Answer:
4x - 43
Step-by-step explanation:
This Question requires the concept of solving algebraic expressions.
Algebraic ExpressionsAlgebraic Expressions are expressions made up of alphabet variables and numbers and can be simplified using order of operations just like numerical expressions.
Example: 8(4x-6) = 32x - 48
ApplicationFor this question, we will use the same concept as above to solve for the expression.
[tex]7(x - 4) - 3(x + 5) = 7x - 28 - (3x + 15) \\ = 7x - 28 - 3x - 15 \\ = 4x - 43[/tex]
Factoring
64v^4-225w^10
I come up with
(8v^2+15w^2)(8v^2-15w^5) can I simplify it?
Your answer can't be simplified but it's also slightly incorrect. No worries!
You can simplify (64v^4 - 225w^10) by applying the difference of squares --> a^2 - b^2 = (a + b)(a - b)
Here, (64v^4) is a^2, and (225w^10) is b^2.
[tex]\sqrt{64v^4 }[/tex] = a = 8v^2
[tex]\sqrt{225w^{10} }[/tex] = b = 15w^5
Substitute the values:
(8v^2 + 15w^5)(8v^2 - 15w^5)
Therefore, the factorization of [tex]64x^{4} -225w^{10}[/tex] is:
[tex](8v^{2} + 15w^5)(8v^2-15w^5)[/tex]
The factorization is already the simplest. It can't be simplified further.
Find the output, f, when the input, t, is 7 f = 2t - 3 f = Stuck? Watch a video or use a hint.
Answer:
f=11
Explanation:
Given the function:
[tex]f=2t-3[/tex]When the input, t=7
The value of the output, f will be gotten by substituting 7 for t.
[tex]\begin{gathered} f=2t-3 \\ =2(7)-3 \\ =14-3 \\ f=11 \end{gathered}[/tex]The output, f is 11.
Estimate the time it would take you to drive 278 miles at38 miles per hour. Round to the nearest hour
Speed formula:
[tex]s=\frac{d}{t}[/tex]d is the distance
t is the time
As you need to find a time having the distance and speed, solve the equation above for t:
[tex]\begin{gathered} t\cdot s=d \\ t=\frac{d}{s} \end{gathered}[/tex]Use the given data to find the time:
[tex]\begin{gathered} t=\frac{278mi}{38mi/h} \\ \\ t=7.31h \\ \\ t=7h \end{gathered}[/tex]Then, it would take you 7 hours to drive 278 mi at 38mi/hThis relation map is the musician to the instrument they play. is this relation a function?
What is the image point of (-12, —8) after the transformation R270 oD ?
Answer
(-12, -8) after R270°.D¼ becomes (-2, 3)
Explanation
The first operation represented by R270° indicates a rotation of 270° counterclockwise about the origin.
When a rotation of 270° counterclockwise about the origin is done on some coordinate, A (x, y), it transforms this coordinates into A' (y, -x). That is, we switch y and x, then add negative sign to x.
Then, the second operation, D¼ represents a dilation of the coordinate about the origin by a scale factor of ¼ given.
The coordinates to start with is (-12, -8)
R270° changes A (x, y) into A' (y, -x)
So,
(-12, -8) = (-8, 12)
Then, the second operation dilates the new coordinates obtained after the first operation by ¼
D¼ changes A (x, y) into A' (¼x, ¼y)
So,
(-8, 12) = [¼(-8), ¼(12)] = (-2, 3)
Hope this Helps!!!
Hello, I need help with this practice problem. Thank you so much.
Answer:
5 units
Explanation:
Given the points:
[tex]\begin{gathered} \mleft(x_1,y_1\mright)=K(-2,-1) \\ \mleft(x_2,y_2\mright)=N(2,2) \end{gathered}[/tex]We use the distance formula below:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Substitute the given values:
[tex]\begin{gathered} KN=\sqrt[]{(2-(-2))^2+(2-(-1))^2} \\ =\sqrt[]{(2+2)^2+(2+1)^2} \\ =\sqrt[]{(4)^2+(3)^2} \\ =\sqrt[]{16+9} \\ =\sqrt[]{25} \\ =5\text{ units} \end{gathered}[/tex]The distance between the two points is 5 units.
