The four mixtures listed above can be separated by filtration. Filtration is a technique commonly used to separate a suspended solid from a liquid, or from another solid, in order to purify or clarify the product or solution. In this respect, mayonnaise, muddy water, shaving cream and gelatin can be separated by filtration.
First, mayonnaise can be separated by filtration. Mayonnaise is a combination of oil and egg yolks, and it is a mixture that can be separated using a cheesecloth or a paper filter. This process works because the large particles of egg yolks and oil can be caught in the filter, while the smaller liquid components can be left behind.
Muddy water can also be separated by filtration. Muddy water typically contains suspended solids such as dirt and clay, which can be removed by passing the water through a filter. These solids are collected on the filter while the remaining water is clarified and clean.
Shaving cream can be separated by filtration as well. By using a filter paper, the oils contained in the shaving cream will stick to the filter, while the rest of the ingredients in the cream will be trapped behind the filter.
Finally, gelatin mixtures can also be separated by filtration. Gelatin is a mixture that contains proteins, fats, sugars and minerals. Separating these components can be achieved by passing the mixture through a filter. The proteins and fats will be collected on the filter, while the minerals and sugars will remain behind.
In conclusion, filtration is a process used to separate different components from a mixture. This process can be used to separate mayonnaise, muddy water, shaving cream and gelatin mixtures. By using filtration, the suspended solids in these mixtures can be removed, while the remaining components can be considered purified or clarified.
What chemical reactions are taking place inside the mouse?
Answer:
the heart and blood
Explanation:
the blood jus move threw heart or sum
Which conditions in Northern Europe encouraged emigration between 1845 and 1860?
A. war and famine
B. disease and slavery
C. natural disasters and climate change
D. religious persecution and poor education
Can someone please help with this chemistry question
24.9 g of oxygen gas would be required to completely burn 7.33 g of propane.
What is oxygen?Oxygen is an element found in air. It is a colorless, odorless gas that makes up about 21% of the Earth's atmosphere. Oxygen is essential for humans and animals to survive, as it is used to produce energy in the cells of living organisms, and to help maintain the balance of other elements in the body.
To answer this question, you need to balance the chemical equation first. The balanced equation is:
[tex]C_3H_8 + 5O_2 - > 3CO_2 + 4H_2O[/tex]
Now that the equation is balanced, you can calculate the mass of oxygen required to burn 7.33 g of propane.
To calculate the mass of oxygen, you need to use the mole ratio of the reactants in the balanced equation. The mole ratio of propane to oxygen is 1:5. Therefore, for every 1 mole of propane, 5 moles of oxygen are required.
Using the mole ratio and the given mass of propane, you can calculate the mass of oxygen required.
7.33 g of propane x (1 mole propane / 44.096 g propane) x (5 moles oxygen / 1 mole propane) x (32.00 g oxygen / 1 mole oxygen) = 24.9 g of oxygen
Therefore, 24.9 g of oxygen gas would be required to completely burn 7.33 g of propane.
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Adenine has a molecular mass of 135. 1 and consist of 44. 45%c, 3. 73%h, and 52. 82%n by mass. Determine its molecular formula
The molecular formula for Adenine with molecular mass of 135.1 and consist of 44. 45% C, 3. 73% H, and 52. 82% N by mass is C₃H₃₆N₂.
The molecular formula expresses the number of atoms of each element in one chemical molecule.
The definition of a molecular formula is the formula that shows the exact number of atoms in a molecule.
The empirical formula is used to derive the Molecular Formula when the molar mass value is known.
n=empirical formula molar mass/mass
The molecular formula is frequently the same as or an exact multiple of an empirical formula.
We have molecular formula = 135.14
so we need to find each atoms contribution so,
C = 135.14 /44.45 = 3.03
H = 135.14 /3.73 = 36.21
N = 135.14 / 52.82 = 2.55
So we have molecular formula as,
C₃H₃₆N₂.
Adenine is a nucleic acid component, specifically the nitrogenous base in the structure. Adenine is a nitrogenous base present on both DNA and RNA molecules (examples of nucleic acids). Adenine is a compound of Carbon, Hydrogen, and Nitrogen atoms, and elemental analysis can assist in determining the chemical formula.
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How many elements and atoms are in these equations?
H2F5BLi
2He2PSO4
3He2O4PH
The only one I know is NaC2HO4. 1 atom in sodium, 2 atoms in carbon, 1 atom in hydrogen and 4 atoms in oxygen completeting the total of 8 atoms in this element.
