energy required to remove the second electron is more than the amount required to remove the first electron.

Similarly, as we go on removing electrons, the energy required to remove each electron continues to increase.

So, the correct option is d) each successive ionization requires increasing amounts of energy.

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Therefore, 0.2062 mol of NO can be produced from 3.3 g of O2. In order to determine the number of moles of NO that can be produced from 3.3 g of O2.

2NO + O2 → 2NO2 From the balanced equation, we can see that the stoichiometric ratio between O2 and NO is 1:2. This means that for every one mole of O2 that reacts, two moles of NO are produced.

To calculate the number of moles of O2 present in 3.3 g, we need to use the molar mass of O2, which is 32.00 g/mol:

moles of O2 = mass of O2 / molar mass of O2

moles of O2 = 3.3 g / 32.00 g/mol

moles of O2 = 0.1031 mol

Now, we can use the stoichiometric ratio to determine the number of moles of NO produced:

moles of NO = 2 x moles of O2

moles of NO = 2 x 0.1031 mol

moles of NO = 0.2062 mol

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Answer:

0.0415mol

Explanation:

C = n/v

n= 4.15ml x 10

n = 41.5mml

Everyone is aware that the first billion years of Earth's existence were marked by intense volcanic activity. Because of the circumstances, there were so many gases in our atmosphere that life could not exist there (Very similar like the atmosphere of Mars & Venus of today).

Carbon dioxide was most prevalent, whereas oxygen was scarce. Next, the modifications that affected the ratio of gases were:

1) To increase oxygen levels. "Photosynthesis by Plants" was the sole and most significant source of increasing oxygen.

2) In order to reduce carbon dioxide. - I Absorbable by plants for the photosynthesis process.

(ii) The majority of the CO2 is dissolved in the oceans, and a large portion of it is trapped in sedimentary rocks like limestone and fossil fuels.

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1.8 is the pH during the titration of 20.00 mL of 0.1000 M HCOOH (formic acid) with 0.1000 M NaOH (aq) after 19.55 mL of the base have been added

This can be calculated using the equation below:

pH = -log10([H+])

Where [H+] is the concentration of H+ ions, given by the formula:

[H+] = Ka * [HCOOH] / (Ka + [NaOH])

Ka is the acid dissociation constant of formic acid, which is 1.7 × 10-4.

Using the above equation and data, we can calculate the pH during the titration of 20.00 mL of 0.1000 M HCOOH with 0.1000 M NaOH after 19.55 mL of the base have been added as follows:

[H+] = 1.7 x 10-4 * 0.1000 / (1.7 x 10-4 + 0.1000) = 0.0156 M

Therefore, pH = -log10 (0.0156) = 1.8

Hence , the pH during given titration is 1.8 .

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Answer: 3 hydrogen Atoms

Answer:3 atoms

Explanation:

Answer:

2.481cm³

Explanation:

this is general has equation so the formula is

P1V1/T1 = P2V2/T2

At STP, pressure is 1.01*10⁵ and temperature is 273K

((1.20*10³)400)/(250+273) = ((1.01*10⁵)V2/(273)

V2 = 2.481cm³

Answer:

When this mixture is supplied at a total pressure of 7.8 atm, the partial pressure of oxygen will be 0.0198 atm.

The amount of pressure that each gas in a mixture exerts is referred to as "partial pressure." This is found by using the formula, Partial pressure = Mole fraction × Total pressure.

Explanation:

Answer:

Option D is the answer of this question

Explanation:

0.100 L

The total molar mass of hydrogen in 8 moles of water is 16 g/mole.

1 molecule of water contains 2 atoms of H and 1 atom of O.

What is molar mass?

The ratio between the mass and the substance content (measured in moles) of any sample of a chemical compound is known as the molar mass (M). The molar mass of a substance is a bulk attribute rather than a molecular one. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.

The molar mass is a crucial characteristic of the material that is independent of sample size. The coherent unit of molar mass in the International System of Units (SI) is kg/mol.

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Explanation:

The reaction between magnesium ribbon and dilute hydrochloric acid is a classic example of a single replacement reaction, which can be represented by the following chemical equation:

Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)

In this reaction, magnesium (Mg) reacts with hydrochloric acid (HCl) to form magnesium chloride (MgCl2) and hydrogen gas (H2).

