Answers
Answer: increases
Explanation:
Related Questions
How long would it take a car from rest and acceleration in a straight line ar 5 metres per sec to cover a dis of 200
Answers
Answer:
Explanation:
To solve this problem, we can use the following kinematic equation:
d = 1/2at^2 + vt
where d is the distance, a is the acceleration, t is the time, and v is the initial velocity.
We know that the car is starting from rest, so v = 0. We also know that the acceleration is 5 m/s^2 and the distance to be covered is 200 m. Plugging these values into the equation, we get:
200 = 1/2(5)t^2 + 0
Simplifying:
t^2 = 80
Taking the square root of both sides:
t = 8.9 s
Therefore, it would take the car approximately 8.9 seconds to cover a distance of 200 meters from rest with an acceleration of 5 meters per second squared.
does kinetic friction speed up or slow down an object? Therefore, which type of work iis done by kinetic friction?
Answers
Answer:
Speed up, friction is the force applied when slowing down.
It would be positive work because an applied force would cause an object to displace and go into a certain direction sending it into a state of motion, hence generating kinetic energy.
What is kinetic energy?
In the ordinary sense, the kinetic energy of a body is the energy that it possesses by virtue of its motion. In fact it is equal to the work that a moving body can do before coming to rest. In other words, it is equal to the amount of work required to stop a moving body.
Using the elementary third equation of motion and Newton's second law, the kinetic energy of a body of mass m and velocity v is given by the simple mathematical relation:
[tex]K=\frac{mv^2}{2}[/tex]
But this identity holds good provided that the body moves with a velocity much smaller than the velocity of light in vacuum.
Now what happens if the velocity of the body is sufficiently large?
From the expression from the relativistic linear momentum of a body of rest mass [tex]m_0[/tex] moving with velocity [tex]v[/tex] is given by
p=m0v1−v2c2−−−−−−√=m0γv
∴K=∫vd(m0γv)
=v.m0γv−∫m0γvdv
=m0γv2−m0∫vdv1−v2/c2−−−−−−−−√
Let u=1−v2/c2⟹du=−2vc2dv
∴K=m0γv2+m0c22∫du√u
=(m0v2+m0c2(1−v2c2))γ−E0
K=m0γc2−E0
Now if the magnitude of velocity is zero, then the above equation takes the form
0=m0c2−E0⟹E0=m0c2
So finally the kinetic energy of a body is given by the general relation:
K=m0γc2−m0c2=m0c2(γ−1)
Now if the velocity is small enough, then this equation closely approximates the classical relation for kinetic energy which can be ensured by expanding γ
by the binomial theorem.
Why is it important to assess your fitness level?
Answers
Assessing your fitness level is important because it help in tracking your progress and determine if you are making improvements. Regular assessments can help you identify areas where you may need to make adjustments to your fitness routine to achieve your goals. By assessing fitness level, you can identify areas where you may be weaker or less flexible. This information can help you design a fitness routine that addresses these areas and reduces our risk of injury.
Regular physical activity and exercise can improve overall health and reduce the risk of chronic diseases such as heart disease, diabetes, and obesity. By understanding your fitness level, you can design an exercise routine that helps you achieve optimal health and wellness.
Student A has a mass of 95 kg and student B has a mass of 82 kg. If their centers of mass are
0.6 meters apart, what will be the gravitational force each student exerts on the other?
Round your answer to the nearest whole number.
Answers
Answer:
0 Newtons, to the nearest whole number
Explanation:
Using the formula attached to this answer,
F = (6.67 x 10-¹¹ • 95 • 82) / 0.6²
F = 5.19593 x 10-⁷ / 0.36
F = 1.4433 x 10-⁶ N
F = 0.000001443 N
To the nearest whole number
F = 0 N
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Given the equation = Ѧ and = 1.1 × 103, = 2.48 × 10−2, and = 6.000. What is w, in scientific notation and with the correct number of significant figures?
Answers
w is 1.07 × 10^4, expressed in scientific notation with the correct number of significant figures.
How do we calculate the value of w?The equation given is:
Ψ = w/(yz^2)
We Substitute the given values, we get:
Ψ = w/(y × z^2) = 1.1 × 10^3 × 2.48 × 10^-2 × 6.000 = 1.6464
solving for w and rearranging the equation as:
w = Ψ × y × z^2
We Substitute the given values, we get:
w = 1.6464 × 37 × (14)^2 = 10,722.7584
we round the value of w to three significant figures, since the values of y, z, and Ψ are given with three significant figures, in order to express the result in scientific notation with the correct number of significant figures,
Rounding 10,722.7584 to three significant figures gives 10,700. Therefore, the value of w is:
w = 1.07 × 10^4
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An archer shoots an arrow at an 82.0 m distant target; the bull's-eye of the target is at same height as the release height of the arrow.
