Answers
To find:
The rate of interest.
Solution:
It is known that the rate of interest is given by:
[tex]r=n[(\frac{A}{P})^{\frac{1}{nt}}-1][/tex]Here. P = 60000, A = 61200, t = 2.5 and n = 12.
[tex]\begin{gathered} r=12[(\frac{61200}{60000})^{\frac{1}{12(2.5)}}-1] \\ r=0.00792366 \end{gathered}[/tex]Change into the percentage by multiplying by 100:
[tex]\begin{gathered} r=0.00792366 \\ r=0.79\% \end{gathered}[/tex]Thus, the answer is 0.79% per year.
Related Questions
ty received test Graves of 71%, 82%, 71%, 78% and 78%.A) what grade would he need to make on the 6th test to get a C if a C is at least 75% but less than 80%?B) is it possible for tie to get a b or better for his test average at least 80%?
Answers
As given that first 5grades are: 71%, 82%, 71%, 78% and 78%.
Let the 6th grade be C
a). Then:
[tex]75\leq\frac{71+82+71+78+78+C}{6}\leq80[/tex]Simplifying it:
[tex]\begin{gathered} 75\leq\frac{71+82+71+78+78+C}{6} \\ 75\times6\leq380+C \\ 450\leq380+C \\ 450-380\leq C \\ 70\leq C \end{gathered}[/tex]And:
[tex]\begin{gathered} \frac{380+C}{6}\leq80 \\ 380+C\leq480 \\ C\leq100 \end{gathered}[/tex]So C should be in between 70 to 100.
b). For at least 80%:
[tex]\begin{gathered} \frac{71+82+71+78+78+C}{6}\ge80 \\ 380+C\ge80\times6 \\ 380+C\ge480 \\ C\ge100 \end{gathered}[/tex]It is not possible for getting b grade as one cannot achieve more than maximum marks if the maximum marks are 100.
Can you write on the paper/photo? So can write on my paper too and write it down
Answers
Answer:
1) 4x + 12
2) new area = 16x + 48
3) Yes, the ratio is the same for positive values of x
Explanation:
The distributive property of multiplication is shown below
a(b + c) = ab + ac
The area of the given rectangle is expressed as
Area = 4(x + 3)
By applying the distributive property, it becomes
4 * x + 4 * 3
= 4x + 12
The equivalent expression is
4x + 12
If the dimensions of the rectangle are doubled, then
new length = 2(x + 3) = 2x + 6
new width = 4 * 2 = 8
Thus,
new area = 8(2x + 6) = 8 * 2x + 8 * 6
new area = 16x + 48
We would input values of x into both areas and find their ratios
For x = 1,
area = 4(1) + 12 = 16
new area = 16(1) + 48 = 64
ratio = 16/64 = 1/4
For x = 2,
area = 4(2) + 12 = 20
new area = 16(2) + 48 = 80
ratio = 20/80 = 1/4
For x = 3,
area = 4(3) + 12 = 24
new area = 16(3) + 48 = 96
ratio = 24/96 = 1/4
Thus, the ratio is the same for positive values of x
the scale of a map is 1cm: 7milesthe distance between two cities is 102.2 miles.find the distance between the two cities on the map
Answers
Ok, so:
We know that the scale given is the next one:
1cm = 7miles.
Now, let me draw something here below:
So, the cities are separated by a distance of 102.2 miles.
If 1 cm = 7 miles,
Then, we're going to convert 102.2 miles to our map scale.
102.2 miles * ( 1cm / 7 miles).
And we obtain:
14.6cm
For each equation in the table, give the slope of the graph.
Answers
y=-6 is 0 or m = 0
y=-6x is -6 or m = -6
Answer:
1. undefined
2. 0
3. -6
Step-by-step explanation:
Slope-intercept form: y = mx + b
m = slope
b = y-intercept.
Since the equation x = -6 is a vertical line, the slope is undefined.