How do you find the number of atoms in a formula?The first stage in calculating the number of atoms is to determine the number of molecules. To determine the number of moles in an element or compound, reduce the specified mass by the element or compound's molar mass. The number of atoms in 1 mole of a material is or. 023 10 23 atoms.
An element is a particle. Since the two terms are identical, the answer is always one, and only one, if you're searching for the number of atoms in an element.
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Full Question: What’s the elements found in these formulas?
NaC2HO4
H2F5BLi
2He2PSO4
3He2O4PH
The element thallium is 70% thallium-205 and 30% thallium-203. Calculate its relative atomic mass. Give your answer to 4 significant figures.
The relative atomic mass is205.976 amu x
Atomic mass calculation.
Relative atomic mass (also called atomic weight) is the average mass of the atoms in a naturally occurring sample of an element, taking into account the abundance of each isotope of the element. It is a dimensionless quantity, defined as the ratio of the average mass per atom of the element to the unified atomic mass unit (u or Da).
To calculate the relative atomic mass of thallium, we need to take into account the abundance and atomic masses of its two isotopes, thallium-205 and thallium-203.
Let X be the relative atomic mass of thallium.
The atomic mass of thallium-205 is 205.976 amu, and its abundance is 70% or 0.7.
The atomic mass of thallium-203 is 202.972 amu, and its abundance is 30% or 0.3.
Using the formula for calculating relative atomic mass, we have:
X = (205.976 amu x
Overall, the answer has been rounded to four significant figures, which is the same as the least number of significant figures given in the input data (two significant figures for the isotopic abundances).
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What are the name and relative atomic mass of the element with which the relative atomic masses of all other elements are compared?
Answer:
Relative atomic mass is the average mass of an atom of an element, compared to 1/12th the mass of carbon 12 atom. Relative molecular mass is the ratio of the average mass of one molecular of an element or compound to1/2 of the mass of an atom of carbon 12.
consider a salt that has a solubility of 551 g/l. you add 123 g of this salt to 421 ml of water. how much (in g) salt will remain undissolved?
The answer is 0 g.
In order to determine how much salt will remain undissolved after adding 123 g of a salt with solubility of 551 g/L to 421 mL of water, we need to first convert the volume of water to liters.421 mL of water = 0.421 L of water
The maximum amount of salt that can dissolve in 1 L of water with a solubility of 551 g/L can be calculated using the formula:
Max amount of salt that can dissolve = Solubility × Volume of solvent Max amount of salt that can dissolve = 551 g/L × 1 L
Max amount of salt that can dissolve = 551 g
Therefore, the maximum amount of salt that can dissolve in 0.421 L of water is:
Max amount of salt that can dissolve = 551 g/L × 0.421 L
Max amount of salt that can dissolve = 231.671 g
Since only 123 g of salt was added to 0.421 L of water, this is less than the maximum amount of salt that can dissolve. Hence, all of the salt will dissolve and there will be no salt left undissolved. Therefore, the answer is 0 g.
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Elabora, en tu cuaderno, un organizador gráfico en el que sintetices la información obtenida en el texto. Evidencia información sobre la formación de los ácidos hidrácidos y oxácidos, su nomenclatura, sus propiedades y su aplicación en la industria
Hydrocid and oxacid acids (formation, nomenclature, properties and application):
HYDRACID ACIDSFormation: binary compounds formed by HYDROGEN and a NON-METAL (from groups 6A and 7A of the periodic table).
Properties: they are found naturally in a gaseous state. They are called hydrocids because when they dissolve in water and dissociate, they generate acidic solutions.
Applications : In the industry they are mostly used for organic synthesis and for the leather tanning industry.
NomenclatureFormula: HX, H is hydrogen and X is the chemical symbol for halogen.
Systematic: name of the acid + suffix -ide + hydrogen. Example: Hydrogen chloride → HCl
Traditional: acid + non-metal + suffix "-hydric". Example: Hydrogen telluric acid → H₂Te
OXACID ACIDSFormation: Acid compounds formed by HYDROGEN, a NON-METAL and OXYGEN. They are obtained by reaction between an anhydride (acid oxide) and water . Hydrogen acts with oxidation number +1 and oxygen with -2.
Properties: They are ternary compounds (formed by three chemical elements), formed by a non-metallic chemical element, oxygen together with hydrogen.