Picture of question linked. The choices for the answer are -infinity, infinity, and 0
The behavior of any polynomial function is determined by the exponent and the signal of the first term of the function.
In the case of f(x), the leading term is negative, and its expoent is odd. Therefore, when x is negative, the leading term will be positive and, when x is positive, the leading term is negative.
Therefore, we have:
[tex]\begin{gathered} As\text{ }x\rightarrow-\infty,\text{ }f(x)\rightarrow\infty \\ As\text{ }x\rightarrow\infty,\text{ }f(x)\rightarrow-\infty \end{gathered}[/tex]You have 4/5 of a pizza left over from your pool party. If you sent 4/9 of the leftover pizza home with your friends how much of the pizza do you have left in the box
If I sent 4/9 of the leftover pizza home with your friends the pizza do I have left in the box is 16/45.
What is pizza?
Pizza is an Italian food consisting of a typically flat, spherical foundation composed of leavened wheat dough that is topped with cheese, tomatoes, and frequently a number of additional toppings. Following that, the pizza is baked at a high temperature, typically in a wood-fired oven. A small pizza is also known as a pizzetta. A pizza maker is referred to as a pizzaiolo.
To get the quantity of the leftover pizza, we need to subtract the pizza sent by me to home from the total pizza I had in my lunch box.
So,
Pizza I have left = Pizza in lunch box - Pizza I have sent
Pizza I have left = 4/5 - 4/9
Pizza I have left = (4(9) - 4(5))/45
Therefore, Pizza I have left is 16/45.
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A middle school football game has four 12-minute quarters. Jason plays 8 minutes in each quarter.Which ratio represents Jason's playing time compared to the total number of minutes of playing time possible?1 to 3 2 to 33 to 24 to 1I’m
The total minutes in the game is 48. The total playing game for Jason is 32. The ratio is
[tex]\frac{32}{48}[/tex]Simplifying it, we have
[tex]\frac{32}{48}=\frac{16}{24}=\frac{8}{12}=\frac{4}{6}=\frac{2}{3}[/tex]So, the playing ratio is 2 to 3 for Jason.
Please help me with this word problem quickly, work is needed thank you!
Given:
Sheila can wash her car in 15 minutes. Bob takes time twice as long to wash the same car.
Required:
Find the time they take both together.
Explanation:
Sheila can wash her car in 15 minutes.
Work done by sheila in a minute =
[tex]\frac{1}{15}\text{ }[/tex]Bob takes time twice as long to wash the same car. He washes the car in 30 minutes.
Work done by Bob in a minute
[tex]=\frac{1}{30}[/tex]If they work together let them take time x per minute.
[tex]\frac{1}{15}+\frac{1}{30}=\frac{1}{x}[/tex]Solve by taking L.C. M.
[tex]\begin{gathered} \frac{2+1}{30}=\frac{1}{x} \\ \frac{3}{30}=\frac{1}{x} \\ \frac{1}{10}=\frac{1}{x} \\ x=10\text{ minutes.} \end{gathered}[/tex]If they work together they will take 10 minutes.
Final Answer:
Sheila and Bob wash the car together in 10 minutes.
A 6000-seat theater has tickets for sale at $24 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue
of $168,000?
The number of tickets for sale at $24 should be ?
The number of tickets which should be sold to $24 and $40 are 4500 and 1500 respectively.
Given, A 6000-seat theater has tickets for sale at $24 and $40.
How many tickets should be sold at each price for a sellout performance to generate a total revenue of $168,000 = ?
first, assign variables:
X = # of $24 tickets, Y = # or $40 tickets
write equations based on the data presented:
"6000 seat theater..."
X + Y = 6000 ...equation 1
"total revenue of 168,000"
The revenue from each type of ticket is the cost times the number sold, so:
24X + 40Y = 168,000 .....equation 2
from equation 1:
X = 6000 - Y
substitute this into equation 2: (replace X with 6000-Y)
24 (6000 - Y) + 40Y = 168,000
expand:
144,000 -24Y + 40Y = 168,000
rearrange and simplify:
16Y = 168,000 - 144,000
y = 24000/16
Y = 1500
from equation 1:
X = 6000 - 1500
X = 4500
hence the number of tickets for sale at $24 should be 4500.
