What must be added to each of the number and the denominator of the fraction 7/11 to make it equal to 3/4

The 95% confidence interval, we can estimate that the proportion of the entire voting population (p) that prefers Candidate A is between 0.572 and 0.668, expressed as decimals to three places

To estimate the proportion (p) of the entire voting population that prefers Candidate A, we'll use the information provided and calculate the 95% confidence interval. Here are the steps:

1. Calculate the sample proportion (p_hat): Divide the number of people who preferred Candidate A (248) by the total number of people sampled (400).
  p_hat = 248 / 400 = 0.62

2. Determine the confidence level (95%) and find the corresponding z-score. For a 95% confidence level, the z-score is 1.96.

3. Calculate the margin of error (ME) using the formula:
 [tex]ME = z-score \sqrt{\frac{(p_hat)(1-p_hat)}{n} }[/tex]
  [tex]ME = 1.96 \sqrt{\frac{0.062(1-0.62)}{400} }[/tex]
  ME = 0.048

4. Calculate the 95% confidence interval:
  Lower bound = p_hat - ME = 0.62 - 0.048 =0.572
  Upper bound = p_hat + ME = 0.62 + 0.048= 0.668

Based on the 95% confidence interval, we can estimate that the proportion of the entire voting population (p) that prefers Candidate A is between 0.572 and 0.668, expressed as decimals to three places.

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The volume enclosed by the torus rho=4sin(φ) for cylindrical or spherical coordinates is V = 32[tex]\pi^{2/3}[/tex].

We can use cylindrical coordinates to find the volume enclosed by the torus.

The torus can be defined in cylindrical coordinates as:

ρ = 4sin(φ)

where ρ is the distance from the origin to a point in the torus, and φ is the angle between the positive z-axis and the line connecting the origin to the point.

To find the volume enclosed by the torus, we integrate over ρ, φ, and z. The limits of integration for ρ and φ are 0 to 4 and 0 to 2π, respectively, since the torus extends from the origin to a maximum distance of 4 and wraps around the z-axis.

For z, we integrate from -√(16-ρ²) to √(16-ρ²), which represents the range of z values that lie on the surface of the torus at a given value of ρ and φ.

The integral for the volume of the torus is:

V = ∫∫∫ ρ dz dφ dρ

where the limits of integration are:

0 ≤ ρ ≤ 4

0 ≤ φ ≤ 2π

-√(16-ρ²) ≤ z ≤ √(16-ρ²)

Evaluating this integral gives the volume of the torus as:

V = 32[tex]\pi^{2/3}[/tex]

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We have shown that F is closed under both addition and scalar multiplication.

To show that F is closed under addition, let x = (x0, x1, x2, ...) and y = (y0, y1, y2, ...) be two sequences in F. We want to show that x+y is also in F, that is, (x+y)n+2 = (x+y)n+1 + (x+y)n for all n.

Using the definition of addition of sequences, we have (x+y)n+2 = xn+2 + yn+2 and (x+y)n+1 = xn+1 + yn+1. Substituting these into the equation to be proved, we get:

(x+y)n+2 = (x+y)n+1 + (x+y)n

xn+2 + yn+2 = xn+1 + yn+1 + xn + yn

Now, using the fact that x and y are both in F, we can simplify this equation as follows:

xn+1 + xn = xn+2

yn+1 + yn = yn+2

Substituting these into the previous equation, we get:

xn+2 + yn+2 = xn+2 + yn+2

This shows that x+y is also in F, so F is closed under addition.

To show that F is closed under scalar multiplication, let x = (x0, x1, x2, ...) be a sequence in F and let a be a scalar. We want to show that ax is also in F, that is, (ax)n+2 = (ax)n+1 + (ax)n for all n.

Expanding both sides of this equation using the definition of scalar multiplication, we get:

(ax)n+2 = axn+2

(ax)n+1 = axn+1

(ax)n = axn

Substituting these into the equation to be proved, we get:

axn+2 = axn+1 + axn

Now, using the fact that x is in F, we can simplify this equation as follows:

axn+1 + axn = axn+2

Substituting this into the previous equation, we get:

axn+2 = axn+2

This shows that ax is also in F, so F is closed under scalar multiplication.

Therefore, we have shown that F is closed under both addition and scalar multiplication.