Applications: In the industry it is used to obtain fertilizers for agriculture . As well as it is used for the synthesis of other acids, sulfates and in the petrochemical industry .
Nomenclature
Formula: HaXbOc, H is hydrogen, X is a non-metal element and O is oxygen
Stock : Acid + prefix indicating the number of oxygens + oxo + prefix for the number of non-metallic atoms + root of that atom ending in "-ico" + valence in Roman numerals (in brackets). Example: Dioxochloric acid (III) → HClO₂
Systematic : prefix that indicates the number of oxygens + oxo + prefix for the number of non-metallic atoms + root of that atom ending in "-ate" + valence in Roman numerals (in parentheses) + hydrogen. Example: Hydrogen tetraoxochlorate (VII) → HIO₄
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Translated Question: Prepare, in your notebook, a graphic organizer in which you synthesize the information obtained in the text. Provides information on the formation of hydroacid and oxacid acids, their nomenclature, their properties and their application in industry. help me
The balanced equation below represents the reaction of glucose, C6H12O6, with oxygen at 298 K and 101.3 kPa.
C6H12O6(s) + 6O2(g) → 6CO2(g) + 6H2O(ℓ)
Determine the mass of CO2 produced when 9.0 grams of glucose completely reacts with 9.6 grams of oxygen to produce 5.4 grams of water. [1]
Compare the entropy of the reactants to the entropy of the products. [1]
Write the empirical formula for glucose. [1]
Answer:
1. 79.2 g of CO2
2. the reaction is spontaneous and favors the formation of products
3. CH2O
Explanation:
To solve the problem, we first need to calculate the limiting reagent by comparing the amount of glucose and oxygen available for the reaction. We will assume that the reaction goes to completion.
The balanced equation shows that for every 1 mole of glucose, 6 moles of oxygen are required. Therefore, the moles of oxygen required for 9.0 grams of glucose is:
moles of glucose = mass/molar mass = 9.0/180.16 = 0.0499 mol
moles of oxygen = 6 x moles of glucose = 6 x 0.0499 = 0.2994 mol
Since we have 0.2994 moles of oxygen available, and only 0.2000 moles of oxygen are required to react with 0.0499 moles of glucose to produce 0.0270 moles of water (according to the balanced equation), oxygen is the limiting reagent.
Using the balanced equation, we can now calculate the moles of CO2 produced:
moles of water produced = mass/molar mass = 5.4/18.02 = 0.2997 mol
moles of CO2 produced = 6 x moles of water produced = 6 x 0.2997 = 1.7982 mol
Finally, we can calculate the mass of CO2 produced:
mass of CO2 produced = moles x molar mass = 1.7982 x 44.01 = 79.2 g
Therefore, the mass of CO2 produced when 9.0 grams of glucose completely reacts with 9.6 grams of oxygen to produce 5.4 grams of water is 79.2 g.
To compare the entropy of the reactants to the entropy of the products, we can use the equation:
ΔS = ΣS(products) - ΣS(reactants)
The entropy of a substance depends on its state and temperature, and can be looked up in tables. At standard conditions (298 K and 101.3 kPa), the molar entropy of glucose, oxygen, CO2, and liquid water are:
S(C6H12O6) = 212.8 J/(mol K)
S(O2) = 205.0 J/(mol K)
S(CO2) = 214.8 J/(mol K)
S(H2O) = 69.9 J/(mol K)
Using the above values and the balanced equation, we can calculate the entropy change:
ΔS = (6 x S(CO2) + 6 x S(H2O)) - (S(C6H12O6) + 6 x S(O2))
ΔS = (6 x 214.8 + 6 x 69.9) - (212.8 + 6 x 205.0)
ΔS = 287.4 J/(mol K)
Since ΔS is positive, the entropy of the products is greater than the entropy of the reactants. This means that the reaction is spontaneous and favors the formation of products.
The empirical formula for glucose can be determined by dividing the subscripts by their greatest common factor. In this case, the empirical formula is:
C6H12O6 ÷ 6 = CH2O
Therefore, the empirical formula for glucose is CH2O.
During which step in "Steps to Solve a Problem" should students pick a strategy to use? Step 1 Step 2 Step 3 Step 4
Students should pick a strategy to use during Step 2 of "Steps to Solve a Problem."
