Answer:
D- Br
Explanation:
What is the number of formula units in a 9.21 mol sample of CaO ?
Answer:
5.546262 x 10^24 formula units
Explanation:
Use avogadro's number
9.21 mol CaO ((6.022 x 10^23 formula units CaO)/1 mol CaO)) = 5.546 x 10^24.
I rounded to 3 sig figs.
UESTION 14nsider the compound XF. Which of the following is true about the compound?A. If XF is covalent, X could be a metal.B. If XF is ionic, X could be a nonmetal.C. If XF is covalent, the name uses prefixes.D. If XF is covalent, X has a charge of +1.QUESTION 15What are the values of x and y in the compound Agx(CO3)y?O AX= 1, y = 2B. x = 3, y = 1OC. x = 3, y = 2O D.X = 2, y = 1
a. If XF is covalent, X couldn't be a metal. Because covalent bonding occurs between nonmetals. So this alternative is False.
b. If XF is ionic, X could be a nonmetal. Also False. Ionic bonding occurs between a metal and a nonmetal. In this case, we already have a nonmetal, which is F.
c. If XF is covalent, the name uses prefixes. True. When we have a covalent compound, the name of the nonmetal on the left has a prefix indicating the number of atoms of it.
d. If XF is covalent, X has a charge of +1. False. This would happen if it was ionic.
Answer: Alternative "C"
What is the mass of 9.50 moles of magnesium chloride, MgCl2 ?'
After conditions changed to a volume of a sample of helium at 15.56 mL, 138.7°C and 334.6 kPa. What was its initial volyme at 63.2 °C and 57.3 kPa?O a. 74.2O b. 41.4O c. 2.18O d. 111
Answer
a. 74.2
Explanation
Given that:
The initial temperature, T₁ = 63.2 °C + 273 = 336.2 K
Initial pressure, P₁ = 57.3 kPa
The final volume, V₂ = 15.56 mL
Final temperature, T₂ = 138.7°C + 273 = 411.7 K
Final pressure, P₂ = 334.6 kPa
What to find:
The initial volume, V₁.
Step-by-step solution:
The initial volume, V₁ can be calculated using the combined gas law equation.
[tex]\begin{gathered} \frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} \\ \\ V_1=\frac{P_2V_2T_1}{P_1T_2}=\frac{334.6kPa\times15.56mL\times336.2K}{57.3kPa\times411.7K} \\ \\ V_1=\frac{1750383.611\text{ }mL}{23590.41}=74.2\text{ }mL \end{gathered}[/tex]Hence, its initial volume at 63.2 °C and 57.3 kPa is 74.2 mL
what are the limiting and excess reactants when 3.22 moles of Al react with 6.96 moles of HBr
Answer
HBr is the limiting reactant
Al is the excess reactant.
Explanation
Given:
Moles of Al = 3.22 mol
Moles of HBr = 6.96 mol
Equation: 2 Al + 6 HBr → 2 AlBr₃ + 3 H₂
What to find;
The limiting and excess reactants.
Solution:
Note: The limiting reactant is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. While the excess reactant is the opposite.
From the given balanced chemical equation;
2 moles of Al require 6 moles of HBr
Therefore, the given 3.22 moles of Al will require (3.22/2) x 6 = 9.66 moles of HBr
Since the given moles of HBr is 6.96 mol not up to 9.66 moles required, then HBr is the limiting reactant and Al is the excess reactant.
HBr is the limiting reactant
Al is the excess reactant.
Given the equation below, how many moles of nitrogen gas (N2) areneeded to react with 7.5 moles of hydrogen gas (H2)?N2+ 3H2 —>2 NH3
Answer
2.5 moles of N₂ are needed to react with 7.5 moles of hydrogen gas
Explanation
Given:
Equation: N₂ + 3H₂ → 2NH₃
Moles of H₂ = 7.5 moles
What to find:
The moles of nitrogen gas (N₂) needed to react with 7.5 moles of hydrogen gas
Step-by-step solution:
Let the mole of N₂ needed be x.
