Answers
The rate of the reaction is obtained from the calculation as 0.022 L/min.
What is the rate of reaction?We know that the rate of reaction has to do with the change in the volume or the concentration of one of the reactant which the volume of the oxygen have been chosen for the particular question that we are dealing with here.
Thus;
Rate of reaction = Change in the volume of oxygen/Time
= v2 - v1/t
= 0.35 L - 0.02 L/15 min
=0.022 L/min
Thus, we can see that the rate of the reaction can be obtained as 0.022 L/min.
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Related Questions
Calculate the volume of barium hydroxide (0.1177 M) necessary to react with 25.00 mL of phosphoric acid (0.1002 M)
Answers
The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the volume of barium hydroxide is 21.28 mL.
Molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is represented as 'M' and its unit is mol/L.
The equation connecting molarity and volume of two solution is given as:
M₁V₁ = M₂V₂
V₁ = M₂V₂ / M₁
0.1002 × 25.00 / 0.1177 = 21.28 mL
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A certain flexible weather balloon contains 3.1 L of helium gas. Initially, the balloon is in WP at 8500ft, where the temperature is 23.8oC and the barometric pressure is 564.8 torr. The balloon then is taken to the top of Pike’s Peak at an altitude of 14,100ft, where the pressure is 400 torr and the temperature is 6.9oC. What is the new volume of the balloon at the top of Pikes Peak?
Answers
The concept combined gas law is used here to determine the new volume of the balloon. This law relate one thermodynamic variable to another holding everything else constant. The new volume is 4.12 L.
The combination of Boyles law, Charles's law and Avogadro's law gives the combined gas law. This law states that the product of pressure volume and temperature of a system remains constant.
The equation is:
P₁V₁ / T₁ = P₂V₂ / T₂
V₂ = P₁V₁T₂ / P₂T₁
0.7455 × 3.1 × 279.9 / 0.528 × 296.8 = 4.12 L
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You have 900,000 atoms of a radioactive substance. After 4 half-lives have past, how many atoms remain?
you cannot have a fraction of an atom, so round the answer to the nearest whole number.
Answers
The number of atoms remaining after 4 half-lives can be calculated using the formula: N = N0 /[tex]2^4[/tex] . Therefore, after 4 half-lives, approximately 56,250 atoms of the radioactive substance remain.
Radioactive decay is the process by which a nucleus of an atom loses energy by emitting ionizing radiation. The rate of decay of a radioactive substance is measured by its half-life, which is the time it takes for half of the radioactive atoms in a sample to decay.
N = N0 /[tex]2^n[/tex]
where: N0 = initial number of atoms N = final number of atoms
Substituting the given values,
N = 900,000 / [tex]2^4[/tex]
N = 56,250
Rounding to the nearest whole number,
N ≈ 56,250 atoms
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Using six carbon atoms as an example, write the condensed structural formula and the names of the following functional groups: alcohol, ether, aldehyde, ketone, carboxylic acid, ester, amine and amide.
Answers
For alcohol, ether, aldehyde, ketone, carboxylic acid, ester, amine and amide, the condensed structural formulas of six carbon members of the series are shown below.