Since y = -6 is a horizontal line, the slope is 0.
The slope of y = -6x is -6. This is because it is the coefficient of the variable x.
Louis food out six different size at the picnic at the end of the picnic he noticed this about about the pies one whole apple pie was eaten and 3/4
Answers
Louis had 6 different pies. Some of them were eating and we want to know how much pie there's left. First, we have the information that one apple pie was entirely gone. From this, we know there were 5 pies remaining.
[tex]6-1=5[/tex]Then, he also noticed the other apple pie had 3/4 gone. Which means that 1/4 of this second apple pie was leftover.
[tex]1-\frac{3}{4}=\frac{1}{4}[/tex]Applying this same logic, we can deduct all the slices that were eaten from the total amount of pie we had at first to get the leftovers.
[tex]\begin{gathered} 6-1-\frac{3}{4}-\frac{1}{2}-\frac{1}{8}-\frac{5}{8}-\frac{3}{4} \\ =5-\frac{1}{2}-\frac{6}{4}-\frac{6}{8} \\ =5-2-\frac{3}{4} \\ =3-\frac{3}{4} \\ =2+\frac{1}{4} \end{gathered}[/tex]What we've done in this last equation, was taking our first amount of pies (6), subtract the whole apple pie that was eaten (1), the three quarters that were eaten from the other apple pie (3/4) and the other eaten slices from the others.
Which means, the result of this calculation is our amount of leftover slices.
We still have 2 and a quarter pies.
mputing and Using a Least-Squares Regression LineVehiclesight (tons) Gas mileage (mpg)1.6291.6451.75261.952221821211822.32.5The table shows the weight and gas mileage of severalvehicles.What is the equation of the least-squares regressionline, where ŷ is the predicted gas mileage and x is theweight?ŷ=V+According to the regression equation, a car that weighs1.8 tons would have a gas mileage of aboutmiles per gallon.
Answers
From the table, we have the following points:
(x, y) ==> (1.6, 29), (1.6, 45), (1.75, 26), (1.95, 22), (2, 18), (2, 21), (2.3, 21), (2.5, 18)
Let's find the regression line.
Apply the slope-intercept form:
y = mx + b
Where m is the slope and b is the y-intercept.
To find the slope, apply the formula:
[tex]m=\frac{n(\Sigma xy)-\Sigma x\Sigma y}{n(\Sigma x^2)-(\Sigma x)^2}[/tex]Where:
• ∑x = 1.6 + 1.6 + 1.75 + 1.95 + 2 + 2 + 2.3 + 2.5 = 15.7
• ∑y = 29 + 45 + 26 + 22 + 18 + 21 + 21 + 18 = 200
• ∑xy = 1.6⋅29 + 1.6⋅45 + 1.75⋅26 + 1.95⋅22 + 2⋅18 +2⋅21 +2.3⋅21 + 2.5⋅18 = 378.1
• ∑x² = 1.6² + 1.6² + 1.75² + 1.95² + 2² + 2² + 2.3² + 2.5² = 31.525
,• n is the number of data = 8
Now, plug in values into the equation and solve for m:
[tex]\begin{gathered} m=\frac{8(378.1)-15.7*200}{8(31.525)-(15.7)^2} \\ \\ m=-20.175\approx20.2 \end{gathered}[/tex]The slope, m = -20.2
To find the y-intercept, b, apply the formula:
[tex]\begin{gathered} b=\frac{(\Sigma y)(\Sigma x^2)-\Sigma x\Sigma xy}{n(\Sigma x^2)-(\Sigma x)^2} \\ \\ b=\frac{200(31.525)-15.7*200}{8(31.525)-15.7^2} \\ \\ b=64.594\approx64.6 \end{gathered}[/tex]Therefore, the regression equation is:
y = 64.6 + (-20.2)x
(b). Substitute 1.8 for x in the equation and solve for y:
y = -20.2(1.8) + 64.6
y = 28.24 = 28.
