What is the range of the function shown in this table? х3 4 5 6 y4 4 2 5 A. (3, 4), (4, 4), (5, 2), {6, 5{ B. {3,4,5,6} C. {3, 4} D. {2,4,5}

Step-by-step explanation:

Hey there!

The given points are; (4,4) and (1,2) as (x1,y1) and (x2,y2).

Note: Use double point formula for the equation.

Now;

[tex](y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)[/tex]

Put all values.

[tex](y - 4) = \frac{2 - 4}{1 - 4} (x - 4)[/tex]

Simplify it.

[tex](y - 4) = \frac{ - 2}{ - 3} (x - 4)[/tex]

[tex](y - 4) = \frac{2}{3} (x - 4)[/tex]

[tex](y - 4) = \frac{2}{3} x - \frac{2}{3} \times 4[/tex]

[tex]y = \frac{2}{3}x - \frac{8}{3} + 4 [/tex]

[tex]y = \frac{2}{3} x - \frac{8 + 12}{3} [/tex]

[tex]y = \frac{2}{3} x + \frac{4}{3} [/tex]

Therefore, the equation is; y = 2/3x+4/3.

Hope it helps...

Answer:

A(-8,5)

Step-by-step explanation:

Given two points (-6, 3), and (-10, 7). The midpoint is calculated by averaging the x, and y values of two coordinates. As (-10, 7) is the the first point (x1, y1), and (-6, 3) is the second point (x2, y2).

[tex]midpoint \: of \: (x_{1},y_{1}), \: and \: (x_{2},y_{2}) \\ = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})[/tex]

[tex] midpoint \: of \: (-6,3), \: and \: (-10,7) = (\frac{-10 + -6}{2}, \frac{7 + 3}{2}) \: = (\frac{-16}{2}, \frac{10}{2}) \: = (-8,5)[/tex]

Answer:

22

Step-by-step explanation:

Let us interpret this problem;

        ---------------34-------------------

       P         Q       S      R            T

                    ----- 8 --------

        --------  --------- --------

             x        x         x

Let PQ = SQ = SR

Find RT;

    QS + SR = 8

    Also;

          x + x = 8

            2x = 8

              x = 4

To find RT;

    RT = PT - (PQ + QR)

   RT = 34 - (4 + 8) = 34 - 12 = 22

Answer:

22

Step-by-step explanation:

Answer:

 y  = 72x

324miles

Step-by-step explanation:

Given parameters:

      Speed of the car = 72miles/hr

       distance  = y

        time  = xhrs

Unknown:

Write a direct variation equation for the distance=  ?

Distance covered in 4.5hrs =?

Solution:

A. Write a direct variation equation for the distance;

    A direct variation is a linear equation.

   It often takes the form y = kx

For this problem;

      Distance  = speed x time

input the parameters;

      y  = 72x

The direct variation equation is  y  = 72x

B. Distance traveled in 4.5hrs

   y  = 72x

  x is the time taken;

  So;

        y  = 72 x 4.5  = 324miles

Answer:3x41 squared

Step-by-step explanation:

Answer:

Jared transfers $55 to his checking account from his savings account.

Jared spends $55 from his checking account to purchase a college Algebra textbook

Jared withdraws $55 from his checking account

Hope this helps!

Answer:

3b+b and 2(2b)

Step-by-step explanation:

BRAINLIEST APPRECIATED!

THANKS!

Answer:

8962

Step-by-step explanation:

8×1+9...etc..etc

= 8962

Answer:

8.962

Step-by-step explanation:

Answer:

The answer is (7.8046875)

Step-by-step explanation:

Hope this helped

Answer:

J

Step-by-step explanation:

dude trust me

Answer:

the answer should be 7a^3-4a^2-2a-87

Answer:

4abc..............................

Answer:

it would be b

Step-by-step explanation:

Answer:

the missing angle is 73

96.666..., or about 97 minutes/every mile.

Answer:

Step-by-step explanation:

We need to set the equation equal to 0

-4 - x > 0

+ -4   +   -4

Answer:

a=58

b=95

Step-by-step explanation:

Answer:

Z^10

Step-by-step explanation:

Answer:

multiply 5*2=10

your answer will be =z^10

Step-by-step explanation:

Answer:

1=$1

2=$2

3=$3

4=$4

Step-by-step explanation:

Answer:

The answer I got was 266

Step-by-step explanation:

700 - 62% = 266

62% = 434

700 - 434 (62%) = 266

Answer:

66⁰ + x = 111⁰

x = 111⁰ - 66⁰

x = 45⁰

Answer:

First, I am taking the interior angle E as 'y' to be able to use the angle sum property to find 'x'.

So we can find 'y' by using 'linear pair'.

So Exterior angle 'E'+y=180 Degree.

=  111+y=180

By transposing: y=180-11

And y= 69 degrees.

And now have angles y & 'Angle G' we can use Angle sum property to find 'x'

THEREFOR, y+x+angle G=180 degrees.

=  69 degrees+66 degrees+x=180 degrees

=  135 degrees+x=180 degrees

by transposing,

x= 180 degrees-135 degrees

And, x= 45 degrees

BY USING EXTERIOR ANGLE PROPERTY.

ACCORDING TO EXTERIOR ANGLE PROPERTY OF TRIANGLE: "An exterior angle of a triangle is equal to the sum of its interior opposite angles"

So, Exterior Angle E= x+ Angle G

=  111 degrees= x+ 66 degrees

By transposing, x= 111 degrees-66 degrees

=  x=45 degrees.

So no matter whichever method is used, the value of x= 45 degrees.

Answer:

x = -15/2 or -7.5

Step-by-step explanation:

6x - 4(x - 9) = 2(3 - x)

6x - 4x + 36 = 6 - 2x

2x + 36 = 6 - 2x

4x + 36 = 6

4x = -30

x = -30/4

x = -15/2

Check:

6(-7.5) + -4(-7.5 - 9) = 2(3 + 7.5)

-45 + 66 = 2(10.5)

21 = 21

Answer:

[tex]-\frac{15}{2}[/tex]

Step-by-step explanation:

6x-4(x-9)=2(3-x)

6x-4x+36=6-2x (expansion)

2x+36=6-2x (collecting like terms)

2x+2x=6-36

4x=-30 (-30/4)

x=-[tex]-\frac{15}{2}[/tex]    

Answer:

The object coordinate Q is (-11,3 )

Step-by-step explanation:

The translation is given as : ( 6,-2 )

The image coordinates for Q' is ( -5,1 )

So, to get the coordinates of object point Q (x,y), will be;

 Q (x,y)  + ( 6,-2 )---translation --------------⇒image Q' ( -5,1 )

Thus,

x+6 = -5

x= -5-6= -11

and

y+ -2 = 1

y-2=1

y=1+2 =3

Thus the object point coordinates Q is (-11,3 )

Answer:

it would take him 19 track practices

Step-by-step explanation:

26miles - 7miles= 19miles

Answer:

3x2 - x + 10 when x=-4 plug in -4 for x 3(-4)^2 -(-4)+10

3(16)+4+10

3x16= 48

48+4+10= 62

Suzie's work is incorrect because of her negative distributions

Step-by-step explanation:

Answer:

Step-by-step explanation:

First you determine the variables x and y as:

x: the value for student tickets

y: the value for chaperone tickets.

Knowing that student tickets cost $ 2 more than companion tickets, it is represented by the equation:

x= y +2

On the other hand, there were 59 students and 6 companions. And the total cost of admission for the group was $ 508, that is to say that what all the students and the companions have paid adds up to $ 508. Expressed by an equation:

59x + 6y = 508

Then the system of equations to solve and thus obtain the price of a student ticket and the price of a companion ticket is:

[tex]\left \{ {{x=y+2} \atop {59x+6y=508}} \right.[/tex]

Solving for x, the price of a student ticket:

Rearranging  the first equation,

y = x - 2

Replacing in the second equation and solving for x:

59*x + 6*(x -2)=508

59*x + 6*x -12=508

65*x -12=508

65*x= 508 +12

65*x= 520

[tex]x=\frac{520}{65}[/tex]

x=8

The cost of a student ticket is 8$

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