What is the condensed structural formula?The condensed structural formula for an alcohol with six carbon atoms is C6H13OH
The condensed structural formula for an ether with six carbon atoms is C6H14O
The condensed structural formula for an aldehyde with six carbon atoms is C6H10O
The condensed structural formula for a ketone with six carbon atoms is C6H10O
The condensed structural formula for a carboxylic acid with six carbon atoms is C6H10O2
The condensed structural formula for an ester with six carbon atoms is C6H12O2
The condensed structural formula for an amine with six carbon atoms is C6H15N
The condensed structural formula for an amide with six carbon atoms is C6H13NO
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a reaction between 1.7 moles of zinc iodide and excess sodium
Answers
Answer: I got you fam
Explanation:
The formula is Na2CO3 + ZnI2 → 2NaI + ZnCO3
Or -5.19
7. What mass of solid NH4Cl and what volume of 1.00 mol-L¹ NaOH solution should be used to
prepare 1 L of a buffer solution of pH 9.00? Suppose the overall concentration of the buffer is 0.125
mol-L¹. (Answer V = 45 mL)
Answers
To prepare a buffer solution of pH 9.00, we need to use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])Where [A-]/[HA] is the ratio of the concentrations of the conjugate base and acid of the buffer, respectively. Since we are given the pH and the overall concentration of the buffer, we can solve for the ratio [A-]/[HA]:
9.00 = pKa + log([A-]/[HA])pKa = 9.25 (the pKa of NH4Cl)9.00 = 9.25 + log([A-]/[HA])log([A-]/[HA]) = -0.25[A-]/[HA] = 0.56Next, we can use the definition of the concentration of a solution to find the concentration of NH4Cl needed to make a 0.125 mol-L^-1 buffer solution:
0.125 mol-L^-1 = [NH4Cl] + [NaOH]
Since the NaOH solution is 1.00 mol-L^-1, we can assume that the contribution of NaOH to the total concentration of the buffer is negligible, and so:
0.125 mol-L^-1 = [NH4Cl]Finally, we can use the molar mass of NH4Cl to find the mass of NH4Cl needed to prepare 1 L of the buffer solution:
mass NH4Cl = molar mass * molesmass NH4Cl = (14.01 g-mol^-1 + 1.01 g-mol^-1 + 35.45 g-mol^-1) * 0.125 molmass NH4Cl = 6.63 gSo we need to use 6.63 g of NH4Cl and enough volume of 1.00 mol-L^-1 NaOH solution to make a total volume of 1 L. To find the volume of NaOH solution needed, we can use the definition of molarity:
molality = moles of solute / volume of solution (in liters)Rearranging this equation, we get:
volume of solution = moles of solute / molalitySince we are adding NaOH solution to NH4Cl to make a total volume of 1 L, the molality of NaOH solution is also 0.125 mol-L^-1. Therefore:
volume of NaOH solution = moles of NaOH / molality of NaOHvolume of NaOH solution = (1 L - volume of NH4Cl solution) * 0.125 mol-L^-1Substituting the values we know:
volume of NaOH solution = (1 L - 0.45 L) * 0.125 mol-L^-1volume of NaOH solution = 0.056 L = 56 mLSo we need to use 6.63 g of NH4Cl and 56 mL of 1.00 mol-L^-1 NaOH solution to prepare 1 L of a buffer solution of pH 9.00.
pH = pKa + log([A-]/[HA])
where [A-]/[HA] is the ratio of the concentration of the conjugate base to the concentration of the weak acid. Since NH4Cl is a salt of a weak acid (NH4+) and a strong base (Cl-), the weak acid in this case is NH4+.
Rearranging the Henderson-Hasselbalch equation gives:
[A-]/[HA] = 10^(pH - pKa)
Substituting the given values into the equation:
[A-]/[HA] = 10^(9.00 - 9.25) = 0.562
Since the overall concentration of the buffer is 0.125 mol-L¹, we can set up the following two equations:
[A-] + [HA] = 0.125 mol-L¹
[V1] [C1] = [V2] [C2]
where V1 is the volume of NaOH solution, C1 is the concentration of NaOH solution, V2 is the total volume of the buffer solution (1 L), and C2 is the concentration of NH4Cl.
Since NH4Cl is a 1:1 electrolyte, [A-] = [NH3] and [HA] = [NH4+]. Therefore, we can rewrite the first equation as:
[NH3] + [NH4+] = 0.125 mol-L¹
Substituting [A-]/[HA] = 0.562 into the equation gives:
[NH3] = 0.562 [NH4+]
Substituting this into the equation [NH3] + [NH4+] = 0.125 mol-L¹ gives:
[NH4+] = 0.125 / (1 + 0.562) = 0.0517 mol-L¹
[C2] = 0.0517 mol-L¹
The molar mass of NH4Cl is 53.49 g-mol¹. Therefore, the mass of NH4Cl needed to prepare 1 L of a 0.0517 mol-L¹ solution is:
m = C × V × M
where m is the mass of NH4Cl, C is the concentration of NH4Cl, V is the volume of
In Activity 2, you tested various compounds for chemical changes. (Barium nitrate, sodium hydroxide, sodium hydrogen carbonate, copper (II) sulfate, potassium iodide, silver nitrate, iron (III) nitrate, and hydrochloric acid.) Write the chemical formulas for each of the reactants.