ANSWER:
(A). y = 64.6 + (-20.2)x
(B). 28
Answer:
here's your answer :)
Step-by-step explanation:
Given a function described as the equation y= 4x - 4, what is y when x is 1, 2, and 3?A 2, 8, 16B 4,8, 12C 0,4,8D 0, 6, 12
Answers
Answer
C. 0, 4, 8
Explanation
Given function:
y = 4x - 4
What to find:
To find y when x = 1, 2, and 3
Step-by-step solution:
When x = 1
y = 4(1) - 4
y = 4 - 4
y = 0
When x = 2
y = 4(2) - 4
y = 8 - 4
y = 4
When x = 3
y = 4(3) - 4
y = 12 - 4
y = 8
Margo borrows $1200, agreeing to pay it back with 4% annual interest after 17 months. How much interest will she pay?
Answers
Answer:
$68
Step-by-step explanation:
P = $1200
R = 4%
T = 17months (Convert to years; 17 months ÷ 12 months)
Formular for Interest; I = PRT
100
I = $1200 × 4 × 17
100 × 12
I = $68
Find the slope of the lines (-3,-1) and (-6,-10)
Answers
m = rise/run = (-10 - (-1))/(-6 - (-3)) = -9/-3 = 3
the slope of the line is equal to 3.
Find the missing quantity with the information given. Round rates to the nearest whole percent and dollar amounts to the nearest cent
Answers
Given:
Original Price $4.50
Markdown=$1.30
[tex]\begin{gathered} \text{ \% Markdown=}\frac{1.30}{4.50}\times100 \\ \text{ \% Markdown=}28.89\text{ \%} \end{gathered}[/tex]Which statements about the opposite of −12 are true? Select each correct answer. Responses −12 and its opposite are on located on the same side of zero on a number line. negative 12, and its opposite are on located on the same side of zero on a number line. The opposite of −12 is −1/12. The opposite of , negative 12, is , negative fraction 1 over 12, . −12 and its opposite are located the same distance from zero on a number line. negative 12, and its opposite are located the same distance from zero on a number line. The opposite of the opposite of −12 is −12.
Answers
Answer:
The opposite would be +12.
Step-by-step explanation:
In math, an opposite number is the number on the other side of zero on the number line that is the same distance from zero. For example, the number 5 is five spaces from zero on the right-hand side of the number line while the opposite. So the opposite would be -5 because it is five spaces from zero on the left side of a number line.
Please help ASAP!! 31 points and brainliest!
I really need help! Please show your work so I can understand how to get the answers too!
Answers
A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
What is a function?A relation is a function if it has only One y-value for each x-value.
The given function is
f(x)=2x²-4x+2
Put x=2/3
f(2/3)=2(2/3)²-4(2/3)+2
=2(4/9)-8/3+2
=8/9-8/3+2
=(8-24+18)/9
f(2/3)=2/9
Now f(x)=4x²+2x-6
Put x=1/4
f(1/4)=4(1/4)²+2(1/4)-6
=4/16+2/4-6
=1/4+1/2-6
= 1+2-24/4
f(1/4)==-21/4
Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6
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I will send a picture of the problem and or question
Answers
The equivalency for grams to centigrams is:
1 gram = 100centigrams
To convert the units you can apply cross multiplication:
1gr_____100cgr
443gr____xcgr
[tex]\begin{gathered} \frac{100}{1}=\frac{x}{443} \\ x=443\cdot100=44300 \end{gathered}[/tex]This means that 443 grams equals to 44300 centigrams
*-*-*-*
The scale is done in a base of 10 and the grams are in its center with value 1.
To convert from smaller units to grater units you have to divide the given measurement by 10
And to convert from greater units to smaller units you have to multiply by 10.
