what is the x intercepts or zeros for y = x^2 - 6x + 5

Answers

Answer 1

Solution:

Given;

[tex]y=x^2-6x+5[/tex]

The x-intercepts are the points where y=0.

Thus;

[tex]x^2-6x+5=0[/tex]

Thus;

[tex]\begin{gathered} x^2-x-5x+5=0 \\ \\ x(x-1)-5(x-1)=0 \\ \\ x-1=0,x-5=0 \\ \\ x=1,x=5 \end{gathered}[/tex]

ANSWER:

[tex]x=1,x=5[/tex]


Related Questions

given which of the following describes the boundary line and shading for the second inequality in the system

Answers

Answer:

Solid Line, Shade Above

Explanation:

Given:

[tex]\left\{\begin{array}{l} y<-2 x+3 \\ y \geq x-4 \end{array}\right.[/tex]

The second inequality in the system is:

[tex]y\geq x-4[/tex]

The intercepts of the boundary line (y=x-4) are (0, -4) and (4,0).

Since the inequality has an equal to sign attached, we use a solid line.

At (0,0)

[tex]\begin{gathered} y\geq x-4 \\ 0\geq-4 \end{gathered}[/tex]

Since the inequality 0≥-4 is true, shade the side that contains (0, 0) as shown in the graph below:

So, we use a solid line and shade above the boundary line.

Determine the value of k for which f(x) is continuous.

Answers

These are the conditions of the continuity in a function:

First, the value of x must have an image.

Second, the lateral limits must be equal:

[tex]\lim_{x\to a^+}f(x)=\lim_{x\to a^-}f(x)[/tex]

Finally, the value of the limit must be equal to the image of x. This means that:

[tex]f(a)=\lim_{x\to a^}f(x)[/tex]

In this case, we must find a value of k that can make the two lateral limits equal in x =3:

[tex]\lim_{x\to3^+}x^2+k=\lim_{x\to3^-}kx+5[/tex]

We can solve these two limits easily by replacing the x with the value of 3

[tex]3^2+k=3k+5[/tex][tex]\begin{gathered} 9+k=3k+5 \\ 4=2k \\ k=2 \end{gathered}[/tex]

Finally, we can see that the answer is k=2.

Kimberly has an empty cardboard box that weighs 0.5 pounds. She puts 10 loaves of bread and a 4-pound jar of peanut butter in the box. The total weight of the box and its contents is 19.5 pounds. One way to represent this situation is with the equation 0.5 - 106 + 4 = 19.5 In this situation, what does the solution to the equation represent? In other words, if you solved for b. what would the value of b tell you? You do not have to find the solution to answer the question

Answers

The equation is represented by:

0.5 + 10b + 4 = 19.5

In which 19.5 is the total weight of the box and it's contents.

0.5 is the weight of the cardboard box.

4 is the weight of the jar of peanut butter.

10b is the weight of all loaves of bread.

And b is the weight of a single loaf of bread

The answer is:

The solution of the equation, which is the value of b, represents the weight of a single loaf of bread.

Solve the right triangle. Write your answers in simplified, rationalized form. DO NOT ROUND!

Answers

base = FG = root 30

perpendicular HG = x

angle = 45 degrees,

we know that

[tex]\text{tan}\theta=\frac{perpendicualr}{base}[/tex][tex]\tan 45=\frac{HG}{\sqrt[]{3}}[/tex][tex]\begin{gathered} 1=\frac{HG}{\sqrt[]{3}} \\ HG=\sqrt[]{3} \end{gathered}[/tex]

so, the value of HG = root 3

Each parking spot is 8 feet wide. A parking lot has 24 parking spots side by side. What is the width (measured in yards) of the parking lot? The shorter tree is

Answers

The width would be: 8ft*24 = 192 ft

Then, we have to convert the unit from ft to yards. Doing so,we have:

[tex]192ft\cdot\frac{1\text{ yard}}{3\text{ ft}}=64\text{ yards (Multiplying and dividing)}[/tex]

The answer is 64 yards

I need help with this and it is delivered at 3:30 pm and sadly I did not understand almost anything and I am confused.Problem 1

Answers

Reflection across the y-axis transforms the point (x,y) into (-x, y)

Applying this rule to points A, B, and C, we get:

A(-5, 6) → A'(5, 6)

B(3, 6) → B'(-3, 6)

C(-3, 2) → C'(3, 2)

Given that figure ABC was reflected, then figure A'B'C' is congruent with figure ABC

HELP ASAP
What is the size of the smallest angle in Triangle A? Give your answer correct to one
decimal place. Show your calculations.