Answers
The chemical formulas are as follows:
Barium nitrate: Ba(NO₃)₂Sodium hydroxide: NaOHSodium hydrogen carbonate: NaHCO₃Copper (II) sulfate: CuSO₄Potassium iodide: KISilver nitrate: AgNO₃Iron (III) nitrate: Fe(NO₃)₃Hydrochloric acid: HClChemical formulas are shorthand notations used to represent the composition of a substance. In this case, the reactants used in Activity 2 are listed with their chemical formulas.
Barium nitrate is represented by the chemical formula Ba(NO₃)₂, which shows that it contains one barium ion (Ba²⁺) and two nitrate ions (NO₃⁻).
Sodium hydroxide is represented by the chemical formula NaOH, which shows that it contains one sodium ion (Na⁺) and one hydroxide ion (OH⁻).
Sodium hydrogen carbonate is represented by the chemical formula NaHCO₃, which shows that it contains one sodium ion (Na⁺), one hydrogen ion (H⁺), one carbonate ion (CO₃²⁻) and one hydrogen carbonate ion (HCO₃⁻).
Similarly, other reactants are represented by their respective chemical formulas.
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(25 pts) Explain in depth the relationship between LIMITING reactant and THEORETICAL yield
Answers
Answer: I got you fam
Explanation:
A limiting reactant is a reactant in a chemical reaction that limits the amount of product created.
So for example if there are elements X and Y reacting to create product XY, once say element X runs out, the reaction stops, even though there is still more of the reactant Y. So there is 0 g of element X remaining, and maybe 2 g left of element Y. X is the limiting reactant since it limits the amount of product made.
Theoretical yield is the maximum amount of product that could be made in an experiment. This occurs if a reaction is 100% effective (and experimentally, this doesn't usually happen, which is why it is called theoretical).
Potential in a different kind of cell.
A typical mammalian cell at 37
∘
C, with only potassium channels open, will have the following equilibrium:
K+ (intracellular) ⇌ K+ (extracellular),
with an intracellular concentration of 150 mM K+, and 4.0 mM K+ in the extracellular fluid.
What is the potential, in volts, across this cell membrane? Note: in this case, n = the charge on the ion, and Eo for a concentration cell = 0.00 V. explain please
Answers
The potential across this cell membrane with only potassium channels open is -0.082 V, which means that the inside of the cell is negatively charged relative to the outside.
The potential across a cell membrane can be calculated using the Nernst equation:
E = (RT/zF) ln([ion]out/[ion]in)
E = potential in volts, R= gas constant (8.314 J/mol*K), T= temperature in Kelvin, z = charge on the ion, F= Faraday constant (96,485 C/mol), and [ion]out and [ion]in are the concentrations of the ion outside and inside the cell, respectively.
K+ (intracellular) ⇌ K+ (extracellular)
The charge on potassium ions is +1, so z = 1.
The temperature is 37°C or 310 K.
The concentrations of potassium ions are [K+]in = 150 mM and [K+]out = 4.0 mM.
Substituting these values into the Nernst equation,
E = (RT/zF) ln([K+]out/[K+]in)
E = (8.314 J/mol.K × 310 K)/(1 × 96,485 C/mol) ln(4.0 mM/150 mM)
E = -0.082 V
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Given the following data
C2H4 (g) + 3O2 (g) -> 2CO2 (g) + 2H2O (l) H = –1411.0 kJ
2C2H6 (g) + 7O2 (g) -> 4CO2 (g) + 6H2O (l) H = –3119.8 kJ
2H2 (g) + O2 (g) -> 2H2O (l) H = –571.7 kJ
calculate H for the reaction
C2H4 (g) + H2 -> C2H6 (g)
Answers
Answer:H = 5
Explanation: You would get this answer if you divide by 2 then multiple by 7
We've figured out what part of the salt causes the flame to change color, so now let's measure the wavelengths created with four metals.
Use the ruler under the "tools" icon in the upper right of the video player to measure the wavelengths of light released by each compound.
Answers
The wavelength of one of the spectral lines for strontium chloride SrCl₂ is approximately 460.7 nanometers (nm).
