The quotient of the expression is [tex]\frac{1}{2y}[/tex]
The expression is given as:
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2}[/tex]
Divide 3y^2 by 3y
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \div \frac{6y^4}{3y^2}[/tex]
Rewrite the equation as a product
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \times \frac{3y^2}{6y^4}[/tex]
Divide 6 by 3
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = y \times \frac{y^2}{2y^4}[/tex]
Multiply y and y^2
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = \frac{y^3}{2y^4}[/tex]
Divide y^3 by y^4
[tex]\frac{3y^2}{3y} \div \frac{6y^4}{3y^2} = \frac{1}{2y}[/tex]
Hence, the quotient of the expression is [tex]\frac{1}{2y}[/tex]
Read more about quotients at:
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Answer:
its B
Step-by-step explanation:
Consider the number. -|-34.5| what is the distance from this number to zero on a standard number line??
Answer:
34.5
Step-by-step explanation:
The absolute value of -|-34.5| is -34.5. So, -34.5 is 34.5 away from 0.
Answer:
34.5 units.
Step-by-step explanation:
When we simplify -|-34.5|, we get -34.5, which is basically 34.5 units away from 0.
Hoped this helped.
Can anyone please answer number 6.
Answer:
Step-by-step explanation:
Exact Form:
2
√
2
+
3
√
5
−
2
2
2
+
3
5
-
2
Decimal Form:
7.53663105
…
Answer:
28
Step-by-step explanation:
2(√2+3)² -3(√2+3*√2-2)
expand collect like terms
2(2+6√2+9)-3(4√2-2)
2(2+6√2+9)-3(4√2-2)
calculate remove parentheses
2(11+6√2)-12√2+6
remove parentheses
22+12√2-12√2+6
remove opposite and calculate
solution= *28*
was this helpful???!
Solve and show your work for each question...
[tex]0.\overline{36} = \dfrac{36-0}{99} = \dfrac{36}{99} = \dfrac{4}{11}\\\\\\0.3\overline{6}= \dfrac{36-3}{90} = \dfrac{33}{90} = \dfrac{11}{30}\\\\\\0.36 = \dfrac{36}{100} = \dfrac{9}{25}[/tex]
Find the area of an equilateral triangle with side length 4.6 cm. Round your answer to 1 DP.
Answer:
A = 9.2 cm²
Step-by-step explanation:
A = 1/2 bh, you know the base = 4.6 and you need to find the height of the triangle.
Drawn the attitude of the equilateral triangle to the base and use a² + b² = c²
c = side of the triangle = 4.6 , b = 1/2 0f 4.6 = 2.3 . the attitude to the base ÷ the base in half.
a² + (2.3)² = (4.6)²
a² + 5.29 = 21.16
a² = 21.16 - 5.29
a² = 15.87
[tex]a = \sqrt{15.87}[/tex]
Now we know the height of the triangle = [tex]\sqrt{15.87}[/tex] , the base = 4.6
A = 1/2bh
A = 1/2 (4.6)([tex]\sqrt{15.87}[/tex] )
A = 9.1625
A = 9.2 cm² or the A of any equilateral triangle = [tex]\frac{\sqrt{3} }{4} s^2[/tex]
A = [tex]\frac{\sqrt{3} }{4} (4.6)^2[/tex]
A = 9.1625
A = 9.2
If TU = 6 units, what must be true?
O SU + UT = RT
O RT + TU = RS
© RS + SU = RU
TU + US = RS
Answer:
SU + UT = RT
Step-by-step explanation:
Given that TU = 6 units, RT = 12 units and RS = 24 units.
So,
For finding US, we will subtract the length of RT and TU from RS.
US = RS - RT - TU
US = 24 - 12 - 6
US = 6 units
Putting all the given values in the given conditions, we get the first option right, which is:
SU + UT = RT
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH180713^5/13^x=13^4
Anyone know how to solve this?
[tex]\frac{13^5}{13^x} =13^4 =>13^{5-x} =13^4\\ =>5-x=4=> x=5-4=1[/tex]
ANSWER: x = 1
ok done. Thank to me :>
Pete grabbed 18 mixed nuts, StartFraction 2 Over 9 EndFraction of which were almonds. Which equation shows how to determine the number of almonds Pete grabbed?
