Which is an expression of degree 4 quadratic term with coefficient of 10.

Answer:

Domain of the function:

In interval notation: [6, ∞)

In set notation: {x: x∈R, x≥6}

Step-by-step explanation:

Remember that the the domain of the square root function are all the values such is is bigger than zero. We can express the later in set notation: {x: x∈R, x≥0}, or in interval notation: [0, ∞)

This is because the square root is not defined, in the real numbers, for negative values.

So, to find the domain of our function, we just need to set the thing inside the radical grater or equal than zero and solve for x:

The domain of the function is all the numbers bigger than 6, including 6.

Domain of the function: x will have values greater than or equal to 6 .

In interval notation: [6, ∞)

In set notation: {x: x∈R, x≥6}

Given, that function y = 2√x-6

Domain of the square root function are all the values which is greater than zero.

Express the later in set notation:

{x: x ∈ R, x≥0},

Interval notation: [0, ∞)

This is because the square root is not defined, in the real numbers, for negative values.

Domain of function y,

[tex]y= 2\sqrt{x-6}[/tex]

[tex]x-6\geq 0 \\x\geq 6[/tex]

The domain of the function is all the numbers greater than 6, including 6. Thus domain of function : [6, ∞) .

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Answer: -30 ==> A

Step-by-step explanation:

a = 3 and b = −4

12(a • b + a2) + 6=

12(a • b + a^2) + 6=

12(3 • (-4) + 3^2) + 6=

12(-12 + 9) + 6=

12(-3)+6=

-36+6=

-(36-6)=-30 ==> A

Answer:

a) -30

Step-by-step explanation:

Given that,

→ a = 3

→ b = -4

Let's solve the problem,

→ 12(a × b + a²) + 6

→ 12(3 × -4 + (3)²) + 6

→ 12(-12 + 9) + 6

→ 12 × -3 + 6

→ -36 + 6 = -30

Hence, the answer is -30.

[tex]y \leqslant 2[/tex]

The solution to the linear equations in three variable are x = 5, y = -11, and z = 3.

It is defined as the relation between three variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

The three linear equations:

2x - y + 4z = 33  ..(i)

x + 2y - 3z = -26 ...(ii)

-5x - 3y + 5z = 23 ...(iii)

After solving the above linear equation by elimination method:

From the equation (i):

[tex]x=\dfrac{33+y-4z}{2}[/tex]  ....(iv)

Plug the above value in the equation (ii) and (iii)

[tex]\rm \dfrac{33+y-4z}{2}+2y-3z=-26\\\\\\\\ -5\cdot \dfrac{33+y-4z}{2}-3y+5z=23[/tex]

After solving the above linear equation in two variables:

y = -11

z = 3

Plug the above values in the equation (iv)

We get the value of x:

x = (33-11-3(4))/2

x = (33-11-12)/2

x = 10/2

x = 5

Thus, the solution to the linear equations in three variable are x = 5, y = -11, and z = 3.

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The property illustrated by each statement of if t-13=52, then 52=t-13 is commutative

t-13=52, then 52=t-13

The property illustrated to each statement is commutative because it shows that for some value of t both statements are equal.

In mathematics, a binary operation is commutative if changing the order of the operands does now not alternate the result. it's far a essential belongings of many binary operations, and lots of mathematical proofs rely on it. most acquainted as the call of the assets that says something like "3 + four = 4 + 3" or "2 × 5 = 5 × 2",

the property also can be utilized in greater superior settings. The name is wanted because there are operations, which includes department and subtraction, that do not have it (for example, "3 − five ≠ 5 − 3");

such operations are not commutative, and so are called noncommutative operations.

The idea that easy operations, along with the multiplication and addition of numbers, are commutative become for many years implicitly assumed.

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Answer:

83 [tex]\frac{8}{10}[/tex] π cm3

Step-by-step explanation:

[tex]\frac{1}{3}[/tex] π ([tex]4^{2}[/tex])(5) = 83.7758040957

Answer:

Deandre spent $36.50 on video games and DVD rentals in the past month.