For example if you have 1mg and want to convert it to grams you have to divide the value 3 times by 10, i.e. divide the value by 1000
[tex]\frac{1mg}{1000}=0.001g[/tex]If you want to convert 1 Kg into 1 decagram, multiply the value two times by 10, i.e. multiply it by 100
[tex]1\operatorname{kg}\cdot100=100\text{dag}[/tex]use 3.14for πThe area of the circle is
Answers
The general expression for the area of circle with radius r is express as :
[tex]\text{ Area of circle = }\Pi(radius)^2,\text{ where }\Pi=3.14[/tex]In the given circle : radius is 5ft
Substitute radius = 5 ft in the expression for the area of circle :
[tex]\begin{gathered} \text{ Area of circle = }\Pi(radius)^2 \\ Area\text{ of circle=3.14}\times5\times5 \\ \text{ Area of Circle = 78.5 ft}^2 \end{gathered}[/tex]Answer : Area of circle is 78.5 square feet
Identify the property of real numbers illustrated in the following equation.(+6) + [y? • (-4)] = [y2 • (-4)] + (-6)
Answers
Given
[tex]\mleft(+6\mright)+\mleft[y^2•(-4)\mright]=\mleft[y^2•(-4)\mright]+(-6)[/tex]Answer
Commutative property of addition
The path of the baseball follows the equation h= -4.9t^2 + 60t + 1.5 where h represents the height of the baseball, t seconds after the baseball was hit. How long will it take the baseball to return to the ground?
Answers
SOLUTION
Given the question in the question tab, the following are the steps to solve the problem:
Step 1: Write out the equation for the path of the baseball where h is height and t is time in seconds
[tex]h=-4.9t^2+60t+1.5[/tex]Step 2: Rewrite the new equation
The height of the baseball when it returns to the ground is zero(0). Therefore, at that point where the baseball returns to the ground, the function becomes:
[tex]0=-4.9t^2+60t+1.5[/tex]Step 3: We solve the quadratic equation to get the value of t:
[tex]\begin{gathered} 0=-4.9t^2+60t+1.5 \\ u\sin g\text{ quadratic formula which states that:} \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ a=-4.9,b=60,c=1.5 \\ \text{Substituting the values, we have:} \\ \frac{-60\pm\sqrt[]{60^2-4(-4.9)(1.5)}}{2(-4.9)} \\ =\frac{-60\pm\sqrt[]{3600+29.4}}{-9.8} \\ =\frac{-60\pm60.2445}{-9.8} \\ =\frac{-60+60.2445}{-9.8}\text{ or }\frac{-60-_{}60.2445}{-9.8} \\ =\frac{0.2445}{-9.8}or\frac{-120.2445}{-9.8} \\ t=-0.024948979\text{ or }12.26984184 \\ t\approx-0.0249\text{ or 12.270} \end{gathered}[/tex]Since the value for time cannot be negative, hence the time it will it take the baseball to return to the ground is approximately 12.270 seconds
Find the indicated quantity, given u = (4, -9), v = (-4, -7).Step 4 of 4: Find (u • v)4v.
Answers
Answer:
[tex]\begin{equation*} \langle-1316,-2303\operatorname{\rangle} \end{equation*}[/tex]Explanation:
Given the vectors:
[tex]\begin{gathered} u=\langle4,-9\rangle \\ v=\langle-4,-7\rangle \end{gathered}[/tex]The dot product of u and v is calculated below:
[tex]\begin{gathered} u\cdot v=4\times-4+-9\times-7 \\ =-16+63 \\ =47 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} (u\cdot v)4v=47\times4\langle-4,-7\rangle \\ =329\langle-4,-7\rangle \\ =\langle-4\times329,-7\times329\rangle \\ =\langle-1316,-2303\operatorname{\rangle} \end{gathered}[/tex]The indicated quantity is:
[tex]\begin{equation*} \langle-1316,-2303\operatorname{\rangle} \end{equation*}[/tex]
8. Here is a graph of the equation 3x - 2y = 12.
Select all coordinate pairs that represent a solution to
the equation.