The rate of this reaction can be altered by changing the concentration of the hydrochloric acid. This is because the rate of a chemical reaction depends on the concentration of the reactants. Specifically, the rate of the reaction is proportional to the concentration of the reactants raised to some power, which is determined by the reaction's rate law.

In this reaction, the rate law can be expressed as:

Rate = k [Mg] [HCl]^x

Where k is the rate constant and x is the order of the reaction with respect to hydrochloric acid. The order of the reaction with respect to magnesium is one, since the concentration of magnesium does not change during the reaction.

When the concentration of hydrochloric acid is increased, the rate of the reaction increases because there are more hydrochloric acid molecules available to collide with magnesium atoms and react. This means that the value of x is greater than zero and the reaction is dependent on the concentration of hydrochloric acid.

Conversely, when the concentration of hydrochloric acid is decreased, the rate of the reaction decreases because there are fewer hydrochloric acid molecules available to react with magnesium. This means that the value of x is less than one and the reaction is not entirely dependent on the concentration of hydrochloric acid.

We need to add 0.57 mL of E. coli to 1.13 mL of diluent.

To make a 1/3 dilution of E. coli, we need to dilute it 1 part in 3. This means that the final volume of the diluted sample will be 3 times the original volume of the E. coli.

To make a 1/3 dilution of e. coli if you had a tube of diluent with a volume of 1.7 ml, we need to follow the given steps:

First, calculate the volume of bacterial culture you need to add:

The volume of bacterial culture = 1/3 × 1.7 = 0.5667 ml. (rounded off to 4 decimal places)

Use a micropipette to take out 0.5667 ml of the culture to a new tube.

Now, add 1.7 - 0.5667 = 1.1333 ml of the diluent into the new tube to get a 1/3 dilution of E. coli. (rounded off to 4 decimal places)

Mix the dilution thoroughly.

Label the tube appropriately. 

It is important to label the tube with the contents inside the tube so that it does not cause any confusion with other tubes or in the future when someone is trying to use it.

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To prepare a 0.40M solution using 90.0g of Kool-Aid, we would need to dissolve the Kool-Aid in 657.5 mL of water.

How to determine the volume of water needed to prepare a 0.40M solution using 90.0g of Kool-Aid?

To determine the volume of water needed to prepare a 0.40M solution using 90.0g of Kool-Aid, we need to know the molar mass of Kool-Aid and the desired volume of the final solution.

Since Kool-Aid is a mixture of various compounds, we do not have a single molar mass value for it. However, we can estimate its average molar mass by assuming that the main component of Kool-Aid is sugar (sucrose), which has a molar mass of 342.3 g/mol.

Assuming that the Kool-Aid powder is 100% sucrose, we can calculate the number of moles of Kool-Aid present in 90.0 g as follows:

number of moles = mass

/ molar mass

number of moles = 90.0 g / 342.3 g/mol

number of moles = 0.263 mol

To prepare a 0.40M solution using this amount of Kool-Aid, we need to dissolve it in a volume of water that will result in a final solution with a total volume of 1 L (1000 mL) and a concentration of 0.40 mol/L. We can calculate the required volume of water as follows:

moles of Kool-Aid = concentration x volume

0.263 mol = 0.40 mol/L x volume

volume = 0.263 mol / 0.40 mol/L

volume = 0.6575 L = 657.5 mL

Therefore, to prepare a 0.40M solution using 90.0g of Kool-Aid, we would need to dissolve the Kool-Aid in 657.5 mL of water.

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The theoretical yield of CuO is 0.403 g.

To calculate the theoretical yield, the first step is to determine the limiting reactant, which is the reactant that is completely consumed and thus limits the amount of product that can be formed. To do this, we need to compare the amounts of CuBr₂ and NaOH that are available, and determine which one will be used up first.

