The mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
The given parameters:
Initial mass of the cylinder, m₁ = 1.0 kgFinal mass of the cylinder, m₂ = 3.0 kgThe gravitational potential energy of an object is calculated as follows;
P.E = mgh
where;
m is the mass
g is acceleration due to gravity
h is the height of the cylinder
when the mass = 1 kg
P.E = 1 x g x h
P.E = gh
when the mass = 3 kg
P.E = 3 x gh
P.E = 3gh
Thus, when the mass of the cylinder increased by a factor of 3, the gravitational potential energy increases by a factor of 3.
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How does the temp of water change when it is heated on a stove top and it begins to boil.
Answer:
The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given
Explanation:
The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?
The rabbits change of momentum is
A. 31 kg•m/s east
B. 31 kg•m/s west
C. 15.5 kg•m/s, west
D. 15.5 kg•m/s, east
This value can also be referred to as
E. Collisions
F. Potential energy
G. Kinetic energy
H. Impulse
Please help will mark brainliest
Hi there!
Recall that:
Change in momentum = mass × change in velocity
Or:
Δp = mΔv = m(vf - vi)
Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).
Thus:
Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.
The correct answer is B.
Change in momentum is EQUIVALENT to the quantity of IMPULSE.
The correct answer is H.
The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the
wavelength? If the frequency is 200. Hz, what is the speed of the wave?
Answer:
Answer:
Speed of the wave in the string will be 3.2 m/sec
Explanation:
We have given frequency in the string fixed at both ends is 80 Hz
Distance between adjacent antipodes is 20 cm
We know that distance between two adjacent anti nodes is equal to half of the wavelength
So \frac{\lambda }{2}=20cm
2
λ
=20cm
\lambda =40cmλ=40cm
We have to find the speed of the wave in the string
Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec
So speed of the wave in the string will be 3.2 m/sec
What is the surface temperature of Sirius B in Kelvins?
Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).
Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).
That would be 9,940 kelvins (K)
Hope it helps! :D
Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s
Answer:
The car that is hald as massive
Explanation:
We can use the eqation for kinetic energy to solve this problem
KE = 1/2mv^2 (where m is mass and v is velocity/speed)
Lets give the original car a mass of 100kg and use the equation
KE = 1/2(100kg)(16m/s)^2 = 12800J
and now lets find kinetic energy of the half as massive car
KE2 = 1/2(50kg)(32m/s)^2 = 25600J
From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity
astronomers have determined the surface temperature of stars by studying their colors. what color emission represents stars with the hottest temperatures?
Answer:
Blue
Explanation:
Did the question already
An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of
the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is
just rolling along, not receiving any additional force to regulate its speed.)
Answer:
Explanation:
that`s a the train car, that you asked the meaning, of that if the train car rolls it`s doing it`s speed, and it`s not ganna fall off the the trail of the train, car.An open train car rolls along a track while it is being filled with sand. There is negligible friction. The speed of the train car will be slowed down.
What is friction?Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor.
Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.
Speed indicates the rate of movement of something or someone. If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.
Therefore, an open railway car is packed with sand and is rolling along a track. Very little friction exists. The railway car's speed will be slowed down.
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Explain briefly about viscous force
The viscous force refers to the resistance of a fluid to flow. It is measured in Newton-second per square meter.
The viscous force can be defined as the resistance that a fluid has to flow in a given space. Viscous force is proportional to the fluid velocity, while this constant is called viscosity.The viscous force can be measured in Newton-second per square meter (abbreviated as N s/m2).Learn more about viscous force here:
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pls answer this question is due today
=============================================
Explanation:
To compute the speed, we divide the distance traveled over the time duration.
For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.
-----------------
For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)
speed = distance/time = (30 km)/(2 hrs) = 15 km/hr
-----------------
We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.
You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.
-----------------
For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)
So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr
The steeper slope of section C, compared to section A, means the car is going faster.
-----------------
Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km
(60 km)/(1.5 hrs) = 40 km/hr
The speed of the car during section D is 40 km per hour.
Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.
what is the capacitance of capacitor
Answer:
The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .
Explanation:
A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the capacitance of the device.
It can be calculated using the formula C = Q/V,
where Q is the electric charge stored on the capacitor in coulombs (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The capacitor's physical properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.
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Why would poor clusters of galaxies be more likely to have irregular shapes then rich
clusters
These Milky Way companion galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small Magellanic clouds (left and right, respectively).
What clusters of galaxies likely to have irregular shapes?In comparison to a rich cluster, the poor cluster typically has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large Magellanic clouds are the two most well-known examples of atypical galaxies.
When two galaxies collide, irregular galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the centre of a massive spiral galaxy.
Therefore, Rich clusters are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its members strongly because of its low bulk.