A. (2,-3)
B. (4,0)
C. (5,-1)
D. (0, -6)
E. (2,3)
Answers
Answer:
A,B,D
Step-by-step explanation:
By replacing the points in the current equation you can get true statements which are correspondent to answer A,B,D
Two question I want to verify my answerSolve for y in terms of x 2x =1-5yAnd Simplify the given expression Write answer with a positive exponent (X^-3/y^4)^-4
Answers
Part 1
we have
2x =1-5y
solve for y
step 1
Adds 5y both sides
2x+5y=1
step 2
subtract 2x both sides
5y=-2x+1
step 3
Divide by 5 on both sides
y=-(2/5)x+1/5
Part 2
we have the expression
[tex](\frac{x^{-3}}{y^4})^{-6}=(\frac{y^4}{x^{-3}})^6=(y^4x^3)^6=y^{(24)}x^{(18)}[/tex]graph a line that is parallel to the given line. determine the slope of the given line and the one you graphed in simplest form. click and drag on the graph to draw a line. Click and drag to plot a parallel line. The line will change colors when a parallel or perpendicular line is drawn accurately.
Answers
Choosing two points of the line given ( Lg ):
• A( ,0, -4, )
,• B( -,1.5, 0, )
Procedure:
0. Finding the slope ( ,m ,) of ,Lg:
[tex]m_{Lg}=\frac{y_2-y_1}{x_2-x_1}[/tex][tex]m_{Lg}=\frac{0_{}-(-4)_{}}{-1.5_{}-0_{}}=\frac{4}{-1.5}=-\frac{8}{3}[/tex][tex]m_{Lg}=-\frac{8}{3}[/tex]Also, based on point (0, -4), we can determine the intersection in y - axis ( b = -4). Therefore, the equation of the line given is:
[tex]y=mx+b[/tex][tex]y=-\frac{8}{3}x-4[/tex]To determine the parallel slope ( mp ), we know that parallel lines have the same slope:
[tex]m_p=m_{Lg}=-\frac{8}{3}[/tex]For the new graph, you would have to choose a different parameter b, all the equation would be the same except b. Choosing b = 3 as an example:
[tex]y=-\frac{8}{3}x+3[/tex]Answer:
• Original slope: -8/3
,• Parallel slope: -8/3
Write an equation in slope-intercept form for the line through (-1, 1) and (0,3).
Answers
The slope intercept form of a line can be written as:
[tex]y=mx+b[/tex]where m is the slope and b is the y-intercept.
We have two points of the line: (-1,1) and (0,3).
Knowing that for x=0, the value of y=3 tells us that the y-intercept b is b=3:
[tex]\begin{gathered} y=mx+b \\ 3=m\cdot0+b \\ 3=b \end{gathered}[/tex]Using the other point and replacing the values of x and y in the equation we can calculate the value of the slope m:
[tex]\begin{gathered} y=mx+3 \\ 1=m\cdot(-1)+3 \\ 1-3=-m \\ -2=-m \\ m=2 \end{gathered}[/tex]Then, with m=2 and b=3, the equation becomes:
[tex]y=2x+3[/tex]Answer: y=2x+3
Mary used the quadratic formula to find the zeros of the equation below. Select the correct zeros of the equation:3x^2 - 9x + 2 = 0Answer choices include:x = fraction numerator 9 plus-or-minus square root of 57 over denominator 6 end fractionx equals fraction numerator negative 9 plus-or-minus square root of 57 over denominator 2 end fractionx equals fraction numerator 9 plus-or-minus square root of 105 over denominator 2 end fractionx equals fraction numerator negative 9 plus-or-minus square root of 105 over denominator 6 end fraction