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Abby scored 88, 91, 95, and 89 on her first four history quizzes. What score does Abby need to get on her fifth quiz to have an average of exactly 90 on her history quizzes? a.85b.86c.87a.88
Solution
For this case we can use the definition of average given by:
[tex]\text{Mean}=\frac{x_1+x_2+x_3+x_4+x_5}{5}[/tex]The final score needs to be 90 so we can do this:
[tex]90=\frac{88+91+95+89+x_5}{5}[/tex]And solving for x5 we got:
5*90 = 88+91+95+89+ x5
x5= 450 - 88- 91- 95 -89 = 87
Final answer:
c.87
Create an equation that models the table below. Use the variables in the table for your equation. Write your equation with 'S' isolated.
The table show piszzas (P) on the left column and the slices of Pepperonin (S) on the right column.
To determine the equation models first check the ratio S/P to determine whether they are proportinal or not.
[tex]\begin{gathered} \frac{36}{3}=12 \\ \frac{96}{8}=12 \\ \frac{228}{19}=12 \end{gathered}[/tex]Now as the ratios are constant it mean the variation is linear and the relationship is proportional.
Thus the model equation can be determine as,
[tex]\begin{gathered} \frac{S}{P}=12 \\ S=12P \end{gathered}[/tex]Thus, the above equation gives the required model equation.
I absolutely dont understand Division Property of Equality please help
We have the following equation.
[tex]20,000-1.8939m=10,000[/tex]Where m is the number of feet in a mile.
Let us subtract 20,000 from both sides of the equation then simplify
[tex]\begin{gathered} -20,000+20,000-1.8939m=10,000-20,000 \\ -1.8939m=-10,000 \end{gathered}[/tex]The negative sign cancels out and the equation becomes
[tex]\text{1}.8939m=10,000[/tex]Finally, we can apply the Division Property of Equality which states that when we divide both sides of the equation with same number then the equation remains valid.
Let us divide both sides of the equation by 1.8939 then simplify
[tex]\begin{gathered} \frac{1.8939m}{1.8939}=\frac{10,000}{1.8939} \\ m=\frac{10,000}{1.8939} \\ m\approx5280 \end{gathered}[/tex]Therefore, there are 5280 feet in a mile (rounded to nearest whole number)
Hello everybody! I would really appreciate it if Somebody could give me the answer for this question and give a brief explanation on how they got it. Look at the photo for instructions!
Recall that the constant of variation of a straight line is the slope of the line.
To compute the slope we will use the following formula for the slope of a line:
[tex]s=\frac{y_2-y_1}{x_2-x_1}\text{.}[/tex]Now, notice that points (-1,3) and (1,-3) are on the line, then substituting these points in the above formula we get:
[tex]s=\frac{3-(-3)}{-1-1}=\frac{6}{-2}=-3.[/tex]Answer: -3.
Choose which function is represented by the graph.111032-11-10 9 8 7 6 5 4-3-2-102 3 4 5 6 7 8 9 10 1110O A. 1(x) = (x − 1)(x +2)(x+4)(x+8)B. f(x) - (x-8)(x-4)(x-2)(x+1)C. f(x)=(x-1)(x+2)(x+4)D. f(x)=(x-4)(x-2)(x+1)876544 4 4 & & To-2X
The factors of a polynomial tell us the points where the graph intersects the x-axis.
From the graph provided in the question, the graph cuts the x-axis at the points:
[tex]x=-4,x=-2,x=1[/tex]Therefore, the factors will be:
[tex]\begin{gathered} x=-4,x+4=0 \\ x=-2,x+2=0 \\ x=1,x-1=0 \\ \therefore \\ factors\Rightarrow(x+4),(x+2),(x-1) \end{gathered}[/tex]Therefore, the polynomial will be:
[tex]f(x)=(x+4)(x+2)(x-1)[/tex]OPTION C is the correct option.
In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Find BC.
Answer:
29 units
Step-by-step explanation:
BC is a side of ACB, which is a 45 45 90 triangle. BC = AB/sqrt2
If In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Then BC is 29 units
What is Trigonometry?Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
Given,
In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units.
