Which expression represents the correct form for the quotient and remainder, written as partial fractions, of StartFraction 7 x squared minus 40 x + 52 Over x squared minus 6 x + 9 EndFraction?

Answer:

give me 2 minutes and I will

The solutions to the equation [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex] are 3 and -5.

To solve any equation is to find the solution of the given equation which satisfied the equation.

The given expression is [tex]\rm (x + 2)^{2} - 2(x + 2) - 15 = 0[/tex]

let u = (x +2)

then the equation becomes

[tex]\rm u^{2} - 2u - 15 = 0[/tex]

by factorizing, we get

(u + 3)(u - 5) = 0

u + 3 = 0, u = -3

u - 5 = 0, u = 5

Since, u = x + 2

So, x + 2 = 5, x = 3

x + 2 = -3, x = -5

Therefore, the solutions to the equation are 3 and -5.

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On factoring, the value of t is 1. This shows that the car will land on the ground after 1 sec.

Quadratic functions are functions having a leading degree of 2.

Given the function height in feet of the car after t seconds expressed as

h = -16t^2 +10t +6

The height of the car on the ground is zero, hence:

16t^2 -10t -6 = 0

8t^2 - 5t - 3 = 0

Factorize the quadratic function

8t^2 - 5t - 3 = 0

On factoring, the value of t is 1. This shows that the car will land on the ground after 1 sec.

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The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).

The given expression is: [tex]2x^{2} +3x-54[/tex]

A factor is a number that divides another number leaving no remainder.

We can rewrite the given expression as:

[tex]2x^{2} +12x-9x-54[/tex] (middle term has been splitted)

Take 2 as common from first two terms while take -9 as common from last two terms.

[tex]2x(x+6)-9(x+6)[/tex]

Take (x+6) as common

[tex](x+6) (2x-9)[/tex]

So, we got the factors (x+6) and (2x-9)

Therefore, The factors of expression [tex]2x^{2} +3x-54[/tex] are (x+6) and (2x-9).

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Answer:

6

Step-by-step explanation:

2 x 3

48 /   -8 = -6

-40 /  8 = -5

12  -  (-2) = 14

18 -  (-12) = 6

18 -  (-20) = -2

22  x  (-0.5) = 11

[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]

Let's use distance formula ~

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(x2 - x1) {}^{2} + (y2 - y1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(2 - ( - 4)) {}^{2} + (0 - 1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{(2 + 4) {}^{2} + ( - 1) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{ {}^{} 36+ 1{}^{} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: d = \sqrt{ {}^{} 37{}^{} } [/tex]

Therefore, the required distance is [tex]\sf \sqrt{37}[/tex] units

Check the picture below.

Answer:

11. b

10.d

9.c

7.b

1.d

the rest I can't see clearly

please give brainiest

Step-by-step explanation:

11.

3/x-4=7/x

*cross multiply

3x=7 (x-4)

3x=7x-28

28=7x-3x

28=4x

x=7

10.

SOHCAHTOA

Cos☆=11/14

cos^-1 (11/14)

☆=38.21 degrees

9.

MLN CONGRUENT TO WBN

ML/WB=LN/BN=MN/WN

LN/BN=10/6

ML/WB

24/x=10/6

24x6=10x

144÷10

=14.4

6^2+14.4^2

=243.36

squareroot

=15.6

John paid $75 for a pair of shoe that cost $100 at a discount of 25 percent.

An equation is an expression that shows the relationship between two or more numbers and variables.

Let us assume that the shoe cost $100, he spins the spinner and gets a discount of 25%, hence:

Money paid = 100 - 25% of 100

Money paid = 100 - 25 = $75

John paid $75 for a pair of shoe that cost $100 at a discount of 25 percent.

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Answer: 10.62 irrational

Step-by-step explanation: You can divide 69.15 by 5.25 which equals 74.4 then divide by 7 which equals 10.62

Answer:

B = (5, 1).

Step-by-step explanation:

From the formula for the midpoint of  a line :-

(-1 + x)/2 , (5 + y)/2 = (6/2, 6/2)    where x and y are the coordinates of B.

so (-1 + x)/2 = 6/2

-1 + x = 6

x = 5.

and (5 + y)/2 = 6/2

5 +  y = 6

y =  1.

Answer: 42.0

Step-by-step explanation:

Answer:

Step-by-step explanation:

slope is -3/1

Slope is Rise/Run

meaning 3 down and 1 right

so in this case the down means the Y-axis

and the right means the x-axis

so lets put out some points.

(2,-1)

Then 1 right and down 3

(3, -4)

(4,-7)

and soo on, but we want to fin the point where x is zero.

Why?

Because that is where the y-Intercept is at.

Slope Intercept form is y=mx+b

Where m is the slope

And b is the y- Intercept

Soooo

Let's work backwards

Instead of Right 1 and Down 3 lets do

Left 1 and Up 3

And we will be starting with our original point

(2,-1)

then left 1, Up 3

2-1=1

-1+3=2

soo...

(1,2)

then again

(0,5)

That is our Y-intercept.

Now lets put all of it together.

Y=Mx+B

M=Slope

B=Y-Intercept

Y=-3x+5

You're welcome...

SonicIsCoool, if you need more help im at your service.