Answers

Answer:

A is an included angle between 3 and 5

Which is the image of vertex K after the parallelogram is rotated 180degrees about the origin?

Answers

Answer:

The image of vertex K is (3,-2)

Step-by-step explanation:

Rotated 180 degrees about the origin means that the value of x will not change, while y will have the same distance from the origin, but in a different direction.

Vertex K:

Value of x: x = 3

Value of y: y = 2

Distance from the origin: 2 - 0 = 2

Rotated, new coordinate: 0 - 2 = -2

The image of vertex K is (3,-2)

Find the area of a triangle with vertices at N(-4,2), A(3,2)and P(-1,-4).

Answers

The distance between points N and A is 7, and we can take that as the base of the tringle (up side down)

The distance between the base (NA) and the point P is 6, and we can take that as the height of the triangle

Area of a triangle = (Base x Height)/2

Area = (7 x 6)/2 = 42/2 = 21

Answer:

Area = 21

The bases of the prism below are rectangles. If the prism's height measures 3 units and its volume is 198 units^3. solve for x

Answers

The volume of a rectangular prism is given by

V=L*W*H

where

V=198 units3

L=6 units

W=x units

H=3 units

substitute given values

198=(6)*(x)*(3)

solve for x

198=18x

x=198/18

x=11 units

What is the slope: (-2, 1) (5,-2)

Answers

Answer:  slope = -3/7

Step-by-step explanation:

m(slope) = (y2-y1)/(x2-x1)

m = (-2+-1)/(5--2)

m = (-2-1)/5+2)

m = -3/7

Bob buys a vase for $15 and spends $2 per flower.
4) Write an equation to represent the cost of buying flowers.

Answers

If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x

The cost of flower vase = $15

The cost of each flower = $2

Consider the number of flowers as x

Then the linear equation that represents the cost of buying flowers = The cost of flower vase + The cost of each flower × x

Substitute the values in the equation

The equation that represents the cost of buying flowers = 15+2x

Hence, If Bob buys a vase for $15 and spends $2 per flower, then the equation to represent the cost of buying flowers is 15+2x

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What is the slope of the line in the graph?A. 2/3B. -2/3C. 3/2D. -3/2

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

graph

Step 02:

slope of the line:

we must analyze the graph to find the solution.

point 01 (0, 8)

point 02 (12, 0)

slope:

[tex]m=\frac{y2-y1}{x2-x1}=\frac{0-8}{12-0}=\frac{-8}{12}=\frac{-2}{3}[/tex]

The answer is:

m = - 2/3

Mr. Edmonds is packing school lunches for a field trip for the 6th graders of Apollo Middle school. He has 50 apples and 40 bananas chips. Each group of students will be given one bag containing all of their lunches for the day. Mr. Edmonds wants to put the same number of apples and the same number of bananas in each bag of lunches. What is the greatest number of bags of lunches Mr.Edmonds can make? How many apples and bananas will be in each bag?

Answers

40 total lunches. 1 apple and 1 banana in each bag.

The Sugar Sweet Company will choose from two companies to transport its sugar to market. The first company charges to rent trucks plus an additional fee of for each ton of sugar. The second company charges to rent trucks plus an additional fee of for each ton of sugar.For what amount of sugar do the two companies charge the same? What is the cost when the two companies charge the same?

