Which angle (A,B, or C) is the diffraction angle?
B because it’s closest to the center line

Answer:

D

Explanation:

If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)

Average force F = 97.52 N acting on window surface.

Pressure on the window: P = 84.39 N/m²

Average force F:

F = mg sinФ

Put the values:

F = 0.05*9.81* sin 67°

F = 0.45 N

Number of hailstones = 216

Average force F = 0.45* 216 = 97.52 N

Pressure on the window:

Pressure = Average force / area

P = 97.52 / 1.156

P = 84.39 N/m²

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Warm, moist air rises because of the disparity in density between warm, moist air and cold air. This is crucial for clouds to develop.

Puffy cumulus clouds can form in the atmosphere as warm, humid air rises in an updraft. As it rises, the moisture in the air condenses into water droplets. As long as warm air rising from below persists, the cloud will expand.

The air in the lightning channel may reach temperatures of 50,000 degrees Fahrenheit, which is five times hotter than the surface of the sun. After the flash, the air swiftly cools and contracts.

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When she let go of the rope, her height above the water would be  3.20 meters.

We can use the equations of motion to solve this problem. Let's assume that the girl's initial height above the water is h, and that the acceleration due to gravity is -9.81 m/s^2 (negative because it is directed downward). Then we have:

Initial horizontal velocity (vx) = 2.25 cos(35º) = 1.84 m/s

Initial vertical velocity (vy) = 2.25 sin(35º) = 1.30 m/s

During the 1.20 s of flight, the girl's vertical motion can be described by the following equation:

h + vy*t + (1/2)gt^2 = 0

where t is the time of flight and g is the acceleration due to gravity. Substituting the known values, we get:

h + (1.30 m/s)(1.20 s) + (1/2)(-9.81 m/s^2)*(1.20 s)^2 = 0

Simplifying and solving for h, we get:

h = -1/2*(-9.81 m/s^2)(1.20 s)^2 - (1.30 m/s)(1.20 s) = 3.20 m

Therefore, the girl was 3.20 meters above the water when she let go of the rope.

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To check your answers, we can use the following equations:

(a) Thrust = (mass flow rate of exhaust gas) * (exhaust velocity of gas) + (initial mass of rocket) * (acceleration due to gravity)

(b) Time to exhaust fuel = (0.8 * initial mass of rocket) / (mass flow rate of exhaust gas)

(c) Final velocity of rocket = (exhaust velocity of gas) * ln(initial mass of rocket / final mass of rocket)

Using the given values:

Mass flow rate of exhaust gas = 200 kg/s

Exhaust velocity of gas = 1.80 km/s = 1800 m/s

Initial mass of rocket = 20,000 kg

Acceleration due to gravity = 9.81 m/s^2

Final mass of rocket = 0.2 * initial mass of rocket = 4,000 kg

(a) Thrust = (200 kg/s) * (1800 m/s) + (20,000 kg) * (9.81 m/s^2) = 360,000 N

Your answer for part (a) is correct.

(b) Time to exhaust fuel = (0.8 * 20,000 kg) / (200 kg/s) = 800 s = 20 minutes

Your answer for part (b) is incorrect. The correct answer is 800 seconds or 20 minutes, not 20 seconds.

(c) Final velocity of rocket = (1800 m/s) * ln(20,000 kg / 4,000 kg) = 205.66 m/s

Your answer for part (c) is correct.

Answer: In order of most inertia to least.

car stopped

motorcycle driving

dog laying

large hot coffee

small mouse

Explanation:

Honestly, I'm not 100% sure about this, but inertia is the want to remain the way it currently is, So the larger the object, the more inertia it should have. So I basically arranged the things by size, I think the moving and not is a red herring to throw you off. Also given that the dog laying in the middle option makes sense because a dog would be in the middle of the size options.

The clay ball that could stick to the door would be more effective when you want to shut the door from a distance be throwing a n object.

The effective way to shut the door could be through the use of the clay ball that could stick to the door and push it to the place where it could jam rather than the rubber ball that would bound back.