(a)
At what angle in degrees must the arrow be released to hit the bull's-eye if its initial speed is 40.0 m/s?
Answers
Answer:
Explanation:
We can use the following kinematic equation to solve this problem:
y = y0 + tanθ(x - x0) - (gx²)/(2v₀²cos²θ)
where
y = 0 (since the target is at the same height as the release height)
y0 = 0
x0 = 0
x = 82.0 m
v₀ = 40.0 m/s
g = 9.81 m/s²
We want to solve for θ.
Rearranging the equation and substituting the values, we get:
tanθ = (xg)/(2v₀²)
θ = tan⁻¹[(xg)/(2v₀²)]
θ = tan⁻¹[(82.0 m)(9.81 m/s²)/(2(40.0 m/s)²)]
θ ≈ 18.1°
Therefore, the archer must release the arrow at an angle of approximately 18.1 degrees to hit the bull's-eye.
Who discovered energy quanta and earned a Nobel Prize in Physics?
Answers
Answer: Max Planck
He won the Nobel Prize for Physics in 1918.
waves are generated in a rope of length 6m. What is the speed of the wave if its period is 2s
Answers
The speed of the wave with the period given above would be = 3m/s
How to calculate the speed of the wave?The wave length generated by the rope = 6m
The period of the wave = 2s
But the formula use for calculate the speed of a wave = v=λf
Where v = speed
λ= wavelength = 6m
f = Frequency.
Also F = 1/T
Where T = period = 2s
F = 1/2 = 0.5 Hz
V = 6× 0.5
V = 3m/s
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Work Energy Theorem QUESTION: A 1200kg automobile is moving at 25m/s along level ground. What is the initial KE of the automobile? What is the final KE of the automobile? What is the change in KE of the automobile?What is the work done?
Answers
(a) The initial kinetic energy (KE) of the automobile is 375,000 J
(b) The final KE will also be 375,000 J.
(c) The work done on the automobile is zero
What is the initial kinetic energy?The initial kinetic energy (KE) of the automobile can be found using the formula:
KE = 1/2mv²
where;
m is the mass of the automobile and v is its velocity.KE = 1/2 x 1200 kg x (25 m/s)²
KE = 375,000 J
The final KE of the automobile will be the same as the initial KE if the velocity remains constant. However, if there is a change in velocity, the final KE can be found using the same formula as above.
The change in KE can be found by subtracting the initial KE from the final KE, or by using the work-energy theorem:
ΔKE = W
where;
ΔKE is the change in kinetic energy and W is the work done.Assuming there is no external work done on the automobile, the change in KE will be zero.
Therefore, the final KE will also be 375,000 J.
The work done on the automobile can be found using the work-energy theorem:
W = ΔKE = 0 J (since there is no change in KE)
Therefore, the work done on the automobile is zero.
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Which has more kinetic energy:
a. A compact car going 70 MPH or a tractor trailer going 15 MPH?
b. An SUV going 30 MPH or a pickup truck going 30 MPH?
c. A school bus going 15 MPH, an SUV going 35 MPH, or a
compact car going 45 MPH?
Answers
Answer:
Explanation:
a. The compact car going 70 MPH has more kinetic energy than the tractor trailer going 15 MPH. Kinetic energy is proportional to the square of the velocity, so even though the tractor trailer may have more mass, the higher velocity of the compact car results in greater kinetic energy.
b. The SUV and the pickup truck have the same kinetic energy since they have the same mass and velocity.
c. The compact car going 45 MPH has the most kinetic energy since it has the highest velocity out of the three vehicles. The SUV going 35 MPH has less kinetic energy, and the school bus going 15 MPH has the least kinetic energy.
Which answer represents a list of UNBALANCED forces?
A group of people playing tug of war, where one side has two small children, and
the other side has two large adults: A motorcycle that is accelerating; A ball that
is decelerating as it rolls.
A skateboard sitting on a sidewalk; A car moving at a constant speed: Two
people pushing on a box with equal force
A person sitting in a chair: A train moving at a constant speed; a wagon being
pulled with 5 N of force from each direction.
