Astronomers and police detectives alike must test their hypotheses against all the evidence they gather.
Astronomy is the study of everything in the universe beyond the Earth's atmosphere. This includes visible objects such as the sun, moon, planets, and stars. This includes objects that can only be seen with the telescopes and other instruments, such as distant galaxies and small particles. Astronomers are people who study the planets, stars, and other celestial bodies. They use the ground-based devices like the optical telescope and space-based devices like the Hubble Space Telescope. Some astronomers study distant galaxies and phenomena such as black holes and neutron stars. These are the difference between the astronomer and the police detective.
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the visual phenomenon whereby an elongated object protruding toward or away from a viewer appears shorter than its actual length, as though compressed, is known as:
The visual phenomenon in which an elongated object moving towards or away from the viewer appears compressed and shorter than its actual length is called linear perspective.
Linear perspective is based on a fixed point of view. A visual phenomenon in which an elongated object projected toward or away from the viewer appears to be compressed shorter than it actually is. Linear perspective is a system that creates the illusion of depth on a flat surface. All parallel (perpendicular) lines in a painting or drawing using this system converge at a single vanishing point on the horizontal line of the composition. An example of linear perspective is the obvious convergence of two parallel lines, especially when viewing a long two-lane highway.
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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1. 40 cm. If the potential difference across the plates was 28. 5 kV, find the magnitude of the electric field (in V/m) in the region between the plates
The magnitude of the electric field (in V/m) in the region between the plates is 20.35x10^5V/m.
Given the distance between the plates (d) = 1.4cm = 1.4x10^-2m
The potential difference across the plates is (V) = 28.5kV = 28.5x10^3V
The electric field between two parallel conducting plates is dependent on the voltage or potential difference between the two plates as well as their separation from one another. The two charged parallel plates would carry their total charges since an electric insulator separates them. Because the two parallel charged plates are kept apart from one another, a homogenous electric field is created there.
According to Coulombs law E = V/d such that
E = 28.5x10^3V/1.4x10^-2m = 20.35x10^5V/m
Hence the required magnitude of the electric field is 20.35x10^5V/m
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the intensity of the sun's rays do not fall uniformly across earth's surface. this is driven, in large part, by:
The intensity of the rays of sun does not fall uniformly across the surface of the earth. In large part, this is driven by latitude and season.
There is a relationship between latitude and temperature across the world, as typically temperatures are warmer approaching the Equator while cooler approaching the Poles. There exist variations, though, as other factors such as ocean currents, elevation, and precipitation affect climate patterns.
As a result latitude and season make the intestity of the sun ray's to fall nonuniformly all around the globe.
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A force of 45 n is exerted on an object, resulting in an acceleration of 5 m/s² for the object. what will the object's acceleration be if the force doubles? question 9 options: a. 2.5 m/s² b. 5 m/s² c. 10 m/s² d. 20 m/s²
Answer:
Option C. 10 m/s²
Explanation:
First we need to find the mass of the object.
We can use Newton's second law to evaluate the mass of the object.
Newton's second law says that the net force of is equal to the mass times it acceleration.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]m[/tex].
Divide each side by [tex]a[/tex].
[tex]m=\frac{F_{net} }{a}[/tex]
We are given
[tex]F_{net} =45\\a=5[/tex]
Lets evaluate [tex]m[/tex].
[tex]m=\frac{45}{5}[/tex]
[tex]m=9[/tex]
Now we can find the object's acceleration if the force doubles.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]a[/tex].
Divide each side by [tex]m[/tex].
[tex]a=\frac{F_{net} }{m}[/tex]
Doubling the force of 45 N leaves us with a force of 90 N.
[tex]a=\frac{90}{9}[/tex]
[tex]a=10[/tex]
We can see that the object's acceleration is directly proportional to the net force and inversely proportional to the object's mass.
A 1.0 kg toy
car is released at the top of a frictionless track on the left and rolls off of the track
from its right side ramp. The car starts at a height of 0.80 m, goes through a 0.50 m diameter
loop, and exits the ramp at a height of 0.25 m.
L
0.80 m
B
0.50 m
0.25 m
The 0.80 m is the starting height of the car at the top of a frictionless track.
What is frictionless?