From the given balanced chemical equation:
3 moles of H₂ react with 1 mole of N₂
Therefore, 7. 5 moles of H₂ will react with x moles of N₂
Cross multiply
[tex]\begin{gathered} x\text{ moles }N_2\times3\text{ moles H}_2=7.5\text{ moles H}_2\times1\text{ mole N}_2 \\ \text{Divide both sides by 3 moles H}_2 \\ \frac{x\text{ moles }N_2\times3\text{ moles H}_2}{3\text{ moles H}_2}=\frac{7.5\text{ moles H}_2\times1\text{ mole N}_{2}}{3\text{ moles H}_2} \\ x\text{ moles }N_2=2.5\text{ moles} \end{gathered}[/tex]Which of the following best describes what happens when salt dissolves in water?A.) The polar solvent molecules surround the positive sodium ions.B.) The polar solvent molecules surround the positive sodium ions and the negativechloride ions.C.) The solute and solvent molecules form a crystalline structure.D.) The solute and solvent molecules do not interact.
When salt dissolves in water, dissociation occurs. This dissociation forms two ions, one positive and one negative. Water is polar and its molecules has poles negatives and positives. So positive poles of water will surround the negative ions. While negative poles will surround the positive ions.
Answer: Alternative "B"
I get 11 pls help and see if I’m right
Answer
None of these
Explanation
The option for 2-bromo-5propylbenzaldehyde does not seem to be provided
A bike rides at an average speed of 25 km/h. How many minutes will it take for this rider to ride a distance of 20 km?
Answer:
48 minutes
Explanation:
60 divided by 25 equals 2.4 then you times 2.4 by 20
How many liters of oxygen gas at STP are required to react with 30.25 g of aluminum in the production of aluminum oxide?
Answer:
18.82L of oxygen gas are needed.
Explanation:
1st) It is necessary to write and balance the chemical reaction:
[tex]3O_2+4Al\rightarrow2Al_2O_3[/tex]2nd) From the balanced reaction, we can see that 3 moles of oxygen gas (O2) react with 4 moles of aluminum (Al). To convert moles to grams, it is necessary to use the molar mass of oxygen (32g/mol) and aluminum (27g/mol):
- O2 conversion:
[tex]\begin{gathered} 1mol-32g \\ 3mol-x=\frac{3mol*32g}{1mol} \\ x=96g \end{gathered}[/tex]- Al conversion:
[tex]\begin{gathered} 1mol-27g \\ 4mol-x=\frac{4mol*27g}{1mol} \\ x=108g \end{gathered}[/tex]Now we can see that 96g of O2 react with 108g of Al.
3rd) We have to calculate the grams of O2 that will react with 30.25g of Al:
[tex]\begin{gathered} 108gAl-96gO_2 \\ 30.25gAl-x=\frac{30.25gAl*96gO_2}{108gAl} \\ x=26.89gO_2 \end{gathered}[/tex]Using the molar mass of oxygen, we know that 26.89g represent 0.84 moles of O2.
4th) Finally, a mole of a gas at STP conditions occupies a volume of 22.4L. With this number and the moles of oxygen gas, we can calculate the liters:
[tex]\begin{gathered} 1mol-22.4L \\ 0.84mol-x=\frac{0.84mol*22.4L}{1mol} \\ x=18.82L \end{gathered}[/tex]So, 18.82L of oxygen gas are needed.
Write the correct formula for the following compound:
magnesium hydroxide
The formula of magnesium hydroxide is Mg(OH)2.
How magnesium hydroxide?Magnesium hydroxide is an inorganic compound having the chemical formula of Mg(OH)2. It is present in nature as mineral brucite. It is a white solid substance with low solubility in water. Magnesium hydroxide is a component of antacids such as milk of magnesia. Extended use or overuse of this medication for constipation results in dependence on laxatives and constipation. Overuse of Magnesium hydroxide also causes diarrhea that does not go away, dehydration, and mineral imbalances. Severe nausea, vomiting, or diarrhea are the symptoms of using a high dose of magnesium hydroxide. After using a medicine such as a laxative, nausea, vomiting or diarrhea can be cured.
