What is the perimeter of the square?

The length of the blade of the windmill will be equal to 7 feet.

We have the equation

[tex]\rm h=7 \ Sin(\dfrac{\pi}{21t})+28[/tex]

At the time 't' = 0, the end of the blade is pointing to the right parallel to the ground meaning it is at the same height as the other end. (Ф = 0°)

So, by calculating the maximum height of this end at  Ф = 90°. we can calculate the length of the blade.

Now, we know that a general model equation of a circular simple harmonic motion is represented as

[tex]\rm y=A\ Sinwt+k[/tex]

Where A is the amplitude that is, maximum displacement from mean to maximum position.

ω is the angular frequency.

Comparing the above equations we can conclude that

A = 7

so the difference in blade's end height at Ф = 0° and Ф = 90° is 7 feet.

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Answer:

7ft or option 1

Step-by-step explanation:

Answer:

To find each length in the new scale drawing, you can multiply each length in the original scale drawing by this scale factor between the two scale drawings. ▫.

fdddkgStep-by-step explanation:

She makes a minimum monthly payment of 62.52 dollars. Then the correct option is B.

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

May currently has a balance of $1,817.43 on her credit card.

If she must make a minimum monthly payment of 3.44% of her total balance.

Then the minimum payment will be given as

Minimum payment = 0.0344 × 1817.43

Minimum payment = 62.519 ≅ 62.52

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Steps to finding the line in the diagram with the format 'ax + by = c

1. Find the slope

                  [tex]Slope = \frac{y2-y1}{x2-x1} =\frac{4-0}{0-3} =-\frac{4}{3}[/tex]

2. Set up, with any one point on the line and the slope, in point-slope form

        [tex](y-y0)=m(x-x0)\\(y-4)=-\frac{4}{3} (x-0)\\y-4 = -\frac{4}{3} x\\\frac{4}{3}x+y = 4[/tex]

Answer: [tex]\frac{4}{3}x+y = 4[/tex]

Hope that helps!

Answer:

[tex]\sf 4x+3y=12[/tex]

Step-by-step explanation:

Choose two points on the line:

Let [tex]\sf (x_1,y_1)=(0,4)[/tex]

Let [tex]\sf (x_2,y_2)=(3,0)[/tex]

Use the slope formula to find the slope of the line:

[tex]\sf slope(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0-4}{3-0}=-\dfrac43[/tex]

Use the point-slope formula to find the equation of the line:

[tex]\sf y-y_1=m(x-x_1)[/tex]

Substitute values into the formula:

[tex]\sf y-4=-\dfrac43(x-0)[/tex]

Expand the brackets:

[tex]\sf y-4=-\dfrac43x[/tex]

Add 4 to both sides:

[tex]\sf y=-\dfrac43x+4[/tex]

Rearrange into the form [tex]ax+by=c[/tex]

Multiply both sides by 3

[tex]\sf 3y=-4x+12[/tex]

Add 4x to both sides:

[tex]\sf 4x+3y=12[/tex]

Answer:

Bottom left = 8

Top right = 15

Middle right = 25

Step-by-step explanation:

Total = 40

3 + 5 = 8

40 / 8 = 5

1 part = 5

5 x 3 = 15

5² = 25

[tex]0.75x = 15[/tex]

[tex]x = \frac{15}{0.75} = 20[/tex]

[tex]0.15(20) = 3[/tex]

Answer: You can use the definition of percentage and the proportions to solve this question. 75% means 75/100, the you want to know which fraction of 15 equals 75/100, which is to solve this proportion: 75/100 = 15/x. Solving for x, x = 15 * 100 / 75 = 20. You can check that the 75% of 20 is equal to 15: 20 * 75% = 20*75/100 = 15. So, the answer is 20.

Step-by-step explanation:

Answer:

$4440 for all performances

Step-by-step explanation:

11 × ¢120 for short performances

12 × $260 for long performances

$1320 for short performances

$3120 for long performances

To get the totel you add them up

( $1320 + $3120)

The total is $4440

Answer:

760

Step-by-step explanation:

Answer:

760 of course

Step-by-step explanation:

3 is below 5 so its 760

If the last digit was a 5 or higher,it'll be 770

Answer:

Answer: 1.4

Step-by-step explanation:

P(Northern pike) = 0.7

P(walleye) = 0.3

If 2 fishes are caught :

Number of northern pike (x) :

X = 0

P(walleye 1 st) * p(walleye 2nd) = (0.3 * 0.3) = 0.09

X = 1

P(walleye 1st)*P(Northern pike 2nd) OR P(Northern pike 1st)*P(Walleye 2nd)

= (0.3 * 0.7) + (0.7 * 0.3)

= 0.21 + 0.21

= 0.42

P(x = 2)

P(northern pike 1st) * P(northen pike 2nd)

0.7 *0.7 = 0.49

X: _ 0 _ 1 __ 2

P(x): ___ 0.09 ___ 0.42 ____ 0.49

Expected value of northern pikes :

(0* 0.09) + (1 * 0.42) + (2 * 0.49)

0 + 0.42 + 0.98

= 1.4

Expected value of the number of walleye is 0.5.