Frictionless is a type of technology that enables activities or processes to occur without resistance or difficulty. It is used in a variety of fields, from banking to digital marketing, and it generally involves the use of software or other digital tools that simplify complex tasks and make them easier to accomplish. With frictionless technology, users are able to perform tasks faster, more securely and with minimal effort. For example, in banking, frictionless technology is used to enable customers to make payments or transfers without having to enter their credentials or payment information each time. Similarly, in digital marketing, frictionless technology is used to enable customers to make purchases without having to enter their billing information multiple times.
The 0.50 m is the diameter of the loop that the car goes through. The 0.25 m is the height of the car when it exits the ramp.
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1. Mr. Gewanter, whose mass is 60 kg, is doing a physics demonstration in the front of the classroom.
A. How much gravitational force does he exert on 55 kg Martha in the front row, 1.5 m away?
B. How much force does he exert on 65 kg Lester in the back row, 4.0 m away?
2. A 400 kg weather satellite is about to launched into orbit.
A. When the satellite is still on Earth, what is the gravitational force on it? (The mass of the Earth is 5.98x1024 kg and the radius of the Earth is 6.37x106 m)
B. What radius of orbit does the satellite need to experience half this force?
By performing a physics demonstration in front of the students. F is 9.79 x 108 newtons.
Given,
Mr. Gewanter weighs 60 kilograms (kg).
The weight of Martha is 55 kg.
d = 1.5 meters separates them.
The equation F = GMm/d2 newton determines the gravitational force between them.
changing the given values in the equation above
F = (6.673 x 1011 x 60 x 55)/1.52 = 9.79 x 108 newtons.
As a result, F = 9.79 x 108 newton is the gravitational pull Mr. Gewanter has on Martha.
A geostationary satellite travels in a circular path around the planet with a 36,000 km radius. The orbital period of a spy satellite will then be roughly (Re = 6400 km), orbiting a few hundred kilometers above the surface of the planet.
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a teacher sends her students on a treasure hunt. she gives the following instructions: 1. walk 300 m north 2. walk 400 m northwest 3. walk 700 m east-southeast and the treasure is buried there. as all the other students walk off following the instructions, joe physics student quickly adds the displacements and walks in a straight line to find the treasure. how far and in what direction does joe need to walk?
The directions she gives are as follows: 1. Move 400 meters to the northwest. 3. The wealth is hidden there, 700 meters to the east-southeast.
What is a displacement example?Change inside an object's position in relation to a reference frame is known as displacement. For instance, a billiards ball moves of one spot to another when one player strikes it. It is alleged to have moved. A vector quantity with both size and direction is displacement.
What is another name for displacement?The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International Unit System (SI) (m).
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what is dark matter? where does it reside in our galaxy? what makes dark matter and dark energy so mysterious and so important?
Dark matter is a hypothetical form of matter that is thought to make up approximately 85% of the total matter in the universe.
What is dark matter and where does it reside?
It is called "dark" because it does not emit, absorb, or reflect any electromagnetic radiation, making it invisible to telescopes.
It is believed that dark matter resides in the halo of our galaxy, which is a large, spherical region that surrounds the galaxy. It is also thought to be present in galaxy clusters and in the large-scale structure of the universe.
Dark matter and dark energy are mysterious because they cannot be directly observed through telescopes or other instruments. They are detected only through their gravitational effects on visible matter, such as the rotation of galaxies and the expansion of the universe.
Dark matter and dark energy are important because they play a crucial role in the formation and evolution of structure in the universe. The gravitational pull of dark matter is thought to be responsible for the formation of galaxies and galaxy clusters, while dark energy is thought to be driving the accelerated expansion of the universe.
Understanding the properties and behavior of dark matter and dark energy is a major focus of current research in cosmology and astrophysics.
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The speed of a moving bullet can be determined by allowing the bullet to pass through two rotating paper disks mounted a distance 99 cm apart on the same axle. From the angular displacement 26° of the two bullet holes in the disks and the rotational speed 407 rev / min of the disks, we can determine the speed of the bullet.
What is the speed of the bullet?
Answer in units of m/s.
Answer:
To calculate the speed of the bullet, we can use the equation v = rωθ, where r is the distance between the disks, ω is the angular speed, and θ is the angular displacement of the bullet holes. In this case, v = 99 cm(2π/60)(26°/360) = 7.8 m/s. Therefore, the speed of the bullet is 7.8 m/s.
these fringe shifts occur because the wavelength of the light changes inside the gas filled tube. assume that 502 nm light is used, the tube is 3.99 cm long, and that 221 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. calculate ngas, the index of refraction of the gas
The index of refraction of gas will be 1.008 units.