In Step 1, students should read the problem and try to understand what is being asked of them. In Step 2, they should analyze the problem and identify what type of problem it is and what strategies could be used to solve it. This is where they should pick a strategy or method to solve the problem.
In Step 3, students should develop a plan for solving the problem using the strategy they have chosen. In Step 4, they should execute the plan and check their work to make sure it is correct.
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Answer:
Step 2
Explanation:
draw and label the diagram of parts of the battery and illustrate the flow of electric current.
The specific components and design of a battery can vary depending on the type of battery and its intended use.
What are the parts of a battery?The basic components of a battery include:
Anode: This is the negative electrode of the battery where the oxidation reaction takes place.
Cathode: This is the positive electrode of the battery where the reduction reaction takes place.
Electrolyte: This is the medium that allows ions to flow between the anode and cathode, completing the circuit and generating the electrical energy.
Separator: This is a porous material that separates the anode and cathode, preventing direct contact between the electrodes while still allowing ions to flow between them.
Terminal: These are the points on the battery where the electrical energy is transferred out of the battery to power a device or charge another battery.
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Grades on tests can also be thought of as a
success statistic. How would you define the actual score and theoretical
score on an exam, and how would you calculate the percent success?
The actual score on an exam refers to the number of points earned by a student on the test, while the theoretical score is the maximum possible score that a student could have earned if they answered every question correctly.
What is concentration?In chemistry, concentration refers to the amount of solute that is dissolved in a given amount of solvent or solution. It is typically expressed in units such as molarity (moles of solute per liter of solution), molality (moles of solute per kilogram of solvent), or percent concentration (the percentage of solute in a solution by mass or volume). Concentration plays an important role in determining the properties and behavior of a solution, including its reactivity, solubility, and osmotic pressure. It also affects the rate of chemical reactions, as the frequency of collisions between molecules or ions is related to their concentration in the reaction mixture.
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Grove School had a play. The graph shows how many people came to the play each night. Look at the data.
Which of the following is true?
A.
More people came to the play on Tuesday than on Friday.
B.
More people came to the play on Tuesday than on Monday.
C.
Everyone liked the play.
D.
Tickets cost less on Thursday.
The true statement on the data on the graph about the attendance for the play made by Grove Street is B. More people came to the play on Tuesday than on Monday.
What does the graph show ?The graph shows the number of people who attended a school play by Grove School from Monday to Saturday in a certain week. We see that Monday had the lowest attendance and was followed by Tuesday.
Attendance continued to rise and was higher on Wednesday than Tuesday but then dropped for Thurdsady and Frifay. It was then highest on the Saturday as more parents probably had time to attend.
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What is the pH of water?
A. 7
O
B. 1 x 107
O
C. -7
D. 1 x 107
Answer: a= 7
Explanation:
Can someone please help with this chemistry question
N2 (g) + 3H2 (g) 2NH3 is the balanced chemical equation of N2 + H2 NH3 (g). Based on the rule of conservation of mass, it is possible to make the atoms on both the reactant and product sides equal.
How do you find the balanced chemical equation?In a balanced chemical equation, the total number of atoms of an element present in a species is equal to the product of the stoichiometric coefficient and the number of atoms of the element in one molecule of the species.
The total number of oxygen atoms in the reactive species '2O2', for example, is four. Use these easy principles to balance equations on your own: Verify that all of the equation's formulas are valid. Just deal with one ingredient at a time. Balancing adds up to a lot of money.
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silver sulfide (ag2s) is the common tarnish on silver objects. what mass of silver sulfide can be made from 1.53 x 10-3g of hydrogen sulfide (h2s) obtained from a rotten egg?\
Silver sulfide (Ag2S) is the common tarnish on silver objects. The mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide (H2S) obtained from a rotten egg is 3.67 g.
Let's understand this in detail:
The balanced chemical equation for the reaction is:
2 AgNO3 + H2S → Ag2S + 2 HNO3
The molar mass of H2S is 34.08 g/mol.
1.53 x 10^-3g of H2S = (1 mol / 34.08 g) * (1.53 x 10^-3g) = 4.49 x 10^-5 mol H2S.
From the balanced equation, it is clear that one mole of Ag2S is formed from one mole of H2S.
Therefore, the number of moles of Ag2S formed from 1.53 x 10^-3g of H2S is 4.49 x 10^-5 mol.
The molar mass of Ag2S is 247.8 g/mol. Therefore, the mass of Ag2S formed from 1.53 x 10^-3g of H2S is
(247.8 g/mol) * (4.49 x 10^-5 mol) = 0.0111 g or 11.1 mg.
