Which is a similar theme in both "The Stag at the Pool" and "Hans in Luck"? O A. The things we think are valuable sometimes turn out not to be valuable after all. 0 B. It is important to know whom we can trust and whom we cannot O C. By working hard, we will end up with possessions that will make us feel successful. 0 D. The best things come in small packages.​

Answers

Answer 1

A similar theme in both "The Stag at the Pool" and "Hans in Luck" is A. The things we think are valuable sometimes turn out not to be valuable after all.

In "The stag at the pool", a thirsty stag went to the pool to drink. As he bent over, he admired his antlers but despised his legs. He saw a lion and ran but his antlers got stuck in a tree and he was caught by the lion.

The theme in "Hans in Luck" shows that one doesn't need possessions to be happy. The character in the story had several possessions but was still unhappy. Both themes showed that the things we think are valuable sometimes turn out not to be valuable after all.

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Related Questions

A spherical ball of lead (density 11.3 g/cm 3) is placed in a tub of mercury (density 13.6 g/cm 3). Which answer best describes the result

Answers

The lead ball will float with about 17% of its volume above the surface of the mercury.

We know that density is defined as mass per unit volume of a substance. The density of a substance is an intrinsic property which can be used to identify a substance.

Given that Lead is less dense that mercury, we know that lead will float on mercury. Since the density of mercury is 13.6 g/cm3 and that of lead is 11.3 g/cm3, lead ball will float with about 17% of its volume above the surface of the mercury.

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Missing parts;

A spherical ball of lead (density 11.3 g/cm3) is placed in a tub of mercury (density 13.6 g/cm3). Which answer best describes the result?

A.The lead ball will float with about 83% of its volume above the surface of the mercury.

B.The lead ball will float with about 17% of its volume above the surface of the mercury.

C.The lead ball will float with its top exactly even with the surface of the mercury.

D.The lead will sink to the bottom of the mercury.

E.none of the above

A 115 kg hockey player, Adam, is skating east when he tackles a stationary 133 kg player, Bob. Afterward, they move at 1.35 m/s east. What was Adam's velocity before the collision? (Unit = m/s) ​

Answers

Answer:

Explanation:

Conservation of momentum

115v + 133(0) = (115 + 133)1.35

v = 2.911304...

v= 2.91 m/s east

Answer:

The velocity east is 2.91

Explanation:

Fill in the box

2.91

please answer this as fast as you can i need it

Answers

Answer:

it says pdf only i dont knowwhat u want me to do

A friend has suggested that you go swimming in a pool having water of temperature 350 K. What would this temperature be on the Fahrenheit scale?

109°F

123°F

170°F

202°F

Answers

This temperature would be 170° F on the Fahrenheit scale. Hence, option (C) is correct.

What is temperature?

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances.

The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes.

the relation between Kelvin scale and Fahrenheit scale is given by:

(F - 32)/180 = (K - 273)/100

F - 32 = (350 - 273)(9/5)

F = 32 + (350 - 273)(9/5)

F = 170

Hence,  this temperature would be 170° F on the Fahrenheit scale.

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Convert :

36°C = ... °F
373 K = ... °C


Question easy​

Answers

Answer:

36 C= 96.8 F

373 K= 99.85

Explanation:

C to F: (36 x 1.8) + 32

         = 64.8 +32

         = 96.8 F

K to C: C= K- 273.15

           C= 373-273.15

           C= 99.85

____

= 36°C

=( 36 × 9/5 ) + 32

=(36 ÷ 5 × 9) + 32

=(7,2 × 9) + 32

= 64,8 + 32

= 96,8°F

______

______

= 373 K

= 373 - 273

= 100°C

[tex] \boxed { \sf semoga \: membantu \: :v }[/tex]

a. How fast should a boy of 40kg mass run so that the kinetic energy becomes 800J?​

Answers

Answer:

[tex]k.e. = \frac{1}{2}mv {}^{2} \\ 800= \frac{1}{2} \times 40 \times v {}^{2} \\ 800 = 20v {}^{2} \\ v {}^{2} = 400 \\ v {}^{2} = 20ms {}^{ - 1} [/tex]

k.e. = kinetic energy

hope helpful <3

How do organisms use communication to survive?


Answers

Answer: Im not entirly sure but I think It's D all the above. I think all but B because I never really heard of that but if you look in our history I think that happen im not sure I would wait untill you know that somone knows for sure.

Explanation:

you are standing ata known distance from the statue of liberty describe how you could determine its height using only a meter stick

Answers

Use the meter stick to measure your height to the level of your eyes, then use trigonometry ratio formula to calculate the height from your eyes' level and above of the statue of liberty with angle of elevation, then, add the two heights.

If you are standing at a known distance from the statue of liberty, a meter stick can be used to measure your known distance away from the statue of liberty.