Answers
We have the next quadratic function given:
[tex]3x^2-9x+2=0[/tex]Mary used the next quadratic formula:
[tex]x=\frac{-b^\pm\sqrt{b^2-4ac}}{2a}[/tex]Replace using the form ax²+bx+c
Where a= 3
b=-9
c=2
Then:
[tex]\begin{gathered} x=\frac{-\lparen-9)\pm\sqrt{\left(-9\right)^2-4\left(3\right)\left(2\right)}}{2\left(3\right)} \\ x=\frac{9\pm\sqrt[]{57}}{6}\frac{}{} \end{gathered}[/tex]Therefore, the correct answer is "x = fraction numerator 9 plus-or-minus square root of 57 over denominator 6 end fraction"
Fill in the table using this function rule. y = -10x +3 y X 6 ? 1 0 a 1
Answers
the function is
[tex]y=-10x+3[/tex]we must replace the value of x and obtain y
x=-5
[tex]\begin{gathered} y=-10(-5)+3 \\ y=50+3 \\ y=53 \end{gathered}[/tex]x=-1
[tex]\begin{gathered} y=-10(-1)+3 \\ y=13 \end{gathered}[/tex]x=0
[tex]\begin{gathered} y=-10(0)+3 \\ y=3 \end{gathered}[/tex]x=1
[tex]\begin{gathered} y=-10(1)+3 \\ y=-7 \end{gathered}[/tex]If you are given a rectangle, what are the degrees of its rotational symmetry? (I need all of them between but not including 0 and 360 degrees)
Answers
A rectangle is an Order 2 of symmetry because it matchs its fugure only 2 times while rotating through 360 degrees.
The degrees of symmetry can be calculated as:
[tex]\frac{360\degree}{\text{Order}}=\frac{360\degree}{2}=180\degree[/tex]We see that at 180 degrees of rotation the shape is identical to the original shape.
This does not repeat for any other angle between 0 and 360 degrees.
Answer: 180 degrees.
Answer two questions about Equations A and B
A. 2r-1= 5x
B. -1 = 3x
1) How can we get Equation B from Equation A?
Choose 1 answer:
Add/subtract the same quantity to/from both sides
Add/subtract a quantity to/from only one side
Rewrite one side (or both) by combining like terms
Rewrite one side (or both) using the distributive property
Answers
In the given equation A, we can (A) subtract the same quantity from both sides.
What are equations?In a mathematical equation, the equals sign is used to express that two expressions are equal. An equation is a mathematical statement that contains the symbol "equal to" between two expressions with identical values. Like 3x + 5 = 15, for example. There are many different types of equations, including linear, quadratic, cubic, and others. The three primary forms of linear equations are point-slope, standard, and slope-intercept.So, obtain equation B from equation A:
Equation A: 2x - 1 = 5xEquation B: -1 = 3xWe can subtract (2x) from both sides to get equation B as follows:
2x - 1 = 5x2x - 2x - 1 = 5x - 2x-1 = 3xTherefore, in the given equation A, we can (A) subtract the same quantity from both sides.