To convert to grams, divide by 1000:11.1 mg ÷ 1000 = 0.0111 g or 11.1 mg = 1.11 x 10^-2
Therefore, the mass of silver sulfide that can be made from 1.53 x 10^-3g of hydrogen sulfide obtained from a rotten egg is 3.67 g (approx).
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YooooooOOO!! Help!
Which of the following statements is incorrect concerning BaF2?
Question 2 options:
The total number of fluoride ions present in one formula unit is 2(6.022 x 1023).
The total number of fluoride ions present in three moles of BaF2 is equal to 6 x (6.022 x 1023).
The mass of 0.600 moles of BaF2 is 105 grams.
0.600 moles of BaF2 is equivalent to 3.61 x 1023 formula units of BaF2.
Explanation:
The total number of fluoride ions present in three moles of BaF2 is equal to 6 x (6.022 x 1023).How many Oxygen atoms in the formula 4H3O2
Answer:
There are 8 oxygen atoms in the formula 4H3O2.
Explanation:
Answer:
There are 6 oxygen atoms in 4H3O2
Explanation:
There are 3 oxygens but since oxygen is a diatomic atom you multiply it by 2 and you get 6.
An energy level diagram is shown below. What is the overall energy change in this reaction?
Using the reaction profile that we can see from the question that has been given, the overall energy change is -250 kJ/mol
What is enthalpy of reaction?Enthalpy of reaction is the amount of heat absorbed or released during a chemical reaction, at a constant pressure. It is a measure of the energy change that occurs when reactants are transformed into products in a chemical reaction.
Enthalpy of reaction is denoted as ΔHrxn, where ΔH is the symbol for the change in enthalpy, and rxn is the abbreviation for "reaction". It is expressed in units of energy per amount of substance, such as joules per mole (J/mol).
Using;
Energy of Products - Energy of reactants
100 - 350 = -250 kJ/mol
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The quantity of electricity that deposit 10. 8g of silver. What mass of aluminum will be deposited by thesame quantity of electricity ( Ag=108, Al= 27, 1F= 96,500 coulomb)
The quantity of electricity that deposit 10.8g of silver is equal to 9,650 coulombs and the the mass of aluminum which will be deposited by the same quantity of electricity is equal to 2.7g.
During the electrolysis process, the amount of substance deposited on an electrode is directly proportional to the amount of electricity passed through the electrolyte solution. This constant of proportionality is called as Faraday's constant. It is equal to 96,500 coulombs per mole of electrons.
In 108g, the number of moles of Aluminum is 1 mole.
In 10.8g, the number of moles of Aluminum is equal to 0.1 moles.
Since 96.500 coulombs of energy is used to transfer 1 mole of substance, So, 9650 coulombs of energy will be required to transfer 0.1 moles of the substance.
Since 27g of Aluminum will be transferred by 96500 coulombs of energy, so in 9650 coulombs of energy, 2.7g of Aluminum will be deposited.
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AgNO 3 + NaCI - AgCI + NaNO 3
Answer:
Correct
pls mrk me brainliest
Please helpppp meeee!!!!!!!
a) A gas was produced
b) Reaction 1 does not takes place in a beaker
c) The reactions are balanced
d) The law of conservation of mass can be used to show that a reaction is balanced.
Why does reaction 1 not occur in a beaker?A combustion reaction, for instance, might not be able to continue if there isn't enough fuel or oxygen in the beaker to support it.
Moreover, a beaker is unlikely to contain an ignition source, like as a spark or flame, which is typically required to start the reaction.
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HELP ME I DONT KNOW WHAT TO DO
Glass Because wood and other materials can be electrified through induction, but glass can't.
Is specific heat capacity C or Q?
The equation q = mcT may be used to compute the amount of heat acquired or lost by a sample (q), where m is the sample's mass, c is the specific heat, and T is the temperature change.
The quantity of heat required to raise the temperature of a given amount of stuff by one degree Celsius is referred to as heat capacity. The heat capacity of one gram of a material is known as its specific heat capacity (or specific heat), whereas the heat capacity of one mole is known as its molar heat capacity.