The balanced chemical equation tells us that 1 mole of CuBr₂ reacts with 2 moles of NaOH to produce 1 mole of CuO. From the given amount of CuBr₂ (0.700 g), we can convert to moles using the molar mass of CuBr₂ (223.36 g/mol):

0.700 g CuBr₂ x (1 mol CuBr2/223.36 g CuBr₂) = 0.00313 mol CuBr₂

From the amount of NaOH (not given), we can assume that there is excess NaOH, meaning that all of the CuBr2 will react and the NaOH will not be completely consumed. Therefore, we can use the amount of CuBr2 to calculate the theoretical yield of CuO:

0.00313 mol CuBr₂ x (1 mol CuO/1 mol CuBr₂) x (79.55 g CuO/mol) = 0.403 g CuO

Therefore, the correct answer is 0.403 g.

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Answer:Let x be the oxidation station of sodium in Na

2

​

O

2

​

.

It contains a peroxide linkage in which each O atom has the oxidation number of -1.

2x+2(−1)=0

x=+1

Thus, the oxidation state of sodium in Na

2

​

O

2

​

 is +1.

Options A, B, D and E are solutions. Among all the solutions, sterling silver, egg white and rubbing alcohol are solvents and chocolate milk is a primary solute.

A solvent is defined as a substance that dissolves a solute resulting in a solution. A solvent is generally of a liquid but can also be a solid, a gas, or a supercritical fluid. A solute is defined as a substance that will dissolve into a liquid. Sterling silver is a solution and it is solvent. Chocolate milk is a solution and considered as solute. Egg white is called as an alkaline solution and contains around 149 proteins. This can be used as a favorable solvent for extracting the active ingredient. Rubbing alcohol is a solution and considered as a solvent.

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The molarity (M) of a solution is defined as the number of moles of solute dissolved in one liter of solution. the molarity of the solution is 0.744 M.

We can use the formula:

M = moles of solute / volume of solution (in liters)

to calculate the molarity of the solution.

Given that 0.45 moles of solute are dissolved to make 605.0 mL of solution, we first need to convert the volume to liters by dividing by 1000:

605.0 mL / 1000 mL/L = 0.605 L

Now we can use the formula to calculate the molarity:

M = 0.45 moles / 0.605 L = 0.744 M

Molarity is a commonly used unit of concentration in chemistry, and it represents the number of moles of solute present in one liter of solution. Molarity is a useful way to express the concentration of a solution because it is independent of temperature and pressure, and it is directly proportional to the amount of solute present in the solution.

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The ratio of the volume and temperature of the gas in the given table is as follows:

Charles's law, also known as the law of volumes, describes the relationship between the volume and temperature of a gas at a constant pressure. According to this law, the volume of a gas is directly proportional to its absolute temperature (measured in Kelvin) when the pressure is constant.

In other words, as the temperature of a gas increases, its volume will also increase proportionally, and vice versa. Mathematically, Charles's law can be expressed as:

V/T = k

where V is the volume of the gas, T is its temperature in Kelvin, and k is a constant of proportionality.

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The correct electron configuration for Cl in noble-gas notation is option D, [Ne]₃s²³p⁵.

This notation indicates that the electron configuration of Cl is the same as that of the noble gas neon ([He]₂s²²p⁶), except for the three additional electrons in the 3rd shell, occupying the 3s and 3p orbitals.

The electron configuration for Y in noble-gas notation can be determined by finding the noble gas that precedes Y in the periodic table, which is Kr. The electron configuration for Kr is [Ar]₃d¹⁰⁴s²⁴p⁶

Yttrium (Y) has an atomic number of 39, which means it has 39 electrons. The electron configuration for Y in noble-gas notation is therefore:

[Kr]₅s²⁴d¹

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The amount of benzene in the sample that burned was [tex]4.14*10^{26}[/tex] molecules.

The molecular weight of benzene is 78.11 g/mol. This means that the number of moles of benzene in the sample can be calculated by dividing the mass of the sample (522 liters of CO2 is approximately 522 kg at STP) by 78.11 g/mol.

The number of moles of benzene in the sample can then be used to calculate the number of benzene molecules. This is given by the equation:

Number of benzene molecules = Number of moles x Avogadro's Constant

The number of benzene molecules in the sample that underwent combustion is:

Number of benzene molecules

[tex]=\frac{ 522 kg }{ 78.11 g/mol} * 6.02 * 10^{23} molecules/mol\\\\= 4.14 * 10^{26 }molecules[/tex]

Therefore,[tex]4.14*10^{26}[/tex] molecules of benzene molecules were in the sample that underwent combustion.

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