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Answer:

Sarah receives $2.48 from the cashier

Step-by-step explanation:

Cost of the scooter = $67.52

Money paid by Sarah to the cashier = $70

Sarah receives money = money paid by Sarah - the cost of the scooter

                                      = $70 - $67.52

                                      = $2.48

Sarah receives $2.48 from the cashier.

To determine which subsets are subspaces of either r3 or p3, we need to check if they satisfy the three conditions for being a subspace:

1. Closure under addition: For any two vectors in the subset, their sum is also in the subset.
2. Closure under scalar multiplication: For any vector in the subset and any scalar, their product is also in the subset.
3. Contains the zero vector: The subset contains the vector of all zeros.

a) The set of all polynomials of degree exactly 3: This subset is a subspace of p3 because it satisfies all three conditions. The sum of two degree-3 polynomials is also a degree-3 polynomial, and a scalar multiple of a degree-3 polynomial is still a degree-3 polynomial. The zero polynomial is also a degree-3 polynomial.

b) The set of all vectors in r3 whose coordinates add up to 0: This subset is a subspace of r3 because it also satisfies all three conditions. The sum of two vectors whose coordinates add up to 0 also has coordinates that add up to 0, and a scalar multiple of such a vector also has coordinates that add up to 0. The zero vector is also in this subset.

c) The set of all polynomials in p3 whose constant term is 1: This subset is not a subspace of p3 because it does not satisfy the closure under addition condition. The sum of two polynomials with constant term 1 may not have a constant term of 1, so it is not closed under addition.

d) The set of all polynomials in p3 whose coefficient of the x^2 term is 0: This subset is a subspace of p3 because it satisfies all three conditions. The sum of two polynomials with a coefficient of 0 for x^2 also has a coefficient of 0 for x^2, and a scalar multiple of such a polynomial also has a coefficient of 0 for x^2. The zero polynomial is also in this subset.

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The area of the given rectangle is 322 square miles.

We know that the area of a rectangle is equal to the product between the dimensions. In this case we know that the dimensions of the rectangle are:

Length  = 23 miles.

Width = 14 miles.

Then the area of this rectangle will be a product between these two values, we will get:

Area = (23 mi)*(14 mi)

Area = 322 mi ²

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There are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

To seat three adults and three children at a circular table such that each child must be next to two adults, we can use the following steps:

There are 2! options for the other two adults and 3! options for children.

The number of ways for two adults and children:

= 2! × 3!

= 2 × 6

= 12 ways to seat them

There are 3 ways to pick the two children, two ways to seat them, and two ways for them to begin the circle, for a total of six options.

The third child has a pair of choices:

6 × 2 so far

Then, there are 3! =6  ways to seat the adults.

6 × 2 × 6 = 72 ways

Putting it all together, the total number of seating arrangements is:

12+72 = 84 ways  

Therefore, there are 84 different ways to seat three adults and three children at a circular table such that each child must be next to two adults.

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The 2-D shape used here is a right triangle. When rotated about the axis, this becomes a cone which is 3-D. See the attached.

In mathematics, rotation is a notion that originated in geometry. Any rotation is a movement of a specific space that retains at least one point.

A rotation differs from the following motions: translations, which have no fixed points, and (hyperplane) reflections, which each have a full (n 1)-dimensional flat of fixed points in an n-dimensional space.

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Answer:Domain is all real numbers

Step-by-step explanation:

f(x)=x^2

it is a parabola and all parabola’s domains are all real numbers

Based on the information, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

lim x→0+ csc(x) = ∞

lim x→0- csc(x) = -∞

Recall that cot(0) is undefined, as the cotangent function has a vertical asymptote at x=0. However, we can still simplify the expression by using the limit definition of the cotangent function as x approaches 0:

lim x→0+ cot(x) = ∞

lim x→0- cot(x) = -∞

Since both sides simplify to ∞, we can say that the identity holds.

Therefore, csc(0) - sin(0) = cot(0) cos(0) is a valid identity.

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The condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

To prove that 22 6. +2,02 is an unbiased estimator of the parameter θ, we need to show that its expected value is equal to θ, i.e.,

E(22 6. +2,02) = θ.

Using the linearity of the expected value operator, we have:

E(22 6. +2,02) = E(k1Ô1 + k2Ô2)

= k1E(Ô1) + k2E(Ô2)

Since both Ô1 and Ô2 are unbiased estimators of θ, we have:

E(Ô1) = E(Ô2) = θ

Substituting these values in the above equation, we get:

E(22 6. +2,02) = k1θ + k2θ

= (k1 + k2)θ

For 22 6. +2,02 to be an unbiased estimator of θ, the above expression should be equal to θ. Therefore, we must have:

(k1 + k2) = 1

This implies that the constants k1 and k2 must satisfy the constraint:

k1 + k2 = 1

Hence, this is the condition that must be imposed on k1 and k2 so that 22 6. +2,02 is an unbiased estimator of θ.

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A sample of at least 782 children under age 6 living in West Virginia is needed to estimate the true proportion of children under age 6 living in poverty in West Virginia within 2% with 90% confidence.

We can use the formula:

n = (z^2 * p * q) / E^2

where:

z = z-score for the desired level of confidence (90% confidence corresponds to a z-score of 1.645)

p = estimated proportion (0.30 based on the federal report)

q = 1 - p

E = margin of error (0.02)

Substituting the values, we get:

n = (1.645^2 * 0.30 * 0.70) / 0.02^2 = 781.96

Rounding up to the nearest whole number, we get a sample size of 782. Therefore, a sample of at least 782 children under age 6 living in West Virginia is needed to estimate the true proportion of children under age 6 living in poverty in West Virginia within 2% with 90% confidence.

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The value of surface area is,

SA = 570 cm²

Given that;

Base of house = 6 cm

And, Height of house = 19 cm

Since, The shape of house is like a prism.

We know that;

Area of Prism is,

SA = 2B + ph,

where B, stands for the area of the base, p represents the perimeter of the base, and h stands for the height of the prism.

Hence, We get;

SA = 2 × (1/2 x 6 × 19) + 2 (6 + 6) × 19

SA = 114 + 456

SA = 570 cm²

Hence, The value of surface area is,

SA = 570 cm²

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One man alone can finish the work in about 1.26 days, and one boy alone can finish the work in about 33.33 days.

Let the work be "1" unit, and let the rate of work of one man be "m" and that of one boy be "b". Then we can set up the following system of equations based on the given information:

8m + 12b = 1/10 (equation 1)

6m + 8b = 1/14 (equation 2)

We have two equations and two unknowns, so we can solve for "m" and "b". First, we'll simplify the equations by multiplying both sides of each equation by the least common multiple of the denominators (10*14 = 140):

112m + 168b = 14 (equation 1, multiplied by 140)

84m + 112b = 10 (equation 2, multiplied by 140)

Now we can solve this system of linear equations using either substitution or elimination. Let's use elimination by multiplying equation 2 by -12 and adding it to equation 1:

112m + 168b = 14

-84m - 112b = -120

28m + 56b = -106

Simplifying, we get:

7m + 14b = -53/2 (equation 3)

Now we can solve for "m" or "b" by using either equation 2 or equation 3. Let's use equation 3:

7m + 14b = -53/2

14m + 28b = -53

7m + 14b = -53/2

Subtracting the bottom equation from the top equation, we get:

-7m - 14b = 53/2

Multiplying both sides by -1, we get:

7m + 14b = 53/2

Adding this equation to equation 3, we get:

21m = -53/2

Solving for "m", we get:

m = -53/42 = -1.26 (rounded to two decimal places)

Now we can use equation 2 to solve for "b":

6m + 8b = 1/1

Substituting "-1.26" for "m", we get:

6(-1.26) + 8b = 1/14

Simplifying and solving for "b", we get:

b = 1/14 - (-7.56)/8 = 0.03 (rounded to two decimal places)

Therefore, one man alone can finish the work in about 1.26 days, and one boy alone can finish the work in about 33.33 days.

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The true statements regarding the slope will be:

Statement 2 is correct because the slope of PQ is (3-0)/(-1-0)=-3 and the slope of RS is (2-5)/(6-5)=-3, indicating that they have the same slope and are thus parallel.

Statement 3 is correct because the slope of QR is (3-0)/(-1-0)=-3 and the slope of PS is (2-5)/(6-5)=-3, indicating that they have the same slope and are thus parallel.

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Answer:

the first order linear differential equations among the given options are:

B. [tex]sin(x)dy/dx - 3y = 0[/tex]

F. [tex]xdy/dx - 4y = x^6*e^x[/tex]

Step-by-step explanation:

A first order linear differential equation has the form:

[tex]dy/dx + p(x)y = q(x)[/tex]

where p(x) and q(x) are functions of x.

Using this form, we can identify the first order linear differential equations among the given options:

A.[tex]dP/dt + 2tP = P + 4t - 2[/tex](Not first order linear)

B.[tex]sin(x)dy/dx - 3y = 0[/tex] (First order linear)

C. [tex]dy/dx = y^2 - 3y[/tex] (Not first order linear)

D. [tex]d^2y/dx^2 + sin(x)dy/dx = cos(x)[/tex] (Not first order linear)

E.[tex](dy/dx)^2 + cos(x)y = 5[/tex] (Not first order linear)

F.[tex]xdy/dx - 4y = x^6e^x[/tex] (First order linear)

Therefore, the first order linear differential equations among the given options are:

B. [tex]sin(x)dy/dx - 3y = 0[/tex]

F[tex]xdy/dx - 4y = x^6*e^x[/tex]

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Answer: 11.76

Step-by-step explanation:  you have to divide by 12 everything and multiply by 6 and you can get the answer

We have shown that (10101) times (10011) in GF(2^5) with [tex](x^5 + x^4 + x^3 + x^2+ 1)[/tex] as the modulus is equal to (101111) in binary or [tex]x^4 + x^2 + x + 1[/tex] in polynomial form.

To multiply (10101) by (10011) in GF [tex](2^5)[/tex] with [tex](x^5 + x^4 + x^3 + x^2+ 1)[/tex] as the modulus, we first need to write these polynomials as binary numbers:

[tex](10101) = 1x^4 + 0x^3 + 1x^2 + 0x + 1 = 16 + 4 + 1 = (21)_10 = (10101)_2[/tex]

[tex](10011) = 1x^4 + 0x^3 + 0x^2 + 1x + 1 = 16 + 2 + 1 = (19)_10 = (10011)_2[/tex]

We will use long multiplication to multiply these polynomials in GF[tex](2^5)[/tex], as shown below:

    1 0 1 0 1   <-- (10101)

  x 1 0 0 1 1   <-- (10011)

  ------------

    1 0 1 0 1   <-- Step 1: Multiply by 1

1 0 1 0 1      <-- Step 2: Multiply by x and shift left

------------

1 0 0 1 0 1    <-- Step 3: Add steps 1 and 2

1 0 0 1 0 <-- Step 4: Multiply by x and shift left

1 0 1 1 1 1 <-- Step 5: Add steps 3 and 4

Now, we have the product (101111)_2, which corresponds to the polynomial [tex]1x^4 + 0x^3 + 1x^2 + 1x + 1 = x^4 + x^2 + x + 1[/tex] in GF[tex](2^5)[/tex] with [tex](x^5 + x^4 + x^3 + x^2+ 1)[/tex] as the modulus. We can verify that this polynomial is indeed in GF(2^5) with modulus [tex](x^5 + x^4 + x^3 + x^2+ 1)[/tex] by noting that all of its coefficients are either 0 or 1, and none of its terms have degree greater than 4. Additionally, we can check that it satisfies the modulus:

[tex]x^4 + x^2 + x + 1 = (x^4 + x^3 + x^2 + x) + (x^3 + 1)[/tex]

[tex]= x(x^3 + x^2 + x + 1) + (x^3 + 1)[/tex]

[tex]= x(x^3 + x^2 + x + 1) + (x^3 + x^2 + x + 1)[/tex]

(since [tex]x^3 + x^2 + x + 1 = 0[/tex] in GF[tex](2^5))[/tex]

[tex]= (x+1)(x^3 + x^2 + x + 1)[/tex]

Therefore, we have shown that (10101) times (10011) in GF(2^5) with [tex](x^5 + x^4 + x^3 + x^2+ 1)[/tex] as the modulus is equal to (101111) in binary or [tex]x^4 + x^2 + x + 1[/tex] in polynomial form.

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Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.

To prove that d is an equivalence relation on Z, we need to show that it satisfies three properties: reflexivity, symmetry, and transitivity.

Reflexivity: For any m ∈ Z, we have [tex]m^2 - m^2[/tex] = 0, which is divisible by 3. Therefore, m is related to itself under d, so d is reflexive.

Symmetry: If m d n, then [tex]3 | (m^2 - n^2)[/tex]). This means that there exists an integer k such that [tex]m^2 - n^2 = 3k.[/tex]

Rearranging this equation, we get n^2 - m^2 = -3k, which implies that 3 divides (n^2 - m^2) as well. Therefore, n d m, and d is symmetric.

Transitivity: Suppose m d n and n d p. Then, we have [tex]3 | (m^2 - n^2)[/tex] and [tex]3 | (n^2 - p^2)[/tex].

Adding these two equations, we get   [tex]3 | ((m^2 - n^2) + (n^2 - p^2)),[/tex], which simplifies to [tex]3 | (m^2 - p^2).[/tex] Therefore, m d p, and d is transitive.

Since d satisfies all three properties of an equivalence relation, we conclude that d is indeed an equivalence relation on Z.

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If sales are expressed as a function of the amount spent on advertising, then the dollar amount at which the rate of change of sales goes from increasing to decreasing is called the point of diminishing returns or diminishers returns to scale.

It sounds like you want to know about the relationship between sales, advertising, and the rate of change. Here's an answer incorporating the terms you've mentioned:

If sales are expressed as a function of the amount spent on advertising, the dollar amount at which the rate of change of sales goes from increasing to decreasing is called the inflection point. If 'x' is that dollar amount, then 'x' represents the advertising budget at which the sales growth rate starts to decline.

This point indicates that increasing the amount spent on advertising beyond this dollar amount will result in a decrease in the rate of change of sales. This is known as the diminishers' scale to return.

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(a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

To find the multiplicative inverse of a number, we use the following formula:

[tex]a^-1 ≡ b (mod n)[/tex]

Where a is the number whose inverse is to be found, b is the multiplicative inverse of a and n is the modulus.

In this case, we have:

[tex]36^-1[/tex] ≡ b (mod 45) = 4

The multiplicative inverse of 22 mod 35 is 4. To find the multiplicative inverse of a number, we use the formula a * x ≡ 1 mod m where a is the number whose inverse we want to find, x is the inverse of a and m is the modulus.

We can solve this equation using the extended Euclidean algorithm1.

In this case, we have 22 * x ≡ 1 mod 35. Using the extended Euclidean algorithm, we can find that x = 41.

Therefore, the multiplicative inverse of 22 mod 35 is 4.

The multiplicative inverse of 158 mod 331 is 201. The modular multiplicative inverse of an integer a modulo m is an integer b such that the product ab is congruent to 1 with respect to the modulus m 1.

The multiplicative inverse of 331 mod 158 is 119.

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(a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

How to find the multiplicative inverse?

To find the multiplicative inverse of a number, we use the following formula:

a⁻¹  = b (mod n)

Where a is the number whose inverse is to be found, b is the multiplicative inverse of a and n is the modulus.

a) In this case, we have:

36⁻¹ ≡ b (mod 45) = 4

b) The multiplicative inverse of 22 mod 35 is 4.

To find the multiplicative inverse of a number, we use the formula

a * x ≡ 1 mod m

where a is the number whose inverse we want to find, x is the inverse of a and m is the modulus.

We can solve this equation using the extended Euclidean algorithm1.

In this case, we have 22 * x ≡ 1 mod 35. Using the extended Euclidean algorithm, we can find that x = 41.

Therefore, the multiplicative inverse of 22 mod 35 is 4.

c) The multiplicative inverse of 158 mod 331 is 201.

The modular multiplicative inverse of an integer a modulo m is an integer b such that the product ab is congruent to 1 with respect to the modulus m 1.

d) The multiplicative inverse of 331 mod 158 is 119.

hence, (a) The multiplicative inverse of 36 mod 45 is 4.

(b) The multiplicative inverse of 22 mod 35 is 4.

(c) The multiplicative inverse of 158 mod 331 is 201.

(d) The multiplicative inverse of 331 mod 158 is 119.

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0 (to four decimal places).

To find the probability that p is less than 0.9, we need to use the normal approximation to the binomial distribution, as n is large (n=255) and p is not too close to 0 or 1 (p=0.83).

The mean of the binomial distribution is given by μ = np = 255 × 0.83 = 211.65, and the standard deviation is given by σ = sqrt(np(1-p)) = sqrt(255 × 0.83 × 0.17) = 4.46 (rounded to two decimal places).