What is index of refraction?Because of their low density, gases at atmospheric pressure have refractive indices close to one.The refractive index, also known as the index of refraction, is a measurement of the bending of a light ray as it passes through one medium and into another.The number of wavelengths originally in the cylinder is m1 = 2L/λ when light is counted in both directions.
It transforms into m2 = 2L/λ/n gas.
= 2ngasL/λ
As the cylinder is filled with gas,
If N is the number of bright fringes passing,
N = m2 - m1
= 2L/λ (ngas - 1) or,
The index of refraction of the gas is,
ngas =1 + Nλ/2L = 1+ (221)(502 x 10⁻⁹ m)/2(3.99 x 10⁻²)
= 1.008 units
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A spring will never do negative work as it moves toward from equilibrium.
a. Tue
b. False
for each of the following cases, indicate whether the work done is positive or negative. explain your answers. a) work done by an applied force in lifting a bucket of water upward. fa mg b) work done by the weight of the bucket c) work done by the applied force and mg if the bucket were lowered.
The work done in case a) is positive, in case b) is negative and in case c) is positive.
Work is said to be done when the displacement is occur in the direction of the applied force.
W = F×d×cosθ
Where F is the force, d is the displacement and θ is the angle between the displacement and the direction of the force.
In case a) as the work is done against the direction of the gravity so the work is positive. In case b) the weight of the buckets acts in downwards direction, that is the direction of the acceleration due to gravity. So the work is negative. In case c) the bucket were lowered, it means the displacement is in the direction of the applied force. Hence the work done is positive.
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A bob of mass m is suspended from a fixed point with a massless string of length L (i. E. , it is a pendulum). You are to investigate the motion in which the string moves in a cone with half-angle θ. What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical? Express your answer in terms of some or all of the variables m, L, and θ and the acceleration due to gravity, g
The tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical is √mgLsinθtanθ.
Given the mass of bob = m
length of string = L
The angle the string of pendulum makes with cone = θ
The tangential speed the bob moves = v
the vertical component of tension must support the weight of the bob which is represented as: Tcosθ = mg where g is acceleration due to gravity.
the horizontal component of tension must equal the centripetal force acting on the bob which is: Tsinθ = v^2/r where r is the radius of orbit.
However, we know that, r = Lsin(θ) then Tsinθ = v^2/Lsin(θ)
Then Tsinθ/Tcosθ = v^2/(mg x Lsin(θ))
tanθ = v^2/mgLsinθ
then v = √mgLsinθtanθ
Hence the tangential speed the bob moves with is √mgLsinθtanθ
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solve: a 7.00-g bullet is fired into a ballistic pendulum whose bob has a mass of 0.950 kg. if the bob rises to a height of 22.0 cm, what was the initial speed of the bullet?
Answer: Intital speed of bullet is 286 m/s.
What is law of conservation of energy?
--The law of conservation of energy states that energy can neither be created nor be destroyed.
-- Although, it may be transformed from one form to another.
-- If you take all forms of energy into account, the total energy of an isolated system always remains constant.
According to law of conservation we have,
V1 = Vbu + Vb/ Vb( 2gh)^1/2
Mass of Bob is 0.950 Kv
Mass of bullet is 7g.
By solving above bw get intial speed of bullet is 289m/s.
What is energy ?
--In physics, energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
--Energy is a conserved quantity—the law of conservation of energy states that energy can be converted in form, but not created or destroyed.
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a boat can move at 30 km/h in still water. how long will it take to move 12 km upstream in a river flowing 6.0 km/h?
A boat can move at 30 km/h in still water, so to move 12 km upstream in a river flowing 6.0 km/h, it will take 20 minutes.
Water is referred to as still water when its motion is zero, or when it is still. Motionless water is defined as water that remains still, not flowing, and has no current, such as in rivers and streams. Therefore, a boat's relative speed on calm water is equal to 12 (a + b) km/hr. The stream is moving at a pace of 1/2 (a - b) km/hr.