The best way to shut a door is to use the door handle or knob to pull the door towards you and guide it into the door frame until it clicks shut.

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The force (in N) she must exert if her deceleration is 7.00 times the acceleration of gravity is 245 N

Given data

Force = Mass x Acceleration

Force = 35.0 kg x (7.00 x 9.81 m/s2)

Force = 245 N

The force required for the 35.0 kg gymnast to decelerate after a somersault is 245 N. This force is calculated by multiplying the mass of the gymnast by the deceleration of 7.00 times the acceleration of gravity.

The amount of force is necessary to slow down the gymnast and reduce the impact of the landing. Without this force, the gymnast could be injured from the sudden stop.

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Answer:

Explanation:

overgeneralization or applying a single solution to a variety of problems without considering their unique characteristics. This is a common issue in math and other problem-solving situations where individuals may rely too heavily on past successful solutions without adjusting for the specific details of each new problem.

The effort needed to lift the load of 300 N, given that the velocity ratio is 6 and the machine has an efficiency of 80% is  62.5 N

First, we shall determine the mechanical advantage of the machine. Details below:

Efficiency = MA / VR

80% = MA / 6

Cross multiply

MA = 80% × 6

MA = 4.8

Finally, we shall determine the effort of the machine. Details below:

Mechanical advantage (MA) = Load (L) / Effort (E)

4.8 = 300 / Effort

Cross multiply

4.8 × Effort = 300

Divide both sides by 4.8

Efoort = 300 / 4.8

Effort = 62.5 N

Thus, we can conclude that the effort of the machine is 62.5 N

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Answer:

2.34

Explanation:

To find the position where the speed is half of its maximum speed, we can set v = v_max/2 and solve for x:

v_max/2 = ω√(A^2 - x^2)

Substituting the given values, we have:

(ωA)/2 = ω√(A^2 - x^2)

Simplifying and rearranging:

A^2 - x^2 = (A/2)^2

x^2 = A^2 - (A/2)^2

x^2 = (3.00 cm)^2 - (1.50 cm)^2

x = √(6.75 cm^2 - 2.25 cm^2)

x = √5.50 cm^2

x ≈ 2.34 cm

Therefore, the position where the speed of the particle is half of its maximum speed is approximately 2.34 cm from the equilibrium position.

The reflected sound wavefronts at the given boundary are waves that have bounced off a surface and changed direction.

The reflected sound wavefront is shown in the attachment.

A reflected wavefront is a wavefront that has bounced off a surface and changed direction. When a wave, such as a light wave or sound wave, encounters a surface, some of the wave energy is reflected back in the opposite direction.

An example of reflected sound wavefronts in water can be seen in underwater sonar imaging.

In sonar imaging, a sound wave is emitted from a source and travels through the water. When the sound wave encounters an object, some of the wave energy is reflected back toward the source.

Reflected wavefronts play an important role in many areas of science and engineering, such as optics, acoustics, and electromagnetism. They are used to model the behavior of waves in complex systems and to design and optimize devices such as mirrors, lenses, and antennas.

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The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.

We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.

The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.

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The distance between the train cars will decrease, as stronger magnets will create a greater attractive force between them. This will cause the cars to be pulled closer together.

The strength of a magnet depends on the type of magnet and the material it is made from. Generally, the strongest magnets are neodymium magnets, also known as rare earth magnets. These are made from a combination of neodymium, iron, and boron and can produce magnetic fields up to 1.4 teslas, or 14,000 gauss. Samarium cobalt magnets are also powerful, producing fields up to 1.4 teslas. Other types of magnets, such as ceramic and Alnico magnets, generally produce magnetic fields of around 0.5 teslas or 5,000 gauss.

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We can see from the table that we have in the question that  Wave W has a faster speed.

Wavelength and frequency are two fundamental properties of waves, including electromagnetic waves and sound waves. The relationship between wavelength and frequency can be described by the following equation:

c = λν

where c is the speed of light (or speed of sound), λ is the wavelength, and ν is the frequency.

According to this equation, the wavelength and frequency are inversely proportional to each other.

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Answer: a) 123.1m

b) 279.1m

Explanation:

The maximum height reached by the rocket is 0 meters. The rocket's greatest horizontal range beyond point A is also 0 meters.

To find the maximum height, we can use the kinematic equation for vertical motion. The rocket starts from rest, so its initial vertical velocity is 0 m/s. We can use the equation:

[tex]h = vi^2 / (2 * g)[/tex]

where h is the maximum height, vi is the initial vertical velocity, and g is the acceleration due to gravity. We can calculate h by substituting the given values:

h = (0 m/s)2 / (2 * 9.8 m/s2)

= 0 m

Therefore, the maximum height reached by the rocket is 0 meters above the ground.

To find the rocket's greatest horizontal range, we can use the horizontal motion equations. Since the rocket is subject to gravity only after leaving the incline, we need to find the time it takes for the rocket to reach the highest point on the incline. We can use the equation:

t = vf / a

where t is the time, vf is the final velocity, and a is the acceleration. We can calculate t by substituting the given values:

t = 3.50/ 3.50

= 1s

Now we can use the equation for horizontal motion to find the horizontal range:

[tex]R = v0 * t[/tex]

where R is the horizontal range and v0 is the initial horizontal velocity. Since the rocket starts from rest, v0 = 0 m/s. Therefore, the rocket's greatest horizontal range beyond point A is 0 meters.

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Answer:

The area of the figure 7 in the area of 6 ft

Answer:

5292.64 m

Explanation:

The total resistance is 3 ohm

The current is 1.5 A

To calculate the total resistance of a circuit, you need to determine the equivalent resistance of all the resistors in the circuit. The equivalent resistance is the single resistance value that could replace all the individual resistors and produce the same overall resistance.

1) This is a parallel circuit thus;

1/RT = 1/6 + 1/6

RT = 3 ohm

2) This is a series circuit thus;

RT = 4 + 6 = 10 ohm

Current = 15V/10 ohm

= 1.5 A

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Answer:

Explanation:The acceleration due to gravity at a distance equal to one full Earth radius above the surface of the Earth is given by:

g' = g/(1 + R/E)^2

Where g is the acceleration due to gravity at the surface of the Earth, R is the radius of the Earth, and E is the distance of the object from the center of the Earth.

Substituting R for E+R, we get:

g' = g/[1 + (E+R)/R]^2

g' = g/[1 + (1+E/R)]^2

g' = g/[1 + (1+1)]^2 (Since E/R is very small compared to 1)

g' = g/16

Therefore, the acceleration due to gravity at a distance equal to one full Earth radius above the surface of the Earth is g/16. Answer: D. g/4.

Answer:

The acceleration of gravity decreases as you move away from the surface of the Earth. The acceleration of gravity at a height of one Earth radius above the surface can be found using the formula:

g' = (R/(R+h))^2 * g

where R is the radius of the Earth, h is the height above the surface, and g is the acceleration due to gravity at the Earth's surface.

If we plug in R = 6,371 km (the radius of the Earth) and h = 6,371 km (one Earth radius above the surface), we get:

g' = ((6,371 km)/(2*6,371 km))^2 * g

g' = (1/2)^2 * g

g' = g/4

Therefore, the answer is D. g/4.

Answer:


The power output of the engine can be calculated using the formula:

Power = Force x Velocity

where force is the net force acting on the car, and velocity is the speed of the car. In this case, the net force is equal to the force exerted by the engine, which is 1,775.0 N, since the car is moving at a constant speed and there is no acceleration. The velocity of the car is 13.0 m/s. Thus, the power output of the engine can be calculated as:

Power = 1,775.0 N x 13.0 m/s = 23,075 W

Therefore, the power output of the engine is 23,075 watts.

Answer:

After the head-on collision, both identical billiard balls will bounce back at the same speed they had before the collision. This is because of the conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls are a closed system, and their total momentum before the collision is equal and opposite to their total momentum after the collision. Therefore, they will both bounce back with the same speed they had before the collision.