Answers
The response that enumerates the unbalanced forces is a bunch of people playing tug-of-war with two young children on one side and two huge adults on the other.
Is the force used in tug of war balanced or unbalanced?In a tug of war, if both teams are applying the same amount of force on the rope, balanced forces are displayed. The forces pulling on the rope are opposing in direction and of equal magnitude.
What's an illustration of an imbalanced force?The imbalanced soldiers are acting onto the football if you kick it and it goes from one area to another. After being kicked, the ball goes from one location to another. An illustration of an uneven force is this.
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What is the electric potential energy of the group of charges in the figure? (Figure 1)
Answers
that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.
How is potential energy calculated?The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.
What is a system with two charges' potential energy?As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).
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From these measurements, compute the possible error in the volume.
Answers
Plugging in the values of the length and diameter, along with the error value, the error in the volume of the cylinder is approximately 1.27 cm³.
What is error in measurement?Error in measurement refers to the deviation or difference between the true or expected value and the measured value of a physical quantity. The presence of errors in measurement can affect the accuracy and precision of the results obtained.
To compute the possible error in the volume of the cylinder, we first need to calculate the volume of the cylinder using the measured values of its length and diameter:
V = πr²h
r = d/2 = 2.1/2 = 1.05 cm
V = π(1.05)²(8.9) = 31.79 cm³
Now, we need to determine the possible error in the volume, which can be calculated using the formula:
ΔV = V × √[(Δd/d)² + (Δh/h)²]
where Δd and Δh are the uncertainties in the diameter and length measurements, respectively. Substituting the given values, we get:
ΔV = 31.79 × √[(0.1/2.1)² + (0.1/8.9)²] = 1.27 cm³ (approx.)
Therefore, the possible error in the volume of the cylinder is approximately 1.27 cm³.
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A harp string has a length of 30.5 cm and vibrates with a node at each end and an antinode inthe center. If its frequency is 440 Hz, find (a) the wavelength and (b) the speed of the waves on the string.
Answers
Answer:
In this problem, the harp string is fixed at both ends, so it is a standing wave with nodes at both ends and an antinode in the center. The frequency of the wave is given as 440 Hz, and the length of the string is 30.5 cm.
(a) To find the wavelength of the wave, we can use the formula:
λ = 2L/n
where λ is the wavelength, L is the length of the string, and n is the number of nodes. In this case, n = 2 (since there are nodes at both ends) and L = 30.5 cm, so we have:
λ = 2(30.5 cm)/2 = 30.5 cm
Therefore, the wavelength of the wave is 30.5 cm.
(b) To find the speed of the wave on the string, we can use the formula:
v = fλ
where v is the speed of the wave, f is the frequency of the wave, and λ is the wavelength. In this case, f = 440 Hz and λ = 30.5 cm, so we have:
v = (440 Hz)(30.5 cm) = 13420 cm/s
Therefore, the speed of the wave on the string is 13420 cm/s
Explanation:
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1. Compare the relative light-gathering power of a telescope with a 40-inch primary lens with an otherwise identical telescope with a smaller 20-inch lens. Then, analyze the limitations and importance of space telescope data across the electromagnetic spectrum. In your answer, describe one way such telescope data can help astronomers determine distances between celestial objects and how this relates to how astronomers use observational astronomy methods like the cosmic distance ladder.
Answers
However, the limitations of telescopes are not solely dependent on their size. Factors such as atmospheric turbulence, light pollution, and the quality of the optics and detectors used in the telescope can also affect the quality of the images produced. Additionally, space telescopes have the advantage of being above the Earth's atmosphere, which can distort and absorb light, allowing for clearer and more precise observations of celestial objects.
Space telescopes can gather data across the electromagnetic spectrum, including wavelengths that cannot be observed from the ground, such as ultraviolet and X-ray radiation. This allows astronomers to study a wide range of celestial objects, from stars and galaxies to black holes and supernovae, in greater detail.
One way in which space telescope data can help astronomers determine distances between celestial objects is through the use of standard candles, which are objects of known luminosity. By measuring the apparent brightness of these objects, astronomers can calculate their distances using the inverse-square law of light. This method is one of several techniques used in observational astronomy to determine the distances of celestial objects, known as the cosmic distance ladder.
In conclusion, while a larger primary lens can improve the light-gathering power of a telescope, other factors also influence the quality of the images produced. Space telescopes have the advantage of being able to gather data across the electromagnetic spectrum, providing astronomers with a wealth of information about celestial objects. This information can help astronomers determine distances between objects using techniques such as the cosmic distance ladder, advancing our understanding of the universe.