Answers

step 1

Find the equation of the line First Company

y=100.25x+6,500

where

y is the total charge

x is the number of ton of sugar

Second Company

y=225.75x+4,492

Part a)

Equate both equations

100.25x+6.500=225.75x+4,492

solve for x

225.75x-100.25x=6,500-4,492

125.50x=2,008

x=16

answer part a is 16 ton

Part b) For x=16 ton

substitute the value of x in any of the two equations (the result is the same)

y=100.25(16)+6,500

y=$8,104

answer Part b is $8,104

Witch phrase best describes the position of the opposite of +4

Answers

To find the position that is opposite to +4, we need to consider 0 as a "mirror point", then we check which point has the same distance to 0 as the distance from +4 to 0:

The position which is opposite to +4 is the position -4.

This position is 4 units to the left of 0 and 8 units to the left of +4.

Looking at the options, the correct option is the second one.

Rewrite the expression in lowest terms.

4x²-12x +9
________
4x2-9

A. -12 x

B. 4x-3
2x-3

C. 2x+3
2x-3

D. 2x-3
2x+3

Answers

answer is D

no real explanation its just math

What is the y intercept of this equation10x+5y=30Write answer in (x,y)

Answers

The y intercept of a straight line is the point on the y axis where the line cuts the y axis.

Given equation of lineis

[tex]10x+5y=30[/tex]

Putting x=0 in the above equation, we have,

[tex]\begin{gathered} 5y=30 \\ y=6 \end{gathered}[/tex]

So, the y intercept is

[tex](0,6)[/tex]

A line's slope is -5. The line passes through the point (5, 30). Find an equation for this line in both point-slope and slope-intercept form A) An equation for this line in point-slope form is:B) An equation for this line in slope-intercept form is.

Answers

Answer:

y - 30 = 5(x - 5) (point slope form)

slope intercept form is y = 5x+5

Explanation:

Given the following

Slope m = -5

Point = (5, 30)

x0 = 5 and y= = 30

The equation of the line in point slope form is expressed as y-y0 = m(x-x0)

Substitute

y - 30 = -5(x - 5) (point slope form)

Express in slope intercept form (y = mx+c)

y - 30 = -5x + 25

y = -5x + 25 + 30

y = -5x + 55

Hence the equation of the line in slope intercept form is y = -5x+55

(x+?)(x+3)=x squared+5x+6

Answers

The given expression is :

(x + ) (x + 3) = x² + 5x + 6

The polynomial is factorize and then written in the form of (x + ) (x + 3)

Let the missing number is "b" substitute in the equation and simplify :

(x + b ) (x + 3) = x² + 5x + 6

x² +bx + 3x + 3b = x² + 5x + 6

x² +x(b +3) + 3b = x² + 5x + 6

Comparing the constant term together :

3b = 6

Divide both side by 3

3b/3 = 6/3

b = 2

Since b is the missing term so, Missing term is 2

(x + 2 ) (x + 3) = x² + 5x + 6

Answer :(x + 2 ) (x + 3) = x² + 5x + 6

The graph shows the proportional relationship between the number of gems collected and the number of levels that have been completed in a video game.

Graph with x axis labeled game levels and y axis labeled gems collected. A line begins at 0 comma 0 and goes through points 6 comma 420 and 8 comma 560.

Determine the constant of proportionality for the relationship.
p = 70
p = 140
p equals 2 over 140
p = 0.0143

Answers

Answer: P = 70

Step-by-step explanation:

p = 70 because on the graph everytime the y number is the  x number multiplied by 70.

70 x 2 = 140
70 x 4 = 280
70 x 6 = 420
70 x 8 = 560
70 x 10 = 700.
Heres the chart for proof

The constant of proportionality (p) for this proportional relationship is equal to: A. p = 70.

How to determine the constant of proportionality?

In Mathematics, the graph of any proportional relationship is characterized by a straight line because as the values on the x-axis increases or decreases, the values on the y-axis increases or decreases simultaneously.

Mathematically, a proportional relationship can be represented by the following equation:

y = px

Where:

p is the constant of proportionality.y represents the gems collected.x represents the game levels.

Next, we would determine the constant of proportionality (p) for the data points on this graph as follows:

p = y/x

p = 420/6 = 560/8

p = 70.