When strontium chloride SrCl₂ is heated, it emits a characteristic red color, which indicates that it produces spectral lines in the red part of the visible spectrum. The most intense spectral line for SrCl₂ is at approximately 460.7 nm, which corresponds to the transition from the 5² electronic configuration to the 4d state.
This transition is responsible for the red color observed when strontium chloride is introduced to a flame. The wavelength of a spectral line is related to the energy of the transition and is given by
λ = hc ÷ E
where λ is the wavelength, h is Planck's constant, c is the speed of light, and E is the energy of the transition. In the case of SrCl₂, the energy of the transition from 5s² to 4d is approximately 2.69 eV, which corresponds to a wavelength of 460.7 nm.
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The complete question is:
What is the wavelength of one of the spectral lines for strontium chloride SrCl₂?
How much energy is released when 73 grams of water cools from 72 degrees Celsius to
30 degrees Celsius?
Answers
q = m × c × ΔT
where q is the amount of energy released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
The specific heat capacity of water is 4.18 J/g°C.
The change in temperature is:
ΔT = 72°C - 30°C = 42°C
Substituting these values into the equation gives:
q = (73 g) × (4.18 J/g°C) × (42°C)
q = 13,633.32 J
Therefore, the amount of energy released when 73 grams of water cools from 72°C to 30°C is 13,633.32 J.
Can u mark my answer as the Brainlyest if it work Ty
An OBJECT absorbs like between the light wavelengths of 430 - 400 nm. What is the color of the OBJECT?
Answers
The color of the object appears as yellow/orange.
What is the color?
The visible light spectrum spans a wavelength range of 400 to 700 nanometers (nm), with shorter wavelengths appearing as blue or violet and longer wavelengths as red.
This object is absorbing light with wavelengths between 430 and 400 nm, indicating that it is absorbing light that is visible in the blue and violet spectrum.
We know that this color that we see is actually a complementary color to blue/violet from the color wheel.
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a 70 piece of metal at 120 C is dropped into a kilometer with 150 g of 30C water the final temperature of the water and little changes 35c what is the specific heat of the metal
Answers
Answer:
cm=0.385 J
cm = (0.15 kg x 4.18 J/gCx (35C - 30C)) / (70 pieces x 0.1 kg/piece x (120C - 35C))
The answer is:
cm = 0.385 J/gc
Therefore, the specific heat of the metal is 0.385
Based on the information provided, which solution is a base and weak electrolyte
Answers
An example of a composition which fulfills the qualifications of being both a base and a weak electrolyte is ammonia (NH3).
How to explain the electrolyteA base is any constituent which voluntarily receives protons (H+) in an associated chemical reaction while an electrolyte denotes any material that can conduct electricity through liquids or in melted state.
Upon dissolution in water, it is apt to accept a proton from such and thus create the acidic ion known as ammonium (NH4+). Nonetheless, due to its scarce dissociation into hydroxide (OH-) and ammonium ions, it is deemed a weak electrolyte.
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This molecule undergoes an E1 mechanism when stirred in water.
Answers
All the 3 chemical species are drawn in the images below/
What is E1 mechanism when stirred in waterThe E1 reaction mechanism instigates a variant of elimination reactions. It materializes in the vicinity of strong acids or bases and it initiates by eliminating a leaving group from the substrate, consequently creating an intermediate carbocation. Once completed, the mechanism eliminates a proton from a neighborly carbon, initiating the construction process of a double bond.
However, performing an E1 reaction in water may yield unexpected results due to water's nucleophilic nature, catalyzing sneaky attacks on the carbocation intermediates, leading to dissimilar products than initially intended. Furthermore, reactions performed with aqueous media cause other side-products thanks to hydrolysis mechanisms that emerge, making them undesirable.
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PLEASE HELP NOW
Caffeine is a weak base with a b of 4.1×10^-4 Calculate the initial molar concentration of a solution of caffeine if the pH is 10.94.
Answers
Answer:430 mg/L = 0.43g/L
Explanation:
5.4g of aluminum reacts with sulfuric acid (H₂SO4) to form aluminum sulfate and hydrogen.
a. Write the chemical equation.
b. Find mass of required sulfuric acid.
C. Find volume of the obtained gas.
(AI=23, S = 32, O=16, H =1, 2g of H2 has 22.4L).
Answers
Answer:
a. The chemical equation for the reaction is:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
b. To find the mass of required sulfuric acid, we need to use stoichiometry. We can start by finding the number of moles of aluminum used in the reaction:
Molar mass of Al = 27 g/mol
Number of moles of Al = 5.4 g / 27 g/mol = 0.2 mol
According to the balanced equation, 3 moles of H₂SO₄ are required to react with 2 moles of Al. Therefore, the number of moles of H₂SO₄ required is:
Number of moles of H₂SO₄ = 3/2 x 0.2 mol = 0.3 mol
Molar mass of H₂SO₄ = 2 x 1 g/mol + 32 g/mol + 4 x 16 g/mol = 98 g/mol
Mass of H₂SO₄ required = 0.3 mol x 98 g/mol = 29.4 g
Therefore, 29.4 g of sulfuric acid is required to react with 5.4 g of aluminum.
c. To find the volume of hydrogen gas obtained, we need to use the ideal gas law:
PV = nRT
where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the universal gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.
We can start by finding the number of moles of hydrogen gas produced in the reaction. According to the balanced equation, 3 moles of H₂ are produced for every 2 moles of Al. Therefore, the number of moles of H₂ produced is:
Number of moles of H₂ = 3/2 x 0.2 mol = 0.3 mol
Assuming the reaction occurs at standard temperature and pressure (STP), which is 0°C (273 K) and 1 atm, we can use the molar volume of a gas at STP, which is 22.4 L/mol. Therefore:
V = nRT/P = 0.3 mol x 0.0821 L atm/mol K x 273 K / 1 atm = 6.58 L
Therefore, the volume of hydrogen gas produced at STP is 6.58 L.
Explanation:
The diagram shows sound and light waves from an emergency vehicle traveling toward a brick wall. The brick wall has both smooth and rough surfaces.
Select the correct answer from each drop-down menu to complete the sentences about how each wave is affected by the brick wall.
The sound waves from the siren will
the smooth surface of the wall. The light waves from the emergency vehicle will
the smooth surface of the wall. Rougher sections of the wall surface will cause the
from the emergency vehicle to scatter.
Answers
The sound waves from the siren will reflect off the smooth surface of the wall. The light waves from the emergency vehicle will reflect off the smooth surface of the wall. Rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.
When sound waves hit a smooth surface, they reflect off the surface in a predictable way called the law of reflection. So, the sound waves from the siren will reflect off the smooth surface of the wall.
Similarly, light waves also follow the law of reflection when they hit a smooth surface. Therefore, the light waves from the emergency vehicle will also reflect off the smooth surface of the wall.
However, when light waves encounter a rough surface, they scatter in all directions due to the irregularities on the surface. Therefore, rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.
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How many different genus groups are there? List them
Answers
What is the molarity 10.0g of Cr(NO3)3 in 325 mL of solution
Answers
Answer:
Explanation:
molar mass Cr(NO3)3 = 238 g/mol
Convert 325 ml to liters: 325 mls x 1 L / 1000 mls = 0.325 L
Convert 10.0 g to moles: 10.0 g x 1 mol / 238 g = 0.0420 moles
Molarity = moles/liters = 0.0420 moles / 0.325 L = 0.129 M (3 sig. figs.)
According to the law of conservation of mass, how much zinc was produced if Calcium = 25 g, Zinc Carbonate = 125 g, and Calcium Carbonate = 95 g.
HELPP
Answers
All the balanced chemical equations obey the law of conservation of mass. The numbers which are used to balance the chemical equation are called the coefficients. So here the mass of zinc is 55 g.
According to the law of conservation of mass, the mass can neither be created nor be destroyed but it can be converted from one form to another. The reactants appear on the left hand side and the products appear on the right hand side.
The amount of products is equal to the amount of reactants according to the law of conservation of mass.
25 + 125 = 95 + Zn
Zn = 55 g
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what is the name for CH3-CH2-C(O)-OCH3
Answers
Answer:
The name for CH3-CH2-C(O)-OCH3 is ethyl methanoate.