A telescope with a 40-inch primary lens has four times the light-gathering power compared to a telescope with a 20-inch lens. Space telescope data is important for studying celestial objects across the electromagnetic spectrum and provides comprehensive information. Telescopic data helps determine distances between objects through techniques like redshift measurement and the cosmic distance ladder.
Explanation:The relative light-gathering power of a telescope is determined by the area of its primary lens or mirror. In this case, the telescope with the 40-inch primary lens has four times the light-gathering power compared to the telescope with the 20-inch lens. This is because the area of the 40-inch lens is four times larger than the area of the 20-inch lens.
Space telescope data is important across the electromagnetic spectrum because it allows astronomers to study celestial objects in different wavelengths, revealing information that is not accessible through visible light observations alone. By using data from telescopes that operate in various parts of the electromagnetic spectrum, astronomers can gather more comprehensive information about the universe.
One way telescope data helps determine distances between celestial objects is through the measurement of redshift. Redshift occurs when light from distant objects is stretched to longer wavelengths due to the expansion of the universe. By analyzing the amount of redshift in the light from a celestial object, astronomers can estimate its distance. This method is a part of the cosmic distance ladder—a set of techniques used to determine distances to different objects in the universe.
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A 80kg stone falls from the top of the 360 meter cliff. Neglecting friction, how fast will the stone be moving just before it hits the ground?
Answers
The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
To find how fast will the stone be moving just before it hits the ground?This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.
Potential energy = mgh,
Where
m is the mass of the stone g is the acceleration due to gravity (9.8 m/s^2) h is the height of the cliff (360 meters)Kinetic energy = (1/2)mv^2,
Where
v is the velocity of the stone just before hitting the ground.Equating these two expressions and solving for v, we get:
mgh = (1/2)mv^2
v^2 = 2gh
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s
Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
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1. A 8.2 kg mass hanging from a spring scale is slowly lowered onto a vertical spring.
A) What does the spring scale read just before the mass touches the lower spring?
B) The scale reads 14 N when the lower spring has been compressed by 2.4 cm . What is the value of the spring constant for the lower spring?
C) At what compression length will the scale read zero?
Answers
The spring scale read just before the mass touches the lower spring is 80.36N, the spring constant for the lower spring is 2765N/m and at 2.9cm length the scale will read zero.
Given the mass of spring = 8.2kg
The force exerted for compressing of spring = 14N
The compression in spring = 2.4cm = 0.024m
(A.) Initially the spring scale reads only the weight of the mass = mg
W = 8.2 * 9.8 = 80.36N
(B) Let the value of spring constant = k
The net force exerted so that the scale reads(F') = 80.36N - 14 = 66.36N
We know that according to Hooke's law the force exerted on spring F = kx such that:
F' = kx then:
66.36 = k * 0.024
k = 66.36/0.024 = 2765N/m
(C) the compression where scale reads zero = x'
The scale reads zero when the restoring force equals to the weight of the mass then the scale reads zero such that:
x' = 80.36/2765 = 0.029m = 2.9cm
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How smart is Albert Einstein?
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Albert Einstein was one of the greatest physicists of all time and is widely considered a genius. He made groundbreaking contributions to our understanding of the universe, including the theory of relativity and the famous equation E=mc².
Einstein's intelligence can be seen in his early academic achievements. He excelled in math and physics, and by the age of 16, he was already doing advanced physics research on his own. He went on to earn a PhD and made significant contributions to physics, publishing numerous papers and developing revolutionary theories.
Moreover, his ability to think creatively and critically is evidenced by his approach to problem-solving. He was known for his thought experiments, which allowed him to explore complex concepts and theories without the need for expensive equipment or experiments. He was also skilled at developing intuitive and elegant solutions to complex problems.
Therefore Einstein's intelligence is widely recognized and respected by scientists, scholars, and the general public alike. He is considered one of the most brilliant minds in history and has made a lasting impact on our understanding of the universe.
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Dish Network sent a satellite into orbit around 36000 km above the Earth's surface. What is the speed of the Satellite in miles per hour?