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Simplify by writing the expression with positive exponents. Assume that all variables represent nonzero real numbers

Answers

[tex]\lbrack\frac{144q^2}{m^6p^4}\rbrack^{}[/tex]

Explanation

Let's remember some properties ofthe fractions ans exponents,

[tex]\begin{gathered} a^{-n}=\frac{1}{a^n} \\ (\frac{a}{b})^n=\frac{a^n}{b^n} \\ (ab)^n=a^nb^n \\ (a^n)^m=a^{m\cdot n} \end{gathered}[/tex]

so

Step 1

[tex]\lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2[/tex]

reduce by using the properties

[tex]\begin{gathered} \lbrack\frac{4p^{-2}q}{3^{-1}m^3}\rbrack^2 \\ \lbrack\frac{4q}{3^{-1}m^3p^2}\rbrack^2 \\ \lbrack\frac{3^1\cdot4q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{12q}{m^3p^2}\rbrack^2 \\ \lbrack\frac{144q^2}{m^{3\cdot2}p^{2\cdot2}}\rbrack^{} \\ \lbrack\frac{144q^2}{m^6p^4}\rbrack^{} \end{gathered}[/tex]

therefore, the answer is

[tex]\lbrack\frac{144q^2}{m^6p^4}\rbrack^{}[/tex]

I hope this helps you

1. The population of Whatville is given by the y=83,000(1.04) where x is the years since 2010.a) What was the population in 2010?b) What is the population in 2020?c) When will the population reach 100,000? Show your work.

Answers

ANSWER:

a) 83,000 people

b) 122,860 people

c) 4.75 years

STEP-BY-STEP EXPLANATION:

We have that the population given by the following equation:

[tex]y=83000\cdot\mleft(1.04\mright)^x[/tex]

a) What was the population in 2010?

Since no year has passed, the value of x would be 0.

Replacing:

[tex]\begin{gathered} y=83000\cdot(1.04)^0 \\ y=83000 \end{gathered}[/tex]

The population in 2010 is 83,000 people

b) What is the population in 2020?

From 2010 to 2020 10 years have passed, therefore the value of x is 10

[tex]\begin{gathered} y=83000\cdot(1.04)^{10} \\ y=122860 \end{gathered}[/tex]

The population in 2020 is 122,860 people

c) When will the population reach 100,000?

Since the population is 100,000 people, it is the value of y, therefore we must solve and calculate the value of x

[tex]\begin{gathered} 100000=83000\cdot\mleft(1.04\mright)^x \\ 1.04^x=\frac{100000}{83000} \\ \ln 1.04^x=\ln \frac{100}{83} \\ x\cdot\ln 1.04=\ln \frac{100}{83} \\ x=\frac{\ln \frac{100}{83}}{\ln 1.04} \\ x=4.75 \end{gathered}[/tex]

Which means that for the population to be 100,000 people, 4.75 years would have to pass

If mZABD = 70°, what are mZABC and mZDBC?
mZABC=
mZDBC=
(6x+3) D
B
(9x-8)
Please help me

Answers

Answer:

Step-by-step explanation:

ABD = ABC + DBC

Eqivalent to:

78 = (5x + 3) + (5x - 5)

78 = 5x + 5x + 3 - 5

78 = 10x - 2

80 = 10x (move -2 to the left side and get 78 + 2 = 80)

8 = x (80/10 = 8)

With x = 8,

ABC = 5x - 5 = 8*5 - 5 = 40 - 5 = 35

DBC = 5x +3 = 8*5 + 3 = 40 + 3 = 43

The rat population in major metropolitan city is given by the formula n(t)=40e^0.015t where t is measured in years since 1991 and n(t) is measured in millions. What does the model predict the rat population was in the year 2008?

Answers

To use the model we need to find the value of t. To do this we substract the year we want to know from the year the model began, then:

[tex]t=2008-1991=17[/tex]

Now that we have t we plug it in the function:

[tex]n(17)=40e^{0.015\cdot17}=51.618[/tex]

Therefore the model predict that there were 51.618 millions of rats in 2008.