Moving upstream, or against the flow of water, refers to a boat going against the current. The distinction when speaking about water in rivers and streams is that upstream is in opposition to the water flow and in the direction of the water's original source (where the river originates).
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Which one of the forces in the diagram below must do negative work (W < 0) while acting
throughout the displacement shown? (Select all that apply.)
a. F1
b. F2
c. F3
d. F4
The forces F2 and F3 are the forces that would do a negative work.
What is negative work?We have to to note that the term work has to do with the product of the force and the distance of the object that has been covered in the direction of the force.
Now we know that we have the system of forces that is acting at a common point. We must note that the quadrant in which the force falls is what would tell us the kind of work that the force would have to do.
The forces that are in the negative quadrants are the ones that would do a negative work.
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maximum current problem. if the current on your power supply exceeds 500 ma it can damage the supply. suppose the supply is set for 37 v. what is the smallest resistance you can measure? please write your answer with integer value.
The smallest value of resistance that we can measure is 74 Ω(ohm), if the maximum power supply is 500 ma and the supply voltage is 37 V.
According to Ohm's law, the current in a conductor is directly proportional to the potential difference between its two ends. In other words, the ratio of the potential difference(V) and the electric current(I) is a constant in a conductor. This constant is called "resistance(R)". its unit is Ω(ohm). Mathematically,
V = IR
R = V/I
The maximum current, I = 500 ma = 500 × 10⁻³ A
Voltage supply, V = 37 Volts
R = 37/ (500 × 10⁻³) = 74 Ω
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4. 77 Augment the rectifier circuit of Problem 4. 70 with a capacitor chosen to provide a peak-to-peak ripple voltage of (i) 10% of the peak output and (ii) 1% of the peak output. In each case: (a) What average output voltage results? (b) What fraction of the cycle does the diode conduct? (c) What is the average diode current? (d) What is the peak diode current?
You may calculate the average load current—the average diode current—by dividing the average load voltage by the average load resistance.
What is the diode's typical forward current?Vavg = 15.45 V
Diode conduction is 7.11 percent.
Iavg = 0.232 A
Ip = 0.449 A
Case (ii) (ii)
Vavg = 16.18 V
Diode conduction is 2.25 percent.
Iavg = 0.735 A
Ip = 1.453 A
The transformer's secondary side has a voltage of
= Vpri/turn ratio
Vrms = 120/10 = 12 V
Peak voltage and rms voltage have the following relationship:
Vp = Vrms / 2.
Vp = 12√2 = 16.97 V
Vd = 0.7 V
We will first determine all the necessary variables for the ripple voltage of 10%, and then for the ripple voltage of 1%.
10% of the highest output in scenario I
What average output voltage is produced?
Vavg = Vp - Vd - 0.5Vr is the average output voltage.
Vp is the maximum output voltage.
Diode voltage drop is denoted by Vd, while ripple voltage is denoted by Vr, which is expressed as a percentage of Vp.
Vavg = 0.5Vr + Vp - Vd
Vavg = 16.97 - 0.7 - 0.5[0.1(16.97 - 0.7)]
Vavg = 15.45 V
(b) The diode conducts what percentage of the cycle?
= Vd - 2Vr/Vp
Vp- Vd = 2*0.1 (Vp-Vd)/Vp
ω = √2*0.1(16.97-0.7)/16.97 - 0.7
ω = 0.447 rad
Diode conductance equals (/2)*100
Diode conductance is (0.447/2)*100
Diode conduction is 7.11 percent.
The typical diode current is (c).
Iavg = Vavg/R[1 + (2(Vp - Vd)/0.1(Vp-Vd))] is the formula for average current.
Average current is equal to Iavg, which is 15.45/1000[1 + (2(16.97 - 0.7)/0.1(16.97-0.7)]
Iavg, or average current, is 0.232 A.
(d) How much diode current peaks at?
Peak current is defined as Ip = Vavg/R[1 + 2(2(Vp - Vd)/0.1(Vp-Vd)]
Peak current is expressed as Ip = 15.45/1000[1 + 2](2(16.97 - 0.7)/0.1(16.97-0.7)]
Peak current is 0.449 A, or Ip.
What average output voltage is produced?
Vavg = 16.97 - 0.7 - 0.5[0.01(16.97 - 0.7)]
Vavg = 16.18 V
(b) The diode conducts what percentage of the cycle?