G=6.67 x 10^-11
M Earth = 5.98 x 10^24 kg
R Earth = 6.37 x 10^6 m
A. 306889 mi/hr
B. 6,864.38 mi/hr
C. 6.86491 mi/hr
D. 9.8mi/hr
Answers
Answer:
Explanation:
First, we need to use the formula for the speed of an object in circular orbit:
v = sqrt(GM/R)
where G is the gravitational constant, M is the mass of the Earth, R is the distance between the center of the Earth and the satellite.
Converting the units to meters and kilograms:
G = 6.67 × 10^-11 m^3/kg s^2
M = 5.98 × 10^24 kg
R = (36000 + 6.37 × 10^6) × 1000 = 4.23 × 10^7 m
Plugging in the values:
v = sqrt((6.67 × 10^-11) × (5.98 × 10^24) / (4.23 × 10^7))
v ≈ 3075.58 m/s
Finally, we can convert this to miles per hour:
v = 3075.58 m/s x (3600 s/hr) / (1609.34 m/mi) = 6873.18 mi/hr
Therefore, the answer is option A. 306889 mi/hr is incorrect.
could any of you please help i really need it
Answers
Answer: B is insulating and A is conducting
Explanation:
I really hope that's right. If not, I am so sorry.
Describe the change to the graph of Y= X +3 when Y=2X -3 is graphed 
Answers
Answer: a stretch of 2
Explanation: because it 2 (x) - 3
Glucose is a reactant in cellular respiration.
True or False?
Answers
Answer:
true
Explanation:
Answer:
True
Explanation:
Glucose is one of the reactants in cellular respiration, which is the process by which cells generate energy in the form of ATP (adenosine triphosphate). Glucose is broken down into simpler molecules in a series of metabolic reactions that occur in the presence of oxygen (aerobic respiration) or in the absence of oxygen (anaerobic respiration). The breakdown of glucose ultimately results in the release of energy that is used to produce ATP, which is the main source of energy for cellular activities.
What is the momentum of a 2.3 kg ball rolling at 6 m/s?
Show your work
Answers
Answer:
13.8 (kgm)/s
Explanation:
p(momentum) = m (mass) * v (velocity)
p= 2.3 * 6
p = 13.8
Explain how a balloon is able to keep its shape?
Answers
Answer:
It depends on how they are made.
Explanation:
Rubber balloons are not always spherical in shape. When filled with air, the inflation forms a balance between the balloon material, including its shape and thickness and its elasticity and the pressure of the air. That’s what determines its shape. Although a sphere is often the shape, it could be tubular, offset, and most other shapes.
Two stars, Bucky and Badger, form in the same giant molecular cloud. Bucky has 5 solar mass and Badger has 1 solar mass. Which of the followings is correct?
A) The main-sequence life of Bucky is 5 times longer
B) Bucky has a longer time to become a protostar
C) We can detect Badger first when it becomes a pre-main- sequence star
D) They have the same heavy elements
Answers
Answer:
Most likely the answer is D;
Explanation:
Because they formed from the same molecular cloud.
Bucky definitely will live shorter. And we can detect Bucky faster due it's enormous rate of burring fuel.
Both of the stars will have the same heavy elements.
The two stars, Bucky and Badger are formed in the same giant molecular cloud. Among them Bucky has five solar mass, which is five times the solar mass of Badger.
As a result of the higher solar mass of Bucky, its fuel will burn up very faster than Badger. So, Bucky will have shorter life. Also it will spin faster and become a protostar in short time.
Since, both the stars, Bucky and Badger are formed in the same giant molecular cloud, both of them will have the same heavy elements.
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waves are generated in a rope of length 6m. What is the speed of the wave if its period is 25.m
Answers
The speed of the wave would be0.48 m/s.
Speed of a waveThe speed of a wave is given by the formula:
v = λ/T
where v is the wave speed, λ (lambda) is the wavelength, and T is the period.
To solve this problem, we need to know the wavelength of the wave. We can find the wavelength using the formula:
λ = 2L
where L is the length of the rope. Substituting L = 6 m, we get:
λ = 2 × 6 m = 12 m
Now we can use the formula for wave speed:
v = λ/T
Substituting λ = 12 m and T = 25 s, we get:
v = 12 m/25 s = 0.48 m/s
Therefore, the speed of the wave is 0.48 m/s.
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z₁ and z₂ are two non-zero complex number such that |z₁|=|z₂| and argz₁ + argz₂ = π then z₂ equals
Answers
z₂ is equal to the negative of z₁.
Let's assume that the two non-zero complex numbers are represented in polar form as:
z₁ = r(cosθ₁ + i sinθ₁)
z₂ = r(cosθ₂ + i sinθ₂)
where r = |z₁| = |z₂| is the magnitude of both complex numbers, and θ₁ and θ₂ are their arguments.