To determine its height using only a meter stick, the angle at which you look at the peak of statue of liberty must be measured or known. The height of the statue of liberty can be calculated if you know the angle of elevation at which you look at the peak of the statue, and the availability of the meter stick.

Use the meter stick to measure your height to the level of your eyes, then use trigonometry ratio formula to calculate the height from your eyes' level and above of the statue of liberty. That is,

Tan Ф = opposite / adjacent

Tan Ф = H/d

H = d x TanФ

Where

H = calculated height from the eyes level and above

Ф = angle of elevation

d = known distance away from the statue

Let h = Your measured height of your body to the eyes level

Then,

The height of the statue of liberty = H + h

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I need help with this equation. 4 tutors so far on the math side are unable to help me solve the problem. ​

Answers

'I need help with this equation. 4 tutors so far on the math side are unable to help me solve the problem. '
whats the equation

I need your help with this question, it’s my final exam for physics

Answers

Answer:

●Bx=Bcos40

Bx=10 × 0.76

Bx=7.6

●By=Bsin40

By=10×0.64

By=6.4

Hope it will help you.

Which properties make a metal a good material to use for electrial wires

Answers

Answer:

Most importantly metals can pass an electric current without being affected and changed by the electricity. Electrical conductivity combined with ductility makes metals the most suitable materials for electrical transmission wires.

True or False: Any wavelength of light would work for this experiment. Explain your response, including the term quantum or quantized.

Answers

Answer:

I think false I don't know if I right but I hoped this help

An object moving at a constant velocity of 5.4 m/s travels for 12 s. How far will it move during that time?

Free-fall Acceleration is -10 m/s^2

I also need the formula

Answers

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 5.4(12) + ½(0)12²

s = 64.8 m

Question: A NEO distance from the Sun is 1.18 AU. What is its relative speed compared to Earth (round your answer to 3 decimal places)

Answers

Its relative speed compared to Earth is 0.921

The speed of the object v = 2πr/T where r = radius of orbit and T = period of orbit.

Let v = speed of earth, r = radius of earth orbit = 1 AU and T = period of earth orbit.

So, v = 2πr/T

Also, v' = speed of NEO, r' = radius of NEO orbit = distance of NEO from sun = 1.18 AU and T' = period of NEO orbit.

So, v' = 2πr'/T'

v'/v = 2πr'/T' ÷ 2πr/T

v'/v = r'/r × T/T'

From Kepler's law, T² ∝ r³

So, T'²/T² = r'³/r³

(T'/T)² = (r'/r)³

T'/T =  √[(r'/r)]³

T/T' = √[(r'/r)]⁻³

So, substituting this into the equation, we have

v'/v = r'/r × T/T'

v'/v = r'/r × √[(r'/r)]⁻³

v'/v = √[(r'/r)]⁻¹

Since r' = 1.18 AU and r = 1 AU, r'/r = 1.18

So, v'/v = √[(r'/r)]⁻¹

v'/v = √[(1.18)]⁻¹

v'/v = [1.0863]⁻¹

v'/v = 0.921

So, its relative speed compared to Earth is 0.921

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calculate the mass of a block of ice having volume 5m³. (density of ice≈920 kg/m³)​

Answers

Answer:

4600 Kg/m³

Explanation:

Volume of block=5m³

Mass of block= 920 kg/m³

Density=mass × volume

=920 × 5³

=4600 /m³

The density of ice is 4600 Kg/m³

___________________________________

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Explanation:

Solution:

Here

volume=5

Density=920

Density =Mass/Volume

or,Mass=Density*Volume

or,M=920*5

so,M=4600kg

please help me with these four i dont rlly get the question itself tbh. 20 points

Answers

Explanation:

These prefixes are very commonly used in naming chemical compounds.

Di- means two.

For example, carbon dioxide's formula is be written as [tex]\text{CO}_2,[/tex] and it has 2 oxygen atoms, hence "di-oxide."

Tetra - means four.

For example, carbon tetrachloride's chemical formula is written as [tex]\text{CCl}_4[/tex], and there are four chlorine atoms

Deca- means ten

For example, lanthanum decahydride's chemical formula is written as [tex]\text{LaH}_{10}.[/tex] In this case there are 10 hydrogen atoms for every lanthanum atom.

Hepta - means seven

For example, iodine heptafluoride is written as [tex]\text{IF}_7[/tex]. Note the seven fluorine atoms attached to the iodine atom, hence the name "hepta-fluoride."

A 0.60-kgkg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.3 mm on a frictionless horizontal surface. Part A If the cord will break when the tension in it exceeds 60 NN , what is the maximum speed the ball can have

Answers

11.4 m/s

Explanation:

The cord will break when the centripetal force exerted on it meets or exceeds the maximum tension [tex]T_{max}[/tex] that it can handle.