Vp - Vd = 2*0.01(Vp-Vd)
ω = √2*0.01(16.97-0.7)/16.97 - 0.7
ω = 0.1417 rad
Diode conductance is (0.1417/2)*100
Diode conduction is 2.25 percent.
The typical diode current is (c).
Average current is equal to Iavg, which is 16.18/1000[1 + (2(16.97 - 0.7)/0.01(16.97-0.7)]].
Average current is 0.735 A (Iavg).
(d) How much diode current peaks at?
Peak current is expressed as Ip = 16.18/1000[1 + 2](2(16.97 - 0.7)/0.01(16.97-0.7)]
Peak current is 1.453 A, or Ip.
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atoms join to form chemical groups called ______, which in turn join to form ______
Atoms join to form chemical groups called molecules, which in turn join to form compounds.
What are Molecules?A molecule is a group of two or more atoms that are chemically bonded together. The bonding is achieved through the sharing or exchange of electrons between the atoms. The atoms in a molecule can be the same or different elements and can be arranged in various ways to form different types of molecules.
Molecules can be either simple or complex, depending on the number of atoms and the types of chemical bonds that hold the atoms together. Simple molecules, such as H2 and O2, are composed of only a few atoms, while complex molecules, such as proteins and DNA, can contain hundreds or even thousands of atoms.
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an airplane starts from a brakes locked position and accelerates down the runway at 11 ft/s2. it reaches takeoff airspeed at 275 ft/s. what is the time for the airplane to reach takeoff speed?
The aircraft takes off from the runway with its brakes locked. At such a speed of 200 fps, the aircraft takes off. Find out when the plane will arrive.
How quickly do airplanes take off and land?
The ground run can be a little bit longer if a decreased power takeoff is being performed. Prior to takeoff, a typical commercial aircraft accelerates to a speed of 120–140 knots. It will need a strong sustained acceleration to complete it in 30 to 35 seconds. Pilots watch for this as they roll out for takeoff.
What is the total vertical force acting on the aircraft when it takes off?
When a result, there is no net vertical force acting on the aircraft as it takes off. When a result, there is no net vertical force acting on the aircraft as it takes off. The net vertical force acting on the aircraft as it ascends is therefore 65000 Newton.
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A car drives 500 m to the East and then 200 m back to the West.
What is the objects total distance
The frequency of a wave is the wide variety of oscillations or cycles according to unit of time, commonly measured in hertz (Hz). The objects total distance is 700 m.
What is wavelength?The wavelength is the distance between consecutive peaks or troughs in a wave, normally measured in meters. The velocity of a wave is the distance it travels consistent with unit of time, generally measured in meters in keeping with 2d. The connection among frequency, wavelength, and velocity is defined by way of the equation: velocity = frequency x wavelength.
This courting is referred to as the wave equation. As frequency increases, wavelength decreases and as frequency decreases, wavelength will increase.
The total distance of the object is
500 m + 200 m
= 700 m.
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what are the (a) magnitude and (b) direction of the net electrostatic force on particle 4 due to the other three particles? all four particles are fixed in the xy plane, and q1
The magnitude and direction of the net electrostatic force on particle 4 due to the other three particles are 6.16×10^−24 N counterclockwise from the +x axis.
The individual force magnitudes are found using Eq., with SI units (soa=0.02 m) and k as in Eq., We use magnitude-angle notation (convenient if one uses a vector-capable calculator in polar mode), listing the forces due to +4.00q,+2.00q, and −2.00q
charges: (4.60×10^−24∠180 deg )+(2.30×10^−24∠−90 deg )+
(1.02×10^−24∠−145 deg)= (6.16×10^−24 ∠−152 deg )
Therefore, the net force has magnitude of 6.16×10^−24 N.
The direction of the net force is at an angle of −152 deg or 208 deg
measured counterclockwise from the +x axis).
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The complete question is :
n Fig. what are the direction of the net electrostatic force on particle 4 due to the other three particles? All four particles are fixed in the xy plane, and q1 = - 3.20 × 10^-19C, q2 = + 3.20 × 10^-19 C, q3 = + 6.40 × 10^-19 C. d 3=2.00 cm.
a 90-kg fullback, running at 5.0 m/s attempts to dive across the goal line for a touchdown. just as he reaches the goal line, he is met head-on in midair by two 73-kg linebackers, one moving at 3.0 m/s and the other at 4.0 m/s. if they all become entangled as one mass, with what velocity do they travel?