Write an equation or inequality and solve:32 is at most the quotient of a number g and 8

Answers

The quotient of a number g and 8 can be written as:

[tex]\frac{g}{8}[/tex]

Since it is given that 32 is at most( this quotient, then it follows that:

[tex]32\le\frac{g}{8}[/tex]

Next, solve the resulting inequality:

[tex]\begin{gathered} 32\le\frac{g}{8} \\ \text{Swap the sides of the inequality and change the sign:} \\ \frac{g}{8}\ge32 \end{gathered}[/tex]

Multiply both sides of the inequality by 8. Note that the sign will not change since you are multiplying a positive number:

[tex]\begin{gathered} \Rightarrow8\times\frac{g}{8}\ge8\times32 \\ \Rightarrow g\ge256 \end{gathered}[/tex]

Hence, the inequality is:

[tex]32\le\frac{g}{8}[/tex]

The solution is:

[tex]g\ge256[/tex]

Use (60° - 45°) = 15° to find the exact value of cos 15º.vaV2 + V6V-V6(b)(c)4(d)4+ V62

Answers

Answer;

[tex]B\text{. }\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]

Explanation;

Given that;

[tex](60^0-45^0)=15^0[/tex]

Hence;

[tex]\text{Cos 15}^0=Cos(60^0-45^0)[/tex]

According to trigonometry identity;

[tex]\begin{gathered} Cos(60^0-45^0\text{) = Cos60 Cos45 + Sin60Sin45} \\ Cos(60^0-45^0\text{) }=\frac{1}{2}(\frac{1}{\sqrt[]{2}})+\frac{\sqrt[]{3}}{2}(\frac{1}{\sqrt[]{2}}) \end{gathered}[/tex]

Evaluate the result by finding the LCM

[tex]Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}[/tex]

Rationalize;

[tex]\begin{gathered} Cos(60^0-45^0\text{) }=\frac{1+\sqrt[]{3}}{2\sqrt[]{2}}\times\frac{\sqrt[]{2}}{\sqrt[]{2}} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}(1+\sqrt[]{3})}{2\cdot2} \\ Cos(60^0-45^0\text{) }=\frac{\sqrt[]{2}+\sqrt[]{6}}{4} \end{gathered}[/tex]

Hence the required reusult is;

[tex]\frac{\sqrt[]{2}+\sqrt[]{6}}{4}[/tex]

The table represents the amount of money in a bank account each month. Month Balance ($) 1 2,215.25 2 2,089.75 3 1,964.25 4 1,838.75 5 1,713.25 What type of function represents the bank account as a function of time? Justify your answer.

Answers

The type of function that represents the bank account as a function of time is a linear function

How to determine the type of function?

The table of values is given as

Month Balance ($)

1           2,215.25

2          2,089.75

3           1,964.25

4            1,838.75

5            1,713.25

From the above table of values, we can see that;

The balance in the bank account reduces each month by $125.5

This difference is calculated by subtracting the current balance from the previous balance

So, we have

Difference = 1,838.75 - 1713.25 =125.5

Difference = 1,964.25 - 1,838.75 =125.5

Difference = 2,089.75 - 1,964.25 =125.5

Difference = 2,215.25  - 2,089.75 =125.5

Functions that have a common difference are linear functions

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Answer:

It's not D I can tell you that but ig just go with the other guy's answer

Step-by-step explanation:

Harriet found the number of At-Bats (AB) using the formula below

Answers

[tex]D;\text{ }0.520\text{ = }\frac{(28)\text{ + (94) +(3) + 240}}{AB}[/tex]

Here, we want to get what should have been written as step 1

As we can see from what is presented, she went directly to step 2 without writing out the individual product and summing them

So, we have the step 1 correctly written as;

[tex]0.520\text{ = }\frac{(28)\text{ + (94) +(3) + 240}}{AB}[/tex]

answer yes or no and explain why or why not.if a/5 = 8 + 9, does a/5 + 9 = 8 + 9?

Answers

Equations

We are given the following equation:

a/5 = 8+ 9

Adding 9 to both sides of the equation we have:

a/5 + 9 = 8 + 9 + 9

It's evident that a/5 + 9 is not equal to 8 + 9, but to 8+9+9 instead.

Answer: No

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