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What is the mass of each element in 100. 0 g vinegar ? (Enter your answers to two decimal places. ) Percent Mass Mass in 100. 0 40. 01 ? 6. 70 % 53. 29 %
G C
G H
G O
the mass of carbon in 100.0 g of vinegar is 40.01 g, the mass of hydrogen is 6.70 g, and the mass of oxygen is 53.29 g.
To calculate the mass of each element in 100.0 g of vinegar, we need to use the percent composition of the compound. The percent composition tells us the percentage of each element in the compound by mass.
The percent composition of vinegar is:
Carbon (C): 40.01%
Hydrogen (H): 6.70%
Oxygen (O): 53.29%
To calculate the mass of each element, we need to multiply the percent composition by the total mass of the compound (100.0 g).
Mass of carbon (C) = 40.01% x 100.0 g = 40.01 g
Mass of hydrogen (H) = 6.70% x 100.0 g = 6.70 g
Mass of oxygen (O) = 53.29% x 100.0 g = 53.29 g
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Please Help. Complete the number of bonds and the total energy for each. Don't forget to state whether this is on the product or reactant side by highlighting the correct one. CEC # of bonds single bond O=O # of bonds C-H # of bonds C-O # of bonds H-O # of bonds (product/reactant) side (product / reactant) side (product/reactant) side (product/reactant) side (product / reactant) side Energy: Energy: Energy: Energy: Energy:
CEC-C-H: 9 bοnds (reactant) / 0 bοnds (prοduct)
C-O: 0 bοnds (reactant) / 2 bοnds (prοduct)
H-O: 0 bοnds (reactant) / 1 bοnd (prοduct)
What are the number οf bοnds fοr each element invοlved in the reactiοn?
CEC: The reactant side has 9 C-H bοnds, while the prοduct side has 0 C-H bοndsCEC: The reactant side has 0 C-O bοnds, while the prοduct side has 2 C-O bοnds.CEC: The reactant side has 0 H-O bοnds, while the prοduct side has 1 H-O bοnd.Single bοnd O=O: The reactant side has 0 O=O bοnds, while the prοduct side has 2 O=O bοnds.The tοtal energy fοr each bοnd is nοt prοvided, but the number οf bοnds and whether they are οn the reactant οr prοduct side is given.
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How many moles of NaOH are needed to create a 2 M solution in 8 liters of solution? Please help, I’m really stuck on this one.
Answer:
To calculate the number of moles of NaOH needed to create a 2 M solution in 8 liters of solution, we need to use the formula:
moles = molarity x volume (in liters)
Here, the molarity (M) is given as 2 M, and the volume (V) is given as 8 liters.
So,
moles = 2 M x 8 L
= 16 moles
Therefore, 16 moles of NaOH are needed to create a 2 M solution in 8 liters of solution.
Explanation:
How many moles of NaBr are there in 0. 50 liters of a 2. 1M NaBr solution?
Answer:
Explanation:
mOLARITY IS moles/L
moles = M X L
2.1 X 0.50 = 1.05 moles NaBr or 1.1 moles NaBr to correct sig figs
Which of the following is a fission reaction?
hydrogen-2 and hydrogen-3 combining to form a helium-4 atom and a neutron
carbon-12 and hydrogen-1 combining to form a nitrogen-13 atom
uranium-235 absorbing a neutron and breaking into barium-141, krypton-92, and three neutrons
a glucose molecule being metabolized with oxygen to form carbon dioxide and water
Un estudiante tiene 6 galletas Graham, 3 piezas de chocolate y 4 malvaviscos. Para hacer un s'more, un estudiante necesita usar dos galletas Graham, una pieza de chocolate y dos malvaviscos. ¿Cuál de los siguientes describe con precisión los reactivos limitantes y en exceso dados estos materiales? Pregunta 1 opciones: Los malvaviscos serían el reactivo limitante y las galletas graham y el chocolate serían el exceso. Se pueden hacer dos s'mores. El chocolate sería el reactivo limitante y las galletas graham y los malvaviscos serían el exceso. Se pueden hacer tres s'mores. El chocolate sería el reactivo limitante y las galletas graham y los malvaviscos serían el exceso. Se pueden hacer dos s'mores.
Answer:
Dado que los malvaviscos solo pueden hacer 2 s'mores, son el reactivo limitante. Esto significa que el número máximo de s'mores que se pueden hacer es 2.
Por lo tanto, la respuesta correcta es: los malvaviscos serían el reactivo limitante y las galletas graham y el chocolate serían el exceso. Puedes hacer dos s'mores.
Explanation: