what will be the molarity of a naoh solution made by diluting 20.0 ml of 1.50 m to a final volume of 50.0 ml.

Answers

Answer 1

Explanation:

Moles in the 20 ml  

   .020 L   *   1.5  moles/L = .03 moles

now in 50 ml   (which is  .05 liters )

      .03 moles / .05 L   = .6 m


Related Questions

4. if 1 drop of acid is equal to 50 microliter. calculate the concentration of h ion and the ph of the solution when 1 drop of 0.25 m hcl is added to 3 ml water. does that conform to your observation in part d. if not, why?

Answers

We are given that 1 drop of 0.25 M HCl is added to 3 mL of water, and we need to find the concentration of H+ ions and the pH of the solution is  2.39

First, let's determine the volume of the HCl solution in the mixture. Since 1 drop of acid is equal to 50 microliters, we have 50 microliters = 0.05 mL

Now, let's find the total volume of the mixture (HCl + water):
0.05 mL (HCl) + 3 mL (water) = 3.05 mL

Next, we need to calculate the moles of H+ ions from the HCl solution. We know that the concentration of the HCl solution is 0.25 M, so:
moles of H+ = (0.25 mol/L) × (0.05 L/1000) = 0.0000125 mol

To find the concentration of H+ ions in the mixture, we divide the moles of H+ by the total volume of the mixture:
[H+] = (0.0000125 mol) / (3.05 L/1000) = 0.004098 mol/L

Now we can calculate the pH of the solution using the formula:
pH = -log10[H+]
pH = -log10(0.004098) ≈ 2.39

The pH of the solution is approximately 2.39 after adding 1 drop of 0.25 M HCl to 3 mL of water.

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Please show explanation: If 1 drop of acid is equal to 50 microliter. Calculate the concentration of H+ ion and the pH of the solution when 1 drop of 0.25 M HCl is added to 3 mL water?

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a sample of br2(g) takes 26.0 min to effuse through a membrane. how long would it take the same number of moles of ar(g) to effuse through the same membrane?

Answers

The same amount of moles of Ar would diffuse through the same membrane in 52.0 minutes more slowly than the sample of Br2 that was provided.

What is the effusion law of Graham?

According to Graham's law, a gas's rate of effusion is inversely proportional to its square root density.

The formula for the ratio of the rates of effusion of two gases is

rate of effusion of gas 1/rate of effusion of gas 2 = √(molar mass of gas 2/molar mass of gas 1)

The molar mass of Br2 is:

Molar mass of Br2 = 2 × atomic mass of Br

= 2 × 79.9 g/mol

= 159.8 g/mol

Now, we can apply Graham's law to get Ar's effusion rate relative to Br2:

rate of effusion of Ar/rate of effusion of Br2 = √(molar mass of Br2/molar mass of Ar)

= √(159.8 g/mol/39.95 g/mol)

= √4 = 2

Ar takes twice as long as Br2 to pass through the membrane before it may effuse. Therefore:

time for Ar to effuse = 2 × time for Br2 to effuse

= 2 × 26.0 min

= 52.0 min

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what is a possible set of quantum numbers m, l, ml, ms for the electron configuration of cobalt g

Answers

One possible set of quantum numbers for cobalt's electron configuration is:

m = -2, -1, 0, 1, 2, 1, 0

l = 2

ml = -2, -1, 0, 1, 2, 0, 1

ms = +1/2, -1/2, +1/2, -1/2, +1/2, -1/2, +1/2

The electron configuration of cobalt in its ground state is:

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^7

To determine the possible set of quantum numbers, we need to first fill the orbitals in the order of increasing energy and the Pauli exclusion principle, Hund's rule, and the aufbau principle.

The last electron enters the 3d subshell, which has five orbitals (dxy, dyz, dxz, dx2-y2, and dz2). The possible quantum numbers for the last electron in the 3d subshell are:

ml can have values from -2 to +2, corresponding to the five d orbitals.

l = 2 since d orbitals have an azimuthal quantum number of 2.

ms can have values of +1/2 or -1/2, corresponding to the electron's spin.

Since there are seven electrons in the 3d subshell, we can have up to seven sets of quantum numbers for the seven electrons. One possible set of quantum numbers for cobalt's electron configuration is:

m = -2, -1, 0, 1, 2, 1, 0

l = 2

ml = -2, -1, 0, 1, 2, 0, 1

ms = +1/2, -1/2, +1/2, -1/2, +1/2, -1/2, +1/2

Note that the last three electrons must have opposite spins (Pauli exclusion principle), and each orbital can have at most two electrons (Hund's rule).

