What is the mass of 32.1 mL the density of copper is 8.96 g/mL

Answers

Answer 1

Answer:

288 g.

Explanation:

Measurements => Density.

Density is the ratio of the mass of an object to its volume:

[tex]D=\frac{m}{V},[/tex]

where D is density, m is mass, and V is volume.

We have two data: the volume (32.1 mL) and the density (8.96 g/mL) and we need to find the mass.

We can solve for 'm' in the given equation and replace the given data, as follows:

[tex]\begin{gathered} m=D\cdot V, \\ \\ m=8.96\frac{g}{mL}\cdot32.1\text{ mL,} \\ \\ m=287.6\text{ g}\approx288\text{ g.} \end{gathered}[/tex]

The answer would be that the mass is 288 g.


Related Questions

0.650 moles of O₂(g) are added to 1.00 L flask and the internal pressure ismeasured at 20.00 atm. What is the temperature of the gas under theseconditions (in *C)? ________ °C?

Answers

1) List the known and unknown quantities.

Sample: O2

Amount of substance: 0.650 mol O2.

Volume: 1.00 L.

Pressure: 20.00 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1)

Temperature: unknown.

2) Set the equation.

Ideal gas law.

[tex]PV=nRT[/tex]

3) Plug in the known quantities and solve for T.

[tex](20.00\text{ }atm)(1.00\text{ }L)=(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(T)[/tex][tex]T=\frac{(20.00atm)(1.00L)}{(0.650\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}[/tex][tex]T=374.97\text{ }K[/tex]

4) Convert K to ºC.

[tex]ºC=K-273.15[/tex][tex]ºC=374.94-273.15[/tex][tex]ºC=101.81\text{ }ºC[/tex]

The temperature of the gas under these conditions is 101.81ºC.

.

How many moles of atoms are in 7 g of 13C

Answers

Answer:

Explanation:

molar mass of 13c = 13 grams

number of moles = mass / molar mass

therefore,

number of moles = 7 / 13

To know the number of atoms in 7/13 moles, we simply multiply the number of moles by Avogadro's number as follows:

number of atoms = (7/13) x 6.022 x 10^23 = 3.2426 x 10^23 atoms

PLEASE HELP, IT’S DUE TODAY!
Isotopes of certain ___ elements that spontaneously emit ____ and ____ from the _____.

Answers

Isotopes of certain __radioactive__ elements that spontaneously emit __radiation__ and _rays___ from the __nuclei____

What causes isotopes to emit radiation ?

Any of multiple species of the same chemical element with differing masses whose nuclei are unstable and spontaneously produce radiation in the form of alpha, beta, and gamma rays are known as radioactive isotopes, also known as radioisotopes, radionuclides, or radioactive nuclides.

Isotopes are identical elemental atoms with differing quantities of neutrons. Numerous elements have one or more radioactive isotopes. Due to the instability of their nuclei, they decay and release radiation.

Many of the radioisotopes in the uranium, thorium, and actinium natural radiation decay series, as well as the naturally occurring radioisotopes potassium-40 and carbon-14, generate gamma radiation.

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Which of the listed species have the following electron configuration?
(See attached)

Answers

Answer:

Al 3+

Na+

Mg2+

F-

Explanation:

The element with the given electron that isn't an ion is Neon. It has 10 electrons in total.

Looking at the periodic table attached will help to see how the elements below are related to the one circled in red (Ne).

Al 3+ lacks 3 (because it has a 3+ charge) of its normal electrons so it has 10 and will have the same electron configuration as shown.

Na+ lacks one electron so it will also have 10 electrons instead of its normal 11.

Mg 2+ lacks two electrons so it will also have 10 total electrons.

F- has gained an extra electron so it now has 10 instead of 9.

Al3+, Na+, F-, and Mg2+ will have the given electronic configuration.

The electronic configuration given in the question is:

2p6, 2s2, 1s2

If it was a stable atom, the answer would have been Neon.

And if that would have been negative ion or anion (to be precise),

the answer would have been either F- or O2-.

But in the case of positive ions or we can say cations,

Al3+, Na+, and Mg2+ have the given electronic configurations.

Because the atom of Aluminum loses three electrons to achieve another state which is responsible for the formation of Al3+.