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Using a balance, determine the mass of the ball and basket of the ballistic pendulum. Fire the ballistic pendulum
and measure the maximum height the pendulum reaches. Use the conservation of energy (initial KE + initial GPE =
final KE + final GPE; KE = 12mv2; GPE = mgh) to calculate the initial speed of the pendulum after the ball has
collided with the pendulum basket. Next, use the conservation of momentum (total initial p = total final p; p = mv)
to determine the initial speed of the ball before it collided with the pendulum basket.
=
=
The conservation of energy and moment allows to find the results for the velocity of the pendulum and the bullet in the system are:
The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m The speed of the bullet, depending on the mass are:m (kg) v (m / s)
0.05 41.58
0.10 21.78
0.15 15.18
0.20 11.88
0.25 9.90
The conservation of mechanical energy is one of the most important principles of physics, it establishes that if there is no friction force, the energy is constant at all points. Mechanical energy is the sum of the kinetic energy plus the potential energies.
In the attachment we can see a diagram of the system, let's start by finding the speed of the pendulum when it leaves, for this we use the conservation of energy.
Starting point. In the lowest part of the movement.
Em₀ = K = ½ (m + M) v₀²
Final point. At the top of the movement.
Em_f = U = (m + M) g y
Energy is conserved because there is no friction.
Em₀ = Em_f
½ (m + M) v₀² = (m + M) g y
[tex]v_o = \sqrt{2gy}[/tex]
They indicate a table with several measurements of the masses and the period, let's use the relationship of the simple harmonic motion.
y = y₀ cos wt
The period and the angular velocity are related.
w = 2π / T
we substitute
y = y₀ cos ( [tex]2 \pi \frac{t}{T}[/tex] )
Let's analyze how long it takes to reach the point of maximum height, the period is the time of a complete oscillation, therefore from the lowest point to the highest point we have ¼ of oscillation, consequently the time to the highest point.
t = T / 4
y = y₀ cos ( [tex]2 \pi 4[/tex])
y = y₀
Therefore the point of maximum amplitude coincides with the maximum height and must be average by the student, suppose that the height is
y₀ = 20 cm = 0.20 m
Let's calculate the initial velocity.
v₀ = [tex]\sqrt{2 \ 9.8 \ 0.20 }[/tex]
v₀ = 1.98 m / s
They ask for the speed of the bullet before striking the basket of mass
M = 1 Kg.
The conservation of the momentum that for an isolated system the momentum is constant in all the instants. Let's form the system by the bullet and the basket.
Initial instant. Before the crash
p₀ = m v
Final moment. Right after the crash.
P_f = (m + M) v₀
The momentum is conserved because the system is isolated.
p₀ = p_f
m v = (m + M) v₀
v = m + M / m v₀
they have tabulated various mass for the bullet, we calculate the speed of each bullet.
m = 0.05 kg
v = [tex]\frac{0.05+1}{0.05} \ 1.98[/tex]
v = 41.58 m / s
m = 0.10 kg
v = [tex]\frac{0.10+1}{0.10} \ 1.98[/tex]
v = 21.78 m / s
m = 0.15 kg
v = [tex]\frac{0.15+1}{0.15y}[/tex]
v = 15.18 m / s
m = 0.20 kg
v = 11.88 m / s
m = 0.25 kg
v = 9.9 m / s
In conclusion with the conservation of energy and the momentum we can find the results for the speed of the pendulum and the bullet in the system are:
The velocity of the pendulum (bullet + basket) is: v₀ = 1.98 m The speed of the bullet, depending on the mass are:m (kg) v (m / s)
0.05 41.58
0.10 21.78
0.15 15.18
0.20 11.88
0.25 9.90
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An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?
Answer:
I = 250N*s
Explanation:
I = F*t
I = impulse or momentum
F = Force
t = time
I = 25N*10s
I = 250N*s
Which of the following is the goal of physical fitness test? *
a. to determine the level of fitness.
b. to identify the area of development/improvement.
c. all of the above
d. to identify strengths and weaknesses.
Answer
C
hope this helps!!
*please mark brainliest if correct!! Trying to level up!!
Determine the percent composition of chromium (III) flouride CrF3
(Show your solution)
Answer:
Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol
51.9961+18.9984032·3
Mass percentage of the elements in the composition
Element Symbol Atomic Mass Number of Atoms Mass Percent
Chromium Cr 51.9961 1 47.707%
Fluorum F 18.9984032 3 52.294%
Notes on using the Molar Mass Calculator
Chemical formulas are case-sensitive.
Enter subscripts as simple numbers.
The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.
Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.
Explanation:
please mark my answer in brainlist plz
23 and 24 only please help!
Answer:
23: Acceleration 24:1m/s^2
Explanation:
[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]
Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks.
Answer:
2:3
Explanation:
mathqway
A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration
The acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
We know that acceleration is the change in velocity divided by the change in time. In this case, the bicycle is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.