Answer:
Thats one heck of a whole lot nuts
Step-by-step explanation:
x*y=xy+2y find 4*[1*-5]
Answer:
- 90
Step-by-step explanation:
Evaluate 1*- 5 then the outer one
1*- 5 ( with x = 1 and y = - 5 )
= 1(- 5) + 2(- 5)
= - 5 - 10
= - 15
Then
4*- 15 ( with x = 4 and y = - 15 )
= 4(- 15) + 2(- 15)
= - 60 - 30
= - 90
If p is the smallest of four consecutive even integers, what is their sum interms of P?
plz be fast
I need full step by step the explanation
The sum in terms of p of four consecutive even integers with p been the smallest is 4(p + 3)
Even numbers are numbers that can be divided into two equal groups and they can be easily divisible by 2 without any remainder.
p is the smallest of the four consecutive even integers. This means p come first and it is the first term of the numbers.
Therefore, the 4 consecutive even integers is represented as follows;
p, p + 2, p + 4, p + 6
So the sum is equal to:
sum = p + p + 2 + p + 4 + p + 6
sum = 4p + 12
sum = 4(p + 3)
learn more on even numbers here: https://brainly.com/question/21514478?referrer=searchResults
Complete the tables of values. X 4â’x â’1 4 0 a 2 b 4 c a = b = c = x ( 2 3 ) x â’1 3 2 0 d 2 e 4 f d = e = f =.
The corresponding values of d, e ad f are 1, 1/16, and 1/256 respectively
Find the table of values attached. From the given table the function of the output is expressed as [tex]g(x) = 4^{-x}[/tex]
If x = 0, then;
[tex]g(0) = 4^{-0}\\g(0) = 1/4^0\\g(0)=1/1 = 1\\[/tex]
If x = 2
[tex]g(2) = 4^{-2}\\g(2) = 1/4^2\\g(2)=1/16[/tex]
If x = 4;
[tex]g(4) = 4^{-4}\\g(4) = 1/4^4\\g(4)=1/256[/tex]
Therefore the corresponding values of d, e ad f are 1, 1/16 and 1/256 respectively
Learn more on table of functions here: https://brainly.com/question/3632175
Answer:
a = ⇒ 1
b = ⇒ 1/16
c = ⇒ 1/256
d = ⇒ 1
e = ⇒ 4/9
f = ⇒ 16/81
Malachi is practicing math fluency. He has 100 math operation flashcards with 42 addition problem cards, 56 subtraction cards, and 2 multiplication cards. He will time himself to see how fast he can solve the problems on two cards. He chooses his two cards and they are both multiplication cards. Is choosing two multiplication cards likely? Explain by running a simulation.
Part A: State the problem or question and assumptions. (2 points)
Part B: Describe the process for one repetition, including possible outcomes, assigned representations, and measured variables. (3 points)
Part C: Use digits from a table of random digits or use your calculator to perform one repetition. Submit the list of random digits and indicate those that represent multiplication cards. (3 points)
Part D: Suppose there were 5 times when both cards selected were multiplication cards after 1,500 repetitions of the simulation. State your conclusions from these results. (2 points)
Essay Submission
Answer: It is highly unlikely to get both multiplication cards on the first try.
Part A The question asked is: there are two multiplication cards out of one hundred cards including forty-two addition problem cards and fifty-six subtraction cards.What are the odds of getting just the multiplication cards.The assumption is this we are talking about the first try.
Part B You make the multiplication cards, card#1 and card#2. All other cards are #3-100. Then you use the random number generator to see odds of two numbers out of one hundred, which is 0.02%. as I did 2/100 x 1/99 then multiply by 100 so.02
Part C I got 83 and 27as my first two numbers with my random number generator, So Malachi didn't get a multiplication card in this random test. card #1 and card #2 are the multiplication cards
Part D The percentage of the time that you'd expect both multiplication cards to be picked is 0.002 or .2%. The proportion of the time that it happened here is 5/1500=.00333 or .33%, which means that this is pretty much in line with what you'd expect
Step-by-step explanation: I got a 10/10 on 3.07 essay test for honors statistics.
HELPPPPP PLEASE ACTUALLY GIVE ME THE ANSWER AND NOT JUST A link PLSSS ITS DUE IN 23 MINUTESSS!!!!!!!!!!!! HELP
Answer:
4 1/9
Step-by-step explanation:
Well we can infer that the whole number will be 4. And 0.111 repeating is 1/9 as a fraction.
If there is a 30% chance of snow today and a 10% chance of snow tomorrow, what is the chance that it will not snow today and tomorrow? Write your answer as a percent.
Answer:
The weather forecast says that there is a "30% chance of rain," and we think we understand what it means. This quantitative statement is assumed to be unambiguous and to convey more information than does a qualitative statement like "It might rain tomorrow." Because the forecast is expressed as a single-event probability, however, it does not specify the class of events it refers to. Therefore, even numerical probabilities can be interpreted by members of the public in multiple, mutually contradictory ways. To find out whether the same statement about rain probability evokes various interpretations, we randomly surveyed pedestrians in five metropolises located in countries that have had different degrees of exposure to probabilistic forecasts--Amsterdam, Athens, Berlin, Milan, and New York. They were asked what a "30% chance of rain tomorrow" means both in a multiple-choice and a free-response format. Only in New York did a majority of them supply the standard meteorological interpretation, namely, that when the weather conditions are like today, in 3 out of 10 cases there will be (at least a trace of) rain the next day. In each of the European cities, this alternative was judged as the least appropriate. The preferred interpretation in Europe was that it will rain tomorrow "30% of the time," followed by "in 30% of the area." To improve risk communication with the public, experts need to specify the reference class, that is, the class of events to which a single-event probability refers.
Two vehicles are moving, one with the velocity of 20 m/s towards east and another with 10 m/s towards west. Calculate the distance between them after 20 minutes they are started from the same place and the same time.
Answer:
12 km
Step-by-step explanation:
20 minutes = 20 * 60 = 1200 second
distance = velocity * time
car 1 = 1200 * 20 = 24000 m = 24km
car 2= 1200 * 10 = 12000 m = 12km
so distance between them after 20 minutes is 24 -12 = 12 km
1.86÷2=1, point, 86, divided by, 2, equals
\text{ hundredths}\div 2 hundredths÷2start text, space, h, u, n, d, r, e, d, t, h, s, end text, divided by, 2
1.86 \div 2 =1.86÷2=1, point, 86, divided by, 2, equals
\text{ hundredths} hundredthsstart text, space, h, u, n, d, r, e, d, t, h, s, end text
1.86 \div 2 =1.86÷2=1, point, 86, divided by, 2, equals
The equivalent value of the expression 1, point, 86, divided by, 2 is given by A = 0.93.
Given data:
Let the expression be represented as A.
Now, the value of A is
A = 1, point, 86, divided by, 2.
Substituting the values in the equation:
[tex]A=\frac{1.86}{2}[/tex]
On simplifying the equation:
[tex]A=0.93[/tex]
Therefore, the value of A is 0.93
Hence, the equation is A = 0.93
To learn more about equations, refer:
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The complete question is attached below:
Find the equivalent value of the expression "1, point, 86, divided by, 2".
A fishbowl has a capacity of 192 fluid ounces. How many quarts is that?
Answer:
hope this helps
Step-by-step explanation:
192 fl oz. = 6 quarts
to get this you divide the fluid ounces by 32.
How many ways are possible to select a president and vice president from an
association with 5400 members?
The Answer there are 9*8 = 72 ways to choose a president and vice president
Step-by-step explanation:
Interpreting Composite Functions in the Real World
Try it
The volume of air in a balloon is represented by the function von = = nr?, where r is the radius of the balloon, in
inches. The radius of the balloon increases with time, in seconds, by the function rt) = 42
Write a composite function that can be used to determine the volume of the balloon after t seconds. Then, select the
two true statements
Answer:
Answer is A and C on edge
Step-by-step explanation:
The composite function that can be used to determine the volume of the balloon after t seconds, when V is composed with r is 1/48πt⁶ and after 6 second it is 972π.
What is composite function?When the two or more than two functions are written in the form of single function. Then such function is called the composite function.
Let suppose there is a function f(x) and another function g(x). Then the composite function can be given as,
[tex]f[g(x)][/tex]
The volume of air in a balloon is represented by the function,
[tex]V(r)=\dfrac{4}{3}\pi r^3[/tex]
Here, r is the radius of the balloon, in inches.
The radius of the balloon increases with time, in seconds, by the function,
[tex]r(t) = \dfrac{1}{4}t^2[/tex]
The composite function that can be used to determine the volume of the balloon after t seconds is,
[tex]V(r(t))=\dfrac{4}{3}\pi (\dfrac{1}{4}t^2)^3\\V(r(t))=\dfrac{4}{3}\pi (\dfrac{1}{64}t^6)\\V(r(t))=\dfrac{1}{48}\pi t^6[/tex]
After the 6 seconds,
[tex]V(r(6))=\dfrac{1}{48}\pi (6)^6\\V(r(6))=\dfrac{1}{48}\pi \times46656\\V(r(6))=972\pi[/tex]
Thus, the composite function that can be used to determine the volume of the balloon after t seconds, when V is composed with r is 1/48πt⁶ and after 6 second it is 972π.
Learn more about the composite function here;
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I do believe i need help.
Answer:
A
Step-by-step explanation:
Can't have 0 in the denominator
I need help and I can’t find any sadly. Help!!
Answer:
See answer below.
Step-by-step explanation:
3x - 2 = 4 Given
+2 = +2
3x = 6 Addition Property of Equality
3x/3 = 6/3
x = 2 Division Property of Equality
which expression is equivalent to 4√8/3√2
Answer:
8/3
Step-by-step explanation:
The square root of 8 can actually be written [tex]2\sqrt2[/tex], so [tex]4\sqrt2 = 4 \cdot 2\sqrt2 = 8\sqrt2[/tex]
Now, we are looking for [tex]\frac{8\sqrt2}{3\sqrt2}[/tex]. Both the square root of 2s cancel, so we are left with 8/3
Drag and drop the answers to the boxes to correctly complete the proof.
Given: Rhombus JKMH with diagonals intersecting at point P
Rhombus J K M H with diagonals J M and H K intersecting at P
Prove: JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯
By the definition of Response area, JK⎯⎯⎯⎯⎯≅KM⎯⎯⎯⎯⎯⎯ and by the reflexive property of congruence, KP⎯⎯⎯⎯⎯≅KP⎯⎯⎯⎯⎯ . Because the diagonals of a rhombus bisect a pair of opposite angles, ∠JKP≅∠MKP , making △JKP≅△MKP by the Response area. Because Response area, ∠JPK≅∠MPK, and these angles are right angles because two angles that form a linear pair are congruent, thereby making JM⎯⎯⎯⎯⎯⊥HK⎯⎯⎯⎯⎯⎯ by the definition of perpendicular segments.
Response area means blank
The answers are Congruent segments, a rhombus, a parallelogram, SSS congruence postulate, ASA congruence postulate, SAS congruence postulate, CPCTC, they are adjacent, and vertical angles are congruent
The completed proof is presented as follows;
By definition of a rhombus [tex]\overline{JK} \cong \overline{KM}[/tex] and by the reflexive property of
congruence [tex]\overline{KP} \cong \overline{KP}[/tex], because the diagonals of a rhombus bisect a pair
of opposite angles, ∠JKP ≅ ∠MKP, making ΔJKP ≅ ΔMKP by the SAS
congruency postulate, because CPCTC, ∠JPK ≅ ∠MPK, and these angles
are right angles because two angles that form a linear pair are congruent,
thereby making, [tex]\overline{JK} \perp \overline{KM}[/tex] by definition of perpendicular segments.
Reasons:
Please find attached the drawing of the given rhombus JKMH, that show
the point of intersection of the diagonals JM and HK at point P.