From the given condition, we have:
arg(z₁) + arg(z₂) = π
Substituting the polar forms of z₁ and z₂ into the equation above, we get:
arctan(sinθ₁/cosθ₁) + arctan(sinθ₂/cosθ₂) = π
Simplifying this expression, we get:
θ₁ + θ₂ = π (Note that cosθ₁ and cosθ₂ are both positive because |z₁| = |z₂|, so we can use the arctan identity for the sum of two angles)
Rearranging this expression, we get:
θ₂ = π - θ₁
Substituting this into the polar form of z₂, we get:
z₂ = r(cos(π - θ₁) + i sin(π - θ₁))
z₂ = r(-cosθ₁ - i sinθ₁)
z₂ = -z₁
Therefore, z₂ is equal to the negative of z₁.
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Complete question is: z₁ and z₂ are two non-zero complex number such that |z₁|=|z₂| and argz₁ + argz₂ = π then z₂ equals to the negative of z₁.
Which material would you choose to make the handrails of the playhouse? Use the data to explain your reasoning.
Answers
Answer:
Explanation:
To choose a material for the handrails of the playhouse, we need to consider its strength and durability. One option could be stainless steel, which has a high tensile strength and is resistant to corrosion and weathering. Another option could be treated wood, which is also strong and can be treated to resist moisture and insects. Ultimately, the choice would depend on factors such as cost, aesthetics, and availability of materials.
The cross-sectional area of vessel A is 50 cm² and it contains water to a height 30 cm. The vessel B has an area of cross-section of 25 cm². The two vessels are connected with a thin tube as shown in the figure, When the tap is slowly opened, and the water attained an equilibrium in both vessels. The reduction in the potential energy of the water is (Density of water is 1000 kgm-³)
1) 7.5 J
2) 22.5 J
3) 0.75 J
4) 8.5 J
5) 75 J
Please show the working along with a brief explanation.
Answers
The reduction in the potential energy of the water is approximately 7.5 J.
option 1
What is the reduction in potential energy?We can use the principle of conservation of energy to determine the reduction in potential energy of the water.
Initially, the water in vessel A has a certain amount of potential energy due to its height above the bottom of the vessel. When the water flows through the tube and reaches vessel B, its height above the bottom of vessel B is lower than that of vessel A, which means that its potential energy has decreased.
The potential energy of the water in vessel A is given by:
PE_A = mgh_A
The mass of the water in vessel A is given by:
m = density x volume
volume = A x h_A
Substituting for m and simplifying, we get:
PE_A = density x A x h_A x g
Similarly, the potential energy of the water in vessel B is:
PE_B = density x A_B x h_B x g
At equilibrium, the height of the water in the two vessels will be the same, so we can set h_A = h_B = h.
Also, since the water is in equilibrium, the pressure at the bottom of both vessels must be the same. This means that the pressure difference between the top and bottom of the water column in vessel A (due to the weight of the water) must be balanced by the pressure difference between the top and bottom of the water column in vessel B.
The pressure difference in vessel A is:
P_A = density x g x h_A
and the pressure difference in vessel B is:
P_B = density x g x h_B
Since the pressure difference must be balanced, we have:
P_A - P_B = density x g x h_A - density x g x h_B = 0
which simplifies to:
h_A = h_B x A_B / A
Substituting for h_A and h_B in the expressions for PE_A and PE_B, we get:
PE_A = density x A x h x g
PE_B = density x A_B x h x g x A / A_B
The reduction in potential energy of the water is:
ΔPE = PE_A - PE_B = density x g x h x (A - A_B x A / A_B)
which simplifies to:
ΔPE = density x g x h x (A - A_B)
Substituting the given values, we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (50 cm² - 25 cm²)
Converting the area units to m², we get:
ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (0.005 m² - 0.0025 m²)
Simplifying, we get:
ΔPE = 7.4 J
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What is the defining property of an mechanical wave?
A. It travels by compressing particles.
B. It travels up and down.
C. It does not need a medium to travel.
D. It needs a medium to travel.
Answers
Answer: D. It needs a medium to travel.
Explanation:
One way to categorize waves is on the basis of the direction of movement of the individual particles of the medium relative to the direction that the waves travel. Categorizing waves on this basis leads to three notable categories: transverse waves, longitudinal waves, and surface waves.