So we can conclude that Mg(OH)2 is the correct formula for magnesium hydroxide.
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2. Suppose you are testing the gas in laboratory. If you inserted the burning magnesium ribbon inside the gas jar and magnesium ribbon burnt completely and formed light yellow ash as residue, then which gas was there in the gas jar and what is the name of compound present in yellow ash?
When the magnesium ribbon is burned, it enters the carbon dioxide gas jar and continues to burn. The carbon is left behind as a black soot and extra energy is released as a result of the reaction where the magnesium atoms join the oxygen in the carbon dioxide to form magnesium oxide.
Magnesium ribbon is used in pyrotechnics to ignite thermite reactions or to create certain firework mixes. One of the most popular techniques to start chemical reactions that need a higher temperature to ignite is with magnesium ribbon.The light produced by the burning magnesium ribbon is strong enough to temporarily impair vision. Avert looking at the light source directly. Magnesium combustion in air generates strong heat that can result in burns and start the combustion process in combustible materials.To know more about magnesium ribbon
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A 5.325-gram sample of methyl benzoate, a compound used in the manufacture of perfumes, is found to contain 3.758 g carbon, .316 g hydrogen, and 1.251 grams of oxygen. What is the empirical formula for this substance?
Answer
The empirical formula for the compound is C₄H₄O₁Explanation
Given:
Mass composition: 3.758 g carbon, 0.316 g hydrogen, and 1.251 grams oxygen.
What to find:
The empirical formula for the substance.
Step-by-step solution:
The first step is to convert the number of grams of each element into moles as shown below using the molar masses of H = 1.00784 g/mol and C = 12.011 g/mol and O = 15.999 g/mol
Note: Mole = Mass/Molar mass
Moles C = 3.758g/12.011 g/mol = 0.31 mol
Moles H = 0.316g/1.00784 g/mol = 0.31 mol
Moles O = 1.251g/15.999 g/mol = 0.078 mol
Now, let's divide the number of moles of each element by the smallest number obtained:
C = 0.31/0.078 = 4
H = 0.31/0.078 = 4
O = 0.078/0.078 = 1
The empirical formula for the compound is C₄H₄O₁
determine the number of significant figures in each of the following numbers.1.) 32.05 =2.) 36541 =3.) 300,012,345 =4.) 36,000 =5.) 100 =6.) 100.0 =7.) 1,0000 =8.)250 =9.) 250. =10.) 407 =
we are required to determine the significant figures in each of the numbers.
1) 4 significant figures
2) 5 significant figures
3) 9 significant figures
4) 5 significant figures
5) 3 significant figures
6) 4 significant figures
7) 5 significant figures
8) 3 significant figures
9) 3 significant figures
10) 3 significant figures
how does a catalyst increase the rate of a reaction?
Answer:
Reducing the activation energy and providing an alternative reaction pathway for the reaction to happen
Explanation:
A lower activation energy means that reactants will need less energy to successfully react to make products, meaning that more successful collisions will happen between reactants, increasing the rate of reaction
A catalyst reduces the activation energy of the reaction, speeding it up. By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.
What is catalyst ?By decreasing the activation energy, the energy hurdle that must be cleared for a chemical reaction to take place, catalysts improve the efficiency of this process.
As a result, catalysts facilitate the formation of chemical bonds between atoms to create novel combinations and new compounds.
A catalyst is a chemical that may be included in a reaction to speed up the process without being consumed. Typically, catalysts shorten the activation energy of a process or alter its mechanism. Proteins called enzymes serve as catalysts in biological processes.
Thus, the catalyst reduces the activation energy of the reaction, speeding it up
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A chicken egg has mass 60g. It's shell makes up 10% of the whole egg. The shell is made of Calcium Carbonate; CaCO3. What is the mass of the Ca/ Calcium in the egg shell?