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what happened to the cell potential when you added aqueous ammonia to the half-cell containing 0.001 m cuso4? how does ammonia react with copper ions in aqueous solution? (think back to coordination complexes in exp

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When aqueous ammonia is added to the half-cell containing 0.001 M CuSO4, the cell potential is likely to change. The reason for this is that ammonia can form coordination complexes with copper ions, which can affect the concentration of copper ions in the solution, and hence the concentration gradient that drives the redox reaction in the cell.

Ammonia can react with copper ions in aqueous solution to form a series of coordination complexes. The most common complex is Cu(NH3)42+, which is a tetraamminecopper(II) complex. The formation of this complex reduces the concentration of free Cu2+ ions in solution, which can shift the equilibrium of the redox reaction in the cell.

If the reduction half-reaction is Cu2+ + 2e- → Cu, the addition of ammonia can reduce the concentration of Cu2+ ions in the solution and shift the equilibrium to the left, decreasing the cell potential. On the other hand, if the oxidation half-reaction is Cu → Cu2+ + 2e-, the addition of ammonia can increase the concentration of Cu2+ ions and shift the equilibrium to the right, increasing the cell potential.

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addictive substances, for which demand is inelastic, are products for which producers can pass higher costs on to consumers.

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The statement is correct. Producers of addictive substances, for which demand is inelastic, can pass higher costs on to consumers.

Inelastic demand refers to a situation where changes in price have little effect on the quantity demanded of a product. Addictive substances, such as tobacco or drugs, often have inelastic demand because users are willing to pay high prices for the product regardless of changes in price.

Producers of addictive substances can take advantage of this inelastic demand by increasing prices without seeing a significant decrease in demand. This means that they can pass on any higher costs, such as increased taxes or production costs, to the consumers, who are likely to continue purchasing the product even at a higher price.

This is often seen in the tobacco industry, where governments may increase taxes on cigarettes as a way to discourage smoking, but the tobacco companies can simply pass on the higher costs to consumers who continue to buy the product.

Therefore, it can be concluded that producers of addictive substances, for which demand is inelastic, can pass higher costs on to consumers.

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shortly after ad 1000, biruni, an arabic physician, composed a pharmacology book with the first written description of

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Shortly after AD 1000, Biruni, an Arabic physician, composed a pharmacology book with the first written description of various drugs and their uses.

This book provided detailed information on the effects and side effects of different medicines, as well as instructions on how to prepare and administer them. Biruni's work laid the foundation for modern pharmacology and greatly contributed to the development of medicine as a science.
Biruni, an Arabic physician, composed a pharmacology book shortly after AD 1000. This book contained the first written description of various medicinal substances, their properties, and their uses in treating diseases. By incorporating detailed information on pharmacology, Biruni's work significantly contributed to the understanding and advancement of medical knowledge during that time period.

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It is believed that the pharmacology book composed by Biruni shortly after AD 1000 contained the first written description of the process of distillation.

This technique involves heating a liquid mixture to vaporize certain compounds, which are then condensed back into a liquid form and collected separately.

Biruni's description of distillation is considered significant because it paved the way for the development of many important chemical processes, such as the production of essential oils, perfumes, and alcoholic beverages.

Additionally, distillation has played a key role in the development of modern chemistry and is still widely used today in a variety of industries, including pharmaceuticals, petroleum refining, and food and beverage production.

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would you expect the carbon-hydrogen bond distances in methanol and formaldehydeto be equal, or will they be significantly different? if they are different, which molecule should have the larger c-h bond distances?

Answers

The carbon-hydrogen bond distances in methanol and formaldehyde are expected to be significantly different, with methanol having larger C-H bond distances.

The bond distance between two atoms is influenced by the size of the atoms, the number of bonds they form with other atoms, and the electronegativity difference between the two atoms. In methanol (CH3OH), the carbon atom is bonded to three hydrogen atoms and one oxygen atom, while in formaldehyde (HCHO), the carbon atom is bonded to two hydrogen atoms and one oxygen atom.

The oxygen atom in methanol is more electronegative than the carbon atom, which results in a greater electron density around the carbon atom and thus, a longer C-H bond distance. Additionally, the presence of the bulky methyl group in methanol causes steric hindrance, making it more difficult for the hydrogen atoms to approach the carbon atom, further increasing the bond distance.

In contrast, in formaldehyde, the carbon atom is bonded to only two hydrogen atoms, and the presence of the oxygen atom draws electron density away from the carbon atom, resulting in a shorter C-H bond distance.

Therefore, we can expect that the C-H bond distances in methanol will be larger than those in formaldehyde.

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What volume is equivalent to 0. 0015 m3?

Answers

The volume is the equivalent to the 0.0015 m³ is the 1.5 × 10³ cm³.

The volume of the substance which can be regarded as the quantity of the specific substance as :

The Volume = 0.0015 m³

The conversion of the m to the cm is as :

1 m³ = 1000000 cm³

The conversion of the m to the cm is as :

1 = 10⁶ cm³

The conversion of the 0.0015 m³ to the cm³ is as :

0.0015 m³ = 0.0015 m³ × ( 1000000 cm³ / 1 m³ )

0.0015 m³ = 1.5 × 10³ cm³.

The conversion of the 0.0015 m³ (meter cubic ) to the cm³ ( cubic centimeter ) is the  1.5 × 10³ cm³.

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q23.41 - level 3 homeworkunanswereddue apr 12th, 11:30 am which alkylating agent(s) should be used for the acetoacetic ester synthesis of methyl isobutyl ketone, a common solvent?

Answers

Alkylating agents are not used in the acetoacetic ester synthesis of methyl isobutyl ketone. The acetoacetic ester synthesis is a type of organic reaction.

The  response of an alkyl halide, ethyl acetoacetate, with a strong base,  similar as sodium ethoxide, yields a beta- keto ester. The process begins by forming an enolate intermediate, which is  latterly alkylated by the alkyl halide. After that, the product is hydrolyzed and decarboxylated to  give the  needed beta- keto ester.    

The alkyl halide employed for alkylation in the acetoacetic ester  conflation of methyl isobutyl ketone would be isobutyl iodide, not an alkylating agent. The enolate intermediate of ethyl acetoacetate is alkylated with isobutyl iodide, followed by hydrolysis and decarboxylation to  induce the product, methyl isobutyl ketone.   It's worth mentioning that alkylating chemicals,  similar as nitrogen mustards and alkyl sulfonates, are utilised in cancer treatment as chemotherapeutic agents.

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what is the % (m/v) concentration of a solution that contains 45.0 g of nacl dissolved in 350.0 ml of water? question 45 options: 7.78 % (m/v) 0.129 % (m/v) 12.9% (m/v) 778 % (m/v

Answers

When 45 g of sodium chloride is dissolved in 350 ml of water, the percentage mass by volume will be 12.9%. Correct option will be option 3.

Concentration of solution is usually expressed as % m/v when the amount of solute and volume of solution are given. It means the percentage of amount of substance in the given volume of the solution. Here the solution is made by mixing 45.0 g of sodium chloride in 350 ml of water.

So,  Ratio = mass/ volume = mass of solute/ volume of solution

                              = 45 / 350 = 0.129

Percentage m/v = 0.129 × 100 = 12.9 %

So here the % m/v will be 12.9%. Option 3 is the right answer.

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A sample of oxygen (O2) gas occupies a volume of 251 mL at 735 torr of pressure. Calculate the volume the oxygen will occupy if the pressure changes to 825 torr.

Answers

The volume the oxygen will occupy if the pressure changes to 825 torr is 223.62 mL.

How to calculate volume?

The volume of a gas with a changing pressure can be calculated in accordance to Boyle's law as follows;

P₁V₁ = P₂V₂

Where;

P₁ and V₁ = initial pressure and volumeP₂ and V₂ = final pressure and volume

According to this question, a sample of oxygen gas occupies a volume of 251 mL at 735 torr of pressure. If the pressure changes to 825 torr, the new volume can be calculated as follows:

251 × 735 = V × 825

V = 184,485 ÷ 825

V = 223.62 mL

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a 17% by mass h2so4(aq) solution has a density of 1.07 g/cm3 . how much solution contains 8.37 g of h2so4?

Answers

46.01 mL of the 17% H2SO4 solution contains 8.37 g of H2SO4, calculated using mass percent, density, and volume.

To decide the volume of a 17% by mass H2SO4 arrangement that contains 8.37 g of H2SO4, we want to utilize the thickness and the mass percent of the arrangement.

The mass percent of an answer is the mass of the solute separated by the mass of the arrangement, increased by 100. The thickness of an answer is the mass of the arrangement separated by its volume. Utilizing these connections, we can set up the accompanying conditions:

mass percent = (mass of solute/mass of arrangement) x 100

thickness = mass of arrangement/volume of arrangement

We can modify the principal condition to settle for the mass of arrangement:

mass of arrangement = mass of solute/(mass percent/100)

Subbing the given qualities, we get:

mass of arrangement = 8.37 g/(17/100) = 49.23 g

Then, we can utilize the thickness to track down the volume of the arrangement:

thickness = mass of arrangement/volume of arrangement

volume of arrangement = mass of arrangement/thickness = 49.23 g/1.07 g/cm3 ≈ 46.01 mL

Thusly, 46.01 mL of the 17% by mass H2SO4 arrangement contains 8.37 g of H2SO4.

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The complete question is:

A 17% by mass H2SO4 (aq) solution has a density of 1.07 g/mL. How many milliliters of solution contain 8.37 g of H2SO4? What is the molality of H2SO4 in solution? What mass (in grams) of H2SO4 is in 250 mL of solution?

karl-anthony is trying to plate gold onto his silver ring. he constructs an electrolytic cell using his ring as one of the electrodes. he runs this cell for 94.7 minutes at 220.8 ma. how many moles of electrons were transferred in this process?

Answers

0.11 moles of electrons were transferred during the electroplating process.

The number of moles of electrons transferred can be calculated using Faraday's constant, which represents the amount of charge carried by one mole of electrons.

Faraday's constant is approximately 96,485 C/mol. Using this constant and the given information, the number of moles of electrons transferred can be calculated as:

moles of electrons = (220.8 mA * 94.7 min * 60 s/min) / (1000 mA/A * 96,485 C/mol)moles of electrons = 0.11 mol

Therefore, 0.11 moles of electrons were transferred during the electroplating process.

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Any sugar that has a free aldehyde group is called a(n) _____. A) reducing sugar. B) non-reducing sugar. C) ketose. D) aldohexose. E) alditol.

Answers

Reducing sugars are a type of sugar that has a free aldehyde group. Option A is the correct answer.

This aldehyde group is capable of reducing other compounds, which is where the name "reducing sugar" comes from. Examples of reducing sugars include glucose, fructose, maltose, and lactose.

These sugars are commonly found in foods such as fruits, honey, and milk.

Non-reducing sugars, on the other hand, do not have a free aldehyde group and are unable to reduce other compounds.

Examples of non-reducing sugars include sucrose and trehalose. It is important to understand the differences between reducing and non-reducing sugars, as they can have different effects on food processing and health.

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Reducing sugars are a type of sugar that has a free aldehyde group. Option A is the correct answer.

This aldehyde group is capable of reducing other compounds, which is where the name "reducing sugar" comes from. Examples of reducing sugars include glucose, fructose, maltose, and lactose.

These sugars are commonly found in foods such as fruits, honey, and milk.

Non-reducing sugars, on the other hand, do not have a free aldehyde group and are unable to reduce other compounds.

Examples of non-reducing sugars include sucrose and trehalose. It is important to understand the differences between reducing and non-reducing sugars, as they can have different effects on food processing and health.

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A buffer solution contains 0.10 mol of acetic acid and 0.14 mol of sodium acetate in 1.00 L. What is the pH of the buffer after the addition of 0.03 mol of KOH?

Answers

The pH of the buffer after the addition of 0.03 mol of KOH is 5.04.

To answer this question, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the concentration of the acid and its conjugate base:

pH = pKa + log([A-]/[HA])

where pKa is the dissociation constant of the acid, [A-] is the concentration of the conjugate base (in this case, sodium acetate), and [HA] is the concentration of the acid (acetic acid).

First, we need to calculate the initial concentrations of acetic acid and sodium acetate:

[HA] = 0.10 mol/L
[A-] = 0.14 mol/L

Next, we need to calculate the new concentrations of acetic acid and sodium acetate after the addition of 0.03 mol of KOH. Since KOH is a strong base, it will react completely with the acetic acid to form acetate ion:

CH3COOH + KOH -> CH3COO- + H2O

The amount of acetic acid that reacts with KOH is:

0.03 mol KOH / 1 L = 0.03 M

Since acetic acid and KOH react in a 1:1 ratio, the concentration of acetic acid is now:

[HA] = 0.10 mol/L - 0.03 mol/L = 0.07 mol/L

The amount of acetate ion that is formed is also 0.03 mol/L, since acetic acid and acetate ion are in equilibrium:

CH3COOH <--> CH3COO- + H+

Since the buffer initially contained 0.14 mol/L of sodium acetate, the new concentration of acetate ion is:

[A-] = 0.14 mol/L + 0.03 mol/L = 0.17 mol/L

Now we can calculate the pH of the buffer using the Henderson-Hasselbalch equation:

pH = 4.76 + log(0.17/0.07) = 5.04

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what are the differences between stratus, cumulus, and cirrus clouds

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Stratus, cumulus, and cirrus clouds are three different types of clouds that can be identified based on their distinct characteristics.

What are distinctive about them?

Stratus clouds that grow in flat, homogeneous layers are known as stratus clouds. They are typically gray or white in appearance and frequently cover the majority or all of the sky. Light precipitation, such as drizzle or light rain, might be expected from stratus clouds.

Cumulus clouds are puffy, white clouds that look like cotton balls. They are normally associated with clear skies, but they can expand into larger, darker clouds capable of bringing thunderstorms. Cumulus clouds may be found at all levels of the atmosphere, from the ground to the upper altitudes.

Cirrus clouds are high-level clouds made of ice crystals. They are thin, wispy clouds that can seem white but also pink or orange at sunrise or sunset. Cirrus clouds frequently signify favorable weather, but they can also indicate an impending storm system.

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the equilibrium concentrations for fe3 and scn- are 5.0 x 10-4 m and 7.5 x 10-4 m. what is the equilibrium concentration for fe(scn)2 ?

Answers

The equilibrium concentration for Fe(SCN)2 is: [Fe(SCN)2+] = 2.81 x 10-10 M (rounded to three significant figures)

The equilibrium concentration for Fe(SCN)2 can be calculated using the equilibrium constant expression (Kc) for the reaction:

Fe3+ + SCN- ⇌ Fe(SCN)2+

Kc = [Fe(SCN)2+]/[Fe3+][SCN-]

Substituting the given equilibrium concentrations, we get:

Kc = [Fe(SCN)2+]/(5.0 x 10-4)(7.5 x 10-4)

If we assume that the initial concentration of Fe(SCN)2 is zero (since it is a product of the reaction), then at equilibrium, the concentration of Fe(SCN)2 will be equal to the numerator of the Kc expression:

[Fe(SCN)2+] = Kc x [Fe3+][SCN-]

[Fe(SCN)2+] = (Kc) x (5.0 x 10-4)(7.5 x 10-4)

Therefore, the equilibrium concentration for Fe(SCN)2 is: [Fe(SCN)2+] = 2.81 x 10-10 M (rounded to three significant figures)

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The chart shows the properties of four elements.



Based on these properties, which element(s) is most likely a metal?

Question 1 options:

Element 1


Element 2


Element 3


Element 4

Answers

Answer:

Element 3

Explanation:

Properties of metals are:

- Being shiny

- Are good conductors of electricity

- Are good conductors of heat

- Have a high melting point

Element 3 has all of these properties, so it is most likely a metal.

Hope this helps!

Answer: 1 and 3

Explanation:

f the barometer read 765.2 mmhg when the measurement in in the figure below took place, what is the pressure of the gas in the flask in kilopascals?

Answers

The pressure of the gas in the flask in kilopascals is given by the term 100.3 kPa, option E.

The pressure of any gas is a crucial characteristic. In contrast to qualities like viscosity and compressibility, we have some experience with gas pressure. Every day, the TV meteorologist reports the value of the atmosphere's barometric pressure.

We have included numerous slides on gas pressure in the Beginner's Guide since comprehending what pressure is and how it works is so essential to understanding aerodynamics. It is possible to investigate how static air pressure varies with altitude using an interactive atmosphere simulator. You can see how the pressure changes around a lifting wing using the FoilSim software.

height difference, h, indicates pressure of gas relative to atmospheric pressure.

h= 13mm

barometric pressure =765.2mmHg (atmosphere)

-from the picture, we can see that atmospheric pressure is greater than the gas pressure. so we minus

765.2mm - 13mm= 752.2mmHg

752.2mmHg * (101.3kPa / 760mmHg) = 100.3kPa.

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Complete question:

If the barometer read 765.2 mmHg when the measurement in in the Figure below took place, what is the pressure of the gas in the flask in kilopascals?

A.     7.55 kPa

B. 102.4 kPa

C. 1.007 kPa

D. 752.2 kPa

E. 100.3 kPa

A sample of helium gas occupies 12.4 L at 23°C and 0.956 atm. What volume will it occupy at 40°C and 0.956 atm? ___L

Answers

WHne the helium gas occupies 12.4 L at 23°C and 0.956 atm,  then at 40°C and 0.956 atm the volume of the helium gas is 13.1 L.

How do you calculate the volume of helium gas ?

We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas in a closed system. The well-known expression for the combined gas law is:

(P₁ x V₁) / T₁ = (P₂ x V₂) / T₂

We are given that P₁ = P₂ = 0.956 atm, V₁ = 12.4 L, T₁ = 23°C = 296 K, and T₂ = 40°C = 313 K. Putting  these values into the gas formula, we obtain the following:

(0.956 atm x 12.4 L) / 296 K = (0.956 atm x V₂) / 313 K

Solving for V₂, we get:

V₂ = (0.956 atm x 12.4 L x 313 K) / (296 K x 0.956 atm) = 13.1 L

Therefore, the volume of the helium gas at 40°C and 0.956 atm is 13.1 L.

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a student dissolves of resveratrol in of a solvent with a density of . the student notices that the volume of the solvent does not change when the resveratrol dissolves in it.calculate the molarity and molality of the student's solution. round both of your answers to significant digits.molaritymolality

Answers

Molarity of the solution is 0.087 M, and the molality of the solution is 0.097 m.

To calculate the molarity, first, we need to convert the given mass of resveratrol to moles using its molar mass. The molar mass of resveratrol is (14 x 12.01 g/mol) + (12 x 1.01 g/mol) + (10 x 16.00 g/mol) = 228.25 g/mol. Therefore, the number of moles of resveratrol is 19 g / 228.25 g/mol = 0.0832 mol. Then we divide the moles of solute by the volume of the solution in liters (450 mL = 0.45 L) to get the molarity: 0.0832 mol / 0.45 L = 0.087 M.

To calculate the molality, we need to use the mass of the solvent, which is equal to the mass of the solution minus the mass of the solute. The mass of the solution is 19 g + (0.81 g/mL x 450 mL) = 382.5 g. Therefore, the mass of the solvent is 382.5 g - 19 g = 363.5 g. We convert the mass of the solvent to moles using its molar mass, which is the same as for the solvent.

The molar mass of the solvent is (12 x 1.01 g/mol) + (16 x 16.00 g/mol) = 80.08 g/mol. Therefore, the number of moles of the solvent is 363.5 g / 80.08 g/mol = 4.54 mol. Finally, we divide the moles of solute by the mass of the solvent in kilograms (363.5 g = 0.3635 kg) to get the molality: 0.0832 mol / 0.3635 kg = 0.097 m.

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The complete question is:

A student dissolves 19. g of resveratrol (C14H1,0) in 450. mL of a solvent with a density of 0.81 g/ml. The student notices that the volume of the solvent Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits. does not change when the resveratrol dissolves in it.

molarity _____

molality _____

identify and describe the characteristic properties of five common acids used in industry. give some examples of the typical uses of each.

Answers

The five common acid used in industry are Hydrochloric acid, Sulfuric acid, Nitric acid, Acetic acid, and Phosphoric acid.

Here are the characteristic properties and typical uses of five common acids used in industry:

1. Hydrochloric acid: This acid is a strong mineral acid with the formula HCl. It is highly corrosive and has a pungent smell. Hydrochloric acid is used in the production of PVC, the purification of table salt, and the pickling of steel.

2. Sulfuric acid: This is a strong mineral acid with the formula H2SO4. It is highly corrosive and can cause severe burns. Sulfuric acid is used in the production of fertilizers, detergents, and dyes. It is also used in the manufacturing of lead-acid batteries.

3. Nitric acid: This is a strong mineral acid with the formula HNO3. It is highly corrosive and can be explosive in certain conditions. Nitric acid is used in the production of fertilizers, plastics, and dyes. It is also used to purify metals like gold and silver.

4. Acetic acid: This is a weak organic acid with the formula CH3COOH. It has a sharp and pungent smell and is commonly found in vinegar. Acetic acid is used in the production of textiles, plastics, and paints. It is also used in the food industry as a preservative.

5. Phosphoric acid: This is a weak mineral acid with the formula H3PO4. It is commonly used in the production of fertilizers and detergents. Phosphoric acid is also used in the food and beverage industry as a flavoring agent, and in the pharmaceutical industry as an ingredient in some medications.

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28 g of nacl is dissolved in water to generate a 0.479 m solution. what is the volume of the solution, in liters?

Answers

Answer:1.0L

Explanation:

Molar mass of NaCl = atomic mass of Na + atomic mass of Cl

= 22.99 g/mol + 35.45 g/mol

= 58.44 g/mol

Now, we can calculate the moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

= 28 g / 58.44 g/mol

≈ 0.479 moles

Next, we can rearrange the molarity formula to solve for the volume of the solution:

Volume of solution = Moles of solute / Molarity

= 0.479 moles / 0.479 M

= 1 L

The volume of the solution can be determined using the formula for molarity. From calculations, the volume of the solution has been found out to be 1 liter.

To determine the volume of the solution, we need to use the formula for molarity which is given as:

Molarity (M) = [tex]\frac{moles of solute}{volume of solution}[/tex]

First, we need to calculate the moles of NaCl. The molar mass of NaCl is 58.44 g/mol.

Moles of NaCl = [tex]\frac{mass of NaCl}{molar mass of NaCl}[/tex]

= [tex]\frac{28}{58.44}[/tex]

= 0.479 mol

Now, we can rearrange the formula for molarity to solve for the volume of the solution:

Volume of solution (in liters) = [tex]\frac{moles of solute}{Molarity}[/tex]

= [tex]\frac{0.479}{0.479}[/tex]

= 1 liter

Therefore, the volume of the solution is 1 liter.

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as ice melts, the water molecules group of answer choices stay ordered the same as in ice. go from a less-ordered phase to a more-ordered phase. go from a well-ordered phase to a less-ordered phase. none of the above previousnext

Answers

As ice melts, the water molecules group go from a well-ordered phase to a less-ordered phase. The correct answer is "go from a well-ordered phase to a less-ordered phase.

As ice melts, the water molecules go from a well-ordered phase to a less-ordered phase. In ice, the water molecules are arranged in a specific pattern, which gives it a solid, crystalline structure.

However, as the temperature increases and the ice begins to melt, the water molecules gain energy and start to move around more freely, breaking the rigid pattern.

This results in a less-ordered phase where the water molecules are no longer held in a fixed position. " None of the other answer choices accurately describe what happens to the water molecules as ice melts.

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Bacteria are most important in the process of

a. combustion.
c. nitrogen fixation.
b. condensation.
d. evaporation.

Answers

Bacteria are most important in the process of nitrogen fixation. That is option C.

What is nitrogen fixation?

Nitrogen fixation is defined as the important step in nitrogen cycle that aids in the conversation of the inert nitrogen gas to more-reactive nitrogen compounds such as ammonia, nitrates, or nitrites.

The bacteria microorganisms such as Azotobacter, Bacillus, Clostridium, and Klebsiella help in nitrogen fixation of nitrogen cycle pathway.

Therefore, bacteria are most important in the process of nitrogen fixation.

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a 10 ml suspension, in water, is made from a bloody stool sample collected from a neonate. the specimen is centrifuged and the resulting pink supernatant transferred in equal volumes to 2 tubes. the first tube serves as a reference while the second tube is alkalinized with 1 ml of 0.25 m sodium hydroxide. the second tube changes to yellow within 2 minutes. this reaction indicates the presence of :

Answers

The pink supernatant obtained from the centrifuged bloody stool sample of the neonate was likely to contain bilirubin. Bilirubin is a yellow-orange pigment that is produced from the breakdown of heme in red blood cells.

Normally, bilirubin is metabolized in the liver and excreted in bile. However, in neonates, the liver is not fully developed, and bilirubin may accumulate in the blood, causing jaundice.

The yellow color observed in the second tube, after adding 0.25 M sodium hydroxide, indicates the presence of conjugated bilirubin. Conjugated bilirubin is a water-soluble form of bilirubin that is excreted in bile.

Alkaline conditions (due to the addition of sodium hydroxide) convert unconjugated bilirubin into its water-soluble form, conjugated bilirubin. The rapid change to yellow color in the second tube suggests that the neonate had an excess of conjugated bilirubin, indicating a possible liver disease or other underlying condition that impairs bilirubin metabolism.

In summary, the yellow color change in the second tube indicates the presence of conjugated bilirubin in the bloody stool sample of the neonate, suggesting a possible liver disease or other underlying condition.

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find the location (in units of a0) of the radial node for the 2s orbital in the he ion and li2 ion. how does the location of the radial node change as the nuclear charge increases?

Answers

The radial node in an atomic orbital refers to the point where the probability of finding an electron is zero. For the 2s orbital in the He+ ion, the location of the radial node can be calculated using the radial distribution function.

This function is dependent on the distance of the electron from the nucleus and the nuclear charge. For the He+ ion, the location of the radial node is approximately 1.69a0.

Similarly, for the Li2+ ion, the location of the radial node for the 2s orbital can also be calculated using the radial distribution function. In this case, the location of the radial node is approximately 2.11a0.

As the nuclear charge increases, the location of the radial node moves closer to the nucleus. This is because the increased nuclear charge exerts a stronger pull on the electrons, causing them to spend more time closer to the nucleus. This also means that the radial distribution function is more tightly bound to the nucleus, resulting in a smaller radius for the node.

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C3H8+O2=CO2+H2O
In this reaction, if you had 5g of C3H8, how many grams of CO2 were produced?

Answers

Answer:

14.9 g of co2 would be produced.

Explanation:

First, let's balance the equation:

C3H8 + 5O2 → 3CO2 + 4H2O

Now, we can use stoichiometry to determine the amount of CO2 produced. We know from the balanced equation that for every 1 mole of C3H8, 3 moles of CO2 are produced. We can use the molar mass of C3H8 (44.1 g/mol) to convert the given 5 g to moles:

5 g C3H8 / 44.1 g/mol = 0.113 moles C3H8

Using the mole ratio from the balanced equation, we can determine how many moles of CO2 are produced:

0.113 moles C3H8 x (3 moles CO2 / 1 mole C3H8) = 0.339 moles CO2

Finally, using the molar mass of CO2 (44.0 g/mol), we can convert moles of CO2 to grams:

0.339 moles CO2 x 44.0 g/mol = 14.9 g CO2

Therefore, if you had 5g of C3H8, 14.9 g of CO2 would be produced.

consider the following polymer (pva) and potential-cross linking agent (boric acid). what type of intermolecular forces is likely to sustain cross-linking of polymeric chains in this system?

Answers

The cross-linking of PVA and boric acid is sustained by a combination of covalent and non-covalent interactions, including hydrogen bonding and van der Waals forces. These interactions lead to the formation of a stable, three-dimensional network structure that has a range of potential applications, including in the development of new materials with unique properties.


Polyvinyl alcohol (PVA) can form cross-linked networks when reacted with boric acid. The cross-linking is due to the formation of borate ester linkages between PVA chains and boric acid molecules. The formation of these linkages is facilitated by a combination of covalent and non-covalent interactions, including hydrogen bonding and van der Waals forces.

Hydrogen bonding is a particularly important intermolecular force that plays a key role in the formation and stability of the cross-linked PVA network. PVA contains hydroxyl (-OH) groups along its polymer chains that can form strong hydrogen bonds with the borate groups on boric acid molecules. This interaction leads to the formation of a three-dimensional network structure that is stabilized by the formation of multiple hydrogen bonds between adjacent PVA chains and boric acid molecules.

Van der Waals forces also contribute to the stability of the cross-linked network. These forces arise from the fluctuating dipoles in atoms and molecules and are responsible for the attraction between non-polar species. In the PVA-boric acid system, van der Waals forces between the polymer chains and boric acid molecules help to stabilize the cross-linked network.

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What types of pros and cons might you need to consider when evaluating different energy sources, such as oil, gas, solar, and wind?

Answers

Despite being simpler to store and transport than other fossil fuels and renewables, natural gas has one significant storage drawback. Its volume is four times more than that of petrol. As a result, natural gas storage is substantially more expensive since more storage area is required.

How many solar panels are required to power a home?

To fully offset power expenditures with solar, a typical home need between 17 and 21 solar panels. The amount of solar panels you require is determined by a few main criteria, including your geographic location and the specs of individual panels.

Renewable energy sources provide the majority of their energy at specific times of the day. Its electrical generation does not correspond with peak demand hours.

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