The expected value exists as a long-run average value of random variables. It also demonstrates the probability-weighted average of all possible values. Expected value exists as a generally utilized financial concept.

W = # of walleye 0, 1, 2

P(W) 0. 49, 0. 42, 0. 09

To estimate the expected value of the number of walleye.

E(X) =  number of walleye

E(X) = (0 [tex]\times[/tex] 0.49) + (1 [tex]\times[/tex] 0.42) + (2 [tex]\times[/tex] 0.09)

E(X) = 0 + 0.42 + 0.08

E(X) = 0.5

Therefore, the number of walleye expected value = 0.5.

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Divide money earned by hours worked to get the hourly rate of $11.00 per gour.

Answer: C. $11.00 per hour

Answer:

1

Step-by-step explanation:

5 + 4 - (8 x 3 – 22)* x 4

5 + 4 - (24 - 22) x 4

5 + 4 - 2 x 4

5 + 4 - 8

1

Answer:

16

Step-by-step explanation:

5+4- (8x3-22) ↑4 x4

         16

5+4 - (24-22) ↑4 x4

5+4- (2) ↑4 x4

2x2x2x2=16

hope that helps:)

Step-by-step explanation:

1 ounce = 28grams

x grams = 392

x = 392/28

x = 14.oo ounces

Answer:

1/6

Step-by-step explanation:

Given;

Luis is going to roll a six-sided die. What is the probability that the die lands on the number 4?

Solve:

Six-sided die = 6

There are only one 4 in the six-sided die.

Hence, fraction = [tex]\frac{1}{6}[/tex]

~Lenvy~

==============================================

Remember, prime numbers have only 2 factors: 1 & themselves.

For example, 5 is a prime number because it's only divisible by 1 and 5 (itself)

Now, write down some primes.

1) between 45 and 55

   - 47

   - it's only divisible by 1 and itself, so it IS prime

2) 62 and 72

67, because it is divisible by 1 and itself only.

====================================================

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)

Answer:

1944 cubic cm

Step-by-step explanation:

Find the answer by figuring out the volumes independently for each figure.  After doing that, add both volumes together to get the full volume.

Bottom figure: 1440 cubic cm

Top figure: 504 cubic cm

Add those together: 1944 cubic cm

Answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

Derivative Rule [Product Rule]:
[tex]\displaystyle (uv)' = u'v + uv'[/tex]

Derivative Rule [Quotient Rule]:
[tex]\displaystyle \bigg( \frac{u}{v} \bigg)' = \frac{vu' - uv'}{v^2}[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle [u(v)]' = u'(v)v'[/tex]

Step-by-step explanation:

*Note:

Since the answering box is way too small for this problem, there will be limited explanation.

Step 1: Define

Identify.

[tex]\displaystyle y = \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \times \frac{\tan^2 x + 5x}{\csc^2 x + 3}[/tex]

Step 2: Differentiate

We can differentiate this function with the use of the given derivative rules and properties.

Applying Product Rule:

[tex]\displaystyle y' = \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) '[/tex]

Differentiating the first portion using Quotient Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( \cos^2 x - 3\sqrt{x} + 6 \big)' \big( \sin^2 x + 6 \big) - \big( \sin^2 x + 6 \big)' \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule:

[tex]\displaystyle \bigg( \frac{\cos^2 x - 3\sqrt{x} + 6}{\sin^2 x + 6} \bigg)' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2}[/tex]

Differentiating the second portion using Quotient Rule again:

[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( \tan^2 x + 5x \big)' \big( \csc^2 x + 3 \big) - \big( \csc^2 x + 3 \big)' \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Apply Derivative Rules and Properties, namely the Chain Rule again:
[tex]\displaystyle \bigg( \frac{\tan^2 x + 5x}{\csc^2 x + 3} \bigg) ' = \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Substitute in derivatives:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - \big( 2 \sin x \cos x \big) \big( \cos^2 x - 3\sqrt{x} + 6 \big)}{\big( \sin^2 x + 6 \big)^2} \frac{\tan^2 x + 5x}{\csc^2 x + 3} + \frac{\cos^2 x - 3\sqrt{x} +6}{\sin^2 x + 6} \frac{\big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) - \big( -2 \csc^2 x \cot x \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2}[/tex]