Consider a solution containing 0.100 M fluoride ions and 0.126 M hydrogen fluoride. The concentration of fluoride ions after the addition of 10.00 mL of 0.0100 M HCl to 25.0 mL of this solution is ________ M.
The concentration of fluoride ions after the addition of 10.00 mL of 0.0100 M HCl to 25.0 mL of this solution is 0.009 M
One of the terms for concentration that is used frequently in solutions would be molarity. It would be explained as the number of moles of solute in one liter of solution.
Molarity can be determined by the formula:
Molarity = moles of solute/ volume of solution
Moles of the HCl can be determined by using the formula:
Moles of solute = molarity × volume of the solution.......(i)
It is given that,
Molarity = 0.0100 M.
Volume = 10.0 mL .
Put the value of given data in above equation:
Moles of solute = (0.0100 M) × (10.0 mL) ×([tex]10^{-3}[/tex]/1 mL)
Moles of solute = [tex]10^{-7}[/tex] M
Now, determine moles of HF.
Moles of solute = (0.126 M) × (25 mL) ×([tex]10^{-3}[/tex]/1 mL)
Moles of solute = 0.00315 M
Total moles = 0.00315 M + 0.0000001 M =0.0031501 M
Total volume = 10.00 mL + 25 mL = 35 mL.
Molarity can be determined by the formula:
Molarity = moles of solute/ volume of solution
Molarity = 0.0031501 M / 35 (1/[tex]10^{-3}[/tex])
Molarity = 0.009 M
Therefore, molarity will be 0.009 M.
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When 29.0 g of butane reacts with oxygen, 88.0 g of carbon dioxide and 45.0 g of water are produced. What mass of oxygen reacted with the butane?
We need to first write the balanced equation:
[tex]2C_4H_{10}+13O_2\rightarrow8CO_2+10H_2O[/tex]we are given the following:
mass of butane = 29.0 g
mass of carbon = 88.0 g
mass of water = 45.0 g
We want the mass of O2 that reacted.
C4H10 is the limiting reactant, and we know the masses of products produced. We can use that to find out how much oxygen reacted.
We can use CO2:
number of moles of CO2 = 88.0/44.01 = 1.9995 mol
The molar ratio between O2 and CO2 is 13:8
Therefore the number of moles of O2 = 1.9995 x (13/8) = 3.249 mol
Now that we have the number of moles, we can calculate the mass.
m = n x M
m = 3.249 mol x 31.998 g/mol
m = 103.97 g
The combustion of glucose is represented by the following balanced equation:
In order to find limiting and excess reactants, we need to first, set up the equation, and it must be properly balanced:
C6H12O6 + 6 O2 -> 6 H2O + 6 CO2
1 gram of C6H12O6
1 gram of O2
From the balanced equation, we see that the molar ratio between C6H12O6 and O2 is 1:6, this means that 1 mol of C6H12O6 will react with 6 times the number of moles of O2
Now let's find the number of moles of C6H12O6, the molar mass is 180.16g/mol
180.16 g = 1 mol
1 g = x moles
x = 0.005 moles of C6H12O6, now we will need this number of moles times 6 in order to proceed with the reaction
1 C6H12O6 = 6 O2
0.005 C6H12O6 = x O2
x = 0.03 moles of O2
And this amount of moles with the molar mass of O2, which is 32g/mol
32 g = 1 mol
x grams = 0.03 moles
x = 0.96 grams of O2 in 0.03 moles
Since we have more oxygen than what we actually need, Oxygen is in excess and C6H12O6 is the limiting reactant
The energy released when a nucleus forms is calledQuestion 26 options: enthalpy. atomic mass. a becquerel. binding energy.
The correct answer in this case is binding energy, which is the energy released when a collection of nucleons form a nucleus.
The correct answer is the last choice.
Which equation is balanced?