To use the normal distribution, we standardize the variable p using the formula z = (p - μ) / σ. Then, we find the probability that z is less than (0.9 - μ) / σ.

z = (0.9 - 211.65) / 4.46 = -35.43 (rounded to two decimal places)

Using a standard normal table or calculator, we find that the probability of a standard normal random variable being less than -35.43 is essentially 0 (to four decimal places). Therefore, the probability that p is less than 0.9 is also essentially 0 (to four decimal places).

Answer: 0 (to four decimal places).

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The correct relationship is n² = 2n.

To finish the combinatorial argument by completing Method 2, we should consider the following:

Method 2:
1. As you mentioned, there are n ways for Arshpreet and Meixuan to choose the same flavor.
2. If they pick different flavors, there are a total of n*(n-1)/2 unique combinations, since this accounts for all the possible flavor pairings without double-counting.

Now, let's combine both parts of Method 2:
Total ways = Ways of choosing the same flavor + Ways of choosing different flavors
Total ways = n + n*(n-1)/2

Since both methods should result in the same number of total ways to order ice cream, we set Method 1 equal to Method 2:

n² = n + n*(n-1)/2

By solving this equation, we can verify if the given partial combinatorial argument holds true:

n² = n + n*(n-1)/2
2n² = 2n + n*(n-1)
2n² = 2n + n² - n
n² = 2n

This result shows that the given partial combinatorial argument (n² = n + 2 - 1 (i – 1)) is incorrect, as the correct relationship is n² = 2n.

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Their net pay will be the same as their gross pay, and option (a) No federal income taxes are withheld is the correct answer.

Based on the given tax table, if a single person earns a gross biweekly salary of $780 and claims 6 exemptions, the federal income tax withheld is $0.

To determine the net payback of a person with a gross biweekly salary of $780 and 6 exemptions, we need to use the federal tax table.

Unfortunately, the table is not provided in the question, so we cannot determine the exact amount of federal income tax that will be withheld.

Assuming that the person is paid on a biweekly basis, their annual gross salary would be $20,280 ($780 x 26).

Using the 2021 federal tax tables for single filers, a person with an annual gross salary of $20,280 and 6 exemptions would have a federal income tax liability of $0.

Based on the information provided, it appears that the person's net pay would not change due to federal income tax withheld, as they would not owe any federal income taxes.

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Complete Question:

The following federal tax table is for biweekly earnings of a single person.

A 9-column table with 7 rows is shown. Column 1 is labeled If the wages are at least with entries 720, 740, 760, 780, 800, 820, 840. Column 2 is labeled But less than with entries 740, 760, 780, 800, 820, 840, 860. Column 3 is labeled And the number of withholding allowances is 0, the amount of income tax withheld is, with entries 80, 83, 86, 89, 92, 95, 98. Column 4 is labeled And the number of withholding allowances is 1, the amount of income tax withheld is, with entries 62, 65, 68, 71, 74, 77, 80. Column 5 is labeled And the number of withholding allowances is 2, the amount of income tax withheld is, with entries 44, 47, 50, 53, 56, 59, 62. Column 6 is labeled And the number of withholding allowances is 3, the amount of income tax withheld is, with entries 26, 28, 31, 34, 37, 40, 43. Column 7 is labeled And the number of withholding allowances is 4, the amount of income tax withheld is, with entries 14, 16, 18, 20, 22, 24, 26. Column 8 is labeled And the number of withholding allowances is 5, the amount of income tax withheld is, with entries 1, 3, 5, 7, 9, 11, 13. Column 9 is labeled And the number of withholding allowances is 6, the amount of income tax withheld is, with entries 0, 0, 0, 0, 0, 0, 1.

The following federal tax table is for biweekly earnings of a single person.

A single person earns a gross biweekly salary of $780 and claims 6 exemptions. How does their net pay change due to the federal income tax withheld?

a. No federal income taxes are withheld.

b. They will add $11 to their gross pay.

c. They will subtract $11 from their gross pay.

d. They will add $13 to their gross pay

Answer:

the correct answer is A!

Step-by-step explanation:

I just took the test and got 100%

The area of the darkest shaded region would be 31.32 yd sq.

We know that the circle is a shape consisting of all points in a plane that are given the same distance from a given point called the center.