We need to find BC
In triangle ACD,
tan 45° = CD/AD
CD = tan 45° x AD
= 1 x 20= 20 units
In triangle CDB,
tanФ = CD/BD
Ф = tan⁻¹(CD/BD)
= tan⁻¹(20/21)
= 43.6°
so, sin 43.6° = CD/BC
BC = CD/sin 43.6°
= 20/0.689
= 29 units
Hence the length of BC will be 29 units.
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I need answer for this word problems you have to shown that you can make several lattes then you add milk and begin to stirring. you use a total of 30 ounces of liquid. write an equation that represents the situation and explain what the variable represents.
hello
the question here is a word problem and we can either use alphabhets to represent the variables.
let lattes be represented by x and milk be represented by y
[tex]x+y=30[/tex]since the total ounce of liquid is equals to 30, we equate the whole sentence to 30.
Sketch the graph of a function that has a local maximum value at x = a where f'(a) is undefined.
Derivative and Maximum Value of a Function
The critical points of a function are those where the first derivative is zero or does not exist.
Out of those points, we may find local maxima or minima or none of them.
One example of a function with a derivative that does not exist is:
[tex]y=-x^{\frac{2}{3}}[/tex]This function has a local maximum at x=0 where the derivative does not exist.
The graph of this function is shown below:
when his bus arrives Calvin is 40 ft east of the corner the door of the bus is 30 feet north of the corner how far will Calvin run directly across the field to the bus
Since this situation can be represented by a right triangle, we can use the pythagorean theorem. Doing so, we have:
[tex]\begin{gathered} a^2+b^2=c^2\text{ } \\ (30)^2+(40)^2=c^2\text{ (Replacing)} \\ 900+1600=c^2\text{ (Raising both numbers to the power of 2)} \\ 2500=c^2\text{ (Adding)} \\ \sqrt[]{2500}=\sqrt[]{c^2} \\ 50=c\text{ (Taking the square root of both sides)} \\ \text{The answer is 50 ft} \end{gathered}[/tex]Angles A and B are adjacent on a straight line. Angle A has a measure of (2r +20) and angle B has a measure of 130.. What is the measure of r?
When two angles are adjacent on a straight line, then the sum of the two angles equals 180 (that is sum of angles on a straight line). Therefore;
[tex]\begin{gathered} (2r+20)+130=180 \\ \text{Subtract 130 from both sides and you'll have} \\ 2r+20=50 \\ \text{Subtract 20 from both sides and you'll have} \\ 2r=30 \\ \text{Divide both sides by 2 and you'll have} \\ r=15 \end{gathered}[/tex]The measure of r is 15
Not sure on how to do this. Could really use some help.
We will have the following:
We will recall that the surface area of a sphere is given by:
[tex]A_s=4\pi r^2[/tex]So, the surface area of the given sphere will be:
[tex]\begin{gathered} A_s=4\pi(\sqrt{\frac{7}{3.14}})^2\Rightarrow A_s=4(3.14)\ast\frac{7}{3.14} \\ \\ \Rightarrow A_s=4\ast7\Rightarrow A=28 \end{gathered}[/tex]So, the surface area of the sphere will be 28 yd^2.
*The reason we can use "mental math" is that we are using an approximation of pi, which makes it so it cancels with the 3.14 in the denominator after a point; leaving a simple multiplication at the very end.
Solve the exponential equation. Express irrational solutions as decimals correct to the nearest thousandth.5x -5.e-2x = 2eSelect the correct choice below and, if necessary, fill in the answer box to complete your choice.A. The solution set is(Round to the nearest thousandth as needed. Use a comma to separate answers as needed.)OB. The solution is the empty set.
We are asked to solve the exponential equation given below:
e^5x - 5 * e^-2x = 2e
First let's apply the exponent rules:
5x - 5 - 2x = In(2e)
Solving 5x - 5 - 2x = In(2e)
3x - 5 = In(2e)
Add 5 to both sides:
3x = In(2e) + 5
Divide both sides by 3
x = In(2e) + 5
3
x = 2.23104
x = 2.231 (To the nearest thousand)
Therefore, the correct option is A, which is The solution set is 2.231 (Round to the nearest thousand).
Referring to the figure, find the unknown measure of ABC.
According to the Inscribed Angle Theorem, the measure of an angle inscribed in a circle equals half the arc that it intercepts.
Then:
[tex]m\angle ABC=\frac{1}{2}m\overset{\frown}{AC}[/tex]Since the measure of the arc AC is equal to 84º, then:
[tex]m\angle ABC=\frac{1}{2}(84º)=42º[/tex]Therefore, the answer is:
The measure of ABC is 42º.
The height of the Empire State Building is 1250 feet tall. Your friend, who is 75 inches tall, is standing nearby and casts a shadow that is 33 inches long. What is the length of the shadow of the Empire State Building? Please help me draw triangles
The length of the building's shadow = 550.66 ft
Explanations:The height of the Empie State Building = 1250 feet
The friend's height = 75 inches
The length of the friend's shadow = 33 inches
[tex]\frac{Actual\text{ height of the friend}}{\text{Length of the friend's shadow}}=\text{ }\frac{Height\text{ of the building}}{\text{Length of the building's shadow}}[/tex][tex]\begin{gathered} \frac{75}{33}=\text{ }\frac{1250}{\text{Length of the building's shadow}} \\ 2.27\text{ = }\frac{1250}{\text{Length of the building's shadow}} \\ \text{Length of the building's shadow = }\frac{1250}{2.27} \\ \text{Length of the building's shadow = }550.66\text{ f}et \end{gathered}[/tex]What is 16.02+8.5+14 ?? i want to know for a home work
Given:
[tex]16.02\text{ + 8.5 + 14}[/tex]To solve,
Step 1:
Express each value to a common decimal place.
We can express each value to two decimal places.
Thus, we have
[tex]16.02+8.50+14.00[/tex]Step 2:
Sum up the values.
Hence, 16.02 + 8.5 + 14 gives 38.52.
Can you please help with 44For the following exercise, sketch a graph of the hyperbola, labeling vertices and foci
We have the following equation of a hyperbola:
[tex]4x^2+16x-4y^2+16y+16=0[/tex]Let's divide all the equations by 4, just to simplify it
[tex]x^2+4x-y^2+4y+4=0[/tex]Just to make it easier, let's put the term if "x" isolated
[tex]x^2+4x=y^2-4y-4[/tex]Now we can complete squares on both sides, just remember that
[tex]\begin{gathered} (a+b)^2=a^2+2ab+b^2 \\ \\ (a-b)^2=a^2-2ab+b^2 \end{gathered}[/tex]Now let's complete it!
[tex]\begin{gathered} x^2+4x=y^2-4y-4\text{ complete adding 4 on both sides} \\ \\ x^2+4x+4=y^2-4y-4+4 \\ \\ (x+2)^2=y^2-4y \\ \end{gathered}[/tex]We already completed one side, now let's complete the side with y^2, see that we will add 4 again, then
[tex]\begin{gathered} (x+2)^2=y^2-4y \\ \\ (x+2)^2+4=y^2-4y+4 \\ \\ (x+2)^2+4=(y-2)^2 \end{gathered}[/tex]And now we can write it using the standard equation!
[tex]\begin{gathered} (y-2)^2-(x+2)^2=4 \\ \\ (y-2)^2-(x+2)^2=4 \\ \\ \frac{(y-2)^2}{4}-\frac{(x+2)^2}{4}=1 \end{gathered}[/tex]And now we can graph it like all other hyperbolas, the vertices will be:
[tex](-2,4)\text{ and }(-2,0)[/tex]And the foci
[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ c^2=2^2+2^2 \\ \\ c^2=2\cdot2^2 \\ \\ c^{}=2\, \sqrt[]{2} \end{gathered}[/tex]Then the foci are
[tex](-2,2+2\, \sqrt[]{2})\text{ and }(-2,2-2\, \sqrt[]{2})[/tex]Now we can plot the hyperbola!
on a horizontal line segment, point A is located at 21, point b is located at 66. point p is a point that divides segment ab in a ratio of 3:2 from a to b where is point p located
We have a one-dimensional horizontal line segment. Three points are indicated on the line as follows:
In the above sketch we have first denoted a reference point at the extreme left hand as ( Ref = 0 ). This is classified as the origin. The point ( A ) is located on the same line and is at a distance of ( 21 units ) from Reference ( Ref ). The point ( B ) is located on the same line and is at a distance of ( 66 units ) from Reference ( Ref ).
The point is located on the line segment ( AB ) in such a way that it given as ratio of length of line segment ( AB ). The ratio of point ( P ) from point ( A ) and from ( P ) to ( B ) is given as:
[tex]\textcolor{#FF7968}{\frac{AP}{PB}}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{\frac{3}{2}\ldots}\text{\textcolor{#FF7968}{ Eq1}}[/tex]The length of line segment ( AB ) can be calculated as follows:
[tex]\begin{gathered} AB\text{ = OB - OA } \\ AB\text{ = ( 66 ) - ( 21 ) } \\ \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = 45 units}} \end{gathered}[/tex]We can form a relation for the line segment ( AB ) in terms of segments related to point ( P ) as follows:
[tex]\begin{gathered} \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = AP + PB }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq2}} \\ \end{gathered}[/tex]We were given a ratio of line segments as ( Eq1 ) and we developed an equation relating the entire line segment ( AB ) in terms two smaller line segments as ( Eq2 ).
We have two equation that we can solve simultaneously:
[tex]\begin{gathered} \textcolor{#FF7968}{\frac{AP}{PB}}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{\frac{3}{2\text{ }}\ldots}\text{\textcolor{#FF7968}{ Eq1}} \\ \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = AP + PB }}\textcolor{#FF7968}{\ldots Eq2} \end{gathered}[/tex]Step 1: Use Eq1 and express AP in terms of PB.
[tex]AP\text{ = }\frac{3}{2}\cdot PB[/tex]Step 2: Substitute ( AP ) in terms of ( PB ) into Eq2
[tex]AB\text{ = }\frac{3}{2}\cdot PB\text{ + PB}[/tex]We already determined the length of the line segment ( AB ). Substitute the value in the above expression and solve for ( PB ).
Step 3: Solve for PB
[tex]\begin{gathered} 45\text{ = }\frac{5}{2}\cdot PB \\ \textcolor{#FF7968}{PB}\text{\textcolor{#FF7968}{ = 18 units}} \end{gathered}[/tex]Step 4: Solve for AP
[tex]\begin{gathered} AP\text{ = }\frac{3}{2}\cdot\text{ ( 18 )} \\ \textcolor{#FF7968}{AP}\text{\textcolor{#FF7968}{ = 27 units}} \end{gathered}[/tex]Step 5: Locate the point ( P )
All the points on the line segment are located with respect to the Reference of origin ( Ref = 0 ). We will also express the position of point ( P ).
Taking a look at point ( P ) in the diagram given initially we can augment two line segments ( OA and AP ) as follows:
[tex]\begin{gathered} OP\text{ = OA + AP} \\ OP\text{ = 21 + 27} \\ \textcolor{#FF7968}{OP}\text{\textcolor{#FF7968}{ = 48 units}} \end{gathered}[/tex]The point ( P ) is located at.
Answer:
[tex]\textcolor{#FF7968}{48}\text{\textcolor{#FF7968}{ }}[/tex]
Find the measures in the parallelogram4. Find AB and AC
Okay, here we have this:
Considering that in a parallelogram the opposite sides are congruent, we obtain the following:
AB=CD
AB=9 units
AC=BD
AC=4 units
I need help with question 4-8, can you please help me?Use f(X) as g(X) for question 5 and 6
Question 4
The x values for which g(x) = 3
From the graph, we have this value to be:
[tex]0\text{ }\leq\text{ x }\leq\text{ 2}[/tex]Question 5
f(x) = 6, What is x?
From the graph, we can determine the value of x corresponding to f(x)= 6:
[tex]x\text{ = }4[/tex]Question 6:
f(x)= 0, What is x?
From the graph, we can determine the value of x corresponding to f(x) = 0
[tex]x\text{ = 7}[/tex]Question 7
The domain of the function:
The domain is the set of allowable inputs.
[tex]\lbrack0,\text{ 12\rbrack}[/tex]Question 8
The range is the set outputs
[tex]\lbrack0,\text{ 6\rbrack}[/tex]