Explanation:
A soft drink contains 33g of sugar in 349g of H2O. A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
Answers
A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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Look back at parts A and B to compare the properties of the unknown elements with the properties of the known
elements. Based on these properties, match each unknown element to its group in the periodic table.
Drag each tile to the correct box.
Tiles
element 1 element 2
Pairs
group 1
group 2
group 11
group 14
group 17
group 18
element 3
element 4
element 5
element 6
Answers
Based on the properties of elements, elements can be arranged into groups in the periodic table as follows:
Group 1 to 3 - metals
Group 14 - non-metals, metalloids, and metals
Group 15 to 18 - non-metals
What are groups and periods in the periodic table?Groups are the names given to the periodic table's columns. In the table, individuals who belong to the same group make bonds of the same kind and have an equal number of electrons in their atoms' outermost shells.
Periods are the horizontal rows found in the periodic table.
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Calculate the oxidation number of oxygen in magnesium pyrophosphate Mg2p2o7
Answers
The oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7) is +5.
o calculate the oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7), we first need to know the oxidation states of the other atoms in the molecule.
The magnesium ion (Mg2+) has a fixed oxidation state of +2 in this compound, and the phosphate ion (PO43-) has an overall oxidation state of -3.
We can set up an equation to solve for the oxidation state of oxygen (O) in the pyrophosphate ion:
2(+2) + 2(O) + 7(-2) = 0
Simplifying the equation gives:
4 + 2O - 14 = 0
2O = 10
O = +5
Therefore, the oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7) is +5.
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The oxidation number of oxygen in magnesium pyrophosphate is -2.
How to calculate oxidation number?Oxidation number refers to the hypothetical charge of an atom within a molecule.
For monoatomic ions, the oxidation number always has the same value as the net charge corresponding to the ion.
Oxidation no. of Mg = +2Oxidation no. of P = +5Oxidation no of O = x0 = +2(2) + 5(2) + X(7)
0 = 14 + 7x
-14 = 7x
x = -2
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Make a drawing representing the reaction that occurs between calcium nitrate and sodium oxalate.
Answers
The reaction between calcium nitrate (Ca(NO₃)₂) and sodium oxalate (Na₂C₂O₄) can be represented by the following chemical equation:
Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2NaNO₃
This is a double displacement reaction, where the calcium ion (Ca²⁺) from calcium nitrate and the oxalate ion (C₂O₄²⁻) from sodium oxalate switch places to form calcium oxalate (CaC₂O₄) and sodium nitrate (NaNO₃). The balanced chemical equation shows that one mole of calcium nitrate reacts with one mole of sodium oxalate to form one mole of calcium oxalate and two moles of sodium nitrate.
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A piece of metal with a mass of 32.8 g is heated to 100.5 C and dropped into 138.2 g of water at 20.0 C. the final temperature of the system is 30.2 C. What is the specific heat capacity of the metal
Answers
Answer:
To solve this problem, we can use the equation:
Q = m * c * ΔT
where Q is the heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.
In this case, we know that the heat lost by the metal is equal to the heat gained by the water:
Q lost = Q gained
We can calculate the heat lost by the metal using the equation:
Q lost = m * c * ΔT
where m is the mass of the metal, c is the specific heat capacity of the metal (which we are trying to find), and ΔT is the change in temperature of the metal (100.5 C - 30.2 C = 70.3 C).
We can calculate the heat gained by the water using the equation:
Q gained = m * c * ΔT
where m is the mass of the water and ΔT is the change in temperature of the water (30.2 C - 20.0 C = 10.2 C).
Setting the two equations equal to each other, we get:
m * c * ΔT (metal) = m * c * ΔT (water)
Simplifying, we get:
c (metal) = (m * c * ΔT (water)) / (m * ΔT (metal))
Plugging in the values we know:
m (metal) = 32.8 g
ΔT (metal) = 70.3 C
m (water) = 138.2 g
ΔT (water) = 10.2 C
c (metal) = (138.2 g * 4.184 J/g·K * 10.2 C) / (32.8 g * 70.3 C)
c (metal) = 0.192 J/g·K
Therefore, the specific heat capacity of the metal is 0.192 J/g·K.