A rhombus is an equilateral quadrilateral, therefore, the adjacent sides [tex]\overline{JK} \ and \ \overline{KM}[/tex] are congruent.The SAS congruency postulate states that if a triangle has two sides and an included angle that are congruent to two sides and an included angle of another triangle, then the two triangles are congruent.CPCTC is an acronym for Congruent Parts of Congruent Triangles are Congruent.Learn more about the properties of a rhombus here:
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how many lines of symmetry does the figure have?
Answer:
Step-by-step explanation:
2
can someone help me with this
[tex]\dfrac{2x-3}x = \dfrac{14}{x+5}\\\\\implies (2x-3)(x+5) = 14x\\\\\implies 2x^2 +10x -3x -15 -14x=0\\\\\implies 2x^2-7x-15=0\\\\\text{Apply quadratic formula,}~~x= \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}.\\\\\text{In this case,}~ a=2, b=-7~ \text{and}~ c = -15. \\\\\\x = \dfrac{-(-7) \pm \sqrt{(-7)^2 -4\cdot 2 \cdot (-15)}}{2(2)}\\\\\\\implies x = \dfrac{7 \pm \sqrt{169}}{4}\\\\\\\implies x = \dfrac{7 \pm 13}4\\\\\\[/tex]
[tex]\text{Hence} ~x = \dfrac{7+13}{4} = \dfrac{20}4 = 5 ~\text{or}~ x = \dfrac{7-13}4 = -\dfrac{6}4 = -\dfrac 32[/tex]
a sweater was on 20% discount. the amount of discount was $7 what was the original price?
Answer:
$35
Step-by-step explanation:
if $7 is only 20% of the original price multiply 7×5
-20%×5=100%
same thing as 7×5=35
just switch the percent by its worth
May I please receive help?
Answer:
a = 19.6 (rounded to the nearest tenth)
Step-by-step explanation:
a^2 + b^2 = c^2
Hypotenuse - 35 m, Legs - 29 m, x
a^2 +29^2 = 35^2
a^2 + 841 = 1225
Subtract 841 from both sides
a^2 = 384
Square root both sides
√a^2 = √384
a = 19.595
Will mark brainliest for 2 possible answers
Answer:
x³ +7x² +7x -15
Step-by-step explanation:
Apply the distributive property repeatedly, and/or recognize the ways that the coefficients of the product are formed.
distributive property
(x -1)(x +3)(x +5)
= (x -1)(x(x +5) +3(x +5))
= (x -1)(x² +5x +3x +15) = (x -1)(x² +8x +15)
= x(x² +8x +15) -1(x² +8x +15)
= x³ +8x² +15x -x² -8x -15
= x³ +7x² +7x -15
__
using knowledge of products of powers
The x³ term will be the product of all of the x-terms.
The x² term will be the pairwise sum of products of two x-terms and the third constant.
The x term will be the pairwise sum of products of one x-term and the two other constants.
The constant term will be the product of all of the constants.
These computations are simplified a bit because all of the x-coefficients are 1.
= x³ +(-1 +3 +5)x² +(-1·3 +(-1)·5 +3·5)x +(-1)·3·5
= x³ +7x² +7x -15
(sin^2(0)) I really need help with this asap
Answer:
Asapa
[tex] (sin2(0) [/tex]
A grocery store sells 25 crates of peaches for $125. How much does 1 crate cost?
Answer: One crate of peaches is $5
Step-by-step explanation:
All you do for this question is divide 125 by 25 gives us 5
Answer:
5
Step-by-step explanation:
Just decide 125 by 25 and get the answer :)
Help...? Thanks! No links
Answer: C) Move it 3 places to the left
Explanation:
We're dividing the number [tex]34.62[/tex] by [tex]10^3[/tex], which is the same as dividing by 1000.
The exponent 3 tells us how many spots to move the decimal point. We move to the left because the number gets smaller. If we multiplied by [tex]10^3[/tex], then we'd move the decimal point 3 spots to the right.
So, [tex]34.62 \div 10^3 = 34.62 \div 1000 = 0.03462[/tex]