Similarly,

The atoms of Sodium and Magnesium also lose one and two electrons respectively to form Na+ and Mg2+.

So, we can conclude that Al3+, Na+, F- and Mg2+ will have the given electronic configuration.

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how many grams of CO2 are in 5.67 moles of CO2

Answers

Mass=relative atomic mass•number of mole —> 5.67•(12+16+16)=249.48≈249g

The International System of Units uses the mole (symbol: mol) as the unit of substance amount.

In 5.67 moles of CO2 there exists 249.48 grams of CO2.

How to calculate grams in moles?

Start by dividing the number of atoms by the atomic weight of each component of the compound to convert grams to moles. After that, tally up all of your responses to determine the compound's molar mass. The final step is to calculate the number of moles by dividing the number of grams of the compound by its molar mass.

The International System of Units uses the mole (symbol: mol) as the unit of substance amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that substance.

Let the equation be

Mass = relative atomic mass × mole number

substitute the values in the above equation, we get

= 5.67 × (12 + 16 + 16)  

= 249.48 g

Therefore, there exists 249.48 grams of CO2 are in 5.67 moles of CO2.

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According to the label on a soft drink, one serving provides 185 kcal. If all of this energy is used to lift 1.0-kg blocks, how many blocks can be lifted 7.0 meters? Note: 1 J is approximately equal to the energy required to raise a 1-kg block a distance of 10 cm against Earth’s gravity.

Answers

The number of blocks that can be lifted through this height is 11563 blocks.

How many blocks can be lifted?

We know that we define the term energy as the ability to do work, Now we have to consider the fact that we are told that one serving provides 185 kcal. Then we are told that  all of this energy is used to lift 1.0-kg blocks through a distance of  7.0 meters.

Given that the energy exerted in lifting each block is;

mgh

m = mass of the block

g = acceleration due to gravity

h = height lifted through

E = 1.0-kg * 9.8 m/s^2 * 7.0 meters = 68.6 J or 0.016 kcal

The number of blocks that can be lifted =  185 kcal/ 0.016 kcal

= 11563 blocks

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Two different signs that indicate a chemical action has occurred. What time is showing in the picture on the left what sign is showing on the picture in the right?

Answers

The reaction that occurs on the left is called a single displacemt reaction

Which choice is an element?
carbon dioxide
carbon
water
air

Answers

carbon dioxide and water

Answer:

Explanation:

Carbon is the only element listed. Carbon Dioxide consists of Carbon AND Oxygen x2 so this is a compound. As stated earlier, air is a mixture of compounds. Water is another compound consisting of Hydrogen x2 and Oxygen.

balanced chemical equation for .1 M barium nitrate and .1 m sodium sulfate

Answers

The balanced chemical equation for 0.1 M barium nitrate and 0.1 M sodium sulfate is -

2 Ba(NO₃)₂ + 2 Na₂SO₄   →   2 Ba(SO₄) + 2 NaNO₃

Balanced chemical equation are the equations having equal amount of reactants and the products formed. The reactants are placed on the left and products are placed on right forming a balanced chemical equation.

When 0.1 M barium nitrate reacts with the 0.1 M sodium sulfate, it gives an insoluble salt of barium sulfate and soluble salt of sodium nitrate as the product. This reaction is a type of precipitation reaction as precipitate is formed in the reaction. It is a double displacement reaction because the sulfate ions replace the nitrate ions to give the product.

Barium sulfate is known to be the most insoluble compound. It is formed as a precipitate.

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# 19. Write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.

(a) Write the correct formulas for the molecular equation (b) balance the equation (c) identify the spectator ions (d) Write the ionic equation and (e) Write the net ionic equation.

Answers

The general molecular equation is; [tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex] while the net ionic equation is; [tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

What is a reaction?

We can define the term reaction as the interaction that occurs between the reactants and helps us to be able to get a product as shown. Now we have a case in which we are asked to write the molecular, ionic and net ionic equation, with the phases of matter for the reaction between Barium acetate + Sodium phosphate --> Barium phosphate + Sodium acetate.

The task now is to make use of the ideas that we have from the question to be able to determine both the molecular reaction equation as well as the net ionic equation as required.