Step-by-step explanation:

values

video game = $3.20

DVD = $4.90

let video games be represented with the variable v

dvd represented by the variable d

make an equation

7d + 1v = ?

plug in values

7(4.90) + 1(3.20) = ?

7 x 4.90 = 34.3

1 x 3.20 = 3.20

34.3 + 3.20 = 36.50

thus 7d + 1v = $36.50

You need a value less than 23.5 or greater than 27.2.

Given the time in his first four races is: 24.7 , 23.5 , 25.6 , 27.2 seconds.

To find the time for her race which would make a higher difference, we need to make use of range.

The range formula is frequently employed in statistics to ascertain the range provided in a specific data set. The formula finds the difference between the lowest and highest value, which aids in locating the set's center. In distribution, a wide range denotes increased variability while a narrow range denotes lower variability. The mean, median, and mode are among the additional statistical concepts included in the range formula.

The range is the difference between the highest and lowest value. In this case, the highest and the lowest numbers are 27.2 and 23.5 seconds.

To make a larger range, we simply need to pick a number smaller than 23.5 or larger than 27.2. This will produce a larger difference (or range).

Hence we acquired the desired result.

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Your question is incomplete. Please find the missing content here.

Your friend swims on the school team.

In his first four races, his times are 24.7, 23.5, 25.6, and 27.2 seconds. Which time listed for her next race would make the range larger?

Using integrals, it is found that the cumulative distribution function(cdf) at x = 2.27 is given by:

P(X ≤ 2.27) = 0.897.

The cumulative distribution function of a distribution given by f(x) at a value of x = x* is given by the following integral:

[tex]\int_{-\infty}^{x^{\ast}} f(x) dx[/tex]

For this problem, the distribution is given by:

[tex]f(x) = e^{-x}, x > 0[/tex]

Hence, at x = 2.27, the cdf is given by:

[tex]\int_{0}^{2.27} e^{-x} dx[/tex]

The infinity was replaced by 0 because the lower bound of the definition of the distribution is of 0. Hence:

[tex]\int_{0}^{2.27} e^{-x} dx = -e^{-x}|_{x = 0}^{x = 2.27}[/tex]

Applying the Fundamental Theorem of Calculus:

P(X ≤ 2.27) = -e^(-2.27) + e^0 = -e^(-2.27) + 1 = 0.897.

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The equations that are true are:

2 + 5 = 19 - 12

5 - 4 - 3 - 2 - 1 = 30 - 34 - 1

Here we have some equations, the equations are only true if we have the exact same number in both sides of the equation.

The first one is:

2 + 5 = 19 - 12

If we simplify both sides we get:

2 + 5 = 7

19 - 12 = 7

Then the equation becomes:

2 + 5 = 19 - 12

7 = 7

This is true.

The next equation is:

5 - 4 - 3 - 2 - 1 = 30 - 34 - 1

If we simplify both sides we get:

5 - (4 + 3 + 2 + 1) = 30 - 35

5 - 10 = 30 - 35

-5 = -5

This is true.

The last equation is:

2x + 5 - 4x = 3x - 2 - 5x + 16

Here we have a variable, so we need to solve this for x.

2x -4x + 5 = 3x - 5x + 16 - 2

-2x + 5 = -2x + 14

-2x + 5 + 2x = 14

5 = 14

This equation is false, because 5 is different than 14.