Answer:

23, 25, 27, 29

Step-by-step explanation:

14*2 = 28, 28-5=23

15*2=30, 30-5=25

16*2=32, 32-4=27

17*2=34, 34-5=29

[tex]14 \times 2 - 5[/tex]

[tex]28 - 5[/tex]

[tex]23[/tex]

[tex]15 \times 2 - 5[/tex]

[tex]30 - 5[/tex]

[tex]25[/tex]

[tex]16 \times 2 - 5[/tex]

[tex]32 - 5[/tex]

[tex]27[/tex]

[tex]17 \times 2 - 5[/tex]

[tex]34 - 5[/tex]

[tex]29[/tex]

Answer:

12×8/2=48

10×10=100

2(48)+3(100)

96+300= 396ft²

Answer:

2 students do Chemistry, but not Mathematics

Step-by-step explanation:

2 students do Chemistry, but not Mathematics

*View attached table*

Hope this helps!

Answer:

45n+12mm

Step-by-step explanation:

I hope this is right if it is right pls mark me as brainliest and learn well

the value of a and b will be 45 and 0 for the given expression.

the property of having suitable proportions in terms of size, number, degree, harshness, etc.: If a defensive action against an unfair attack results in the destruction that contravenes the proportionality criterion, it may even go far beyond a justifiable defense.

Given, the shapes are a circle with a radius of 21mm and a quarter circle of 6mm.

Since Radius = 21 cm

the radius of the circle/ radius of the quarter circle = 7/2

Total length = Sum of the circumference of both the circle

Since the formula for the circumference of a circle:

C = 2 * pi * radius

Total length = 2* pi* r + 1/4 * (2 * pi * r')

Total length = 2 *pi * 21 + pi * 3

Total length = π(42 + 3)

total length = 45π + 0

therefore, the value of a and b will be 45 and 0 for the given expression.

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#SPJ2

Hey there!

"less than" is "<"

y+15<3

Solve it:

y<3-15

y<-12

Hope everything is clear.

Let me know if you have any questions!

Always remember: Knowledge is power!

Answer:

y < -12

Step-by-step explanation:

Edge

The rotation of point G to point H is an illustration of a circular movement

The rotation that maps point G to point H is 72 degrees clockwise

From the figure, we have the following parameters:

Number of sections (n) = 5

Angle at the center = 360

The angle of rotation is then calculated as:

Rotation = 360/5

Evaluate

Rotation = 72

Point H is to the left of point G.

This represents a clockwise direction

Hence, the rotation that maps point G to point H is 72 degrees clockwise

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Answer:

72° clockwise

Step-by-step explanation:

Answer:

[tex] 1 \frac{2}{3}\: liters [/tex]

Step-by-step explanation:

[tex]V_{soda}[/tex] in one bottle = 5/9 liters

No of bottles = 3

Total volume of soda

[tex] = \frac{5}{9} \times 3 \\ \\ = \frac{5}{3} \\ \\ = 1 \frac{2}{3} \: liters[/tex]

Answer:

V(sphere) =

[tex] \frac{4 }{3} \pi \:{r}^{3} = 195.43 \\ [/tex]

V(hemisphere) = V(sphere)/2 = 97.715 = 97.7

Answer:

2

Step-by-step explanation:

3^2 = 9

[tex](x - 3)(2x {}^{2} - 5x + 1)[/tex]

[tex]2x {}^{3} - 5x {}^{2} + x - 6x {}^{2} + 15x - 3 [/tex]

[tex]2x {}^{3} - 11x {}^{2} + 16x - 3[/tex]

Using proportions, it is found that it would take 1 hour for the pedestrian to travel the same distance.

A proportion is a fraction of a total amount.

In this problem, the cyclist takes 25 minutes, while the pedestrian's time is [tex]2\frac{2}{5} = \frac{12}{5}[/tex] slower(greater), hence his time is given by:

[tex]t = \frac{12}{5} \times 25 = 12 \times 5 = 60[/tex]

It would take 1 hour for the pedestrian to travel the same distance.

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Answer:

B. 2 3/4 lbs

Step-by-step explanation:

there ar 16 ticks on a scale, the pointer is on 12, meaning it is 12/16, whihc is answer b

Answer:

its b

Step-by-step explanation:

looked it up

[tex]\mathsf\blue{♧ANSWER♧}[/tex]

[tex] \mathsf \orange{ \frac{x \times y}{2}} [/tex]

[tex] \mathsf \green{ \frac{8 \times 12}{2} }[/tex]

[tex] \mathsf \orange{ \frac{96}{2} }[/tex]

[tex] \mathsf \green{48 \: square \: units}[/tex]

[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]

[tex]\qquad\qquad\qquad \large\underline{ \boxed{ \sf{✰\: Information }}}[/tex]

[tex]{ \boxed{ ✟ \: \underline{ \boxed{ \sf \: Area \: of \: kite = \frac{ d_1 \times d_2}{2} \: or \blue{ \: \frac{1}{2} \times d_1 \times d_2}}}✟ }}[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

[tex] \qquad \rm{➛Area \: of \: kite = \frac{BD×AC}{2} }[/tex]

[tex]\qquad \rm{➛Area \: of \: kite = \frac{8×12}{2} } \\ \qquad \rm{➛Area \: of \: kite = \frac{ \cancel{96}}{ \cancel2} } \\ \qquad \rm{➛Area \: of \: kite = 48 {units}^{2} }[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

★Hence area of kite with diagonals BD = 8 units and AC = 12 units is

[tex]\qquad\qquad\qquad{ \boxed{↪ \underline{ \boxed{ \sf{\: 48 {units}^{2} \green✓ }}}↩}}[/tex]

[tex]\rule{80mm}{2.5pt}[/tex]

★ More info regarding this topic ★

[tex]\rule{80mm}{2.5pt}[/tex]

Hope it helps !