Let us no take the reaction individually. We can write the molecular reaction as;

[tex]Ba(CH3COO)_{2} (aq) + Na_{3} PO_{4} ------ > Ba_{3} (PO_{4})_{2} (s)+ Na(CH3COO)_{2} (aq)[/tex]

After we have written the molecular reaction equation, then we can identify the spectator ions as  acetate ion and the sodium ion as we can see from the balanced reaction equation.

The net ionic equation therefore is;

[tex]2PO_{4} }^{3-} (aq) + 3Ba^{2+ } (aq) ------- > Ba_{3} (PO_{4})_{2} (s)[/tex]

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Find the molecular formula for a compound that contains 4.90 % N and 11.2 % O. The molecular mass of the compound is 92.0 g/mol.

Answers

The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄

How to determine molecular formula

We'll begin by obtaining the empirical formula for the compound. This is illustrated below:

Nitrogen (N) = 4.90 gOxygen (O) = 11.2 gEmpirical formula =?

Divide by their molar mass

N = 4.9 / 14 = 0.35

O = 11.2 / 16 = 0.7

Divide by the smallest

N = 0.35 / 0.35 = 1

O = 0.7 / 0.35 = 2

Thus, the empirical formula of the compound is NO₂

Finally, we shall determine the molecula formula. Details below

Molar mass of compound = 92 g/molEmpirical formula = NO₂Molecular formula =?

Molecular formula = empirical × n = molar mass

[NO₂]ₙ = 92

[14 + (16×2)]ₙ = 92

46n = 92

Divide both side by 46

n = 92 / 46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

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Complete question:

Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.

Predict the shape of the molecule around the indicated atom.

Answers

Answer:

Linear (180 degrees)

Explanation:

Whenever you have a triple bond between two atoms, their shape is linear. This is because the density of the triple bond between them is heavy, causing the other things attached to the atom to be as far away as possible, creating a linear structure.

Some hydrogen and iodine are mixed at 229 degrees Celsius in a 1.00L container. When equilibrium is established, the following concentrations are present: [HI] = 0.490 M, [H2] = 0.080 M, [I2] = 0.060 M. If an additional 0.300 mol of HI is then added, what concentration will be present when the new equilibrium is established?

Answers

The concertation of the HI that would be present in the new equilibrium position is 0.15 M.

What is the new equilibrium position?

We have to first obtain the equilibrium constant that we have under the initial conditions and then we have; H2 + I2 ------> 2HI

K = [HI]^2/[H2] [I2]

K = (0.490)^2/(0.080) (0.060)

K = 0.2401/(0.080) (0.060)

K = 50

Again;

                               H2      +      I2                     ------> 2HI

Initial                     0.080           0.060                        0.060

concentration         +x                   +x                            -2x

Equilibrium     0.080 + x      0.060 + x                 0.490 - 2x

50 = (0.490 - 2x)^2/( 0.080 + x) (0.060 + x)

Working through the quadratic we have;

46x^2 + 10.2 x - 0.38 = 0

x = 0.32 M

In each case we now have;

 H2 =  0.080 +  0.32  = 0.4 M

[I2] = 0.060  +  0.32  = 0.38 M

[HI] = 0.790 - 2( 0.32 ) = 0.15 M

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How many pounds in 16.1lbmol of pure HCl

Answers

Answer:

586.846 lbs

Explanation:

the molar mass of HCl is 1 + 35.45 = 36.45

this means you can do 16.1 lbmol * 36.45 lb/lbmol = 586.845

NaCl + _Cal2 → Nal + CaCI2

Answers

Answer

2NaCl + Cal₂ → 2Nal + CaCI₂

Explanation

Given unbalanced equation;

NaCl + _Cal₂ → Nal + CaCI₂

Step 1: Balance the Cl atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaCl in the reactant side.

2NaCl + _Cal₂ → Nal + CaCI₂

Step 2: Balance the Na atom on both the reactant and product sides of the equation by putting 2 as the coefficient of NaI in the product side.

2NaCl + Cal₂ → 2Nal + CaCI₂

Therefore, the balanced equation is: 2NaCl + Cal₂ → 2Nal + CaCI₂

explain the process of photosynthesis with these

Words:
Photosynthesis,
light,
water,
energy,
Carbon Dioxide,
Oxygen,
xylem,
stomata,
Sugar(Glucose),
phloem,
chloroplasts,
leaves,
roots

Be legible and neat please and thank you

Answers

The process of photosynthesis used by plant in which they produce sugar ( glucose ).