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Answer:-12+16x

Step-by-step explanation:

-5x-20+8+16x

-5x-12+16x

-12+16x

Answer: 11x-12

Step-by-step explanation:

It would be easier to rearrange this equation by degree (ie ax^2, ax^1, a)

You cannot subtract ax^1 by a, but you can subtract ax^1 by ax^1 (16x-5x)

We can also subtract a by a (-20+8)

Remember your positive and negative signs

The dimensions of the rectangle are 10 inches by 25 inches

The given parameters are

The above parameters mean

w = 3l - 5

P = 70

The perimeter of the rectangle is

P =2(l + w)

So, we have

2(l + 3l - 5) = 70

Divide by 2

l + 3l - 5 = 35

Evaluate the like terms

4l = 40

Divide by 4

l = 10

Substitute l = 10 in w = 3l - 5

w = 3 * 10 - 5

w = 25

Hence, the dimensions of the rectangle are 10 inches by 25 inches

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Answer:

-1/3

Step-by-step explanation:

The slope of the line passing through the points (-2, 5) and (1, 4) is m = -1/3.

Answer:50.02

Step-by-step explanation:

This is about proper writing of decimals. We are given;(5 × 10) + (2 × 1/100) From BODMAS, let us first solve what is inside both brackets;5 × 10 = 502 × 1/100 = 2/100 = 0.02Since we have solved what is in the brackets, next is to add both of them;50 + 0.02 = 50.02Thus, the decimal equivalent is 50.02

Answer: it is 50.02

Step-by-step explanation: the decimals are equivalent

Answer:

Step-by-step explanation:

Answer:

there are many case and additional

items are needed to fulfill to order

of60items ordered

Step-by-step explanation:

The angle ∠3 = 153° by alternate angle theorem.

Parallel lines are those lines that are equidistant from each other and never meet.

Parallel lines cut by a transversal, forms different angle relationship like alternate angles, corresponding angles, etc.

Line a and m are parallel lines . Therefore, angles 1, 2, 3, 4, 5, 153 degrees are related base on alternate and corresponding relationship.

Hence,

∠3 = 153°(alternate angles)

Alternate angles are congruent.

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Answer: x=-2, 4/3

Step-by-step explanation:

-2|3x+1|=-10

-2|3x+1| / (-2) = -10/(-2)

-2|3x+1| / (-2) = 5

|3x+1|=5

3x+1=5

3x=4

x=4/3

3x+1=-5

3x=-6

x=-2

x=-2, 4/3

Using linear functions, it is found that:

A linear function is modeled by:

y = mx + b

In which:

For Shop A, we have a linear function that:

Hence the functions are given by:

Due to the lower slope, shop A charges less per hour. The costs will be the same when:

A(x) = B(x)

3x + 9 = 4x + 6

x = 3.

The canoe must be rented for 3 hours for the costs to be the same.

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Using translation concepts, we have that:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

On the translation of △ABC to △A′B′C′, the rule applied to the vertices is:

(x,y) -> (x + 4, y).

Hence it was translated 4 units right.

On the translation of △A′B′C′​ to △A′′B′′C′', the rule is given by:

(x,y) -> (-y,x).

Hence it was rotated 90 degrees counterclockwise about the origin.

The triangle keeps the same size after the translations, hence:

Because the transformations are both rigid, the pre-image and the image are congruent.

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density

a derived unit is something that comes from using base units in mathematical operations.

Answer:

65°

Step-by-step explanation:

  Exterior angle of a triangle equals the sum of opposite interior (remote) angles.

 3x - 10 = x + 15 + 25

 3x - 10 = x + 40

Add 10 to both sides,

       3x = x + 40 + 10

       3x = x +50

Subtract 'x' from both sides,

     3x- x = 50

         2x = 50

Divide both sides by 2

           x = 50÷ 2

           x = 25

Exterior angle = 3x -10

                        = 3*25 - 10

                        = 75 - 10

                        = 65°

Answer:

209.106 = (2 x 100) + (0 x 10) + (9 x 1) + (1/10) + (0/100) + (6/1000)

Answer: 200 + 9 + 0.1 + 0.005

Step-by-step explanation: For expanded form you need to break up the number into its individual parts. You have 2 hundreds, 9 ones, 1 tenths, and 5 thousandths.

Using proportions, the correct statement is given as follows:

Between 2010 and 2013, Mr. Jones' student loan balance decreased by 4750 dollars.