We can use the following equation to find the acceleration:
a = (v2 - v1) / t
where:
a is the acceleration
v2 is the final velocity (6 m/s)
v1 is the initial velocity (0 m/s)
t is the time
Plugging in the values from the problem, we get:
a = (6 m/s - 0 m/s) / 50 s
= 0.12 m/[tex]s^{2}[/tex].
Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].
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Which statement best explains why a wet saw used to cut through a fine optical crystals is constantly lubricated with oil
The major reason why a wet saw that is used in cutting optical crystals is constantly lubricated with oil is largely due to friction, lubrication decreases friction and minimises the increase of internal energy.
Friction is basically the coming together of two parts that rubs against each other, it causes heat and lead to deterioration of surfaces, it can also lead to wear and tear.
Although, despite it down side, friction is desire-able in most applications
e.g the brake system of vehicles, and if not for friction, we humans cannot walk without falling
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1) A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of
the light as the cart moves with constant velocity?
How do I solve this?
Option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
At constant velocity, the change in displacement with time is uniform. The displacement of the given object in motion increases at equal rate.
At constant velocity, the initial velocity is equal to the final velocity.
v₁ = v₂
The acceleration of the object at constant velocity is zero, because the change in velocity with time will be zero.
[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]
Thus, from the given options we can conclude that option C with uniform displacement at each time interval represents the photograph of light as the cart moves with constant velocity.
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Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.
Which part of the statement is not true?
Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.
Primary clarifiers removing biological nutrients is not true. Primary clarifiers
involves the use of processes such as sedimentation in order to remove
particles floating or other inorganic solids from the waste water.
Biological nutrients such as nitrogen and phosphorus are found in waste
water and removal of these important nutrients for other uses is a part of
waste water management.
The secondary clarifiers are the ones responsible for the removal of
biological nutrients in the waste water through biofiltration etc.
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The diagram shows a nephron.
A nephron. W points to branch of renal artery. X points to branch of renal vein. Y points to tubular point of nephron. Z points to collecting duct.
Where is the blood first filtered?
Answer:
w
Explanation:
renal artery...the blood flow into the kidney via this blood vassles
and the filtration take place is called ultrafiltration
A machine does 2500 J of work in 1 min. What is the power developed by the machine?
Answer:
41.7 watts
Explanation:
power=work done/time
2500/60seconds
=41.6666
NEES HELP!!!!
Which of the following is "NOT" a theory of the formation of the universe?
A. Steady State Theory
B. Doppler Theory
C. Oscillating Theory
D. Big Bang Theory
Answer:
Doppler Theory
Explanation:
it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.
Solve the science problem
Answer:
ybuTouch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.
which distance indicator can be used to measure the most distant objects?
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
In the field of Astronomy, there are different kind of distance indicators that can be used to measure the distance objects.
Few among them are :
Cepheids Type Ia supernovae Parallax Main-sequence fittingCepheid variables can be measured up to 18 million light years.
The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the Type Ia supernovae
Parallax means illusory state of an object when viewed from different points
Main sequence fitting makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.
The distance indicator can be used to measure the most distant objects among all indicators stated above is Type Ia supernovae
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For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?
Answer:2 reactants 2 products.
this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow
Explanation: i think this answer will help you very much
if you immerse an object into a known mass of water, the measured mass of the water will _____, and will be equal to the mass of the water displaced by the immersed object.
Answer: decrease
Explanation: it does
Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.
I already know...
[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]
But I don't understand what steps I have to take to solve that equation
From Newton's law of gravity, the force of gravity is 245 Newtons
To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters
Mass m = 25 kg
Mass of the earth M = 5.97x10^24kg
Radius r = 6.38x10^6m
Force F = ?
The formula to calculate the force of gravity is
F = (GMm)/[tex]r^{2}[/tex]
Where G = 6.67 x [tex]10^{-11}[/tex]
Substitute all the parameters
F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2
F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]
F = 244.56 N
F = 245 Newtons (approximately)
Therefore, the force of gravity is 245 Newtons
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Two billiard balls having the same mass and speed roll directly toward each other. What is their combined momentum after they meet
Their combined momentum after they meet is 0.
What is law of conservation of momentum?According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
Let the mass of each billiard balls = m.
If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.
Hence, initial momentum of the first ball is: P₁ = mu
initial momentum of the second ball is: P₂ = -mu
Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.
So, according to law of conservation of momentum:
Their combined momentum after they meet is = 0.
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The combined momentum of the two billiard balls after they meet is zero.
When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.
Let us denote the speed of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.
[tex]\rm p_1= -p_2[/tex]
When the balls collide, their momentum increases:
Total momentum after the collision= [tex]\rm p_1+ p_2[/tex]
Substituting the relationship
[tex]\rm p_1= -p_2[/tex]
Total momentum after the collision
[tex]\rm p_1- p_1= 0[/tex]
Therefore, the combined momentum of the two billiard balls after they meet is zero.
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