Photosynthesis is the process in which plants produced sugar by using sun - light , water and carbon dioxide. In the process of photosynthesis plants use carbon dioxide ( CO₂ ) and water H₂O from the air and the soil  then this carbon dioxide and water transforms to oxygen and sugar (glucose). the oxygen produced by plant back into the air and the sugar produces stores by the plant as the form of energy.

                                                sunlight

carbon dioxide  +   water       -------------->     glucose   +   oxygen

In the leaf cell a part called chloroplast in it energy in sunlight used to break oxygen and hydrogen. T he water required in the process of photosynthesis taken by the roots from soil and then it transport with the help of xylem cell to the different parts of plant. phloem takes sugar from leaves to different parts of plant. The stomata is for the transpiration exchange that means it takes carbon dioxide and the release oxygen back to air after the photosynthesis end.

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What are the products of the neutralization reaction between HNO3 andCa(OH)2?OA. CaO, NO₂, and H₂OB. Ca3N₂ and H₂OOC. Ca(NO3)2 and H₂OOD. CaNO3 and H30+

Answers

Answer:

Ca(NO3)2 and H₂O. Option C is correct

Explanations:What is a neutralization reaction?

The combination of acid and base to form salt and water at the product is known as a neutralization reaction.

Hence the products of the neutralization reaction between HNO3 and Ca(OH)2 must be salt and water

From the given option, the equivalent product that are salt and water is Ca(NO3)2 and H₂O which gives the required product.

DUE IN 9 MINUTES HELP
The reaction written below has a ΔH of +2,962 kJ/mol


6CO2(g) + 6H2O(g) --> C6H12O6(g) +6O2(g)


How much energy must be input into this reaction to make 58.9 grams of C6H12O6(g) ?

Answers

The amount of heat energy that must be inputted into the reaction to make 58.9 grams of C₆H₁₂O₆ is 968.574 KJ

How to determine the amount of heat energy

We'll begin by obtainig the number of mole of 58.9 grams of C₆H₁₂O₆. This can bbe obtained as follow:

Mass of C₆H₁₂O₆ = 58.9 grams Molar mass of C₆H₁₂O₆ = (6 × 12) + (12 × 1) + (16 × 6) = 180 g/molMole of C₆H₁₂O₆ =?

Mole = mass/ molar mass

Mole of C₆H₁₂O₆ = 58.9 / 180

Mole of C₆H₁₂O₆ = 0.327 mole

Finally, we shall determine thhe heat energy needed.

The balanced equation for the reaction is given below:

6CO₂(g) + 6H₂O(g) → C₆H₁₂O₆(g) + 6O₂(g) ΔH = +2962 KJ/mol

From the balanced equation for above,

1 moles of C₆H₁₂O₆ was produced by 2962 KJ of heat energy.

Therefore,

0.327 mole of C₆H₁₂O₆ will be produce by = (0.327 × 2962) / 1 mole = 968.574 KJ of heat energy

Thus, 968.574 KJ of heat energy is needed for the reaction

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500 ml of an unknown concentration of KOH solution and 250 ml of 0.01 ml were mixed KOH solution.
The pH of the resulting solution is 12.7. Calculate the concentration of the first KOH solution.

Answers

Answer:

262

Explanation:

A 25.0 mL solution of HNO₃ is neutralized with 31.4 mL of 0.250 M Ba(OH)₂. What is the concentration of the original HNO₃ solution?

Answers

The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3

The neutralization reaction involved with HNO₃ and Ba(OH)2 is

Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.

From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)

By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values

Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles

Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃

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find the natural logarithm of7.56

Answers

2.0228711901914416
In a graph:

Select the answer that correctly describes the masses the subatomic particles from lightest to having.

Answers

1) Subatomic particles. Atoms are made up of smaller parts called subatomic particles. Proton, neutron, and electron are some of them.

Electron: 9.11*10^-31 kg.

Proton: 1.672 18*10^-27 kg.

Neutron: 1.674 93*10^27 kg.

