what is the relationship between the unit cell length a and the atomic radius r for the body centered cubic

Answers

Answer 1

The relationship between the unit cell length a and the atomic radius r for the body centered cubic can be expressed by the formula:
a = 4r/√3

A unit cell is a cube of atoms, and in the body centered cubic structure, the unit cell contains 8 corner atoms and 1 central atom.

The 8 corner atoms each occupy a space of one-eighth of the total unit cell volume, whereas the central atom occupies one-half of the total unit cell volume. Thus, the total volume of a unit cell can be expressed as: V = a3.


The atomic radius, r, is the distance between the center of an atom and its outermost electron shells. Thus, the atomic radius of the central atom will be half of the length of the unit cell, a.

This can be expressed mathematically as: r = a/2.

By combining the two equations, a = 4r/√3, we can get the formula for the relationship between the unit cell length a and the atomic radius r for the body centered cubic: a = 4r/√3.

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Related Questions

determine the percent ionization of a solution having a ph of 4.35 and an initial weak acid concentration of 0.00019.

Answers

The percent ionization of a solution having a pH of 4.35 and an initial weak acid concentration of 0.00019 is 0.00021%.

To calculate this, first calculate the [H3O+] concentration.

This can be done by taking 10 raised to the power of the pH value, which in this case is 10^-4.35 = 3.2x10^-5 M.

Then, calculate the ionization fraction (alpha) using the equation alpha = [H3O+]/[HA], where [HA] is the initial weak acid concentration. In this case, alpha = 3.2x10^-5/0.00019 = 0.00021.

Finally, convert the ionization fraction to percent ionization using the equation Percent Ionization = 100 * alpha.

Thus, the percent ionization of the given solution is 0.00021 * 100 = 0.021%.

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onsider a process in which an ideal gas is compressed to one-fourth of its original volume at a constant temperature. calculate the entropy change per mole of gas.

Answers

The entropy change per mole of gas is -1.387R.

The entropy change per mole of gas in a process in which an ideal gas is compressed to one-fourth of its original volume at a constant temperature can be calculated as follows:

Let us denote the original volume as V₁, the final volume as V₂, and the number of moles of the gas as n. The entropy change can be calculated using the formula:

ΔS = nR ln (V₂/V₁)

Therefore, the entropy change per mole of gas is given by:

ΔSper mole = R ln (V₂/V₁)


In this case, V₁ = 4V₂ and so,

ΔSper mole = R ln (1/4) = - R ln 4 = -2.303 R log 4 = -1.387R

Thus, the entropy change per mole of gas when an ideal gas is compressed to one-fourth of its original volume at a constant temperature is -1.387R.

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4. a laboratory experiment calls for 0.150 m hno3. what volume of 0.150 m hno3 can be prepared form 0.350 l of 1.98 m hno3?

Answers

The volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

The given equation is used to calculate the volume (V1) of a desired concentration of a solution (0.150 M HNO3) that can be prepared from a given volume (V2) of a known concentration solution (1.98 M HNO3), using the ratios of their concentrations (C1 and C2).

Let's break down the calculation step by step using the given values:

V2 (given volume) = 0.350 L

C1 (desired concentration) = 0.150 M

C2 (known concentration) = 1.98 M

Plugging these values into the equation, we get:

V1 (0.150 M HNO3) = V2 (1.98 M HNO3) x (C1 (0.150 M) / C2 (1.98 M))

V1 = 0.350 L x (0.150 M / 1.98 M)

V1 = 0.350 L x 0.0758

V1 = 0.07112 L

Therefore, the volume of 0.150 M HNO3 that can be prepared from 0.350 L of 1.98 M HNO3 is 0.07112 L, or approximately 71.12 mL (since 1 L = 1000 mL).

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The diagram shows the cycling of matter in the interior of Earth.



Which statement correctly explains the cycling of matter in the interior of Earth?

Responses

The heat from Earth’s core causes material in the area under the crust to become less dense and rise, while more dense material sinks.

The heat from Earth’s core causes material in the area under the crust to become less dense and rise, while more dense material sinks.

The heat from Earth’s core causes material in the area under the crust to become more dense and rise, while less dense material sinks.

The heat from Earth’s core causes material in the area under the crust to become more dense and rise, while less dense material sinks.

The heat from Earth’s core causes material in the area under the crust to become less dense and sink, while more dense material rises.

The heat from Earth’s core causes material in the area under the crust to become less dense and sink, while more dense material rises.

The heat from Earth’s core causes material in the area under the crust to become more dense and sink, while less dense material rises.

The heat from Earth’s core causes material in the area under the crust to become more dense and sink, while less dense material rises.

Answers

Answer:

Explanation:

I think 'The heat from Earth's core causes material in the area under the crust to become denser and rinse, while less dense material sinks.

please help the image is attached!!!​

Answers

Answer:

0.6096

Explanation:

*formula for moles= mass/molormass(RFM)

Molarmass= (28×1)+(19×4)= 104

63.4/104= 0.60961

a sample of xe takes 75 seconds to effuse out of a container. an unknown gas takes 37 seconds to effuse out of the identical container under identical conditions. what is the most likely identity of the unknown gas?

Answers

The most likely identity of the unknown gas that effuses taking 37s is Oxygen(O₂).


Since the unknown gas effuses out faster, it must be lighter than Xe.

The most likely identity of the unknown gas can be determined using Graham's Law of Diffusion. According to this, the time taken for effusion/diffusion of two different gases under identical conditions is directly proportional to the square roots of their densities or molecular masses. It is given as:

t₂/t₁ = √(M₂/M₁)

where t₂,t₁ are the times taken and M₂, M₁ are the molecular masses.

This ratio is determined by the ratio of the molecular weights of the unknown gas and the sample of Xe. The heavier the molecular weight, the slower the rate of effusion.



Rearranging and plugging in the values as t₂= 75s, t₁= 37s,  M₁= 131g (for Xe), we get M₂ as follows:

M₂= (37/75)² x 131 = 31.8 ≈ 32g

32g corresponds to the molecular weight of O₂ and it is lighter than Xe.

Therefore, the unknown gas that effuses out of the container faster than the sample of Xe, resulting in the unknown gas taking 37 seconds, and the sample of Xe taking 75 seconds is oxygen(O₂).

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If I have 6.00 moles of gas held at a temperature of 93.5 C and in a container with a volume of 41.7 liters, what is the pressure of the gas (ka)?

Answers

The pressure of the gas is approximately 4.57 atm or 438.629 kPa

What is the pressure of the gas (ka)?

The Ideal gas law or general gas equation states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given that;

P = pressure of the gas (in atm) = ?V = volume of the gas (in L) = 41.7 Ln = number of moles of gas = 6R = the ideal gas constant (0.08206 L.atm/mol.K)T = temperature of the gas (in Kelvin) 93.5°C

First, we need to convert the temperature to Kelvin:

T (K) = T (Celsius) + 273.15

T (K) = 93.5 + 273.15

T (K) = 366.65 K

Now we can substitute the given values into the formula:

PV = nRT

P = nRT / V

P = ( 6 × 0.08206 × 366.65 ) / 41.7

P = 4.33 atm

Convert to kPa by multiplying the pressure value by 101.3

P = ( 4.33 × 101.3 ) kPa

P = ( 4.33 × 101.3 ) kPa

P = 438.629 kPa

The pressure is approximately 4.57 atm or 438.629 kPa.

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research a common household chemical, a cosmetic compound, a medical drug, or something else that is commonly known and find out what its chemical name is.

Answers

The chemical name of water is hydrogen oxide.

Water is a compound with the chemical name hydrogen oxide (H2O).

It is a colorless, odorless, and tasteless liquid that is essential for most forms of life on Earth.

Water is a chemical molecule; therefore, its many forms have different names depending on their individual constituents. According to the nomenclature established by the IUPAC, water may alternatively be referred to as dihydrogen monoxide, dihydrogen oxide, hydrogen hydroxide, or hydric acid.

Being the primary component of Earth's hydrosphere and the fluids of all known forms of life, water (chemical formula H 2 O) is an inorganic, clear, tasteless, odorless, and almost colorless chemical substance (in which it acts as a solvent). None of the known forms of life could survive without it, despite the fact that it offers neither dietary energy nor organic micronutrients.

Water is made up of two hydrogen atoms and one oxygen atom, with the formula H2O.

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Select all that apply
Identify the cranial nerves associated with gastrointestinal tract motor output. Select all that apply.
vagus
trochlear
hypoglossal
facial
olfactory
glossopharyngeal

Answers

The cranial nerves associated with gastrointestinal tract motor output are vagus nerve, glossopharyngeal nerve, and facial nerve. The correct options are option A, D, and F.

Cranial nerves are the nerves that emanate directly from the brain. There are 12 pairs of cranial nerves. These nerves are responsible for transmitting sensory information such as vision, hearing, and touch as well as motor signals like movement and coordination to different parts of the body.

The cranial nerves that are responsible for gastrointestinal tract motor output are Vagus, Glossopharyngeal, and Facial.

The vagus nerve is the 10th cranial nerve and is one of the most critical nerves for gut activity. This nerve is a major parasympathetic supply to the upper GI tract, including the stomach and small intestine.

It has both motor and sensory fibers. The parasympathetic component of the vagus nerve promotes the release of acetylcholine, which stimulates the GI muscles to contract and propel food through the digestive tract.

The vagus nerve may also control some metabolic activities, including insulin release and glucose metabolism.

The glossopharyngeal nerve is the 9th cranial nerve and plays an essential role in controlling the muscles of the pharynx and throat. This nerve's motor component is responsible for activating the pharynx and upper esophageal sphincter when swallowing, which helps in propelling food through the GI tract.

The facial nerve is the 7th cranial nerve and plays a crucial role in controlling the muscles of facial expression. It also has a sensory component, which is responsible for taste perception in the anterior two-thirds of the tongue.

Additionally, it supplies parasympathetic fibers to the salivary and lacrimal glands, which are responsible for secreting enzymes and fluids that help in digestion.

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what would be the unit of measurement for a surface area that has degrees farenheit as the height and time as the width?

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The unit of measurement for a surface area that has degrees Fahrenheit as the height and time as the width would be square degrees Fahrenheit x time.

Surface area is a measurement of the total area that the surface of an object occupies. The surface area is measured in square units. If the surface of an object is rectangular or square, it is calculated by multiplying the length of the object by the width of the object. For the curved surfaces, the formula for the surface area is complicated. However, the concept of square units remains the same for curved surfaces.

Fahrenheit is a unit of temperature that is used to measure the temperature of an object. This is used primarily in the United States and other countries that have adopted the Imperial system of units. It is based on a scale of 180 degrees between the freezing and boiling points of water, where the freezing point is 32°F and the boiling point is 212°F.

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which of the combinations below will produce an insoluble salt? a) ba(oh)2 hcl b) mnso4 pb(no2)2 c) h2so4 albr3

Answers

The combination that will produce an insoluble salt is b) MnSO4 Pb(NO2)2.

A salt is a chemical compound made up of cations (positively charged ions) and anions (negatively charged ions) (negatively charged ions). The ions must be combined in such a way that the sum of the charges is zero. NaCl is the most well-known saltand it is made up of sodium cations (Na+) and chloride anions (Cl-).MnSO4 Pb(NO2)2 is the answer since both of these elements are soluble. MnSO4 is a soluble substance that is sometimes used in the production of ceramics.

MnSO4 is often used as a nutritional supplement for animals since it is a good source of manganese. Pb(NO2)2 is a powder that is bright yellow, it has a molar mass of 325.2 g/mol. It is made up of two NO2 anions (negatively charged ions) and one Pb2+ cation (positively charged ion).The formation of insoluble salts can occur when the cations and anions in a reaction solution bind to create a new solid. Since the newly formed solid is insoluble, it settles to the bottom of the solution and can be separated from the liquid through filtration. The insoluble salt that is formed is a white or colorless substance that appears as a powder.

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potassium nitrate is used for a variety of applications, including fertilizer, rocket fuel, and fireworks. how many formula units of potassium nitrate are in a 25 g sample?

Answers

There are 1.49 × 10²³ formula units of potassium nitrate in a 25 g sample.

One formula unit is defined as the simplest formula of a substance, which indicates the relative amounts of the elements in the molecule. As a result, the number of formula units in a sample can be calculated by dividing the sample's mass by the substance's molar mass.

The molecular formula of potassium nitrate is KNO3. It contains one potassium atom (K), one nitrogen atom (N), and three oxygen atoms (O). The atomic masses of the elements can be used to calculate the molar mass of the compound.

One potassium atom has a molar mass of 39.1 g/mol, one nitrogen atom has a molar mass of 14.0 g/mol, and three oxygen atoms have a combined molar mass of 48.0 g/mol.

The molar mass of KNO3 = (1 × 39.1 g/mol) + (1 × 14.0 g/mol) + (3 × 16.0 g/mol) = 101.1 g/mol.

Now, on dividing the sample's mass (25 g) by the molar mass of potassium nitrate (101.1 g/mol), a value of 0.247 mol is obtained. The Avogadro constant can be used to convert moles into formula units. The Avogadro constant, 6.022 × 10²³ formula units per mole, represents the number of formula units in one mole of a substance.

The number of formula units = (0.247 mol) × (6.022 × 10²³ formula units/mol) = 1.49 × 10²³ formula units.

Therefore, there are 1.49 × 10²³ formula units of potassium nitrate in a 25 g sample.

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in which scenario would we be unable to treat the first and second ionization of a diprotic acid as completely separate reactions?

Answers



The first and second ionization of a diprotic acid cannot be treated as completely separate reactions when the reaction is taking place in an environment with a fixed pH.

The second ionization of the acid is dependent on the concentration of the ions produced from the first ionization.

If the pH is fixed, then the concentration of the first ionization is also fixed, so the second ionization will not occur completely independently.

For example, a diprotic acid such as oxalic acid can be completely ionized in two steps. In the first ionization, the hydrogen ions of the oxalic acid are replaced with hydroxide ions, forming the oxalate ion:

H2C2O4 + 2H2O → H3O+ + HC2O4–

In the second ionization, the oxalate ion is further dissociated, forming two separate anions and hydronium ions:

HC2O4– + H2O → H3O+ + C2O4–2

However, in an environment with a fixed pH, the second ionization will not take place as the concentration of oxalate ions from the first ionization is fixed.

Therefore, the two ionizations must be treated together in order to accurately predict the final concentrations of the products.

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Answer:

The first ionization constant is greater than the second ionization constant by only a factor of 10.

Explanation:

The two ionization constants must differ by a factor of at least 20 in order to treat the first and second ionizations as chemically (and mathematically) distinct.

the energy required to break one mole of iodine-iodine bonds in i2 is 151 kj/mol. what is the longest wavelength of light capable of breaking a single i-i bond?

Answers

The longest wavelength of light capable of breaking a single I-I bond is approximately 787 nm (nanometers).

What is energy ?

Energy is considered a quantitative property that can be transferred from an object to perform work.

The energy required to break a mole of I2 molecules is 151 kJ/mol. We can use this information to calculate the energy required to break a single I-I bond:

Energy required to break a single I-I bond = Energy required to break one mole of I2 molecules / Avogadro's number

Energy required to break a single I-I bond = 151 kJ/mol / 6.022 x 10^23 molecules/mol

Energy required to break a single I-I bond = 2.51 x 10^-19 J/bond

To calculate the longest wavelength of light capable of breaking a single I-I bond, we can use the equation:

E = hc/λ

Where

E is the energy of a photon h is Planck's constant c is the speed of lightλ is the wavelength of light

We want to find the wavelength of light that has an energy of 2.51 x 10^-19 J, so we can rearrange the equation as follows:

λ = hc/E

λ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (2.51 x 10^-19 J)

λ = 7.87 x 10^-7 m

Therefore, the longest wavelength of light capable of breaking a single I-I bond is approximately 787 nm (nanometers).

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how much oxygen is needed to completely oxidize 1.67*10-3 m glucose solution (c6h12o6) completely to co2 and h2o?

Answers

8 moles of oxygen are required to completely oxidize 1.67*10-3 m glucose solution (C6H12O6) completely to CO2 and H2O.

In order to completely oxidize 1.67*10-3 m glucose solution (C6H12O6) completely to CO2 and H2O, 8 moles of oxygen are required.

The balanced equation of the reaction, which is: C6H12O6 + 6O2 ---> 6CO2 + 6H2O.

As there are 6 moles of oxygen molecules on the reactant side, 8 moles of oxygen molecules are needed to completely oxidize 1.67*10-3 m of glucose solution.

This can also be calculated by the equation n=N/V, where n is the molarity of the solution, N is the number of moles of solute and V is the volume of the solution.

Therefore, 8 moles of oxygen is equal to the molarity of the glucose solution multiplied by the volume.

The reaction between oxygen and glucose to form CO2 and H2O is an oxidation reaction. In oxidation reactions, the reactant molecules are oxidized, and as a result, oxygen is reduced.

Therefore, oxygen is needed for the oxidation of glucose molecules to occur. In other words, without the presence of oxygen, the oxidation of glucose to CO2 and H2O cannot occur.

In conclusion, 8 moles of oxygen are required to completely oxidize 1.67*10-3 m glucose solution (C6H12O6) completely to CO2 and H2O.

This can be calculated by the balanced equation of the reaction or by the equation n=N/V. This is an oxidation reaction, meaning oxygen is necessary for the oxidation of glucose molecules to occur.

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A gas sample at constant pressure and temperature filled with Helium gas had a volume of 221 mL and 4.00 moles. If the volume is increased to 500 ml what is the number of moles of Helium gas that could occupy the container? 0.11 K 9.05 kPa 0.11 kPa 9.05 mol​

Answers

The number of moles of Helium gas that could occupy the container when the volume is increased to 500 mL is 9.05 mol.

What is the number of moles of the gas?

We can use the combined gas law to solve this problem:

(P1 x V1) / (n1 x T1) = (P2 x V2) / (n2 xT2)

where;

P is pressure, V is volume, n is number of moles, and T is temperature.

We know that the pressure and temperature are constant, so we can simplify the equation to:

V1/n1 = V2/n2

Solving for n2, we get:

n2 = (V2n1) / V1

Plugging in the values, we get:

n2 = (500 mL * 4.00 mol) / 221 mL

n2 = 9.05 mol

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upon combustion, a compound containing only carbon and hydrogen produces 2.77 gco2 and 0.851 gh2o . find the empirical formula of the compound.

Answers

Answer:Gco is 0.953

Explanation:

Calculate the pH of a 0.050 M solution of hydroxylamine, NH2OH. Kb = 6.6 x 10^-9

Answers

The pH of hydroxylamine will be 8.76.

The first step is to write the balanced equation for the reaction of hydroxylamine with water:

NH₂OH + H₂O ⇌ NH₃OH⁺ + OH⁻

The Kb expression for this reaction is:

Kb = [NH₃OH⁺][OH⁻] / [NH₂OH]

We are given the Kb value as 6.6 x 10⁻⁹, so we can use this to find the concentration of hydroxylamine that has been deprotonated:

Kb = [NH₃OH⁺][OH⁻] / [NH₂OH]

6.6 x 10⁻⁹ = x² / (0.050 - x)

Assuming that x is very small compared to 0.050, we can simplify the expression as follows:

6.6 x 10⁻⁹ = x² / 0.050

x² = 3.3 x 10⁻¹⁰

x = 5.7 x 10⁻⁶ M

Now that we have the concentration of hydroxide ions, we can use this to find the pH of the solution:

pOH = -log[OH-] = -log(5.7 x 10⁻⁶) = 5.24

pH = 14.00 - pOH = 8.76

Therefore, the pH of a 0.050 M solution of hydroxylamine is 8.76.

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which of the following samples has the most moles of the compound? a) 163.0 g of fe2o3 b) 75.0 g of cas c) 150.0 g of bao d) all of the above have the same moles. e) impossible to determine unless the density of each compound is known.

Answers

The samples that  has the most moles of the compound is option B which is 75.0g

Moles calculation .

To determine which sample has the most moles of the compound, we need to calculate the number of moles of each compound using its molar mass.

a) Fe2O3:

Molar mass of Fe2O3 = 2(55.85 g/mol of Fe) + 3(16.00 g/mol of O) = 159.70 g/mol

Number of moles of Fe2O3 = 163.0 g / 159.70 g/mol = 1.02 mol

b) CaS:

Molar mass of CaS = 40.08 g/mol of Ca + 32.06 g/mol of S = 72.14 g/mol

Number of moles of CaS = 75.0 g / 72.14 g/mol = 1.04 mol

Therefore, sample b) (75.0 g of CaS) has the most moles of the compound, with 1.04 moles. Sample a) (163.0 g of Fe2O3) has 1.02 moles and sample c) (150.0 g of BaO) has 0.98 moles.

So, the correct answer is b.

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a solution of cacl2 cacl 2 in water forms a mixture that is 31.5% 31.5 % calcium chloride by mass. if the total mass of the mixture is 195.4 g, 195.4 g, what masses of cacl2 cacl 2 and water were used?

Answers

The masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.

The mass of calcium chloride (CaCl2):
The percentage of calcium chloride (CaCl2) in the mixture is 31.5%.


Multiply the total mass of the mixture (195.4 g) by 31.5% to find the mass of calcium chloride (CaCl2) in the mixture:
Mass of calcium chloride (CaCl2) = (195.4 g) x (31.5%) = 61.18 g

The mass of water:
Subtract the mass of calcium chloride (CaCl2) from the total mass of the mixture (195.4 g) to find the mass of water in the mixture:


Mass of water = (195.4 g) - (61.18 g) = 134.22 g

Therefore, masses of calcium chloride (CaCl2) and water used to form the mixture are 61.18 g and 134.22 g, respectively.

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Universal waste shipments records must be retained for a minimum of three years

Answers

Universal waste is a category of hazardous waste that includes certain widely generated electronic devices, batteries, lamps, and other devices that contain hazardous materials.

The handling, storage, transportation, and disposal of universal waste is subject to regulations by the United States Environmental Protection Agency (EPA) under the Universal Waste Rule.

One of the requirements of the Universal Waste Rule is that records of universal waste shipments must be retained for a minimum of three years. This applies to any person who generates, collects, transports, or receives universal waste. The records must include the following information:

Name and address of the universal waste handler (generator, transporter, or receiving facility)EPA identification number of the universal waste handlerDate of shipmentType and quantity of universal waste shippedName and address of the transporter (if applicable)

Retention of these records helps to ensure compliance with the regulations and enables tracking of the movement and disposition of universal waste. The records must be made available for inspection by authorized EPA officials upon request.

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A solution with eggs has a [H+] of 1×10−8 M.

Which type of solution is this?

Responses

ionic

basic

acidic

neutral

Answers

A solution with eggs has a [H⁺] of 1×10⁻⁸ M is basic in nature which has more pH of 8  which is slightly alkaline, but still considered neutral.

What is solution ?

In chemistry, a solution is a homogeneous mixture of two or more substances in relative amounts that can be varied constantly up to the limit of solubility. The term "solution" refers to the liquid state of matter, but solutions of gases and solids are also conceivable. For example, air is a solution made up primarily of oxygen and nitrogen, with trace quantities of several other gases, whereas brass is a solution made up of copper and zinc. The liquid in a solution is known as the solvent, and the substance introduced is known as the solute. If both components are liquids, the difference becomes meaningless; the one with the lower concentration is likely to be referred to as the solute. Any component's percentage in a solution can vary.

pH is directly proportional to hydrogen ion concentration.

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A solution with eggs has a [H⁺] of 1×10⁻⁸ M is basic in nature which has more pH of 8  which is slightly alkaline, but still considered neutral. The correct option is B.

pH of egg shell?Due to presence of calcium carbonate in the shells it has the pH in the basic range.Egg white is one of the few food products that is naturally alkaline, with an initial pH value that can be as low as 7.6 at the time of lay but with rising alkalinity as the egg ages and can reach pH of 9.2. Whole eggs are typically pH neutral, but egg white is one of the few food products that is naturally alkaline.Eggshells have an alkaline pH. If enough alkaline material is used, it will react with the acid to neutralize some or even all of it.Eggshells that have been ground very finely will barely make a difference in less acidic soil. After the pH of the soil reaches about 6.8, the study in (ref 4) discovered that eggshells no longer effect pH. Because they cease decomposing at a pH of 6.8, they stop modifying the pH.

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Complete question:

A solution with eggs has a [H+] of 1×10−8 M.

Which type of solution is this?

Responses

A. ionic

B. basic

C. acidic

D. neutral

in an equilibrium mixture at 500k, the partial pressure of pcl 5 is 0.860 atm, pcl 3 is 0.350 atm, and cl 2 is 1.22 atm. calculate the equilibrium constant (k p ) for this reaction.

Answers

0.493 is the equilibrium constant (k p ) for [tex]PCl_5[/tex] (g) ⇌ [tex]PCl_3[/tex] (g) + [tex]Cl_2[/tex] (g) reaction at 500k.

The reaction is given as

[tex]PCl_5[/tex] (g) ⇌ [tex]PCl_3[/tex] (g) + [tex]Cl_2[/tex] (g)

At 500 K, the partial pressure of [tex]PCl_5[/tex] is 0.860 atm, [tex]PCl_3[/tex] is 0.350 atm, and [tex]Cl_2[/tex] is 1.22 atm.

To calculate the equilibrium constant ([tex]K_P[/tex]) for this reaction, we need to use the equation

[tex]K_P[/tex] = [[tex]PCl_3[/tex]] [[tex]Cl_2[/tex]] / [[tex]PCl_5[/tex]]

Here, [[tex]PCl_5[/tex]] = 0.860 atm

[[tex]PCl_3[/tex]] = 0.350 atm

[[tex]Cl_2[/tex]] = 1.22 atm

Substituting these values, we get

[tex]K_P[/tex] = (0.350)(1.22) / 0.860

[tex]K_P[/tex] = 0.493

Therefore, the equilibrium constant ([tex]K_P[/tex]) for this reaction at 500 K is 0.493.

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water molecules are attracted to each other and to ions due to . group of answer choices the viscosity of water. electron transfer. electron sharing. surface tension. the polarity of water molecules.

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Water molecules are attracted to each other and to ions due to the polarity of water molecules.

The separation of electric charge leading to a molecule having two poles, one positive and the other negative, is referred to as polarity. A polar molecule has a permanent dipole, whereas a nonpolar molecule does not. Water is an example of a polar molecule. The polarity of water is the reason why it is a good solvent and why it is attracted to other polar molecules and ions.

In water, the polar water molecules are pulled toward each other, forming hydrogen bonds. These hydrogen bonds give water its unique properties, such as high surface tension, capillary action, and high boiling and melting points. Ions are also attracted to water due to the polar nature of water molecules. Water molecules surround ions in a process known as hydration or solvation, which stabilizes the ions in solution.

As a result of the polarity of water, it is able to dissolve a wide range of ionic and polar substances, making it one of the most significant substances on the planet.

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a certain organic compound contains only c, h, and o. combustion of 0.1000 g of this compound produced 0.2921 g of co2 and 0.0951 g of h2o. what is the empirical formula of the compound?

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The empirical formula of the organic compound is C1H1O1 and the simplified form is CHO.

To find the empirical formula of the compound, we need to determine the mole ratios of the elements in the compound.

First, we need to find the number of moles of CO2 and H2O produced by the combustion of 0.1000 g of the compound:

moles of CO2 = 0.2921 g / 44.01 g/mol = 0.006639 mol

moles of H2O = 0.0951 g / 18.02 g/mol = 0.005275 mol

Next, we need to find the number of moles of C and H in the compound. From the combustion reactions, we know that all of the carbon in the compound is converted to CO2, and all of the hydrogens are converted to H2O.

Therefore, the number of moles of C and H in the compound is equal to the number of moles of CO2 and H2O produced, respectively:

moles of C = 0.006639 mol

moles of H = 0.005275 mol

Finally, we need to find the number of moles of O in the compound. We can do this by subtracting the number of moles of C and H from the total number of moles of elements in the compound, which is equal to the mass of the compound divided by its molar mass:

moles of O = (0.1000 g / molar mass of compound) - moles of C - moles of H

The molar mass of the compound is equal to the sum of the molar masses of its constituent elements:

molar mass of compound = molar mass of C + molar mass of H + molar mass of O

Since we don't know the formula of the compound yet, we can assume a generic formula of CxHyOz and calculate the molar mass of this compound as:

molar mass of compound = x(molar mass of C) + y(molar mass of H) + z(molar mass of O)

Using the atomic masses of C, H, and O, we can calculate the molar masses of these elements as:

molar mass of C = 12.01 g/mol

molar mass of H = 1.01 g/mol

molar mass of O = 16.00 g/mol

Substituting these values, we get:

molar mass of compound = 12.01x + 1.01y + 16.00z

Now, we can solve for the number of moles of O in the compound:

moles of O = (0.1000 g / molar mass of compound) - moles of C - moles of H

Substituting the values we found earlier for moles of C and H, we get:

moles of O = (0.1000 g / (12.01x + 1.01y + 16.00z)) - 0.006639 mol - 0.005275 mol

Simplifying, we get:

moles of O = 0.1000 g / (12.01x + 1.01y + 16.00z) - 0.011914 mol

To determine the empirical formula of the compound, we need to find the smallest whole number mole ratio of the elements in the compound. We can do this by dividing the number of moles of each element by the smallest number of moles:

moles of C / 0.005275 = 1.259

moles of H / 0.005275 = 1.000

moles of O / 0.005275 = (0.1000 g / (12.01x + 1.01y + 16.00z) - 0.011914 mol) / 0.005275

Simplifying, we get:

moles of O / 0.005275 = 18.998 - (1.258x + y)

To find the smallest whole number ratio, we can multiply each mole ratio by a common factor that makes the smallest ratio a whole number. In this case, the smallest ratio is 1:1, so we can multiply each ratio by a factor of approximately 0.79 to make the C and H ratios both equal to 1. This gives us:

C: 1.000

H: 0.790

O: 1.484

Since we want whole numbers, we can round these ratios to the nearest whole number, giving us the empirical formula: C1H1O1 or simply CHO.

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if the rate constant for a reaction triples when the temperature rises from 25 oc to 65 oc, what is the activation energy of the reaction? give answer in kj/mole.

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The activation energy of the reaction, given that the rate constant has tripled when the temperature rose from 25 °C to 65 °C, is 42.6 kJ/mole.


Activation energy is the minimum energy required for a reaction to take place. It is calculated using the Arrhenius equation, which states that the rate constant, k, is proportional to the exponential of negative activation energy (Ea) divided by the gas constant (R) multiplied by the absolute temperature (T).

As the rate constant has tripled when the temperature increased, the activation energy can be calculated as Ea = -R * (1/T2 - 1/T1).

Plugging in the given temperature values of 25 °C and 65 °C and the gas constant, R, the activation energy is 42.6 kJ/mole.

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which of the following substances would undergo dissociation when placed into a polar solvent? question 1 options: c6h12o6 h2o2 mgcl2 co2

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The substance that would undergo dissociation when placed into a polar solvent is option C which is  MgCl2.

Dissociation explained.

Dissociation refers to the separation of a molecule or compound into smaller particles, such as ions or radicals, usually in a solvent or under the influence of a certain energy input, such as heat or light.

In the context of chemistry, dissociation often refers to the separation of an ionic compound into its constituent ions in a solvent, such as water

MgCl2 is an ionic compound that consists of Mg2+ cations and Cl- anions. When this compound is placed in a polar solvent, such as water, the polar water molecules surround the ions and separate them from one another, resulting in the dissociation of the compound into its constituent ions.

Therefore,  other substances listed, C6H12O6 (glucose), H2O2 (hydrogen peroxide), and CO2 (carbon dioxide), are not ionic compounds and do not dissociate into ions when placed in a polar solvent. Glucose and hydrogen peroxide are polar molecules, but they do not ionize in water. Carbon dioxide is a nonpolar molecule and is insoluble in water.

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Indicate if the following pairs of compounds could be separated via liquid-liquid extraction.First, draw the structures of the compounds, next determine whether they are acids or bases or neutral. Finally, look up their pKa (or pKb) values and indicate which aqueous solution would separate them or if they are inseparable. Assume that you can utilize aqueous HCl, NaOH, or NaHCO3 for your extractions. For each case that will not work, give the reason.You don't have to draw structure, just explain if they are able to be separated or not and with what and why.1. picric acid and phenol2. salicyclic acid and phenol3. triethylamine and diethylamine4. 3-nitrobenzoic acid and 2-nitrobenzoic acid5. benzylamine and aniline

Answers

Picric acid and phenol, Salicylic acid and phenol & Benzylamine and aniline can be separated using liquid-liquid extraction but Triethylamine and diethylamine & 3-nitrobenzoic acid and 2-nitrobenzoic acid cannot be separated using liquid-liquid extraction.

1. Picric acid and phenol can be separated using liquid-liquid extraction. Picric acid is a stronger acid (pKa ~0.4) than phenol (pKa ~10). Adding aqueous NaOH will deprotonate picric acid and make it soluble in the aqueous layer, while phenol remains in the organic layer. Then, the two compounds can be separated.
2. Salicylic acid and phenol can also be separated using liquid-liquid extraction. Salicylic acid (pKa ~3) is more acidic than phenol (pKa ~10). Adding aqueous NaHCO3 will deprotonate salicylic acid, making it soluble in the aqueous layer, while phenol remains in the organic layer. The compounds can then be separated.
3. Triethylamine and diethylamine cannot be easily separated via liquid-liquid extraction, as both are bases (pKb values are similar). Aqueous HCl, NaOH, or NaHCO3 will not be effective in separating these compounds. Alternative separation methods, like distillation, may be needed.
4. 3-nitrobenzoic acid and 2-nitrobenzoic acid cannot be separated using liquid-liquid extraction, as they have similar acidity (pKa values are close) and will react similarly with HCl, NaOH, or NaHCO3. Alternative separation methods, like chromatography, should be considered.
5. Benzylamine and aniline can be separated using liquid-liquid extraction. Benzylamine is a weaker base (pKb ~4.2) than aniline (pKb ~9.4). Adding aqueous HCl will protonate aniline, making it soluble in the aqueous layer, while benzylamine remains in the organic layer. The two compounds can then be separated.

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when fecl3 is ignited in an atmosphere of pure oxygen, this reaction takes place if 3.00 moles of fecl3 is ignited in the presence of 2.00 moles of o2 gas, how much of which reagent is present in excess and therefore remains unreacted?

Answers

The excess reagent is FeCl₃ and 0.33 moles of FeCl₃ remains unreacted after igniting 3.00 moles of FeCl₃ with 2.00 moles of O₂ gas.

The balanced chemical equation for the reaction between FeCl₃ and O₂ is:

4 FeCl₃ + 3 O₂ → 2 Fe₂O₃ + 6 Cl₂

From the balanced equation, we can see that for every 4 moles of FeCl₃, we need 3 moles of O₂.

To determine what is the excess reagent and how much of it is left over, we need to calculate the amount of each reagent required for complete reaction:

3.00 moles FeCl₃ × (3 moles O₂/4 moles FeCl₃) = 2.25 moles O₂ required

2.00 moles O₂ × (4 moles FeCl₃/3 moles O₂) = 2.67 moles FeCl₃ required

Since we only have 2.00 moles of O₂ available, this is the limiting reagent and there is not enough O₂ to react completely with all 3.00 moles of FeCl₃. Therefore, FeCl₃ is the excess reagent.

The amount of excess reagent remaining can be calculated by subtracting the amount required for complete reaction from the amount initially present:

Excess FeCl₃ = 3.00 moles - 2.67 moles = 0.33 moles

Therefore, there is an excess of 0.33 moles of FeCl₃ remaining unreacted. There is no excess of O₂ remaining, as we started with less than the amount required for complete reaction.

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A mixture of 90. 0grams of ch4 and 10. Ograms of argon has a pressure of 250 torr under the condition of constant temperature and pressure the partial pressure of ch4 is

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The partial pressure of CH₄ in the mixture is 239 torr.

We can use the mole fraction of methane (CH4) to calculate its partial pressure in the mixture. First, we need to convert the masses of each component into moles:

moles of CH₄ = 90.0 g / 16.04 g/mol = 5.61 mol

moles of Ar = 10.0 g / 39.95 g/mol = 0.250 mol

Next, we can calculate the total moles of gas in the mixture,

total moles = moles of CH₄ + moles of Ar = 5.61 mol + 0.250 mol = 5.86 mol

Now we can calculate the mole fraction of CH₄,

mole fraction of CH₄ = moles of CH₄ / total moles = 5.61 mol / 5.86 mol = 0.957

Finally, we can use the mole fraction and total pressure to calculate the partial pressure of CH₄,

partial pressure of CH₄ = mole fraction of CH₄ x total pressure = 0.957 x 250 torr = 239 torr

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