The final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
To find the velocity of the combined mass of the fullback and the two linebackers, we need to use the principle of conservation of momentum. This principle states that the total momentum of an isolated system remains constant if no external forces act on it.
First, we need to find the initial momentum of the fullback by multiplying his mass (90 kg) by his velocity (5.0 m/s):
Initial momentum of fullback = 90 kg * 5.0 m/s = 450 kg m/s
Next, we need to find the initial momentum of the two linebackers by multiplying each of their masses by their velocities:
Initial momentum of first linebacker = 73 kg * 3.0 m/s = 219 kg m/s
Initial momentum of second linebacker = 73 kg * 4.0 m/s = 292 kg m/s
Now, we need to add the initial momentum of the three individuals to find the total initial momentum:
Total initial momentum = 450 kg m/s + 219 kg m/s + 292 kg m/s = 961 kg m/s
Since the final velocity of the combined mass is going to be the same as the initial momentum, we can say:
Final velocity = 961 kg m/s / (90 kg + 73 kg + 73 kg) = 961 kg m/s / 236 kg = 4.09 m/s
Therefore, the final velocity of the combined mass of the fullback and the two linebackers is 4.09 m/s.
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the coriolis effect describes the . multiple choice question. wobble of air masses resulting from a titled earth apparent deflection from straight-line movement of air and water masses condensation of water vapor on rotating aerosols expansion of air and water masses due to heating and cooling
The Coriolis effect describes the deflection pattern experienced by an object that is not firmly anchored to the ground as it travels long distances around the Earth. Many large-scale weather patterns are caused by the Coriolis effect.
The rotation of the Earth is important for the Coriolis effect. In particular, the Earth rotates faster at the equator than at the poles. Because the Earth is wider at the equator, the equatorial region must travel about 1,000 kilometers (1,000 miles) per hour to make one revolution of her in 24 hours. The Earth rotates slowly near the poles at 0.00008 kilometers (0.00005 miles) per hour. If you play catch anywhere in the northern hemisphere, the ball will curve to the right.
Apparent deflection is due to the Coriolis effect.
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Four cannonballs, each with mass M and initial
velocity V, are fired from a cannon at different
angles relative to the Earth. Neglecting air friction,
which angular direction of the cannon produces the
greatest projectile height?
1. 70 degrees
2. 20 degrees
3. 45 degrees
4. 90 degrees
4. 90 degrees angular direction of the cannon produces the greatest projectile height.
which angular direction of the cannon produces the greatest projectile height?The angular direction of the cannon that produces the greatest projectile height is 90 degrees. This is because at 90 degrees, the cannonball has the greatest initial velocity component in the vertical direction, and the least initial velocity component in the horizontal direction.With no air friction, the vertical component of velocity will remain constant and the horizontal component of velocity will be zero, resulting in the cannonball traveling in a parabolic arc with maximum height at the top. Therefore, the ball fired at 90 degrees will reach the greatest height. The cannonball fired at 70 degrees will also have a significant vertical component of velocity, but its horizontal component will be greater than that of the 90 degree shot, resulting in a lower maximum height.The cannonball fired at 20 degrees will have a small vertical component and a large horizontal component resulting in the trajectory being relatively flat with a much lower maximum height.The cannonball fired at 45 degrees will have an equal vertical and horizontal component of velocity, resulting in a trajectory somewhere in between the 90 and 20 degree shots, but with a lower maximum height than the 90 degree shot.To learn more about The angular direction of the cannon refer to:
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A 120 kg skydiver jumped out of a plane 3500m in the air. Determine the Gravitational potential energy of the skydiver
The gravitational potential energy of the skydiver is 4.2 × 10⁷.
Define Gravitational potential energy of the skydiverThe amount of work done on an object is directly proportional to the force applied on the object and the distance it moves in the direction of that force. The speed of an object does not directly affect the amount of work done on it. However, if the force and distance are constant, the work done on an object will be greater if it is moving at a higher speed because the object will have greater kinetic energy.
In addition, the time taken to do the same amount of work on an object will be less if it is moving at a higher speed, as the work is done over a shorter period of time.