0.250 mol of KNO3 in 0.835 L of solution
Answers
0.30M is the molarity of the given solution with 0.250 mol and 0.835 L volume of solution
The amount of moles of solute that exist in a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Solvent, and 'solution' to make it simpler to comprehend the principles that will follow. A homogenous combination with any number of solutes in it is referred to as a solution.
Molarity = number of moles/ volume of solution in liter
Molarity = 0.250/ 0.835
= 0.30M
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Reaction Ai Sodium Bicarbonate and Hydrochloric Acid
Experimental Data
(a) Mass of evaporating dish
watch glass
(b) Mass of evaporating dish watch glass sodium bicarbonate
(c) Mass of sodium bicarbonate used
(d) Mass of evaporating dish watch glass sodium chloride
(e) Mass of sodium chloride collected (experimental yield)
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Mole Ration and Reaction Story
.
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Data Analysis
1) Use your data to determine the experimental mole-to-mole ratio between sodium bicarbonate and sodium chloride
Show your work for each
NaHCOS
Convert the mass of sodium bicarbonate used to moles
100.69
1
mole
9
Convert the mass of sodium chloride collected in moder
Nac
2g
104.2
3.bg
mole
g
Divide both of your results from the preceding two steps by the lower mole value to determine the simplest mole-to-
mole ratio between sodium bicarbonate and sodium chloride.
Answers
The reaction between sodium carbonate and hydrochloric acid
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
How to solveFor reaction A
Mass of sodium bicarbonate used = (Mas of evaporating dish + watch glas + sodium bicarbonate) - (Mas of evaporating dish + watch glas)
= 46.582 - 46.263
= 0.319 g
Mass of sodium chloride = (mas of evaporating dish + watch glas + sodium chloride) - (Mas of evaporating dish + watch glas)
= 46.473 - 46.263
= 0.210 g
Moles of sodium bicarbonate (NaHCO3) used = mas/molecular weight
= (0.319 g) / (84 g/mol)
= 0.00380 mol
Moles of sodium chloride (NaCl) used = mas/molecular weight
= (0.210 g) / (58.44 g/mol)
= 0.00359 mol
Mol ratio of NaHCO3 : NaCl = 0.00380 : 0.00359
Divide by 0.00359
Simple mol ratio
NaHCO3 : NaCl = 1.06 : 1
After rounding
Mol ratio of NaHCO3 : NaCl = 1 : 1
Moles of NaHCO3 = moles of NaCl = 0.00359 mol
Theoretical yield of NaCl = moles x molecular weight
= 0.00359 mol x 58.44 g/mol
= 0.210 g
the percent yield of sodium chloride
= actual yield x 100 / theoretical yield
= 0.210*100/0.210
= 100%
the reaction between sodium bicarbonate and hydrochloric acid
NaHCO3 + HCl = NaCl + CO2 + H2O
For reaction B
Mass of sodium carbonate used = (Mas of evaporating dish + watch glas + sodium carbonate) - (Mas of evaporating dish + watch glas)
= 51.677 - 51.368
= 0.309 g
Mass of sodium chloride = (mas of evaporating dish + watch glas + sodium chloride) - (Mas of evaporating dish + watch glas)
= 51.671 - 51.368
= 0.303 g
Moles of sodium carbonate (Na2CO3) used = mas/molecular weight
= (0.309 g) / (106 g/mol)
= 0.00292 mol
Moles of sodium chloride (NaCl) used = mas/molecular weight
= (0.303 g) / (58.44 g/mol)
= 0.00518 mol
Mol ratio of
Na2CO3 : NaCl = 0.00292 : 0.00518
Divide by 0.00292
Simple mol ratio
Na2CO3 : NaCl = 1 : 1.78
After rounding
Mol ratio of Na2CO3 : NaCl = 1 : 2
Moles of NaCl = 2 x moles of Na2CO3
= 2 x 0.00292 = 0.00584 mol
Theoretical yield of NaCl = moles x molecular weight
= 0.00584 mol x 58.44 g/mol
= 0.341 g
the percent yield of sodium chloride
= actual yield x 100 / theoretical yield
= 0.303*100/0.341
= 88.86%
the reaction between sodium carbonate and hydrochloric acid
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
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