Explanation:

Answer:

≈ 192.7 m/s

Explanation:

Let's start by finding the velocity of the block just before it hits the ground. We can use the conservation of energy:

Conservation of energy tells us that these two energies are equal:

mgh = (1/2)mv^2

Solving for v, we get:

v = sqrt(2gh)

Plugging in the given values, we get:

v = sqrt(2 * 9.8 m/s^2 * 1.9 m) = 6.06 m/s

Now, let's use conservation of momentum to find the initial speed of the bullet. We know that the total momentum of the system (bullet + block) is conserved before and after the collision. Before the collision, the momentum is:

p = mb * vb

where mb is the mass of the block and vb is its initial velocity, which is 0 since it is at rest.

After the collision, the bullet and block move together with a common velocity v. The total momentum is:

p = (mb + m) * v

where m is the mass of the bullet. Since momentum is conserved:

mb * vb = (mb + m) * v

Solving for vb, we get:

vb = (mb + m) * v / mb

Plugging in the given values, we get:

vb = (345 g + 7 g) / 7 g * 6.06 m/s = 192.7 m/s

Therefore, the initial speed of the bullet was approximately 192.7 m/s.

From the given circuit, the value of I1 = -4 Amp, V1 = -4 V, and the V2 = 4V. Ohm's law has three different variations that are related to voltage, current, and resistance. The relationship between the voltage across the terminals and the resistor's resistance determines the current for a constant flow of current.

According to Ohm's law, the voltage across a conductor determines how much current flows through it. For many materials, including metals, this is true so long as the temperature (as well as other physical parameters) stay constant.

Any electrical network may be solved using nodal analysis, which is what it is called. the formula used to determine how much voltage is shared across circuit nodes. Since the node voltages are with respect to the ground, this method is also referred to as the node-voltage method.

Applying KCL,

I1 = -1 -3

I1 = -4 A

Applying concept of super-node,

V2 = 4V

[tex]\frac{4-V1}{2} -1-3=0[/tex]

[tex]2-\frac{V1}{2} =4[/tex]

[tex]\frac{-V1}{2} =4-2[/tex]

[tex]V1=-4V[/tex]

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Answer: Diffraction

Explanation: It is diffraction, because due to diffraction, sound waves bend on the corner as their size is of the order of wavelength of sound waves.

Answer:

-3525.000 m/s

Explanation:

In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.

The initial momentum of the system is:

p_initial = m1 * v1 + m2 * v2

= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)

= -282.000 kg·m/s

Here, we convert the masses to kilograms to match the units of velocity.

Since the particles stick together after the collision, their masses add up:

m_final = m1 + m2

= 12.000 mg + 68.000 mg

= 80.000 mg

= 0.080 g

Now, we can use the conservation of momentum to find the final velocity:

p_final = m_final * v_final

where p_final = p_initial and m_final = 0.080 g.

Therefore:

v_final = p_final / m_final

= -282.000 kg·m/s / 0.080 g

= -3525.000 m/s

Answer:

a

Explanation:

a push or a pull that occurs when an object interacts with another object or field.

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The potential energy of the shot as it left the hand relative to the ground would be -524 J.

At the moment the shot putter releases the shot, the total energy of the system is:

E = KE + PE

where KE is the kinetic energy of the shot and PE is its potential energy relative to the ground. We can assume that the kinetic energy is entirely due to the motion of the shot in the horizontal direction, so we can write:

KE = (1/2)mv^2

where m is the mass of the shot, and v is its horizontal velocity. Substituting the known values, we get:

KE = (1/2)(5.00 kg)(15.0 m/s)^2 = 1125 J

At the maximum height of 14.5 m, the shot has zero kinetic energy, so all its energy is potential energy:

PE = mgh

where g is the acceleration due to gravity and h is the height above the ground. Substituting the known values, we get:

PE = (5.00 kg)(9.81 m/s^2)(14.5 m - 3.00 m) = 601 J

Therefore, the potential energy of the shot as it left the hand relative to the ground was:

PE = E - KE = 601 J - 1125 J = -524 J

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