The area of the circle =πr²

We are given that the radius of circle is 10 yd.

The area of the circle =πr²

= 10 x 10 π

= 100π

Now the area of the octagon will be;

282.84 yd sq.

Therefore, the area of the darkest shaded region is;

area of the circle - area of the octagon

= 100π - 282.84

= 31.32 yd sq.

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Answer: 50%

Step-by-step explanation:

For an even # to result, the fraction would be 3/6 or 1/2 which would become 0.5 or 50%.

(a) The probability of rolling a 3 is 1/6.

(b) The probability of rolling a 10 is 0 since a standard six-sided die only has numbers from 1 to 6.

(c) The probability of rolling an even number is 3/6 or 1/2. This is because there are three even numbers (2, 4, and 6) out of the six possible outcomes.

(a) The probability of rolling a 3 on a six-sided die is 1/6. There are 6 possible outcomes when rolling a die, and only 1 of those outcomes is a 3.

(b) The probability of rolling a 10 on a six-sided die is 0. There are no possible outcomes when rolling a die that will result in a 10.

(c) The probability of rolling an even number on a six-sided die is 1/2. There are 3 possible outcomes when rolling a die that will result in an even number: 2, 4, and 6.

Here are the answers in mathematical notation:

(a) P(3) = 1/6

(b) P(10) = 0

(c) P(even) = 1/2

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The experimental probability of the name Grace being​ chosen = 11/108

The theoretical probability of the name Grace being​ chosen = 1/6

We know that formula for the experimental probability of event A is :

P(A) = (Number of occurance of event A) / (Total number of trials)

Here, a name is chosen 108 times and the name Grace is chosen 11 times.

Let event A: the name Grace being​ chosen

the number of occurance of event A = 11

And the Total number of trials = 108

Using above formula the experimental probability would be,

P(A) = 11/108

Here, six different names were put into a hat.

This means that the number of possible outcomes n(S) = 6

And n(A) = 1

So, the theoretical probability would be,

P = n(A)/n(S)

P = 1/6

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In the right triangle JKL, the statement cosL = 24/25 is not true considering the right use of trigonometric ratios.

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

tanL = 24/7 {opposite/adjacent is a correct statement}

cosL = 24/25 {not a correct statement because cosL = 7/25, adjacent/hypotenuse}

tanJ = 7/24 {opposite/adjacent is a correct statement}

sinJ = 7/25 {opposite/hypotenuse is a correct statement}

Therefore, the statement cosL = 24/25 is not true considering the right use of trigonometric ratios.

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The Probability density Function of Z is given by:
[tex]f_Z(z)[/tex] = { 2z, 0 ≤ z ≤ 1   , 0  otherwise. }

To find the CDF of Z = |X - Y|, we need to consider two cases:
Case 1: z < 0

If z < 0, then P(Z < z) = 0 since Z is always non-negative.

Case 2: z ≥ 0
If z ≥ 0, then we can express the event {Z < z} in terms of X and Y as follows:
{Z < z} = {(X,Y) : |X - Y| < z}
This event corresponds to a square region in the unit square with vertices at (0,0), (1-z, z), (z,1-z), and (1,1).
The area of this square is [tex]1 - (1-z)^2 = 2z - z^2.[/tex]
Since X and Y are independent and uniformly distributed in [0,1], the joint PDF of (X,Y) is fXY(x,y) = 1 for 0 ≤ x,y ≤ 1, and zero elsewhere.

Therefore, the probability of the event {Z < z} is given by the double integral:

P(Z < z) = ∫[tex]\int {Z < z} f_{XY}(x,y) dxdy[/tex]

= ∫∫|x-y| < z 1 dxdy

[tex]= 2 \int z^0 y^z 1 dxdy[/tex]

= 2∫[tex]z^0[/tex](z-y) dy

= z^2.

Thus, the CDF of Z is given by:

FZ(z) = P(Z ≤ z)

= 0, if z < 0

= z², if 0 ≤ z ≤ 1

= 1, if z > 1.

To find the PDF of Z, we can differentiate the CDF:

fZ(z) = d/dz FZ(z)

= 2z, if 0 ≤ z ≤ 1

= 0, otherwise.

Therefore, the PDF of Z is given by:

[tex]f_Z(z)[/tex] = { 2z, 0 ≤ z ≤ 1

0, otherwise. }

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