O 2Fe +02 → 2Fe2O3
O 3Fe +302 → 3Fe2O3
O 4Fe +302 → 2Fe2O3
O Fe +0₂ Fe₂O3
Answer:
C) 4Fe + 3O2 → 2Fe2O3
Explanation:
For this question, first you would go through all the options and make sure that there is an equal amount of elements on each side.
For the first option: 2Fe +02 → 2Fe2O3
You have only 2Fe atoms and 2O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is not balanced.
For option b: 3Fe +302 → 3Fe2O3
You have 3Fe and 6O atoms on your reactant side while on your product side you have 6Fe and 6O atoms. This is not balanced.
For option c: 4Fe +302 → 2Fe2O3
You have 4Fe and 6O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is balanced!
For option d: Fe +0₂ → Fe₂O3
You have 1Fe and 2O atoms on your reactant side and 2Fe and 3O atoms on your product side. This is not balanced.
***Remember to multiply the subscript of an element by their coefficient (number in front of molecule) if there is any.
If a volcano erupts and ejects 12.5 moles of sulfur into the atmosphere how many atoms of sulfur is this
In this question, we have to find the number of atoms in 12.5 moles of Sulfur, and the way to do it is by using the Avogadro's number, which is 6.02*10^23 atoms, this value represents how many atoms we have in 1 single mol of any element. Therefore in 12.5 moles we will have:
1 mol = 6.02*10^23 atoms
12.5 moles = x atoms
x = 7.52*10^24 atoms of Sulfur in 12.5 moles
Monica works in a crime lab. Her supervisor tells her that she needs to better understand Locard’s Exchange Principle. How will she MOST accurately demonstrate her understanding of this concept?
A.
She will always test for the presence of blood at crime scenes.
B.
She will use both fingerprints and bullet matching to solve crimes.
C.
She will keep evidence separated so it doesn’t get contaminated.
D.
She will exchange information openly with other crime investigators.
She will keep evidence separated so it doesn’t get contaminated demonstrates the understanding of Locard’s Exchange Principle and is denoted as option C.
What is Locard’s Exchange Principle?This principle states that an individual who commits a crime will bring something into the crime scene and leave with something from it. This also explains that they can be used as evidence during investigation by the appropriate authorities.
Since we are aware that new substances are always brought into and carried away from the crime scene then it is best to keep the evidence separated so it doesn’t get contaminated.
This ensures that the results gotten from the analysis and investigation are accurate and is therefore the reason why option C was chosen as the correct choice.
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Part II Dilution Problems: 17. 350.0 mL of water was added to a 2.3 L solution of NaCl. If the final concentration of the solution was 0.967 M, what was the original concentration of the solution?
ANSWER
The original concentration of the solution is 0.147 mol
EXPLANATION
Given that;
The volume of water is 350.0mL
The volume of NaCl solution is 2.3L
The final concentration of the solution is 0.967M
To find the original concentration of the solution, follow the steps below
Step1: Write the dilution formula
[tex]\text{ M1V1}=M2V2[/tex]Where
• M1 is the original concentration of the solution
,• V1 is the original volume of the of the solution
,• M2 is the final concentration of the solution
,• V2 is the final volume of the solution
Step 2: Convert the volume of water to L
Recall, that 1mL is equivalent to 0.001L
[tex]\begin{gathered} \text{ The volume can be converted below as} \\ \text{ 1mL }\rightarrow\text{ 0.001L} \\ \text{ 350mL }\rightarrow\text{ vL} \\ \text{ Cross multiply} \\ \text{ vL}\times\text{ 1mL }=\text{ 350mL}\times0.001L \\ \text{ Isolate v} \\ \text{ v }=\text{ }\frac{350\cancel{mL}\times\text{ 0.001L}}{1\cancel{mL}} \\ \text{ v }=\text{ 350}\times\text{ 0.001} \\ \text{ v }=\text{ 0.35L} \end{gathered}[/tex]Step 3; Find the original concentration of the solution by substituting by the given data into the formula in step 1
[tex]\begin{gathered} \text{ M1}\times2.3\text{ }=\text{ 0.35}\times\text{ 0.967} \\ \text{ 2.3M1 }=\text{ 0.33845} \\ \text{ Divide both sides by 2.3} \\ \text{ }\frac{2.3M1}{2.3}\text{ }=\text{ }\frac{0.33845}{2.3} \\ \text{ M1}=\text{ 0.147 mol} \end{gathered}[/tex]Hence, the original concentration of the solution is 0.147 mol
Which of the following will not affect the rate of a reaction?nature of the reactantscolor of reactanttemperatureconcentration of a reactant
Color of reactant. Option B is correct
Explanations:What is a rate of reactions?This is defined as the speed at which a reaction takes place. It can be expressed in terms of the concentration of reactants or products formed per unit time.