The required details for gravitational in given paragraph
Joules (120 x 9.8 x 3500)
= 42,000,000 or 4.2 × 10⁷
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A ball freely falling at 20 m/s will in the next second have a speed of ______. 30 m/s. What two units of measurement are necessary for describing speed?
Two units of measurement are necessary to describe the speed, are meter and second.
Speed of an object is nothing but the distance travelled by the object in unit time. A freely falling ball experience the acceleration due to gravity in the downward direction. The value of acceleration due to gravity of the earth is roughly taken as 10 m/s². If the initial speed is 20 m/s. and Time, t = 1 sec. Then speed in the next second will be v = u + at
v = 20 + 10 × 1
v = 30 m/s
Meter is the SI unit of length or distance and second is the SI unit of time.
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nitrogen is contained in a 5-m3 rigid vessel at a pressure of 2200 kpa. (a) determine the mass if the temperature is 25oc. (b) determine the mass if the temperature is 250oc. (c) what would be the height of a column of mercury (in mm) in a manometer for this pressure? the density for mercury is 13600 kg/m3.
Barometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.
How tall a column does a mercury have vertically?As a result, less than 76 cm of mercury can be held vertically in space by a basic barometer at sea level.Indicators of atmospheric pressure include the mercury column's height. The mercury column rises to a height of roughly 30 inches (76 centimeters) at sea level at a temperature of 0 degrees Celsius (C). This is equivalent to about 14.7 psia of pressure.Ytop minus YBot in HcolumnBarometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.To learn more about Barometric column refer to:
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Sc 1.1 Two forces act on an object. The first is a horizontal 50 N force. The second is a 40 N force acting at an angle to the horizontal. Use a graphical method drawn to a scale of 1 mm : 1 N to find the resultant if the 40 N force is inclined at: 1.1.1 30° to the horizontal 1.1.2 60° to the horizontal.
1.1.1: The force, which is 61.4 N and inclined at a 34.4° angle to the horizontal,
1.1.2: The resultant force is 30.8° inclined to the horizontal and is 66.9 N in magnitude.
How does vector addition work?
The process of adding vectors together to determine the resulting force is known as vector addition.
Vector addition is the theory that was applied in this question
The steps involved in adding vectors are as follows:
First, use the two provided vectors and the resulting vector to scale up a vector diagram.
Step 2: Apply the Pythagorean theorem to determine the magnitude of each vector.
Calculate each vector's angle with respect to the horizontal in step three.
4th step: Apply the Use the law of cosines to find the magnitude of the resultant vector
Step 5: Use the law of sines to find the angle of the resultant vector with respect to the horizontal.
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An object starts from rest and accelerates uniformly in a straight line in the positive x direction.
After 11 seconds, its speed is 70.0 m/s.
a. Determine the acceleration of the object.
b. How far does the object travel during the first 11 seconds?
c. What is the average velocity of the object during the first 11 seconds?
d. The object continues to accelerate with the acceleration computed in 1.a. for another 5 seconds. Determine the final velocity at this time.
e. What was the objects displacement at this time?
a. The acceleration of the object is calculated to be 6.36 m/s².
b. During the first 11 seconds, the object travels 385 m.
c. The average velocity of the object during the first 11 seconds is 70 m/s.
d. The final velocity is 31.8 m/s.
e. The object's displacement at this time is 79.5 m.
Speed of the object = 70 m/s
Time = 11 sec
The acceleration of the object is described to be the rate of change of speed.
So, acceleration = 70/11= 6.36 m/s²
From the equations of motion, we know, s = ut + 1/2 a t²
As, u = 0 here, s = 1/2 a t²
s = 1/2 (70/11) 11² = 385 m
The following formula is used to determine the object's initial displacement,
s₀ = ut
s₀ = 0
After the first 11 seconds, the object's displacement is determined as follows,
s₁ = v t
s₁ = 70 × 11 = 770 m
The object's average velocity is computed as follows:
v = (s₁ - s₀)/t = (770-0)/11 = 70 m/s
Hence, the average velocity of the object is 70 m/s.
Relation between initial, final velocity, acceleration is
v = u + a t
v = 0 + 6.36 × 5 = 31.8 m/s
To find displacement, let us use the equation, v² - u² = 2 a s
Making s as subject, we have, s = (v² - u²)/2 a = (31.8² - 0)/(2 × 6.36) = 79.5 m
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