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

His balance is only 100 - 71.4 = 28.6% of the initial balance of $6,400, hence it is currently of:

0.286 x 6400 = $1830.

The decrease was of:

6400 - 1830 = $4750.

Hence the correct statement is:

Between 2010 and 2013, Mr. Jones' student loan balance decreased by 4750 dollars.

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To calculate marginal cost ; we use "subtract the quantity change from the overall cost change."

The potential cost of increasing orange output from 50 to 80 units was (250 – 200) = 50 cherries.

The potential cost of increasing cherry production from 100 to 200 units was (86-80) = 6 oranges.

Opportunity cost for an orange right now is,

equals 1.67 cherries.

Opportunity cost is therefore 3.34 cherries for two oranges.

One cherry's opportunity cost is,

0.06 orange units

1.8 oranges are the opportunity cost of 30 cherries.

Conclusion

a. Cherry 50

b. Oranges, six

c. Cherry 3.34

d. Oranges, 1.8

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The constant of variation is 3.

It should be noted that in the information, we are given the values of both x and y.

When x is 2, y is 6. When x is 5, y is 15. Finally when x is 8, y is 24.

The constant is given as 6/2 or 15/5 or 24/8. This will give 3.

Therefore, the constant of variation is 3.

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X And y values shown x

X. Y

2. 6

5. 15

8. 24

What is the constant of variation?

Answer:

0.35 feet per second

Step-by-step explanation:

To start, there's 3 feet in 1 yard.

So, we have to convert the 7 yards per minute to feet.

7 x 3 = 21

Then, we have to convert 21 feet per minute to X amount of feet per second.

To note, there are 60 seconds in a single minute

Therefore, you have to divide 21 by 60 to find the amount of feet in one second.

21 / 60 = 0.35

The answer is 0.35 feet per second

System of liner equation [tex]x+3y-z=2[/tex],[tex]x+y-z=0[/tex] and [tex]3x+2y-3z=-1[/tex] has no solution.

What do you mean by system of linear equation?

A set of two linear equations with two variables is a system of linear equations.

Given:

[tex]x+3y-z=2[/tex]           ---1

[tex]x+y-z=0[/tex]             ---2

[tex]3x+2y-3z=-1[/tex]     ---3

Rearranging the equation 2

[tex]z=x+y[/tex]   ---4

Putting equation 4 in equation 1

⇒ [tex]x+3y-(x+y)=2[/tex]

⇒ [tex]x+3y-x-y=2[/tex]

⇒ [tex]2y=2[/tex]

⇒ [tex]y=1[/tex]

Putting equation 4 in equation 3

⇒ [tex]3x+2y-3(x+y)=-1[/tex]

⇒ [tex]3x+2y-3x-3y=-1[/tex]

⇒ [tex]-1y=-1[/tex]

⇒ [tex]y=1[/tex]

Putting value of y above

⇒ [tex]1=1[/tex]

Therefore, system of liner equation has no solution.

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Answer:

60 and 600

Step-by-step explanation:

im guessing..

Check the picture below.

[tex]{\LARGE \begin{array}{llll} y = ab^x \end{array}} \\\\[-0.35em] ~\dotfill\\\\ \textit{we know that} \begin{cases} x=0\\ y=40 \end{cases}\implies 40=ab^0\implies 40=a(1)\implies 40=a \\ ~\hfill \underline{y = 40b^x} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\textit{we also know that} \begin{cases} x=3\\ y= 15 \end{cases}\implies 15 = 40b^3\implies \cfrac{15}{40}=b^3\implies \cfrac{3}{8}=b^3 \\\\\\ \sqrt[3]{\cfrac{3}{8}}=b\implies \cfrac{\sqrt[3]{3}}{\sqrt[3]{8}}=b\implies \cfrac{\sqrt[3]{3}}{2}=b~\hfill \underline{y = 40\left( \frac{\sqrt[3]{3}}{2} \right)^x}[/tex]