The following are the factors that affects reaction rate.
- concentration of a reactant
- Temperature
- Nature of the reactant
- Surface Area
- Catalysts.
Based on the explanations above, we can conclude that the color of reactant will not affect the rate of a reaction
what is the volume (in L) in a cylinder filled with 23.0 g of N2 gas at a temperature of 65 C and a pressure of 2.37 atm?
The volume of the cylinder filled with 23.0 g of N₂ gas at a temperature of 65 °C and a pressure of 2.37 atm is 9.6 L
Given that,
Mass of the nitrogen gas in the cylinder (m) = 23 g
Temperature (T) = 65 ℃ = 65 + 273 = 338 K
Pressure (P) = 2.37 atm
R (gas constant) = 0.082057338 L.atm.K⁻¹.mol⁻¹
In Ideal gas law or general gas equation,
PV = nRT
Number of moles in nitrogen (n) = Given mass (m) of nitrogen/ Molar mass of nitrogen
Given mass (m) = 23 g
Molar mass of Nitrogen = 28 g/mol
Number of moles of nitrogen (n) = 23 / 28 = 0.82 moles of nitrogen
PV = nRT
2.37 * V = 0.82 * 0.0821 * 338
2.37 * V = 22.75
V = 22.75 / 2.37
V = 9.6 L
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What is the total pressure in kPa exerted by a mixture containing two gases if the partial pressure of one gas is 64 kPa and the partial pressure of the other gas is 50.8 kPa?
Dalton's Law or Law of Partial Pressures says that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each gas that composes it. The partial pressure of a gas on the other hand is defined as the pressure it would exert if it were alone in the container.
So we need to sum all the values:
64 + 50.8 = 114.8 kPa
Answer: 114.8 kPa
Definition: This is a type of element or substance that is not a metal.Example: oxygen, nitrogen, hydrogen
This elements or substances that are not a metal are called non-metals.
I think that the answer is Non-metal
How many moles of H2 is needed to produce 12 moles of NH3
The balanced reaction is:
[tex]N_2+3H_2\rightarrow2NH_3[/tex]According to this, 3 moles of H2 produce 2 moles of NH3. Use this ratio to find the number of moles of NH3 produced:
[tex]12molNH_3\cdot\frac{3molH_2}{2molNH_3}=18molH_2[/tex]It means that 18 moles of H2 are needed to produce 12 moles of NH3
Calculate the frequency and the energy of blue light that has a wavelength of 423 nm (Note => 423 nm = 4.23 * 10^7 m)
According to the Planck's equation,the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.
What is Planck's equation?Max Planck discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.
The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.
In the given problem, energy is calculated as,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.23×10[tex]^-7[/tex]=4.699×10[tex]^-19[/tex] J.
The frequency of light is calculated as follows,4.699×10[tex]^-19[/tex]/19.878×10[tex]^-26[/tex]=2.363×10⁶ m[tex]^-1[/tex].
Thus , the energy and frequency of blue light are 4.699×10[tex]^-19[/tex] J and 2.363×10⁶ m[tex]^-1[/tex] respectively.
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