The lightest subatomic particle is the electron, then comes the protons, and finally the electron.

Given the following equation, if I make 18.5G of iron (III) sulphate, what is the percent yield? I picked B but I’m not sure if I’m correct

Answers

Answer:

B. The percent yield is 55.9%.

Explanation:

From the balanced reaction we know that 2 moles of FePO4 produce 1 mole of Fe2(SO4)3.

1st) It necessary to convert moles into grams, using the molar mass of FePO4 (151g/mol) and the molar mass of Fe2(SO4)3 (400g/mol):

- FePO4 conversion:

[tex]2moles*\frac{151g}{1mole}=302g[/tex]

- Fe2(SO4)3 conversion:

In this case, it is not necessary the conversion, because there is 1 mole, so it is equal to 400g.

Now we know that 302g of FePO4 produce 400g of Fe2(SO4)3.

2nd) Now we have to calculate the Theoretical yield of Iron (III) sulfate, that is, the amount of Iron (III) sulfate that we must produce from 25g of Iron (III) phosphate:

[tex]\begin{gathered} 302gFePO_4-400gFe_2(SO_4)_3 \\ 25gFePO_4-x=\frac{25gFePO_4*400gFe_2(SO_4)_3}{302gFePO_4} \\ x=33.11gFe_2(SO_4)_3 \end{gathered}[/tex]

So, the Theoretical yield is 33.11g.

3rd) Finally, we can calculate the Percent yield using the Theoretical yield (33.11g) and the Actual yield (18.5g):

[tex]\begin{gathered} PercentYield=\frac{ActualYield}{TheoreticalYield}*100\% \\ PercentYield=\frac{18.5g}{33.11g}*100\% \\ PercentYield=55.9\% \end{gathered}[/tex]

So, the percent yield is 55.9%.

For the following equations you will be given the names of reactants and products. In the space below each reaction provide theformulas of each reactant and product along with coefficients.

Answers

Explanation:

First, let's write the formulas:

Potassium chlorate: KClO3

Oxygen: O2

Potassium chloride: KCl

So the reaction will be:

KClO3 -> O2 + KCl

Now let's balance it.

To balance the equation it is necessary to have the same number of atoms of each element on both sides of the equation (reactant side and product side). Let's count the number of atoms of each element for the unbalanced equation: KClO3 -> O2 + KCl

Reactant side:

K - 1

Cl - 1

O - 3

Product side:

O - 2

K - 1

Cl - 1

As you can see, oxygen number of atoms is not equal on both sides of the equation. Let's balance it by changing the stoichiometric coefficient.

2KClO3 → 2KCl + 3O2

Let's count the number of atoms of each element for the balanced equation.

Reactant side:

K - 2

Cl - 2

O - 6

Product side:

K - 2

Cl - 2

O - 6

Now the equation is balanced.

Answer: 2KClO3 → 2KCl + 3O2

Coefficients are: 2, 2 and 3.

Light below the necessary critical frequency doesn't eject electrons from metal because

Answers

Light below the necessary critical frequency doesn't eject electrons from metal because no electrons will be emitted when the light shines on the metal.

What is Frequency?

This is a term in physics which is used to describe the number of occurrences of a repeating event per unit of time.

The amount of energy which is present in each photon in the beam is determined by and proportional to the frequency of the beam. This therefore means that if there is light which is below the threshold frequency, there will be no electrons emitted when light shines on the metal thereby making it the correct choice.

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Limestone is a sedimentary rock composed largely of the mineral calcite, (calcium carbonate) CaCO3. To test the purity of the calcium carbonate, a sample of the mineral is reacted with hydrochloric acid to produce calcium chloride, carbon dioxide and water If a 15.70 g sample of calcite is reacted with excess hydrochloric acid and 16.89 g of calcium chloride are produced, what is the percent by mass of the calcium carbonate in the limestone? A) 69.4% B)93.0 % C) 96.94% D)98,22 %

Answers

Answer:

[tex]C\text{ : 96.94 \%}[/tex]

Explanation:

Here, we want to get the percentage by mass of calcium carbonate in the limestone

We start by writing an equation of chemical reaction

The reaction involves calcium carbonate reacting with hydrochloric acid to give calcium chloride, carbon dioxide and water

We have the equation as follows:

[tex]\text{CaCO}_{3(s)\text{ }}+2HCl_{(aq)}\rightarrow CaCl_{2(aq)\text{ }}+CO_{2(g)\text{ }}+H_2O_{(l)}[/tex]

Now, let us work with the extra information

16.89 g of calcium chloride are produced

Let us get the number of moles of calcium chloride produced

We can get that by dividing the mass by the molar mass of calcium chloride

The molar mass of calcium chloride is 111 g/mol

So, the number of moles will be:

[tex]\frac{16.89}{111}\text{ = 0.1522 mole}[/tex]

From the equation,

1 mole of calcite gave 1 mole of calcium chloride, then 0.1522 mole of calcium chloride was produced by 0.1522 mole of calcite

To get the mass of calcite that produced this, we have to multipply the number of moles by the molar mass of calcite

The molar mass of calcite is 100 g/mol

That means the mass of calcite that produced the calcium chloride will be:

[tex]0.1522\text{ }\times\text{ 100 = 15.22 g}[/tex]

What this mean is that 15.22 g of calcite produced the given mass of calcium chloride

The percentage by mass of calcite in the limestone will be:

[tex]\frac{15.22}{15.70}\times\text{ 100\% = 96.94 \%}[/tex]

2.65 moles of an ideal gas at 36.9oC and 40,205Pa occupy 54.7mL. Additional gas is added to this container such that the temperature and pressure change to 113.7oC and 131,874Pa, with the volume remaining the same. How many moles of this gas were added?


Answers

The moles of gas added could not be determined because of an apparent error in the data provided for the volume of the container.

What is the number of moles of gas in the container?

The moles of gas in the container is calculated from the ideal gas equation as follows;

PV = nRTn = PV / RT

Data given:

P = 131,874 Pa or 131.874 kPa

V = 54.7 mL = 0.0547 L

T = 113.7 °C or (113.7 + 273) K

T = 386.7 K

R, molar gas constant  = 8.314 L⋅kPa.K/mol

n = (131.874 * 0.0547 L) / (8.314 * 386.7 )

n = 0.000224 moles

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What volume of carbon dioxide (in L) will 2.00 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction?
CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Answers

The volume of carbon dioxide (in L) that can be made from the 2.00 g of the antacid is 5.09 L

How to determine the volume of CO₂

We'll beging by obtaining the mole of CO₂ produced. This can be obtained as follow:

Mass of CaCO₃ = 2 gMolar mass of CaCO₃ = 100 g/mole Mole of CaCO₃ = 2 / 100 = 0.02 mole

CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

From the balanced equation above,

1 mole CaCO₃ reacted to produce 1 mole of CO₂.

Therefore,

0.02 mole CaCO₃ will also react to produce 0.02 mole of CO₂.

Finally, we shall determine the volume of the CO₂ produced. Details below.

Number of mole (n) = 0.02 moles Pressure (P) = 1 atm Temperature (T) = 37 °C = 37 + 273 = 310 KGas constant (R) = 0.0821 atm.L/Kmol Volume (V) =?

PV = nRT

1 × V = 0.02 × 0.0821 × 310

V = 5.09 L

Thus, the volume obtained is 5.09 L

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Calculate the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy (Note => 16.0 um = 16.0 * 10^6 m & 2.3KJ = 2300 J)

Answers

The number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

What are photons?

Photons are defined as a basic particle that is both the force carrier for the electromagnetic force and a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves.

It can also be defined as a discrete bundle of electromagnetic energy is what is known as a light particle.

Energy = 2.3 KJ

Wavelength = 16.0 x 10⁶ m

Energy = hc / ∧

            = 6.63 x 10²⁴ x 3 x 10³ / 16.0 x 10⁶

            = 1.24 x 10¹⁹ J

Number of photons used = 2.3 KJ / 1.24 x10¹⁹

                                          = 1.85 x 10¹⁹

Thus, the number of photons having a wavelength of 16.0 um required to produce 2.3KJ of energy is 1.85 x 10¹⁹

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Which two types of information are written in an element's box in the periodic
table?
A. Atomic mass
B. Number of electron shells
C. Nuclear composition
D. Chemical symbol

Answers

Answer:

b d my good mannnnnnnnnnnn

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