Simplify:

[tex]\displaystyle y' = \frac{\big( \tan^2 x + 5x \big) \bigg[ \big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \sin^2 x + 6 \big) - 2 \sin x \cos x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \bigg]}{\big( \sin^2 x + 6 \big)^2 \big( \csc^2 x + 3 \big)} + \frac{\big( \cos^2 x - 3\sqrt{x} +6 \big) \bigg[ \big( 2 \tan x \sec^2 x + 5 \big) \big( \csc^2 x + 3 \big) + 2 \csc^2 x \cot x \big( \tan^2 x + 5x \big) \bigg] }{\big( \csc^2 x + 3 \big)^2 \big( \sin^2 x + 6 \big)}[/tex]

We can rewrite the differential by factoring and common mathematical properties to obtain our final answer:

[tex]\displaystyle y' = \frac{\big( -2 \cos x \sin x - \frac{3}{2\sqrt{x}} \big) \big( \tan^2 x + 5x \big) + \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( 2 \sec^2 x \tan x + 5 \big)}{ \big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)} + \frac{2 \cot x \csc^2 x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big)^2 \big( \sin^2x + 6 \big)} - \frac{2 \cos x \sin x \big( \cos^2 x - 3\sqrt{x} + 6 \big) \big( \tan^2 x + 5x \big)}{\big( \csc^2 x + 3 \big) \big( \sin^2 x + 6 \big)^2}[/tex]

∴ we have found our derivative.

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Topic: Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Answer:

The answer should be B. 86.7

Answer: WZ=10, YZ=15

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

If we divide the shape we can get 3 x 10 with equals 30. Then take the remaining which is 2 x 10 and we get 20. Add the two to get 50. The area is 50sq miles.

Hope this helps. pls mark brainliest

Answer:

$750

Step-by-step explanation:

2500 divided by 100 = 25 and 25 x 30 = 750

Sorry if im wrong

The price for 2500 pencils is $750.

The unitary technique involves first determining the value of a single unit,  followed by the value of the necessary number of units.

For example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.

12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.

As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.

This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.

We have,

A box of 100 personalized pencils costs $30.

So, cost of 1 pencil = $30 / 100 = 3/10

Now, the price to buy the 2500 pencils

= 2500 x 3/10

= 250 x 3

= $750

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Answer:

A = bh

A = 45 x 46

A = 2070 inches

Answer:

2070 squre in

Step-by-step explanation:

because the base is 46 and the height is 45 then we just multiply the two together to find the area.

so we solve it and we get

45*46=2070

Answer:

there are 18 milk chocolates

Answer:

Step-by-step explanation:

convert it to fraction first: 2/5 are plain and 3/5 is milk

30÷5= 6

2x6=12

3x6=18

to check wheter or not it is correct add the amount. if it gets the total, it is correct.

The place values in 5.6 and 1.78 are the positions of the digits in the numbers

In a number, the non-zero digit at the left-most position is the greatest place value

This means that:

The greatest place value in 5.6 is 5 (i.e. ones place)

The greatest place value in 1.78 is 1 (i.e. ones place)

So, we can conclude that the largest place value common in 5.6 and 1.78 is the ones place

Hence, Nichole is correct

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Answer:

15

Step-by-step explanation:

Okay, so we know that Base*Length=Area, so we just have to divide the area by the base, so the formula here is Area/Base=Length.

That would get us 120/8=Length,

and if we just divide 120 by 8 we get 15, so the length is 15

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \frac{1}{2} (5 + 13) - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \: \frac{1}{2} (18) - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \: 9 - 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \:4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \:(5 + 11) - (24 - 15) \times 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:16 - (9 \times 3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:16 - 27[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 11[/tex]

[tex]\qquad \sf  \dashrightarrow \: {6}^{2} + (3 \times 7) - (9 \div 3)[/tex]

[tex]\qquad \sf  \dashrightarrow \:36 + 21 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:57 - 3[/tex]

[tex]\qquad \sf  \dashrightarrow \:54[/tex]

Answer:

y = x - 5

Step-by-step explanation:

Line A

Equation

Answer:

Step-by-step explanation:

Radius = circumference / 2π

= 43.96 / 2π

= 7.00 yards to the nearest hundredth.