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Suppose angles a and B are the two acute angles in a right triangle and that b < a. Apply the relationship between sine and cosine todetermine which statements are correct.sin(6x - 10) = cos(4x + 10)A)x = 9B)a = 46°a = 48°D)B = 42°E)B = 44
Answers
The right statements are: A, B and E
Sin(A)=cos(B)
then we check if using x=9 this holds true:
sin(6x-10)=cos(4x+10)
sin((6*9)-10) = sin(44º)
cos(4x+10)=cos(46)
Sin(44)=0.694=cos(46)
then a is true
Now, we know that b
triangle XZW ~ triangle XYV, find the perimeter of triangle XZW
Answers
176.4
Explanation
as the triangle are similar we can set a proportion
Step 1
find the YZ value
a) let
[tex]ratio1=\frac{hypotenuse}{rigth\text{ side}}[/tex]so,for triangle XZW
[tex]ratio=\frac{40+32}{28+YZ}[/tex]and for triangle XYV
[tex]ratio=\frac{40}{28}[/tex]as the ratios are equal, we can set a proportion
[tex]\frac{40+32}{28+YZ}=\frac{40}{28}[/tex]b) now,solve for YZ
[tex]\begin{gathered} \frac{40+32}{28+YZ}=\frac{40}{28} \\ \frac{72}{28+YZ}=\frac{40}{28} \\ cross\text{ multiply} \\ 72*28=40(28+YZ) \\ 2016=1120+40YZ \\ subtract\text{ 1120 in both sides} \\ 2016-1120=1120+40YZ-1120 \\ 896=40YZ \\ divide\text{ bothsides by 40} \\ \frac{896}{40}=\frac{40YZ}{40} \\ 22.4=YZ \end{gathered}[/tex]so
YZ=22.4
Step 2
find the length of the side WZ
a) let
[tex]ratio=\frac{hypotenuse\text{ }}{base}[/tex]hence
[tex]\begin{gathered} ratio_1=\frac{40+32}{WZ}=\frac{72}{WZ} \\ ratio_2=\frac{40}{30} \end{gathered}[/tex]set the proportion and solve for YZ
[tex]\begin{gathered} ratio_1=\text{ ratio}_2 \\ \frac{72}{WZ}=\frac{40}{30} \\ cross\text{ multiply} \\ 72*30=40WZ \\ 2160=40WZ \\ divide\text{ both sides by 40} \\ \frac{2160}{40}=\frac{40WZ}{40} \\ 54=WZ \end{gathered}[/tex]Step 3
finally, find the perimeter of triangle XZW
Perimeter is the distance around the edge of a shape,so
[tex]Perimeter_{\Delta XZW}=XY+YZ+ZW+WV+VX[/tex]replace and calculate
[tex]\begin{gathered} Per\imaginaryI meter_{\Delta XZW}=XY+YZ+ZW+WV+VX \\ Perimeter_{\Delta XZW}=28+22.4+54+32+40 \\ Perimeter_{\Delta XZW}=176.4 \end{gathered}[/tex]therefore, the answer is
176.4
I hope this helps you
Each of John’s notebook is 3/4 inches wide. If he has 36 inches of space remaining on his bookshelf, how many notebooks will fit? Write your answer in simplest form.
Answers
Given that:
- The width of each of John’s notebooks is:
[tex]\frac{3}{4}in[/tex]- The space remaining on his bookshelf is:
[tex]36in[/tex]Let be "x" the number of notebooks that will fit in John's bookshelf.
Knowing that:
[tex]\frac{3}{4}in=0.75in[/tex]You can set up the following proportion:
[tex]\frac{1}{0.75}=\frac{x}{36}[/tex]Now you have to solve for "x":
[tex]\begin{gathered} (\frac{1}{0.75})(36)=\frac{x}{36} \\ \\ \frac{36}{0.75}=x \end{gathered}[/tex][tex]x=48[/tex]Hence, the answer is:
[tex]48\text{ }notebooks[/tex]Is 1/4 n - 16 equivalent to 4(n - 4)?
Answers
Answer:
[tex]\frac{1}{4}n-16[/tex]is not equivalent to:
[tex]4(n-4)[/tex]Explanation:
The expression
[tex]\frac{1}{4}n-16[/tex]can be written as:
[tex]\frac{1}{4}(n-64)[/tex]It is not equivalent to:
[tex]4(n-4\text{)}=4n-16[/tex]In an all boys school, the heights of the student body are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. What is the probability that a randomly selected student will be taller than 71 inches tall, to the nearest thousandth?
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Answer:
0.010
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score = 63 inches
μ is the population mean = 70 inches
σ is the population standard deviation = 3 inches
For x shorter than 63 inches = x < 63
Z score = x - μ/σ
= 63 - 70/3
= -2.33333
Probability value from Z-Table:
P(x<63) = 0.0098153
Approximately to the nearest thousandth = 0.010
Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.