[tex]T_{max} = m\dfrac{v_{max}^2}{r}[/tex]

Solving for [tex]v_{max},[/tex] we get

[tex]v_{max}^2 = \dfrac{rT_{max}}{m}[/tex]

or

[tex]v_{max} = \sqrt{\dfrac{rT_{max}}{m}} =\sqrt{\dfrac{(1.3\:\text{m})(60\:\text{N})}{(0.6\:\text{kg})}}[/tex]

[tex]\:\:\:\:\:= 11.4\:\text{m/s}[/tex]

An object will begin moving from rest when acted upon by which forces?

A. Forces that are slightly less than the force of friction

B. Forces that result in a net force of zero

C. Forces that are equal and act in opposite directions

D. Forces that are greater in one direction than in any other direction

Answers

Answer:

D

Explanation:

Process of elimnination + it's the only one that makes sense

An object will begin moving from rest when acted upon by forces that are greater in one direction than in any other direction. Hence, Option (D) is correct.

What is force?

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

When  forces that are greater in one direction than in any other direction, resultant will be  unbalanced forces.  Unbalanced forces are those acting on a body when the net force acting on the body is greater than zero. The body alters its state of motion when unbalanced forces act on it.

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A 5 kg box is sitting on a rough wooden surface. The coefficient of static friction between the box and surface is 0.6. If the normal force on the box is 50 N, calculate the force of friction which must be overcome to move the box. Round your answer to the nearest whole number.

Answers

The force of friction needed to overcome to move the box is 29.4N

According to Newton's second law;

[tex]\sum F_x = ma_x\\[/tex]

Taking the sum of force along the plane;

[tex]F_m -F_f = ma\\F_m -F_f = 0\\F_m=F_f = \mu R[/tex]

This shows that the moving force is equal to the frictional force

Given that

[tex]\mu = 0.6\\R = mg = 49N[/tex]

Get the frictional force;

Since

[tex]F_f = \mu R\\F_f = 0.6 \times 49\\F_f = 29.4N[/tex]

Hence the force of friction needed to overcome to move the box is 29.4N

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A truck moves 60 km West, and then 80 km North, and then
travels in a straight line back to its starting point. The distance
travelled by the truck is ____km and its displacement is _____km

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Distance travelled by the truck is ~

[tex] \boxed{240 \: \: km}[/tex]

And it's displacement is ~

[tex] \boxed{0 \: \: km}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

See the diagram in attachment for reference ~

Let O be the initial point, It travels 60 km towards west till point B and then 80 km towards north till point P and returns to initial point O in a straight line, now as we can observe here, it forms a right angled Triangle.

The measure of two legs is 60 km and 80 km, let's find the hypotenuse ~

According to Pythagoras theorem ~

hypotenuse² = sum of squares of other two legs

that is ~

[tex]h {}^{2} = 60 {}^{2} + 80 {}^{2} [/tex]

[tex] {h}^{2} = 3600 + 640 0[/tex]

[tex]h {}^{2} = 10000[/tex]

[tex]h = \sqrt{10000} [/tex]

[tex]h = \sqrt{100 \times 100}{}[/tex]

[tex]h = 100 \: \: km[/tex]

So, the distance between the point A and O is 100 km

Now, The total distance is equal to the distance covered through actual path that is ~

60 km + 80 km + 100 km

240 km

And displacement is the distance between the final point and initial point, but since the truck returns to the point from where it started the journey, so the final and initial point is same therefore displacement is equal to 0.

An object of mass m is hanging by a string from the ceiling of an elevator. The elevator is moving down at constant speed. What is the tension of the string?

A. Zero
B. Equal to mg
C. Less than mg
D. Greater than mg​

Answers

Answer:

D. Greater than mg​

Explanation:

According to Newton’s second law of motion, the net force equals mass times acceleration. We are going to use a free body diagram (force diagram) to show that the equation of the motion is given by

T – mg = – ma

Thereby,

T = mg – ma

and the answer is: (d)

D. Greater than mg​

_________________________________

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When is the estimated due date (post conception) for parturition?

Answers

Answer: 38 weeks (266 days) from the date of conception.

Explanation: www.momjunction.com/pregnancy-due-date-calculator/

The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A

Answers

We have that for the Question "" it can be said that Calculate the moment which must be applied to the handle of the screw to raise the block is

M = 7.30 N.m

From the question we are told

The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A

Generally the equation for the Block is mathematically given as

[tex]\sum Fy=0[/tex]

[tex]981cos21.80 = R_2cos53.6\\\\R_2=1535N[/tex]

the equation for the Wedge is mathematically given as

[tex]\sum Fx=0\\\\1535cos36.4=Pcos21.8\\\\P=1331N[/tex]

the equation for the Screw is mathematically given as

[tex]\beta = tan^{-1}*\frac{L}{2*\pi*r} \\\\\beta = tan^{-1}*\frac{10}{2*\pi*(15)} \\\\\\beta = 6.06\\\\\theta = tan^{-1}*0.25 \\\\\theta = 14.04\\\\\\Therefore\\\\\theta + \beta = 20.1\\\\[/tex]

Therefore

[tex]M = Pr tan (\theta + \beta)\\\\M = 1331(0.015) tan20.09\\\\M = 7.30 N.m[/tex]

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When tightening a bolt, you push perpendicularly on a wrench with a force of 185 N at a distance of 0.11 m from the center of the bolt. How much torque are you exerting relative to the center of the bolt

Answers

Explanation:

The torque exerted on the wrench is

[tex]\tau = Fd\sin{\theta} = Fd[/tex]

since the force is applied perpendicular to the wrench, in which sin90 = 1. The torque then is

[tex]\tau = (185\:\text{N})(0.11\:\text{m}) = 20.35\:\text{N-m}[/tex]

given two vector
p= 2i + 2j + 4k
q = i - 4j + 4k
find p+ q​

Answers

Answer:

3i - 2j + 8k

Explanation:

p + q = (2i + i) + (2j - 4j ) + (4k + 4k )

= 3i -2j + 8k

Why can't we feel all the action-reaction forces around us?

Answers

Answer:

This happens when the mass of one of the objects is very large and does not move.

Explanation:

A branch falls from a tree. How fast is the branch moving after 0.28 seconds?
A. 2.7 m/s
B. 1.3 m/s
C. 4.4 m/s
D. 3.1 m/s

Answers

Answer:

A. 2.7 m/s

Explanation:

Answer:

[tex]\boxed {\boxed {\sf A. \ 2.7 \ m/s}}[/tex]

Explanation:

We want to find how fast a branch is falling after 0.28 seconds.

Essentially, we want to find its final velocity at exactly 0.28 seconds. We will use the following kinematic equation:

[tex]v_f= v_i+at[/tex]

The branch fell from the tree, so it initially started at rest or 0 meters per second. The branch is in free fall, so its acceleration is due to gravity, or 9.8 meters per second squared. It falls for 0.28 seconds.

[tex]v_i[/tex]= 0 m/s a= 9.8 m/s²t= 0.28 s

Substitute the values into the formula.

[tex]v_f= 0 \ m/s + (9.8 \ m/s^2)(0.28 \ s)[/tex]

Multiply the numbers in parentheses.

[tex]v_f= 0 \ m/s +(9.8 \ m/s/s * 0.28 \ s )[/tex]

[tex]v_f= 0 \ m/s +2.744 \ m/s[/tex]

Add.

[tex]v_f= 2.744 \ m/s[/tex]

The original measurement of time has 2 significant figures, so our answer must have the same. For the number we found, that is the tenth place. The 4 in the hundredth place tells us to leave the 7.

[tex]v_f \approx 2.7 \ m/s[/tex]

The branch is moving at a velocity of approximately 2.7 meters per second.

a body of mass 15 kg accelerates from rest of the rate of 4.0 ms^-2. determine the distance with the body travel in 25 seconds​

Answers

The distance traveled by the body in the given time is 1,250 m.

The given parameters;

mass of the body, m = 15 kgacceleration of the body, a = 4 m/s²time of motion, t = 25 sinitial velocity, u = 0

The distance traveled by the body in the given time is calculated as follows;

[tex]s =ut + \frac{1}{2} at^2\\\\s = 0 \ + \ \frac{1}{2} (4)(25^2)\\\\s =1,250 \ m[/tex]

Thus, the distance traveled by the body in the given time is 1,250 m.

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-
9 Two bodies of 6 kg and 4 kg masses have their
velocity 5i - 2j +10k and 10î – 2ġ +5ť,
respectively
. Then, the velocity of centre of me
(a) 5ỉ +23 - 8 (b) 7î+ 29 - 8
(2) 7î – 2į +8ỉ (d) 5î – 29 +8k
+
-

Answers

Answer:

I don't know he he.

just joking


3) A force of magnitude Fx acting in the x-direction on a 2.00 kg particle varies in time as shown
in FIGURE 2. Find
a) The impulse of the force
b) The final velocity of the particle if it is initially at rest
c) The final velocity of the particle if it is initially moving along the x-axis with velocity
of -2.00 ms -1

Answers

Answer:

a) Impuise of force =F∗?(t) = area of F-T graph area= impulse =triangle + rectangle + triangle = 0.5*4*2 + 4*1 + 0.5*4*2 = 12 N-s (b) impulse = change in momentum \(= mExplanation:

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